Explanation:
the world of introductory physics, Newton's second law is one of the most important laws you'll learn. It's used in almost every chapter of every physics textbook, so it's important to master this law as soon as possible.
We know objects can only accelerate if there are forces on the object. Newton's second law tells us exactly how much an object will accelerate for a given net force.
\Large a=\dfrac{\Sigma F}{m}a=
m
ΣF
The density for gold is 19.3 g/cm3. What would be the mass of a 45 cm3 piece of gold?
Answer:
868.5 g
Explanation:
Mass= Density x Volume
Mass= 19.3 x 45
=868.5
Answer:
675.5g
Explanation:
The formula for density is: D = m/V.
To solve this problem, we need to rearrange this formula to solve for mass:
m = D x V.
Next, we plug the given values in for density, D, and volume, V:
m = 19.3 g/cm3 x 35 cm3
So, m = 675.5 g
A student puts a besker of warm water next to a besker of cold water so that they fough which two statements are true? DA Thermal energy will move from the warm water to the cold water Thermal energy will move from the air to the cold water. Thermal energy utill move from the air to the warm water Thermal energy till move from the cold water to the warm water
Explanation:
so sorry
don't know but please mark me as brainliest please
Which dwarf planet has a moon nearly as large as itself?
Answer:
The answer is the Pluto.
A group of students conduct an experiment with a block of wood sliding down an incline. They find that the final energy of the block is less than the initial energy of the block. Which statement best describes this situation?
A. The students made an error in deterring the final energy.
B. The students made an error in calculating the initial energy.
C. Some energy was transformed to other forms.
D. Some energy was destroyed or lost.
A copper block rests 17.4 cm from the center of a steel turntable. The coefficient of static friction between block and surface is 0.465. The turntable starts from rest and rotates with a constant angular acceleration of 0.406 rad/s 2 . The acceleration of gravity is 9.8 m/s 2 . After what interval will the block start to slip on the turntable
Answer:
12.61 s
Explanation:
Given that
Distance from the center if the turntable, r = 17.4 cm = 0.174 m
Coefficient of static friction, μ = 0.465
Angular acceleration, α = 0.406 rad/s²
Acceleration due to gravity, g = 9.8 m/s²
We know that
F_max = μmg
Also, we know that
F = mω²r
Now, for slip to occur, both forces must be equal to one another, and thus
mω²r = μmg
ω²r = μg
ω² = μg/r
ω² = (0.465 * 9.8)/0.174
ω² = 4.557 / 0.174
ω² = 26.19
ω = √26.19
ω = 5.12 rad/s
t = ω/α
t = 5.12/0.406
t = 12.61 s.
Thus, after 12 seconds, the block will start to slip on the turntable
What form of energy is released into the atmosphere by the earth's surface
Answer:
Thermal Energy (Heat)
Answer:
Heat
Explanation:
the form that is raised from the atmosphere from earths surface is heat
People have been able to make materials such as fiber optics cables A. using nails and screws. B. using glue and scissors. C. using rocks and stones. D. using science and technology.
Answer:
D
Explanation:
What is a possible equation fir an ionic compound with calcium
Answer:
CaO, CaMg, or CaF2
Ca2Cl, CaNa, or CaP
CaF, CaMg, or CaNa
CaO, CaF2, or CaCl2
Explanation: i think
Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal?
a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV
Answer:
Ke = 1.41 eV
Explanation:
We know that
h = 6.626 x 10⁻²⁴
c = 3 x 10⁸
λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹
Computation:
Ke = [hc / λ] - w
Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70
Ke = 1.41 eV
What is the best description for a transverse wave? *
A.The movement of the atoms around the wave is parallel to the movement of the ENERGY it is transferring.
B.The movement of the atoms around the wave is parallel to the movement of the MATTER it is transferring.
C.The movement of the atoms around the wave is perpendicular to the movement of the energy it is transferring.
D.The movement of the atoms around the wave is perpendicular to the movement of the matter it is transferring.
Answer:
Option - CHope it helps youCalculate the pressure in pascals if a 560N is applied to an area of 1.6m².
Answer:
P = 350 [Pa]
Explanation:
The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.
Units of 1 [Pa] = 1 [N/m²]
P = F/A
where:
P = pressure [Pa]
F = force = 560 [N]
A = area = 1.6 [m²]
P = 560/1.6
P = 350 [Pa]
what is simple harmonic motion
give two examples
Answer:
S.H.M:- If the acceleration of the vibrating body directly varies with the displacement of the body from the mean position and always directed to the mean position, the motion of that body is called simple harmonic motion.
Ex:- (i) The motion of a pendulum is an S.H.M.
(ii) The motion of vibrating mass attached to a spring is an S.H.M.
I need help ASAP
The water cycle functions because the matter in water changes:
a.forms
b.properties
c.minerals
Answer:
(a). forms.
Explanation:
Bro even i ain't sure.
Answer:
I think its A? Because in the water cycle it goes from a liquid to a gas?
Explanation:
the force of gravity acting on an object is known as
Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum value?
a. [S]=KM
b. [S]=KM/3
c. [S]=2KM
d. [S]=KM+3
e. [S]= (KM)^1/3
Solution :
Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists, Leonor Michaelis and Maud Menten.
The formula is :
[tex]$v=\frac{V_{max}[S]}{K_M + [S]}$[/tex]
where v = velocity of reaction
[tex]$V_{max}$[/tex] = maximum rate achieved
[tex]$K_M$[/tex] = Michaelis constant
[S] = concentration of the substrate, S
According to the question, by putting the velocity of reaction, v as [tex]$\frac{V_{max}}{4}$[/tex], we get the above equation as
[tex]$[S]= \frac{K_M}{3}$[/tex]
Therefore the answer is [tex]$[S]= \frac{K_M}{3}$[/tex]
At the focal point of a converging lens, the object cannot be seen. O A. True B. False
Answer: True
Explanation: Guessed on A p E x and it was correct
Answer:
True
Explanation:
a p e x
While Barb was playing soccer, she was kicked in the anterior thigh by an opposing teammate. Due to this injury, what muscle function may she find difficult to perform?
Answer:
knee extension is the muscle function that will be difficult to perform.
Explanation:
Barb was kicked in the anterior thigh. Now, the thigh muscles performs a combined operation of moving the knee and leg and they reside in the following compartments.
- Anterior compartment which is composed of knee joint extension and thigh flexion.
- Lateral Compartment which is composed of the tensor fasciae latae, which is a tiny muscle that abducts and centrally will make the thigh to rotate.
-Medial compartment which involves thigh addiction which is rotating of the thigh around the hips.
- Posterior compartment which involves knee joint flexion and high extension.
Thus, from the different compartments listed above, we can see that the muscles that extend the knee and flex the thigh all lie in the anterior compartment of the upper leg.
Thus, we can conclude that knee extension is the muscle function that will be difficult to perform.
For a 99 kg person standing at the equator, what is the magnitude of the angular momentum about Earth's center due to Earth's rotation?
Answer:
L = 4.58 x 10⁴ kg.m²/s
Explanation:
The angular momentum is given by the formula:
L = mvr
but, v = rω
Therefore,
L = mr²ω
where,
L = Angular Momentum of the person = ?
m = mass of person = 99 kg
r = radius of earth = 6.37 x 10⁶ m
ω = Angular Speed of Earth's Rotation = θ/t
Since, earth completes 1 rotation in 1 day. Hence,
ω = (2π rad/1 day)(1 day/24 h)(1 h/3600 s)
ω = 7.27 x 10⁻⁵ rad/s
Therefore,
L = (99 kg)(6.37 x 10⁶ m)²(7.27 x 10⁻⁵ rad/s)
L = 4.58 x 10⁴ kg.m²/s
When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery?
a. 3.60 Ω
b. 0.51 Ω
c. 0.30 Ω
d. 1.56 Ω
e. 0.98 Ω
Answer:
B. 0.51 ohms
Explanation:
Our data is as follows:
Resistor R = 20.0ohms
V1 = 12 volts
V2 = 0.300 V
We are to get the internal resistance of this battery
Now,
I = change in voltage/R
Change in voltage = v1-v2
= 12-0.300
= 11.7
Then,
I = 11.7/20
= 0.585Ri
Now
O.300 = 0.585Ri
Ri = 0.300/0.585
= 0.51 ohms
This is therefore the internal resistance of the battery.
Thank you!
A particle with charge q and mass m moving with speed v in the x direction enters a magnetic field of strength B pointing in the y direction. The magnitude of the acceleration of the particle as it travels one semicircle is
Answer:
The acceleration of the particle as it travels one semicircle is
[tex]a= \frac{\pi R}{t^2}[/tex]
Explanation:'
Kindly see attached a sketch of a semi-circle
Step one:
given data
velocity =v
let the time taken be t
The path PQM is the distance covered
so distance [tex]d= \pi R[/tex]
we know that time= distance/velocity
t= πR/v
step two:
velocity =distance/time
[tex]velocity=\frac{\pi R}{t}[/tex]
also, we know that acceleration is velocity/time
[tex]a= \frac{\pi R}{\frac{t}{t} }[/tex]
[tex]a= \frac{\pi R}{t}*\frac{1}{t}[/tex]
[tex]a= \frac{\pi R}{t^2}[/tex]
If the light ray moves from inside the glass toward the glass–air interface at an angle of 30.0° to the normal, determine the angle of refraction.
Answer:
This question is incomplete
Explanation:
This question is incomplete, however, the relationship to between the angle of incidence and angle of refraction is best explained by snell's law with the equation below
ni sinθi = nr sinθr
where ni is the refractive index of the incident medium (assuming it's plate glass then 1.52)
nr is the refractive index of the refractive medium (1.33)
θi is the angle of incidence (30°)
θr is the angle of refraction (X)
If we substitute the values, we have
1.52 × sin 30 = 1.33 × sin X
1.52 × 0.5 = 1.33 × sin X
0.75 = 1.33 × sin X
sin X = 0.75/1.33
sin X = 0.571
X = sin⁻¹ 0.571
X = 34.82°
Thus, the angle of refraction will be 34.82°
If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?
Answer: 207 W
Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:
where
m = 47 kg is the mass of the object
g = 9.8 m/s^2 is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power used, which is given by
Hope this helps I'm sorry if i'm wrong but I tried :(
I need help with this science work
Please tell us the question and we will try to answer.
A machinist with normal vision has a near point at 25 cm. This machinist wears +4.25-diopter eyeglasses in order to do very close work. With these eyeglasses, what is the near point of the machinist?
a. 12 cm
b. 10 cm
c. 7 cm
d. 15 cm
e. 17 cm
Answer: 12cm.
Explanation:
First we need to calculate the focal length which will be:
= 100 / 4.25
= 23.529
The near point of the machinist will be solved using the equation:
1/u + 1/v = 1/f
where,
v = -25
f = 23.529
1/u + 1/v = 1/f
1/u - 1/25 = 1/23.529
1/u = 1/23.529 + 1/25
u = 12.12cm
u = 12cm approximately
Therefore, the near point of the machinist is 12cm
find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3
Answer:
12 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 1.5 × 8
We have the final answer as
12 gHope this helps you
frequency of a vibrating string with a period of 4 seconds
Answer: 2 Hz (8 cycles/4 s = 2 cycles/s).
Explanation:
If a coil of slinky makes 3 vibrational cycles in one second, then the frequency is 3 Hz. And if a coil makes 8 vibrational cycles in 4 seconds, then the frequency is 2 Hz (8 cycles/4 s = 2 cycles/s).
When a satellite is in orbit around the Earth, the force of the gravity on the satellite is...
Answer:
Is always towards the center of the Earth
Explanation:
n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Use the measured length to predict the theoretical pendulum period with a range of error (use the error propagation method you learned in Lab 1). ii. Compute the percentage difference (as defined in Lab 1) between the measured value and the predicted value .
Answer:
The answer is "[tex](1.265 \pm 0.010) \ s \ and \ 0.709 \%[/tex]"
Explanation:
In point i:
[tex]T_{theo}= 2\pi \sqrt{\frac{l}{g}}[/tex]
[tex]=2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s[/tex]
If error in the theoretical time period :
[tex]\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2} \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}[/tex]
[tex]= 0.010 \ s[/tex]
[tex]T_{theo} = (1.265 \pm 0.010) \ s[/tex]
In point ii:
[tex]\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100[/tex]
[tex]= \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%[/tex]A metallic spherical shell has a charge density of 1 mC/m2 on its surface. The shell has radius of 7.5 cm. Determine the electric field magnitude (in kV/m) 10 meters away from the center of the shell.
Answer:
Explanation:
charge on the shell = 4πR² x charge density
= 4 x 3.14 x 7.5² x 10⁻⁴ x 10⁻³ C
= 706.5 x 10⁻⁷ C
electric field = k Q / d² , d is distance of point from centre
= 9 x 10⁹ x 706.5 x 10⁻⁷ / 10²
= 6358.5 N /C
= 6.358 kV / m
This is a graph of a car speeding up and then reaching a constant speed of 105 m/s . After it finishes speeding up, how far does the car travel during the last 6 seconds of the graph, from 4 to 10 s?
60 m
Explanation:Concept Used:
We know that the area under a velocity-time graph represents the Displacement of the body
Displacement in the Last 6 seconds:
To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10
We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds
Area of the Rectangle:
From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide
Area of Rectangle= length*Breadth
replacing the values
Area = 10 (m/s) * 6 (s)
Area = 60 m
Hence, the car travelled 60 m in the last 6 seconds of the graph