Which strategy used in the above essay appeals to the audience’s sense of logic? a) use of details b) appeal to ethics c) attention grabber d) emotional language.

There are different kinds of poem. In the poem "War Is Kind," the best description of the effect of the repetition of the lines is that the lines emphasize the harshness of the scenes the speaker describes.

War is not a pleasant situation. Stephen Crane in his poem calls war "kind". This is because he laugh at the idea that young men often believe that going to war is noble and dying for one's country is an heroic act.

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Answer:

These lines emphasize the harshness of the scenes the speaker describes.

Explanation:

D on edge!

Answer:

um... ok

Explanation:

Answer:

B. Low Light

Explanation:

Answer:

The option A, releasing fimbria to for fertilization is not a function of the female reproductive system.

Answer:

B) A humiliating sight

Explanation:

took the test on edge

Answer:

B

Explanation:

The first person was right

WWW is an abbreviation for World Wide Web ...

Corporation, Customer, Competitors (3C's) Model is a business model that focuses on the three key factors needed for success. This model was conceived by the famous business strategist, Kenichi Ohmae.

Answer:

Explanation:

Considering the situation described in the question, the type of sample Inspector used is called Simple Random Sampling

Simple Random Sampling is a random sampling technique in which participants are taken randomly from a given population.

Here, the given population is the hospital chain with multiple locations; since the inspector only randomly selects some of their locations, this is a simple random sampling.

Hence, in this case, it is concluded that the correct answer is Simple Random Sampling

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Answer:

Its intended goal is to protect the interests of those who hold equity in the bank.

The amount of capital required depends on the type of assets the bank holds.

Explanation:

edge!!

Protista, would be the answer

Answer:

0.67 m

Explanation:

Mass of Tasha, m1 = 20 kg Mass of the board, m2 = 10 kg

0.67 m is correct for Tasha has mass 20 kg and wants to use a 4.0-m board of mass 10 kg as a seesaw. Her friends are busy, so Tasha seesaws by herself by putting the support at the system's center of gravity when she sits on one end of the board.

(Hope this helps can I pls have brainlist (crown)☺️)

How are we supposed to answer this question without the theorems mentioned in the question????

Answer:

(3√7)4

81−−√7

Explanation:

We have

x = t³   ===>   dx/dt = 3t²

y = t⁴   ===>   dy/dt = 4t³

Then with the given parameteriztion, the line integral along C of x/y is

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^3}{t^4} \sqrt{(3t^2)^2 + (4t^3)^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac1t \sqrt{9t^4 + 16t^6} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{\sqrt{t^4}}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}[/tex]

The line integral will be "[tex]\frac{265\sqrt{265} - 125 }{48}[/tex]". To understand the calculation, check below.

According to the question,

Curves, x = t³ or,

            [tex]\frac{dx}{dt}[/tex] = 3t²

             y = t⁴ or,

            [tex]\frac{dx}{dt}[/tex] = 4t³  

Now, the line integral along C will be:

→ [tex]\int\limits_C {\frac{x}{y} } \, ds[/tex] = [tex]\int\limits^4_1 {\frac{t^3}{t^4} }[/tex] √(3t²)² + (4t³)² dt

             = [tex]\int\limits^4_1 {\frac{1}{t} }[/tex] √9t⁴ + 16t⁶ dt

             = [tex]\int\limits^4_1 {\frac{t^4}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1 {\frac{t^2}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1[/tex] t√9 + 16t² dt

             = [tex]\frac{1}{32}[/tex] [tex]\int\limits^4_1[/tex] √9 + 16t² d (9 + 16t²)

             = [tex]\frac{1}{32}\times \frac{2}{3}[/tex] [tex](9+16t^2)^{\frac{3}{2} } |_1^4[/tex]

             = [tex]\frac{1}{48}[/tex] ([tex]265^{\frac{3}{2}} - 25^{\frac{3}{2}[/tex])

             = [tex]\frac{265 \sqrt{265 } -125 }{48}[/tex]

Thus the above approach is correct.

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Answer: I=U/R

U=I*R U=0.10*15=1.5

Explanation:

The term which best describes the region "b" of the phospholipid model in the attached image (below) is: Hydrophobic.

Phospholipids are also referred to as phosphatides and they are a type of lipid whose molecule comprises the following:

This ultimately implies that, a large potion of the cell (plasma) membrane is made up of lipids, which are mainly phospholipids and they control the movement of large hydrophilic molecules such as alkanes, oils, and fats.

In conclusion, hydrophobic is a term that is used to describe the tail or lower part of a phospholipid model, which is the "b" region in the image attached below.

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Answer: 20 km

Explanation:

6 + 4 + 6 + 4 = 20

Answer:

Its less than or equal to 17

Explanation:

Answer:

Where's the graph?

Explanation:

Considering the definition of enthalpy of vaporization, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is 18.8 kJ.

When a material changes phase from solid to liquid, or from liquid to gas, a certain amount of energy is involved in this phase change.

In case of phase change from liquid to gas, this amount of energy is known as enthalpy of vaporization (symbolized as ∆Hvap).

So, the enthalpy of vaporization is the amount of energy required to change a unit of mass (for example, moles or kg) of a substance from phase liquid to phase gas at constant temperature and pressure.

In this case, you know that enthalpy of vaporization is ∆Hvap = 38.0 kJ/mol.

On the other side, you want to vaporize 15.8 g of CH₃OH.  Then, being the molar mass of the compound 32 [tex]\frac{g}{mole}[/tex] (that is, the amount of mass contained in one mole), the number of moles to be vaporized is:

[tex]15.8 gramsx\frac{1 mole}{32 grams} =0.49375 moles[/tex]

Then, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is calculated taking into account the enthalpy of vaporization by:

0.49375 moles× 38.0 [tex]\frac{kJ}{mol}[/tex]= 18.76 kJ ≅ 18.8 kJ

Finally, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is 18.8 kJ.

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Answer:

0.25

Explanation:

multiply the fraction by the same number by the denominator.

Explanation:

Whooo doesn't like food

By definition, the heat required to change 1 gram of a solid at its normal melting point is called heat of fusion.

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

Fusion is the process by which a solid becomes a liquid phase. In this case, the temperature remains constant throughout the time that the solid turns into a liquid.

This occurs because in the solid phase the molecules are held together forming a rigid crystalline structure, in such a way that the substance has a defined shape and volume. As heat is supplied, the energies of the solid's particles gradually increase. After a certain time, this energy becomes so great that some of the particles exceed the force that kept them in their fixed positions.

In this way, the greatest separation between the particles is associated with the liquid phase.

Thus, the energy absorbed by the substance is used to separate the molecules more than in the solid phase, so that the temperature does not increase during the change of state.

In summary, it is called "heat of fusion", the energy required to change 1 gram of substance from a solid state to a liquid state, without changing its temperature.

In others words, the heat required to change 1 gram of a solid at its normal melting point is called heat of fusion.

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Answer:

Law of transparency

Explanation:

The law that will be used in simplifying the option is a3¹⁰/3⁴ is the quotient of powers. The correct option is a.

According to the Quotient of Powers Property, exponents are subtracted from powers when they are divided by the same base, provided the base is not equal to 0. Using variables, nanb=n(ab) n a n b = n (a b) is defined.

It is quicker and simpler to subtract the bases than to write down the multiplications and cancel. The denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator, is how the Quotient Rule defines the derivative of a quotient.

[tex]\dfrac{x^a}{x^b} = x^{( a - b)}[/tex]

[tex]\dfrac{3^{10}}{3^4} = 3 ^ {( 10 - 4)}\\\\\dfrac{3^{10}}{3^4} = 3^6[/tex]

Therefore, the correct option is a, the quotient of powers.

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The question is incomplete. Your most probably complete question is given below:

The equation is:

3^10/3^4

Answer: ( Answer A) It is important to understand historical causes as the English language continues to develop

Explanation: because I just took the assignment

The sentence that best concludes the paragraph is that it is important to understand historical causes as the English language continues to develop. Thus, the correct option for this question is A.

A Paragraph may be defined as a collection of sentences that significantly represents some thoughts and ideas to the reader or audience. It is a brief piece of writing that all relate closely to the topic sentence.

According to the context of this question, it is consequential in order to understand the causes and influence of the English language which continues to develop till now. It is the significance of the English language.

Therefore, it is important to understand historical causes as the English language continues to develop is the sentence that best concludes the paragraph. Thus, the correct option for this question is A.

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Answer:

1500 N

Explanation:

Weight = mg = 150 kg * 10 m/s^2

Weight = 1500 N

9

9 is a square root because when u multiply 3×3=9