Answer:
Step-by-step explanation:
Since you have this categorized under college math, I'm going to go out on a limb here and assume you're in calculus. We will solve using the position function and its first derivative (velocity) to solve. Remember that at an object's max height, the velocity is 0.
If the position function is
[tex]s(t)=-16t^2+24t+7[/tex] the first derivative, velocity, is
v(t) = -32t + 24. Set this equal to 0 to find the time when the object is at its max height:
0 = -32t + 24 and
-24 = -32t so
t = .75 seconds. Now we can plug that time into the position function to find where it is at that time. This "where" will be the max height:
s(.75) = [tex]-16(.75)^2+24(.75)+7[/tex] so
s(.75) = 16 feet
For any number n>1, is
|(.5 +.2i)^n|
A. greater than 1?
B. less than 1?
C. equal to 1?
PLZ HELP
Answer:
B. Less than 1
Step-by-step explanation:
You could plug in values of n greater than 1 and see what happens....
Example n=2 gives |(.5+.2i)^2|
Simplifying inside gives |(.5)^2+2(.5)(.2i)+(.2i)^2|
=|.25+.2i+.04i^2|=|.25+.2i-.04|=|.21+.2i|.
Applying the absolute value part gives sqrt(.21^2+.2^2)=sqrt(.0441+.04)=sqrt(.0841)=.29
This value is less than 1.
We should also be able to do the absolute value first then the power.
|.5+.2i|=sqrt(.25+.04)=sqrt(.29)
So |.5+.2i|^2=.29 which is what we got long way around.
Anyways (sqrt(.29))^n where n is greater than 1 will result in a number greater than 0 but less than 1.
if a plane can travel 500 miles per hour with wind and 400 miles per hour against the wind find the speed of the plane with out a wind and speed of the wind.
Answer: hello there here is your answer:
Still air speed:450 mph.
Step-by-step explanation:
500-450=450-400=50 mph
Still air speed:450 mph. Wind speed:50 mph..
hope this help have a good day
On Friday Evelyn sold 9 dresses and 20 pairs of pants. On Saturday she sold twice as many dresses and 10 more pants than Friday. How many dresses did Evelyn sell on Friday and Saturday?
Answer: 27 Dresses and 50 Pants
Step-by-step explanation:
If she sold 9 pairs of pants and
9 x 2 = 18
18 + 9 = 27
20 + 10 = 30
30 + 20 = 50
Evelyn sold 9 dresses and 20 pairs of pants on Friday, and on Saturday, she sold 18 dresses and 30 pairs of pants.
Evelyn's sales of dresses and pants over two days, Friday and Saturday. We'll use some mathematical expressions and reasoning to find out how many dresses Evelyn sold on each day.
Let's start by assigning some variables to represent the number of dresses and pants Evelyn sold on Friday and Saturday. We'll use "F" for Friday and "S" for Saturday. So, let [tex]D_F[/tex] be the number of dresses sold on Friday, [tex]D_S[/tex] be the number of dresses sold on Saturday, [tex]P_F[/tex] be the number of pants sold on Friday, and [tex]P_S[/tex] be the number of pants sold on Saturday.
According to the problem, on Friday, Evelyn sold 9 dresses, which can be expressed as:
[tex]D_F[/tex] = 9
She also sold 20 pairs of pants on Friday:
[tex]P_F[/tex] = 20
Now, let's move on to Saturday's sales. It says she sold twice as many dresses as Friday, which means the number of dresses on Saturday is double that of Friday's sales:
[tex]D_S = 2 * D_F[/tex]
Additionally, she sold 10 more pairs of pants on Saturday compared to Friday:
[tex]P_S = P_F + 10[/tex]
We already know that [tex]D_F = 9[/tex], so we can find the number of dresses sold on Saturday by substituting this value into the equation for [tex]D_S[/tex]:
[tex]D_S = 2 * 9 = 18[/tex]
Next, we'll calculate the number of pants sold on Saturday using the given information. Since [tex]P_F = 20[/tex], we can find [tex]P_S[/tex]:
[tex]P_S = 20 + 10 = 30[/tex]
So, to summarize, Evelyn sold 9 dresses and 20 pairs of pants on Friday, and on Saturday, she sold 18 dresses and 30 pairs of pants.
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Not sure how to do this.
Answer:
-4 ≤ x ≤ -2, 4 ≤ x ≤ 7
Step-by-step explanation:
A function shows the relationship between two or more variables. A function is said to be constant over an interval if its output value is same for every input value within that interval.
As seen in the question, the x variable is the input while the y variable is the output. The function is constant from x = -4 to x = -2. Also, the function is constant within the interval from x = 4 to x = 7. Hence, the interval is:
-4 ≤ x ≤ -2, 4 ≤ x ≤ 7
2(-x-4)+3=-7x+5+5x
Pls help!!!!!!!!
A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points extra credit on his 4th exam and his average score is 80, what was his score on the 4th exam
=================================================
Explanation:
The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.
The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.
Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.
So we have these scores
first exam = 70second exam = 80third exam = 43fourth exam = x+5Adding up these scores and dividing by 4 will get us the average
(sum of scores)/(number of scores) = average
(70+80+43+x+5)/4 = 80
(x+198)/4 = 80
x+198 = 4*80
x+198 = 320
x = 320 - 198
x = 122
So the student got a score of x+5 = 122+5 = 127 on the fourth exam.
Using the following image, solve for x.
Answer:
please provide an image.
Please help i need answer asap
Answer:
23
Step-by-step explanation:
5. Lisa has a cubed-shaped box with a
volume of 512 cm. If Lisa fills the box
with 1-cubic centimeter blocks, how
many blocks make up each layer?
Answer:
64
Step-by-step explanation:
[tex]\sqrt[3]{512} = 8\\8x8 = 64[/tex]
When simplified (32/3125)^(2/5) is the same as 4/25 true or false?
9514 1404 393
Answer:
True
Step-by-step explanation:
Your calculator can tell you this is true. Or, you can simplify the given expression:
[tex]\left(\dfrac{32}{3125}\right)^{2/5}=\left(\dfrac{2^5}{5^5}\right)^{2/5}=\dfrac{2^2}{5^2}=\boxed{\dfrac{4}{25}}[/tex]
__
The applicable rule of exponents is (a^b)^c = a^(bc).
PLEASE HELP: A standard six-sided die is rolled.
What is the probability of rolling a number greater than 4? Express your answer as a simplified fraction or a decimal rounded to four decimal
places.
Answer in fraction form is 1/3
Answer in decimal form is 0.3333
Pick one answer only.
==========================================================
Explanation:
The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6
S = sample space
S = {1,2,3,4,5,6}
There are 6 items here. Let B = 6.
We want to roll a number greater than 4, so the event space we're after is
E = {5,6}
which consists of 2 items. Let A = 2.
The probability we want is A/B = 2/6 = 1/3 = 0.3333
So if you go with the fraction option, then you'll type in 1/3
If you go with the decimal option, then you'll type in 0.3333
Does it pay to ask for a raise? A national survey of heads of households showed the percentage of those who asked for a raise and the percentage who got one. According to the survey, of the men interviewed, 21% had asked for a raise and 60% of the men who had asked for a raise received the raise. If a man is selected at random from the survey population of men, find the following probabilities. (Enter your answers to three decimal places.)
Answer:
a) P(man asked for a raise) = 0.21.
b) P(man received raise, given he asked for one) = 0.6.
c) P(man asked for raise and received raise) = 0.126.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
21% asked for a raise, so:
P(man asked for a raise) = 0.21.
Question b:
Event A: Asked for a raise.
Event B: Received a raise:
21% had asked for a raise and 60% of the men who had asked for a raise received the raise:
This means that [tex]P(A) = 0.21, P(A \cap B) = 0.21*0.6[/tex], thus:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.21*0.6}{0.6} = 0.6[/tex]
P(man received raise, given he asked for one) = 0.6.
Question c:
[tex]P(A \cap B) = 0.21*0.6 = 0.126[/tex]
P(man asked for raise and received raise) = 0.126.
If s(x)= 2 -x^2 and f(x)=3x, which value is equivalent to (s°f)(-7)
calculate limits x>-infinity
-2x^5-3x+1
Given:
The limit problem is:
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
To find:
The value of the given limit problem.
Solution:
We have,
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]
Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].
2.According to www.city-data, the mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000. Check the three assumptions associated with the Central Limit Theorem. What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009
Answer:
0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean price for a detached house in Franklin County, OH in 2009 was $192,723. Suppose we know that the standard deviation was $42,000.
This means that [tex]\mu = 192723, \sigma = 42000[/tex]
Sample of 75:
This means that [tex]n = 75, s = \frac{42000}{\sqrt{75}}[/tex]
What is the probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009?
1 subtracted by the p-value of Z when X = 190000. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{190000 - 192723}{\frac{42000}{\sqrt{75}}}[/tex]
[tex]Z = -0.56[/tex]
[tex]Z = -0.56[/tex] has a p-value of 0.2877
1 - 0.2877 = 0.7123
0.7123 = 71.23% probability that a random sample of 75 detached houses in Franklin County had a mean price greater than $190,000 in 2009.
With the information that you gather from the summary tables, test the following (you can use excel when appropriate): Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in the United States and territories at the 0.10 level of significance. Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500 in the United States and territories at the .05 level of significance. Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance.
Answer:
Kindly check explanation
Step-by-step explanation:
A.)
H0 : μ = 5000
H0 : μ > 5000
xbar = 6671 ; s = 8185.21 ; n = 52 ; α = 0.05
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (6671 - 5000) ÷ (8185.21/√52)
T = 3.814
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at 3.814; 51 = 0.000185
Pvalue < α ; Reject H0 and conclude that average birth is greater than 5000
B)
H0 : μ = 6000
H0 : μ < 6000
xbar = 4187 ; s = 4386 ; n = 52 ; α = 0.01
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (4187 - 6000) ÷ (4386/√52)
T = - 2.981
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at - 2.981; 51 = 0.0022
Pvalue < α ; Reject H0 and conclude that average death is less than 6000
C.)
H0 : μ < 2500
H0 : μ ≥ 2500
xbar = 2744 ; s = 3134.41 ; n = 52 ; α = 0.05
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (2744 - 2500) ÷ (3134.41/√52)
T = 0.561
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at 0.561; 51 = 0.289
Pvalue > α ; Fail to Reject H0 and conclude that average marriage is not greater Tha or equal to 2500
D.)
H0 : μ = 4000
H0 : μ ≤ 4000
xbar = 1451 ; s = 1217 ; n = 52 ; α = 0.01
The test statistic :
T = (xbar - μ) ÷ (s/√(n))
T = (1451 - 4000) ÷ (1217/√52)
T = - 15.10
Pvalue from Test statistic : ; df = n - 1 = 52-1= 51
Pvalue at - 15.10; 51 = 0.000001
Pvalue < α ; Reject H0 and conclude that average divorce is less eqaul to 4000
Please answer i will give you brainlest please help me
have attached the solution, couldn't solve 13 and 17 tho, if it helps, then do mark me the brainliest...
Btw, which class r u in?
Step-by-step explanation:
For the inequality 4x2>y−3, where is the graph shaded and is the curve solid or dotted?
Answer:
Dotted Curve
Shaded Area includes the Origin.
Step-by-step explanation:
I am assuming that you mean 4x² > y-3.
Since the inequality sign is greater than, the line would be dotted. The curve would be solid if the inequality was an 'X or equal to' sign.
----------------------------------
4(0)² > 0 - 3
0 > -3
Since the given statement is true, the origin is a solution and we would shade below the curve.
----------------------------------
See the graph attached.
Hope this helps.
Question 19 of 30
An angle is formed by two rays or segments that share a(n).
A. Vertex
B. Side
Ο Ο Ο Ο
O C. Endpoint
OD. Ray
Answer:
A a vertex
Step-by-step explanation:
When rays meet they form a point is formed known as the vertex.
How to find B?
what type of angle is it?
Answer:
Obtuse angle; 57°
Step-by-step explanation:
b and 43° form a right angle. A right angle is 90°. Solution: 90°-43°=57°
43° is acute, so angle b must be obtuse.
Translate the sentence into an inequality. The product of w and 2 is less than 23.
Answer:
2w<23
Step-by-step explanation:
The product of w and 2 mean that w multiplied by 2
You have some money to invest in one of two accounts. The first account pays
5% simple interest, and the second pays 4% compound interest. How would
you decide which account to use? Discuss your answer.
Answer:
compound interest
Step-by-step explanation:
compound interest yields higher profit than simple interest
Answer:
the simple interest function will be greater in the beginning, but the
compound interest equation will overtake the simple after a while.
it appears that the 4% compound equation will overtake the simple at about 10 years
Step-by-step explanation:
[tex]1 + .05t = 1(1.04)^t[/tex]
Golf Scores In a professional golf tournament the players participate in four rounds of golf and the player with the lowest score after all four rounds is the champion. How well does a player's performance in the first round of the tournament predict the final score
Answer:
Mean scores.
Step-by-step explanation:
The golf player will score in the first round, according to these scores the golf player scores can be predicted. The golf player can perform high in first round but he may score lesser in the second round due to stress or mental pressure. The scores can be predicted taking mean of the scores and adding standard deviation to it.
Which statement is true about the equations
-3x + 4y = 12 and 1/4x-1/3y = 1
O The system of the equations has exactly one solution at (-8, 3).
O The system of the equations has exactly one solution at (-4, 3).
O The system of the equations has no solution; the two lines are parallel.
O The system of the equations has an infinite number of solutions represented by either equation.
What is the greatest common factor of 3^3 x 5^4 and 2 x 5^3 x 11?
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{3^3 \times 5^4}[/tex]
[tex]\mathsf{3^3}[/tex]
[tex]\mathsf{= 3\times3\times3}[/tex]
[tex]\mathsf{= 9\times3}[/tex]
[tex]\mathsf{= \bf 27}[/tex]
[tex]\mathsf{5^4}[/tex]
[tex]\mathsf{= 5\times 5\times5\times 5}[/tex]
[tex]\mathsf{= 25\times25}[/tex]
[tex]\mathsf{= \bf 625}[/tex]
[tex]\mathsf{27 \times625}[/tex]
[tex]\mathsf{= \bf 16,875}[/tex]
[tex]\mathsf{2\times5^3\times11}[/tex]
[tex]\mathsf{5^3}[/tex]
[tex]\mathsf{= 5\times 5\times5}[/tex]
[tex]\mathsf{= 25\times 5}[/tex]
[tex]\mathsf{\bf = 125}[/tex]
[tex]\mathsf{2\times125\times11}[/tex]
[tex]\mathsf{= 250\times11}[/tex]
[tex]\mathsf{\bf = 2,750}[/tex]
[tex]\large\textsf{Find the Greatest Common Factor (GCF) of 16,875 \& 2,750}[/tex]
[tex]\large\textsf{16,875: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 625, 675, 1,125,}\\\\\large\textsf{1,875, 3,375, 5,625, \& 16,875}[/tex]
[tex]\large\textsf{2,750: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 125, 250, 275, 550, 1,375, \& 2,750}[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: the GCF is \bf 125 }}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
What is the area of triangle ABC? - OP 03 square units 0 7 square units o 11 square units 0 15 square units see pic
Answer:
7 sq unit
Step-by-step explanation:
Area of triagle ABC = Area of rectangle mnBp - Area of trangle AmC - Are of triangle CnB - Area of triangle ABp
Area of rectangle mnBp = 5x3 = 15 sq unit
Area of trangle AmC = 4x2 /2 = 4 sq unit
Are of triangle CnB = 5x1 /2 = 2.5 sq unit
Area of triangle ABp = 3x1 /2 = 1.5 sq unit
I believe you can work out thd answer from the above
A person participates in a weekly office pool in which he has one chance in ten of winning the prize. If he participates for 5 weeks in succession, what is the probability of winning at least one prize.
The probability of winning at least one prize is 0.40951.
What is probability?Probability is the likelihood that an event will occur.
The following information can be deduced:
P = probability of winning = 1/10
q = probability of not winning = 1- (1/10) = 9/10
x = no. of winning
then, p (x ≥ 1) = 1 - p (x < 1)
= 1 - p (x=0)
= 1 - ⁵C₀ (1/10)^⁰ (9/10)^(5-0)
= 1 - (1) (1) (9/10)^5
= 1 - (9/10)^5
= 1 - 0.59049
= 0.40951
Therefore, the probability is 0.40951.
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Weatherwise magazine is published in association with the American Meteorological Society. Volume 46, Number 6 has a rating system to classify Nor'easter storms that frequently hit New England states and can cause much damage near the ocean coast. A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating.
(A) Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. What would be the null hypothesis regarding average wave height?
a) μ < 16.4.
b) μ > 16.4.
c) μ = 16.4.
d) μ ≠ 16.4.
(B) If you wanted to test the hypothesis that the storm is getting worse, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ > 16.4.
(C) If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ ≠ 16.4.
c) μ > 16.4.
d) μ = 16.4.
(D) Suppose you do not know if the storm is getting worse or dying out. You just want to test the hypothesis that the average wave height is different (either higher or lower) from the severe storm class rating. What would you use for the alternate hypothesis?
a) μ > 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ < 16.4.
(E) For each of the tests in parts (b), (c), and (d), would the area corresponding to the P-value be on the left, on the right, or on both sides of the mean?
a) left; right; both.
b) left; both; right.
c) both; left; right.
d) right; left; both.
Answer:
a) c) μ = 16.4.
b) d) μ > 16.4.
c) a) μ < 16.4.
d) c) μ ≠ 16.4.
e) d) right; left; both.
Step-by-step explanation:
Question a:
Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.
Question b:
At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.
Question c:
Dying down, so if the mean is lower than 16.4 inches, so option a.
Question d:
Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.
Question e:
Test if more -> right, so on question b) is a right tailed test.
Test if less -> left, so on question c) is a left tailed test.
Different -> both sides, so on question d) it is a two-tailed test.
Thus the correct answer is given by option d.
How do I solve this?
The answer for the first line segment : (-3,-7) (-4,0)
The answer for 2nd line segment is :(-3,8) (-9,-5)
Step-by-step explanation:
Let do line segment QR and ST. first.
Step 1: Find a line that contains a points that is perpendicular to the line of reflection
"A reflection of a pre image and new image is perpendicular to the line of reflection.
This means for points Q,S,T and R, there is a line that. contains one point that is perpendicular to the line of reflection.
A line that is perpendicular to the line of reflection is the negative reciprocal of the slope so this means all 4 lines must be on a different slopes but the slopes must be 1/2.
To simplify, things, here are the lines that will all 4 points be on
Point R will be on line y=1/2x-11/2Point Q will be on line y=1/2x+2Point S will be on line y=1/2x+19/2Point T will be on line y=1/2x-1/2Step 2: Find a point where both the line and line of reflection intersect at.
Now we need to find a line where both the line of reflections and the 4 lines will intersect at separately.
The line with Point R will intersect with the line of reflection at point (1,-5)The line with Point Q will intersect with line of reflection at Point (-2,1)The line with Point S will intersect at point (-5,7)The line worth Point T will intersect at Point(-1,-1).Step 3: Find the endpoints given the midpoint and the originally endpoint.
A reflection per and new image is equidistant from the point of reflection. So we. an say that the point where the line intersect is the midpoint of the pre and new image.
Using this info,
The endpoint for R prime is (-3, -7).The endpoint for Q prime is (-4,0). The endpoint of S prime is (-3,8).The endpoint of T prime is (-9,-5).Connect R prime and Q prime. And that the new line segments
Connects S prime and T prime and that the new line segments.
If U= {1,2,3,......8} , A={1,4,6,7} , B= {2,4,5,7} & C= {3,5,6,7} prove that 1) An( BUC ) = ( AnB) U ( AnC ). 2) AU (BnC)= (AUB) n ( AUC )
Step-by-step explanation:
BUC={2,3,4,5,6,7}
An(BUC)={4,6,7}
AnB={4,7},AnC={6,7}
(AnB)U(AnC)={4,6,7}
Au(BnC)={1,4,5,6,7}
(AUB)n(AUC)= {1,4,5,6,7}