Write the equation of the line in fully simplified slope-intercept form.

Write The Equation Of The Line In Fully Simplified Slope-intercept Form.

Answers

Answer 1

Answer:

y = 1/2 x + 6

Step-by-step explanation:

m = (7 - 6 )/ 2-0

m = 1/2

y-8=1/2(x-4)

y=1/2x-4/2 +8

y=1/2+6


Related Questions

plz help ASAP with explanation

Answers

[tex]\displaystyle\bf \boxed{V=abh \ ; \ 1dm^3=1litre=1000cm^3} \\\\a=12cm \ ; \ b=8 cm ;\: h_1=7 \; ; \ h_0=h_1+h_2=?\\\\abh_2=1,2litre=1,2dm^3\ = 1200cm^3\\\\ 8\cdot 12 h_2=1200\\\\h_2=12.5 cm\: then \\\\h_0= 7+12,5=19,5 \\\\Answer : the \ height \ of \ the \ tank \ is \ 19,5 cm[/tex]

Which statement about a right triangle is true?

A: The length of each leg equals 1/2 of the hypotenuse.

B: The square of the hypotenuse is equal to the sum of the squares of the legs.

C: One leg is always longer than the hypotenuse.

D: A right triangle can have only one obtuse angle.

Answers

Answer:

the square of hypotenuse rs eqaul to the sum of the square of the legs

Using B.P.T., prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side. (Recall that your have proved it in class IX)

Answers

Answer:

See Explanation

Step-by-step explanation:

(For Diagram please find in attachment)

Given, Let Assume triangle ABC Where, DE is Parallel to BC & D is midpoint to AB . ∵ AD=DBTo Prove, E is the midpoint of AC.Proof, If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.

Since DE∥BC

∴ By Basic Proportionality Theorem,

AD/DB  = AE/EC

​ Since it is Given, AD=DB

∴ AE/EC  =1

AE=EC  (Proved)

Which rates are unit rates? Check all the apply.
12 apples: 3 baskets
9 students
1 table
87 pebbles per aquarium
10 apple slices for each child
$5 for 4 muffins

Answers

12:3
87 per aquarium
10 apples each child
5 for 4 muffins

The table shows information about some children.

Age 11 Age 12 Total
Girls 3
a
b
Boys
c
5 8
Total
d
13
e

A pupil is selected at random.
What is the probability of selecting a student aged 12?
Give your answer in its simplest form.

Answers

Answer:

[tex]P(Age\ 12) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

        Age 11    Age 12    Total  

Girls   3             5              8

Boys   1             3             4

Required

[tex]P(Age\ 12)[/tex]

The number of aged 12 children is:

[tex]Age\ 12 = 5 + 3[/tex]

[tex]Age\ 12 = 8[/tex]

The total number of children is:

[tex]Total=8+4[/tex]

[tex]Total = 12[/tex]

So, we have:

[tex]P(Age\ 12) = \frac{Age\ 12}{Total}[/tex]

[tex]P(Age\ 12) = \frac{8}{12}[/tex]

Simplify

[tex]P(Age\ 12) = \frac{2}{3}[/tex]

- During the summer, you work 5 hours a day as a lifeguard at a beach and
earn $8 each hour. Use properties of multiplication to find how much
money you earn during a 6-day work week.

Answers

Answer:

240 If its wrong pleas correct me

89 x , 16x , -30x please show your work .

Answers

Answer:

Step-by-step explanation:

89x = 89 * x

16x = 2 * 2 * 2 * 2 * x

-30x = -1 * 2 * 5 * 3 * x

x is the only factor that is common in all three.

GCF = x

Jac is reading this paragraph from The Code Book. Mathematicians have been studying factoring for centuries, and modern factoring techniques are not significantly better than ancient techniques. Indeed, it could be that the laws of mathematics forbid the existence of a significant shortcut for factoring. Which question will best help Jac apply the reading to his own life

Answers

Answer:

The answer is "What is important for me to understand?".

Step-by-step explanation:

It is because it is based also on the conclusion that the word in the text read the Jac can draw. Essentially, the particular excerpt read by Jac in his coding book explains that, whether old or new, all older techniques used in the past, compared with the new factorization methods, in truth all shortcuts in mathematics are not feasible and hence all steps have to occur. This implies Jac has to discover what really is important, what he must comprehend, and whether whatever tactics he is using are old and new. The same would be valid of life itself; irrespective of how he chooses to live his life, there are times where shortcuts cannot be used.

Can someone help me with this math homework please!

Answers

Answer:

the correct options are 1, 2, 5, and 6th

1. and 2.

all functions have a dependant variable y and independent variable x, and the set of dependant variables is called its range whereas the set of independent variables is called its domain.

5. and 6.

In a horizontal line 1 input associates itself with exactly one ouput, even tho the output is constant (same) for all values of x, and that's the property of a function

Answer:

all functions have dependent variables

all functions have an independent variable

a horizontal line Is an example of a functional relationship

What is the equation of the line graphed below?
5
-5
5
(1, -3)
-5
O A. y = 3x
B. y=-3x
c. y=-5
D. y =
-X

Answers

Answer:

C: y=-3x

Step-by-step explanation:

Rise over run: in this case you go down so -3/1=-3

What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0StartRoot x^2y^3 EndRoot +2 StartRoot x^3y^4 EndRoot +xy StartRoot y EndRoot

Answers

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

A Basket contains 3 types of fruits weighing 58/3 kg in all. If 73/9 kg of are apples,19/6 are oranges and the rest are pears. What is the weight of the pears in the basket?​

Answers

Answer:

Step-by-step explanation:

233 322

Write the ratio 5/36 as a fraction in simplest form.
Use the slash key (/) to indicate a fraction.

Answers

9514 1404 393

Answer:

 5/36

Step-by-step explanation:

5 and 36 have no common factors, so the fraction 5/36 is already in simplest form.

Answer:

[tex] \frac{5}{36} [/tex]

Step-by-step explanation:

#CARRYONLEARNING

72/8 divided by 8/7=

Answers

63/8.

When you divide 72/8 by 8/7, it is the same thing as doing 72/8 x 7/8 since you are just required to flip the numerator and the denominator the other way round in the 2nd fraction.

What is the domain of the ordered pairs shown in the graph?




{–2, –1, 0, 1}


{–2, –1, 0, 2}


{–1, 0, 1, 2}


{–2, 0, 2, 3}

Answers

Answer:

-2 0 2 3 this is the domain of the ordered pairs shown in the graph above

Se tienen tres tanques de la misma altura (5 metro) pero sus formas son diferentes. El primero es de base circular de 3 metros de radio, el segundo su base es elíptica y su eje mayor y menor mide 6 y 4 metros respectivamente. El último tanque es un cono invertido, con una base circular de 3 metros de radio. Si en todos se llena agua con un caudal de 1.5 litros por cada segundo, determine la razón de cambio de la altura respecto al tiempo.

Answers

Answer:

1.-dh/dt  =  5.31*10⁻⁵ m/seg

2.-dh/dt =   1.99*10⁻⁵  m/seg

3.-dh/dt  =  1.59*10⁻⁴  m/seg

Step-by-step explanation:PREGUNTA INCOMPLETA NO SE INDICAN LAS FORMAS DE LOS TANQUES.

Asumiremos que los tres tanques son:

el primero cilindro recto     de  Vc = π*r²*h      ( r es radio de la base y h la altura)

el segundo asumiremos que es eliptico recto de Ve = π*a*b*h aqui a y b son los ejes de la elipse y h la altura

El tercero es un cono invertido Vco  = 1/3 *π*r²*h  ( r es el radio de la base.

1.-Caso del cilindro

Vc = π*r²*h

Derivando en ambos miembros de la expresión tenemos:

dV(c) / dt  = π*r²*dh/dt

Sustituyendo

1.5 Lts/seg =  3.14 * (3)²*dh/dt  

1.5/1000 m³/seg  =  28.26 m² dh/dt

1.5/ 28260 m  =  dh/dt

Despejando dh/dt

dh/dt  =  1.5 / 28260    =  5.31*10⁻⁵ m/seg

dh/dt  =  5.31*10⁻⁵ m/seg

2.-La elipse

Ve  = π*a*b*h  

Aplicando el mismo procedimiento tenemos:

DVe/dt  =  1.5 Lts/seg  =  π* 6*4* dh/dt

1.5 /1000   =  75.36 *dh/dt

dh/dt =  1.5 / 75360  m/seg

dh/dt =   1.99*10⁻⁵  m/seg

3. El cono invertido

Vco = (1/3)*π*r²*h

DVco/dt =  (1/3)*π*r²*dh/dt

1.5/1000  =  9.42 *dh/dt

dh/dt  =  1.5/9420

dh/dt  =  1.59*10⁻⁴  m/seg

Find (4/5+3/6-5/12) ÷ 2/3​

Answers

Answer:

1/2 + 2/3 + 5/4 = 29/ 12 = 2 5/  12  ≅ 2.4166667

Step-by-step explanation:

Add: 1/ 2  + 2/ 3  = 1 · 3/ 2 · 3  + 2 · 2/ 3 · 2  = 3/ 6  + 4/ 6  = 3 + 4/ 6  = 7/ 6

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(2, 3) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 3 = 6. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - one half plus two thirds = seven sixths.

Add: the result of step No. 1 + 5/ 4  = 7/ 6  + 5/ 4  = 7 · 2/ 6 · 2  + 5 · 3/ 4 · 3  = 14/ 12  + 15/ 12  = 14 + 15/ 12 = 29/ 12

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 4) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 4 = 24. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths plus five quarters = twenty-nine twelfths.

hope it helps...

correct me if I'm wrong...

Factor 140c + 28 -14a to identify the equivalent expressions.

Answers

Step-by-step explanation:

140c+28-14a14(10c+2-a)

hope it helps

stay safe healthy and happy...

Please help me with this problem

Answers

Answer:

2nd one, 3rd one and last one

a set of data contains four values. the mode is 5, the range is 3 and the median is 5. the smallest value in the data set is 4. write the numbers in the data set.

Answers

Answer:

4,5,5,7

Step-by-step explanation:

The answer is 4,5,5,7

For the diagram below, which equation is the correct use of the distance formula?

Answers

Answer:

D

Step-by-step explanation:

asap help answer ---------

Answers

Answer:

[tex]C(n)=30-20n[/tex]

Step-by-step explanation:

Arithmetic sequence given in the question is,

10, -10, -30, -50........

Explicit formula of an Arithmetic sequence is given by,

[tex]C(n)=C(1)+(n-1)d[/tex]

Here, [tex]C_1=[/tex] First term

[tex]n=[/tex] number of terms

[tex]d=[/tex] common difference

From the given sequence,

[tex]C(1)=10[/tex]

[tex]d=-10-10[/tex]

  [tex]=-20[/tex]

Substitute the values in the formula,

[tex]C(n)=10+(n-1)(-20)[/tex]

[tex]C(n)=10-20n+20[/tex]

[tex]C(n)=30-20n[/tex]

Situation:
Find the substance's half-life, in days.
• Round your answer to the nearest tenth.
A 25 gram sample of a substance that's
used for drug research has a k-value of
0.1229.
Enter the correct answer.
N = Noe
-kt
DONE
No = initial mass (at time t = 0)
?
N = mass at time t
k = a positive constant that depends on
the substance itself and on the units
used to measure time
t = time, in days

Answers

Answer:

5.6 days

Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

t = 5.6 days

subject
Math, 25.02.2021 09:15 hajuyanadoy
Illustrate the following and determine the number of permutations. 1. Arranging 4 pots with different plants in a row
2. Forming a four-digit ATM pin.
3. Securing a motorcycle with a three-digit combination lock using the numbers 1, 2, 3 and 6
4. Displaying 3 identical small vases, 1 figurine, and a photo frame in a row
5. 3 girls sitting around a circular table​

Answers

Answer:

1: 16

2: 4940

3: 24

4: 25

5: 9

Step-by-step explanation:

A permutation is a method of calculating the number of possible outcomes. It follows the following general formula;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

There (n) is the number of objects, and (r) is the number of objects selected.

1. Arranging 4 pots with different plants in a row

In order to solve this, one needs two pieces of information, the number of objects, and the number of objects selected. One is given the number of objects; (4), but when the problem states "in a row" it never specifies how many plants are in a row. Thus, let one assume that a "row" can have an infinite amount of space, but in this case, only (4) space will be used. Therefore there are (4) objects with (4) objects selected. However, the drawback is that the combination formula doesn't work when the two parameters (n) and (r) are the same. Hence, to solve this special case, one simply multiplies the two numbers to get the answers:

[tex]n*r\\\\=4*4\\\\=16[/tex]

2. Forming a four-digit ATM pin

One is given that there are (4) digits in the ATM pin, this is the number of objects selected. One is also given that number of objects, there are (10) digits including (0). Set up the permutation and solve;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

[tex]_1_0P_4=\frac{10!}{(10-4)!}\\\\=\frac{10!}{6!}\\\\=\frac{10*9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}\\\\=10*9*8*7\\\\=4940[/tex]

3. Securing a motorcycle with a three-digit combination lock using the numbers (1), (2), (3), and (6).

There are (4) digits to choose from on the lock. But there are (3) numbers that can be selected.

[tex]_4P_3=\frac{4!}{(4-3)!}\\\\=\frac{4!}{1!}\\\\=\frac{4*3*2*1}{1}\\\\=4*3*2*1\\\\=24[/tex]

4. Displaying 3 identical small vases, 1 figure, and a photo frame in a row.

There are (5) objects, and (5) spaces (read problem (1) for an explanation for the objects being put in a row). Thus, this is a special case; multiply the two numbers to get the result;

[tex]n*r\\=5*5\\=25[/tex]

5. 3 girls sitting around a circular table

There are (3) subjects, and (3) spaces in this problem. Apply the same logic applies to a row in this problem. Therefore, this is another special case; multiply the two numbers to get the result;

[tex]n*r\\=3*3\\=9[/tex]

I don't exactly understand ​

Answers

Check this link: https://brainly.com/question/12053038

The same question is explained here :).

Hope it helps.

Which number line represents the solutions to -2x = -6?

Answers

Answer:

3

Step-by-step explanation:

-2x = -6

or, x = -6 / -2

or, x = 3

Carina spent a total of $5.27 buying a pineapple for $3.40 and some tomatoes that were on sale for $0.85 per pound ​

Answers

what's the whole question??

x + y = 15
5x - y = 9
Elimination method

(4, ? )

what number is the ?​

Answers

The ? Is 11.


You add the equations to get rid of one variable, then you have 6x=24 then you divide both sides and you have x=4, then you substitute the given value of x and you are left with 5*4 - y = 9. And the solution or well possible solution is y = 11 which gives youuuuu. (x , y) = (4 , 11)
4 + y = 15....1
20 - y = 9.....2

....1*5
20 + 5y = 75....3

....3 - .....2
4y = 60
y = 15

the answer for (?) is 15
i’m not sure if this 100% correct but i’m trying my best to help you

Which sentence represents the inequality -2b + 7 > 27.5?
A)Two times a number, plus seven, is less than twenty-seven and five tenths.
B)Two times a number, plus seven, is greater than twenty-seven and five tenths.
C)Negative two times a number, plus seven, is fewer than twenty-seven and five tenths.
D)Negative two times a number, plus seven, is greater than twenty-seven and five tenths. (Worth 10 points)

Answers

Answer:

C , negative two times a number, plus seven , is fewer than twenty-seven and five tenths

Answer:

D

Step-by-step explanation:

I got it right on edge

HELP ASAP PLEASE NOWWWW!!!!!!!!!!!!!!!

Answers

(x - [3])² + (y- [2])² = 16

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