WORTH 25 POINTS AND WILL MARK BRANLIEST Write an expression that can be used to determine the final cost of the cards. ThE ANSWER IS 0.8268 JUST NEED AN EXPRESSION

Answer:

x = 3 +√43, x = 3 - √43

Step-by-step explanation:

x^2 - 6x - 34 = 0

move the 34 across

x^2 - 6x = 34

take -6 and divide by two, then square it

(-6/2)^2 = 9

add the product to your equation

x^2 - 6 + 9 = 34 + 9

solve

(x - 3)^2 = 43

x - 3 = ± √43

x = 3 ± √43

Answer:

The answer is 6

Step-by-step explanation:

This is due to the nth term sequence going up by 6

Answer:

63

Step-by-step explanation:

5(13)-2 is 65-2 or 63.

Answer:

No, it is not correct. You should divide by 21 and 3.

Step-by-step explanation:

3x=21

x=7

Q 1)

3(x + 5) = 36

3x + 15 = 36

3x = 36 - 15

3x = 21

x = 21/3

x = 7

Verification:

3(x + 5) = 36

3(7 + 5) = 36

3(12) = 36

36 = 36

Hence proved that x = 7

Answer:

100 red balls and 20 blue balls.

Step-by-step explanation:

So to find out what you need to multiply the ratio by to get the answer, you add 10 and 2. That's 12. 120/12 is 10. 10:2 times 10 = 100: 20, so there are 100 red balls and 20 blue balls.

Answer:

I don't really know what you mean so I would say to just look on the tag but if you gave more info then I could help you out

The required expression is v(t) = 80,000 - $6000t

Cost of the truck =  $80,000

Depreciation rate = $6000/year

Cost price is that price for buyer which he pays to seller for an object or product.

Required expression-

m = $6000
t = time in years
b = original price
v(t) = mt + b
v(t) = -$6000t + $80000

negative sign for depreciation

Thus, the required expression is v(t) = 80,000 - $6000t

Learn more about cost price here:
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Answer:

A XD  (um i dont know what else to put sof frpijfpoemd-eod)

she cut the sum in (3+5+4) in 12 parts

J had 3/12 of the sum S

L had 5/12 of the sum S

and R had 4/12 of the sum S

4/12 x S = 320

S = 320 x 12/4

S = 960

$960 shared

Answer:

Rational

Step-by-step explanation:

An irrational number is any number that cannot be turned into a fraction. 7 can be turned into a fraction.

Answer:

  244 sq. ft.

Step-by-step explanation:

The net for a triangular prism consists of a central rectangle and two triangles. The length of the central rectangle is equal to the perimeter of the triangular faces.

__

The area of the central rectangle of the net is ...

  A = LW = (12 +7 +10 ft)(6 ft) = 174 ft²

The two triangles are right triangles, so the area of each is half the product of the leg lengths.

  A = 1/2(bh) = 1/2(10 ft)(7 ft) = 35 ft²

Then the sum of the rectangle and two triangles is ...

  surface area = 174 ft² +2 × 35 ft² = 244 ft²

Answer:

The slope is 0 or there is no slope.

Step-by-step explanation:

Only a y-intercept of -4.

Answer:

0

Step-by-step explanation:

The slope is defined as rise/run. Since y does not increase at all as x increases, the slope is 0.

Answer:

B. -3

Step-by-step explanation:

From (-1,4) it goes down 3 (rise) units then 1 unit (run) to the right. Simply, its sloping to the left, so negative.

Solving using slope formula:

y2-y1/x2-x1

4--2/ -1-1

6/-2

3/-1

-3

Answer:  B

Step-by-step explanation:

y2-y1/x2-x1

-2-4/1-(-1)

-6/1+1

-6/2

-3

Answer: 4 Hours

Step-by-step explanation:

It is 5,760.

Stay safe & humble <3

Answer:

A. If the dividend is greater than the divisor, the quotient will be greater than 1.

Step-by-step explanation:

Checking all options

A. If the dividend is greater than the divisor, the quotient will be greater than 1.

That is,

4 ÷ 3 = 1.33

Where,

4 is the dividend

3 is the divisor

1.33 is the quotient

THIS IS TRUE

B.If the dividend is less than the divisor, the quotient will be greater than 1

That is,

3 ÷ 4 = 0.75

Where,

3 is the dividend

4 is the divisor

0.75 is the quotient

NOT TRUE

C. If the dividend is equal to the divisor, the quotient will be less than 1

That is,

3 ÷ 3 = 1

Where,

3 is the dividend

3 is the divisor

1 is the quotient

NOT TRUE

D. If the dividend is greater than the divisor, the quotient will be less than 1.

That is,

4 ÷ 3 = 1.33

Where,

4 is the dividend

3 is the divisor

1.33 is the quotient

NOT TRUE

Therefore, option A is TRUE

Answer:

r=2

Step-by-step explanation:

r + 8 r + 11 = 29

( 1 + 8 ) r + 11 = 29 9 r + 11 = 29

Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:

9 r + 11 − 11 = 29 − 11

9 r + 0 = 18

9 r = 18

Now we can divide each side of the equation by 9 to get

r : 9 over 9 = 18 under 9

1 r = 2

r = 2

Answer: r = 2

Steps:  

r + 8r + 11 = 29

9r + 11 = 29

9r + 11 - 11 = 29 - 11

9r = 18

r = 2

plz mark brainliest

Answer:(that was a joke)

1.) acute

2.) right

3.) obtuse

4.) acute

5.) obtuse

6.) right

Step-by-step explanation:

if hes doing advanced stuff like isosceles equilateral and that then im sorry for the answer.

Answer:

[tex]m=\frac{17}{37}[/tex]

Step-by-step explanation:

When given two coordinates, you must use this formula to find the slope of a line:

[tex]m= \frac{y_{2} - y_{1}}{x_{2}-x{1}}[/tex]

where m is your slope.

So, plug in your coordinates. Remember, a coordinate is denoted by (x,y). So, for example, your [tex]x_{1}[/tex] would be -18 and your [tex]x_{2}[/tex] would be 19.

[tex]m =\frac{4--13}{19--18}[/tex]

[tex]m =\frac{17}{37}[/tex]

And that would be your slope. (Answer choice D.)

[tex] {n}^{2} - n - 56 = [/tex]

[tex](n - 8)(n + 7)[/tex]

_____________________________________________

[tex]a {x}^{2} + bx + c = 0[/tex]

[tex]delta = {b}^{2} - 4ac[/tex]

[tex]x(1) = \frac{ - b + \sqrt{delta} }{2a} \\ [/tex]

[tex]x(2) = \frac{ - b - \sqrt{delta} }{2a} \\ [/tex]

_____________________________________________

[tex] {n}^{2} - n - 56 = 0[/tex]

[tex]delta = ({ - 1})^{2} - 4(1)( - 56)[/tex]

[tex]delta = 1 + 224[/tex]

[tex]delta = 225[/tex]

Thus ;

[tex]n(1) = \frac{ - ( -1) + \sqrt{225} }{2 \times 1} \\ [/tex]

[tex]n(1) = \frac{1 + 15}{2} \\ [/tex]

[tex]n(1) = \frac{16}{2} \\ [/tex]

[tex]n(1) = 8[/tex]

[tex]n(2) = \frac{ - ( - 1) - \sqrt{225} }{2 \times 1} \\ [/tex]

[tex]n(2) = \frac{ 1 - 15}{2} \\ [/tex]

[tex]n(2) = - \frac{14}{2} \\ [/tex]

[tex]n(2) = - 7[/tex]

[tex]n(1) = 8[/tex]

[tex]n(1) - 8 = 0 \: \: \: (\alpha )[/tex]

[tex]n(2) = - 7[/tex]

[tex]n(2) + 7 = 0 \: \: \: \: \: ( \beta )[/tex]

_____________________________________________

[tex] \alpha \times \beta = [/tex]

[tex](n - 8)(n + 7)[/tex]

PLEASE CHECK THE ATTACHED FILE

We are given that ;

[tex]{\quad \longrightarrow \displaystyle \sf \lim_{x\to 0}\bigg\{1+\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]

Where p(x) is a polynomial of degree 4 , it will help us later, but let's do some manipulations first ;

Can be further written as ;

[tex]{:\implies \quad \displaystyle \sf 1+\lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=1}[/tex]

So, here p(x) is polynomial of degree 4, so it will be a biquadratic polynomial, so we will write p(x) in the form of general biquadratic polynomial, so p(x) = ax⁴ + bx³ + cx² + dx + e

Now, first find p(x)/x² ;

[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=\dfrac{ax^{4}+bx^{3}+cx^{2}+dx+e}{x^2}}[/tex]

[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=ax^{2}+bx+c+\dfrac{d}{x}+\dfrac{e}{x^2}}[/tex]

So now, as [tex]{\bf{x\to 0}}[/tex] , for any values of a, b, c, d and e, the RHS will approach ∞ iff d ≠ e ≠ 0, as the denominator of d and e will be approaching 0 and so the whole limit will be ∞ , but we want the limit to be approaching 1, so when if d = e = 0, the denominator of d and e will be approaching 0 (not absolutely 0), and if d = e = 0, we will have the limit be approaching ax²+ bx + c for x approaching 0 being the limit 1 , and for any values of a, b and c . So now we have ;

[tex]{:\implies \quad \displaystyle \bf \lim_{x\to 0}\dfrac{p(x)}{x^{2}}=\begin{cases}\bf \infty \:, iff\: d\neq e\neq 0 \\ \\ \bf 1\:, iff\: d=e=0\end{cases}}[/tex]

So, now we had to consider the second case, for which the limit is approaching 1, for d = e = 0, so the limand here will just be ax² + bx + c

Now, we so have ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}ax^{2}+bx+c=1}[/tex]

Putting the limit we will have ;

[tex]{:\implies \quad \sf c=1}[/tex]

So, now as p(x) have extremum at 1 and 2, so p'(x) = 0, for x = 1, 2 , so now finding p'(x)

[tex]{:\implies \quad \sf p(x)=ax^{4}+bx^{3}+x^{2}\quad \qquad \{\because c=1\: and\: d=e=0\}}[/tex]

So, differentiating both sides wr.t.x ;

[tex]{:\implies \quad \sf p^{\prime}(x)=4ax^{3}+3bx^{2}+2x}[/tex]

Now, p'(1) and p'(2) must be 0

[tex]{:\implies \quad \sf p^{\prime}(1)=4a+3b+2=0}[/tex]

[tex]{:\implies \quad \sf p^{\prime}(2)=32a+12b+4=0}[/tex]

So, now we have ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 4a+3b=-2 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]

On multiplying first equation by 8 on both sides we can thus obtain ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 32a+24b=-16 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]

On solving both the equations we will be having ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf a=\dfrac{1}{4} \\ \\ \bf b=-1\end{cases}}[/tex]

So , now as d = e = 0, c = 1, a = (1/4), b = -1, so putting all the values in p(x) we can obtain p(x) as ;

[tex]{:\implies \quad \sf p(x)=\dfrac{1}{4}(x)^{4}-(x)^{3}+x^{2}}[/tex]

Now, at x = 2 ;

[tex]{:\implies \quad \sf p(2)=\dfrac{1}{4}(2)^{4}-(2)^{3}+2^{2}}[/tex]

[tex]{:\implies \quad \sf p(2)=4-8+4=8-8}[/tex]

[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{p(2)=0}}}[/tex]

This is the required answer

volume of cylinder = 3.14×1.5×1.5×4

1.34×2.25×4=

1.34×9=

12.06 in³

volume of cone =1/3×3.14×2×2×6

1/3×3.14×4×6

1/3×3.14×24

3.14×8

=25.12 in³

therefore he need to buy the cone shaped cup

Answer:

= 1= RHS

Step-by-step explanation:

shee i got u bud ok LHS-

(1+cot^2A)(1+cosA)(1-cosA)

=Cosec^2A(1-cos^2A)

=1/sin^2A×(sin^2A)

= 1= RHS

Hope this helps~! Brainliest is 'preciated if it does!