which shapes have 2 obtuse angles

Answer:

68,000

Step-by-step explanation:

53,000+5,000x3

5,000x3=15,000

53,000+15,000=68,000

Answer:

try -5

Step-by-step explanation:

mainly because it says -3 plus 5 and there's only 4 and 5 so It can't really go further

Answer:try -5

Step-by-step explanation:

mainly because it says -3 plus 5 and there's only 4 and 5 so It can't really go further

Therefore , the solution of the given problem of equation comes out to be  the error range for x is [1250, 1350].

A mathematical equation is a formula that uses the equal sign (=) to connect two statements and express equality. A mathematical statement that proves the equality of two mathematical expressions is known as an equation in algebra. For instance, the components 3x + 5 and 14 in the equation 3x + 5 = 14 are separated by an equal sign. The equal sign is a crucial part of mathematical formulas, especially equations. Algebra is frequently utilized in equations. Algebra is used in mathematics when it is difficult to determine a precise quantity.

Here,

Given: Some material has a length of 8.3 meters

We have provided a number, x, that has been rounded to two significant numbers with the supplied error.

Next, we must determine the x error interval.

​It is necessary for x to have a value that is both bigger than or equal to 1250 and less than or equal to 1300.

i.e.,1250 ≤ x ≤ 1300 ---(1)

2. The value of x is more than 1300 but not equal to 1350.

1300  ≤ x ≤ 1350--- (2)

When (1) and (2) are combined, we obtain

1250≤ x ≤ 1350

As a result, 1350 is not part of the error-interval for x.

As a result, the interval notation is [1250, 1350].

As a result, the error range for x is [1250, 1350].

Therefore , the solution of the given problem of equation comes out to be  the error range for x is [1250, 1350].

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Answer:

Step-by-step explanation:

8x+18=2x+x+4x-3

8x+18=7x-3

perimeter = x+21

quadrilateral with both pairs of opposite sides congruent

What is a parallelogram?

A parallelogram is the name given to a quadrilateral in geometry. In a parallelogram, the opposing sides are parallel and of equal length. The rhombus, rectangle, and square are just a few shapes that are parallelograms.

Having two sets of parallel sides makes a quadrilateral a parallelogram. A parallelogram has opposite sides that are the same length and angles that are the same size. Additionally, the internal angles on the same transverse side are supplementary. 360 degrees are equal to the total of all internal angles.

If both pairs of opposite sides of a quadrilateral are congruent , then the quadrilateral is a parallelogram.

So, the option  I only is correct

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Answer:

1st, 4th and 5th are correct.

Step-by-step explanation:

The slope of the straight line connecting the break's ends to the function's diagram.

For 0 < x < 4 will be -60

For 4 < x < 8 will be -31

The mathematical formula f (x) = [tex]$$a^{x[/tex] denotes an exponential function. a constant known as the function's base and a variable called x are present. The transcendental number e, roughly equivalent to 2.71828, is the most frequent exponential-function base.

When a positive constant other than 1 is raised to a variable exponent, the function is said to be exponential. Solving at a certain input value yields the evaluation of a function. If you know the growth rate and the starting point, you can find an exponential model.

We have to use the knowledge of functions to describe the average rates of each one of them, so:

For 0 < x < 4 will be -60

For 4 < x < 8 will be -31

It is a measurement of how much the function changed for one person on average throughout that interval. It results from the slope of the straight line connecting the break's ends to the function's diagram.

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The equation that models the height of the tent, h, in feet, with respect to the horizontal distance in feet from the left edge, d, is h = 1.5 d + h0.

The height of the tent is 22. 5 feet at a horizontal distance of 15 feet.

What is an equation?

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("=").

The height of the tent varies at a rate of 1. 5 feet with the horizontal distance from the left edge.

This can be written as -

h = 1.5 d, where d is the distance.

So, the equations that models the situation is -

h = 1.5 d + h0

The peak of the tent is at 30 feet and is at a horizontal distance of 20 feet from the left edge.

So, when d =20, then h =30.

Plugging the values in the equation -

30 = 1.5 (20) + h0

30 = 30 + h0

h0 = 0

The height of the tent is 22. 5 feet.

So, now h = 1.5 d and h = 22.5.

Equating these two -

22.5 = 1.5 d

d = 22.5/1.5

d = 15

Therefore, the distance value is obtained as 15 feet.

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The equation -15x + 4x + 2 - x = x has  solution and the solution is 2/13

From the question, we have the following parameters that can be used in our computation:

-15x+4x+2-x= x+

Express the equation properly

So, we have the following representation

-15x + 4x + 2 - x = x

Collect the like terms in the equation

This gives

-x - 15x + 4x - x = -2

Evaluate the like terms

So, we have the following representation

-13x = -2

Divide both sides by -13

This gives

x = 2/13

Hence, the solution is 2/13

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Answer:

Step-by-step explanation: infinity or undefined.

An expression to represent the sum of their ages is as follows.

g = 14 + L

If the ratio of the ages of X and Y is p:q and their sum is X, then the following formula can be used to calculate Y's age: Age of Y = Y/Total Ages x Total Ratios. Age of Y = (p+q) q x A.

Assume that L is Louannel's sister's age, m is Mark's age, and g is Gregory's age.

Gregory's age difference with his cousin Mark, who is 20 years older (m).

∴ g = 20 + m            .............(1)

Also given that Mark is 6 years younger than his sister Louanne(L)

∴ m = L - 6                ............(2)

Now, substituting m = L - 6 from (2) in (1),

∴ g = 20 + L - 6

∴ g = 14 + L

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Mama bear only ate (1/4) of the pie, leaving Goldilocks with the remaining (1/8) fraction.

The fraction is expressed in the form a/b, where an is referred to as the numerator and b is referred to as the denominator. The fraction is a rational number that only divides two integers.

Let the pie's largest portion be a.

Half of the pie was consumed by Papa Bear.

Papa Bear then consumed = (1/2)a.

Rest of the pie is equal to a- (1/2).

a= (1/2)a

Mama bear consumed (half) of the remaining pie.

Mother bear consumed (1/2)(1/2).

pie portion a= (1/4) pie portion after mom bear has eaten = (1/2)

a- (1/4)a= (1/4)a

Baby bear afterwards consumed (half) of the remaining pie.

Baby bear ate (1/2)(1/4), thus. After the young bear has finished eating, the remaining pie is equal to (1/4) a- (1/8)a= (1/8)

The remainder of the component was given to GoldLiocks.

As a result, mom bear only ate (1/4) of the pie, leaving Goldilocks with the remaining (1/8) portion.

The complete question is Papa Bear ate 1/2 of a pie. Mama Benr ate 1/2 of what was left Baby Bear ate 1/2 of what

was left after Mama Bear finished.

3) What fractional part of the pie did Mama Bear eat?

4) What fractional part of the pie was left for Goldilocks?

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Answer:

6

Step-by-step explanation:

Call the bigger number a, smaller b
a + b = 10
b + 2 = a
a + b + 2 = a + a = 2a = 12
a = 12 : 2
a = 6

 As per Given data,

The month in which the balance of two bank accounts A is become equal to the balance of account B is 30thmonths,

Unknown variables are used to find the unknown values of the problem using the algebraic expressions.

Month       Account A        Account B

 0                    $ 100                 $ 250  

  1                    $ 125                 $ 270

  2                   $ 150                 $ 290

Clearly

The amount in account A is growing with $25 each month. Thus, the amount in this account in nth month is,

100+25[tex]n[/tex]

The amount in account B is just growing with $20. Thus, the amount in this account in nth month is,

250+20[tex]n[/tex]

x month

balances of two

account becomes equal,

then

100 + 25x =250 + 20x

25x - 20x = 250 - 100

5x = 150

x =30

Therefore, in 30th month balance of account A equal to balance of account B

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Q. The table shows the balances of two bank accounts for 3 months. In 30th month will the balance of account A be equal to the balance of account B?

Month       Account A      Account B

   0               $100                $250

    1               $125                 $270

    2              $150                 $290

x = 5

AB = 6

BC = 13

A line can be defined as a straight set of points that extend in opposite directions, It has no ends in both directions(infinite). It has no thickness. It is one-dimensional.

Given,

AB = 2x - 4

BC = 3x - 2

AC = 19

By the figure

AB + BC = AC

2x - 4 + 3x - 2 = 19

5x - 6 = 19

5x = 25

x = 5

AB = 2 × 5 - 4 = 10 - 4 = 6

BC = 3 × 5 - 2 = 15 - 2 = 13

Hence the value of x, AB and BC is 5, 6, 13 respectively.

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Answer:

Yes, the zeros can be used as place holders. When using place holders, the value does not change.

Answer:

[tex]\dfrac{3}{a-6}\quad \textsf{if}\;\;a \neq -6,a \neq 6[/tex]

Step-by-step explanation:

Given expression:

[tex]\dfrac{a}{a-6}-\dfrac{3}{a+6}+\dfrac{a^2}{36-a^2}[/tex]

Rewrite the third fraction:

[tex]\implies \dfrac{a^2}{36-a^2}=\dfrac{-a^2}{-(36-a^2)}=\dfrac{-a^2}{a^2-36}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Difference of two squares }\\\\$x^2-y^2=(x-y)(x+y)$\\\end{minipage}}[/tex]

Apply the difference of two squares to the denominator of the third fraction:

[tex]\implies a^2-36=a^2-6^2=(a-6)(a+6)[/tex]

Therefore the expression can be written as:

[tex]\implies \dfrac{a}{a-6}-\dfrac{3}{a+6}+\dfrac{-a^2}{(a-6)(a+6)}[/tex]

[tex]\implies \dfrac{a}{a-6}-\dfrac{3}{a+6}-\dfrac{a^2}{(a-6)(a+6)}[/tex]

The least common multiplier (LCM) of the denominator is (a - 6)(a + 6).

Adjust the fractions based on the LCM:

[tex]\implies \dfrac{a(a+6)}{(a-6)(a+6)}-\dfrac{3(a-6)}{(a-6)(a+6)}-\dfrac{a^2}{(a-6)(a+6)}[/tex]

Simplify:

[tex]\implies \dfrac{a^2+6a}{(a-6)(a+6)}-\dfrac{3a-18}{(a-6)(a+6)}-\dfrac{a^2}{(a-6)(a+6)}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}-\dfrac{b}{c}-\dfrac{d}{c}=\dfrac{a-b-d}{c}:[/tex]

[tex]\implies \dfrac{a^2+6a-(3a-18)-a^2}{(a-6)(a+6)}[/tex]

Simplify:

[tex]\implies \dfrac{3a+18}{(a-6)(a+6)}[/tex]

Factor out 3 from the numerator:

[tex]\implies \dfrac{3(a+6)}{(a-6)(a+6)}[/tex]

Cancel the common factor (a + 6):

[tex]\implies \dfrac{3}{a-6}[/tex]

Therefore:

[tex]\dfrac{a}{a-6}-\dfrac{3}{a+6}+\dfrac{a^2}{36-a^2}=\dfrac{3}{a-6}\quad \textsf{if}\;\;a \neq -6,a \neq 6[/tex]

[tex](\stackrel{x_1}{-7}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{6}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{6}-\stackrel{y1}{(-8)}}}{\underset{\textit{\large run}} {\underset{x_2}{-5}-\underset{x_1}{(-7)}}} \implies \cfrac{6 +8}{-5 +7} \implies \cfrac{ 14 }{ 2 } \implies \text{\LARGE 7}[/tex]

Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$ 41 thousand less than twice that of an individual. the average yearly salary of an individual with each of these final degrees is: $50,000 (Bachelor's degree) and $59,000 (Master's degree )

Let x represent the average yearly salary of an individual with the bachelor's degree

Let (2x-41000) represent the   average yearly salary of an individual with the master's degree

Let the sum of these salaries = 109000

So, x + (2x-41000) = 109000

Simplify and solve:

3x = 109000 + 41,000

3x = 150,000

Divide both side by 3x

x= 150,000/3

x = 50,000 (Bachelor's degree)

So,

(2x-41000)

= 2(50,000) - 41,000

=100,000 - 41,000

= $59,000 (Master's degree )

Therefore the average yearly salary is $50,000 (Bachelor's degree) and $59,000 (Master's degree )

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The equation of a line can be written in both slope-intercept form and standard form.

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Therefore , the solution to the given problem of unitary method comes out to be 34 marbles are therefore on the sixth line.

The term unitary refers to a single or unique or variable unit. As a result, the purpose of this strategy is to construct values with regard to a single unit. For instance, if a car drives 44 kilometres on two litres of fuel, the unitary technique can be used to determine how many kilometers it will travel on one.

Here,

Every subsequent line, beginning with one, contains two less characters than the one before it.

This signifies that your starting line contains three marbles. The 3 marbles are multiplied by 2 to get 3x2=6, and the result is subtracted to get 6-2=4.

This implies that you will receive 4 marbles for the following line.

As a result, in order to determine the sixth line, you must first determine the fifth line by counting the number of marbles on the fourth line because your diagram does not include a fifth line.

(4) = ten marbles.

10×2=20

20-2=18

(5) line = (18)

18×2=36

36-2=34

Therefore , the solution to the given problem of unitary method comes out to be 34 marbles are therefore on the sixth line.

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Answer:

The matrix does not have an inverse (D)

Step-by-step explanation:

The matrix is singular, therefore doesn't have an inverse

A function A = 3000 e^(-0. 05t) is an exponential decay function.

And the landfill after 9 years =  1912.8 acres

From given information, the number of acres in a landfill is given by the function A = 3000 e^(-0. 05t), where t is measured in years.

To find:  the landfill after 9 years

Substitute t = 9 years in above function.

A = 3000 × e^(-0. 05t)

A = 3000 × e^(-0.05 × 9)

A = 3000 × e^(-0.45)

A = 3000 × 0.6376

A = 1912.8                 .............(1)

Substitute t = 9 years in given function.

A = 3000 e^(-0. 05t)

A = 3000 × e^(-0.05 × 0)

A = 3000 × e^(0)

A = 3000 × 1

A = 3000

This means, initially a landfill was 3000 acres.

From (1) we can observe that after 9 years, the landfill is  1912.8    acres.

A landfill has been reduced.

So, a function is exponential decay function.

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So, on  solving the provided question, we can say that  to form a inequality - x * y > 8

An inequality in mathematics is a relationship between two expressions or values that is not equal. Thus, imbalance leads to inequality. An inequality creates the link between two values that are not equal in mathematics. Egality is distinct from inequality. When two values are not equal, most commonly use the not equal sign (). Different inequalities are used to contrast values, no matter how little or large. Many simple inequalities may be resolved by modifying the two sides until the variables are all that remain. But a number of things contribute to inequality: Negative values on both sides are divided or added. Trade off the left and right.

here to form a inequality-

let x = goals by each player

y = no. of players

x * y > 8

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The sum of two functions, f and g: (f + g)(x) = f (x) + g(x) and The difference of two functions f and g: (f - g)(x) = f (x) - g(x).

What is operation function ?

The operations function refers to all the activities that focus on producing goods and services for the customers. It includes the production process of converting raw material into final products. It helps to reduce costs and make process improvements.

Have given ,

Two function f and g then ,

There is one more way that functions can be combined. The fifth operation is called the composition of two functions. The composition of the functions f (x) and g(x) is symbolized this way: (fog)(x). It is equivalent to f (g(x)). It is read "f of g of x." The concept is simple. First, the value of g at x is taken, and then the value of f at that value is taken. Let's try an example to clear things up.

So , The sum of two functions, f and g: (f + g)(x) = f (x) + g(x) and The difference of two functions f and g: (f - g)(x) = f (x) - g(x).

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The given equation does not give same solution set.The first equation gives negative number and second equation gives positive number as a solution.

The relationship between two values that are not equal is defined by inequalities. Inequality means not equal. Generally,Compare the two values whether it is less than or greater than,then different inequalities are used.

Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own. But these things will change direction of the inequality: Multiplying or dividing both sides by a negative number.

Now we solve

5-x>8                            x-5<8

5-5-x>8-5                      x-5+5<8+5

-x>3                                  x<13

Hence given equation does not give same solutions.

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On solving the provided question, we can say that - The provided arithmetic sequence's 66th term is -950.

An arithmetic sequence is a set of integers that are ordered and have a common difference between each following word.An ordered group of integers with a shared difference between each word is known as an arithmetic sequence.

The given arithmetic sequence is,

25, 10, -5, .....

The sequence's initial word, a, equals 25, while the common difference, d, equals -15.

Use the formula nth term of arithmetic series = a+ (n-1)d to determine the 66th term of the sequence.

66th term =

[tex]25 + (66-1)(-15)\\ = 25 + 65× (-15)\\ = 25 - 975\\ = -950\\[/tex]

The 66th term of the arithmetic sequence is -950.

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To find the zeros of a polynomial algebraically, you can use the following steps:

Write the polynomial in standard form, with the terms arranged in descending order of the degree of the term. For example, if the polynomial is 3x^2 - 2x + 5, it is already in standard form.

Set the polynomial equal to zero. For example, if the polynomial is 3x^2 - 2x + 5, you would set the equation equal to zero like this:

3x^2 - 2x + 5 = 0

Use the quadratic formula to find the solutions (i.e., the zeros) of the equation if the polynomial is a quadratic (degree 2). The quadratic formula is:

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

where a, b, and c are the coefficients of the polynomial, and sqrt represents the square root.

For example, if the polynomial is 3x^2 - 2x + 5, the solutions would be:

x = (-(-2) +/- sqrt((-2)^2 - 4 * 3 * 5)) / (2 * 3)

x = (2 +/- sqrt(4 - 60)) / 6

x = (2 +/- sqrt(-56)) / 6

Since the square root of a negative number is not a real number, there are no real solutions (zeros) for this polynomial.

Use the Rational Root Theorem to find the solutions of the equation if the polynomial is not a quadratic. The Rational Root Theorem states that if a polynomial of degree n has a rational root p/q (where p and q are integers and q is not equal to zero), then p must be a divisor of the constant term and q must be a divisor of the coefficient of the term of highest degree.

For example, if the polynomial is x^3 - 2x^2 + x - 6, the constant term is -6 and the coefficient of the term of highest degree is 1. The divisors of -6 are -6, -3, -2, -1, 1, 2, 3, and 6. The divisors of 1 are 1 and -1. Therefore, the possible rational roots of this polynomial are -6, -3, -2, -1, 1, 2, 3, and 6.

To find the actual roots, you can try each of these numbers as a root and see if it works. For example, if you try -6 as a root, you would get:

(-6)^3 - 2(-6)^2 + (-6) - 6 = 0

(-216) - (-72) + (-6) - 6 = 0

-144 - 6 - 6 = 0

-156 = 0

This equation is not true, so -6 is not a root of the polynomial. You can repeat this process for each of the other possible rational roots until you find all of the roots of the polynomial.

Substitution method is a method used to solve equations. It involves replacing a variable with its given value, which helps to isolate it and solve for the unknown. For example, if we have the equation 2x+5=17, we can solve for x by substituting 17 for 2x+5 and then subtracting 5 from both sides to obtain x=12.

The substitution method is a technique used to solve systems of equations. An example of the substitution method would be solving the system of equations:

x + 2y = 5

3x + 6y = 15

First, solve the first equation for x:

x = 5 - 2y

Substitute the expression for x into the second equation:

3(5 - 2y) + 6y = 15

Simplify:

15 - 6y + 6y = 15

Solve for y:

15 = 15

Now substitute the value of y back into the expression for x:

x = 5 - 2(3)

Solve for x:

x = -1

Therefore, the solution to the system of equations is:

x = -1, y = 3

Substitute x in equation 1 into equation 2, solve, then substitute y back into equation 1.

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The area of the garden is 625 square meters.

We know that the perimeter of a square is equal to the sum of all four sides. Since the gardener is using 100 meters of fencing to enclose the garden, and since the garden is a square, we can set the perimeter equal to 100 meters:

P = 4s

100 = 4s

Where P is the perimeter, and s is the length of one side of the square.

We can solve for s by dividing both sides of the equation by 4:

s = 100/4 = 25

Since the area of a square is equal to one side of the square squared, we can find the area of the garden by squaring the value of s:

A = s^2

A = 25^2

A = 625

So the area of the garden is 625 square meters.

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