Answer:
Calcium carbonate is an ionically bonded compound.
Covalent Bond: This bond is formed because atoms share a pair of electrons through an orbital.
Predict the product of this reaction
Al(s) + N2(g)—->
Which general equation represents an endothermic reaction?
A. reactants - energy - products + energy
B. reactants
products + energy
C. reactants + products - energy
D. reactants + energy
products
Explanation:
The general equation for an endothermic reaction is: Reactants + Energy → Products.
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The equation represents an endothermic reaction is reactants + energy
products.
What is an endothermic reaction?
Endothermic reactions are chemical reactions in which the reactants soak up warm strength from the surroundings to form products.
net energy is not released.heat is not evolved with the product.heat is required to start the reaction.increase with the increase in temperature.decrease with a decrease in temperature.Learn more about the endothermic reaction here:-https://brainly.com/question/6506846
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How many grams of ( S ) - 1 - chloro - 4 - ethyl - 2 - methylhexane and triphenylphosphine would you need to create 4 . 1 5g of ( S ) - 1 - chloro - 4 - ethyl - 2 - methyl triphenylphosphonium assuming an 8 1 % yield for the reaction?
Answer:
Explanation:
The standard molar mass is:
For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol
For triphenylphosphine = 262 g/mol
For ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol
The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]
Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]
= 5.1235 g
thus, since 424.5 g yield produce from 162.5 g
∴
5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]
= 1.9613 g of alkyl halide (-chloro) required.
Also, since 424.5 g yield produce from 262 g phosphine
∴
5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]
= 3.1622 g of triphenylphosphine required.
Predict the products and balance the equation
classify the reaction
Answer:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
Explanation:
Hello there!
In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
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write the balanced chemical equation of the reaction between strong acid and weak base also mention the types of salt obtained in the reaction
Answer:
write the balanced chemical equation of the reaction between strong acid and weak base also mention the types of salt obtained in the reaction
Explanation:
HCl → H+(aq) + Cl−(aq) (100%)
Any acid that dissociates 100% into ions is called a strong acid. If it does not dissociate 100%, it is a weak acid. HC2H3O2 is an example of a weak acid:
HC2H3O2→ H+(aq) + C2H3O2−(aq) (~5%)
Because this reaction does not go 100% to completion, it is more appropriate to write it as an equilibrium:
HC2H3O2 ⇄ H+(aq) + C2H3O2−(aq)
As it turns out, there are very few strong acids, which are given in Table 12.2 “Strong Acids and Bases”. If an acid is not listed here, it is a weak acid. It may be 1% ionized or 99% ionized, but it is still classified as a weak acid.
Calculate the wave number and
Frequency of violet radiation having
wavelength of 3500 Å
Answer: frequency is 8.57 ·10^14 Hz
Explanation: lambda = 3500 A = 0,000 000 350 m
Wave number is 1/ lambda = 2857142.857 1/m
Wave equation c = frequency · lambda and f = c / lambda
Frequency = 300 000 000 m/s / 0,000 000350 m
The wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].
Explanation:
Given that,
The wavelength of violet radiation,
[tex]\lambda=3500\ A\\\\=3500\times 10^{-10}\ m\\\\=3.5\times 10^{-7}\ m[/tex]
To find,
The wave number and frequency of violet radiation.
Solution,
Wavelength, [tex]\lambda=3.5\times 10^{-7}\ m[/tex]
Wave number is the reciprocal of the wavelength,
[tex]\overline{\lambda}=\dfrac{1}{\lambda}[/tex]
Put all the values,
[tex]\overline{\lambda}=\dfrac{1}{3.5\times 10^{-7}}\\\\\overline{\lambda}=2.85\times 10^{6}\ m^{-1}[/tex]
The relation between the wavelength, frequency and speed of wave is given by :
[tex]f=\dfrac{c}{\lambda}[/tex]
Where
c is the speed of light
Put all the values,
[tex]f=\dfrac{3\times 10^8}{3.5\times 10^{-7}}\\\\f=8.57\times 10^{14}\ Hz[/tex]
So, the wavelength number is [tex]2.85\times 10^{6}\ m^{-1}[/tex] and the frequency is [tex]8.57\times 10^{14}\ Hz[/tex].
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Would you rather wear
Socks in sandals or wear shoes without socks
Answer:
i always wear shoes without socks
Explanation:
Calculate the pH at the equivalence point for the titration of 0.200 M 0.200 M methylamine ( CH 3 NH 2 ) (CH3NH2) with 0.200 M HCl . 0.200 M HCl. The K b Kb of methylamine is 5.0 × 10 − 4 . 5.0×10−4. pH =
Answer:
pH = 5.85
Explanation:
The reaction of methylamine with HCl is:
CH₃NH₂ + HCl → CH₃NH₃⁺ + Cl⁻
As the titration was made with two solutions with the same molarity, the final concentration of the CH₃NH₃⁺ ion is 0.100M ([CH₃NH₃⁺] = 0.100M)
Then, the conjugate acid will be in equilibrium with water as follows:
CH₃NH₃⁺(aq) + H₂O(l) ⇄ CH₃NH₂(aq) + H₃O⁺(aq)
And the equilibrium constant, Ka, of this reaction is:
Kw/Kb = Ka = 1.0x10⁻¹⁴ / 5.0x10⁻⁴= 2x10⁻¹¹
2x10⁻¹¹ = [CH₃NH₂] [H₃O⁺] / [CH₃NH₃⁺]
As both CH₃NH₂ and H₃O⁺ comes from the same equilibrium we can say:
[CH₃NH₂] = [H₃O⁺] = X
And as we know [CH₃NH₃⁺] = 0.100M:
2x10⁻¹¹ = [X] [X] / [0.100M]
2x10⁻¹² = X²
X = 1.414x10⁻⁶M = [H₃O⁺]
And as pH= -log [H₃O⁺]
pH = 5.853.0L of a gas is at a temperature of 78c. Find the volume of the gas at standard temperature
Answer:
V=2.33361811192L or 2.3x10
Explanation:
Using Charles law V1/T1=V2/T2 Remember to convert celcius to kelvin by using the standard temperature 273.15K
3L/(78C+273.15)=V/273.15
which memrane lines the abdomino pelvic cavity
Answer:
The peritoneum
Explanation:
The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.
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The answer for this
Mass of watch glass + filter paper = 105.98 g
Mass of watch glass + filter paper + crystallized product = 109.03 g
Mass of uncrystallized product (show work) =
Mass of methyl benzoate = 3.08 g
Volume of nitric acid used = 2.0 mL
Theoretical yield based on each of the starting materials
(Please use two Dimensional Analysis (DA) equations, one for the maximum amount of product obtainable from the amount of methyl benzoate you used and the other from the concentrated nitric acid, then use the lesser of the two to determine the Limiting Reagent; you must determine the number of moles in 2.00 mL of concentrated nitric acid [concentration 69.0% (w/w), and density (1.42 g/mL)].
Required:
a. Identity of the Limiting reagent (LR) based on the above two DA equations = __________
b. Max amount of product obtainable from the LR = ___________
c. Mass of the product you obtained: ____________
Answer:
Explanation:
Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)
Mass of uncreystaliized product = 109.03 gm - 105.98 gm
Mass of uncrystaliized product = 3.05 gm
For methyl benzoate;
mass = 3.08 g
no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole
It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.
moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles
∴
mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol
mass of nitro methyl benzoate = 4.098 gm
For HNO_3 solution:
mass = 1.42 gm/ml × 2.0 ml
mass = 2.84 gm
Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]
= 1.9596 gm
Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]
= 0.0311 mole
1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate
Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole
The mass for nitro methyl benzoate can now be determined as:
= 0.0311 mole × 181.5 gm/mole
= 5.634 gm
Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.
The mass obtainable from the LR = 4.098 gm
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes?
Molecules in both the metal and the surrounding air will start moving at lower speeds.
Molecules in both the metal and the surrounding air will start moving at higher speeds.
The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Explanation:
There will be a transfer of thermal energy (heat) from the hot metal plate to the surrounding air. This transfer of energy equates to a transfer of kinetic energy in the molecules. As the plate loses heat, the molecules in the plate will lose kinetic energy and slow down. As the surrounding air gains heat, the molecules will gain kinetic energy and speed up.
Answer: C
Explanation:
Consider the following equilibrium
N204(9) - 2NO2(9) Keq = 5.85 x 10-3
Which statement about this system is true?
If the equilibrium concentration of NO2 is 1.78 x 10-2 M, the equilibrium concentration of N2O4 is
The equilibrium concentration of N₂O₄, given that the concentration of NO₂ is 1.78×10⁻² is 5.42×10⁻²
Data obtained from the question N₂O₄ <=> 2NO₂Equilibrium constant (Keq) = 5.85×10⁻³ Equilibrium concentration of NO₂ = 1.78×10⁻²Equilibrium concentration of N₂O₄ =?How to determine the equilibrium concentration of N₂O₄Keq = [Product] / [Reactant]
Keq = [NO₂]² / [N₂O₄]
5.85×10⁻³ = [1.78×10⁻²]² / [N₂O₄]
Cross multiply
5.85×10⁻³ × [N₂O₄] = [1.78×10⁻²]²
Divide both sides by 5.85×10⁻³
[N₂O₄] = [1.78×10⁻²]² / 5.85×10⁻³
[N₂O₄] = 5.42×10⁻²
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Answer:
First answer is "The equilibrium lies to the left", and the second one is 5.42 x 10^-2 M.
Explanation:
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What is a hot spot? Must be in your own words ( please hurry)
Answer:
It depends. what hot spot are you looking for?
Answer:
A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.
Explanation:
Hope this is what you mean be hot spot!
I hope this helps you!
Acidic hydrolysis involves the nucleophilic addition of water to the protonated amide.
a. True
b. False
Answer:
a
Explanation:
dont have to explain
The correct value of m, n, x and y to obtain a balanced equation is?
m B2O3(s) + n HF(l) → x BF3(g) + y H2O(l)
a.
m=1, n=1, x=1 and y=1
b.
m=1, n=6, x=2 and y=3
c.
m=1, n=1.5, x=1 and y=1
d.
m=2, n=12, x=4 and y=6
Answer:
d
Explanation:
answer d makes the equation balance
How to balance NaOH+CO2=Na2CO3+H2O by algebraic method?
Explain what method you would use to obtain
Petrol (boiling point 20
60 C) from a mature of petrol and kerosene (boiling point 180 220 C)
Answer:
Fractional distillation of crude oil in laboratory
Explanation:
In general, we can sort them according to their boiling point.
We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.
Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.
A separatory funnel contains the two immiscible liquids water and toluene. Use the given densities to determine which layer is on top and which is on the bottom in the binary mixture.
Solvent Density (g/mL)
toluene 0.87
water 0.998
Drag and drop each label into the box to indicate the position of the liquid in the mixture.
Top layer
Bottom layer
Answer:
Top layer TolueneBottom layer WaterExplanation:
When two non-miscible liquids are put together, the one with the higher density will be on the bottom, while the one with the lower density will be on top.
Meaning that in this problem's case toluene would be on the top layer and water in the bottom layer.
write the value of atmosphere pressure at sea level .
Answer:
standard sea- level pressure,by definition,equals 760 mm of Mercury,14.70 pounds per square inch, 1,013.25x10³ dynes per square centimetre, 1,013.25 millibars,one standard atmosphere,or 101.325 kilopascale
Here's your answerl hope it's helpful for u....
What is the molality of a solution containing 18.2 g HCl and 250. g of water?
Answer:
m=2.0mol/kg
Explanation:
Hello there!
In this case, according to the formula to compute molality, which requires moles of solute (HCl) and kilograms of solvent (water), we first compute the moles of the former with its molar mass as shown below:
[tex]n=\frac{18.2g}{36.46g/mol}= 0.50mol[/tex]
And then the kilograms of water:
[tex]\frac{250.g}{1000g/kg} =0.250kg[/tex]
Finally, the molality turns out to be:
[tex]m=\frac{0.50mol}{0.250kg}\\\\m=2.0mol/kg[/tex]
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You have 281 kilojoules how many kilocalories is it need to know ASAP
How many moles of water will be produced from the reactions 3.25 moles of hydrochloric acid react with excess calcium hydroxide
Answer:
3.25 moles of H2O
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2HCl + Ca(OH)2 —> CaCl2 +2H2O
Now, we can obtain the number of mole H2O produced from the reaction as follow:
From the balanced equation above,
2 moles of HCl reacted to produce 2 moles of H2O.
Therefore, 3.25 moles of HCl will also react to produce 3.25 moles of H2O.
Therefore, 3.25 moles of H2O were produced from the reaction.
What is the pressure inside a balloon that contains 10.0 g of helium at 25.0°C when the helium occupies a volume of 56.0 L?
A 10.9 atm
B 0.916 atm
C 11.1 atm
D 1.09 atm
Explanation is in the file
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depression How does a person get the disorder (causes) - it might be genetic, the result of an injury, or possibly the factors are unknown.
Answer:
There's no single cause of depression. It can occur for a variety of reasons and it has many different triggers. For some people, an upsetting or stressful life event, such as bereavement, divorce, illness, redundancy and job or money worries, can be the cause. Different causes can often combine to trigger depression. For example, you may feel low after being ill and then experience a traumatic event, such as a bereavement, which brings on depression.
calculate the ph of one solution containing 0.1 M formic acid and 0.1 M sodium formate before and after the addition of 1mL of 5 M Naoh. how much could the Ph change if the NaOh were added to 1 L of pure water
Answer:
Pka of formic acid (HCOOH)= 3.75
pH= PKa +log [ Sodium formate/ formic acid] = 3.75
NaOH reacts with HCOOH as HCOOH (aq) + NaOH(aq) --> NaCHO2 (aq) and H2O (l)
Moles of HCOOH= 0.1*1= 0.1 moles
Moles of NaOH= 5*1/1000= 0.005 moles
HCOOH is in excess and the excess is = 0.1 - 0.005 = 0.095
Moles of sodium formate = 0.005 + 0.1 = 0.105 moles of HCOOH= 0.095
volume after mixing = 1 + 5 /1 000=1.005
Concentrations : HCOOH= 0.095/1.005 sodium formate= 0.105/1.005
pH= 3.75+log (0.105/0.095)=3.85
When NaOH is added, molarity is , 1*5= 1000*M
M= 5/1000=0.005
The pH remains the same. Only the molarity of NaOH changes.
What is the correct chemical name for N3H4
Answer:
Molar mass of N3H4 name is 84.0761 g/mol
Convert between N3H4Na(CH3) weight and moles
The chemical name for the formula N₃H₄ is Trinitrogen Tetrahydride
How a chemical compound is named ?The first element is named by simple using the name of the element. The second element is named by taking the stem of the element name and adding the suffix -ideThe element that is less electronegative is written first ,there are exceptions like , Carbon is always first in a formula and hydrogen is after nitrogen in a formula such as NH3 . The sequence of common nonmetals in binary compound is
C , P , N , H , S , I , Br , Cl , O , F .
So Now for N₃ = Tri Nitogen
and for H₄ = Tetra Hydride
Therefore the chemical name is Trinitogen Tetrahydride.
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A certain metal M forms a soluble nitrate salt M NO Suppose the left half cell of a galvanic cell apparatus is filled with a 3.00 mM solution of M(NO) and the right half cell with a 3.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C.
1. Which electrode will be positive? What voltage will the voltmeter show?
a. left
b. right
2. Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answer:
Explanation:
From the information given:
left half-cell = 3.00 mM M(NO)
right half-cell = 3.00 M M(NO)
Since the electrode are the same in both cells, then the concentration for the cell are also the same.
Negative electrode = Anode = lower concentration = 3.00 mM
Positive electrode = cathode = higher concentration = 3.00 M
Thus, right half cell will be postive electrode.
To determine the concentration cell:
[tex]Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)[/tex]
SInce [Cathode] > [anode],
[tex]R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol[/tex]
n = 3
[tex]Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}[/tex]
[tex]\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}[/tex]
What is Tiny grains that contain sperm call
Answer:
Pollen
Explanation:
Pollen is a powdery substance consisting of pollen grains which are male microgametophytes of seed plants, which produce male gametes (sperm cells).