Your teacher asks the class to evaluate the expression (3³)¹. Your classmate gives an incorrect answer of 81. Evaluate the expression. Then find the likely error.

Answer:

hypotenuse= 26

Step-by-step explanation:

c= a^2 + b^2

10^2 + 24^2= 26

Answer:

Line EF is a secant. I hope this helps!

Answer:line ef

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

9/g+2h+5

g=3

h=6

=9/3+2(6)+5

=3+12+5

=20

hope dis helps.

pls brainliest!!!!!

Answer:

a; line BC corresponds to line FG

Step-by-step explanation:

we know that a is correct as after translating BC and FG are on the same side of the rectangle and have the same length

Answer (it has two solutions):

I hope this helps!

At the end of the fourth month, we would have a total number of 4800 readers. The factor by which the number changes monthly is 2 and we would have 2n number of readers the following month

Data;

The difference in number of people who read from month to month will be

[tex]0 = 300\\1 = 2 * 300 = 600\\2 = 2 * 600 = 1200\\3 = 2 * 1200 = 2400\\4 = 2 * 2400 = 4800[/tex]

At the end of the fourth month, we would have a total number of 4800 readers.

The factor by which the number changes monthly is 2. From the pervious calculation, we can see a constant increase by a factor of 2 month to month.

Since we already established that the factor by which the readers increase is by two, we can simply say that at the next month, we would have 2n number of readers.

[tex]next month = 2 * n = 2n[/tex]

Learn more on linear equations here;

https://brainly.com/question/14323743

Answer:

56 people

Step-by-step explanation:

49 times 8= 392

392 divided 7= 56

Answer:

3:5 & 18:30

Step-by-step explanation:

To find an equivalent ratio, just multiply or divide both terms by the same number. For the two I did, I divided by 3 for one, and multiplied by 2 for the other, but there are infinite possibilities. Hope this helped!

Answer:   [tex]\frac{x^{20}}{y^{15}}[/tex]

This is the same as writing (x^20)/(y^15)

===================================================

Work Shown:

[tex]\left(x^{-4}y^3\right)^{-5}\\\\\left(x^{-4}\right)^{-5}*\left(y^3\right)^{-5}\\\\x^{-4*(-5)}y^{3*(-5)}\\\\x^{20}y^{-15}\\\\\frac{x^{20}}{y^{15}}[/tex]

In the second step, I used the rule that (a*b)^c = (a^c)*(b^c)

In step 3, I used the rule (a^b)^c = a^(b*c)

In the last step, I used the rule a^(-b) = 1/(a^b)

Answer:

x=12

Step-by-step explanation:

the area of a triangle is 1/2hb. so half of the shape's area would be:

(1/2)4x12=24

and 24x2=48

Answer:

At age 20, you will be 90 in

20 is not a perfect square.

36 = 6 times 6.

49 = 7 times 7.

68 is not a perfect square.

121 = 11 times 11.

400 = 20 times 20.

Hope this helps

Answer:

27 feet

Step-by-step explanation:

We can set up a proportion comparing the height of each object to the length of the shadow.

h/s

h/15=18/10

Cross multiply.

10*h=18*15

10h=270

Use the multiplicative Inverse

10/10=270/10

h=27

Answer:

  4x +3y = -3

Step-by-step explanation:

The standard form equation can be written from ...

  (y2 -y1)x -(x2 -x1)y = (y2 -y1)x1 -(x2 -x1)y1

  (-13 -3)x -(9 -(-3))y = (-16)(-3) -(12)(3)

  -16x -12y = 12

The standard form has a positive leading coefficient, and all terms mutually prime. We can get that by dividing the equation by -4:

  4x +3y = -3

_____

Additional comment

The form we used above for the equation of the line essentially comes from the fact that the slope of a line is the same everywhere:

  (y2 -y1)/(x2 -x1) = (y -y1)/(x -x1)

Multiplying by the product of denominators and separating variable terms from constant terms gives the form used above.

Answer:

The blank should say 'protractor'.

Step-by-step explanation:

I do not have one sorry,

Answer:

Step-by-step explanation:

Mark BRAINLIEST

Thank you ☺️☺️

95 times 2 is 190.

90 times 2 is 180, and 5 times 2 is 10.

180 + 10 = 190.

Answer:

[tex]\displaystyle y=\frac{2}{3}(x+5)+2[/tex]

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

[tex]\displaystyle y=-\frac{3}{2}x+4[/tex]

We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

[tex]m_1.m_2=-1[/tex]

Solving for m2:

[tex]\displaystyle m_2=-\frac{1}{m_1}[/tex]

[tex]\displaystyle m_2=-\frac{1}{-\frac{3}{2}}[/tex]

[tex]\displaystyle m_2=\frac{2}{3}[/tex]

Now we know the slope of the new line, we use the slope-point form of the line:

[tex]y=m(x-h)+k[/tex]

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

[tex]\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}[/tex]

Answer:

166.4

Step-by-step explanation:

Percentage of 12.8% of 1300 = ? 12.8% of 1300 is equivalent to multiplying them: 12.8% × 1300. 12.7% of 1300 = ? 12.9% of 1300 = ? 1% of 1300 = ? Detailed ...

Answer: Social science or sociology is considered as science but it is a pseudoscience.

Step-by-step explanation:

The sociology is considered as science as the study of social class, ethnicity, and religion abide by people of the society. Like, other factual sciences like chemistry, biology, and physics the facts cannot be rectified or verified by experimental trials. Instead, it is based on assumption and day to day experience with surrounding social environment. Thus, we can say that sociology is a science is a lie.

Answer:

123 milligrams

Step-by-step explanation:

76 : 3.1 = x : 5

76 * 5 = 3.1x

x = 76*5/3.1 = 123 milligrams

The range of function (f + g)(x) is (-9, ∞) option (D) is correct the linear function g(x) is g(x) = -3x - 5

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = x² + 3x - 4

The domain of the f(x) is all real numbers

The range of the g(x) is [-6.25, ∞)

g(x) is shown in the table:

x      –6     –3     –1       4

g(x)    13      4     –2    –17

The linear function g(x) is:

[tex]\rm g(x) = \ -13=\dfrac{\left(4-13\right)}{-3+6}\left(x+6\right)[/tex]

g(x) = -3x - 5

(f + g)(x) = f(x) + g(x)

= x² + 3x - 4 - 3x - 5

(f + g)(x) = x² - 9

The domain of the function is all real numbers.

The range of the function (-9, ∞)

Thus, the range of function (f + g)(x) is (-9, ∞) option (D) is correct the linear function g(x) is g(x) = -3x - 5

Learn more about the function here:

brainly.com/question/5245372

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Answer:

Step-by-step explanation:

3ab + 7a² + 2b² - (7a² - 4ab + 2b²) = 3ab + 7a² + 2b²  - 7a² + 4ab - 2b²

Now combine like term. Like terms have same variable with same power.

= 3ab + 4ab  + 7a² - 7a²  + 2b² - 2b²

= 7ab

Answer:

x = 41° , y = z = 74°

Step-by-step explanation:

x and 41 are alternate angles and are congruent , then

x = 41°

the 2 sides of the triangle with vertex = 32° are congruent so the triangle is isosceles with base angles being congruent , then

y = [tex]\frac{180-32}{2}[/tex] = [tex]\frac{148}{2}[/tex] = 74°

y and z are vertically opposite angles and are congruent so

z = 74°

Answer:

The area of the small square is 1 cm^2

Step-by-step explanation:

The large square consist in four identical rectangles and one small square.

Then the area of the small square will be equal to the difference between the area of the large square and the areas of the rectangles.

Because we have 4 equal rectangles, if R is the area of one rectangle, and S is the area of the large square, the area of the small square will be:

area = S - 4*R

We know that the area of the large square is 49 cm^2

Then:

S = 49cm^2

Remember that the area of a square of side length K is:

A = K^2

Then the side length of the large square is:

K^2 = 49 cm^2

K = √(49 cm^2) = 7cm

And we know that the diagonal of one rectangle is 5cm.

Remember that for a rectangle of length L and width W, the diagonal is:

D = √(L^2 + W^2)

Then:

D = √(L^2 + W^2) = 5cm

And for how we construct this figure, we must have that the length of the rectangle plus the width of the rectangle is equal to the side length of the large square, then:

L + W = 7cm

L = (7cm - W)

Replacing this in the diagonal equation, we get:

√((7cm - W)^2 + W^2) = 5cm

(7cm - W)^2 + W^2 = (5cm)^2 = 25cm^2

49cm^2 - 14cm*W + W^2 + W^2 = 25cm^2

2*W^2 - 14cm*W + 49cm^2 = 25cm^2

2*W^2 - 14cm*W + 49cm^2 - 25cm^2 = 0

2*W^2 - 14cm*W + 24cm^2 = 0

We can solve this for W using the Bhaskara's formula, the solutions are:

W = [tex]\frac{-(-14)(+/-)\sqrt{14^{2}-4(2)(24) } }{2(2)}[/tex]

Then we have two solutions, and we only need one (because the length will have the other value)

We can take:

W = (14 cm + 2cm)/4  = 4cm

Then using the equation:

L + W = 7cm

L + 4cm = 7cm

L = 7cm - 4cm = 3cm

L = 3cm

Now remember that the area of one rectangle of length L and width W is:

R = L*W

Then the area of one of these rectangles is:

R = 4cm*3cm = 12cm^2

Now we can compute the area of the small square:

area = S - 4*R = 49cm^2 - 4*12cm^2 = 1cm^2

The area of the small square is 1 cm^2

This took me ages to complete so please brainliest

Answer:

Cindy has $45 and Emily has $60

Step-by-step explanation:

let x be the amount of money , then

[tex]\frac{1}{2}[/tex] x + [tex]\frac{2}{3}[/tex] x = 105

multiply through by 6 ( the LCM of 2 and 3 ) to clear the fractions

3x + 4x = 630 , that is

7x = 630 ( divide both sides by 7 )

x = 90

Cindy has [tex]\frac{1}{2}[/tex] × 90 = $45

Emily has [tex]\frac{2}{3}[/tex] × 90 = $60

Answer:

x = - [tex]\frac{7}{2}[/tex], x = - 3

Step-by-step explanation:

Given

2x² + 13x = - 21 ( add 21 to both sides )

2x² + 13x + 21 = 0 ← in standard form

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × 21 = 42 and sum = + 13

The factors are + 6 and + 7

Use these factors to split the x- term

2x² + 6x + 7x + 21 = 0 ( factor the first/second and third/fourth terms )

2x(x + 3) + 7(x + 3) = 0 ← factor out (x + 3) from each term

(x + 3)(2x + 7) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

2x + 7 = 0 ⇒ 2x = - 7 ⇒ x = - [tex]\frac{7}{2}[/tex]