a 28 kg student stand on the surface of the Earth. What is the magnitude of the
gravitational force of the earth on the student?

Answer:

the seed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance divided by Time

So, here speed be 515m

And, the time is 1.50 second

So, the speed of the sound is

= 515m divided by 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

Answer:

0.1m

Explanation:

k = 64N/m

Ep = 0.32J

x = ?

Ep = 1/2 * kx²

make x the subject of the formula

x² = 2Ep/k

x = √(2Ep/k)

x = √(0.64/64)

x = √0.01

x = 0.1m

Explanation:

Q = energy applied

m = mass

C = specific heat

ΔT = delta T = change in temperature

Answer:

the total flight time is 1.29 s

Explanation:

The computation of the total flight time is given below:

The initial velocity is 15 m/s = v

And, the angle from horizontal is [tex]\theta = 25\ degrees[/tex]

Now the total time is

[tex]t = \frac{2\times v\times \sin \theta }{g} \\\\= \frac{2\times 15\times sin 25^{\circ}}{9.8} \\\\= 1.29 s[/tex]

Hence, the total flight time is 1.29 s

Answer:

Explanation:

1.electric

2.radio wave

3.broadcast

Hope it helped you.

Answer:

when an acount is made online i can also give you the other awnsers

Explanation:

Answer:

Velocity

Explanation:

Since velocity is magnitude and direction, 40mph south is velocity.

Answer:

Skin damage

Explanation:

exposure can lead to sunburn, and long term exposure can lead to aged skin and much more

Answer:

from

force =mass x acceleration

mass = force/acceleration

m = f/a

m = 7.5/15

m=0.5kg

[tex]\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}[/tex]

acceleration = 1000 m/s²

force = 5000 N

Mass of the cannonball

[tex]\longrightarrow[/tex] [tex]\underline{\boxed{\sf mass = \dfrac{force}{acceleration}}}[/tex]

:[tex]\implies[/tex] [tex]\sf mass = \dfrac{5000}{1000}[/tex]

:[tex]\implies[/tex] [tex]\sf mass = 5 kg [/tex]

hence, the required answer is 5kg.

______________________________

Answer:

33.65 N

Explanation:

Force that will push them away is given from the equation;

F = Kq1•q2/r²

Where;

K is coulumbs constant = 8.99 × 10^(9) Nm²/C²

We are given;

q1 = q2 = -2 C

r = 32692 m

Thus;

F = 8.99 × 10^(9) × (-2) × (-2)/32692²

F ≈ 33.65 N

Answer:

The change in momentum of the car is 16380.8 kg.m/s

Explanation:

Given;

mass of the car, m = 1600 kg

time of motion, t = 4.20s

force of friction on the car, F = 3900 N

final velocity of the car after the brakes were applied, v = 0

The initial velocity of the car during the motion is calculated as;

[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]

The change in momentum of the car is calculated as;

ΔP = mu

ΔP = 1600 x 10.238

ΔP = 16380.8 kg.m/s

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.

Answer:

4 days

either multiply 128 by .5 until you get to 2 counting each time or use 2 formulas ln(n2/n1)=-k(t2-t1) to get k then input k into ln(2)=k*t1/2

n2 is final amount and n1 is beginning and t is either time elapsed as in the first formula or the actual half life that is t1/2

Explanation:

The half life of the sample will be "4 days".

According to the question,

Let,

→  [tex]\frac{N}{N_o} = (\frac{1}{2} )^n[/tex]

By substituting the values, we get

→  [tex]\frac{2}{128} = (\frac{1}{2} )^n[/tex]

→    [tex]\frac{1}{64} = (\frac{1}{2} )^n[/tex]

→ [tex](\frac{1}{2} )^6= (\frac{1}{2} )^n[/tex]

→     [tex]n=6[/tex]

So,

It takes 6 half life just to reduce from 128 mg - 2mg which is also "24 days".

→ [tex]6 \ half \ life = 24 \ days[/tex]

Hence,

→ [tex]Half \ life = \frac{24}{6}[/tex]

                   [tex]= 4 \ days[/tex]

Thus the answer above is right.

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Answer:

The bear is actually sharpening his claws. That's the only reason he scratches a tree with his claws

Explanation:

Answer:

Substance 1 because it became a liquid faster

Explanation:

Answer:

gravity

Explanation:

there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less

In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.

We must understand that the mass of an object may differ depending on its location on the planet. This is due to the effect of gravity on the object.

Gravity is simply defined as any force which attracts an object towards the centre of the earth.

From the question given, we are told that the weight of sugar is 10N on the earth and 4N on Mars. This difference in their mass is attributed to the effect of gravity on the object.

In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.

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Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

Answer:

the bike

Explanation:

it has less mass than the motorcycle so so it would have more acceleration

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.

Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body

An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.

An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.

The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.

The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.

Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.

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Answer:

the answer for how much work was done is 90

Work done to push a box is 150 J.

force= 30N

displacement= 5 meters.

work done= 30 * 5

               ⇒ 150 joule.

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Answer:

An atom that contains 12 protons

Explanation:

Atomic number is the same as how many protons and electrons an atom has. The mass is how many protons and neutrons there are together. In this case it would be 25 (mass) - 12 (protons) = 13 (neutrons).

Answer:

The first four resonance frequency in the string are;

1) 50·√50 Hz

2) 100·√50 Hz

3)150·√50 Hz

4) 200·√50 Hz

Explanation:

The given parameters of the string are;

The density of the string, ρ = 0.01 kg/m

The tension force on the string, T = 5 N

The length of the string, l = 0.1 m

Therefore the mass of the string, m = Length of string × Density of the string

∴ m = 0.01 kg/m × 0.1 m = 0.001 kg

The formula for the fundamental frequency, f₁, is given as follows;

[tex]f_1 = \dfrac{\sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{\sqrt{\dfrac{T}{\rho} } }{2 \cdot L}[/tex]

Where;

f₁ = The fundamental frequency in the string

T = The tension in the string = 5 N

m = The mass of the string = 0.001 kg

L = The length of the string = 0.1 m

ρ = The density of the string = 0.01 kg/m

By plugging in the values of the variables, we have;

[tex]f_1 = \dfrac{\sqrt{\dfrac{5}{0.01} } }{2 \times 0.1} = 50 \cdot \sqrt{5}[/tex]

The first four harmonics are;

f₁, 2·f₁, 3·f₁, 4·f₁

Therefore, we have the first four resonance frequency of the string are as follows;

1 × 50·√50 Hz = 50·√50 Hz

2 × 50·√50 Hz = 100·√50 Hz

3 × 50·√50 Hz = 150·√50 Hz

4 × 50·√50 Hz  = 200·√50 Hz

Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.

When static electricity is discharged, such as in a spark or a sudden discharge of stored charge, it happens in a rapid and uncontrolled manner, resulting in a brief burst of energy rather than a steady and sustained flow.

Power sources typically require a continuous and controllable flow of electrical energy to be useful for various applications. Static electricity, in its nature, does not provide this continuous flow but instead releases energy in an instantaneous manner. Therefore, it is not suitable for most practical power needs and applications.

Option A is not correct because electrons can be transferred in bursts of static electricity. Option C is not correct because static electricity is a real form of electricity, even though it has unique characteristics. Option D is not correct because static electricity can occur in various circumstances, not just in lightning.

Therefore, Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.

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Answer:

The answer is d

Explanation:

Because he is from the same species

Answer:

D

Explanation:

D) Less than 20.

Explanation:

Equivalent resistance in a parallel combination is less than their individual value.

Answer:

The net charge on each sphere is -1.5 q

Explanation:

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]

The net charge on each sphere, Q = -1.5 q.

The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again

The given parameters of the conducting spheres meant to touch are;

The net charge on the first sphere, Q₁ = +5.0 q

The net charge on the second sphere, Q₂ = -8.0 q

The net charge on each sphere after touching and then separated, 'Q', is given as follows;

[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]

Therefore, by substituting the known values of the variables, we have;

[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]

Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q

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Answer:

210N

Explanation:

According to pascal principle

Fb/Ab = Fa/Aa

Given

Fb = 16,170N

Ab = 5,005cm²

Fa = ?

Aa = 65 cm².

Fa is the force that must be exerted on piston A to lift the car

Substitute

16170/5005 = Fa/65

Cross multiply

5005Fa = 65 * 16170

5005Fa = 1,051,050

Fa = 1,051,050/5005

Fa = 210N

Hence the required force is 210N

The force which must be exerted on piston A to lift the car is equal to 210 Newton.

Given the following data:

To determine the force which must be exerted on piston A to lift the car:

Mathematically, the pressure acting on an area is given by the formula:

[tex]Pressure = \frac{Force}{Area}[/tex]

Since, the weight of the car remains constant, the pressure on piston A must be equal to the pressure on piston B.

Pressure A = Pressure B

Mathematically, this given by:

[tex]\frac{F_A}{A_A} = \frac{F_B}{A_B}[/tex]

Making [tex]F_A[/tex] the subject of formula, we have:

[tex]F_A =\frac{A_AF_B}{A_B}[/tex]

Substituting the given parameters into the formula, we have;

[tex]F_A = \frac{65 \times 16170}{5005} \\\\F_A = \frac{1,051,050}{5005}\\\\F_A = 210\;Newton[/tex]

Therefore, the force which must be exerted on piston A to lift the car is equal to 210 Newton.

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