write down the next two terms of the number pattern 2,5,8,11,14
​

The volume of each birthday hat is 56.55 in³ and the 12 hats has a total volume of 678.58 in³

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of a cone is given by:

volume = (1/3) * π * radius² * height

The cone that has a height of 6 inches and a radius of 3 inches. Hence:

Volume = (1/3) * π * 3² * 6 = 56.55 in³

For 12 hats:

Volume = 12 *  56.55 in³ = 678.58 in³

The volume of each birthday hat is 56.55 in³ and the 12 hats has a total volume of 678.58 in³

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Answer:

Area of shaded rectangle = 42 cm²

55%

Step-by-step explanation:

The length of the shaded area is equal to the length of the white rectangle.

Therefore, length of shaded rectangle = 7 cm

The width of the shaded rectangle is equal to the length of the white rectangle minus two widths of the white rectangle.

Therefore, width = 7 - (2 x 0.5) = 6 cm

Area of shaded rectangle = width x length

                                          = 6 x 7

                                          = 42 cm²

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Perimeter of a square = 4 × side length

If the perimeter of the square is 40 cm,
then the side length = 40 ÷ 4 = 10 cm

Area of a square = side length x side length

⇒ area of this square = 10 x 10 = 100 cm²

To determine the shaded area, calculate the areas of the 2 white triangles and subtract these from the area of the square.

Area of a triangle = 1/2 x base x height

⇒ area of left triangle = 1/2 x (10 - 7) x 10 = 15 cm²

⇒ area of right triangle = 1/2 x 10 x (10 - 4) = 30 cm²

Therefore, shaded area = 100 - 15 - 30 = 55 cm²

To calculate the percentage, divide the shaded area by the area of the square and multiply by 100:

(55 ÷ 100) × 100% = 55%

Answer:

The maximum profit is $854

Step-by-step explanation:

Profit is the difference between the revenue and the cost price of an item. It is given by:

Profit = selling price - cost price

Since x represent the profit made by the company, is related to the selling price of each widget, x and it is given by the formula:

y = -3x² + 155x - 1148

At maximum profit, dy/dx = 0, hence:

dy/dx = -6x + 155

0 = -6x + 155

6x = 155

x = 25.83

The maximum profit is at gotten when the selling price of each widget is 25.83. Hence:

y = -3(25.83)² - 155(25.83) - 1148

y = $854

Therefore the maximum profit is $854

Answer:

first would be a translation of (2,-3) second one is another 90 degree rotation counter clockwise.

Answer:

0.92 cm

Step-by-step explanation:

Do not pick 0.920 as it is the same as 0.92 but 0.92 is always the preferable option

The accurate measurement for the length of the green box is indeed 0.92 cm.

To measure the length of the green box accurately, we must carefully analyze the given image. By comparing the green box to the provided scale, we can deduce the correct measurement.

Upon examination, the green box appears to span almost the entirety of the "0.1 cm" scale division and extends slightly beyond it. Given that the box reaches around 9 divisions on the scale, it is reasonable to deduce that its length is 0.92 cm. This is because it's covering 9 divisions of 0.1 cm each, and considering the small extension.

Hence, the accurate measurement for the length of the green box is indeed 0.92 cm. This value takes into account its coverage of 0.9 cm (9 divisions) and a slight extension, aligning with the provided options.

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Answer:

Step-by-step explanation:

Assuming you can use any digit from 0-9

You can do 5% of 260 = 13 . All of which are different digits and not the same

This is true because 260 x .05 = 13

Answer:

68 degrees

Step-by-step explanation:

EHD and CHF are vertical angles, meaning their angle measures are the same.

Answer:

m<CHF = 68°

Step-by-step explanation:

Angles EHD and CHF are vertical angles, so their measures are equal.

m<CHF = m<EHD = 68°

Answer:

slope = [tex]\frac{1}{5}[/tex]

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (9, 6 ) and (x₂, y₂ ) = (4, 5 )

m = [tex]\frac{5-6}{4-9}[/tex] = [tex]\frac{-1}{-5}[/tex] = [tex]\frac{1}{5}[/tex]

well, we know that he makes $60 weekly, that'd be the 100%, we also know that he saves 30% of that and the rest, well, 100% - 30% = 70%, so 70% he spends it on food.

if we take 60 to be the 100%, what is 70% of it?

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 60 & 100\\ x& 70 \end{array} \implies \cfrac{60}{x}=\cfrac{100}{70}\implies \cfrac{60}{x}=\cfrac{10}{7} \\\\\\ 420=10x\implies \cfrac{420}{10}=x\implies 42=x[/tex]

Answer: look at the image

Step-by-step explanation:

Answer:

The one on top is y^8 - 1/y^8   (option 1)

The one on the bottom is 1/y^8 + 1/y^2  (option 5)

Answer:3

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

By the triangle midsegment theorem, 2(VX)=YZ.

This means that 2(t-25)=t, and thus t=50.

Answer:

c/6 ≥ -20

Step-by-step explanation:

The quotient of c and 6 basically means c divided by 6 (minor note: we also go by the order it's written in). We place in '≥' in this inequality because, greater than means '>' and the line underneath it signifies an equal to sign, and as a result of this, we get -20.

Answer:

4

Step-by-step explanation:

Answer:

Option 4 is correct.

Step-by-step explanation:

To find: Polynomial whose solution are not real numbers.

Given Polynomials are Quadratic Polynomial.

So, we can check if solution of quadratic polynomial by find & checking value of discriminant.

Standard form of Quadratic polynomial is given by

ax² + bx + c

then Discriminant, D = b² - 4ac

If, D > 0 ⇒ Solutions are distinct real numbers

if, D = 0 ⇒ Solutions are equal real numbers

if, D < 0 ⇒ Solutions are not real numbers (They are complex conjugates)

Option A:

By comparing with standard form

a = 1 , b = -6 , c = 3

D = (-6)² - 4 × 1 × 3 = 36 - 12 = 24 > 0

Thus, Solutions are Real numbers.

Option B:

By comparing with standard form

a = 1 , b = 4 , c = 3

D = (4)² - 4 × 1 × 3 = 16 - 12 = 4 > 0

Thus, Solutions are Real numbers.

Option C:

By comparing with standard form

a = -1 , b = -9 , c =-10

D = (-9)² - 4 × (-1) × (-10) = 81 - 40 = 41 > 0

Thus, Solutions are Real numbers.

Option D:

By comparing with standard form

a = 1 , b = 2 , c = 3

D = (2)² - 4 × 1 × 3 = 4 - 12 = -8 < 0

Thus, Solutions are not Real numbers.

Therefore, Option 4 is correct.

Answer: Division of Equality

Step-by-step explanation: In this equation, using division, we can find what y is by dividing 5 on both sides. Y equals to 15.

[tex]3x-17+x+40+2x-5=180\\3x+x+2x-17+40-5=180\\6x+18=180\\6x=180-18\\6x=162\\x=27[/tex]Answer:

Step-by-step explanation:

Since the sum of all interior angles of a triangle sums up to 180.

Answer:

At 9:39 they both will Flick

Step-by-step explanation:

so when the first light flicks it resets and starts counting to anthor 8 mins while the other takes 4 mins extra just keep adding till they both have same time

Answer/Step-by-step explanation:

 All of the solutions to the equation 3x^2 - 12 = 0 are x = 12 and x = -2

Answer: False

Explanation:

[tex]3x^2-12+12=0+12[/tex]

[tex]3x^2=12[/tex]

[tex]\frac{3x^2}{3}=\frac{12}{3}[/tex]

[tex]x^2=4[/tex]

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{4},\:x=-\sqrt{4}[/tex]

[tex]x=2,\:x=-2[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

There are two unique solutions to the equations (x-3)^2 = 16

Note: Each variable in the matrix can have only one possible value, and this is how you know that this matrix has one unique solution.

Answer: True

Explanation:

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=7,\:x=-1[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Ths solutions for the equation 2(x-3)^3 - 18 = 0 are x = 6 and x = 0

Answer: False

Explanation:

[tex]2\left(x-3\right)^3-18+18=0+18[/tex]

[tex]2\left(x-3\right)^3=18[/tex]

[tex]\frac{2\left(x-3\right)^3}{2}=\frac{18}{2}[/tex]

[tex]\left(x-3\right)^3=9[/tex]

[tex]\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}[/tex]

[tex]=\sqrt[3]{9}+3,\:x=\frac{6-\sqrt[3]{9}}{2}+i\frac{\sqrt[3]{9}\sqrt{3}}{2},\:x=\frac{6-\sqrt[3]{9}}{2}-i\frac{\sqrt[3]{9}\sqrt{3}}{2}[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Answer: False

Explanation:

[tex]2\left(x-5\right)^2-8+8=0+8[/tex]

[tex]2\left(x-5\right)^2=8[/tex]

[tex]\frac{2\left(x-5\right)^2}{2}=\frac{8}{2}[/tex]

[tex]\left(x-5\right)^2=4[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=7,\:x=3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

Answer: False

Explanation:

[tex]\left(x+3\right)^2-25+25=-8+25[/tex]

[tex]\left(x+3\right)^2=17[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{17}-3,\:x=-\sqrt{17}-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

Answer: False

Explanation:

[tex]\frac{2\left(2x-1\right)^2}{2}=\frac{18}{2}[/tex]

[tex]\left(2x-1\right)^2=9[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=2,x=-1[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The only solution for equation (2x-1)^2-49=0 is x = 4

Answer: False
Explanation:

[tex]\left(2x-1\right)^2-49+49=0+49[/tex]

[tex]\left(2x-1\right)^2=49[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=4,\:x=-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

Answer: True
Explanation:

[tex]3\left(x+2\right)^2-3+3=0+3[/tex]

[tex]3\left(x+2\right)^2=3[/tex]

[tex]\frac{3\left(x+2\right)^2}{3}=\frac{3}{3}[/tex]

[tex]\left(x+2\right)^2=1[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=-1,\:x=-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x  = -6

Answer: True

Explanation:

[tex]5x^2-180+180=0+180[/tex]

[tex]5x^2=180[/tex]

[tex]\frac{5x^2}{5}=\frac{180}{5}[/tex]

[tex]x^2=36[/tex]

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{36},\:x=-\sqrt{36}[/tex]

[tex]x=6,\:x=-6[/tex]

~Lenvy~

Answer:

  AA similarity postulate

Step-by-step explanation:

Triangles are similar if corresponding angles are congruent or if corresponding sides are proportional.

Here, the missing reason in the proof follows a step in which two angles are shown congruent. That means you can claim similarity by the AA similarity postulate.

__

Additional comment

The similarity postulates include ...

  AA -- two corresponding angles (the third angle is determined by these two)

  SSS -- three proportional corresponding sides

  AAS -- two congruent angles and a proportional corresponding side

  ASA -- a variation of AAS

  SAS -- proportional corresponding sides flanking a congruent angle

With the exception of AA, these are the same postulates as used to prove triangle congruence when the corresponding sides are congruent, rather than proportional.

Answer:

The price for each pound of tuna is not always the same.

Step-by-step explanation:

What we do is divide the price by the amount of tuna to find the price for each amount of tuna

For the 1st one, we have $8 for 2 tuna so we do 8/2

8/2 = 4

For the 2nd we have $16 for 4 so we do 16/4

16/4 = 4

For the 3rd, we have $27 for 9 so we do 27/9

27/9 = 3

Answer:

X= 5/18

Step-by-step explanation:

Answer:

okay so think of the polygon as like a rectangle in a way now use the method of finding a area with a triangle  

Step-by-step explanation:

A= bxh divide by 2 then A= bxh x 2

it worked for me

Answer:

x=-8

Step-by-step explanation:

5x-3x=-2-14

2x=-16

x=-8

Answer:

12

Step-by-step explanation:

Convert the 3 liters into milliliters and then divide it normally or in the fraction way

Answer:

V=4960in^3

S.A=2116in^2

Step-by-step explanation:

36x2

1- 72in^2

5-2=3in

8x3

2- =24in^2

5-2=3in

5+3=8in

8x10

3- =80in^2

36-(10+8)=

0.5×18×8

4-=72in^2

72+24+80+721

C.S.A=248in^2

V= 248×20

=4960in^3

248x2

1- =496in^2

36x20

2- =720in^2

20×2

3- =40in^2

20×5

4- =100in^2

20×8

5- =160in^2

20×20

6- =400in^2

20×10

7- =200in^2

=496+720+40+100+160+400+200

=2116in^2

Answer:

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

tanΘ = [tex]\frac{\sqrt{3} }{3}[/tex] , then

Θ = [tex]tan^{-1}[/tex] ( [tex]\frac{\sqrt{3} }{3}[/tex] ) = [tex]\frac{\pi }{6}[/tex]

since tanΘ > 0 then Θ is in first / third quadrants

Θ = π + [tex]\frac{\pi }{6}[/tex] = [tex]\frac{7\pi }{6}[/tex]

solution is { [tex]\frac{\pi }{6}[/tex] , [tex]\frac{7\pi }{6}[/tex] } in the interval 0 < Θ < 2π