Which type of radiation can reach the furthest?
A. Beta

B. Gamma

C. Alpha

Answer:

they both weight the same

Explanation:

they both weigh one kilo so they are the same

On Earth, 1 kg weighs 9.8 Newton's.

Doesn't matter what substance it's a kg of.

Answer:

everything except smell,hate,love,cold

Answer:

chair, air, almonds, cold-drink, smell of perfume

Explanation:

Anything that occupies space and has mass is called matter. Matter can exist in three physical states which are the:

Solid state

Liquid state

Gaseous state

therefore:

Solids: chair and almonds

Liquids: cold-drink

Gas: air and smell of perfume

•Love, smell, hate, thought, and cold are not in the category of matter/are not considered matter

•The sense of smell is not considered a form of matter. However, the smell or odour of a substance is classified as matter.

-The smell of any substance (say, perfume) is the gaseous form of that substance our olfactory system can detect (even at deficient concentrations).

Hence, the smell of some substances is considered matter.

Explanation:

let's assume that:

v1= 600ml=0,6l

T1=27°C= 300K

p1=700mmHG=93326Pa

T2=-20°C=253K

p2=500mmHg=66661

V2=?

p1V1/T1=p2V2/T2 => V2=p1V1T2/p2

V2= 93326*0,6*253/66661

V2=212,52l

Answer:

a sidereal day is the time it takes for the earth to rotate about it axis so that the distant star appears In the same position in the sky while a solar day is the time it takes for the earth to rotate about it axis so that the sun appears in the same position in the sky

Answer:

Período del tambor: [tex]T = 0.25\,s[/tex], fuerza sobre la prenda: [tex]F \approx 80.852\,N[/tex], velocidad lineal del tambor: [tex]v \approx 10.053\,\frac{m}{s}[/tex], velocidad angular del tambor: [tex]\omega \approx 25.133\,\frac{rad}{s}[/tex].

Explanation:

La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:

"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."

El tambor gira a velocidad angular constante ([tex]\omega[/tex]), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga ([tex]a[/tex]), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor ([tex]T[/tex]), en segundos:

[tex]T = \frac{1}{f}[/tex] (1)

Donde [tex]f[/tex] es la frecuencia, en hertz.

([tex]f = 4\,hz[/tex])

[tex]T = \frac{1}{4\,hz}[/tex]

[tex]T = 0.25\,s[/tex]

Ahora determinamos la fuerza aplicada sobre la prenda ([tex]F[/tex]), en newtons:

[tex]F = m\cdot a[/tex] (2)

[tex]F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}[/tex] (2b)

Donde:

[tex]m[/tex] - Masa de la prenda, en kilogramos.

[tex]r[/tex] - Radio interior del tambor, en metros.

([tex]m = 0.32\,kg[/tex], [tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])

[tex]F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}[/tex]

[tex]F \approx 80.852\,N[/tex]

La velocidad lineal de la lavadora es:

[tex]v = \frac{2\pi\cdot r}{T}[/tex] (3)

([tex]r = 0.4\,m[/tex], [tex]T = 0.25\,s[/tex])

[tex]v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}[/tex]

[tex]v \approx 10.053\,\frac{m}{s}[/tex]

Y la velocidad angular del tambor de la lavadora:

[tex]\omega = \frac{2\pi}{T}[/tex]

([tex]T = 0.25\,s[/tex])

[tex]\omega = \frac{2\pi}{0.25\,s}[/tex]

[tex]\omega \approx 25.133\,\frac{rad}{s}[/tex]

Answer:

A. Looking at stick shadows on the equinox.

Explanation:

He measures the circumference by placing a pole when the sun is overhead on the days of solstice. He determined the circumference by measuring the difference between  Alexandria to Syene and the angle of the pole's shadow.

The equation used for the calculation of circumference is as follow

[tex]\frac{360 degrew}{7.2 degree} = \frac{Circumference of earth}{Distance from Alexandria to Syene}[/tex]

Please refer to the following link for more details

https://www.khanacademy.org/humanities/big-history-project/solar-system-and-earth/knowing-solar-system-earth/a/eratosthenes-of-cyrene

Answer:

PE = mgh

Explanation:

PE is potential energy

m is mass

g is gravitational field strength

h is height

Explanation:

Momentum conservation

V=3.38

Delta kinetic energy =1/2m(vi^2-v^2)

Answer:

Positive acceleration is when an object is increasing its velocity, speeding up.

Negative acceleration is when an object is decreasing its velocity, slowing down from it’s motion.

Zero acceleration is when an object is either at rest or moving without speeding up or slowing down, in a constant way.

Answer:

d- Earth revolves around the sun.

Explanation:

Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.

This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun.

On the other hand, earth revolution can be defined as a complete trip along a path around the sun. This path is known as an orbit and it typically takes the Earth 365¼ days to complete it's journey around the Sun.

When a constellation (stars) changes its position in the sky, at the same time of the evening and over a period of several weeks; it ultimately implies or is an evidence that Earth revolves around the sun.

Explanation:

→ Force = Mass × Acceleration

→ F = (1.12 × 1.11) N

→ F = 1.2432 N

Answer:

Dynamo

Explanation:

As we all know, there are dynamos in bicycles. When we paddle the cycle, the wheels of the cycle rotates by generating kinetic energy. When the wheels rotate, the dynamo starts to rotate. This makes the motor inside the dynamo rotates and generate electrical energy.

Answer:the voltmeter measures the potential difference of the circuit,. Voltmeter is a device used to measure potential difference.

Explanation:

Answer:

i dont know guy sorry ha babu

Answer:

uugizj8iwuu3ueugeeuieieyeueureir

The question is incomplete. The complete question is  :

The pressure difference, Δp, ac[tex]K_u[/tex]ross a partial blockage in an artery (called a stenosis) is approximated by the equation :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the  artery diameter, [tex]A_0[/tex] the area of the unobstructed artery, and A1 the area of the stenosis.  Determine the dimensions of the constants [tex]K_v[/tex] and [tex]K_u[/tex]. Would this equation be valid in any  system of units?

Solution :

From the dimension homogeneity, we require :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Here, x means dimension of x. i.e.

[tex]$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$[/tex]

                    [tex]$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$[/tex]

So, [tex]$[K_u]=[K_v]=[1 ]=$[/tex] dimensionless

So, [tex]K_u[/tex] and [tex]K_v[/tex]  are dimensionless constants.

This equation will be working in any system of units. The constants [tex]K_u[/tex] and [tex]K_v[/tex] will be different for different system of units.

Answer:

The other component is 17.32m/s.

For more information

lemme so you how to solve it!

given velocity v = 20 m/s

let the given rectangular component is

cos somponent, so 10 = v cos x

so, other component will be sin component

i.e., v sin x

or, 10 = 20 cos x

or, cos x = 1/2 

and as sin^2 x + cos^2 x = 1

or, 1 - cos^2 x = sin^2 x

or, 1 - (1/2)^2 = sin^2 x

so, sin x = sqrt( 1 - 1/4)

or, sin x = sqrt(3/4)

so, rectangular component is 

20 sin x = 20 sqrt(3/4)

= 10 sqrt3

= 17.32 m/s

Explanation:

hope to help you (:

Answer:

69

Explanation:

just because

Answer:

To protect control circuits or small devices with insufficient cutting power

Explanation:

Answer:

Family

1. Definition of a family

A family is a group of people living together in a home related by blood, marriage or adoption.

2. Two function of the family are;

3. Two types of family are;

4. Two roles and responsibilities of the parents and children in the home are;

Accident in the Home

1. Definition of accident in the home

accidents in the home are common to persons of all ages, therefore home accidents occurs in one's home that may cause an result an injury of a person

2. Two types of accident in the home

3. The two uses of cereals in cooking

Cereals in cooking are used as thickened agents.

4. complete table

1. minor cuts and wounds

2. Poisoning

Care labels

1. definition of care label

care labels can be defined as a permanent label or we can say a tag, which contains regular instructions that is attached at the back of a cloth.

3. two classification of carbohydrates

Answer:

Explanation:

what do u need help with

Answer:

that's for frequency other answers are coming soon

Answer:

Explanation:

Formula

Force = G * m1 * m2 / r^2

Givens

Solution

1.67 * 10^-9 = 6.67 * 10^-11 * 110 * m2/(11)^2        Divide both sides by 10^-9

1.67 * 10^-9/10^-9 = 6.67*10^-11/(10^-9 *110*m2/121

1.67 = 6.67 * 110 * 10^-2 * m2 / 121                      Multiply both sides by 121

1.67 * 121  = 6.67 * 10 ^-2 * 110 * m2 * 121/121      Combine

202.07 = 7.337 * m2                                           Divide both sides by 7.337

202.07/7.337  =  m2

m2 = 27.54 kg

Answer:

All of the above

Explanation:

To ensure the ball go to where we expected it go

Answer:

Kayla. You can calculate it using the formula for momentum: momentum=mass×velocity and find the bigger number between the two momentums

Answer:

yes

Explanation:

masses attract each other

with a teeny-tiny force

Answer:

The ball exerts a force of 400 N on the bat.

Explanation:

Given that,

A baseball player hits a ball with 400 N of force.

We need to find the force the ball exert on the bat.

We know that,

According to Newton's third law, when object 1 exerts a force on an object 2, then object 2 will exert a force on object 1 but in opposite direction.

So, the ball exerts a force of 400 N on the bat.