Yellow cab charges 1.75 flat rate in in addition to $0.75per mile. Leo has no more than $20 to spend on a ride. How many miles can Leo travel without exceeding his limit?
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The percentages of returns are given as follows:

a. Greater than 33%: 2.28%.

b. Below -37%: 0.13%.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters for this problem are given as follows:

[tex]\mu = 5, \sigma = 14[/tex]

The proportion above 33% is the one subtracted by the p-value of Z when X = 33, hence:

Z = (33 - 5)/14

Z = 2.

Z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228 = 2.28%.

The proportion below -37% is the p-value of Z when X = -37, hence:

Z = (-37 - 5)/14

Z = -3.

Z = -3 has a p-value of 0.0013.

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The area of the shaded region is 0.725746882.

The probability distribution of random variables is described using the cumulative distribution function. The probability for a discrete, continuous, or mixed variable may be described using it. The cumulative probability for a random variable is calculated by adding the probability density function.

Given:

The graph depicts the IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 91.

From the diagram,

the critical value is 91.

The formula to calculate the z-score is,

z = (x - u) / s,

Substituting the given values to the formula,

the given values are;

x = critical value = 91

u = mean = 100

s = standard deviation = 15

Thus,

z = (x - u) / s

z = -0.6

P(z > -0.6 ) = 0.725746882

Therefore, the area is 0.725746882.

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They wanted to produce 50 more racing bikes per week (point B), what would be there opportunity cost There is no opportunity cost.

What is meant by speed?

The opportunity cost of producing 50 more racing bikes per week (moving from point A to point B) would be the amount of mountain bikes that the factory would have to give up producing in order to allocate resources to producing more racing bikes.

From the PPF, we can see that in order to produce an additional 50 racing bikes per week, the factory would have to decrease its production of mountain bikes by 50 (moving from 250 to 200). Therefore, the opportunity cost of producing 50 more racing bikes per week is 50 mountain bikes (option C).

So the answer is C. 50 mountain bikes.

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In mathematical terms, if T is injective, then for any vectors u and v in the domain V, T(u) = T(v) only if u = v. This property is also known as one-to-one correspondence.

One important property of linear operators is their infectivity, which means that the function maps distinct vectors in the domain to distinct vectors in the codomain.

To prove that {Tvi} is also linearly independent, we need to show that if a1T(v1) + a2T(v2) + ... + akT(vk) = 0, then the only solution is a1 = a2 = ... = ak = 0. We can do this by assuming that there exist scalars a1, a2, ..., ak that are not all zero, and show that this leads to a contradiction.

Suppose that

=> a1T(v1) + a2T(v2) + ... + akT(vk) = 0,

where not all of the ai's are zero. Then, we can write this as

=> T(a1v1 + a2v2 + ... + akvk) = 0.

Since T is injective, this implies that a1v1 + a2v2 + ... + akvk = 0.

Now, let's move on to the second part of the problem statement, which deals with the surjectivity of the linear operator T.

In other words, if T is surjective, then for any vector w in the codomain V, there exists a vector v in the domain V such that T(v) = w.

If {vi} spans V, then every vector in V can be expressed as a linear combination of the {vi}'s. In other words, for any vector u in V, there exist scalars c1, c2, ..., ck such that

=> u = c1v1 + c2v2 + ... + ckvk.

To prove that {Tvi} also spans V, we need to show that every vector w in V can be expressed as a linear combination of the T(vi)'s.

Then, we can express v as a linear combination of the {vi}'s:

=> v = c1v1 + c2v2 + ... + ckvk.

Applying T to both sides, we get:

w = T(v) = T(c1v1 + c2v2 + ... + ck

W = c1T(v1) + c2T(v2) + ... + ckT(vk)

This shows that w can be expressed as a linear combination of the T(vi)'s, which means that {Tvi} also spans V.

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maybe if you ask politely

The requried a measure of the exterior angle ∠4 = 63°.

The triangle is a geometric shape that includes 3 sides and the sum of the interior angle should not be greater than 180°

Here,

As we know that for a triangle, the sum of the remote interior angle is equal to the measure of the exterior angle.

So, from the figure.

31 + 32 = ∠4

∠4 = 63°

Thus, the requried measure of the exterior angle ∠4 = 63°.

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Answer:

1. 26*

2. 17*

3. 23*

The adage "You should wait until after paying all of your bills and discretionary expenses before budgeting for savings" is accurate.

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I'm sorry, there is no image or diagram provided to identify the shaded region. Could you please provide more information or a visual aid for me?

The expected value of an unbiased estimator is equal to the parameter whose value is being estimated. A) True B) False . the answer is false

Answer:[tex]34\pi[/tex]

Step-by-step explanation:

c=[tex]2\pi R=2*17\pi =34\pi[/tex]

Answer:

43.98 meters

Step-by-step explanation:

Answer:

38 & 27 & 147

Step-by-step explanation:

4) 38cm²

5*4 = 20cm²

2*9 = 18cm²

5) 27m²

6*6 = 36m²

3*3 = 9m²

6) 147in²

14*14 = 196cm²

7*7 = 49in²

Answer:

4)  38 cm²

5)  27 m²

6)  147 in²

Step-by-step explanation:

To calculate the area of each given figure, subtract the area of the cut-out rectangle (marked in blue on the attached diagram) from the area of the larger rectangle.

[tex]\boxed{\begin{minipage}{5cm}\underline{Area of a rectangle}\\\\$A=w\cdot l$\\\\where:\\ \phantom{ww} $\bullet$ \quad $w$ is the width.\\ \phantom{ww} $\bullet$ \quad $l$ is the length.\\\end{minipage}}[/tex]

[tex]\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&=9 \cdot 6- (9-5)\cdot 4\\&=9 \cdot 6- 4\cdot 4\\&=54-16\\&=38\; \sf cm^2\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&= 6\cdot 6- 3\cdot 3\\&=36-9\\&=27\; \sf m^2\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&= 14\cdot 14- 7\cdot 7 \\&=196-49\\&=147\; \sf in^2\end{aligned}[/tex]

Mean of this random variable is 3.14 and standard deviation is 1.82. The mean is calculated by multiplying each value of x by its corresponding probability and then summing the result.

Mean = (-2 * 0.12) + (0 * 0.26) + (3 * 0.28) + (4 * 0.14) + (7 * 0.22)

= 3.14

standard Deviation = [tex]\sqrt{[( (-2)2 * 0.12 ) + (02 * 0.26) + (32 * 0.28) + (42 * 0.14) + (72 * 0.22) - (3.142) ] }[/tex]= 1.82

The mean and standard deviation of a random variable with a given discrete probability distribution can be calculated using the following steps. First, each value of x is multiplied by its corresponding probability and then the results are summed to calculate the mean. For example, for the given discrete probability distribution, the mean is calculated by multiplying -2 by 0.12, 0 by 0.26, 3 by 0.28, 4 by 0.14 and 7 by 0.22 and then summing the results which is 3.14.To calculate the standard deviation, the square of each value of x multiplied by its corresponding probability is summed. Then the square of the mean is subtracted from this result and the square root of the remainder is taken to calculate the standard deviation. For the given probability distribution, the standard deviation is calculated by summing the square of -2 multiplied by 0.12, 0 multiplied by 0.26, 3 multiplied by 0.28, 4 multiplied by 0.14 and 7 multiplied by 0.22. Then the square of the mean which is 3.142 is subtracted from this result and the square root of the remainder is taken which is 1.82.

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The probability of at most 2 phone calls received in a given day is roughly 0.021.

Since we are asked for the likelihood of a specific number of phone calls in a given day and are provided the average daily rate of phone calls, we must use the Poisson distribution to solve this problem.

Let represent the average daily call volume, which is provided as = 8.6. Following that, the likelihood of getting no more than two phone conversations in a day is:

P(X ≤ 2) = e^(-λ) * (λ^0/0!) + e^(-λ) * (λ^1/1!) + e^(-λ) * (λ^2/2!)

= e^(-8.6) * (8.6^0/0!) + e^(-8.6) * (8.6^1/1!) + e^(-8.6) * (8.6^2/2!)

≈ 0.021

Therefore, the probability of receiving no more than 2 phone calls in a given day is roughly 0.021.

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The number of different combinations that are possible for Nick, given his baseball hats are A. 4 combinations.

Nick has two options for hats, and two options for sweatshirts/sweaters. To find the number of combinations, we can multiply the number of options for each item.

There are two baseball hats and two clothes - sweatshirt and sweater.

The number of combinations is:

= 2 (hats) x 2 (sweatshirts/sweaters)

= 4 combinations

In conclusion, as regards the number of combinations that Nick can make, there are four.

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The correct statements regarding the linear functions are given as follows:

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

For Company P, the function is given as follows:

y = 30x + 50.

Meaning that:

From the table, for company R, the function is given as follows:

y = 25x + 75.

Meaning that:

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The domain of the function g(x) is given as follows:

x ≥ -1.

The domain of a function is composed by the set that contains all possible input values for the function.

The square root function is defined only for non-negative values, hence the domain is obtained as follows:

6x + 6 ≥ 0

6x ≥ -6

x ≥ -6/6

x ≥ -1.

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The average water level at the dock between 4 and 19 is 17.5 feet, calculated by taking the average of the water level at 4 and 19.

H(4) = 5 sin (pi/6 (4 - 6)) + 19 = 17

H(19) = 5 sin (pi/6 (19 - 6)) + 19 = 18

Average water level = (17 + 18)/2 = 17.5

The given equation is H(t) = 5 sin (pi/6 (t - 6)) + 19. This equation represents the water level at a dock over a 24 hour period, where t represents the time in hours. To calculate the average water level at the dock at 4 and 19, we need to first calculate the water level at 4 and 19. To do this, we substitute 4 and 19 in the equation in place of t. This gives us H(4) = 5 sin (pi/6 (4 - 6)) + 19 = 17 and H(19) = 5 sin (pi/6 (19 - 6)) + 19 = 18. The average water level is then calculated by taking the average of these two values, which is (17 + 18)/2 = 17.5. This is the average water level at the dock between 4 and 19.

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Answer:15

Step-by-step explanation:

We know this figure's all angles sum is equal to 180*(n-2)=180*3=540

so,

112+7x+5+6x+2+10x-8+4x+24=540

27x+135=540

27x=405

x=15

Answer:

Equivalent fractions.

Step-by-step explanation:

[tex]\dfrac{1}{2}\\\\\dfrac{2}{4}=\dfrac{2 \div 2}{4 \div 2}=\dfrac{1}{2}\\\\\\\dfrac{4}{8}=\dfrac{4 \div 4}{8 \div 4}=\dfrac{1}{2}[/tex]

So, they are equivalent fractions. Equivalent fractions are fractions with different denominators and numerators representing the same part of a whole.

Answer:

thet are equivalent fractions

Step-by-step explanation:

1/2*2/2=2/4,

2/4*2/2=4/8 or

The  Equation of Parabola shown in the graph is y=2x².

The general equation of a parabola is given by

y = a(x – h)² + k or x = a(y – k)² +h.

Here (h, k) denotes the vertex. y = a(x – h)² + k is the regular form. x = a(y – k)²+h is the sidewise form.

Given:

We have vertex (0, 0).

As, from the Graph the parabola is open up.

So, it is of the form y= ax², a>0.

Thus, the Equation of parabola is y=2x².

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Given that the area of the region bounded by the curve f(x) and x-axis from x=4 to x=10 is 13/5, the average value of the negative-valued function y=f(x) over the interval [4,10] is -13/30.

The average value of a function f(x) over an interval [a,b] is given by:

average value = (1/(b-a)) * integral from a to b of f(x) dx

In this case, we are given that the function y=f(x) is negative-valued, and the area of the region bounded by the curve and x-axis from x=4 to x=10 is 13/5. This means that the integral of f(x) over the interval [4,10] is equal to -13/5:

[tex]\int\limits^{10}_4 \, f(x) dx[/tex] = -13/5

To find the average value of f(x) over this interval, we divide this integral by the length of the interval:

average value = (1/(10-4)) * [tex]\int\limits^{10}_4 \, f(x) dx[/tex]

             = (1/6) * (-13/5)

             = -13/30

Therefore, the average value of the negative-valued function y=f(x) over the interval [4,10] is -13/30. This means that if we were to draw a horizontal line at the height of -13/30 over the interval [4,10], the area between this line and the x-axis would be equal to the area of the region bounded by the curve f(x) and x-axis over the same interval.

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Answer:

Tamika has painted 1/3 of the mural, and Li has painted 1/6 of it. To find the total part of the mural that they have painted together, we need to add these fractions:

1/3 + 1/6

We need to find a common denominator to add these fractions. The smallest common multiple of 3 and 6 is 6. We can convert 1/3 to 2/6 by multiplying the numerator and denominator by 2:

2/6 + 1/6 = 3/6

So, Tamika and Li have painted 3/6 of the mural in all. We can simplify this fraction by dividing both the numerator and denominator by 3:

3/6 ÷ 3/3 = 1/2

Therefore, Tamika and Li have painted 1/2 of the mural in all

The probability that a defective part made at this factory was made on the first assembly line is 0.299 or 29.9%,

This issue can be resolved using Bayes' theorem. Let L1, L2, and L3 represent the events that the component was produced on the first, second, and third assembly lines, respectively, and let D represent the event that a defective part is produced. Next, given that the part is defective, we want to determine P(L1 | D), which is the likelihood that the component was made on the first production line.

We can determine P(D), the overall likelihood of creating a defective part, using the rule of total probability:

P(D) = P(D | L1) P(L1) + P(D | L2) P(L2) + P(D | L3) P(L3)

= 0.02 × 0.29 + 0.04 × 0.27 + 0.01 × 0.44

= 0.0195

next, we can determine P(L1 | D) using Bayes' theorem:

P(L1 | D) = P(D | L1) P(L1) / P(D)

= 0.02 × 0.29 / 0.0195

= 0.299

As a result, there is a 29.9% chance that a defective component produced at this factory was made on the first assembly line, or about 0.299 of a chance.

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As per the tension the weight of the chain is 2.55 kg

The tension is the force exerted by a rope, cable, or chain on an object to which it is attached.

To solve this problem, we need to understand the relationship between tension and weight. The weight of an object is the force with which it is attracted towards the earth due to gravity.

Using the given magnitude of tension (25 N) for each end, we can rewrite this equation as:

25 N - 25 N = Weight of the section

Simplifying this, we get:

Weight of the section = 0 N

This means that the weight of a small section of the chain is negligible compared to the tension at each end. However, if we consider the entire length of the chain, the weight cannot be ignored.

To calculate the weight of the chain, we need to find its mass. We can do this using the formula:

Mass = (weight of the chain) / (gravitational acceleration)

We know that the tension at each end of the chain has a magnitude of 25 N. Since the chain is in equilibrium, the net force on the chain must be zero. This means that the weight of the chain must be equal to the tension at each end.

Therefore, we can write:

Weight of the chain = 25 N

Now we can use the formula for mass:

Mass = (25 N) / (9.8 m/s²)

Using a calculator, we get:

Mass = 2.55 kg

This confirms that the weight of the chain is indeed equal to the tension at each end, as expected.

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Complete Question:

The tension T at each end of the chain has magnitude 25 N (see the figure). What is the weight of the chain?

Answer: Solution set of the quadratic equation is, Empty set

Step-by-step explanation:

Given the quadratic equation:  

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract both sides by 1 we get;

Simplify:

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 6 we get;

Simplify:

For any x in real number there does not exist any number x which satisfy

, therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.

A graph that shows a slow and steady increase at first, followed by a steeper increase as the bottle approaches full capacity, would be the most accurate representation. Without seeing the available graphs, it's difficult to say which one is the best representation.

The best graph to represent the height of water in a spherical bottle as a function of the amount of water in the bottle is a non-linear graph that has a curved shape.

As the volume of water in the bottle increases, the height of the water will also increase, but not at a constant rate. The curve will become steeper as the bottle fills up, because the same amount of water will fill less and less of the remaining space in the bottle. Therefore, a graph that shows a slow and steady increase at first, followed by a steeper increase as the bottle approaches full capacity, would be the most accurate representation.

The height of water in a spherical bottle as a function of the amount of water in the bottle would be represented by a non-linear graph that has a curved shape. As the volume of water in the bottle increases, the height of the water will also increase, but not at a constant rate. The curve will become steeper as the bottle fills up, because the same amount of water will fill less and less of the remaining space in the bottle.

The most correct illustration would be a graph showing a gradual increase at initially, followed by a sharper increase as the bottle nears capacity. It's challenging to determine which graph is the best depiction without seeing the available graphs.

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The simplest way to calculate the surface area of a polyhedron, though, remains to simply sum the areas of the polygons that make up its faces. The surface area of a sphere has a very interesting formula. It depends solely on the radius of the sphere. The surface area of a sphere is equal to 4Π times the square of the radius of the sphere: 4Πr2.

The statement that " Homogeneous equation Ax = 0 has trivial solution if it has at least 1 free variable"  is FALSE .

For a system of Linear Equations, a free variable is a variable which can take any value, whereas

the Leading Variable is a variable which is determined by the values of the free variables.  

The presence of a free variable means that existence of a non trivial solution to Ax = 0  because a free variable corresponds to a column of A that does not contain a pivot position in the corresponding row of [A|0].

So , the corresponding variable can be set to any non zero value, which gives a non trivial solution to Ax = 0.

Therefore, we can conclude that the homogeneous equation Ax = 0 has the trivial solution if and only if the equation has no free variables.

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The given question is incomplete , the complete question is

The homogeneous equation Ax = 0 has the trivial solution if and only if the equation has at least one free variable. True or False ?