A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for which the interval between times of maximum brightness is 4.4 days. Its average brightness is 4.2 and the brightness changes by +/-0.45. Using this data, we can construct a mathematical model for the brightness of Cephei Joe at time t , where t is measured in days: B(t)=4.2 +0.45sin(2pit/4.4)
(a) Find the rate of change of the brightness after t days.
(b) Find the rate of increase after one day.

Answer:

i cant see

Step-by-step explanation:

it, its to tiny

The relationship between the resonant wavelength λ and the length of an open-closed tube L for the n=1,3,5, and 7 harmonics follows the general equation λ=(2n+1)L/2n. This means that the nth harmonic has a wavelength that is (2n+1) times the length of the tube divided by 2n.

For example, the wavelength of the 1st harmonic is λ= (21+1) L/21=3L/2, the wavelength of the 3rd harmonic is λ= (23+1) L/23=7L/4, the wavelength of the 5th harmonic is λ= (25+1) L/25=11L/4, and the wavelength of the 7th harmonic is λ= (27+1) L/27=15L/4. Therefore, the algebraic relationship between the resonant wavelength and length of an open-closed tube follows the general equation λ= (2n+1) L/2n, where n is the harmonic number. This equation can be used to calculate the resonant wavelength for any harmonic number.

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In a 100-meter race, the runner travels the 1st and 2nd 50-meters in time t1 and t2. Then t1>t2. So, the correct option is D.

During the first half , the runner has to start from the rest and will gain some velocity as he move further from start point, where as for the second half , as he already has the velocity required to run, he will complete the second half faster than first half.

Let us assume that V1 is the velocity , that the runner is having during the first half. V1 doesn't start as soon as he starts running, at first the body is in rest and velocity V1 starts increasing after he travels few distance.

And Let V2 be the velocity for the runner in second half , as he already have the velocity V1, there will be no delay to start the second half. So, second half takes less time than first half. This can be expressed as:

t2>t1

where t2 is second half time and t1 is first half time.

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Complete question is:

In a 100-meter race, the runner travels the 1st and 2nd 50-meters in time t1 and t2. usually: group of answer choices

a) do not know t1 or t2 is longer.

b) t1 = t2

c) t1<t2

d) t1>t2

The total number of golf balls with Jack as -

{n} = 3b + 6.

Given is that Jack had 3 bags of golf balls with {b} balls in each bag; then his friend gave him 6 golf balls more.

We can write the total number of golf balls with Jack as -

{n} = 3b + 6

Therefore, the total number of golf balls with Jack as -

{n} = 3b + 6.

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{Question in english -

Jack had 3 bags of golf balls with b balls in each bag; then his friend gave him 6 golf balls more. How many golf balls does Jack have now?}

Answer:

1 ticket - $4.25

5 tickets - $21.25

Step-by-step explanation:

12.75/3=4.25 which is one ticket then take the price of one ticket and multiply it by 5, 4.25*5=21.25.

Answer: To find the minimum point of the curve y = x^2 + 4x - 7, we need to find the vertex of the parabolic function. The x-coordinate of the vertex can be found using the formula:

x = -b / (2a)

where a = 1 (coefficient of x^2), b = 4 (coefficient of x), and c = -7 (constant term). So, we have:

x = -4 / (2 * 1) = -2

The y-coordinate of the vertex can be found by substituting the x-coordinate into the original equation:

y = -2^2 + 4 * -2 - 7 = 4 - 8 - 7 = -11

So, the minimum point of the curve y = x^2 + 4x - 7 is located at the point (-2, -11).

Step-by-step explanation:

Answer:

s=2

Step-by-step explanation:

It takes Tara 5 months to pay off the balance.

An interest rate tells you how high the cost of borrowing is, or high the rewards are for saving. So, if you're a borrower, the interest rate is the amount you are charged for borrowing money, shown as a percentage of the total amount of the loan.

Given that, Tara used a credit card to pay for a jacket that costs $150.

The credit card company charges 25% interest each month on the remaining balance.

Now, 25% of 150

25/100 ×150

0.25×150= 37.5

So, total money is 150+37.5

= 187.5

Number of months = 187.5/40

= 4.6875

≈ 5

Therefore, it takes Tara 5 months to pay off the balance.

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Answer: 11g

Step-by-step explanation:

This is so because 6g and 5g are both like terms

They both have the variable g which makes them like terms

U can just add like terms straight away

To simplify an expression with like terms, you add their coefficients. In this case, we have [tex]6g+5g[/tex].

Combine Like Terms:
[tex]6g+5g[/tex]

[tex]=\fbox{11g}[/tex]

Andrew's monthly net income is $65280.

Lisa's monthly net income is $60960.

The total monthly net income is $126240.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Andrew's monthly gross income.

= $81, 600

Lisa's monthly gross income.

= $76,200

Now,

Tax = 20%

So,

Andrew's monthly net income.

= 80/100 x 81, 600

= $65280

Lisa's monthly net income.

= 80/100 x 76,200

= $60960

Now,

Total monthly net income.

= 65280 + 60960

= $126240

Thus,

Andrew's monthly net income = $65280

Lisa's monthly net income = $60960

Total monthly net income = $126240

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The boxplot for the provide data is present in above figure. Median or central tendency of data is equals to 8.08. The lower and upper limits of outliers are 7.928 and 8.248 respectively.

The first task is to compute the median and the quartiles. And, in order to compute the median and the quartiles, the data needs to be put into the ascending order, as shown in the above table. Since the sample size n = 14 is even, we have that (n+1)/2 = (14+1)/2 =7.5, is not an integer value, the median is computing by taking the average of the values at the positions 7ᵗʰ and 8ᵗʰ, as shown below Median = (8.08 + 8.08)/2 = 8.08

Quartiles : The quartiles are computed using the table with the data in the asencending order. For Q₁ we have to compute the following position:

pos(Q) = (n+1)× 25/100 = 15×25/100 = 3.75

Since 3.75 is not an integer number, Q₁ is computed by interpolating between the

values located in the 3ᵗʰ and 4ᵗʰ positions, as shown in the formula above

Q₁ = 8.04+ (3.75 - 3) (8.05 - 8.04) = 8.0475

pos(Q₃) = (n + 1)× 75/100

= (14+1)×75/100 = 11.25

Since 11.25 is not an integer number, Q₃ is computed by interpolating between

the values located in the 11ᵗʰ and 12ᵗʰ positions, as shown in the formula below

Q₃ = 8.12 + (11.25 - 11) × (8.15 8.12) = 8.1275

The interquartile range is therefore

IQR = Q₃ - Q₁ = 8.1275 - 8.0475 = 0.08

Now, we can compute the lower and upper limits for outliers:

Lower = Q₁ - 1.5 x IQR = 8.0475 - 1.5×0.08 =7.928

Upper = Q₃ + 1.5 x IQR = 8.1275 + 1.5× 0.08 =8.248

and then, an outcome X is an outlier if X < 7.928, or if X > 8.248.

In this case since all the outcomes X are within the values of Lower = 7.9275 and Upper = 8.2475, then there are no outliers. The above boxplot is obtained.

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Answer:chicken nuggets

Step-by-step explanation:

chickemn nuggets

Answer:

8/5 = 1.6

Step-by-step explanation:

8/5 = 1.6

The answers to each part is given below.

A function is a elation between a dependent and independent variable.

Given is the function as -

f(x) = x² + 10x + 12

{ 1 } -

Using the quadratic formula, we can write -

x = - 10 ± √(100 - 48)/2

x = {- 10 ± √52}/2

{ 2 } -

We can write the area as -

1/2 x b x h = 96

1/2 x 2(x + 4) x {x} = 96

x(x + 4) = 96

x² + 4x - 96 = 0

Using the quadratic formula, we can write -

x = - 4 ± √(16 + 384)/2

x = -4 ± 20/2

Therefore, the answers to each part is given above.

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The number of days required to pave 155 miles of the road will be 7 days. The length of the road paved in 13 days will be 113 miles.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the length, L (in miles) that is left to be paved after d days is given by the following function. L (d) =204-7d.

The number of days will be calculated as:-

L (d) =204-7d

155 = 204 - 7d

7dv = 49

d = 7 days

The length of the road paved in 13 days will be calculated as:-

L (d) =204-7d

L (d) =204-7 x 13

L (d) =113 miles

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a) The probability distribution for a player's winnings is shown in table.

b) The expected winnings for a player are $3.70.

What is probability distribution?

A probability distribution is a mathematical function that describes the likelihood of various variable values. Probability distributions are frequently represented using graphs or probability tables.

a) Since there are 10 possible digits for each of the four positions, there are a total of 10^4 = 10,000 possible sequences of numbers that could be drawn.

Only one of these sequences will be the winning sequence, corresponding to a probability of 1/10,000. If a player wins, the prize is $3,700. Therefore, the probability distribution for a player's winnings is shown in below table.

b) To find the expected winnings, we multiply each possible winning amount by its probability and add the products together:

E(Winnings) = (0) * (9999/10000) + (3700) * (1/10000)

= 37/10

= $3.70 (rounded to two decimal places)

Therefore, the expected winnings for a player are $3.70.

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The solution of second order linear equation DE  (1- tcot t) y - ty y 0 for 0 < t < T is y2(t) = sin(t). There cannot be exist a constant k such that {x^2, e^x} is a set of solutions to the given differential equation.

To check if y1(t) = t is a solution to the given differential equation, we substitute it into the DE and simplify:

(1 - t cot(t))y - t(dy/dt) = (1 - t cot(t))t - t(1) = t - t^2 cot(t) - t = t(1 - t cot(t))

So y1(t) = t is a solution to the DE.

To check if y2(t) = sin(t) is a solution, we substitute it into the DE and simplify:

(1 - t cot(t))y - t(dy/dt) = (1 - t cot(t))sin(t) - t(cos(t)) = sin(t) - t sin(t) (csc(t)) - t(cos(t)) = sin(t) - t tan(t) sin(t) - t(cos(t))

So y2(t) = sin(t) is also a solution to the DE.

To check if y1(t) and y2(t) are linearly independent, we can check if their Wronskian is nonzero. The Wronskian of two solutions y1(t) and y2(t) of a second-order linear differential equation is given by:

W(y1, y2) = y1(t) (dy2/dt) - y2(t) (dy1/dt)

Substituting y1(t) = t and y2(t) = sin(t), we get:

W(y1, y2) = t cos(t) - sin(t)

Since W(y1, y2) is not identically zero (it is zero only at certain values of t), we can conclude that y1(t) and y2(t) are linearly independent.

The general solution to the given differential equation is given by:

y(t) = c1 t + c2 sin(t)

where c1 and c2 are constants determined by the initial or boundary conditions.

Let W(x) be the Wronskian of the solutions y1(x) and y2(x) of the differential equation given by:

(1 - x^2) y'' - 2x y' + k y = 0

Then, we have:

W(x) = y1(x) y2'(x) - y1'(x) y2(x)

Substituting y1(x) = x^2 and y2(x) = e^x, we get:

W(x) = x^2 e^x - 2x e^x - x^2 e^x = -2x e^x

Since we are given that W(0) = 1, we have:

W(0) = -2(0) e^0 = 1

This gives us a contradiction, so there cannot exist a constant k such that {x^2, e^x} is a set of solutions to the given differential equation.

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Expanding the polynomial, (7x + 5)(2x³ − 4x² + 9x − 3), we have: A. 14x^4 - 18x³ + 43x² + 24x - 15.

By applying the distribution property, we can expand a given polynomial expression like the one given above.

Given, (7x + 5)(2x³ − 4x² + 9x − 3), distribute to eliminate the parentheses:

7x(2x³ − 4x² + 9x − 3) + 5(2x³ − 4x² + 9x − 3)

14x^4 - 28x³ + 63x² - 21x + 10x³ - 20x² + 45x - 15

Combine like terms:

14x^4 - 18x³ + 43x² + 24x - 15

The correct solution is option A.

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Step-by-step explanation:

A = 1/2 bh

divide by 1/2

2A = bh

divide by h

2A/h = b

Hope this helps.

Answer:

[tex] b = \dfrac{2A}{h} [/tex]

Step-by-step explanation:

[tex] A = \dfrac{1}{2}bh [/tex]

[tex] 2A = 2 \times \dfrac{1}{2}bh [/tex]

[tex] 2A = bh [/tex]

[tex] \dfrac{2A}{h} = \dfrac{bh}{h} [/tex]

[tex] \dfrac{2A}{h} = b [/tex]

[tex] b = \dfrac{2A}{h} [/tex]

The center and radius of the circle in the equation is given by (-5, 3) and 4 respectively.

A circle is a round-shaped figure that has no corners or edges. In geometry, a circle can be defined as a closed, two-dimensional curved shape.

Given that, an equation of a circle, (x+5)²+(y-2)² = 4, we need to identify the center and radius of the circle,

The standard form for the equation of a circle is (x−h)²+(y−k)² = r². The center is (h, k) and the radius measures r units.

Comparing with the standard form, we get,

(h, k) = (-5, 2) and r² = 4

Therefore, the center is (-5, 2) and the radius is r = 4

Hence, the center and radius of the circle in the equation is given by (-5, 3) and 4 respectively.

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a) f1(t) = 1 is a even function, the even part is simply 1/2, and the odd part is 0.

b) f2(t) = t^3 - 2t is odd function, the even part is t^3 - t, and the odd part is   -t.

Part (a) asks us to classify the function f1(t) = I as even, odd, or neither. Here, I represents a constant, so f1(t) is a constant function.

A function f(t) is even if f(-t) = f(t) for all t in the domain of f. In other words, the function has symmetry about the y-axis.

A function f(t) is odd if f(-t) = -f(t) for all t in the domain of f. In other words, the function has rotational symmetry about the origin.

For a constant function, we have f(-t) = I = f(t) for all values of t. Therefore, f1(t) is even.

Part (b) asks us to classify the function f2(t) = t^3 - 2t as even, odd, or neither.

To determine whether f2(t) is even, odd, or neither, we need to apply the definitions of even and odd functions.

If f2(t) is even, then we have f2(-t) = f2(t) for all t.

If f2(t) is odd, then we have f2(-t) = -f2(t) for all t.

We can check these conditions as follows:

f2(-t) = (-t)^3 - 2(-t) = -t^3 + 2t

Since f2(-t) is not equal to f2(t) for all t, we know that f2(t) is not even.

We can also check if f2(t) is odd:

f2(-t) = (-t)^3 - 2(-t) = -t^3 + 2t = -f2(t)

Since f2(-t) = -f2(t) for all t, we know that f2(t) is odd.

To find the even and odd parts of a function, we use the following formulas:

even part of f(t) = (f(t) + f(-t))/2

odd part of f(t) = (f(t) - f(-t))/2

For f1(t) = I, the even part is (I + I)/2 = I/2, and the odd part is (I - I)/2 = 0.

For f2(t) = t^3 - 2t, the even part is (t^3 - 2t + (-t)^3 - 2(-t))/2 = t^3 - t, and the odd part is (t^3 - 2t - (-t)^3 + 2(-t))/2 = -t.

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The change in Kareem's total pay for each copy of Math is fun he sells is $90. Kareem's total pay if he doesn't sell any copies of Math is fun is  $2500.

Total Pay means regular straight-time earnings or base salary, plus payments for overtime, shift differentials, incentive compensation, bonuses, and other special payments, fees, allowances or extraordinary compensation.

Given that, the equation 90x+2500 = y, represents the relation between number of copies (x) Kareem sells and total pay (y) he receives,

We are asked to find, Kareem's total pay if he doesn't sell any copies of History is Fun and the change in Kareem's total pay for each copy of History is Fun he sells,

So, from the equation, 90x+2500 = y,

If we compare this equation with the general equation of the line, i.e. y = mx+c, where m is the slope, which shows 'change', we will get m = 90.

Therefore, the change in Kareem's total pay is $90.

Now, the number of copies he is selling is shown by x, if he sells no copy, then x = 0,

Therefore, Kareem's total pay, for x = 0,

y = 2500+90(0)

y = 2500

Hence, the change in Kareem's total pay for each copy of Math is fun he sells is $90. Kareem's total pay if he doesn't sell any copies of Math is fun is  $2500.

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The area of a rectangle with the given length breadth is 1.5 square feet.

The area occupied by a rectangle within its boundary is called the area of the rectangle. The formula to find the area of a rectangle is Area = Length × Breadth.

Given that, length of a rectangle= 3 ft and width of a rectangle= 1/2 ft.

Area is defined as the total space taken up by a flat surface or shape of an object.

Here, area of a rectangle =Length × Breadth

= 3×1/2

= 3×0.5

= 1.5 square feet

Therefore, the area of a rectangle is 1.5 square feet.

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The correct statement is -

company {R} charges less money for 1 hour of service compared to company {P}.

Division is used to split a number into equal parts. It is one of the four arithmetic operations.

Given is that Limousine Company {P} charges a rental fee plus an additional charge per hour. The equation {y} = 50 + 30x shows the total cost. The cost to rent a limousine from Company {R} is shown below in the table as -

Time :   1       2        3         4       5

Cost : $100  $125  $150  $175  $200

We can write the unit charge for company {P} as -

{r₁} = $30

We can write the unit charge for company {R} can be calculated as -

{r₂} = (125 - 100) ÷ (2 - 1)

{r₂} = $25

We can conclude -

company {R} charges less money for 1 hour of service compared to company {P}.

Therefore, the correct statement is -

company {R} charges less money for 1 hour of service compared to company {P}.

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The missing term y in the given data having mean is 33.

The Arithmetic Mean is the average of the numbers: a calculated "central" value of a set of numbers.

Given that, the mean = 13,

we need to find the value of y.

4+6+9+y+16+19 / 6 = 13

y = 33

Hence, the missing term y in the given data having mean is 33.

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The ecologist needs to carefully choose the size of the sampling region based on the pdf of R.

Sampling is the process of selecting a representative subset of individuals or objects from a larger population to study or analyze.

To ensure that their data is representative of the entire ecosystem, it is important to choose a sampling region that is large enough and well-defined.

In this scenario, an ecologist wishes to mark off a circular sampling region with a fixed radius of 13 meters. However, due to natural variation, the actual radius of the sampling region is a random variable, denoted by R. The probability density function (pdf) of R is given as

=> s(r) = { 1-(13-r)] ¹²,

which means that the probability of a particular value of R is proportional to the area of a circle with that radius.

Now, when the ecologist takes a sample, it is important to consider the effects of this random variation in the sampling region. If the radius of the sampling region is too small, it may not capture the full range of variability in the ecosystem.

On the other hand, if the radius is too large, it may include areas that are not representative of the ecosystem as a whole.

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Answer:

Step-by-step explanation:

I can explain how the two graphs would look like.

If we are comparing two installment factors with respect to the total amount repaid (T) over time (N), we can plot two separate graphs on the same set of axes. The x-axis would represent the number of months (N) and the y-axis would represent the total amount repaid (T).

For each installment factor, we would plot a line that represents the total amount repaid over time. The shape and slope of each line would depend on the interest rate, the amount borrowed, and the number of payments per year.

The two lines would likely have a similar shape, but different slopes and intercepts. The slope of each line would depend on the interest rate and the amount borrowed, with steeper slopes indicating higher interest rates or larger amounts borrowed. The intercept of each line would depend on the amount borrowed and the number of payments per year.

To compare the two installment factors, we would look at the relative slopes and intercepts of the two lines. If one line has a steeper slope than the other, it would indicate that the total amount repaid increases more rapidly over time for that installment factor. If one line has a higher intercept than the other, it would indicate that the total amount repaid is higher at the beginning of the repayment period for that installment factor.

Overall, by plotting the two graphs on the same set of axes, we can visually compare how the total amount repaid (T) depends on the number of months (N) for both installment factors.

The Total Stockholder's Equity is $1,266,290.00

Income Statement Amount $ Amount $

Sales Revenue 1,585,000.00

Interest Revenue 2,940.00

Total Revenue  1,587,940.00

Less: Expenses  

Cost of merchandise sold 793,000.00

Selling and admin expense 158,000.00

Credit card expense 7,650.00

Bad debt reinstated (5,500.00)

Total Operating expense  953,150.00

Net Income  634,790.00

Statement of changes in Stockholder's Equity Amount $ Amount $

Beginning Common Stock 515,000.00

Add: Common Stock issued -

Ending Common Stock  515,000.00

Beginning Retained Earnings 116,500.00

Add: Net Income 634,790.00

Ending Retained Earnings  751,290.00

Total Stockholder's Equity  1,266,290.00

Balance Sheet Amount $ Amount $

Assets  

Cash  586,350.00

Inventory  303,000.00

Accounts Receivable 399,200.00

Allowance for uncollectible accounts (10,200.00) 389,000.00

Notes Receivable  63,000.00

Interest Receivable  2,940.00

Total Assets  1,344,290.00

Liabilities & Stockholder's Equity  

Liabilities  

Current Liabilities  

Accounts Payable 78,000.00

Current Liabilities  78,000.00

Stockholder's Equity  

Common Stock 515,000.00

Retained Earnings 751,290.00

Total Stockholder's Equity  1,266,290.00

Total Liabilities & Stockholder's Equity  1,344,290.00

Statement of cash flows Amount $ Amount $

Cash flow from operating activities  

Cash sales 310,000.00

Inflow from customers 997,350.00

Payment for inventory (675,000.00)

Payment for expenses (158,000.00)

Net Cash flow from operating activities  474,350.00

Cash flow from investing activities  

Notes receivable provided  (63,000.00)

Cash flow from financing activities  

Cash flow from financing activities  -

Net Change in cash  411,350.00

Add: Beginning cash balance  175,000.00

Ending cash balance 586,350.00

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