At the top of the mountain where the ambient pressure is 11.5 psi, your tire pressure gauge reads 28 psig. After riding down the mountain to sea level where the ambient pressure is 14.7 psi. The tire pressure gauge at sea level will read 24.8 psig.
In this case, we can start by converting the gauge pressure at the top of the mountain (28 psig) to absolute pressure (pa) using the formula:
pa = gauge pressure + ambient pressure
pa = 28 psig + 11.5 psi
pa = 39.5 psi
At sea level, the ambient pressure is 14.7 psi, so the gauge pressure (pg) can be calculated as:
pg = pa - ambient pressure
pg = 39.5 psi - 14.7 psi
pg = 24.8 psig
So, the tire pressure gauge at sea level will read 24.8 psig.
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You want to build a bird house and attach it to a branch in a 12 foot tree. You have the following materials: wood, glue, screws, saw, hammer, screw driver, nails, ruler and a pulley system connected to a tree. Your bird house needs to be a rectangle that is 30cm long and 15cm wide. List the simple machines you would use to make this. (at least 3)
Answer:
just build it lol
Explanation:
The birdhouse is made from seven pieces of wood cut from a single 1- x 12-inch pine board, 6-feet long. Measure, mark and cut a 5- x 7-inch piece of board for the bottom of the birdhouse. Measure, mark and cut two 5- x 5
and go from there
A 0. 5 kg block of playdough moving at 1. 5 m/s is smashed into a 0. 25 kg blob of playdough. Calculate the speed
of the two stuck-together blobs immediately after colliding.
The final speed of both play doughs which stick together after the collision is 0.5 m/s.
The mass of the first play dough = 0.5 kg
The mass of the second play dough = 0.25 kg
The initial speed of the first play dough = 1.5 m/s
The initial speed of the second play dough = 2 m/s
The final speed of both play doughs can be found using the formula,
m₁u₁ + m₂u₂ = (m₁ + m₂) v
where,
m₁,m₂ is the mass of the first and second play dough respectively
u₁,u₂ is the initial speed of the first and second play dough respectively
v is the final speed of both play dough
Let us enter the known values in the above equation,
0.5 × 1.5 + 0.25 × 2 = (0.5 + 0.25) v
0.75 × 0.5 = 0.75v
0.375 = 0.75v
v = 0.375 / 0.75 = 0.5 m/s
The given question is incomplete. The complete question is ' The speed of the bob of the pay dough is 2 m/s.'
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how much tension must a cable withstand if it is used to accelerate a 1300- kg car vertically upward at 0.80 m/s2 ?
Tension that a cable withstand if it is used to accelerate a 1300- kg car vertically upward is 13780 N.
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable. Tension can be defined as an action-reaction pair of forces acting at each end of the said elements.
Given that,
Mass of the car, m = 1300 kg
Acceleration of the car vertically upwards,
As the car is moving vertically upwards. So,
T - mg = ma
T = m(a+g)
[tex]T = 1300 \times (0.8+9.8)[/tex]
T = 13780 N
So, the tension in the cable is 13780 N. Hence, this is the required solution.
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If you pull a pendulum with a mass of 7.4 kg back at an angle of 13°, what is the magnitude of the restoring force on it?
F=-mg sin is the net force operating on a basic pendulum bob of mass m. It is a force that restores.
What force is the restoring force in a straightforward pendulum in straightforward harmonic motion?A simple pendulum's restoring force is directed towards the mean position when it moves in a simple harmonic motion (lowest point). Here, the force of gravity acts as the restoring force at the centre of mass of the bob.
What is the pendulum motion equation?Pendulums are employed to control clock movement because the period—the amount of time between each full oscillation—is constant. The formula for a pendulum's period T is T = 2L/g squared.
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when two metal spheres of radius r are placed in contact, they attract each other with a small gravitational force. if two spheres of the same metal that have twice the radius were placed in contact, they would attract each other with a stronger gravitational force. how much stronger?
The gravitational force between two spheres with twice the radius would be 4 times stronger.
The strength of the gravitational force between two masses is proportional to the product of their masses and inversely proportional to the square of the distance between them.
In this scenario, the mass of the spheres increases with the cube of their radius, while the distance between their centers decreases with the increase in radius.
Hence, when the radius of the spheres is doubled, the mass of each sphere increases by a factor of 8 and the distance between their centers decreases by a factor of 2, resulting in a net increase in gravitational force by a factor of 4.
The formula for the gravitational force between two point masses is given by:
F = G × (m1 × m2) / r²
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two spheres, and r is the distance between their centers.
If we have two spheres with radius r, their masses are given by:
m1 = m2 = (4/3) × π × r³ × ρ
Where ρ is the density of the metal. When the radius of the spheres is doubled, their masses become:
m1' = m2' = (4/3) × π × (2r)³ × ρ = 8 × (4/3) × π × r³ × ρ
And the distance between their centers is halved:
r' = r/2
Substituting these values into the equation for gravitational force, we get:
F' = G × (m1' × m2') / r'²
F' = G × (8 × (4/3) × π × r³ × ρ)² / (r/2)²
F' = 4 × G × (4/3) × π × r³ × ρ × (4/3) × π × r³ × ρ / r²
F' = 4 × F
So the gravitational force between the spheres with twice the radius is 4 times stronger than the force between the spheres with the original radius.
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b The students investigating the speed of sound in gold declared that their
value of speed of sound in gold (from the graph in the task) is accurate
within a range of ±25 m/s. A reliable source of information gives the value
of speed of sound in gold as 3240 m/s. Are the results of the group of
students in agreement with the accepted value? Explain your answer.
Clap-echo technique With this technique, you time how long it takes you to hear an echo after a loud clap. You clap loudly when far away from a wall, then wait for the echo.
How do you calculate distance and sound speed?speed equals distance/time. A sound wave will cover a greater distance in the same amount of time as it moves quicker. The speed of a sound wave would be 350 m/s if it were noticed to cover 700 meters in 2 seconds.
The distance traveled is twice as far as the gap between you and the wall (because the sound has to travel to the wall and back).
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Problem 1 A skydiver of mass 80.0 kg (including parachute) jumps off a plane and begins her descent. Ра Throughout this problem use 9.80 m/s² for the magnitude of the acceleration due to gravityAt the beginning of her fall does the skydiver have an acceleration?A) No, the skydiverfalls at a constant speed B) Yes and her acceleration is directed upward C) Yes and her acceleration is directed downward
At the start of her fall, the skydiver experiences an acceleration of 9.80 m/s2 in a downward direction. The correct response is option (C), which states that she is accelerating downward.
At the beginning of her fall, the skydiver has an acceleration, and her acceleration is directed downward.
The acceleration is caused by the force of gravity, which is proportional to the mass of the skydiver, and since the skydiver has a mass of 80.0 kg, the force of gravity on her is,
F_gravity = m * g
= (80.0 kg) * (9.80 m/s^2)
= 784 N
According to Newton's second law of motion, the acceleration of an object is proportional to the net force acting on it, and inversely proportional to its mass,
a = F_net / m
The net force,
F_net = F_gravity = (80.0 kg) * (9.80 m/s^2) = 784 N
a = F_net / m = 784 N / 80.0 kg = 9.80 m/s^2
Therefore, the skydiver has an acceleration of 9.80 m/s^2 directed downward at the beginning of her fall. Answer: (C) Yes and her acceleration is directed downward.
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a 15 pf capacitor is charged to 1 kv and then removed from the battery and connected in parallel to an uncharged 65 pf capacitor. what is the new charge on the second capacitor? answer in units of nc.
The new charge on the second capacitor when two capacitors are connected in parallel is calculated to be 611× 10⁻¹⁴ C.
The formula Q = C V = C E d describes the charge held in a capacitor.
where,
C is capacitance
V is the potential across the capacitor
E is the uniform electric field
d is the distance between the plates
The energy stored in a capacitor is given by,
U = 1/2 C V² = 1/2 Q²/C = 1/2 A ε₀ E² d
where,
C is the capacitance
V is the voltage
Q is the charge stored
A is the area of the plates
ε₀ is 8.85 × 10⁻¹² F/m is the permittivity free space
E is the electric field
d is the distance
C₁ is given as 15 × 10⁻¹² F
C₂ is given as 65 × 10⁻¹² F
V₁ is given as 5 × 10³ V
Initial charge on the first capacitor is,
Q' = C₁ V₁ = 15 × 10⁻¹² × 5 × 10³ = 75× 10⁻⁹ C
When two capacitors are connected together, the equivalent capacitance of the new system is,
C = C₁ + C₂ = 15 × 10⁻¹² + 65 × 10⁻¹² = 80 × 10⁻¹² F
Voltage for the new system is, V = Q'/C = (75× 10⁻⁹)/(80 × 10⁻¹²) = 9.4× 10⁻² V
Charge on the second capacitor is,
Q₂ = C₂ V = 65 × 10⁻¹² × 9.4× 10⁻² = 611× 10⁻¹⁴ C
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how long does it take for an object to hit the ground falling 1.2 meters ar 5.3 m/s
It takes approximately 0.111 seconds for an object to fall .
Solving for how long does it take for an object to hit the ground:
The time it takes for an object to fall 1.2 meters at a velocity of 5.3 m/s can be calculated using the equation:
t = [tex]\sqrt{\frac{2 * d}{g} }[/tex]
where,
d = the distance fallen
g = the acceleration due to gravity
t = the time taken to fall that distance.
d = 1.2 meters
g = 9.8 m/s²
t= ?
Substituting in the numbers, we get:
t =[tex]\sqrt{\frac{ 2 * 1.2}{9.8\\ } }[/tex]
t = 0.111 seconds
Hence, it takes approximately 0.111 seconds for an object to fall 1.2 meters at 5.3 m/s.
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What is your hypothesis (or hypotheses) for this experiment? (kinetic energy)
Kinetic energy of any object is always positive. This should be hypothesis for any experiment.
What is hypothesis?
A hypothesis is a theory put up to explain a phenomenon. A hypothesis must be testable according to the scientific method for it to be considered a scientific hypothesis.
Scientific hypotheses are typically based on prior observations that cannot be adequately explained by the current body of knowledge. Despite the frequent confusion between the terms "hypothesis" and "theory," a scientific hypothesis differs from a scientific theory.
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a box is being pushed across the floor by a constant force the coeficient of kinetic friction is at time what is the new velocity and position
The velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are determined by Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration.
In this scenario, the applied force, friction force, and mass of the box all play a role in determining its velocity and position.
The applied force is the force being applied to the box to move it across the floor. The frictional force, which acts in the opposite direction to the applied force, is proportional to the normal force and the coefficient of kinetic friction. The normal force is the force exerted by the floor on the box, perpendicular to the floor.As the box is pushed, it will eventually reach a velocity at which the frictional force is equal in magnitude to the applied force, and the net force on the box will be zero. At this point, the box will move at a constant velocity, as it is no longer accelerating. The position of the box will be dependent on the initial velocity, the applied force, and the time elapsed.
Overall, the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are interrelated and determined by the balance of forces acting on the object.
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What is the relationship between the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction?
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Two parents, both heterozygous (Tt) and tall, are crossed to produce offspring. What are the possible genotypes and phenotypes of the offspring? What is the percentage chance of being homozygous?
Answer:
Look below
Explanation:
The possible genotypes of the offspring are: TT, Tt, and tt.
The possible phenotypes of the offspring are: tall and short.
The percentage chance of being homozygous can be calculated using a Punnett square. When the heterozygous parents are crossed, the possible genotypes of the offspring are:
| T | t
--|---|---
T | TT| Tt
t | Tt| tt
From the Punnett square, we can see that there is a 25% chance of the offspring being homozygous (TT or tt). This is because there are four possible outcomes and two of them result in a homozygous genotype (TT and tt).
object 1 has a momentum of 5 kg*m/s before colliding with object 2 which has a momentum of -3 kg*m/s before the collision. after they collide, object 1 immediately stops. what is the momentum of object 2 after the collision?
The momentum of object 2 after the collision is 2 kg × m/s.
Momentum = mass × velocity
Before the collision, object 1 has a momentum of 5 kg * m/s, and object 2 has a momentum of -3 kg * m/s. The total momentum of the two objects before the collision can be calculated as the sum of the individual momenta:
Total momentum before collision = 5 kg × m/s + (-3 kg × m/s) = 2 kg × m/s
According to the law of conservation of momentum, the total momentum of a system remains constant unless acted upon by an external force. In this case, the two objects are colliding with each other and no external forces are present, so the total momentum of the system must remain constant.
After the collision, object 1 stops, so its velocity becomes 0, and its momentum becomes 0 kg × m/s.
Momentum of object 2 after collision = Total momentum of the system - Momentum of object 1
= 2 kg × m/s - 0 kg × m/s = 2 kg × m/s
So, the momentum of object 2 after the collision is 2 kg × m/s.
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what do you notice about the momentum before and after of the red cart vs the momentum before and after of the blue cart?
However, in general, the law of conservation of momentum states that the total momentum of an isolated system remains constant if there are no external forces acting on the system. This means that the sum of the momenta before an event is equal to the sum of the momenta after the event.
What is the momentum ?
Momentum is the quantity of motion of a moving body, also known as its mass multiplied by its velocity. Momentum is a vector quantity, which means it has both a direction and a magnitude. Momentum is conserved in an isolated system. This means that the total momentum of a system remains constant as long as no external forces act on it. Momentum is an important concept in classical mechanics, as well as in modern physics. In everyday life, momentum can be seen in sports, such as a baseball thrown with a certain speed, or a car moving with a certain speed.
If the red and blue carts are part of an isolated system, their total momentum before the event would be equal to their total momentum after the event. Therefore, any change in the momentum of one cart must be compensated for by an equal and opposite change in the momentum of the other cart.
So, if one cart experiences an increase in momentum after the event, the other cart must experience a decrease in momentum of the same magnitude. Conversely, if one cart experiences a decrease in momentum, the other cart must experience an increase in momentum of the same magnitude.
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Margaret drops a coin down a funnel shaped object. The coin rolls around the outer edge in a circular motion. As it moves closer to the bottom, it completely rolls around the edge. Margaret drops another coin into the same funnel shaped object. Which type of motion can Margaret predict this coin will have
a Margaret drops a coin down a funnel shaped object.
a A straight line
b A circling motion
c A front to back motion
d A zigzagging motion
The required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.
What is motion?motion is defined as an object's change of position over time is called motion.
Here,
As Margaret drops a coin down a funnel-shaped object. The coin rolls around the outer edge in a circular motion. As it moves closer to the bottom, it completely rolls around the edge.
Margaret can predict that the second coin will have a circling motion as it moves down the funnel-shaped object. The shape of the funnel will cause the coin to roll around the edge in a circular motion.
Thus, the required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.
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the thicknesses are h1 5 0.5 mm and h2 5 0.3 mm, respectively. find the force f to make the upper plate move at a speed of 1 m/s. what is the fluid velocity at the interface between the two fluids?
The upper plate must move with a force of 143 N in order to move at a speed of 1 m/s. The two fluids' contact has a fluid velocity of 0.714 m/s.
What is the pipe's fluid velocity?Pipe velocity is an area averaged attribute that is unaffected by the cross-sectional flow pattern or laminarity of the flow in the pipe. For instance, fluid may be moving twice as fast down the center axis as predicted by the pipe velocity.
Fluid Velocity
We are given fluid viscosities as;
₁ = 0.1 N.s/m²
₂ = 0.15 N.s/m²
Thicknesses of plates are;
h₁ = 0.5 mm and h₂ = 0.3 mm
Since the shear stress is constant throughout,
τ = ₁(du₁/dy₁) = ₂(du₂/dy₂)
⇒ ₁(Ui/h₁) = ₂(U - Ui)/h₂
where Ui is the interface speed and U is the upper body's movement speed, we have;
Ui = U/(1 + (₁/₂)*(h₂/h₁))
⇒ Ui = 1/(1 + (0.1/0.15)*(0.3/0.5))
⇒ Ui = 0.714 m/s
Force required is;
F = ₁ * (Ui/h₁) * (A)
We are given A = 1 m²
Thus;
F = 0.1 * (0.714/0.0005) * 1
F ≈ 143 N
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Question:
Luids of viscosities 1 =0.1 N.s/ms and 2 =0.15 N.s/m2 are contained between two plates (each plate 1
m2 area). The thicknesses are h1=.5 mm and h2=0.3 mm, respectively. Find the force F to make the upper
plate move at a speed of 1 m/s. What is the fluid velocity at the interface between the two fluids?
primary vehicle controls include: group of answer choices transmission controls accelerator pedal clutch pedal all of the above
The aforementioned accelerator pedal, clutch pedal, and other primary controls are all included in a car.
What is an accelerator's function?In conclusion, accelerators play a significant part in fostering innovation through a plan designed to guide a cohort few participants with their concepts through an intense program to develop, produce, and commercialize an alternative investment product that can grow and function in the real world.
What exactly is a catalytic energy?A SHOC's innovative energy drink ACCELERATOR was created to fulfill the needs of your modern, energetic, and healthy lifestyle.
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can a vector have a component equal to zero and still have nonzero magnitude? match the words in the left column to the appropriate blanks in the sentences on the right.
The statements stands true. A vector have a component which is equal to zero and still have nonzero magnitude.
In a 2-D plane a vector can be resolved into the rectangular components. These are rectangular components to each other. These are available at right angles to each other. One component is directed along x-axis. It is the termed as horizontal component. The other one is directed along y-axis. Is termed as vertical component.
Sometimes, the vector is directed entirely either along x-axis or y-axis. When the vector is along x-axis or parallel to x-axis, then the complete magnitude will be directed along horizontal component. The vertical component will be zero. For a vector which is along y-axis, the horizontal component will be zero. The entire magnitude will be along y-axis.
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On a banked race track, the smallest circular path on which cars can move has a radius of 101 m, while the largest has a radius 159 m, as the drawing illustrates. The height of the outer wall is 18 m.
(a) Find the smallest speed at which cars can move on this track without relying on friction.
(b) Find the largest speed at which cars can move on this track without relying on friction.
The smallest speed at which cars can move on this track without relying on friction is 31.46 m/s.
The largest speed at which cars can move on this track without relying on friction is 39.10 m/s.
What is centripetal acceleration?An attribute of an object moving in a circular route is centripetal acceleration. Any object moving in a circle with an acceleration vector pointing in the direction of the circle's center is said to be experiencing centripetal acceleration.
a) The smallest speed at which cars can move on this track without relying on friction is = √(gr₁)
= √(9.8 × 101) m/s
= 31.46 m/s.
b) The largest speed at which cars can move on this track without relying on friction is = √(gr₂)
= √(9.8 × 159) m/s
= 39.10 m/s.
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Can someone explain this to me in detail, please?
By comparing the acceleration due to gravity on each planet, the highest speed would be on earth.
What is the acceleration due to gravity?The acceleration due to gravity is the acceleration experienced by an object as it falls freely under the influence of Earth's gravity. The acceleration due to gravity is commonly denoted by the symbol "g" and has a value of approximately 9.8 meters per second squared (m/s^2) near the surface of the Earth.
This value can vary slightly depending on factors such as altitude, latitude, and the local geological structure.
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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of the carriage has__ energy. Calculate it.
The required energy the carriage has, when the displacement of the carriage and mass of the carriage with the baby are given is calculated to be 1029 J.
The energy in the above case is nothing but the work done by the carriage.
The work is defined as,
W = F d
where,
F is force
d is displacement
Entering the values in the above equation, we have,
W = F d = m × a × d = 5 × 9.8 × 21 = 1029 J
Thus, the required energy the carriage has is calculated to be 1029 J.
The given question is inappropriate. The question is 'a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 5kg whats the energy the carriage has?'
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A man standing on a lift throws a ball upwards with the maximum initial velocity he can and is found to be equal to 55 m/s. After what time the ball returns to his hand if (a) the lift is stationary, (b) the lift is moving up with a uniform velocity of 7 m/s, (c)the lift is moving down with a velocity of 7 m/s. Also given g = 9.8 m/s2
bumper cars a and b undergo a collision during which the momentum of the combined system is conserved. which equation(s) correctly states the principle of conservation of momentum?
According to the given equation(s) correctly states the principle of conservation of momentum.
A. P Ai + P Bi = P A f + P Bf
D. ΔPA + ΔPB=0
What exactly is momentum conservation?The total momentum of two or more entities working on each other in an isolated system must remain constant until an external force is applied, according to the law of conservation of momentum. Because of this, momentum cannot be created or destroyed.
Briefly defined, what is the law governing the conservation of momentum?The conservation of momentum, or total momentum of a system, is a general statement of physics that states that the quantity known as momentum, which characterizes motion, never changes inside an isolated collection of particles.
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Bumper cars A and B undergo a collision during which the momentum of the combined system is conserved. Which equation(s) correctly states the principle of conservation of momentum? Check all that apply.
A. P Ai + P Bi = P A f + P Bf
B. P Ai + P A f = P Bi + P Bf
C. ΔPA = ΔPB
D. ΔPA + ΔPB=0
Four 2. 0-µC point are at the corners of a rectangle with sides of length 3. 0 cm and 4. 0 cm. What is the electric potential (relative to infinity) at the midpoint of the rectangle? (k = 1/4πε0 = 9. 0 × 109 N ∙ m2/C2)
The electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
How close to infinity is electric potential?
Whenever a charge Q is infinitely far away from another charge, the electric potential is deemed to be 0. The resultant electric field is zero at P, the halfway between two identical charges.
To find the electric potential at the midpoint of the rectangle, we need to calculate the electric potential due to each of the four point charges, and then add them up. The electric potential at a point is given by the equation:
[tex]\mathrm{V = k \times q / r}[/tex]
where V is the electric potential, k is Coulomb's constant (1/4πε0), q is the charge, and r is the distance from the point charge to the point where we want to calculate the potential.
Let's assume that the rectangle lies in the x-y plane, with one corner at the origin. We can label the other corners as A, B, and C, where AB is parallel to the x-axis and BC is parallel to the y-axis.
The distance from the midpoint of AB to each of the four point charges is given by:
[tex]\mathrm{r_1 = r_3 = \sqrt{(1.5 cm)^2 + (2 cm)^2}= 2.5 cm}[/tex]
[tex]\mathrm{r_2 = r_4 = \sqrt{(1.5 cm)^2 + (1 cm)^2}= 1.8 cm}[/tex]
The electric potential due to each of the point charges at the midpoint of AB is given by:
[tex]\mathrm{V_1 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (2.5 \times 10^{-2} m) = 720 V}[/tex]
[tex]\mathrm{V_2 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (1.8 \times 10^{-2} m) = 100V}[/tex] = 1000 V
[tex]\mathrm{ V_3 =k \times q / r_3 = 720 V}[/tex]
[tex]\mathrm{ V_4 =k \times q / r_4 = 1000V}[/tex]
The total electric potential at the midpoint of AB is the sum of these four potentials:
[tex]\mathbf{V_{total} }[/tex] = V1 + V2 + V3 + V4
= 720 V + 1000 V + 720 V + 1000 V
= 3440 V
Therefore, the electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
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A ray of light is incident on a right angled prism of refractive index 1,5 , calculate the angle of refraction of the ray within the prism
The angle of refraction of the ray within the prism is 1.3
What is angle of refraction?The angle of refraction is described as the angle between a refracted ray and the normal drawn at the point of incidence to the interface at which refraction occurs.
Given, μ=refractive index of liquid.
The angle of incidence, i = 60 °
internal reflection , angle of refraction r = 90 °
Now,
sinr/ sini = μ / μ1
sin60° = μ/ 1.5
μ= √3 / 2 x 1.5
μ=1.3
in conclusion, the angle of refraction is the measurable quantity that indicates the amount of refraction taking place at any boundary.
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Complete question:
ACB is a right-angled glass prism with refractive index 1.5. Angle A, B, C are 60
∘
,30
∘
and 90
∘
respectively. A thin layer of liquid is on the AB. For a ray of light which is incident normally on AC to ;be totally reflected at AB, the refractive index of the liquid on AB should be
when making a lane change in front of a car, where should that car be in your mirrors? in the middle of your side mirror on the outside edge of your side mirror on the very edge of your rearview mirror toward the middle of your rearview mirror
When making a lane change in front of a car, the car should be toward the middle of your rearview mirror. Correct option is D.
Place the seat and steering wheel so that you can access the gear shifter, brake pedal, and accelerator while still feeling comfortable. Move the rearview mirror gently so that you can look straight out of the back windshield's centre without turning your head.
A straight, even reflection of the back window should be visible in the rearview mirror. Every 5 to 8 seconds, check your rearview mirror. You can keep track of who is approaching you, who has already past you, and who is acting erratically or dangerously close behind you by often checking your rearview mirror.
An adjustable reflecting device called a rearview mirror allows drivers to see the road, other cars, and things behind their vehicle.
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select the accurate statements concerning membrane fluidity.
-The degree of membrane fluidity varies depending on the composition of the membrane. -Phospholipids are relatively free to move around laterally within the membrane. -Unanchored proteins are relatively free to move around laterally within the membrane.
All of the above given statements are true.
What is membrane?A membrane controls the flow of chemicals between two environments as a selectively permeable barrier. The cell membrane is the most well-known biological membrane.
a. The amount of membrane fluidity varies based on the membrane's make-up. This is because the fluidity of the membrane can be impacted by the lipid composition, particularly the length of fatty acid chains and degree of unsaturation of phospholipids.
b. Phospholipids can travel around the membrane's lateral space quite freely. This is so that individual phospholipids can migrate laterally inside the membrane's lipid bilayer structure.
c. Unanchored proteins can essentially travel wherever they choose in the membrane's lateral space. This is due to the ability of proteins to diffuse laterally within the lipid bilayer, independent of the cytoskeleton or other proteins in the membrane.
These conclusions accurately characterize the degree of fluidity within the membrane and how the ratio of lipids to proteins affects it.
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perform a kline-mcclintock uncertainty analysis on the pump power calculation. what is the uncertainty of the pump power measurement in watt?
The Kline-McClintock uncertainty analysis is used to estimate the uncertainty associated with measurements of power output from a pump. The uncertainty is usually determined by analyzing the errors associated with the measurements taken and the accuracy of the equipment used.
The uncertainty of the pump power measurement in watt will depend on the accuracy of the measurements, the precision of the instruments used, and the degree of accuracy of the calculations. Generally, the uncertainty of the pump power measurement in watt can be estimated as the combined standard deviation of all measurement errors.
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a 2.0- kg blob of play dough moving at 2 m/s slams into a 2.0- kg blob of play dough at rest. find the speed of the two stuck-together blobs immediately after colliding.
After hitting, the two putty blobs that were locked together moved at a speed of 1.5 metres per second.
Both before and after the contact, the momentum is preserved. In other words, the starting and end momentum values are equal.
Initial momentum is 6 kg/s (kg/s = 2 * 3 + 2 * 0).
Thus, the ultimate momentum is 6 kg/m/s.
Final body weight is 2 plus 2 kg.
Final body speed is calculated as final speed/final mass, which is 6/4 = 1.5 m/s.
Thus, 1.5 m/s was the speed of the two putty blobs that had just collided and were stuck together.
Speed is defined as the ratio of distance to the amount of time it took to cover that distance. Due to its lack of magnitude and merely having a direction, speed is a scalar number.
When an item travels an identical distance in a same amount of time, this is referred to as having uniform speed.
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Calculate the time it takes a 200 W appliance to transfer 40,000 J of energy
Explanation:
P=energy used/time taken
200=40000/t
200t=40000
divide both sides by 200
t=200s
[tex] power = \frac{workdone}{time \: taken} [/tex]
[tex] p = \frac{w}{t} [/tex]
200 = 40,000 / t
200t = 40,000
200t / 200 = 40,000 / 200
t = 200s