Answer:
W = 0.7071 F x, W = 35.355 J
Explanation:
Work is defined
W = F. d
bold indicates vectors,
W = F d cos θ
where the angle is between force and displacement.
As the system runs on snow, the friction force is negligible, therefore
W = F x cos 45
W = 0.7071 F x
Unfortunately the values of the force and the distance do not appear, suppose that the force is F = 10 N and the distance x = 5m
W = 0.7071 10 5
W = 35.355 J
Work is positive because force and displacement go in the same direction
A car took 5 minutes to travel from town A to town B which are 12km apart.Calculate the average speed of the path.
Speed = distance / time
Speed = 12km / 5 minutes
Speed = 2.4 km per minute
Speed is measured per hour, 1 hour has 60 minutes.
2.4 km per minute x 60 minutes = 144 km per hour
If displacement has a magnitude AND direction is it a scalar or vector quantity?
scalar
vector
Explanation:
Obviously vector quantity
A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block accelerate toward the end of the table where the mass was located. The student then places the block on the table and hangs a second, larger mass from the opposite end of the block. The block accelerates in the opposite direction from the first trial. What does this experiment demonstrate? Answer:
Magnitude of acceleration
Explanation:
We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).
This Newton's second law establishes a relationship between the summary of the external force and the acceleration of the body, It is demonstrated with the change in the direction and magnitude of the acceleration in the experiment
Newton's second law establishes a relationship between the net force and the acceleration, according to the expression
∑ F = m a
where ∑F is the sum of the external forces, m the mass and the acceleration of the body
In this case we have an initial situation, the block and a baking mass, therefore an acceleration is created towards the hanging mass given by
W₁ = M₁ g
F = ma
M₁ g = m a
a = [tex]\frac{M_1}{m} \ g[/tex]
where W₁ and M₁ are the weight and the masses of the mass of the body hanging under the acceleration of gravity.
In the second case, perhaps you have two masses, one on each side,
∑ F = W₁ -W₂
∑F = (M₁ -M₂) g
let's use Newton's second law
(M₁ -M₂ ) g = m a
a = [tex]\frac{M_1 - M_2}{m} \ g[/tex]
We can see that in the second case the acceleration depends on the difference of the hanging masses. This is a proof of Newton's second law where the effect on acceleration is due to the sum of all external forces and not of each force individually.
In conclusion with the realization of this experiment demostrate the valid true of Newton's second law
Learn more about Newton's second law here: https://brainly.com/question/19860811
a tennis ball “A” is released from rest down a 10.0 m long inclined ramp with a uniform acceleration of 5.0 m/s2. Another tennis ball “B” is initially located at the same height as ball “A” right above the lower edge of the ramp. Ball “B” is thrown upward with some initial speed at the same instant as the release of ball “A”.
a) What was the initial velocity of ball "B" so that "A" and "B" reach the bottom of the ramp at the same time?
Answer:
Please find the complete question in the attached file.
Explanation:
The time is taken by ball A to reach the bottom [tex]\to t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2 \times 10}{5}}=\sqrt{\frac{2 0}{5}}= \sqrt{4}=2\ s[/tex]
Calculating the velocity of the ball:
[tex]-h=ut-\frac{1}{2}gt^2\\\\-S \sin 30=ut-\frac{1}{2}gt^2\\\\-5=u(2)-\frac{1}{2}\times 9.81 \times 2^2\\\\[/tex]
[tex]-5=2u-9.81 \times 2\\\\-5=2u-19.62\\\\-5+19.62=2u\\\\14.62=2u\\\\u=\frac{14.62}{2}\\\\u=7.31 \ \frac{m}{s}[/tex]
Which of the following is an example of a surface wave?
A. Compression wave
B. Sound wave
C. Electromagnetic wave
D. Ocean wave
Answer:
ocean wave
hope it helped you
Do you believe in aliens? And if so, what's your reasoning for believing in them?
Answer:
I believe in aliens but I do not think everyone should. I started to believe in aliens since the US government said they would be taking extraterrestrial life seriously. They will be in our lives sooner or later, so we shouldn't be ignoring their presence. I believe them because surveys show that nearly half of Americans believe that aliens have visited the Earth, either in the ancient past or recently. That percentage has been increasing. Belief in alien visitation is greater than belief that Bigfoot is a real creature, but less than belief that places can be haunted by spirits. Also there have been a lot of UFO sightings, and a Navy Jet has a video of that as well. These small things is just hard to ignore, and they make me and hopefully others believe in aliens.
Help Meeeeeeeee. Have a nice day:)
Answer:
01.
Explanation:
Half the acceleration. Its heavier and moves slower. If it moved the same acceleration, the forces would also have to be doubled since the mass was.
While using a digital radiography system, suppose a radiographer uses exposure factors of 10 mAs and 70 kVp with an 8:1 grid for an AP shoulder radiograph with acceptable anatomical part penetration and detector element (DEL) exposure. If the radiographer desires to increase scatter absorption using a 12:1 grid, what new exposure factors should be used to maintain the same DEL exposure
Answer:
b. 12.5 mAs, 70 kVp
Explanation:
The given parameter are;
The initial exposure factors := 10 mAs and 70 kVp
The initial Grid Ratio, G.R.₁ = 8:1
The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂ = 12:1
Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;
The GCF for G.R. 8:1 = 4
The GCF for G.R. 12:1 = 5
Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;
mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs
Therefore the new exposure factors are;
12.5 mAs, 70 kVp
A flywheel turns through 40 rev as it slows from an angular speed of 1.5 rad/s to a stop. (a) Assuming a constant angular acceleration, find the time for it to come to rest. (b) What is its angular acceleration
Answer:
The time of motion is 333.3 s
The angular acceleration is -0.0045 rad/s²
Explanation:
Given;
angular distance of the flywheel, θ = 40 rev
initial angular speed, [tex]\omega_i[/tex] = 1.5 rad/s
When the wheel comes to rest, the final angular speed, [tex]\omega_f[/tex] = 0
The angular acceleration is calculated as follows;
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta \\\\0 = (1.5 \ rad/s)^2 + 2\alpha (40 \ rev\times \frac{2\pi \ rad}{1 \ rev} )\\\\0 = 2.25 + 160\pi \alpha\\\\160\pi \alpha = - 2.25\\\\\alpha = -\frac{2.25 }{160\pi} \\\\\alpha = -0.0045 \ rad/s^2[/tex]
The time of motion is calculated as;
[tex]\omega_f = \omega _i + \alpha t\\\\0 = 1.5 + (-0.0045t)\\\\0 = 1.5 - 0.0045t\\\\0.0045t = 1.5\\\\t = \frac{1.5}{0.0045} = 333.3 \ s[/tex]
what is chemical change ??
Answer:
the combination,decomposition or replacement that occurs in the molecules of matter during chemical change called chemical reaction
Answer:
A chemical change happens when one chemical substance is transformed into one or more different substances, such as when iron becomes rust. ... A chemical change is different from a physical change, which doesn't rearrange atoms or molecules and produce a completely new substance.
In a whispering gallery, a person standing at one focus of the ellipse can whisper and be heard by another person standing at the other focus, because all sound waves that reach the ceiling from one focus are reflected to the other focus. A hall 120 feet in length is to be designed as a whispering gallery. Of foci are located 40 feet from the center, how high will the ceiling be at the center
Answer:
Hence, the height of the ceiling at the center is 44.72 feet.
Explanation:
Consider that a whispering gallery has a length of 120 feet, and the foci are located 40 feet from the center.
Assume that the shape is a horizontal semi-ellipse with a center (0,0) and has the equation,
[tex]\frac{x^{2} }{ a^{2} } + \frac{y^{2} }{b^{2} } =1[/tex] where a>b,
so,
2a = 120
a = 60
and
c = 40
Therefore, the equation of the ellipse is,
[tex]c^{2} = a^{2} -b^{2} \\\\40^{2} = 60^{2} -b^{2}\\\\b^{2} =2000\\\\b= 44.72.[/tex]
(Q020) Stars a. all explode cataclysmically when they die and contribute their matter to future star generations. b. begin as protostars, which fire up when they collapse and become denser and hotter. c. have unlimited amounts of fuel and therefore exist indefinitely. d. create elements by splitting the nuclei of small atoms into the nuclei of larger atoms.
Answer:
Option (b).
Explanation:
A star is a heavenly body which emits a tremendous amount of energy by the reaction of nuclear fusion.
Sun is the smallest star in the universe.
The star stars from the proto star, this is the process of birth of a star. Then it collapse due to the gravitational pull and then it tarts emit light and energy and become a star.
After the long long time, it starts to decay and become a neutron star or the black hole.
So, the correct option is (b).
Capacitance (C) is measured in farads, where 1 farad is equivalent to 1 coulomb per volt. Resistance (R) is measured in ohms, and 1 ohm is equal to 1 volt per ampère. The coulomb is defined as the amount of charge passing when a current of 1 ampère flows for 1 second. What is the unit of RC expressed in its simplest form?
When fundamental units are combined, they result in derived units. RC (which means Resistance Capacitance) is a derived unit and its unit in the simplest form is Coulomb per Ampere (C/A)
Given that:
Capacitance (C) [tex]\to[/tex] Farads (f)
and
[tex]1f = 1\frac CV[/tex] ----- 1 farad = 1 capacitance per volt
Resistance (R) [tex]\to[/tex] Ohms [tex]\Omega[/tex]
[tex]1 \Omega = 1\frac{V}{A}[/tex]
The unit of RC is the product of the unit of R by the unit of C.
i.e.
[tex]RC = 1f \times 1\Omega[/tex]
Substitute [tex]1f = 1\frac CV[/tex]
[tex]RC = 1\frac CV \times 1\Omega[/tex]
Substitute [tex]1 \Omega = 1\frac{V}{A}[/tex]
[tex]RC = 1\frac CV \times 1\frac VA[/tex]
Cancel out volts (V)
[tex]RC = 1\frac CA[/tex]
[tex]\frac CA[/tex] means Coulomb per Ampere
Hence, the unit of RC is Coulomb per Ampere.
Read more about units at:
https://brainly.com/question/10167613
Try working backward from the desired goal to the starting point or current state. This advice describes a
Answer:
heuristic.
Explanation:
Psychology can be defined as the scientific study of both the consciousness and unconsciousness of the human mind such as feelings, emotions and thoughts, so as to understand how it functions and affect human behaviors in contextual terms.
This ultimately implies that, psychology focuses on studying behaviors and the mind that controls it.
A heuristic is an automatic mental shortcut or rule of thumb that avail people the opportunity to make quick and efficient judgement in decision-making process, as well as proffering solutions to a problem. Thus, it allows people to make decisions, pass probability judgement or proffer solutions to problem quickly and efficiently while applying minimal mental effort.
Basically, a heuristic helps an individual to shorten the decision-making time while paying less attention on thinking of his or her next course of action.
Hence, when you're advised to try working backward from the desired goal to the starting point or current state. This advice describes a heuristic.
The reservoir stores 6 500 000 m3 of water. The density of the water is 998 kg/m3. Calculate the mass of water in the reservoir. Give your answer in standard form.
Answer:
Mass = 64,870,000,000 kilograms
Explanation:
Given the following data;
Density = 998 kg/m³
Volume = 6,500,000 m³
To find the mass of water in the reservoir;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
Density = mass/volume
Making mass the subject of formula, we have;
Mass = density * volume
Mass = 998 * 6,500,000
Mass = 64,870,000,000 kilograms
Gas to liquid with explanation on the basis of kinetic model and condensation point.
Answer:
Explanation:
1)Melting:
Melting is the process by which a substance changes from the solid phase to the liquid phase. ... Melting occurs when the internal energy of a solid increases, usually through the application of heat or pressure, such that the molecules become less ordered.
2) liquefication:
In physics and chemistry, the phase transitions from solid and gas to liquid (melting and condensation, respectively) may be referred to as liquefaction. The melting point (sometimes called liquefaction point) is the temperature and pressure at which a solid becomes a liquid.
3) vaporization:
Vaporization, conversion of a substance from the liquid or solid phase into the gaseous (vapour) phase. If conditions allow the formation of vapour bubbles within a liquid, the vaporization process is called boiling. Direct conversion from solid to vapour is called sublimation.
4) Sublimation occurs as molecules of a substance in the solid state go to the vapor state directly, rather than through the liquid state. ... ⭕In terms of the kinetic molecular theory, we know that molecules are in constant random motion, even when the substance is below the melting point.
¿ Sobre que superficie se desplazara mas rápidamente un tejo, sobre cemento o sobre cerámica? ¿por que?
Answer:
cemento potque es plano
total distance divided by total time
Explanation:
average speed is the total distance divided by total time
Liquid to solid with explanation on the basis of kinetic model and freezing point.
Answer:
As a liquid is cooled its molecules lose kinetic energy and their motion slows. When they've slowed to where intermolecular attractive forces exceed the collisional forces from random motion, then a phase transition from liquid to solid state takes place and the material freezes.
hope this helps you..!!!!A particle is moving on a circular path of radius R. What will be its displacement and distance covered after 3 ½ round?
(please help fast)
Answer:
2r or diameter
Explanation:
After 3 1/2 rounds it will end up on the other side of the circle and displacement will be 2 x the radius = d
Distance = 7 π R
Displacement = 2 R from the starting point directed through the center of the circle
please help me with this question
Answer:
(4) A = 3 A, A₂ = 11 A
(5) 7 A
Explanation:
(4)
From the diagram,
A = 3+6+2
A = 11 A
V = A₂R
A₂ = V/R₂............ Equation 1
Given: V = 12 V, R₂ = 4 Ω
Substitute these values into equation 1
A₂ = 12/4
A₂ = 3 A
(5) Applying,
V = IR'
I = V/R'............ Equation 1
Where V = Voltage, I = cuurent, R' = total resistance.
But,
1/R' = (1/3)+(1/4)
1/R' = (3+4)/12
1/R' = 7/12
R' = 12/7 Ω
Given: V = 12 V
Substitute these values into equation 1
I = 12/(12/7)
I = 7 A
Therefore
A = 7 A
A student walks 350 m [S], then 400 m [E20°N], and finally 550 m [N10°W]. Using the component method, find the resultant (total) displacement). Round your answer to the appropriate significant figures. Round your angle to the nearest degree.
In component form, the displacement vectors become
• 350 m [S] ==> (0, -350) m
• 400 m [E 20° N] ==> (400 cos(20°), 400 sin(20°)) m
(which I interpret to mean 20° north of east]
• 550 m [N 10° W] ==> (550 cos(100°), 550 sin(100°)) m
Then the student's total displacement is the sum of these:
(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m
≈ (280.371, 328.452) m
which leaves the student a distance of about 431.8 m from their starting point in a direction of around arctan(328.452/280.371) ≈ 50° from the horizontal, i.e. approximately 431.8 m [E 50° N].
What is the period? Blank seconds.
Answer:
Period refers to the time for something to happen and is measured in seconds/cycle
Answer:
What is the period of time? 5.62 Seconds
What is the amplitude? 1 Centimeters
Explanation:
it just makes sense
Two parallel conducting plates are separated by 12.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude of the electric field strength between them, if the potential 5.6 cm from the zero volt plate is 450 V
Answer:
-8.036 kV/m
Explanation:
The electric field E = -ΔV/Δx where ΔV = change in electric potential = V - V' where V = electric potential at x = 5.6 cm = 450 V and V' = electric potential at x = 0 cm, = 0 V . So, ΔV = V - V' = 450 V - 0 V = 450 V.
Δx = distance between the 0 V plate and the 450 V point = 5.6 cm = 0.056 m
So, E = -ΔV/Δx
Substituting the values of the variables into the equation, we have
E = -ΔV/Δx
E = -450 V/0.056 m
E = -8035.7 V/m
E = -8.0357 kV/m
E ≅ -8.036 kV/m
Since the electric field between two parallel conducting plates is constant, the electric field between the plates is E = -8.036 kV/m
why is the value of g more in terai than in the mountain
The solution and answer are well written in the Pic above.
If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The radius of the earth is 6400km and the value of g on the earth surface is 9.8m/s2. please explain....
Answer:
Explanation:
You need something that relates distance to what the gravitational pull is. You can set up a complex sort of proportion. What you need is a number that is comparable to 9.81 or you can just use the Gravitational Force formula with a 4 tier fraction.
Givens
x = the additional distance toward outer space above the radius of the earth.
G is the gravitational constant.
m1 = the person's mass (which does not change no matter where you are).
m2 = the earth's mass
F1 = 588 N
F2 = 300 N
Formula
[tex]\frac{F1}{F2} = \frac{588 N}{300N}=\frac{\frac{Gm1*m2/}{6400^2} }{\frac{G*m1*m2}{(6400 + x)^2} }[/tex]
Solution
G*m1*m2 all cancel. So what you get looks like this.
[tex]\frac{588}{300} = \frac{(6400 + x)^2}{6400^2}[/tex]
Cross Multiply
588 * 6400^2 = 300*(6400+x)^2 Now all you need do is solve for x.
x will be in km.
588*40960000 = 300 * (40960000 + 12800x + x^2)
1.2288*10^10 + 3840000x + 300x^2 = 2.408448*10^10
300x^2 + 3840000x + 1.2288*10^10 = 2.408448 * 10^10
Subtract 2.409448 * 10^10 from both sides.
300x^2 + 3840000x - 1,179648 * 10^10
Now use the quadratic formula
I'm guessing I should have converted this to meters because I'm getting ridiculous numbers. They are already large enough as you can see. The method is correct, even if the numbers are not.
kettles heated on stoves used to be made of copper. was this a good choice?
Kettles heated on stoves are used to be made up of copper. This is because copper is a good conductor of heat and electricity.
Why copper is used in making kettles?Copper is used in making kettles. This is because copper is an excellent choice for a tea kettle as it is an excellent conductor of heat and electricity. This means that copper heats up quickly and evenly, making it ideal for the purpose of boiling water and preparing tea. Copper is also a durable material which can last for many years with proper care.
Copper kettles are polished from the outer surface as it is subject to corrosion that is caused by salts and sulfates. If the kettles are not cleaned completely, this corrosion, even as a slight film, will affect the taste of what is prepared in that copper kettle, giving a metallic sensation to taste.
Learn more about Copper here:
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A piano string of density 0.0050 kg/m is under a tension of 1,350 N. Find the velocity with which a wave travels on the string.
Answer:
519.62 m/s
Explanation:
Applying,
v = √(T/m').............. Equation 1
Where v = velocity of the wave, T = Tension on the string, m' = mass per unit length of the string
From the question,
Given: T = 1350 N, m' = 0.005 kg/m
Substitute these values into equation 1
v = √(1350/0.005)
v = √(270000)
v = 519.62 m/s
the weight of body is less at moon than its weight is more at earth
Answer:
Gravity
Explanation:
There's no gravity on space so you're floating
Which forms of energy determine temperature: translational kinetic energy, rotational kinetic energy, vibrational kinetic energy, or all of these
oh this question seems to be difficult I don't think I can answer this