A ball is dropped off of a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window what is the distance from the top of the building to the top of the window?

Answer:

velocity

Explanation:

because the si unit of mass is kg, velocity is m/s, acceleration is m/S2 , moment is kgm2/s . so 5 is given as velocity.

if the distance between the objects is doubled the force is reduced by a factor of 4

Gravitational force is the force of attraction between objects in the universe.

f = G * m1 * m2 / r^2

f = gravitational force

G = gravitational constant

m1 = mass of object 1

m2 = mass of object 2

r = distance between the objects

From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4

Therefore: The force decreases by a factor of 4.

hope it helps

Answer:                                                                                    

Explanation:

Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

Hi there!

We can use the following equation to solve for equivalent resistance:

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]

We can plug in the givens and solve.

[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

The volume that the gas will occupy based on the temperature given will be 0.80 liters.

From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.

Therefore, the volume will be:

= (0.20) × (2.0/0.50)

= 0.20 × 4

= 0.80

In conclusion, the volume is 0.80 liters.

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Answer:

wood lighters gasoline hope it helps

Explanation:

Answer:

1.2 is the correct answer due to the graph

Explanation:

math teacher

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[tex] \tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}[/tex]

[tex] \text{\underline\red {Horticulture}}[/tex]

The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.

[tex] \text{\underline\green{Agriculture}}[/tex]

It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.

Answer:

let alpha be y,

1/2=y(x-6)^(-b)

1/2=y(1/x-6)

1/2=y/x-6

x-6=2y

x-6/2=y

(1/2)x-(6/2)=y

y=(1/2)x-3

Answer:

A.

Explanation: both triple by 3

Answer: B

Explanation: It is because the formula for this eq is KE=V^2. In the eq, it says that the mass is triple meaning the KE also must have tripled. For the speed, since it has a formula then you just have 3^2 which is 9.

Answer:

Your answer is attached above

Hope it helps

TC

have a great time

Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

For a tire on a car is rolling smoothly and It's center of mass is moving at 18 m/s, the speed of the top of the tire is mathematically given as

Vtop=36m/s

Generally, the equation for the relationship between the top and the core is mathematically given as

Vtop=2*(vcore)

Threrefore

Vtop=2*18

Vtop=36m/s

In conclusion, the speed of the top

Vtop=36m/s

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When the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

Hooke's law states that force or load applied to elastic material is directly proportional to the extension produced in the material. This law can be written as;

F = kx

where;

The speed of the block increases with decreasing displacement of the bock. This is because the kinetic energy of the block is maximum at zero displacement and minimum at maximum displacement of the block.

Thus, when the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

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Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t    = power X time

W / t = P   power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec  = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c)  E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

Answer:

Explanation:

The hot exhaust from a rocket travels in one direction, and the rocket travels in the opposite direction. This is an example of?

A. Equal and opposite forces.

B. Friction.

C. Balanced forces.

D. Inertia.

Answer:

D. Neither the box nor people will move.

Explanation:

We are given three forces that are present on the box and friction is the result of someone trying to move the box. The net force of the people pulling/pushing is barely 50 Newtons which doesn't compare with the frictional force of 400 Newtons, you will need to surpass a net force of 400 Newtons in order for the box to START moving.

Answer:

the three gases our atmosphere is mainly composed of are nitrogen oxygen and carbon

The resulting charge in sphere A from the two given different charges is determined as +2 μC.

The resulting charge of the two spheres is determined by suming the two individual charges together as shown below;

Resulting charge = +6 μC - 2 μC

Resulting charge = +4 μC

The resulting charge will be distributed uniformly between the two spheres and charge in sphere A and B will be equal.

Charge in sphere A = charge in sphere B = ¹/₂ x +4 μC = + 2 μC

Thus, the resulting charge in sphere A from the two given different charges is determined as +2 μC.

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Answer:

Explanation:

500-0.05=499.95

500-100+5=405

100+100=10000

The statements that are true are;

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Heat capacity of body 1 :

[tex]\qquad \sf  \dashrightarrow \:m_1s_1[/tex]

Heat capacity of body 2 :

[tex]\qquad \sf  \dashrightarrow \:m_2s_2[/tex]

it's given that, the the head capacities of both the objects are equal. I.e

[tex]\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:m_1 = \dfrac{m_2s_2}{s_1} [/tex]

Now, consider specific heat of composite body be s'

According to given relation :

[tex]\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }[/tex]

[ since, [tex] m_2s_2 = m_1s_1 [/tex] ]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{ \cancel{m_2}(\frac{s_2}{s_1} + 1)}[/tex]

[tex]\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{ (\frac{s_2 + s_1}{s_1} )}[/tex]

[tex]\qquad \sf  \dashrightarrow \: s' = \dfrac{2s_1s_2}{s_1 + s_2} [/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]

When people are interested in changing their personalities, they are usually most interested in more neurotic less assertive.

Personality makes up an individual, they are the features or characteristics that forms an individual.

Each individual is made of distinctive character which makes one of different from other.

Therefore, when people are interested in changing their personalities, they are usually most interested in more neurotic less assertive

Learn more on personality here,

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By using the right-hand rule for magnetic force to determine the charge on the moving particle, it's a negative charge.

It should be noted that the magnetic force simply means the attraction or repulsion that arises between electrically charged particles.

The right-hand rule for magnetic force states that to determine the direction of the magnetic force, one should point the right thumb in the direction of the velocity.

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Answer:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

✔ 2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

✔ 0.12

N

Explanation:

Hope this helps

Answer:

how can you support to leprosy victims?

Answer: 20 m/s

Explanation:

Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s