Answer:
Odour is intensive
Explanation:
intensive properties are Independent of the amount of matter
Draw the Lewis structure for H2O. How many lone pairs of electrons are there in the central atom?
Answer:
2 lone pairs of electrons
Explanation:
In this case, the central atom is oxygen. If we check the periodic table we will have an atomic number of 8. So, the electronic configuration would be:
[tex]1s^2~2s^2~2p^4[/tex]
We have 6 electrons in the last level. Therefore, we have 6 valence electrons. For the hydrogens, we will have only 1 electron each. So, in total, we have 8 electrons.
With this in mind, we have to draw two lone pairs in the oxygen and 1 bond with each hydrogen.
See figure 1.
I hope it helps!
What is the definition of weight
Answer:
Weight is a noun that means a human body's mass.
For example: Joh is 168 pounds.
This is the correct definition of weight.
Here to help!
Balanced chemical equations show:
the reactants entering the reaction
the products formed by the reaction
the ratios of moles needed to balance the reactants and products
all of the above
the products formed from the reaction
all of the above
Which one is most
stable.
A) primary alcohol.
B) secondary alcohol.
C) teritary alcohal.
Answer:
C
Explanation:
Tertiary alcohol should be the answer.
This is because tertiary alcohol has a less polar compound which means it is less likely to have chemical reaction with other compounds whereas primary and secondary alcohol has a higher chance of having chemical reaction with other compounds.
Answer:
I think the answer is A
Explanation:
primary alcohol has only one methyl group bonded to the central carbon atom, and the extent of decrease in partial posative charge is less, making it more prone to attack by nucleophiles. thus tertiary alcohols are more stable than primary alcohols
PLEASE HELP WILL GIVE BRAINLIEST!!!!
Xenon-133 has a half life of 5.2 days. A 237 gram sample of Xenon is collected and stored. It is later measured to be 29.625 grams. How long has it been in storage?
A. 15.6 days
B. 39.9 days
C. 20.8 days
D. 8 days
Answer:
A. 15.6 days
Explanation:
We have a general formula used to solve for questions dealing with half life.
N(t) = No (1/2)^t/t½
Where
N(t) = Quantity of sample left after t days
No = Initial amount of sample
t½ = Half life of sample
t = Duration or time required for sample to decay
In the above question, we are asked to determine how long(time) that the sample has been in storage.
The formula for time (t) has been derived as:
t =[ t½ × In(Nt/No)] ÷ - In 2
Where
No = 237 grams
N(t) = 29.625 grams
t½ = 5.2 days
t = ????? Unknown
t = [ t½ × In(Nt/No)] ÷ - In 2
t = [ 5.2 × In(29.625/237)] ÷ - In 2
t = [5.2 × -2.0794415417] ÷ - In 2
t = -10.813096017 ÷ - ln 2
t = 15.6 days
Therefore, the sample has been in storage for 15.6 days.
Write the molecular balanced chemical equation and the net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
Answer:
1. Balanced Molecular equation
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
2. Net ionic equation
OH-(aq) + H+(aq) —> H2O(l)
Explanation:
1. Molecular balance equation for the reaction between Ca(OH)2(aq) and HCl(aq).
This is illustrated below:
Ca(OH)2(aq) + HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by putting 2 in front of H2O as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
Therefore the equation above is balanced.
2. Net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
In solution, Ca(OH)2(aq) and HCl(aq) will dissociate as follow:
Ca(OH)2(aq) —> Ca2+(aq) + 2OH-(aq)
HCl(aq) —> H+(aq) + Cl-(aq)
Ca(OH)2(aq) + 2HCl(aq) —>
Ca2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) —> Ca2+(aq) + 2Cl-(aq) + 2H2O(l)
Cancel out the spectator ions i.e Ca2+ and Cl- to obtain the net ionic equation
2OH-(aq) + 2H+(aq) —> 2H2O(l)
OH-(aq) + H+(aq) —> H2O(l)
An unknown gas diffusion 0.25 times as fast as he .what is the molecules mass of the unknown gas
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Explanation:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
how many hydrogen atom are there in 5 moles of methyl alcohol
Answer:
20 hydrogen atoms in 5 moles of methyl alcohol.
Explanation:
Hi!
So, there are 4 hydrogen atoms in 1 mole of methyl alcohol. If you multiply 4*5, it equals to 20.
Have a great day!
How many TOTAL ions would be produced as aqueous species in the water solvent if four molecules of aluminum perchlorate dissolved? The answer is _____ total ions
Answer:
the total I think would be 35
Match.
The expression of concentration that provides the moles of solute per kilograms of solvent is _______.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution,the_______ is water.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the ________is sodium chloride.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the ________of sodium chloride would be 0.25.
A way to express concentration that provides the moles of solute per liter of solution is _______-.
Solvent
Mole fraction
solute
pH
Molarity
Molality
Answer:
Molality, Solvent, Solute, Mole fraction, Molarity.
Explanation:
The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.
A way to express concentration that provides the moles of solute per liter of solution is Molarity.
5
Select the correct answer.
Which of the following is a physical model of the Sun?
A.
an equation that describes the Sun's motion
B.
a chart that lists the temperatures of different parts of the Sun
O c.
a computer program that shows how the Sun changes over time
OD
a paragraph that describes the Sun's structure
O E.
a small yellow ball that represents the Sun
Reset
Next
Answer:
E. a small yellow ball that represents the Sun
Explanation:
key word on the question, 'physical'
Need help I need a short imaginary science lab story where several safety rules were ignored by students and things went wrong include at least 4 safety rules that were ignored.
Arrange the following substances in the order of increasing entropy at 25°C.
a. HF(g)
b. NaF(s)
c. SiF 4(g)
d. SiH 4(g)
e. Al(s)
Answer:
In solving this question it is important to note that entropy is referred to as the degree of randomness in a compound or system.
Entropy is highest in gas and lowest in solids
The order is given as:
Gas > Liquid > Solid
Another criteria is the more the elements in a compound, the more the entropy.
For example: KO3 has more entropy than KO2 due to the presence of more elements.
The last criteria is calculating their masses , the one with a greater mass has the higher entropy.
The option with the least entropy will be a solid. Al(s) and NaF(s) are both solids. NaF(s) has more elements in a compound which makes it have a higher entropy than Al(s). This means NaF(s) > Al(s).
The next to consider are the gaseous compounds which are HF(g) , SiF4(g) and SiH4(g). The least entropy will be HF(g) . This is because it has the least number of elements of the 3 compounds.
SiF4(g) and SiH4(g) have equal number of elements in a compound but the one with the highest mass is SiF4(g) because fluorine has a higher mass when compared to hydrogen. This means the compound with the highest entropy is SiF4(g).
The order of increasing entropy is given below:
Al(s) < NaF(s) < HF(g) < SiH4(g) < SiF4(g)
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
The chemical reaction that causes aluminum to corrode in air is given by
4Al+3O2?2Al2O3
in which at 298 K
?Hrxn? = ?3352 kJ
?Srxn = ?625.1 J/K
What is the standard Gibbs free energy for this reaction? Assume the commonly used standard reference temperature of 298 K?
What is the Gibbs free energy for this reaction at 5975K ? Assume that ?H and ?S do not change with temperature.
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K
Standard Gibb's free energy at 298 & 5975K is 3.16×10⁶J and -3.83×10⁵J respectively, and temperature at equilibrium state is 5362.3 K.
How do we calculate standard Gibb's free energy?Standard Gibb's free energy of any reaction will be calculated as:
∆G° = ∆H° - T∆S°, where
∆G° = change in free energy = to find?
∆H° = change in enthalpy = 3352 kJ = 3,352 × 10³J
∆S° = change in entropy = 625.1 J/K
T = absolute temperature = 298 K
On putting all these values on the above equation, we get
∆G° = (3,352 × 10³) - (298 × 625.1) = 3.16 × 10⁶J
Gibb's free energy at 5,975 K temperature:
∆G° = (3,352 × 10³) - (5,975 × 625.1) = -3.83 × 10⁵J
At the equilibrium state value of Gibb's free energy is zero, so from the equation and given data we can calculate the value of temperature as:
0 = (3352 × 10³)J - (T × 625.1 J/K) = 5362.3 K
Hence required values are 3.16 × 10⁶J, -3.83 × 10⁵J and 5362.3 K.
To know more about Gibb's free energy, visit the below link:
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The melting point of water is 0°C at 1 atm pressure because under these conditions:
A. ΔS for the process H2O(s) → H2O(l) is positive.
B. ΔS and ΔSsurr for the process H2O(s) → H2O(l) are both positive.
C. ΔS and ΔSsurr for the process H2O(s) → H2O(l) are equal in magnitude and opposite in sign.
D. ΔG is positive for the process H2O(s) → H2O(l).
E. None of these is correct.
Answer:
The correct answer is option C, that is, ΔS and ΔSsurr for the process H2O (s) ⇒ H2O(l) are equal in magnitude and opposite in sign.
Explanation:
The temperature at which solid state of water get transformed into liquid state is termed as the melting point of 0 °C. It can be shown by the reaction:
H2O (s) ⇒ H2O (l)
The degree of randomness of a molecule is known as entropy. With the transformation of ice into liquid state, there is an increase in randomness. Thus, the value of entropy becomes positive as shown:
Entropy change (ΔSsys) = ΔSproduct - ΔSreactant
= (69.9 - 47.89) J mol/K
= 22.0 J mol/K
Therefore, the value of entropy change is positive.
Now the value of entropy for surrounding ΔSsurr will be,
ΔSsurr = -ΔHfusion/T
= -6012 j/mol/273
= -22.0 J/molK
Hence, the value of ΔSsurr and ΔSsys exhibit same magnitude with opposite sign.
Which of the following gases will escape through a hole in a balloon at the highest rate? Kr NO Ar N2O
Answer:
NO.
Explanation:
The rate of diffusion of gases is inversely proportional to the square root of its density as explained by Graham's law of diffusion i.e
Rate (R) & 1/√(density (d))
R & 1/√d
But the density of a gas is proportional to the molar mass (M) of the gas.
Thus, the above equation can written as:
R & 1/√d
R & 1/√M
This implies that rate is inversely proportional to the molar mass of a gas i.e the lighter the gas, the faster the rate and the heavier the gas, the slower the rate of diffusion.
Now, to obtain the answer to the question, let us determine the molar mass of each gas.
This is illustrated below:
Molar mass of Kr = 84 g/mol
Molar mass of NO = 14 + 16 = 30 g/mol
Molar mass of Ar = 40 g/mol
Molar mass of N2O = (14x2) + 16 = 44 g/mol
Summary
Gas >>>>>>> Molar mass
Kr >>>>>>>>> 84 g/mol
NO >>>>>>>> 30 g/mol
Ar >>>>>>>>> 40 g/mol
N2O >>>>>>> 44 g/mol
From the above table, we can see the lightest gas is NO.
Therefore, NO will escape through the hole in the balloon at the highest rate.
Give the effect on the melting point of the presence of a cis double bond in a fatty acid.
Answer:
The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.
Explanation:
Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.
At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.
In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.
If you are not sure about what to do during a lab activity, what should you do?
Ask someone else at your table.
Use your best judgement.
Watch to see what everyone else isdoing.
Ask the teacher.
Answer:
ask a teacher is the correct answer.
Explanation:
You must ALWAYS ask a teacher if you are not sure about what to do during a lab activity.
Answer:
It's important to ask the teacher, lab safety policies all state that if you're confused about instructions it's always good to ask the teacher to clarify them.
Benzene exists as a resonance hybrid and its bonds exhibit characteristics that are halfway between single and double bonds. Resonance hybrids are best defined as
Answer:
Explanation:
We can only talk about resonance hybrid for a compound in which more than one structure is possible based on its observed chemical properties.
There are compounds whose chemical properties can not be satisfactorily explained on the basis of a single chemical structure. In the case of such compounds, we invoke the idea of resonance.
A resonance hybrid is a single structure drawn to represent a given chemical specie which exhibits resonance behaviour and can otherwise be represented on paper in the form of an average of two or more chemical structures separated each from the next by a double-headed arrow.
Answer:
Resonance hybrids are best defined as a molecule's electron pattern cannot be described by a single structure.
Explanation:
its right
Part D There is a structure for CH2CHCHCH2CHCH3 with a double bond between the first (from left to right) and the second carbons and a chlorine atom attached to the third and the fifth carbon. Spell out the full name of the compound.
Answer:
3,5-dichlorohex-1-ene
Explanation:
The compound is; H2C=CH-C(Cl)H-CH2-C(Cl)H-CH3. We can rightly call this compound by the name, 3,5-dichlorohex-1-ene.
We arrived at this name by first counting the longest parent carbon chain, that gives hexane. The compound has a double bond at the 1-position. Also, there are two substituent chlorine atoms at positions 3 and 5 in the structure, hence the name given.
Sodium hydroxide is a strong base. What is the pH in a 0.01 mol/dm3
solution?
a. pH=2
b. pH=12
c. pH=-2
d. pH=0.01 mol/dm3
Answer:
b. pH=12
Explanation:
Step 1: Given data
Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M
Step 2: Write the reaction for the dissociation of NaOH
NaOH is a strong base that dissociates according to the following equation.
NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)
The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.
Step 3: Calculate the pOH
pOH = -log [OH⁻] = -log 0.01 = 2
Step 4: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -2 = 12
Phosphoric acid, H3PO4, will undergo three successive ionization reactions to varying extents in water. What is the balanced equilibrium identified as Ka3
Answer:
HPO₄⁻² + H₂O ⇄ PO₄⁻³ + H₃O⁺ Ka3
Explanation:
Phosphoric acid, H3PO4 is a dyprotic acid which undergoes in these three succesive ionization reactions.
The last equillibrium is conditionated to the Ka3
H₃PO₄ + H₂O ⇄ H₂PO₄⁻ + H₃O⁺ Ka1
H₂PO₄⁻ + H₂O ⇄ HPO₄⁻² + H₃O⁺ Ka2
HPO₄⁻² + H₂O ⇄ PO₄⁻³ + H₃O⁺ Ka3
It is an acid because it release a proton, to make the [H₃O⁺] rise.
pH of solution will always be < 7
H₂PO₄⁻ and HPO₄⁻² are amphoteric compounds, which means that they can work as an acid (release protons), or base (take protons)
One of these two substances is a liquid at room temperature and the other one is a gas. Which one is the liquid and why?
A. CH3OCH3
B. CH3CH2OH
Answer:
B. CH3CH2OH
Explanation:
Ethanol has a chemical formula of CH3CH2OH, it is the second member of the series in the alkanol family. Ethanol is a colourless, volatile liquid with a characteristic smell and taste. It is readily soluble in water in all proportions. It has a boiling point of 78° C. The physical properties such as the solubility of alkanols are affected by the presence of hydrogen bonding. The hydroxyl group is capable of bonding to other alkanol molecules. The boiling points rise with increasing molecular mass.
Hydrogen bonding helps the molecules to stick together. For example comparing the boiling point of pentane ( 36° C) with that of butan-1-ol (118° C) , the boiling point of alkanol is much higher even though the two compound are of similar relative molecular mass. This is due to the presence of hydrogen bonds in butanol.
Hydrocarbons are not soluble in water but alkanols are soluble in water because of the hydroxyl groups in the molecules can form hydrogen bond with water. Solubility of alkanol in water decreases as the number of carbon atom increases. Primary alcohol with more than five carbon atoms are insoluble in water.
Using the measurements in the table, determine which unidentified metal has the lowest density?
Answer:
Metal C
Explanation:
Density = mass (g)/ volume (mL, which is the same thing as cm cubed)
Divide mass by volume for each metal, the metal with the lowest value (metal C) is your answer.
Answer:
IT IS
NOT. I REPEAT - IT IS NOT> D
Explanation:
i got it wrong :(
he mass of a single molybdenum atom is 1.59×10-22 grams. How many molybdenum atoms would there be in 38.3 milligrams of molybdenum?
Answer:
2.41 × 10²⁰ atoms
Explanation:
Step 1: Given data
Mass of a single molybdenum atom: 1.59 × 10⁻²² gMass of the molybdenum sample: 38.3 mgStep 2: Convert the mass of the sample to grams
We will use the relationship 1 g = 1,000 mg.
38.3 mg × (1 g/1,000 mg) = 0.0383 g
Step 3: Calculate the number of atoms in 0.0383 g of molybdenum
0.0383 g × (1 atom/1.59 × 10⁻²² g) = 2.41 × 10²⁰ atom
Part B
What is the symbol of the atom obtained by adding one proton to 19F?
Express your answer as an isotope
Answer:
Neon
Explanation:
A proton is the positively charged particle in the atom. The atomic number of an atom is the number of protons present in the atom while the mass number of an atom is the sum of the number of protons and neutrons in the nucleus of an atom.
If an extra proton is added to 19F, then neon is formed.
1. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Al(s) 28.3
Explanation:
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.4Al(s) + 3O2(g) ? Al2O3(s)
AnswerAluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Explanation:
Explanation:
why are step by step written procedures are an essential part of any scientific experiment
Answer: The scientific method attempts to minimize the influence of bias or prejudice in the experimenter. Even the best-intentioned scientists can't escape bias. ... That's the job of the scientific method. It provides an objective, standardized approach to conducting experiments and, in doing so, improves their results.
Consider a solution made from a nonvolatile solute and a volatile solvent. Which statement is true?
a) The vapor pressure of the solution is always greater than the vapor pressure of the pure solvent.
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
c) The freezing point of the solution is always greater than the freezing point of the pure solvent.
Answer:
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
Explanation:
Hello,
In this case, when we add a nonvolatile solute to a volatile solvent which has a relatively low boiling point, we can evidence the increase of the boiling point of the resulting solution as more energy must be supplied to take the molecules from liquid to gas. This fact matches with the boiling point elevation colligative property due to the solute's addition, which states that the boiling point of the solution is always greater than the boiling point of the pure solvent, therefore, answer is b).
Best regards.
The statement true about the solution made from a nonvolatile solute and a volatile solvent is, the boiling point of the solution is always greater than the boiling point of the pure solvent. Thus option C is correct.
The boiling point of the solution can be defined as the temperature where the liquid has been converted to the gaseous state. In the solvent, the energy has been provided to the sample for the conversion of liquid molecules to gas.
The addition of a nonvolatile solute to the volatile solvent results in the addition of the molecules to the solvent. This will result in the requirement of more energy for the conversion of solvent from a liquid state to a gaseous state.
Thus, with the addition of a nonvolatile solute to the volatile solvent, the boiling point of the solution will be increased and will always be greater than the boiling point of the pure solvent.
Thus option C is correct.
For more information about the volatile solvent, refer to the link:
https://brainly.com/question/3013635
How many seconds (s) are needed to deposit 7.25 g of copper metal from an aqueous solution of CuCl2, using a current of 3.1 Amps.
Answer:
7,052.6secs
Explanation:
n of Cu = +2
R.A.M of Cu = 64g
m = 7.25g
I = 3.1A
F = 96500
nF = R.A.M
It = m
2*96500 = 64
3.1*t = 7.25
1,399,250 = 198.4t
t = 7,052.6secs