Which sport shows the greatest variability in players’ heights? which sport shows the least variability?

Answer:

25π + 30m which is approx. 108.54m

Step-by-step explanation:

First, we can work out the angle of the middle of the playground. 360 - 60 = 300°

Next, we can find out the arc length of the playground using the formula:

θ/360 × πd → 300/360 × 30π = 25π

Finally, we need to add on the two radii to find the perimeter of the playground: 25π + 15 + 15 = 25π + 30m which is approx. 108.54m

Hope this helps!

Answer:

Step-by-step explanation:

Answer:

"LOCATION: Most temperate, deciduous (leaf-shedding) forests are located in the eastern United States, Canada, Europe, China, Japan, and parts of Russia. Deciduous forests are broken up into five zones."

Step-by-step explanation:

✖ Brazil

✓ China

✓ United States

✓ Russia

✖ Chile

Hopefully this helps you!

-Keira

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

[tex]-7x+3y=-21.5[/tex]  

Convert it to the general form given below:

[tex]\rm y=mx+c[/tex]

[tex]\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x[/tex] or

[tex]\rm y = \frac{7}{3}x-\frac{21.5}{3}[/tex]

[tex]m = \frac{7}{3}[/tex]   (Slope of AB line)

For the slope(m') of the PQ line:

[tex]\rm m'=-\frac{1}{m}[/tex]    ( because AB and PQ are perpendicular to each other)

[tex]\rm m' = -\frac{3}{7}[/tex]

We know the:

[tex]\rm (y-y')=m'(x-x')[/tex]

Where (x', y') = (7, 6), we get:

[tex]\rm (y-6)=-\frac{3}{7} (x-7)[/tex]

[tex]\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63[/tex]

[tex]\rm -1.5x-3.5y=-31.5[/tex]   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

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Answer:

51.0285714…

Step-by-step explanation:

you just multiply them together.

Answer:

Step-by-step explanation:

→ Multiply the 2 lengths together

[tex]6\frac{5}{7} *7\frac{3}{5}[/tex]

→ Convert both to improper

[tex]\frac{47}{7} *\frac{38}{5}[/tex]

→ Multiply

[tex]\frac{1786}{35}[/tex]

→ Convert to mixed fraction

[tex]51\frac{1}{35}[/tex]

Answer:

False

Step-by-step explanation:

45/100 × 72 = 32.4

45/72 × 100 = 62.5

62.5 ≠ 32.4

Answer:

false

Step-by-step explanation:

45/100x72=32.4%

45/72X100=62.5%

Answer:

143 square meters

Step-by-step explanation:

The surface has a width of 11 meters and a length of 13 meters.

13 x 11 = 143.

Is this correct?

Answer:

180 degree rotation

Step-by-step explanation:

Answer:

Reflect across the y-axis

Translate horizontally 7 units right

Step-by-step explanation:

Alright I'll try to quickly answer this for you.

Firstly you could try reflecting figure P across the y axis. That would mean multiplying the whole function times -1.

So a point like (-2,3) would be come (-2,-3), and then visualize moving that point to where it would be on figure Q. It looks like it would be on (5,-3) on figure Q. So to take (-2,-3) to (5,-3) you translate it horizontally 7 units right.

Answer:

D. answer po

Step-by-step explanation:

Tama yan na D

Answer:

I believe the answers are a and e.

Step-by-step explanation:

Let me know if you want an explanation.

Hope this helps!!!

The equation can be used to model the height as a function is[tex]\rm h = 0.5\ cos(\frac{\pi}{6} t)+9.5[/tex]  where t is time, the second option is correct.

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We know the general equation for the cosine function:

[tex]\rm y = A\ cos(bx-c)+d[/tex]

Where A is the amplitude

We have a wall clock that varies from 9 feet to 10 feet.

The value of 'A' is given by:

[tex]\rm A = \frac{10-9}{2} \Rightarrow 0.5[/tex]

b is the cycle speed, we know:

[tex]\rm T = \frac{2\pi}{b}[/tex]   (T is period)

[tex]\rm12 = \frac{2\pi}{b}[/tex]

[tex]\rm b=\frac{\pi}{6}[/tex]

The value of d is given by:

[tex]\rm d = \frac{10+9}{2}[/tex]

d = 9.5

The equation can be modeled:

[tex]\rm h = 0.5\ cos(\frac{\pi}{6} t)+9.5[/tex]   (c =0 and y =h)

Thus, the equation is  [tex]\rm h = 0.5\ cos(\frac{\pi}{6} t)+9.5[/tex]

Know more about trigonometry here:

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Answer: B, h = 0.5 cosine (StartFraction pi Over 6 EndFraction t) + 9.5

Step-by-step explanation: edge :)

Answer:

4

Step-by-step explanation:

By the triangle midsegment theorem, 2(WY)=VZ.

So, 2(7s)=s+52, meaning s=4.

Answer:

12

Step-by-step explanation:

Laura makes 14 dollars an hour and it will take her 12 hours to make a total of $168!

Answer: AAS

Step-by-step explanation:

Answer:

Ten apples cost 9 dollars

Step-by-step explanation:

C(10) = 9

The input is 10 and the output is 9

You bought 10 apples for 9 dollars

Answer:

The last one

Step-by-step explanation:

10 is a function of C which says that the cost of 10 = 9.

Hey There! Happy to Help! Your answer is below.

Answer:

17/20 = 0.85000

Step 1:

⇒ (3/4 + 4/5) - 7/10

Step 2:

⇒ (3/4 + 4/5) - 7/10

Step 3:

⇒(3/4 + 4/5) - 7/10

Step 4:

⇒ Find the Least Common Multiple

Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

5 0 1 1

Product of all

Prime Factors  4 5 20

  Least Common Multiple:

     20

⇒  Calculate multipliers for the two fractions

⇒  Denote the Least Common Multiple by  L.C.M

   ⇒ Denote the Left Multiplier by  Left_M

⇒   Denote the Right Multiplier by  Right_M

⇒    Denote the Left Deniminator by  L_Deno

⇒    Denote the Right Multiplier by  R_Deno

⇒ Rewrite the two fractions into equivalent fractions

⇒ Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num.               3 • 5

-----------------------------    =  ------------

L.C.M                                     20  

  R. Mult. • R. Num.      4 • 4

----------------------------- =  -------

   L.C.M                           20  

 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 + 4 • 4     31

------------------ = ---

     20           20

Equation at the end of step 4:

 31     7

---- - ----

20   10

Step 5:

 Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       10

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 1 2

5 1 1 1

Product of all

Prime Factors  20 10 20

   Least Common Multiple:

     20

Calculating Multipliers :

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num.      31

------------------------- = ----

L.C.M                      20

R. Mult. • R. Num.      7 • 2

---------------------------- = -----

L.C.M              20  

Adding fractions that have a common denominator :

Adding up the two equivalent fractions

31 - (7 • 2)     17'

--------------  = ---

20          20

 17          

 —— = 0.85000

 20        

Answer:

8. = 0.1x = -0.12. 8yz. 88. D. – 1.2. = y 2 3

Step-by-step explanation:

Answer:

x = 21

a= 22

b = 13

Step-by-step explanation:

18 / 6 = 3

3 * 7 =21

20 / 10 = 2

2 * 11 = 22

10 / 20 = 0.5

26 * 0.5 = 13

Answer:

A' (- 4, 6 )

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply each coordinate by the scale factor , that is

A (- 6, 9 ) → A' ([tex]\frac{2}{3}[/tex] (- 6), [tex]\frac{2}{3}[/tex] (9) ) → A' (- 4, 6 )

Answer:

The perimeter is 24 feet :]

hope this helps! <33

Answer:

12 feet

Step-by-step explanation:

The perimeter of a rectangle is just the sum of all the sides. There are four sides, two that represent the width, and two that are the length. Basically, the easiest way for us to find the perimeter of this shape is to add together the length and the width 2 times.

4 + 2 + 4 + 2 = 12

So, the perimeter of the mirror is 12 feet! I hope this helps! Have a lovely day!! :)

Rotating a shape involves moving it in a circular way around its axis

The true statement about the rotation is (c) Rotating a right triangle around its vertical axis will form a cone.

When a two-dimensional shape such as triangles, trapezoid, square, rectangles, etc are rotated about their axes, the new shape formed is a three-dimensional shape

As a general rule, the rotation of a right triangle around its axis would form a cone.

Hence, the true statement about the rotation is (c)

Read more about rotation at:

https://brainly.com/question/4289712

Answer: C. Rotating a right triangle around its vertical axis will form a cone.

Step-by-step explanation: CORRECT on Plato/Edmentum.

Answer:

Step-by-step explanation:

The salaries are the same. Only the fraction of how much is saved is quite different.

Equation

x ( 9/11 - 7/9) = 1584

Explanation: The salary amount is x. The fractional amounts saved are also given. You have to take the difference because one of the people saves more than the other.

The amount that is more is 1584.

Solution

9/11 = 0.8182

7/9 = 0.7778

9/11 - 7/9 = 0.8182 - 0.7778 = 0.0404

Put that into the equation.

x(0.0404) = 1584                     Divide by 0.0404)

x(0.0404) = 1584/0.0404        

answer:x = 39204

Answer:

You have no image so how could i solve?

Step-by-step explanation:

Answer:Rewrite the cartesian equation as a polar equation.

Rewrite the cartesian equation as a polar equation.r

Rewrite the cartesian equation as a polar equation.r2

Rewrite the cartesian equation as a polar equation.r2cos

Rewrite the cartesian equation as a polar equation.r2cos2

Rewrite the cartesian equation as a polar equation.r2cos2(

Rewrite the cartesian equation as a polar equation.r2cos2(θ

Rewrite the cartesian equation as a polar equation.r2cos2(θ)

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6r

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−r

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ)

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ)=

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ)=−

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ)=−9

Rewrite the cartesian equation as a polar equation.r2cos2(θ)−6rcos(θ)−rsin(θ)=−9Tap to view steps...

The quadratic function which is represented by the graph of a Parabola fails the Horizontal Line Test thus is not a one to one function. Therefore the inverse is not a function unless with restricted domain.

Edit: Adding the solution below to address update in the comments:

y

=

(

x

+

3

)

2

x

=

(

y

+

3

)

2

±

√

x

=

y

+

3

y

=

−

3

±

√

x

=> inverse relation

Restricting the domain: Recall that the domain and the range of the inverse function are the range and the domain of the original function respectively. The range of the original function in this case is

y

≥

0

, that should be the domain of the inverse function so for the inverse function we take the positive square root as follow:

f

−

1

(

x

)

=

−

3

+

√

x

=> this is the inverse function the domain and the range are:

domain:

x

≥

0

range:

y

≥

−

3

This means we need to restrict the domain of the original function to:

x

≥

−

3

in order for it to have an inverse function.

Answer:

angle 3 = 61

angle 4 = 119

angle 6 = 61

angle 7 = 119

Step-by-step explanation:

there are a few ways you could look at this

first, each angle that is diagonal from eachother is going to be equal so 1 is the same as 3, 2 is the same as 4 etc

also each line going across has to be 180° so if angel 1 was 175 then angle 2 has to be 5 so when you combine them it becomes 180

if you look at the sizes some are bigger than the others, because you're given angle 1 = 61 then all the other small angles would be 61 too, and 180 - 61 = 119 so the all the big ones have to be 119

if this confused u more I'm sorry lol let me know if this helped

Answer:
Answer: (b) 5.

Step-by-step explanation:

Simple and best practice solution for (c-5)d=2 equation. ... If it's not what You are looking for type in the equation solver your own equation and let us solve it. ... 2 + 5d cd = 2 + 5d Divide each side by 'd'. c = 2d-1 + 5 Simplifying c = 2d-1 + 5 Reorder ... 11/4-t8 | | (3x^2+5x+2)+(4x^2+3x+2)= | | 4Y+7-Y=4+2Y-8 | | 10x+190=360 ...

For example, let's say with have the equation x+5 ... If we evaluate the same expression when x=10, we get 3(10)+7=30+7=37. Here's a variable expression with two variables: 3x−2y ... How do you express the phrase "a number z divided by 19" as an algebraic expression? ... How do you simplify 11c+5d−9c−9d?Let the number of cows be x and their legs be 4x. ... or, x = 7 [dividing by 2 on both sides]. ... The roots of the equation ax2 + bx + c = 0 will be reciprocal if: ... A circle of radius 10 inches has its center at the vertex C of an equilateral triangle ABC ... (a) 15, (b) 30, (c) 60, (d) 90, (e) 120. Circle Problem Answers. Answer: (b) 5.

Answer:

C) 50°

Step-by-step explanation:

[tex]m\angle BEC= 180\degree-(65\degree+65\degree)[/tex]

[tex]\implies m\angle BEC= 180\degree-130\degree[/tex]

[tex]\implies m\angle BEC= 50\degree[/tex]