Which transformations could be performed to show that △ABC is similar to △A"B"C"?

a reflection over the x-axis, then a dilation by a scale factor of 3
a reflection over the x-axis, then a dilation by a scale factor of One-third
a 180° rotation about the origin, then a dilation by a scale factor of 3
a 180° rotation about the origin, then a dilation by a scale factor of One-third

2x + 40 = 180

2x = 140

x= 70

answer is 70

Answer

6x<-12

Step-by-step explanation:

Answer:

There would be 2 answers in this case:

C. 6x > 32

and

D. 21 + x < 28

Step-by-step explanation:

A. Incorrect

6-13 = -7, and -7 is NOT greater than 7

B. Incorrect

6(6) = 36, and 36 is NOT less than -12.

C. Correct

6*6 = 36, which is greater than 32.

D. Correct

21+6 = 27, which is less than 28.

Answer:

78

Step-by-step explanation:

Add all the numbers given =256 then take the mean and multiply it with 7 =334 then take 334_256=78 and done

Answer:

22x 28 x 25 x 30 = 462000

whats are the units.....cm or m

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{22(28)(25)(30)}\\\large\textsf{22(28) = \bf 616}\\\large\textsf{616(25)(30)}\\\large\textsf{616(25) = \bf 15,400}\\\large\textsf{15,400(30)}\\\large\textsf{ = \bf 462,000}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 462,000}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

10 has 2 digits

1000 has 4 digits

Difference of 2 digits

Answer:

[tex]40\ cm^3[/tex]

Step-by-step explanation:

Let the actual volume is V.

The measured volume of an object is 46 cubic cm  which was 15% high from the actual volume.

According to the given condition,

[tex]V+\dfrac{15V}{100}=46\\\\\dfrac{115V}{100}=46\\\\V=\dfrac{4600}{115}\\\\V=40\ cm^3[/tex]

So, the actual volume was [tex]40\ cm^3[/tex].

Answer:

A.

by-step explanation:

m to k

1 to 1.609

Answer:

[tex]Ratio = 1 : 6[/tex]

Step-by-step explanation:

Given

[tex]n = 24[/tex]

Results:

[tex]1, 2, 0, 0, 3, 2, 4, 2, 1, 4, 3, 2[/tex]

[tex]1, 1, 2, 1, 0, 3, 3, 2, 4, 1, 1, 0[/tex]

Required

Ratio of students not participating to all students

Students not participating are represented with 0;

So, we have:

[tex]n(0)= 4[/tex]

The ratio is then calculated as:

[tex]Ratio = n(0) : n[/tex]

[tex]Ratio = 4 : 24[/tex]

Divide by 4

[tex]Ratio = 1 : 6[/tex]

Answer:

x + y ≥ 240

5x + 8y ≤ 1200

Step-by-step explanation:

Assume;

Number of chicken meals = x

Number of Beef meals = y

Total budget = $1200

Find:

Inequality

Computation:

Number of chicken meals + Number of Beef meals  ≥ Total students

x + y ≥ 240

Total cost = (Number of chicken meals)(Cost of chicken meal) + (Number of Beef meals)(Cost of beaf meal)

5x + 8y ≤ 1200

Answer:

sum of five and 3 is divided by n

Answer:

2

Step-by-step explanation:

if you're looking at the table and you heard of rise/run, your rise is -10 if you go down from (6,6) and -5 if you go left to reach (1,-4). That will give you -10/-5 which gives you a positive 2. it would be the same if you went up 10 from (1,-4) and then 5 right to reach (6,6).

Answer:

358

Step-by-step explanation:

the step by step is in the photo so look at it

Answer:

(1/3) r2 =(1/3) r +14

1/6 divided by 83 r + 14

97r

i think...

I hope this helps you!

XoXo Mashayla

Step-by-step explanation:

Answer:

y = 5x + 19

Step-by-step explanation:

y = 5x + b

4 = 5(-3) + b

4 = -15 + b

19 = b

Answer:

4x^4+3x^2y^2+9y^2

(2x^2)^2 + 2×2x^2×3y^2 + (3y^2)^2 - 9

(2x^2 + 3y^2)^2 - (3)^2

(2x^2 +3y^2+3)(2x^2+3y^3-3)

Answer:

Answer is A

Step-by-step explanation:

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]f(x) = \frac{2x + 3}{4x + 5} \\[/tex]

For [tex]f(-9)[/tex], put "[tex]-9[/tex]" for every value of "[tex]x[/tex]".

[tex]↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\ [/tex]

[tex]↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\[/tex]

[tex]↬ f(-9) = \frac{ - 15}{ - 31}\\ [/tex]

[tex]↬ f(-9)= \frac{15}{31}\\ [/tex]

[tex] ↬f(-9)= 0.48\\ [/tex]

[tex]\bold{ \green{ \star{ \red{Mystique35}}}}⋆[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = \dfrac{2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{ 2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{2(-9) + 3}{4(-9) + 5}}[/tex]

[tex]\mathsf{2(-9)}[/tex]

[tex]\mathsf{\bf = -18}[/tex]

[tex]\mathsf{y = \dfrac{-18 + 3} {4(-9) + 5}}[/tex]

[tex]\mathsf{-18 + 3}\\\mathsf{= \bf -15}[/tex]

[tex]\mathsf{y = \dfrac{ -15} {4(-9) + 5}}[/tex]

[tex]\mathsf{4(-9)}\\\mathsf{\bf = -36}[/tex]

[tex]\mathsf{y = \dfrac{-15}{-36 + 5}}[/tex]

[tex]\mathsf{-36 + 5}\\\mathsf{= \bf-31}[/tex]

[tex]\mathsf{y = \dfrac{-15}{ -31}\rightarrow\boxed{\bf \dfrac{15}{31}}}[/tex]

[tex]\boxed{\boxed{\huge\text{Answer: } \boxed{\bf f(-9) = \dfrac{15}{31}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Hello!

8 × 3 + 10 - 13 × 2 =

= 24 + 10 - 13 × 2 =

= 24 + 10 - 26 =

= 34 - 26 =

= 8

Good luck! :)

Answer:

8

Step-by-step explanation:

According to bdmas rule

First multiply 8 and 3 or 13 and 2

Then, there will be 24 + 10 - 26

Then add 24 + 10, there will be 34

and again minus by 26

Then finally answer will be 8

Answer:

option 2. -1 1/4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 1/4x

Step 2: Evaluate

Answer:

Linear functions are

f(x) = 0.45 x - 1

f(x) = 5

f(x) = 4.5 x + 18

Quadratic function is

R(x) = 19x^2

Step-by-step explanation:

The linear function is a function in which the degree of function is 1.

So,

f(x) = 0.45 x - 1

f(x) = 5

f(x) = 4.5 x + 18 are the linear functions.

The quadratic function is a function in which the degree of function is 2.

So,

R(x) = 19 x^2 is a quadratic function.

The exponential function is a function which involves the exponents.

Answer:

pic

Step-by-step explanation:

Answer:

B) 67°C.

Step-by-step explanation:

Newton's Law of Cooling is given by:

[tex]\displaystyle \frac{dT}{dt}=k(T-A)[/tex]

Where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.

We are given that the coffee cools from 100°C to 90°C in one minute at a room temperature A of 25°C.

And we want to find the temperature of the coffee after four minutes.

First, solve the differential equation. Multiply both sides by dt and divide both sides by (T - A). Hence:

[tex]\displaystyle \frac{dT}{T-A}=k\, dt[/tex]

Take the integral of both sides:

[tex]\displaystyle \int \frac{dT}{T-A}=\int k\, dt[/tex]

Integrate:

[tex]\displaystyle \ln\left|T-A\right| = kt+C[/tex]

Raise both sides to e:

[tex]|T-A|=e^{kt+C}=Ce^{kt}[/tex]

The temperature of the coffee T will always be greater than or equal to the room temperature A. Thus, we can remove the absolute value:

[tex]\displaystyle T=Ce^{kt}+A[/tex]

We are given that A = 25. Hence:

[tex]\displaystyle T=Ce^{kt}+25[/tex]

Since the coffee cools from 100°C to 90°C, the initial temperature of the coffee was 100°C. Thus, when t = 0,T = 100:

[tex]100=Ce^{k(0)}+25\Rightarrow C=75[/tex]

Hence:

[tex]T=75e^{kt}+25[/tex]

We are given that the coffee cools from 100°C to 90°C after one minute at a room temperature of 25°C.

So, T = 90 given that t = 1. Substitute:

[tex]90=75e^{k(1)}+25[/tex]

Solve for k:

[tex]\displaystyle e^k=\frac{13}{15}\Rightarrow k=\ln\left(\frac{13}{15}\right)[/tex]

Therefore:

[tex]\displaystyle T=75e^{\ln({}^{13}\! /\!{}_{15})t}+25[/tex]

Then after four minutes, the temperature of the coffee will be:

[tex]\displaystyle \begin{aligned} \displaystyle T&=75e^{\ln({}^{13}\! /\!{}_{15})(4)}+25\\\\&\approx 67^\circ\text{C}\end{aligned}[/tex]

Hence, our answer is B.

Answer:

A

Step-by-step explanation:

because y-intercept is when x=0, so right on the y axis.

Answer:

V = wlh

Step-by-step explanation:

Given

w = [tex]\frac{V}{lh}[/tex] ( multiply both sides by lh to clear the fraction )

wlh = V

Answer:

Step-by-step explanation:

Given identity is,

[tex]\text{tanA}=\pm\sqrt{\frac{1-\text{cos2A}}{1+\text{cos2A}}}[/tex]

To prove this identity, we will take left side of the identity,

[tex]\pm\sqrt{\frac{1-\text{cos2A}}{1+\text{cos2A}}}=\pm\sqrt{\frac{1-(1-2\text{sin}^2A)}{1+(2\text{cos}^2A-1)} }[/tex]

                  [tex]=\pm\sqrt{\frac{1-1+2\text{sin}^2A}{1+2\text{cos}^2A-1} }[/tex]

                  [tex]=\pm\sqrt{\frac{2\text{sin}^2A}{2\text{cos}^2A} }[/tex]

                  [tex]=\pm(\sqrt{\text{tan}^2A})[/tex]

                  [tex]=\text{tanA}[/tex] [Right side of the identity]

Hence, proved.