Answer:
(110.295, 122.093).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 12 - 1 = 11
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 11 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.7959
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.7959\frac{11.3781}{\sqrt{12}} = 5.899[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 116.194 - 5.899 = 110.295
The upper end of the interval is the sample mean added to M. So it is 116.194 + 5.899 = 122.093
So
(110.295, 122.093).
what is the slope of the function, represented by the table of values below?
A. -2
B. -3
C. -4
D. -6
Answer:
B. -3
Step-by-step explanation:
Gsggagsgsvhdgdvdvdvdvdg help me fast I’ll give you brainliste
The answer is D
Hope that was fast enough
So for this problem I got 0.00023833 however it is not accepting my answer. If I rounded 4 decimal places it would be 0.000. How would I go about this problem? Can someone please help?
Answer:
0.0002
Step-by-step explanation:
4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.
Find the value of x in each case:
NEED IT NOW PLEASE
Angle QNM is =x by alternate angle reason (QU is parallel to MP)
X = 69
In one state lottery game, you must select four digits (digits may be repeated). If your number matches exactly the four digits selected by the lottery commission, you win.
1) How many different numbers may be chosen?
2) If you purchase one lottery ticket, what is your chance of winning?
3) There are ___ different numbers that can be chosen. (Type a whole number.)
4) There is a ___ chance of winning.*
*The answer choices for number 4 are:
1 in 10,000
1 in 6,561
1 in 100
1 in 1,000
1 in 9,999
Answer:
Part 1)
10,000 different numbers.
Part 2)
A) 1 in 10,000.
Step-by-step explanation:
Part 1)
Since there are four digits and there are ten choices for each digit (0 - 9) and digits can be repeated, then we will have:
[tex]T=\underbrace{10}_{\text{Choices For First Digit}}\times\underbrace{10}_{\text{Second Digit}}\times\underbrace{10}_{\text{Third Digit}}\times \underbrace{10}_{\text{Fourth Digit}} = 10^4=10000[/tex]
Thus, 10,000 different numbers are possible.
Part 2)
Since there 10,000 different tickets possible, the chance of one being the correct combination will be 1 in 10,000.
This is equivalent to 0.0001 or a 0.01% chance of winning.
1 cm = 5km scale ratio
Answer: Definition: Ratio of the size of the map to its subject: Scale ... so scale = 1 cm / 100,000 cm = 1/100,000. - Scale ... STEP 1: - 2 cm represents 5 km
Step-by-step explanation:
STEP 1: - 2 cm represents 5 km - (write in full)
- STEP 2: - 1 cm represents 2.5 km - (divide so left side = 1)
- STEP 3: - 1 cm represents 250,000 cm - (convert to same units)
- STEP 4: - scale is 1 : 250,000 - (express as a representative fraction)
please simplify this one. I need answers fast as possible.
This is the answer.
Hope it helps!!
Answer:
[tex]120.\sqrt{2}.\sqrt[3]{3}[/tex]
Step-by-step explanation:
[tex]\sqrt{32} = \sqrt{16.2} =\sqrt{4^{2}.2} = 4\sqrt{2}[/tex]
[tex]\sqrt[3]{81} =\sqrt[3]{27.3} =\sqrt[3]{3^{3}.3 }=3\sqrt[3]{3}[/tex]
∴[tex]5\sqrt{32}.2\sqrt[3]{81} =5. [4\sqrt{2}].2.[3\sqrt[3]{3} ][/tex]
[tex]=120.\sqrt{2}.\sqrt[3]{3}[/tex]
Identify the transformation that results in an image that's not congruent to the pre-
image.
A) Dilation
B) Translation
C) Rotation
D) Reflection
Answer:
dilation
Step-by-step explanation:
12
х
8
6
Find the value of x.
A) 9
B) 16
C) 14
D) 10
Answer:
The answer is 10, hope this helps!
Step-by-step explanation:
Two events A and B are _______ if the occurrence of one does not affect the probability of the occurrence of the other.
Answer:
Independent
Step-by-step explanation:
From the word independent, which means being able ot stand alone, that is the absence or presence of one has no impact on the outcome of each phenomenon. Two events A and B are said to be independent, if the occurence of one has no bearing on the probability or chance that B will occur. This means that each event occurs without reliance on the occurence of the other. This is different from mutually exclusive event whereby event A has direct bearing in the probability of the occurence of event B.
Write the equations for a line parallel to the line:
y=-4/3x-4
That goes through the point (-7,-6)
Write your equation in slope intercept form, using reduced fractions for the slope and intercept if necessary.
Answer:
y = -4/3x -46/3
Step-by-step explanation:
The question tells us to write an equation that is:
- parallel to the given line
- goes through the point (-7, -6)
Parallel lines will have the same slope, because if the slope was different, they would eventually intersect and not be parallel lines anymore.
We are going to use the point-slope form to find the other line.
Point-slope form uses a point that the graph will cross through and the slope of the graph to find the graph in y = mx + b form (also called slope-intercept form).
(I attached the point-slope form as an image below)
m = slope
x1 = x coordinate of the point
y1 = y coordinate of the point
We are going to substitute our slope into the form first:
y - y1 = (-4/3)(x - x1)
Next let's put in our point (-7, -6):
(Remember! -7 is our x coordinate & -6 is our y coordinate :-) )
y - (-6) = -4/3(x - (-7))
(cancel out the negatives to make them positive)
y + 6 = -4/3 (x +7)
Now solve for x using basic algebra:
y + 6 = -4/3 (x +7)
(distribue the -4/3)
y + 6 = -4/3x - 28/3
(subtract 6 from both sides)
y = -4/3x -46/3
That's your answer!
Hope it helps (●'◡'●)
Answer:
Step-by-step explanation:
y + 6 = -4/3(x + 7)
y + 6 = -4/3x - 28/3
y + 18/3 = -4/3x - 28/3
y = -4/3x - 46/3
rewrite the polynomial in the form ax^2 + bx + c then identify the values of a, b, and c
x^2/8 - 8
Answer:
[tex]x^{2} -16[/tex]
a = 1
b=0
c= -16
i assume the next question is to factor that...
(x-4)(x+4)
Step-by-step explanation:
It says I need too put 20 characters in too ask the question so ignore this part
Verify which of the following are identities.
Determine whether the following fractions terminate in their decimal form. Show all work and explain your reasoning. YOU CAN NOT USE A CALCULATOR. Try not using long division.
Answer:
8/22: this fraction will NOT terminate
189/270: this fraction WILL terminate
Step-by-step explanation:
I saw in the question that it says to solve the question by demonstrating the method discussed in class. I don't know what's the method you were taught, but I'll explain how I solved it.
When a fraction is in its simplest form, write out the prime factors of the denominator. If the denominator has 2s and/or 5s, the fraction WILL terminate in their decimal form.
8/22 in its simplest form is 4/11:
The only prime factors of the denominator, 11, are 1 and 11. There are no 2s and/or 5s present, so this fraction will NOT terminate.
189/270 in its simplest form is 7/10.
The prime factors of 10 are 2 and 5, meaning that this fraction WILL terminate.
Hope it helps (●'◡'●)
A license plate consists of a letter, followed by three numbers, followed by another
letter. Due to possible confusion, the letters I and O are not used. Repetition is not
allowed.
How many different license plates are possible?
This is one single number that's slightly smaller than 400 thousand.
======================================================
Explanation:
There are 26 letters in the english alphabet. We don't use letters i or o, so we have 26-2 = 24 choices for that first slot.
Then we have 10 choices for the second slot because there are 10 single digits 0 (zero) through 9.
After making the selection for the second slot, we have 10-1 = 9 choices left for the third slot. The fourth slot has 10-2 = 8 digits to pick from. The subtraction occurs because we cannot reuse the digits.
Finally, the last slot will be a letter. We have 24-1 = 23 letters left to pick from.
Overall, we have 24*10*9*8*23 = 397,440 different license plates possible.
--------------------
Extra info (optional section)
You may be wondering "why do we multiply those values?". Well consider a simple example of having only 2 slots instead of 5.
Let's say the first slot is a letter A to Z, excluding letters i and o. The second slot will be the digit from 0 through 9.
If you make a table with 24 rows and 10 columns, then you'll have 24*10 = 240 cells overall. Notice the multiplication here. The 24 rows represent each letter, and the 10 columns are the digit numeric digits.
Each inner cell is a different two character license plate. For example A5 is one such plate. This idea can be extended to have 5 characters.
Simplify the given expression into the form a+bi, where a and b are rational numbers.
2(-36 - 3i) +(5 +2i)(12 - 2i)
Answer:
[tex]2(-36 - 3i) +(5 +2i)(12 - 2i) \\ \implies - 72 - 6i + 60 - 10i + 24i + 4\\ \implies \: - 8 + 8i[/tex]
The 11th term of an arithmetic progression is 14 and the sum of the first 26 terms is 416. Find the first term and the common difference.
Answer:
The first term is 6; the common difference in 0.8.
Step-by-step explanation:
The nth term is:
[tex] a_n = a_1 + (n - 1)d [/tex]
The sum of the first n terms is:
[tex] S_n = \dfrac{n(a_1 + a_n)}{2} [/tex]
[tex] a_{n} = a_1 + (n - 1)d [/tex]
[tex] a_{11} = a_1 + (11-1)d [/tex]
[tex] a_1 + 10d = 14 [/tex] Equation 1
[tex] S_n = \dfrac{n(a_1 + a_n)}{2} [/tex]
[tex] S_{26} = \dfrac{26(a_1 + a_{26})}{2} [/tex]
[tex] \dfrac{26(a_1 + a_1 + 25d}{2} = 416 [/tex]
[tex] \dfrac{52a_1 + 650d)}{2} = 416 [/tex]
[tex] 26a_1 + 325d = 416 [/tex] Equation 2
Equation 1 and Equation 2 form a system of equations in 2 unknowns.
To eliminate a_1, subtract 26 times Eq. 1 from Eq. 2.
[tex] 65d = 52 [/tex]
[tex] d = \dfrac{52}{65} [/tex]
[tex] d = \dfrac{4}{5} = 0.8 [/tex]
[tex] a_1 + 10d = 14 [/tex]
[tex] a_1 + 10 \times 0.8 = 14 [/tex]
[tex] a_1 + 8 = 14 [/tex]
[tex] a_1 = 6 [/tex]
Answer:
The first term is 6; the common difference in 0.8.
19. In a random sample of 250 students, we found that 75 work out 4 or more times a week. Find the 95% confidence interval for the proportion of students who work out 4 or more times a week.
Answer:
The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
In a random sample of 250 students, we found that 75 work out 4 or more times a week.
This means that [tex]n = 250, \pi = \frac{75}{250} = 0.3[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 - 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.2432[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 + 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.3568[/tex]
The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).
Next anyone help it always helps haha 20 points
Answer:
Distance between Amber and Claire's house = 17.63 blocks
Step-by-step explanation:
In this graph three points are showing the locations of Amber's, Betsey's and Claire's houses.
Each unit on the graph represents 1 block.
Amber walks from her house to Claire's house, then on to Betsey's house.
We have to calculate the distance covered by Amber.
Since Distance from Claire's house to Betsey's house = 7 blocks = 7 units
and distance between Amber and Betsey's house = 8 blocks = 8 units
Now we will calculate the distance between Amber and Claire's house by Pythagoras theorem.
Distance² = 7² + 8² = 49 + 64 = 113
Distance = √113 units = 10.63 units
Therefore, total distance walked by Amber = 10.63 + 7 = 17.63 units = 17.63 blocks
Answer:
the answer might be 17. 63 because there are 7 blocks in between them so try that sorry if its wrong
f(x) = 2x + 9
f^-1(x)= ??
Step-by-step explanation:
Given
f(x) = 2x + 9
f^-1 (x) = ?
Let
y = f(x)
y = 2x + 9
Interchanging the roles of x and y we get
x = 2y + 9
2y = x - 9
y = ( x - 9) / 2
Therefore
⏩f^-1(x) = (x-9)/2
Hope it will help :)
convert 23/4 into mixed number
helppp
True or false: f(x) represents a function.
Consider the equations y = VI and y
32 – 1.
The system of equations is equal at approximately
Answer:
[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]
Step-by-step explanation:
[tex]y = \sqrt x\\[/tex]
[tex]y = x - 1[/tex]
Required
y, when they are equal.
To do this, we set them to another
[tex]\sqrt{x} = x - 1[/tex]
Square both sides
[tex]x = (x - 1)^2[/tex]
Expand
[tex]x = x^2 - 2x + 1[/tex]
Collect like terms
[tex]x^2 -x-2x+1 = 0[/tex]
[tex]x^2 - 3x + 1 = 0[/tex]
Using quadratic formula
[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]
What is the smallest 6-digit palindrome (a number that reads the same forward and
backward) divisible by 99?
Answer:
108801
Step-by-step explanation:
Well, you should first add 99 to 99999 which is 10098. And since it's not a palindrome you need to keep adding 99 to the sum until you reach one.
----------------------------------
This is with a calculator
Btw, I used calculator soup.com for it.
100089, 100188, 100287, 100386, 100485, 100584, 100683, 100782, 100881, 100980, 101079, 101178, 101277, 101376, 101475, 101574, 101673, 101772, 101871, 101970, 102069, 102168, 102267, 102366, 102465, 102564, 102663, 102762, 102861, 102960, 103059, 103158, 103257, 103356, 103455, 103554, 103653, 103752, 103851, 103950, 104049, 104148, 104247, 104346, 104445, 104544, 104643, 104742, 104841, 104940, 105039, 105138, 105237, 105336, 105435, 105534, 105633, 105732, 105831, 105930, 106029, 106128, 106227, 106326, 106425, 106524, 106623, 106722, 106821, 106920, 107019, 107118, 107217, 107316, 107415, 107514, 107613, 107712, 107811, 107910, 108009, 108108, 108207, 108306, 108405, 108504, 108603, 108702, 108801, 108900, 108999, 109098, 109197, 109296, 109395, 109494, 109593, 109692, 109791, 109890
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Answer:
eh width = 103.5 inches
Step-by-step explanation:
x = width
Length = (x/2 - 5 )*6
so 384=x+3x-30
414=4x
x=414/4=103.5 inches
A coffee distributor needs to mix a(n) Costa Rican coffee blend that normally sells for $9.10 per pound with a Arabian Mocha coffee blend that normally sells for $13.10 per pound to create 100 pounds of a coffee that can sell for $11.58 per pound. How many pounds of each kind of coffee should they mix?
9514 1404 393
Answer:
38 pounds Costa Rican62 pounds Arabian MochaStep-by-step explanation:
Let 'a' represent the number of pounds of Arabian Mocha in the mix. Then the number of pounds of Costa Rican blend is (100-a). The cost of the mix will be ...
9.10(100 -a) +13.10(a) = 11.58(100)
4a = 248 . . . . . . . . . . . . . collect terms, subtract 910
a = 62 . . . . . . . . . . . . divide by 4
62 pounds of Arabian Mocha and 38 pounds of Costa Rican blend should be mixed.
Joe's Auto Insurance Company customers sometimes have to wait a long time to speak to a
customer service representative when they call regarding disputed claims. A random sample
of 25 such calls yielded a mean waiting time of 22 minutes with a standard deviation of 6
minutes. Construct a 95% and 99% confidence interval for the population mean of such
waiting times. Explain what these interval means.
Answer:
The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.
The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0639
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.0639\frac{6}{\sqrt{25}} = 2.5[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 22 - 2.5 = 19.5 minutes
The upper end of the interval is the sample mean added to M. So it is 22 + 2.5 = 24.5 minutes
The 95% confidence interval for the population mean of such waiting times is between 19.5 and 24.5 minutes. This means that we are 95% sure that the true mean waiting time of all calls for this company is between 19.5 and 24.5 minutes.
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.797
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.797\frac{6}{\sqrt{25}} = 3.4[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 22 - 3.4 = 18.6 minutes
The upper end of the interval is the sample mean added to M. So it is 22 + 3.4 = 25.4 minutes
The 99% confidence interval for the population mean of such waiting times is between 18.6 and 25.4 minutes. This means that we are 99% sure that the true mean waiting time of all calls for this company is between 18.6 and 25.4 minutes.
Mark draws one card from a standard deck of 52. He receives $ 0.30 for a heart, $ 0.55 for a queen and $ 0.90 for the queen of hearts. How much should he pay for one draw
Answer
$0.1346
Explanation:
Find probability of each card and the value of each card and then add them together.
Probability of getting a heart = 13/52
Price of one heart =$0.30
Pay for one heart = 13/52×0.30=$0.075
Probability of getting a queen =4/52
Price of one queen =$0.55
Pay for one queen =4/52×$0.55=$0.0423
Probability of getting a queen of hearts =1/52
Price of one queen =$0.90
Pay for one queen =1/52×$0.90=$0.0173
Therefore the pay for one draw= $0.075+$0.0423+$0.0173=$0.1346
• A certain test consists of multiple-choice questions
and essay questions in the ratio of 5:2. If the test
contains 6 essay questions, what is the total number
of questions on the test?
Answer: 21
Step-by-step explanation:
My teacher just did it