Answer:
Q = 80000 cal
Explanation:
La expresin para el calor es
Q = m [tex]c_{e}[/tex]ce ΔT
el calor especifico del agua es ce= 1 cal/gr ºC
la temperatura de ebullición del agua es Ef = 100ºC y partimos de la temperatura ambiente To= 20 OC
Q = m 1 ( 100 – 20)
q= 80 m
en el ejercicio no se da la masa de agua, pro podemos suponer, pote lleva 1 litros = 100 G
Q = 80 1000
Q = 80000 cal
What is the main reason why would a fan be expected to warm the air that passes through it? A or B?
A. The fan does work on the air in the room leading to an increase in its thermal energy and temperature.
B.The fan transfers heat to the air in the room leading to an increase in its thermal energy and temperature.
Answer:
A. The fan does work on the air in the room leading to an increase in its thermal energy and temperature.
Explanation:
Fans move fluid, typically a gas, such as air, through a room or an enclosure. A fan consists of a rotating arrangement of vanes or blades (impeller), which acts on the air. The action of the impeller does work on the fan by compressing and moving the air forward, doing work on it in the process. The work done on the fan leads to an increase in the thermal energy of the air.
A 121-kg astronaut (including space suit) acquires a speed of 2.90 m/s by pushing off with her legs from a 1600-kg space capsule. Use the reference frame in which the capsule is at rest before the push.
A) What is the velocity of the space capsule after the push in the reference frame?
B) If the push lasts 0.660 s , what is the magnitude of the average force exerted by each on the other?
C) What is the kinetic energy of the astronaut after the push in the reference frame?
D) What is the kinetic energy of the capsule after the push in the reference frame?
Answer:
a) 0.22 m/s
b) 531.67 N
c) 508.81 J
d) 38.72 J
Explanation:
the mass of the astronaut = 121 kg
astronaut's push of speed = 2.9 m/s
mass of the space capsule = 1600 kg
a) according to the conservation of momentum, the summation of the total momentum in a system must be equal to zero.
let us take the direction of the astronaut as positive.
Astronaut's momentum p = mv
where
m is the mass
v is the velocity
momentum p = 121 x 2.9 = 350.9 kg-m/s
The space capsules momentum = mv
==> 1600 x (-v) = -1600v this is because the space capsule moves in the opposite direction to the astronaut.
according to conservation of momentum
350.9 + (-1600v) = 0
350.9 = 1600v
v = 350.9/1600 = 0.22 m/s
b) magnitude of the force F is the rate of change of momentum.
The astronaut and the space capsule both change momentum from 0 to 350.9 kg-m/s. In 0.66 seconds, the force will be
F = [tex]\frac{m(v - u)}{t}[/tex]
where
u is their initial velocity = 0 m/s
where v = 2.9
t = 0.66
substituting, we have
F = [tex]\frac{121(2.9 - 0)}{0.66}[/tex] = 350.9/0.66 = 531.67 N this same force is experienced by the space capsule
c) Kinetic energy of the astronaut = [tex]\frac{1}{2} mv^{2}[/tex]
m is the mass = 121 kg
v is the velocity = 2.9 m/s
KE = [tex]\frac{1}{2}*121*2.9^{2}[/tex] = 508.81 J
d) Kinetic energy of the space capsule = [tex]\frac{1}{2} mv^{2}[/tex]
KE = [tex]\frac{1}{2}* 1600* 0.22^{2}[/tex] = 38.72 J
Ball A is dropped from the top of a building. At the same instant ball B is thrown vertically upwards from the ground. When the balls collide, they are moving in opposite direction and the speed of A is twice the speed of B. At what fraction of the height of the building did the collision occurs ?
Answer:
y/y₀ = 1/2 + v₀²/(2 g y₀)
Explanation:
This in a kinematics exercise in a mention
ball A.
Since the ball is dropped, its velocity starts at zero, at the meeting point the equation is
[tex]v_{A}^2[/tex]= - 2 g (y₀-y)
ball B
v_{B}^2 = v₀² - 2 g y
we substitute
2v_{B}^2 = -2 g (y₀ -y)
v_{B}^2 = - g y₀ + 2g y
v_{B}^2 = v₀² - 2gy
we have a system of two equations with two unknowns, therefore it can be solved. Let's multiply-by -1 and add
0 = g y₀ + v₀² -2gy
we clear the height
y = (g yo + v₀²) / 2g
y = yo / 2 + v₀² / 2g
In this exercise we assume that the height of the building is known and the initial velocity of ball B
The fraction is
y/yo = 1/2 + v₀²/(2gyo)
When submerged in water, the brick appears to have an additional force pushing it ___upward ___downward. This additional force is the buoyant force (B).
Answer:
Therefore, the brick appears to have an additional force pushing it upward.
Explanation:
When a brick is submerged in the water, it has two forces acting upon it. One force is the gravitational force or the weight of the brick, that acts downward. The weight force also acts on the brick when it is not in water. But, in water an additional force acts on the brick. This additional force is named as Buoyant Force. This force is equal to the weight of the water displaced by the brick. And this Buoyant Force acts on the brick in the upward direction. The formula for this force is given as follows:
Buoyant Force = (Density of Water)(Volume of Water Displaced)(g)
Therefore, the brick appears to have an additional force pushing it upward.
Which of the following is not a factor in whether a reaction will spontaneously occur? A. Entropy change of the system B. Enthalpy change of the system C. Temperature of the system D. Pressure change of the system
Answer:
D
Explanation:
pressure change have nothing to do with the spontaneity.
Entropy change , enthalpy change , temperature have roles in deciding spontaneity.
A student attaches a length of nylon fishing line to a fence post. She stretches it out and shakes the end of the rope in her hand back and forth to produce waves on the line. The most efficient way for her to increase the wavelength is to
Answer:
increase the tension on the hose and shake the end fewer times per second.
Explanation:
This is because Tension of the rope is directly proportional to wavelength and inversely proportional to the frequency ( shakes per second) so increasing tension increases wavelength and vice versa
Wavelength= Tension/ frequency
The most efficient way for her to increase the wavelength is to increase the rate of shaking the rope per second.
What is wavelength?Wavelength measures the distance of wave that occur between one crest and another crest.
To increase the wavelength the rope end should be shaked in a number of time per second this will help build up tension in the rope.
Therefore, she should increase the rate of shaking the rope per second.
Learn more on wavelength here,
https://brainly.com/question/10750459
According to the chart, one gram of copper and
gram(s) of gold
would change their temperatures by approximately the same amount by
adding heat to them.
A) one
B) two
C) three
D) four
Answer:
C) three
Explanation:
Let gram of gold required be m . Let temperature change in both be Δ t .
heat absorbed = mass x specific heat x change in temperature
for copper
heat absorbed = 1 x .385 x Δt
for gold
heat absorbed = m x .129 x Δt
So
m x .129 x Δt = 1 x .385 x Δt
m = 2.98
= 3 g approximately .
Silver has a work function of 4.5 eV . Part A What is the longest wavelength of light that will release an electron from a silver surface
Answer:
λ = 2.7608 x 10⁻⁷ m = 276.08 nm
Explanation:
The work function of a metallic surface is the minimum amount of photon energy required to release the photo-electrons from the surface of metal. The work function is given by the following formula:
Work Function = hc/λ
where,
Work Function = (4.5 eV)(1.6 x 10⁻¹⁹ J/1 eV) = 7.2 x 10⁻¹⁹ J
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = longest wavelength capable of releasing electron.
Therefore,
7.2 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ
λ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(7.2 x 10⁻¹⁹ J)
λ = 2.7608 x 10⁻⁷ m = 276.08 nm
You toss a ball straight up in the air. Immediately after you let go of it, what force or forces are acting on the ball
Answer and Explanation: When tossing a ball up in the air, the forces acting on the ball are due to Gravity, which is defined by gravitational acceleration on that location on Earth (approximately 9.8 m/s²) multiplied by mass of the ball; Force of thrown, i.e., the force you threw the ball and air resistance force, which is proportional to the square of the ball's through the air and the ball's cross section area. To facilite calculations, air resistance force is normally ignored.
Answer:
weight and drag
Explanation:
A toy of mass 0.190-kg is undergoing SHM on the end of a horizontal spring with force constant k = 350 N/m . When the toy is a distance 0.0140 m from its equilibrium position, it is observed to have a speed of 0.400 m/s .
A) What is the toy's total energy at any point of its motion?
B) What is the toy's amplitude of the motion?
C) What is the toy's maximum speed during its motion?
Answer
a)0.0495 J
b)0.01681 m
c)0.7218 m/s
Explanation:
Given
Mass of the.toy M = 0.190 kg
force constant k = 350 N/m
Displacement from equilibrium x = 0.0140 m
Speed v = 0.400 m/s
a)What is the toy's total energy at any point of its motion?
The total energy at any point of it's motion can be calculated by adding together both the potential and kinetic energy of the toy, since it's posses potential energy when at rest and kinetic energy at motion
Total energy E = kinetic energy + potential energy
E = ¹/₂mv² + ¹/₂kx²
E = ¹/₂ (0.190)(0.4)² + ¹/₂ (350)(0.0140)²
E = 0.0495 J
Hence,the total energy is 0.0495 J
b) the amplitude of the motion can be calculated using below formula
Let amplitude = A
E = ¹/₂KA²
if we make Amplitude A the subject of the formula we have
A=√(2E/k)
But we have calculated our E up there, our K was given in question then if we substitute we have
A= √(2×0.0495)/350
Ans: 0.01681 m
Hence, our Amplitude is 0.01681 m
c) the the toy's maximum speed during its motion can be calculated using the expression below
Let maximum speed = vmax
E = (1/2)M * vmax^2
If we make vmax the subject of the formula we have
vmax =√(2E/m)
vmax= √(2×0.0495)/0.190
vmax=0.7218 m/s
Hence our vmax is 0.7218 m/s
Cassidy walks 1 mile then turns 90 degrees and walks 2 miles Distance:Displacement:
Explanation:
The total displacement is 3 miles
What is displacement?
Simply put it is the sum total of the changes in position of an object from it initial position to it final position, It is a vector quantity and has a direction and magnitude.
In our example the displacement the total points of movement can be annotated as
From A to B to C
From A to B= 1 mile
From B to C= 1 miles
Displacement is 1 + 2= 3 miles
Friction: During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the puck and the ice
Answer:
The value is [tex]\mu_k = 0.102 0[/tex]
Explanation:
From the question we are told that
The initial speed is [tex]u = 10 \ m/s[/tex]
The distance traveled is [tex]d = 50 \ m[/tex]
Generally we can obtain the acceleration using the kinetic equation as follows
[tex]v^2 = u^2 + 2as[/tex]
=> [tex]a = \frac{v^2 - u^2 }{ 2s}[/tex]
=> [tex]a = \frac{0^2 - 10^2 }{ 2 * 50 }[/tex]
=> [tex]a = -1 m/s^2[/tex]
The negative sign shows that the pluck is decelerating
The force driving the pluck is mathematically evaluated as
[tex]F = ma[/tex]
This force is also equivalent to the frictional force acting on the pluck
So
[tex]ma = m * g* \mu_k[/tex]
=> [tex]\mu_k = \frac{a}{g}[/tex]
=> [tex]\mu_k = \frac{1}{9.8 }[/tex]
=> [tex]\mu_k = 0.102 0[/tex]
In coming to a stop, a car leaves skid marks 80 m long on the highway. Assuming a deceleration of 3.5 m/s2 , estimate the speed of the car just before braking.
Answer:
The speed of the car just before braking is 23.66 m/s.
Explanation:
Given;
mark of the skid, d = 80 m
deceleration of the car, a = 3.5 m/s²
To determine the speed of the car just before braking, we apply the following kinematic equation;
[tex]v^2 = u^2 + 2ad\\\\v^2 = 0 + 2(3.5)(80)\\\\v^2 = 560\\\\v= \sqrt{560}\\\\v = 23.66 \ m/s[/tex]
Therefore, the speed of the car just before braking is 23.66 m/s.
The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the −32 2 function h(x) = (80)2 x + x where x is the horizontal distance traveled and h(x) is the height in feet. Use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Answer:
The height of the object is 50 feet
Explanation:
Given that:
The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the function [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]
where;
x is the horizontal distance traveled and h(x) is the height in feet.
The objective is to use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Before then;
If the function [tex]h (x) =\dfrac{-32}{(80)^2}x^2+x[/tex]
and x = 100
then :
[tex]h (x) =\dfrac{-32}{(80)^2}(100)^2+100[/tex]
[tex]h (x) =\dfrac{-32}{6400} \times 10000+100[/tex]
[tex]h (x) =- 0.005 \times 10000+100[/tex]
[tex]h (x) =- 50+100[/tex]
h(x) = 50 feet
Using the TRACE CALCULATOR,
In your Trace calculator;
input Y = X - 32 X^2/(80) this because in the calculator Y denotes h(x)
Now over to the WINDOW
set the window as follows:
Xmin = 0
Xmax = 200
Xsc1 =1
Ymin = 0
Ymax = 50
Ysc = 1
Xres = 1
After that, click on the graph key and an output will display as seen in the image below.
Therefore, the show the value of Y which we earlier said it denotes the h(x) = 50 feet
When an auditorium has a solid wall, sound waves will tend to perfectly reflect off the wall (i.e. with a 180o phase change). If listening to music, as from an orchestra, the incoming and reflected waves will interfere with each other. For a listener sitting 0.5 m from the wall, what is the lowest frequency which gets suppressed by this interference
This question is incomplete, the complete question is;
When an auditorium has a solid wall, sound waves will tend to perfectly reflect off the wall (i.e. with a 180o phase change). If listening to music, as from an orchestra, the incoming and reflected waves will interfere with each other. For a listener sitting 0.5 m from the wall, what is the lowest frequency which gets suppressed by this interference? Use vsound=330 m/s.
Answer: f = 165 Hz
the lowest frequency which gets suppressed by this interference is 165 Hz
Explanation:
For a reflected wave (out of phase), the path difference between the incoming and reflected wave should be equal to the half integral multiple of wavelength.
r₂ - r₁ = ( m + 1/2) λ/2
r₂ is the distance from the source to observer via reflection
r₁ is distance from source to observer
here r₂ would travel an additional distance of 0.5 m due to reflection that straight approaching wave.
Therefor to have minimum/lowest possible frequency, we say m = 0
we substitute
0.5 = ( 0 + 1/2 ) λ/2
λ = 2m
The frequency would be
f = Vsound / λ
f = 330 / 2
f = 165 Hz
Therefore the lowest frequency which gets suppressed by this interference is 165 Hz
Select the correct answer.
Based on the law of conservation of energy, which statement is false?
O A. Energy is lost when machines don't work right.
OB.
We can't add more energy to the universe.
Ос.
We can't destroy energy that exists in the universe.
OD. Energy changes from one form to another.
Answer:A is the correct answer
Explanation:
A medicine ball has a mass of 6 kg and is thrown with a speed of 4 m/s. What is its kinetic energy?
(24 j ) (48 J )(96 j )( 12j )
none of these
Answer:
[tex] \boxed{\sf Kinetic \ energy \ (KE) = 48 \ J} [/tex]
Given:
Mass (m) = 6 kg
Speed (v) = 4 m/s
To Find:
Kinetic energy (KE)
Explanation:
Formula:
[tex] \boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}[/tex]
Substituting values of m & v in the equation:
[tex] \sf \implies KE = \frac{1}{2} \times 6 \times {4}^{2} [/tex]
[tex] \sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3 \times 16[/tex]
[tex] \sf \implies KE =3 \times 16[/tex]
[tex] \sf \implies KE = 48 \: J[/tex]
A cylinder contains 3.5 L of oxygen at 350 K and 2.7 atm . The gas is heated, causing a piston in the cylinder to move outward. The heating causes the temperature to rise to 620 K and the volume of the cylinder to increase to 9.1 L.What is the gas pressure? P= _____atm
Answer:
The pressure is [tex]P_2 = 1.84 \ a.t.m[/tex]
Explanation:
From the question we are told that
The first volume of is [tex]v_1 = 3.5 \ L[/tex]
The first pressure is [tex]P_1 = 2.7 \ a.t.m[/tex]
The first temperature is [tex]T_1 = 350 \ K[/tex]
The new temperature is [tex]T_2 = 620 \ K[/tex]
The new volume is [tex]V_2 = 9.1 \ a.t.m[/tex]
Generally according to the combined gas law we have that
[tex]\frac{P_1 V_1 }{T_1 } = \frac{P_2 V_2 }{T_2 }[/tex]
=> [tex]P_2 = \frac{P_1 * V_1 * T_2 }{T_1 * V_2 }[/tex]
=> [tex]P_2 = \frac{ 2.7 * 3.5 * 620 }{ 350 * 9.1 }[/tex]
=> [tex]P_2 = 1.84 \ a.t.m[/tex]
What is the magnitude of the momentum of a 33 g sparrow flying with a speed of 8.7 m/s?
Answer:
0.2871 kg m/s
Explanation:
p = mv
convert 33g into kg (0.033)
mulitply byt 8.7 to get 0.2871
Find the minimum value of n in the Balmer series for which the predicted wavelength is in the ultraviolet region of the spectrum. View Available Hint(s)
Answer:
λ =365.4 nm
Explanation:
Boh's atomic model of the Hydrogen atom the energy of each level is
Eₙ = - 13.606 / n²
where the synergy is in electonvotes and the value of E₀ = 13.606 eV is the energy of the base state of hydrogen.
An atomic transition occurs when an electron goes from an excited state and joins everything of lower energy.
ED = 13.606 (1 / n₀² - 1 /[tex]n_{f}^{2}[/tex])
we are going to apply this relationship to answer slash.
At the beginning of the studies of atomic transitions, each group did not consider having a different name
name Initial state
Lymman 1
Balmer 2
the final state is any other state sta the continuum that corresponds to n = inf
Let's look for the highest energy of the Balmer series
ΔE = 13.606 (1/2² - 1 /∞)
ΔE = 3.4015 eV
Let's use the Planck relation for the energy
E = h f = h c /λ
λ = h c / E
Let's reduce the energy to J
E = 3.4015 eV (1.6 10⁻¹⁹ J / 1 eV) = 5.4424 10⁻¹⁹
λ = 6.63 10⁻³⁴ 3 10⁸ / 5.4424 10⁻¹⁹
λ = 3.654 10⁻⁷ m
λ = 3,654 10⁻⁷ m (10⁹ nm / 1m)
λ =365.4 nm
this eta radiation in the ultraviolet range
The following represents a mass attached to a spring oscillating in simple harmonic motion. X(t) = 4.0 cos(3.0t +0.10) units of meters, radians and seconds
a. What is the amplitude? (1)
b. What is the angular frequency? (1)
c. What is the frequency? (2)
d. What is the period? (2)
e. What is the phase constant? (1)
f. What is the maximum speed? (2)
g. If the mass m= 1.2 kg, what is the spring constant? (2)
h. If the mass m= 1.2 kg, what is the total energy of the oscillator? (3)
i. What is the potential energy of the oscillator at t=0 s? (3)
j. What is the kinetic energy of the oscillator at t=0 s? (3)
Answer:
a) A = 4.0 m , b) w = 3.0 rad / s , c) f = 0.477 Hz , d) T = 20.94 s
Explanation:
The equation that describes the oscillatory motion is
x = A cos (wt + fi)
In the exercise we are told that the expression is
x = 4.0 cos (3.0 t + 0.10)
let's answer the different questions
a) the amplitude is
A = 4.0 m
b) the frequency or angular velocity
w = 3.0 rad / s
c) angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 3 / 2π
f = 0.477 Hz
d) the period
frequency and period are related
T = 1 / f
T = 1 / 0.477
T = 20.94 s
e) the phase constant
Ф = 0.10 rad
f) velocity is defined by
v = dx / dt
v = - A w sin (wt + Ф)
speed is maximum when sine is + -1
v = A w
v = 4 3
v = 12 m / s
g) the angular velocity is
w² = k / m
k = m w²
k = 1.2 3²
k = 10.8 N / m
h) the total energy of the oscillator is
Em = ½ k A²
Em = ½ 10.8 4²
Em = 43.2 J
i) the potential energy is
Ke = ½ k x²
for t = 0 x = 4 cos (0 + 0.1)
x = 3.98 m
j) kinetic energy
K = ½ m v²
for t = 00.1 ²
v = A w sin 0.10
v = 4 3 sin 0.10
v = 1.98 m / s
In a photoelectric experiment, a metal is irradiated with light of energy 3.56 eV. If a stopping potential of 1.10 V is required, what is the work function of the metal?
Answer:
The work function is [tex]\phi = 2.46 \ eV[/tex]
Explanation:
From the question we are told that
The light energy is [tex]E = 3.56 eV[/tex]
The stopping voltage is [tex]V = 1.10 \ V[/tex]
Generally work function is mathematically represented as
[tex]\phi = E - KE[/tex]
Where KE is the kinetic energy of the ejected electron and it is mathematically represented as
[tex]KE = V * e[/tex]
Where e is the charge on the electron
So
[tex]KE = 1.10eV[/tex]
Thus
[tex]\phi = 3.56eV - 1.10 eV[/tex]
=> [tex]\phi = 2.46 \ eV[/tex]
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. Let's say we now have
3C+4D=5
2C+5D=2
None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. Which of the following expressions would result from that process?
C= 53−43D
C= 1−52D
D= 25−25C
D= 54−34C
SubmitMy AnswersGive Up
Correct
Part E - Solving for Two Variables
Now that you have one of the two variables in Part D isolated, use substitution to solve for the two variables. You may want to review the Multiplication and Division of Fractions and Simplifying an Expression Primers.
Enter the answer as two numbers (either fraction or decimal), separated by a comma, with C first.
Need the answer with work shown for Part E.
Answer:
Explanation:
Given the simultaneous equation,
3C+4D=5 .............. 1
2C+5D=2 ............... 2
Solving for the value of C and D using substitution method.
From equation 1;
3C = 5-4D
Divide both sides by 3
3C/3 = (5-4D)/3
C = (5-4D)/3 .... 3
From equation 2:
2C+5D=2
5D = 2-2C
Divide both sides by 5;
5D/5 = 2-2C/5
D = (2-2C)/5 ..... 4
Substitute equation 4 into 3;
C = 5-4{(2-2C)/5}/3
C = [5 - (8-8C/5)]/3
C = [25-(8-8C)/5]/3
C = (17+8C)/15
15C = 17+8C
15C-8C = 17
7C = 17
C = 17/7
Substitute C = 17/7 into equation 4 to get the value of D
D = (2-2(17/7))/5
D = (2-34/7)/5
D = 14-34/35
D = -20/35
D = -4/7
Hence the value of C = 17/7, D = -4/7
A horizontal rope is tied to a 55.0 kg box on frictionless ice. What is the tension in the rope if: The box is at rest
Answer:
T = 0
Explanation:
Given that,
Mass of the box, m = 55 kg
We need to find the tension in the rope if the box is at rest. When the object is at rest, its acceleration is equal to 0. It would mean that the net force equals 0. So, the tension in the rope is equal to 0.
A 1.10kg block is attached to a spring with spring constant 18 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 40cm/s .What is the block's speed at the point where x = 0.45 A?
Answer:
The velocity is [tex]v_x = 0.356 \ m/s[/tex]
Explanation:
From the question we are told that
The mass is [tex]m = 1.10 \ kg[/tex]
The spring constant is [tex]k = 18 \ N/m[/tex]
The speed is [tex]v = 40 \ cm / s = 0.4 m/s[/tex]
The position considered is x = 0.45 A
Here A is the amplitude which is mathematically represented as
[tex]A = v * \sqrt{\frac{m}{k} }[/tex]
=> [tex]A = 0.4 * \sqrt{\frac{1.10}{18 } }[/tex]
=> [tex]A = 0.0989 \ m[/tex]
So [tex]x = 0.45 * 0.0989[/tex]
=> [tex]x = 0.045 \ m[/tex]
Generally the speed at x is mathematically represented as
[tex]v_x = \sqrt{ \frac{k}{m} * [A^2 - x^2 ]}[/tex]
=> [tex]v_x = \sqrt{ \frac{18}{ 1.10} * [0.0989^2 - 0.045^2 ]}[/tex]
=> [tex]v_x = 0.356 \ m/s[/tex]
A toy car travels at 5.3 m/s. The car travels a distance of 17.8 m. How long did it
take to travel that distance?
Explanation:
Assuming constant speed:
Distance = speed × time
17.8 m = (5.3 m/s) t
t = 3.36 s
How does the energy stored in an isolated capacitor change if the potential difference is increased by a factor of six
Answer:
Energy will be reduced by 0.3
Explanation:
Given that E = 1/2 QV
So if V is increased by 6
=> V = E/ 3Q
So the energy will be divided by a factor 1/3 of be reduced by 0.3
A gas is compressed by an isothermal process that decreases its volume by a factor of 2. In this process, the pressure:________
a. Does not change
b. Increases by a factor of less than 2.
c. Increases by a factor of 2.
d. Increases by a factor of more than 2.
Answer:
In this process, the pressure increases by a factor of 2.
Explanation:
For an isothermal process, the temperature remains constant throughout the process.
Also, PV = constant
It means that there is an inverse relationship between pressure and volume of the gas.
If the volume is decreased by a factor of 2, the pressure increases by a factor of 2. Hence, the correct option is (c).
3.60×10^23 nitrogen molecules collide with a 16.0 cm^2 wall each second. Assume that the molecules all travel with a speed of 450 m/s and strike the wall head on. What is the pressure on the wall?
Answer:
The pressure on the wall is 9416.25 N/m²
Explanation:
Please see the attachments below
How is the work done to hoist the counterweight related to the potential energy of the counterweight at its specified height?
Answer:
The work done to lift the counterweight equals the potential energy acquired
Explanation:
since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy