The correct answers are:
a. The total force exerted by the block on the incline.
b. The normal force exerted on the block by the incline.
a. The total force exerted by the block on the incline must have a magnitude equal to mg. This force can be decomposed into two components: one parallel to the incline (friction force) and one perpendicular to the incline (normal force). The sum of these two components is equal to mg.
b. The normal force exerted on the block by the incline must have a magnitude equal to mg. The normal force is the force exerted perpendicular to the incline, and it balances the component of the weight of the block that acts perpendicular to the incline.
c. The force of friction exerted on the block by the incline does not necessarily have a magnitude equal to mg. The force of friction depends on the coefficient of friction between the block and the incline, as well as the other forces acting on the block.
d. The gravitational force exerted on Earth by the block is equal to the weight of the block, which is mg. However, this force is not relevant to the situation of the block on the incline.
Therefore, the correct options are a and b.
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an object is with thrown with 25.2 km/h at angle 27.4 degrees. a) find the height it reaches at 0.430 seconds? b) find the velocity of the object 0.380 seconds after the release.
A) the height the object reaches is 0.148 m.
B) the velocity of the object 0.380 seconds after release is 10.79 m/s.
a) To find the height the object reaches, we need to find the vertical component of velocity. We can use the following equation:
Vy = V0y + ayt
Where V0y is the initial vertical velocity (0 m/s, since the object was thrown from rest), a is acceleration due to gravity (-9.8 m/s^2), t is time (0.430 s), and Vy is the final vertical velocity.
Plugging in the values, we get:
Vy = 0 + (-9.8)(0.430) = -4.266 m/s
Next, we can find the height using the following equation:
y = V0yt + (1/2)at^2
Plugging in the values, we get:
y = (0)(0.430) + (1/2)(-9.8)(0.430)^2 = -0.148 m
So, the height the object reaches is 0.148 m.
b) To find the velocity of the object 0.380 seconds after release, we need to use the following equation:
V = V0 + at
Where V0 is the initial velocity (25.2 km/h converted to m/s), a is acceleration due to gravity (-9.8 m/s^2), and t is time (0.380 s).
Plugging in the values, we get:
V = 25.2 * 1000/3600 + (-9.8)(0.380) = 10.79 m/s
So, the velocity of the object 0.380 seconds after release is 10.79 m/s.
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Stairways must be installed at least _____ degrees, but no more than ____ degrees from the horizontal.
Stairways must be installed at least 30 degrees, but no more than 50 degrees from the horizontal.
Stairways and stepping stools are a significant wellspring of wounds and fatalities among development laborers.OSHA gauges that there are 24,882 wounds furthermore, upwards of 36 fatalities each year because of falls from flights of stairs and stepping stools utilized in development. Almost 50% of these wounds are adequately serious to demand investment off the gig - 11,570 lost working day wounds and 13,312 non-lost business day wounds happen yearly because of tumbles from flights of stairs and stepping stools utilized in development.
These information show that work nearby stepping stools and flights of stairs is dangerous. All the more significantly,they show that consistence with OSHA's necessities for the protected utilization of stepping stools and flights of stairs might have forestalled large numbers of these wounds.
This conversation fills in as a speedy and simple reference for use on places of work. The prerequisites of OSHA security guidelines for the protected utilization of stepping stools and steps (Subpart X, Title 29 Code of Government Guidelines, Part 1926.1050 through 1926.1060) are made sense of conversation.
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lan holds a magnet a few centimeters away from a pile of metal washers. The magnetic force on
the washers is strong enough that they slide across the table towards the magnet.
How could lan decrease the magnetic force on the washers?
lan can decrease the magnetic force on the washers by increasing the distance between the magnet and the pile of metal washers.
What is a magnet?A material or object that creates a magnetic field is called a magnet.
The most noteworthy characteristic of a magnet, a force that pulls on other ferromagnetic elements like iron, steel, nickel, cobalt, etc., as well as the ability to attract or repel other magnets, is caused by this invisible magnetic field.
The strength of the magnetic force produced by a magnet increases when the distance between the magnet and an object experiencing the magnetic force is reduced.
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suggest how the student could find the total mass of of copper produced
A student could find the total mass of copper produced by using production data, use density and volume, use chemical analysis, or consult an expert.
We can use several methods to find total mass of copper produced:
Use production data: If the student has access to production data, they could determine the total mass of copper produced by summing the masses of copper produced in each unit of time (e.g. day, week, month, year). The data could be obtained from the copper producer or through publicly available sources, such as industry reports or government statistics.Use density and volume: If the student knows the density of copper and the volume of copper produced, they could calculate the mass of copper produced by multiplying the density by the volume. The density of copper is typically around 8,960 kilograms per cubic meter, but this value can vary depending on the purity of the copper.Use chemical analysis: If the student has access to a sample of the copper produced, they could use chemical analysis techniques, such as gravimetric analysis or spectroscopy, to determine the total mass of copper. This approach would require specialized equipment and knowledge, and may not be feasible for large-scale production.Consult an expert: The student could consult an expert in the field of copper production, such as a metallurgist or engineer, who would have access to production data and could provide an estimate of the total mass of copper produced.Learn more about copper here:
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in a 4-pole, 60 hz, 200v inudction motor having a full-load current of 350 a, torque developed is 700 n-m. what is the approximate speed of the motor
The approximate speed of the motor is 1800 RPM.
To determine the approximate speed of the motor, we can use the formula:
Speed (in RPM) = (120 x Frequency) / Number of Poles
The speed of the motor is calculated by the ratio of the product of 120 and frequency by the number of poles. the speed is measured in rotation per minute.
Given information:
Frequency (f) = 60 Hz
Number of Poles (p) = 4
Using the formula, the speed will be calculated as:
Speed = (120 x 60) / 4
Speed = 1800 RPM
Therefore, the approximate speed of the motor is 1800 RPM.
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5. are the 4 v, 5 v, 6 v equipotential lines between the two parallel plates evenly spaced? explain why or why not.
The 4 V, 5 V, and 6 V equipotential lines between two parallel plates are evenly spaced.
Equipotential lines represent points in space that are at the same potential or voltage. In the context of two parallel plates, these lines would be perpendicular to the plates and would indicate the potential at different points between them.
If the 4 V, 5 V, and 6 V equipotential lines are evenly spaced, this means that the potential difference between the plates is uniform and the same at each of these points. This would occur if the electric field between the plates was uniform and the same in strength everywhere.
The uniformity of the electric field is due to the plates being parallel and of equal size, as well as the presence of a uniform electric charge on each plate. These conditions would lead to a uniform distribution of the electric field and the equipotential lines being evenly spaced.
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Calculate the magnitude and direction of the electric field 0. 45 m from a +7. 85 x 10−9 C point charge
The electric field is directed away from the positive charge, so its direction is radially outward from the charge. The magnitude of the electric field is 9.29 x 10^5 N/C.
An electric field is a field that surrounds a charged particle or a collection of charged particles and can affect other charged particles in the vicinity. It is a vector field that represents the force that would be exerted on a test charge placed in that field. The strength of the electric field at a particular point is defined as the force per unit charge at that point.
The electric field (E) generated by a point charge (Q) at a distance (r) from the charge is given by Coulomb's law: E = k * Q / r^2, where k is Coulomb's constant (approximately equal to 8.99 x 10^9 N m^2/C^2). To find the magnitude and direction of the electric field 0.45 m from a +7.85 x 10^-9 C point charge, we can use the formula:
E = k * Q / r^2 = 8.99 x 10^9 N m^2/C^2 * 7.85 x 10^-9 C / (0.45 m)^2 = 9.29 x 10^5 N/C
Therefore, The electric field is directed away from the positive charge, so its direction is radially outward from the charge. The magnitude of the electric field is 9.29 x 10^5 N/C.
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For the transistor model in the following figure, obtain the Thevenin equivalent at terminals a-b if R1 = 3 kΩ and R2 = 5 kΩ 21V (± 20i R. 2 Th eq
For the transistor model in the following figure, obtain the Thevenin equivalent is [tex]V_{th}[/tex]=-700V and [tex]R_{th}=5[/tex]kohm.
To find the Thevenin equivalent ,
By temporarily removing the load resistance from the original circuit and reducing what is left to an analogous circuit made up of a single voltage source and series resistance, Thevenin's theorem can simplify this analysis.
After reconnecting the load resistance to the Thevenin equivalent circuit, calculations can be performed as if the entire network were just a straightforward series circuit.
Now, the voltage given is 21V
[tex]R_{1}=3[/tex] kohm
[tex]R_{2}=5[/tex] kohm
as, V=ir
So, I=[tex]\frac{21}{R_{1} }[/tex]
I=[tex]\frac{21}{3}[/tex]
I=7mA
[tex]V_{th}[/tex]=-20I×[tex]R_{2}[/tex]
[tex]V_{th}[/tex]=-20×7×5
[tex]V_{th}[/tex]=-700V
and to find the value of [tex]R_{th}[/tex]
i=0A
20i=0 means it is short circuit.
[tex]R_{th}=R_{2}=5[/tex] kohm
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according to kepler’s second law, a planet in an elliptical orbit around the sun is travelling fastest when it is at what position?
Kepler's second law states that a planet moves most quickly during perihelion and most slowly at aphelion. The orbit's total period (T) is related to the cube of the planet's average distance from the Sun (R).
What is the second law of Kepler?According to Kepler's Second Law, as a planet rounds the Sun, an arbitrary vertical connecting them sweeps across the same amount of space at the same rate. In essence, this means that asteroids do not travel throughout their revolutions at a constant speed.
The significance of Kepler's second law:The speed of the planet as it travels through its elliptical orbit is governed by Kepler's second law. Kepler demonstrated that no matter where in the orbit the planet is, the region that it "sweeps out" over a period of time is the same.
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calculate the change of free energy expressed in kj.mol-1) for the hydrolysis of atp in both tissues. note: the reactions in tissues occur at 37°c.
The change in free energy for the hydrolysis of ATP can be calculated using the equation ΔG = ΔH - TΔS, where ΔG is the change in free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.
To calculate ΔG for the hydrolysis of ATP in tissues at 37°C, the values of ΔH and ΔS must be known. At 37°C, the temperature must be converted to Kelvin (T = 37 + 273 = 310 K).
The specific values of ΔH and ΔS are required to determine the ΔG for the hydrolysis of ATP in tissues and can be obtained from thermodynamic databases or literature. Without these values, the ΔG cannot be calculated.
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a hypothetical planet has a radius 1.98 times that of earth, but has the same mass. what is the acceleration due to gravity near its surface? the radius of the earth is 6380 km, and the mass of the earth is 5.98 x 1024 kg.
The acceleration due to gravity near the surface of the hypothetical planet is 9.79 m/s^2, which is the same as the acceleration due to gravity near the surface of the Earth.
The acceleration due to gravity near the surface of a planet is given by the formula:
g = G * M / R^2
where G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), M is the mass of the planet, and R is the radius of the planet.
Since the mass of the hypothetical planet is the same as the Earth, we can use the mass of the Earth for M. The radius of the hypothetical planet is 1.98 times the radius of the Earth, so we can use the following for R:
R = 1.98 * 6380 km = 12618.4 km
We can now substitute these values into the formula for g:
g = 6.67 x 10^-11 Nm^2/kg^2 * 5.98 x 10^24 kg / (12618.4 x 10^3 m)^2
Simplifying this expression gives us:
g = 9.79 m/s^2
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An object has been traveling at a constant velocity of 50ms for 5seconds what was the acceleration of the object?
Answer:it would be zero since its constant velocity and there is no acceleration
Explanation:
How much is 43 degrees Fahrenheit in Celsius?
We may determine that 43°F is equivalent to 6°C using the formula.
What is Celsius?The global standard for measuring temperature is Celsius, sometimes known as centigrade. Anders Celsius, a Swedish astronomer, first used it in 1742. The freezing point of water is 0° on the Celsius scale, and the boiling point of water at standard atmospheric pressure is 100°. The most common temperature scale in use worldwide, it is utilised for scientific purposes.
How do you determine it?The formula used is,
C = (F - 32) * 5/9
Where F and C are the Fahrenheit and Celsius temperatures, respectively.
The difference between the zero points and increments on the Fahrenheit and Celsius scales means that a temperature reading on one scale will not have an exact equal on the other. While the Celsius scale is widely used and is thought to be the norm for most scientific purposes, the Fahrenheit scale is mostly used in the United States.
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What would be the coefficient of
friction between a sandal and wood
if the weight of the shoe is 14 N
and it takes 7N of force to slide it at
a constant speed across the wood?
The coefficient of friction between a sandal and wood would be 0.5
In physics, what is a friction?
The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.
A coefficient of friction is a number that depicts the interaction between two objects and their typical response to one another. The resistive force of friction divided by the normal or perpendicular force pushing the objects together yields the coefficient of friction, which is a numerical value. Equation represents it as follows:
Coefficient of friction, μ = Ff /FN
μ = 7/14
μ = 0.5
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How to convert 132 pounds to kilograms?
132 pounds are converted to kilograms. 59.8742 Formula= Divide the pertinent by 2.205 to get an approximation.
How do you use the pounds to kg conversion formula?
Add 0.45359237 kg to the given number of pounds to convert it to kilograms. For instance, multiply your given 5 pounds by 0.45359237 kg to translate 5 lbs to kilograms. Consequently, 5 lbs is roughly equivalent to 2.26796185 kg.
What is the quickest conversion factor between pounds and kilograms?
To use the conventional equation, multiply the amount of pounds by 2.2046. To convert pounds to kilograms, for instance, divide 50 by 2.2046; the result is 22.67985 kg. Divide 200 pounds by 2.2046 to get kilograms, which equals 90.71940 kg.
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what are the magnitude and direction of the rock's velocity at impact
The magnitude and direction of the rock's velocity at impact is - 50 deg or 50 deg below the horizontal.
vx = v0x = 25
cos35 = 20.5 m/s
vy = v0y + ay
t = (25 sin35) + (-9.8 x 3.96)
vy = -24.5 m/s
magnitude = sqrt(vx^2 + vy^2)
= 31.9 m/s
direction = tan^-1(vy /vx)
= - 50 deg or 50 deg below the horizontal.
Take the height and multiply it by the acceleration caused by gravity twice before taking the square root of the result to determine the impact velocity. As illustrated in Figure 4.12, the magnitudes of the components of velocity v v are v x = v cos and v y = v sin, v x = v cos and v y = v sin, where v is the magnitude of the velocity and is its direction with respect to the horizontal.
Question
A Large Rock Is Ejected From The Volcano With A Speed Of 25.0 M/S And At An Angle 35.09 Above The Horizontal. The rock Strikes the side of the volcano at an altitude 20.0 m lower than its starting point. What are the magnitude and direction of the rock's velocity at impact?
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Express D in the form Dx, Dy, where the x and y components are separated by a comma using two significant figures. The figure shows vectors A and B. Find Ď=2.4 Ā+B. (Figure 1) Figure (< 1 of 1 > 2. m 15011 1150 4 m
For each Part, the x- and y-components of the vectors are mathematically stated as follows.x=-1.939 km and y=3.498 km,x= -2 cm/s,0, y=, x= -7.6412m/s^2, -10.517m/s^2
What are the vectors' x- and y-components?
Measures for the question
We typically adhere to a fundamental premise where
component=Fsintheta for x
Fcostheta as the y component
Therefore
For A
the x component
x= -4 x sin (29°)
x= -1.939 km
Is y component
y= 4 x cos (29°)
y= 3.498 km
For B
the x component
x= -2 cm/s
Is y component
y= 0
For C
the x component
x= -13 x sin (36°)
x= -7.6412m/s^2
Is y component
y= -13 x cos (36°)
y= -10.517m/s^2
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The full question:
Part AFind the x- and y-components of the vector d⃗ = (4.0 km, 29 ∘ left of +y-axis). Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.d⃗ = km Part BFind the x- and y-components of the vector v⃗ = (2.0 cm/s , −x-direction).Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.v⃗ = cm/s Part CFind the x- and y-components of the vector a⃗ = (13 m/s2 , 36 ∘ left of −y-axis).Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.a⃗ x = m/s2
a car slows down at -5.00m/^2 until it comes to a stop after traveling 15.0m how much time did it take to stop
The time it will take for the car moving at an acceleration of 5.00m/s² is 2.45s.
How to calculate acceleration?Acceleration refers to the change of velocity with respect to time (can include deceleration or changing direction).
The acceleration can be calculated using one of the equation of motions as follows:
s = ut + ½at²
Where;
s = distanceu = initial velocitya = accelerationt = time15 = (0 × t) + ½ × -5 × t²
15 = 0 + -2.5t²
15 = -2.5t²
t² = 6
t = √6
t = 2.45s
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A 0. 36 kg object, attached to a spring with spring constant k = 10 n/m, is moving on a horizontal frictionless surface in simple harmonic motion of amplitude of 0. 082 m. What is its speed at the instant when its displacement is 0. 041 m? (hint: use conservation of energy. ).
Its speed at the instant when its displacement is 0. 041 m is 0.4321 m / s
Utilizing energy efficiency at two locations the place of interest and the furthest point of greatest elongation
Maximum initial elongation
Em₀ = K= ½ k x²
k=Force constant
K= energy
x= Spring displacement
we know, x = A = 0.082 m.
Final point of interest
Em= Ke = ½ m v²
Energy is conserved
Em₀ = Em
½ k A² = ½ m v²
v² = k / m A²
v = √(k/m) A
Then we can calculate
v = √(k/m) A
v = √ (10 / 0.36) 0.082
v = 0.4321 m / s
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A red planet is orbiting the blue sun with the Semi-Major axis (a) of 1,550,000 m and the linear eccentricity (c) of 850,000 m.
What is the eccentricity of the red planet? (Round up to the nearest fourth - 0.xxxx) _______________
*Hint : Use the formula eccentricity = ca and some algebra.
The eccentricity of the red planet is 1.3175 x 10¹² m².
What is the eccentricity of the red planet?
The eccentricity of the red planet is the product of the Semi-Major axis (a) and the linear eccentricity (c).
The Semi-Major axis (a) is given as 1,550,000 m and the linear eccentricity (c) is given as 850,000 m.
The eccentricity of the red planet is calculated as follows;
e = ca
e = 850,000 m x 1,550,000 m
e = 1.3175 x 10¹² m²
Thus, the eccentricity of red planet is a function of the Semi-Major axis (a) and the linear eccentricity (c) .
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which of the following are true? check all that apply. in equilibrium, there is a net flow of mobile charged particles inside a conductor. the net electric field at any location inside a block of copper is zero if the copper block is in equilibrium. if the net electric field at a particular location inside a piece of metal is zero, the metal is not in equilibrium. the electric field from an external charge cannot penetrate to the center of a block of iron. the net electric field inside a block of metal is zero under all circumstances.
The following are true:
The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.
The net electric field inside a block of metal is zero under all circumstances.
The electric field from an external charge cannot penetrate to the center of a block of iron.
Equilibrium in a conductor refers to a state where the electric field is zero inside the conductor and there is no net flow of mobile charged particles. The electric field from an external charge cannot penetrate to the center of a block of iron, meaning that the electric field is confined to the surface of the metal. The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium, meaning that the electric field is uniform and balanced throughout the conductor. The net electric field inside a block of metal is zero under all circumstances, regardless of the presence of an external electric field. This is because the electric field inside a metal is always balanced and uniform, due to the movement of mobile charged particles within the conductor.
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what is the 'energy per degree of freedom' of a gas particle at temperature 376k? state the answer in [ev] units.
The energy per degree of freedom of a gas particle at temperature 376K is 3/2 kT, where k is the Boltzmann constant and T is the temperature in Kelvin.
Hence, the energy per degree of freedom at 376K is 3/2 x 8.6173 x 10-5 x 376 = 0.007845 ev.
What is temperature?
Temperature is a physical quantity which measures the degree of hotness or coldness of an object. It is measured on the Celsius (°C), Fahrenheit (°F) or Kelvin (K) scales. Temperature is related to the amount of thermal energy in a system, and is an important factor in many fields of science, such as physics, chemistry, meteorology, and engineering. Temperature affects the rate of many chemical reactions, and is a key factor in the functioning of living organisms. It also plays an important role in the Earth's climate and weather pattern.
Therefore, energy per degree of freedom at 376K is 3/2 x 8.6173 x 10-5 x 376 = 0.007845 ev.
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A 55-kg skier skies down the smooth (frictionless) ski slope illustrated in the diagram. She pushes off at the top with a speed of 10 m/s. At the bottom (0 m), she comes to a stop by digging her skis in sideways.a) Construct a complete Energy-Interaction diagram to predict the speed of the skier when she is on the middle flat part (10 m).b) Repeat a) to find the speed of the skier at the bottom of the hill (before she starts stopping).c) Assuming that the snow where she comes to a stop is at a temperature of 0°C, and that all of the kinetic energy of the skier goes into melting the snow, construct a complete Energy-Interaction diagram to predict the amount of snow melted by the skier while stopping.d) Choose a different interval from the one you used in b), and solve again for the amount of snow melted when the skier stops. Is your answer the same as in b)?
a) To construct an Energy-Interaction diagram, we first need to identify the energy sources and interactions involved in the scenario. The energy sources in this case are gravitational potential energy and kinetic energy. At the top of the hill, the skier has potential energy due to her height above the ground and kinetic energy due to her initial velocity of 10 m/s. As she skis down the slope, she loses potential energy and gains kinetic energy. At the middle flat part (10 m), the skier's velocity can be calculated using the conservation of energy principle. The change in potential energy is equal to the change in kinetic energy.
PEinitial = mgh = 55 x 9.8 x 10 = 5390 J
KEinitial = 0.5mv^2 = 0.5 x 55 x 10^2 = 275 J
PEfinal = mgh = 55 x 9.8 x 10 = 5390 J
KEfinal = 0.5mv^2
5390 - 275 = 5390 - 0.5mv^2
v^2 = 10780/55 = 196
v = sqrt(196) = 14 m/s
So the skier's velocity at the middle flat part (10 m) is 14 m/s.
b) To find the speed of the skier at the bottom of the hill (before she starts stopping), we need to again use the conservation of energy principle. The potential energy at the bottom of the hill is zero, and all of the skier's energy is in the form of kinetic energy.
PEinitial = mgh = 55 x 9.8 x 10 = 5390 J
KEinitial = 0.5mv^2 = 0.5 x 55 x 10^2 = 275 J
PEfinal = 0
KEfinal = 0.5mv^2
5390 - 275 = 0.5mv^2
v^2 = 5115/55 = 93
v = sqrt(93) = 9.64 m/s
So the skier's velocity at the bottom of the hill (before she starts stopping) is 9.64 m/s.
c) To predict the amount of snow melted by the skier while stopping, we need to calculate the amount of energy required to melt the snow. The energy required to melt the snow is given by the heat of fusion, which is the amount of energy required to change a substance from a solid to a liquid at its melting point. For water, the heat of fusion is 333.55 J/g. We also need to know the mass of snow melted, which can be calculated using the velocity of the skier just before she comes to a stop (9.64 m/s) and the conservation of energy principle.
PEinitial = 0
KEinitial = 0.5mv^2 = 0.5 x 55 x 9.64^2 = 257 J
PEfinal = 0
Q = KEinitial
Q = 257 J
m = Q/Lf = 257/333.55 = 0.766 g
So the skier melted 0.766 g of snow while stopping.
d) To solve for the amount of snow melted using a different interval, we could use the velocity of the skier at the middle flat part (10 m) instead of the velocity just before she comes to a stop. The calculation would be the same as in c), but with the velocity being 14 m/s instead of 9.64 m/s. This
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Calculate approximately the total translational kinetic energy of all the molecules in an E. coli bacterium of mass 2.0 x 10-15 kg at 37°C. Assume 70% of the cell, by weight, is water, and the other molecules have an average molecular mass on the order of 10' u.
The total translational kinetic energy of the molecules in an E. coli bacterium at 37°C can be made.
To calculate the total translational kinetic energy of all the molecules in an E. coli bacterium, we need to know its temperature and the molecular masses of the constituent molecules.
At 37°C, the temperature of the bacterium can be converted to kelvins: 37°C + 273.15 = 310 K
We can then use the equation for the average kinetic energy of an ideal gas to find the translational kinetic energy per molecule:
[tex]E_k = \frac{3}{2} kT[/tex], where k is the Boltzmann constant ( [tex]1.38 x 10^{-23} J/K[/tex]) , T is the temperature in kelvins, and [tex]E_k[/tex] is the average kinetic energy per molecule.
For the water molecules, which make up 70% of the bacterium by weight, their average molecular mass is approximately 18 u, and for the other molecules, the average molecular mass is on the order of 10' u.
By assuming the bacterium has N molecules, we can find its total translational kinetic energy:
[tex]E_t = N \cdot E_k = N \cdot \frac{3}{2} \cdot k \cdot T = \frac{3}{2} \cdot k \cdot T \cdot N[/tex]
(mass of bacterium / average molecular mass)
Therefore, the total translational kinetic energy of all the molecules in an E. coli bacterium of mass [tex]2.0 * 10^{-15} kg[/tex] at 37°C can be calculated as:
[tex]E_t = \frac{3}{2} * (1.38 x 10^{-23} J/K) * 310 K * (2.0 * 10^{-15} kg / (18 u * (10^{-3} kg/u) * 0.7 + (10^5 u * (10^{-3} kg/u) * 0.3))[/tex]
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what is the direction of the net force on the charge at the top
The direction of the net force on the charge at the top is downwards.
This is because the electric field created by the charge at the bottom exerts an electric force on the charge at the top, which is directed downwards. This electric force is greater than the force of gravity, which acts upwards, resulting in a net force directed downwards. This is a result of the inverse square law of electrostatics, which states that the force between two point charges is proportional to the inverse of their distance squared. Thus, the force between the charges is stronger when they are closer together, resulting in a net force directed downwards.
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can we change one or more of the quantities r, f, or in such a way that we are sure that the torque remains unchanged?
Yes, if we decrease r and increase F by the same quantity or vice versa then the torque remains unchanged.
Torque is defined as the cross product of the force vector and radius vector.
T = r × F
Now for the magnitude;
T = (r)(F) sinθ (where θ is the angle between r and F)
If the angle between r and F is 90 i.e. perpendicular to each other then,
T = (r)(F)
Now if we increase radius(r) by 'x' times and decrease force(F) by 'x' times or vice versa then the quantity torque of the body remains constant.
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Part A)
What is the electric flux ? through each of the six faces of the cube?
Use ?0 for the permittivity of free space.
Part B)
What would be the flux ?1 through a face of the cube if its sides were of length L1 ?
Use ?0 for the permittivity of free space.
Part A.
It is impossible to determine the speed of the test charge at point y based solely on the information provided. The speed of the charge at point y could be greater than, less than, or equal to v0 depending on various factors such as the presence of electric flux or magnetic fields, resistance, or other forces that may have acted on the charge between points x and y. A detailed analysis of the situation taking into account all relevant factors would be required to determine the speed of the charge at point y.
Part B.
The electric flux through a face of a cube can be calculated using the following formula:
Φ = ε0 * E * Awhere Φ is the electric flux, ε0 is the permittivity of free space (8.854 x 10^-12 C^2/Nm^2), E is the electric field through the face, and A is the area of the face.
Given that the sides of the cube have length L1, the area of one face can be calculated as A = L1^2. Substituting this value into the formula for Φ, we get:
Φ = ε0 * E * L1^2So, the electric flux through one face of the cube can be calculated by multiplying the permittivity of free space, the electric field through the face, and the square of the side length.
About Electric Flux
Electric Flux is the number of lines of force from the electric field that penetrates a surface, even though the electric field in a conductor is not moving. Electric flux is used to describe and measure the magnitude of the electric field at a certain distance from the test charge.
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A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. The scale reads 836 n. A. As the elevator moves up, the scale reading increases to 936 n. Find the acceleration of the elevator.
The acceleration of the elevator is 1.1 m/s^2.
We have given that when the elevator is at rest the scales reads 834 N.
So W = 834 N
Acceleration due to gravity , g = 9.8 m/s^2
We know that W = mg
So, m = 834/9.8 = 85.1 kg
Now as the elevator moves upward so effective acceleration = g+a
Scale reading W = 928 N and mass m = 85.1 kg.
So,
ma + mg = W
⇒ a + g = W/m
⇒ a + g = 928/ 85.1
⇒ a + g = 10.90
⇒ a = 10.90 - g
⇒ a = 10.90 - 9.80
⇒ a = 1.10 m/s^2
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how many variables should there be in a well-designed experiment?
The answer is One, so you can determine a cause and effect relationship between the variable you are changing and the observed response.
A well-designed experiment can involve many variables, including the type of experiment, the number of participants, the type of material being tested, and the conditions of the experiment. change is the variable you are changing. The effect is the observed response.
Experimental conditions can be controlled by the researcher. For example, a study of the effects of diet on heart health can be controlled by measuring the effects of different diets on heart health under different conditions.
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What is the spinning cylinder called when it is tipped up?
A
Semitornado
B
Mesocyclone
C
Supertwister
D
Water spout
The spinning cylinder is called a vertical mesocyclone, when it is tipped up. Hence, option B is correct.
What is a mesocyclone ?A mesocyclone is a meso-gamma mesoscale zone of rotation (vortex) that normally has a diameter between 2 and 6 mi (3.2 and 9.7 km) and is most frequently seen on radar during thunderstorms.
The most powerful and hazardous thunderstorms, known as supercells, include mesocyclones. Compared to "spin-up tornadoes," which occur in some events, supercells remain a lot longer.
Hail is produced by supercells 100% of the time, while tornadoes occur around 30% of the time. These storms are thunderstorms that rotate.
Often, before a tornado touches down, a hail core and heavy rain pass by as a forerunner and warning. Here, the tipped up spinning cylinder forms a mesocyclone.
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