Will a projectile follow a perfectly parabolic path when there is no air resistance?

Answers

Answer 1

A projectile will follow a perfectly parabolic path when there is no air resistance because of gravity:

In kinematics, the term "acceleration of a particle" is used to describe the rate at which velocity changes in a given direction and over a given time. When a particle moves vertically, it is sometimes referred to as gravity-induced acceleration.

The acceleration caused by gravity always operates downward in a parabolic path when there is no air resistance, and the velocity vector always acts perpendicular to the path.

At the topmost point, when the acceleration acts downward and the velocity is tangent to the path, it will automatically act in a perpendicular direction to the acceleration, as mentioned in section A concerning the path of the acceleration and the velocity.

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Answer 2

To find the vector components of a vector with respect to two orthogonal vectors, we can use the projection formula. Let's first find the projection of  on the vector :

proj  = (( · ) / ( · ))

= ((-9)(-6) + (-1)(2)) / ((-9)^2 + (-1)^2)

= -56/82

= -28/41

Now, let's find the vector  in the direction of :

in  = proj  = (-28/41)  

To find  perpendicular to , we can subtract  from :

⊥  =  - in  

⊥  =  [6/41, -28/41]

Therefore, we can write  as the sum of two orthogonal vectors:

=  in  + ⊥  

= [-9, -1]

= [-9*(-28/41) , -1*(-28/41)] + [6/41, -28/41]

= [252/41, -28/41] + [6/41, -28/41]

= [258/41, -56/41]

Thus, we have decomposed into two orthogonal vectors,  in  the direction of  and ⊥ perpendicular to.

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Related Questions

A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is 700 , and the total resistance (air drag plus friction with the runway) on each may be assumed constant and equal to 2800 . The tension in the towrope between the transport plane and the first glider is not to exceed 12000 . Part A If a speed of 40 is required for takeoff, what minimum length of runway is needed? Express your answer using two significant figures. Part B What is the tension in the towrope between the two gliders while they are accelerating for the takeoff? Express your answer using two significant figures. Please try to explain how you get to the answer. Don't just give the answer alone. Thank you!

Answers

The maximum length of runway needed and tension in the towrope will be 175.05 m and 5999N.

For solving this question we will use the laws of Kinematics as well as the Newton's Laws of Motion. According to the third law of Kinematics

v² = u² + 2aS ; where v is the final velocity, u is the initial velocity, a is the acceleration and S is the displacement.

According to Newton's Laws of Motion we know that the net force is equal to product of mass and acceleration that is

F = ma ; where F is net force, m is mass of the body and a is the acceleration.

Now, form the free body diagram of the gliders, we balance the forces by Newton's law of motion as:

For glider 1 the forces in x axis will be:

T₁ - T₂ - f = ma                                                    ......(1)

where T₁ and T₂ are tensions on glider 1 and 2 respectively and f is the frictional force.

In y axis the forces will be:

N₁ - W = 0 ; where N₁ is the normal on first glider and W is the weight due to gravity.

For glider 2 the forces in x axis will be:

T₂ - f = ma                                                           ......(2)

where T₂ is tensions on glider 2 and f is the frictional force.

In y axis the forces will be:

N₂ - W = 0 ; where N₂ is the normal on second glider and W is the weight due to gravity.

From equation (1) and (2) we get

T₁ - 2f = 2ma

a = T₁ - 2f/2m

a = 12000 - 2(2800)/2(700)

a = 6400/1400

a = 4.57 m/s²

Now from laws of Kinematics we have

v² = u² + 2aS; here the initial velocity is zero so u = 0 and v = 40 m/s

(40)² = 0 + 2 × 4.57 × S

S = 1600/9.14

S = 175.05 m

Now for the tension in the second rope of glider we use equation (2) that is

T₂ - f = ma

T₂ = ma + f

T₂ = 700 × 4.57 + 2800

T₂ = 3199 + 2800

T₂ = 5999 N

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Given that the human body is mostly made of water, estimate the total amount of positive charge in a 70 kg person. Express your answer to two significant figures and include the appropriate units.

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The estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

Since the human body is mostly made of water, we can assume that the total amount of positive charge is equal to the total amount of sodium ions (Na+) and other positively charged ions in the body.

The concentration of sodium ions in the human body is approximately 140 milliequivalents per liter (mEq/L), which is equivalent to 0.140 moles per liter (mol/L).

Assuming that the total volume of water in a 70 kg person is approximately 42 liters, we can estimate the total amount of sodium ions in the body as follows:

Total amount of sodium ions = concentration x volume of water
Total amount of sodium ions = 0.140 mol/L x 42 L
Total amount of sodium ions = 5.88 mol

Since each sodium ion has a charge of +1, the total amount of positive charge in a 70 kg person is also 5.88 C.

Therefore, the estimated total amount of positive charge in a 70 kg person is 5.88 Coulombs (C).

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(1 point) let f(t) be the number of centimeters of rainfall that has fallen since midnight, where t is the time in hours. match the following statements to their interpretations, given below. (a) f(6)

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This statement refers to the value of the function f(t) at t = 6, which represents the amount of rainfall that has fallen since midnight up to 6 AM.

To find the value of f(6), we would need to know the rainfall rate at different times and integrate it with respect to time from midnight to 6 AM. If we have this information, we can plug in t = 6 into the function f(t) and obtain the corresponding value in centimeters.The value of f(6) is important because it can give us an idea of how much rainfall has fallen during the first six hours of the day, which can be useful in predicting the total rainfall for the day or assessing potential flooding risks. Additionally, knowing the rate of rainfall at different times can help us plan for water management and make informed decisions regarding outdoor activities.

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A box slides down an inclined plane 37° above the horizontal. The mass of the block, m, is 35 kg, the coefficient of kinetic friction is 0.3 and the length of the ramp, d, is 8 m. (a) How much work is done by gravity? (b) How much work is done by the normal force? (c) How much work is done by friction? (d) What is the total work done?(1690J; 0; -671J; 1019J)

Answers

part a.

the work done by gravity is approximately 1690 J.

part b.

the work done by the normal force is 0.

part c.

the work done by friction is approximately -671 J

part d.

the total work done is approximately 1019 J

What is work done?

work done is described  as the multiplication of magnitude of displacement d and the component of the force that is in the direction of displacement.

For part a, the work done by gravity can be found using the formula:

W_gravity = mgh

h = dsin(37°) = 8sin(37°) = 4.83 m

W_gravity = (35 kg) * (9.81 m/s^2) * (4.83 m) ≈= 1690 J

In conclusion, the same pattern can be followed to calculate for b, c and d.

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Sally was removing her nail polish to get ready for a dance. She was also drinking a bottle of water. The doorbell rang and she rushed to answer it, leaving the open bottle of nail polish remover (acetone) and the bottle of water open. Sally forgot about them until the next morning and when she checked, the nail polish remover (acetone) was empty and the water looked untouched.

Sally believes the particles in water stick together more. In terms of your knowledge of the strength of electrical forces and the structure of substances, explain Sally's statement.

Answers

This is because water vapour present in air collide with the surface of cold water bottle which and condenses into water droplets. These water droplets collect and form a puddle of water around the bottle.

Two identical beads, each have a mass m and charge q. When placed in a hemispherical bowl of radius R with frictionless, non-conducting walls, the beads move and at equilibrium they are at a distance R apart (as shown in figure). Determine the charge on each bead :

Answers

The charge on each identical bead is calculated to be q = √[4πε/√3× (R² m g)].

The mass of the two identical beads is given as m.

The charge on each bead is q.

The radius of the hemispherical bowl is R.

The beads are said to be in equilibrium.

For the charges to balance at a point, the force of electric repulsion along the tangent should balance the force of gravitation along the tangent.

1/4πε q²/R² cos 30° = m g cos 60°

1/4πε q²/R² (√3/2) = m g (1/2)

√3/4πε q²/R² = m g

q² = (4πε)/√3 × (R² m g)

q = √[4πε/√3× (R² m g)]

Thus, the charge on each bead is calculated to be √[4πε/√3× (R² m g)].

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A SOLID OF MASS 1.3KG Suspended by a spring Is Completely Immersed in H₂0. If the tension in the spring is 6N. Calculate: a. upthrust on the solid b. the volume of the solid c. Density (take g=10m/s², density of H₂0= 1000kg/m³)​

Answers

a. Upthrust on the solid:

[tex]Upthrust = volume of solid * density of fluid * g = 1000 kg/m^3 * volume of solid * 10 m/s^2[/tex]

b. Volume of the solid:

[tex]volume = mass/density = 1.3 kg / (1000 kg/m^3) = 1.3 x 10^-3 m^3[/tex]

c. Density of the solid:

So,[tex]density = mass/volume = 1.3 kg / (1.3 x 10^-3 m^3) = 1000 kg/m^3[/tex]

What is upthrust?

Upthrust is the upward force exerted on an object immersed in a fluid. It is equal to the weight of the fluid displaced by the object and acts in the opposite direction to gravity. Upthrust helps to counteract the weight of the object and keep it afloat.

a. The upthrust on an object immersed in a fluid is equal to the weight of fluid displaced by the object. The weight of fluid displaced can be calculated using the formula:

Weight of fluid = volume of fluid * density of fluid * g

Since the solid is completely immersed in water, the volume of the fluid displaced is equal to the volume of the solid. The density of water is given as 1000 kg/m^3, and the acceleration due to gravity is given as[tex]10 m/s^2.[/tex]

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physics conclusion question:explain why the reading on a scale would be less after leaving the top floor and heading downward.

Answers

The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

What is gravity ?

Gravity is a fundamental force of nature that exists between all objects that have mass or energy. It is the force that pulls two objects towards each other, and it is what keeps objects like planets, stars, and galaxies in their orbits.

The force of gravity is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them. This means that the greater the mass of the objects and the closer they are to each other, the greater the force of gravity between them.

Gravity is responsible for many phenomena that we observe in our daily lives, such as keeping us and other objects on the surface of the Earth, causing tides in the ocean, and making objects fall to the ground when we drop them. It is also a key concept in the fields of astronomy and astrophysics, as it is what allows us to understand the motion and behavior of celestial objects in the universe.

Hence, The reading on a scale could be less after leaving the top floor and heading downward due to the effect of gravity on the body.

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isotope A: 95
ending measure weight 5.9
half life 6 days
what day was isotope measured

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If the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.

What is an Isotope?

Isotope may be defined as the type of atom in which the number of neutrons differs and the number of protons is the same. They are atoms of the same element, having the same atomic number but different mass numbers.

According to the context of this question,

The initial weight of an isotope = 95

The final weight of an isotope = 5.9

The half-life = 6 days

After 6 days, the weight of 95 reduced to 47.5.

After 6 days, the weight of 47.5 was reduced to 23.75.

After 6 days, the weight of 23.75 reduced to 11.87

After 6 days, the weight of 11.87 was reduced to 5.93.

Therefore, if the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.

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Your question is incomplete, but most probably your full question is as follows:

An isotope A has an initial weight of 95g, but after some time its weight was reduced to 5.9g being a half-life of 6 days. On what day it was measured?

1)Depending on the amount of water in the lake, the salinity of an ocean is 34.5 0/00, If this were the case, 1000g of this would consist of____ grams of water and ____grams of salt.

2)Describe how salinity and temperature effect the density of sea water:

Answers

(1) If this were the case, 1000g of this would consist of 965.5 grams of water and 34.5 grams of salt.

(2) Increase in either salinity or temperature leads to an increase in the density of seawater and vice versa.

What is the amount of water and salt contained?

The salinity of seawater is typically measured in "parts per thousand" (ppt), which means that for every 1000 parts (by weight) of seawater, 34.5 parts are salt.

So it implies that  in 1000g of seawater with a salinity of 34.5 ppt, there would be 34.5g of salt and 965.5g of water.

Salinity has a direct effect on the density of seawater because the dissolved salts in seawater increase its mass, which in turn increases its density.

Temperature also affects the density of seawater because as the temperature increases, the water molecules move faster and the spaces between them increase, leading to a decrease in the density of the water.

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A car drives straight off the edge of a cliff that is 58 m high. The police at the scene of the accident note that the point of impact is 0.136 km from the base of the cliff. How long did it take to hit the ground?

Answers

It will take the car 3.2 seconds to hit the ground.

Using the kinematic equation,

y = yo + vot + 1/2a*t^2

where y is the displacement (in this case, y = -58 m), yo is the initial displacement (yo = 0), vo is the initial velocity (vo = 0), a is the acceleration due to gravity (a = -9.81 m/s^2), and t is the time we want to find.

We can solve for t by rearranging the equation:

t = sqrt(2*y/a)

t = sqrt(2*(-58)/(-9.81))

t = 3.2 seconds (to two significant figures)

Time taken is 3.2 seconds.

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. HELP
Which are characteristics of bryophytes? (Select all that apply.)

Most of them are vascular plants.

Most of them grow tall.

Most of them need water to help reproduce.

Most of them live in shady, moist, or humid areas.

Answers

Answer: Most of them need water to help reproduce & Most of them live in shady, moist, or humid areas.

Explanation:

Bryophytes are non-vascular plants, meaning they do not have specialized tissue for transporting water and nutrients throughout their bodies. Instead, they absorb nutrients and water from the environment. Bryophytes are usually short-lived and don't grow tall, and they prefer to live in shady, moist, or humid areas because they require water to help them reproduce.

watch the tsunami arrival topic of the tsunami initiation animation, and pay close attention to see what happens along the beach just before the wave hits.

Answers

1. As the Tsunami wave approaches the beach, water levels will start to rise, and the ocean may appear to recede away from the shoreline.

2. The ocean may become very calm, and the surface may appear glassy.

3. Strong currents may be felt, and debris such as seaweed, branches, and shells may be seen rushing away from the shoreline.

4. Animals such as birds may be seen fleeing from the shoreline, and a loud roar may be heard as the wave approaches.

5. The wave will eventually reach the beach, and the water levels will quickly rise to a high level. The wave will then crash into the shore, causing destruction and flooding.

What is a Tsunami?

A  Tsunami is a powerful series of ocean waves caused by an underwater disturbance, such as an earthquake, volcano, or landslide. These waves travel across the ocean at high speeds and can reach up to hundreds of feet in height when they reach coastlines, causing severe flooding and destruction. Tsunamis are also known as seismic sea waves, and they can occur anywhere in the world.As the wave energy travels, it causes the sea level to rise and creates a “wave” that can travel up to 500 miles per hour. Tsunamis can reach heights of up to 100 feet and can cause extensive damage to coastal areas. The strength of the wave depends on the intensity of the earthquake or eruption that caused it.

Tsunamis usually arrive onshore suddenly and without warning, leaving little time for people to evacuate to safety and are often accompanied by strong currents and large amounts of debris, making them even more destructive.

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true/false. shubham wants to know the current mileage ( distance traveled in km in 1 ltr of petrol ) of his car and for that decided to create a function in python where he can pass distance traveled by his car and amount of petrol consumed by the car.

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By supplying the distance travelled and the quantity of gasoline spent as inputs, Shubham may write a Python function to get the current mileage of his automobile. The statement is true.

Shubham can create a function in Python to calculate the current mileage of his car by passing the distance traveled and the amount of petrol consumed as parameters. He can define the function to take two arguments: distance and petrol, and then calculate the mileage by dividing the distance by petrol.

If the function is written correctly, it will return the current mileage of his car in km/l. By passing the appropriate values to this function, he can easily calculate the mileage of his car at any time, which can help him keep track of his car's fuel efficiency and plan his journeys accordingly.

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Derive the expression for the RMS pressure of a square wave and a triangular wave. Compare the value of the RMS pressure for sinusoidal, square and triangular waves. Assume all three waves have the same period and amplitude and all have zero mean values

Answers

Answer:

Explanation:

The Root Mean Square (RMS) pressure of a waveform can be defined as the square root of the average of the square of the pressure values over one period of the wave. The RMS pressure provides a measure of the effective pressure of a waveform and is often used to compare the strength of different waveforms.

For a square wave, the RMS pressure can be found as follows

P_RMS = sqrt((1/T) * ∫_0^T (P_square(t))^2 dt)

Where T is the period of the waveform and P_square(t) is the pressure value of the square wave at time t. The integral is taken over one period of the waveform.

For a triangular wave, the RMS pressure can be found as follows:

P_RMS = sqrt((1/T) * ∫_0^T (P_triangular(t))^2 dt)

Where T is the period of the waveform and P_triangular(t) is the pressure value of the triangular wave at time t. The integral is taken over one period of the waveform.

The RMS pressure of a sinusoidal wave is given by the equation:

P_RMS = (A/sqrt(2))

Where A is the amplitude of the waveform.

Comparing the RMS pressures of the three waveforms, it can be seen that the RMS pressure of a sinusoidal wave is (A/sqrt(2)) which is smaller than the RMS pressure of a square wave or a triangular wave. This is because the square wave and triangular wave have sharper transitions from positive to negative values compared to the sinusoidal wave, which results in higher peak pressure values and hence a higher RMS pressure.

It is worth noting that while the RMS pressures of the three waveforms are different, they provide a measure of the effective pressure of the waveforms and can be used to compare their strengths.

Here is a definition of each variable used in the equation:

P_RMS: The Root Mean Square (RMS) pressure of the waveform. It is a measure of the effective pressure of the waveform.

T: The period of the waveform. It is the time it takes for the waveform to repeat itself.

P_square(t): The pressure value of the square wave at time t.

P_triangular(t): The pressure value of the triangular wave at time t.

∫_0^T: The integral symbol. It represents the sum of the pressure values over one period of the waveform, from time t = 0 to time t = T.

A: The amplitude of the waveform. It is the maximum positive or negative deviation from the zero line of the waveform.

sqrt: The square root symbol. It is used to find the square root of a value.

(A/sqrt(2)): The RMS pressure of a sinusoidal wave. It is calculated as the amplitude divided by the square root of 2.

Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A) =. 30 and P(B) = .50...

Answers

According to the statement, on the assumption of requesting help from a statistical software consultant, the given case that P(A) + P(B) = 1 is not true, since A and B are not mutually exclusive events.

It is possible for the next request to be related to both SPSS and SAS, in which case it would be included in both A and B.  Therefore, we cannot simply add their probabilities to get the total probability of either event.

B. P(A') represents the probability that the next request is NOT related to the SPSS package. We can find this by subtracting P(A) from 1, since the sum of the probabilities of an event and its complement is always equal to 1:

P(A') = 1 - P(A) = 1 - 0.30 = 0.70

Therefore, the probability that the next request is NOT related to SPSS is 0.70.

C. P(A ∪ B) represents the probability that the next request is related to either SPSS or SAS or both. We can find this by using the formula:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Where P(A ∩ B) represents the probability that the next request is related to both SPSS and SAS. Since we don't have information about the probability of this intersection, we cannot calculate P(A ∪ B) exactly. However, we know that the probability of the intersection must be between 0 and the minimum of P(A) and P(B), which in this case is 0.30. Therefore, we can say:

0 ≤ P(A ∩ B) ≤ 0.30

and use this range to get a lower and upper bound for P(A ∪ B):

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≤ 0.30 + 0.50 - 0 = 0.80

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≥ 0.30 + 0.50 - 0.30 = 0.50

Therefore, the probability that the next request is related to either SPSS or SAS (or both) is between 0.50 and 0.80.

D. P(A' ∩ B') represents the probability that the next request is NOT related to either SPSS or SAS. We can find this using the formula:

P(A' ∩ B') = P((A ∪ B)')

Where (A ∪ B)' represents the complement of the event that the next request is related to either SPSS or SAS (or both). We can find (A ∪ B)' using the formula:

(A ∪ B)' = A' ∩ B'

Which represents the event that the next request is NOT related to either SPSS or SAS. Therefore:

P(A' ∩ B') = P((A ∪ B)') = 1 - P(A ∪ B)

From part c, we know that 0.50 ≤ P(A ∪ B) ≤ 0.80, so:

P(A' ∩ B') = 1 - P(A ∪ B) ≤ 1 - 0.50 = 0.50

P(A' ∩ B') = 1 - P(A ∪ B) ≥ 1 - 0.80 = 0.20

Therefore, the probability that the next request is NOT related to either SPSS or SAS is between 0.20 and 0.50.

Complete question:

Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A) =. 30 and P(B) = .50.

a. Why is it not the case that P(A) + (B) = 1?

b. Calculate P(A ′).

c. Calculate P(A ∪B).

d. Calculate P(A′ ∩B′).

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Which of the following sets of quantum numbers represents the highest energy of an atom?A. n = 3, l = 0, m = 0, s = +1/2B. n = 3, l = 1, m = 1, s = +1/2C. n = 3, l = 2, m = 1, s = +1/2D. n = 4, l = 0, m = 0, s = +1/2

Answers

 (c) n=3,1=2,m=1,s=+1/2 this set of quantum number represents the highest energy of atom

Correct option is C)

The sets of the quantum numbers and the corresponding orbitals are as shown below.

a)n=3,l=0 means 3s− orbital

b)n=3,l=1 means 3p− orbital

c)n=4,l=2 means 4d− orbital

d)n=4,l=0 means 4s− orbital

Increasing order of energy among three orbitals is 3s<3p<4s<4d

∴4d has highest energy.

Hence, the set c of quantum numbers (n=4,l=2,m=1,s=+1/2)  represents the highest energy of an atom.

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Two metal spheres are connected by a metal wire that has a switch in the middle. Initially the switch is open. Sphere 1, with the larger radius, is given a positive charge Sphere 2, with the smaller radius, is neutral. Then the switch is closed. Afterward, Sphere 1 has charge Qi, is at potential Vi, and the electric field strength at its surface İs E1-The values for Sphere 2 are Q2. V2, and E2. a) Is Vi larger than, smaller than, or equal to V2? Explain b) Is Qi larger than, smaller than, or equal to Qa? Explain. c) Is Ei larger than, smaller than, or equal to E2? Explain.

Answers

(1) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal.(2)  Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed.

a) The potential difference between the two spheres will cause charges to flow from Sphere 1 to Sphere 2 until their potentials are equal. Since Sphere 1 has a positive charge, electrons will flow from Sphere 2 to Sphere 1 until their potentials are equal. This means that Sphere 1 will end up with a lower potential than its initial potential and Sphere 2 will end up with a higher potential than its initial potential. Therefore, Vi is smaller than V2.

b) Since the total charge is conserved, the total charge on both spheres after the switch is closed will be equal to the charge on Sphere 1 before the switch is closed. Therefore, the final charge on Sphere 2, Q2, will be equal to the initial charge on Sphere 1. Hence, Qi is equal to Q2.

c) The electric field strength at the surface of a charged conductor is proportional to the surface charge density. Since Sphere 1 has a larger radius than Sphere 2, it has a larger surface area and therefore a lower surface charge density. This means that E1 will be smaller than E2. Additionally, as charges move from Sphere 1 to Sphere 2, the surface charge density on Sphere 1 decreases, leading to a decrease in E1. Therefore, E1 will be smaller than E2 after the switch is closed.

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You and your best buddy have to carry two crates up a flight of stairs. Your crate is twice as heavy as your buddy's. Your buddy is doing ______________ work as you are doing.

Answers

half I think that's just a guess though

Can anyone solve this​

Answers

Answer:

sorry I'm not smart

Explanation:

Consider the two vectors A and B. You know the magnitudes of these vectors (lmand 10 m respectively), but you do not know anything about their directions ca ment Status here for 9 H a vector is defined to be the sum of these two vectors CHA+B) which of the following are true about the magnitude of C7 Choose all that apply C. cannot be determined Grade Summary Cain

Answers

A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.

When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,

where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:

|C|min = |A| - |B| = 1 m - 10 m = 9 m.

The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:

|C|max = |A| + |B| = 1 m + 10 m = 11 m.

Therefore, the magnitude of C is between 1m and 10m, and it can be determined.

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correct question

Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)

A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.

HELPPP A wave with an amplitude of 0.25m intereferes with a wave with an amplitude of 1m. What
is the resulting amplitude? Draw the waves before the interference and after the
interference in the show your work section.

Answers

The resulting amplitude of the two waves is 1.25 m

What happens when two waves of different amplitudes interfere?

When two waves of different amplitudes interfere, the resulting wave pattern is determined by the relative phase and amplitude of the two waves. If the two waves are in phase, meaning that their peaks and troughs line up, they will reinforce each other and produce a wave with a larger amplitude. This is known as constructive interference.

In this case the amplitude of the resulting wave would be a combination of two amplitudes of the waves and that would be 1.25 m

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space station consists of three modules, connected to form an equilateral triangle of side length 82.0 m. Suppose 100 people, with an average mass of 75.0 kg each, live in each capsule and the mass of the modules is negligible compared to the mass of the people. At the current rotational rate the effec- tive acceleration of gravity is g/2. (a) What angular momentum of the system? (b) If the modules are pulled closer what should happen to the rota- tional rate? Explain. (c) What distance between the modules would give an effective acceler- ation of gravity equal to g? A

Answers

The angular momentum of the system is  225,540 kg [tex]m^{2} /s[/tex] and the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

(a) The angular momentum of the system is given by L = Iω.

The moment of inertia of an equilateral triangle of mass M and side length a is I = (1/6)M[tex]a^{2}[/tex]

The mass of each capsule is 100 people × 75.0 kg/person = 7,500 kg.

Therefore, the total mass of the system is M = 3 × 7,500 kg = 22,500 kg.

The radius of the circle is half the side length of the equilateral triangle, so r = 41.0 m.

Therefore, the angular velocity of rotation is given by ω = (g/2)/r = 0.120 rad/s.

Using these values, the angular momentum of the system is L = (1/6)M[tex]a^{2}[/tex]ω = (1/6) × 22,500 kg × (82.0 [tex]m^{2}[/tex]) × 0.120 rad/s = 225,540 kg[tex]m^{2} /s[/tex]

(b) If the modules are pulled closer together, the moment of inertia of the system will decrease, because the mass of the system will be closer to the axis of rotation. According to the conservation of angular momentum, if the moment of inertia decreases, the angular velocity of rotation must increase in order to keep the angular momentum constant. Therefore, pulling the modules closer together would increase the rotational rate of the space station.

(c) The effective acceleration of gravity is given by g_eff = (g/2) + ([tex]v^{2}[/tex]/r), where v is the linear velocity of the space station. At the current rotational rate, the linear velocity of the space station is v = rω = 41.0 m × 0.120 rad/s = 4.92 m/s.

g.eff = (g/2) + ([tex]v^{2}[/tex]/r) = g

([tex]v^{2}[/tex]/r) = (g/2)

r = (2[tex]v^{2}[/tex])/g

Substituting the values for v and g, we get:

r = (2 × [tex]4.92m/s ^{2}[/tex])/9.81 [tex]m/s^{2}[/tex] = 24.8 m

Therefore, the distance between the modules that would give an effective acceleration of gravity equal to g is 24.8 m.

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suppose that earth's spin would suddenly reverse direction, but the direction of earth's motion around the sun was preserved. which of the following changes would you expect to observe?

Answers

The east would be the location of the Sun's rising and setting are the changes would you anticipate seeing.

Annual motion is the term used to describe variations in the position of the stars in the sky.

Annual motion, which is a direct result of the Earth's rotation around the sun, is the visible yearly move of the stars as seen from Earth. The ecliptic is a line on the surface of a sphere around which the revolves around the sun 360 degrees each year.

The stars seem to rise with in east as set in the west, but why is that so?

We, the watchers on Earth, whirl past this foreground of far-off stars as the planet rotates on its axis. The stars seem to travel throughout our darkness of space from east to west as Earth spins for the same reason.

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what is a biotic animal that lives in two terrestrial ecosystems

Answers

Answer: A bear

Explanation:

I think it is a bear because in the North pole it swims to get food and walks in land to hide.

What is the average force of gravitation between Mercury and the Sun?

Answers

Answer:

The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N

Explanation:

Answer:

Average force of gravitation between Mercury and the Sun is approximately 3.54 x 10^20 N.

Explanation:

The following equation determines the gravitational force between two objects:

F = G * (m1 * m2) / d^2

In this equation, F is the gravitational force, G is the gravitational constant (G = 6.67 x 10-11 Nm2/kg2), m1 and m2 are the objects' masses, and d is the space between their centres.

We need the masses of Mercury and the Sun as well as their typical separation in order to compute the average gravitational force between them.

The Sun's mass is roughly 1.989 x 1030 kg, while Mercury's mass is roughly 3.285 x 1023 kg. Mercury and the Sun are typically separated by around 57.9 million kilometres (0.39 astronomical units).

With these values entered into the formula, we obtain:

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F is equal to G * (3.285 x 1023 kg) * (1.989 x 1030 kg) * (57.9 x 106 m) * 2

F = 3.54 x 10^20 N

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the speed of a boat in still water is 24 mph. if the boat travels 54 miles upstream in the same time it take to travel 90 miles downstream, find the speed of the current

Answers

Let's call the speed of the current "c". Then, the speed of the boat relative to the water when it is going upstream is 24 - c mph, and the speed of the boat relative to the water when it is going downstream is 24 + c mph.

Using the time it takes to travel the given distances, we can set up the following equation:

(54) / (24 - c) = (90) / (24 + c)

Expanding and solving for c, we find that:

c = 4 mph

So the speed of the current is 4 mph.

Answer: Upstream: 24 - 6 = 18  --->   54 = 18 x?  --->  ? = 54/18 = 3 hours

   (24 - 6)x 3 = 18 x 3 = 54 miles

   (24 + 6) x 3 = 30 x 3 = 90 miles

The speed of the current is 6 mph.

Time is 3 hours

assuming that the string and pulley are massless, the magnitude of the acceleration of each block is

Answers

The magnitude of the acceleration of each block is given by the absolute value of a

In a system with a massless string and pulley, the forces acting on each block must be taken into account in order to calculate the amount of each block's acceleration.

Assume that the mass of block 1 is m1, the mass of block 2 is m2, and the string's tension is T.

Block 1 is being pulled up and down by the tension in the string (T) and its weight (m1g), respectively.

Block 2 is being pulled up and down by the tension in the string (T) and its weight (m2g), respectively.

The tension in the string remains constant throughout due to the masslessness of the string and the pulley as well as the absence of friction, which causes the blocks to accelerate in opposing directions at the same rate (a).

As a result, we may express the two blocks' motion equations as follows:

m1g - T = m1a for block 1.

T - m2g = m2a for block 2.

These equations for T and a can be resolved:

T = (m1 + m2)g / 2

m1 + m2 / (m2 - m1)g = a

The absolute value of a, which is as follows, determines the extent of each block's acceleration:

A is equal to (m1 + m2)g / (m2 - m1)g.

This formula indicates that the acceleration of each block is a function of both the total and difference of their masses.

A negative acceleration means that block 1 is travelling downhill and block 2 is moving upward if m1 is bigger than m2.

A positive acceleration means that block 1 is going upward and block 2 is falling downward if m2 is larger than m1.

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Adults are not born knowing what they like to do.
A. True
B. False

Answers

The answer is A. True.

a 1.2 kg pebble is stuck in a tread of a .76 m

Answers

Answer:

Fc=mv2/r v=√(Fcr/m) v=√[(3.6 N)(0.38 m)/(0.0012kg)] v=33.76388603 m/s v=38 m/s

Explanation:

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