Answer:
.
Explanation:
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 2.10 cm from the axis to equal 5.00×105 g (where g is the free-fall acceleration)
Answer:
ω = 15275.25 rad/s
Explanation:
Given that,
Radial acceleration of an ultracentrifuge is, [tex]a=5\times 10^5g[/tex]
Distance from the axis, r = 2.1 cm = 0.021 m
g is the free-fall acceleration such that g = 9.8 m/s²
We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :
[tex]a=r\omega^2[/tex]
Putting all the values,
[tex]\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5\times 10^5\times 9.8}{0.021}} \\\\\omega=15275.25\ rad/s[/tex]
So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.
Which piece of ice has the most thermal energy?
A. A 10 g ice cube at -1°C
B. A 10 g ice cube at -3°C
C. A 10,000 g ice sculpture at -2°C
D. A 10,000 g ice sculpture at -1°C
Answer:
(B.) sorry if I'm wrong
Explanation:
Answer:
D.
Explanation:
It is D. A 10,000 g ice sculpture at -1 c
Two cars traveling in the same direction pass you at exactly the same time . The car that is going faster
moves farther in the same amount of time.
Explanation:
based on my answer......
we supposed to assume that both cars are equal except for speed. So they would have the same mass.....
Anyway, the question doesn't tell you anything about weight or size, so you can't tell from the information given which has more mass.
But the very definition of 'faster' is 'moves farther in the same amount of time'.
Hope this helps
Answer:
They both moves at the same speed
Explanation:
hope it works
Convert 56,340,040 meters into scientific notation?
Answer:
5.634004 × 10^7
Explanation:
the number 7 is for the numbers before the number 5
what is 25.61 cm to Gm?
Explanation:
25.61 cm * 1 Gm
100000000000 cm = 2.561e-10 Gm
1 Gm = 10^9 m =10^11 cm
then 10^11 cm = 1Gm
25.61 cm = 25.61 /10^11
=25.61 * 10^-11 Gm
what is the initial position
Answer:
Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.
hope it is helpful...
Which of the following graphs shows the motion of an object that starts to travel forward, stops for several seconds, then returns to its original position?
Answer:
Pls can you send the following graphs
1- Write Gauss’ Law.
2- Consider an electric field line passing through a closed surface. What is the sign of the flux if:
a) The line passes from inside to outside?
b)The line passes from outside to inside?
Think of a conductor as having both positive and negative mobile charges. Consider a conductor in electrostatic equilibrium – that is, whose charges are stationary.
3- Given that all of the charges are stationary, what must the E-field be at any point inside of the conductor?
1)The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.
PHYSICS HELP URGENT!!! While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 7.59 m/s. The stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand. At what speed does the stone impact the ground? Ignore air resistance and use =9.81 m/s2 for the acceleration due to gravity. I need help finding out the impact speed, please.
Answer:
v = 20.69 m/s
Explanation:
Given that,
Initial speed of a stone, u = 7.59 m/s
he stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand, h = 18.9 m
We need to find the speed of the stone impact the ground. Let the speed be v. Using the equation of kinematics to find v. So,
[tex]v^2-u^2=2as[/tex]
Here, a = g
So,
[tex]v^2=2gs+u^2\\\\v=\sqrt{2gs+u^2} \\\\v=\sqrt{2\times 9.81\times 18.9+(7.59)^2} \\\\v=20.69\ m/s[/tex]
So, the speed of the stone impact the ground is 20.69 m/s.
derive ideal gas equation for n mole of gas.
Answer:
Explanation:
Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,
the relationship for these variables PV=nRT where R gas constant is called the ideal gas law
Derivation of the Ideal Gas Equation
Let us consider the pressure exerted by the gas to be ‘p,’
The volume of the gas be – ‘v’
Temperature be – T
n – be the number of moles of gas
Universal gas constant – R
According to Boyle’s Law,
it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.
i.e. v∝1p ………………………………(i)
According to Charles’ Law,
When p & n are constant, the volume of a gas bears a direct relation with the Temperature.
i.e. v∝T ………………………………(ii)
According to Avogadro’s Law,
When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.
i.e. v∝n ………………………………(iii)
Combining all the three equations, we have-
v∝nTp
or pv=nRT
where R is the Universal gas constant, which has a value of 8.314 J/mol-K
I don't quite understand. Can you help please?
If such a particle is moving, with respect to the laboratory, with a speed of 0.950 c , what average lifetime is measured in the laboratory?
Complete Question
The positive [tex]muon (^+)[/tex], an unstable particle, lives on average [tex]2.20 * 10^{-6}\ s[/tex] (measured in its own frame of reference) before decaying.
If such a particle is moving, with respect to the laboratory, with a speed of 0.950 c , what average lifetime is measured in the laboratory?
Answer:
The value is [tex]\Delat t = 7.046 *10^{-6} \ s[/tex]
Explanation:
From the question we are told that
The the average live time of [tex]muon (^+)[/tex] is [tex]\Delta t_o = 2.20 *10^{-6} \ s[/tex]
The speed of of [tex]muon (^+)[/tex] in the laboratory is [tex]v = 0.950 c[/tex]
Generally the average life time of the positive [tex]muon (^+)[/tex] measured in the laboratory is mathematically represented as
[tex]\Delat t = \frac{\Delta t_o }{ \sqrt{1 - \frac{v^2}{c^2} } }[/tex]
[tex]\Delat t = \frac{2.20 *10^{-6}}{ \sqrt{1 - \frac{(0.950 c)^2}{c^2} } }[/tex]
[tex]\Delat t = \frac{2.20 *10^{-6}}{ \sqrt{1 - \frac{0.9025 c^2}{c^2} } }[/tex]
[tex]\Delat t = \frac{2.20 *10^{-6}}{ \sqrt{1 - 0.9025 } }[/tex]
[tex]\Delat t = \frac{2.20 *10^{-6}}{ \sqrt{ 0.0975 } }[/tex]
[tex]\Delat t = 7.046 *10^{-6} \ s[/tex]
Which electromagnetic wave is used in dental scans?
Answer:
X-rays are most often used to examine bones and teeth.
Hope this helps!
In 2.5 s, a car increases its speed from 60 km/h to 65 km/h while a bicycle goes from rest to 5 km/h. Which undergoes the
greater acceleration?
What is the acceleration of each? (Don't forget your units when reporting answers).
Answer:
Same, 2 km/h/s
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The car's acceleration is:
a = (65 km/h − 60 km/h) / 2.5 s
a = 2 km/h/s
The bicycle's acceleration is:
a = (5 km/h − 0 km/h) / 2.5 s
a = 2 km/h/s
-5 1/3 - 2 1/3 in math
Answer:
3
Explanation:
5 1/3 - 2 1/3 = 3
Broken down: 1/3 - 1/3 = 0 5 - 2 = 2
10 points
If a boat traveling East has a Net Force of 324 N, and the wind blowing
West has a Net Force of 789 N. What is the overall Net Force and which
side?
465 N, East
465 N, West
1113 N, West
1113 N, East
Answer:
465 N,East ............
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the width of the central bright spot on the screen change if the slit width is doubled? A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the width of the central bright spot on the screen change if the slit width is doubled? It will be cut in half. It will double. It will become eight times as large. It will be cut to one-quarter its original size. It will become four times as large.
Answer:
It will be cut in half
Explanation:
The diffraction of a slit is given by the formula
a sin θ = m where
a = width of the slit,
λ = wavelength and
m = integer that determines the order of diffraction.
Next we divide both sides by a, we have
sin θ = m λ / a
Also, recall that
a’ = 2 a
Then we substitute in the previous equation
2asin θ' = m λ, if divide by 2a, we have
sin θ' = (m λ / 2a).
Now again, from the first equation, we said that sin θ = m λ / a, so we substitute
sin θ ’= sin θ / 2
Then we use trigonometry to find the width, we say
tan θ = y / L
Since the angle is small, we then have
tan θ = sin θ / cos θ
tan θ = sin θ, this then means that
sin θ = y / L
we will then substitute
y’ / L = y/L 1/2
y' = y / 2
this means that when the slit width is doubled the pattern width will then be halved
Will give brainliest!!!!! Help asap
Answer:
Correct choice: 5,400 Km/h
Explanation:
Unit Conversions
We'll use the following conversions:
1 Km = 1,000 m
1 h = 3,600 s
Convert the speed of sound in water (1.5\cdot 10^3\ m/s) to Km/h:
[tex]\displaystyle 1.5\cdot 10^3\ m/s*\frac{ 3,600\ s/h}{ 1000 \ Km/m}[/tex]
[tex]=5,400\ Km/h[/tex]
Correct choice: 5,400 Km/h
The coefficient of friction for an object sliding across a rough floor is 0.7. A 125 N horizontal force causes the object to accelerate at 1.2 m/s2 . What is the objects weight
Answer:
152 N
Explanation:
From the question,
F-F' = ma................. Equation 1
Where F = Horizontal force, F' = Frictional force, m = mass of the object, a = accleration of the object.
But,
F' = mgμ............... Equation 2
Where g = acceleration due to gravity, μ = coefficient of friction.
make m the subject of the equation
Substitute equation 2 into equation 1
F-mgμ = ma.
make m the subject of the equation
m = F/(gμ+a).............. Equation 3
Given: F = 125 N, g = 9.8 m/s², μ = 0.7, a = 1.2 m/s²
Substitute these value into equation 3
m = 125/[(9.8×0.7)+1.2)
m = 125/8.06
m = 15.51 kg.
But,
W = mg.............. Equation 4
Where W = weight of the object.
W = 15.51(9.8)
W = 152 N
Do 2. A cyclist starts from rest and accelerates along a straight path to a speed of
12.15 m/s in a time of 4.5 seconds.
What is the cyclist's acceleration to the nearest tenth?
O
54.7 m/s2
o
24.3 m/s?
2.7 m/s2
De
3.4 m/s?
The cyclist's acceleration to the nearest tenth is: C. 2.7 [tex]m/s^2[/tex].
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).Final velocity = 12.5 m/s.Time = 4.5 seconds.To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]A = \frac{V - U}{t}[/tex]
Where:
A is the acceleration.V is the final velocity.U is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}[/tex]
Acceleration, A = 2.7 [tex]m/s^2[/tex]
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 [tex]m/s^2[/tex].
Read more: https://brainly.com/question/8898885
Which two types of waves require matter in order to travel A:light waves B:sound waves C:electromagnetic waves D:Water waves
Answer:
Sound Waves
Light Waves
Explanation:
A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotates horizontally about one end while the pilot is seated at the other end. In order to achieve a radial acceleration of 29.9 m/s2 with a beam of length 5.33 m , what rotation frequency is required
Answer:
Rotation frequency is 0.377 hertz.
Explanation:
After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:
[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)
Where:
[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.
[tex]\omega[/tex] - Angular velocity, measured in radians per second.
[tex]L[/tex] - Length of the beam, measured in meters.
Now we clear the angular velocity within:
[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]
If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:
[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]
[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]
The frequency is the number of revolutions done by device per second and can be found by using this expression:
[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)
Where [tex]f[/tex] is the frequency, measured in hertz.
If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:
[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]
[tex]f = 0.377\,hz[/tex]
Rotation frequency is 0.377 hertz.
explain what happent to the pressure exerted by an object when the area over which it is exerted:
a) increase
b) decrease
I forgot how to breath
Answer:
1-steal an inhaler 2-use it 3-your good
orrrr
1-swallow air(preferably air from space)
Answer:
then breath
Explanation:
If a car travels 600m west in 25 seconds, what is its velocity?
Answer:
The answer is 24 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{600}{25} \\ [/tex]
We have the final answer as
24 m/sHope this helps you
A sports car of mass 1.00x103 kg can accelerate from rest to 30.0 m/s in 7.00 s. What is the average forward force on the car?
Answer:
Explanation:
Before you can find the force, you need to find the acceleration.
Givens
vi = 0
vf = 30 m/s
t = 7 seconds
Formula
a = (vf - vi) / t
Solution
a = (30 - 0)/7
a = 4.28 m/s
Now you can look at the Force
F = m * a
F = 1.00*10^3 * 4.28
F = 4.28 * 10^3 N
You do 32 joules of work using a pair of scissors. The scissors do 25 joules of
work cutting a piece of fabric. What is the efficiency of the scissors?
Answer:
Efficiency = 65%
Explanation:
The formula of Efficiency applied to any circumstance is:
Efficiency = Useful Energy / Energy applied
Then replacing the values given its:
Efficiency = 25 J / 32 J
Efficiency = 0.65
0.65 written as percentage is 65%, then:
Efficiency = 65%
As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.
What is efficiency?
Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.
The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.
Mathematically,
efficiency of a machine = (work output/work input)×100%
Given parameters:
Input work to the pair of scissors= 32 joules.
Output work from the pair of scissors= 25 joules.
Hence,
The efficiency of a machine = (work output/work input)×100%
= ( 25 joule/32joule)×100%
= 78.125%
Learn more about efficiency here:
https://brainly.com/question/14502027
#SPJ2
A bar of gold has a temperature of 22 Celsius, and a bar of aluminum has a temperature of 27 Celsius. Which statement explains why the bar of aluminum as a higher temperature
Answer:Type of metal
Explanation:Basically certain types of metal may heat and get cold faster maybe the alumm may collect more sun and heat more and stay that way
Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.
What is meant by thermal conductivity ?The ability of a material to conduct or transport heat is referred to as thermal conductivity.
Here,
It is not the solid itself that moves in bulk as a result of thermal conductivity; rather, it is molecular agitation and contact.
A region of high temperature and high molecular energy is moved towards a region of lower temperature and lower molecular energy via a temperature gradient.
The density of aluminium is small. It is easily castable, machinable, and formable, and it has a high thermal conductivity and great corrosion resistance.
At 20 °C, gold has an electrical resistivity of 0.022 micro-ohm m and a thermal conductivity of 310 W m-1 K-1.
Aluminium conducts more heat than gold.
Hence,
Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.
To learn more about thermal conductivity, click:
https://brainly.com/question/23897839
#SPJ7
which one is not a derived unit?
1. Hertz
2. mol
3. Watt
4. Newton
Answer:
mol
Explanation:
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A 1250 kg car was traveling at 10 m/s toward a traffic signal when the light suddenly turned red. The driver slammed on his brakes, stopping the car in 3.3 seconds. What was the acceleration of the car ?
Answer:
a = - 3 m/s^2 (negative 3 meters per second squared)
Explanation:
We use the formula for acceleration as the change in velocities (from initial velocity "vi" to final velocity "vf") divided the time "t" it took. In our case:
a = (vf - vi) / t = (0 - 10) / 3.3 = -10 /3.33 = -3 m/s^2