which problom can we solve with 60 devided by 6

Answer:

3/8

Step-by-step explanation:

3/4 x 1/2 = 3/8

3/8 x 1/1 = 3/8

Hope that helps!

Answer: y= 4x + 4

Step-by-step explanation: The equation is in slope intercept form, y=mx+b. The slope is the same since it is parallel to the equation, and since b is the x interecept, b is 4.

[tex] \mathfrak{V=a³}[/tex]

Where,

In our case,

[tex] \sf \: V= {5}^{3} [/tex]

[tex] \sf \: V= {125} \: ft^{3} [/tex]

➪ Thus, The volume of the cube is 125 feet³...~

We know that:

[tex]Volume = L^{3} = (L)^{3}[/tex]

Substituting the side length into the equation:

[tex]Volume = (L)^{3}[/tex]

[tex]Volume = (5)^{3}[/tex]

Evaluating the volume:

[tex]Volume = (5)(5)(5)[/tex]

[tex]Volume = 125 \space\ ft^{3}[/tex]

Answer:

May makes $23.25, Inez makes $2325, and Jo makes $232.50.

Step-by-step explanation:

Inez makes 100x 23.25= 2325

jo makes 2325/10=232.5

Answer:

option B shows the correct solution.

Find y-intercept:

3y - 4x = -3

3y - 4(0) = -3

3y = -3

y = -1

Find x-intercept:

3y - 4x = -3

3(0) - 4x = -3

-4x = -3

x = 3/4

Check option B

So

Hence verified

Option B is correct

Answer:

5.51181 Inches

Step-by-step explanation:

No table is provided, to turn cm to inches divide the cm by 2.54, if you need help with division contact me, thank you.

Answer:

13C2 = 78

Step-by-step explanation:

Formula

[tex]nCr=\dfrac{n!}{r!(n-r)!}[/tex]

The ! symbol in math is called "factorial".  When placed after a number, it means to multiply the number by every natural number below it.

For 13C2:

Substitute these values into the formula:

[tex]13C2=\dfrac{13!}{2!(13-2)!}[/tex]

        [tex]=\dfrac{13!}{2! \ 11!}[/tex]

        [tex]=\dfrac{13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{2 \times 1 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}[/tex]

        [tex]=\dfrac{13 \times 12}{2 \times 1}[/tex]

        [tex]=\dfrac{156}{2}[/tex]

        [tex]=78[/tex]

Step-by-step explanation:

MR+CR=CM by the segment addition postulate.

(9x+8)+17=4x+1

9x+25=4x+1

5x+25=1

5x=-24

x=-24/5

Answer:

93.3 square feet

Step-by-step explanation:

12.8 + 5.9 = 18.7

18.7 x 10 = 187

187 / 2 = 93.3

Answer:

2

Step-by-step explanation:

substitute 2 in for x in the g(x) to get 2(2)-2= 2

The book value of a $3,500 computer after 2 years is $2380

How to calculate book value

The book value is gotten by subtracting the product of the initial value and MACRS rate from the initial value.

The book value after 2 years = 3500 - (32% of 3500)

The book value after 2 years = 3500 - (0.32 * 3500) = 2380

The book value of a $3,500 computer after 2 years is $2380

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Answer:

x + 12 = 30

Step-by-step explanation:

For the answer subtract 12 from 30 to get 18 which would be Manoela's age

Answer:

6

Step-by-step explanation:

5y - 12 = 18

5y = 30

y = 6

Answer:

I would say five, not positive though. if it isn't five then i'd say 12!

Step-by-step explanation:

Answer:

answer 1 goes in 1st box

answer 2 goes in box 3

answer 3 goes in box 2

answer 5 goes in the last box

answer 4 goes in 2nd to last box

Step-by-step explanation:

Answer:

D is correct answer

Step-by-step explanation:

Answer:

it is d i know im late but may i plz get brainliest

Step-by-step explanation:

Answer:

Explanation:

A ratio is the fractional representation of two different numbers, defined by the order in which we want to describe them We want a ratio of (Occupied)/(Empty) seats, so we put the occupied seat value in the numerator and the empty seat value in the denominator.

Ratio = 17/11

The decimal form can be obtained by doing the division: 1.545 occupied seats per empty seat.

Answer:

21.68 feet

Step-by-step explanation:

5.42 feet in one minute

so how many in 4 minutes

just multiple the rate (5.42 feet per minute) by 4 to get 21.68 feet

Answer:

$37.76

Step-by-step explanation:

.18*32 = 5.67

5.67+32 = 37.76  

Answer:Some equations may not have solutions and some may have one or more than one is because of the variables or how they are written

Step-by-step explanation:not 100% sure this is the correct answer,I tried my best.

A system of equations consists on a group of equations that we must solve at the same time.

From this, the solutions of a system of equations appear as the intersections between the graphs of the equations that conform the system.

So for example, if a system has two parallel lines (two lines that never intersect) that system will have no solution.

If a system has two different and not parallel lines, these lines will intersect at some point, so this system will have one solution.

And finally, if the system has twice the same line, the graphs of the lines will intersect in infinite points, thus, this system has infinite solutions.

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Answer:

1.42857

Step-by-step explanation:

[tex]\mathrm{Write\:the\:problem\:in\:long\:division\:format}[/tex]

[tex]28\overline{|\smallspace40}\:\:[/tex]

[tex]\mathrm{Divide\;40\;by\;28\;to\;get\;1}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\:\:\:\:\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;120\;by\;28\;to\;get\;4}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\emptyspace4\:\:\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0\cdot \:0}\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\underline{\emptyspace1\emptyspace1\emptyspace2}\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\emptyspace8\emptyspace0\:\:\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;80\;by\;28\;to\;get\;2}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\emptyspace4\emptyspace2\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0\cdot \:0\cdot \:0}\:\:\:\:\:\\ \underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \underline{\emptyspace1\emptyspace1\emptyspace2}\:\:\:\:\:\:\:\:\:\:\\ \;\;\emptyspace8\emptyspace0\:\:\:\:\:\:\:\:\\ \:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\\ \emptyspace2\emptyspace4\emptyspace0\:\:\:\:\:\:\end{matrix}[/tex]

[tex]\mathrm{Divide\;240\;by\;28\;to\;get\;8}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\emptyspace4\emptyspace28\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0\cdot \:0\cdot \:0}\:\:\:\:\:\\ \underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \underline{\emptyspace1\emptyspace1\emptyspace2}\:\:\:\:\:\:\:\:\:\:\\ \;\;\emptyspace8\emptyspace0\:\:\:\:\:\:\:\:\\ \:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\\ \emptyspace2\emptyspace4\emptyspace0\:\:\:\:\:\:\end{matrix}[/tex]

       [tex]\underline{\emptyspace2\emptyspace2\emptyspace4}\\160[/tex]

[tex]\mathrm{Divide\;160\;by\;28\;to\;get\;5}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\emptyspace4\emptyspace285\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0\cdot \:0\cdot \:0}\:\:\:\:\:\\ \underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \underline{\emptyspace1\emptyspace1\emptyspace2}\:\:\:\:\:\:\:\:\:\:\\ \;\;\emptyspace8\emptyspace0\:\:\:\:\:\:\:\:\\ \:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\\ \emptyspace2\emptyspace4\emptyspace0\:\:\:\:\:\:\end{matrix}[/tex]

       [tex]\underline{\emptyspace2\emptyspace2\emptyspace4}\\160[/tex]

       [tex]\underline{\emptyspace1\emptyspace4\emptyspace0}\\200[/tex]

[tex]\mathrm{Divide\;200\;by\;28\;to\;get\;7}[/tex]

[tex]\begin{matrix}\:\:\:\:\:\:\:\:\emptyspace1.\emptyspace4\emptyspace2857\:\:\:\:\:\:\:\\ 28\overline{|\smallspace40.0\cdot \:0\cdot \:0}\:\:\:\:\:\\ \underline{\emptyspace2\emptyspace8}\:\:\:\:\:\:\:\:\:\:\:\:\\ \emptyspace1\emptyspace2\emptyspace0\:\:\:\:\:\:\:\:\:\:\\ \underline{\emptyspace1\emptyspace1\emptyspace2}\:\:\:\:\:\:\:\:\:\:\\ \;\;\emptyspace8\emptyspace0\:\:\:\:\:\:\:\:\\ \:\underline{\emptyspace5\emptyspace6}\:\:\:\:\:\:\:\:\\ \emptyspace2\emptyspace4\emptyspace0\:\:\:\:\:\:\end{matrix}[/tex]

      [tex]\underline{\emptyspace2\emptyspace2\emptyspace4}\\160[/tex]

     [tex]\underline{\emptyspace1\emptyspace4\emptyspace0}\\200[/tex]

     [tex]\underline{\emptyspace1\emptyspace9\emptyspace6}\\4[/tex]

[tex]\mathrm{Stopping\:at\:5\:decimal\:places}[/tex]

[tex]\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{40}{28}\:\mathrm{is}\:1.42857[/tex]

~[RevyBreeze]~

Tell me if you don't understand!

The division of the expression when 40 divided by 28 is [tex]\dfrac{10}{7}[/tex] or  1.42857143.

A number that divides another number without leaving any remainder and the quotient is a whole number is called a factor.

The factors of 12 are = 1,2,3,4,6 and 12.

Here, when these factor will divide 12, there will no remainder, i.e. they will completely divide 12.

The division of the expression 40 divided by 28 is calculated as:

The factors of 40 are : 1,2,4,5,8,10,20 and 40

The factors of 28 are: 1,2,4,7,14 and 28.

This expression can be written as:

[tex]\dfrac{40}{28}=\dfrac{1\times2\times4\times5\times8\times10\times20\times40}{ 1\times 2\times 4\times 7\times 14\times 28}[/tex]

The numbers cancel out using the rule of divisibility, and the remaining  fraction will be [tex]\dfrac{10}{7}[/tex] and in decimal form will be 1.42857143.

Thus, when 40  is divided by 28, the result is 1.42857143 or [tex]\dfrac{10}{7}[/tex] in fraction form.

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Answer:

C) 16 cubic cm

Step-by-step explanation:

1 cubic cm / cube

4 x 2 x 2 on each side = 16 cubes

16 cubic cm

Answer:

[tex]3\sqrt{6}+3\sqrt{2}i[/tex] and [tex]-3\sqrt{6}-3\sqrt{2}i[/tex]

Step-by-step explanation:

For a complex number [tex]z=a+bi[/tex] in rectangular form, polar form is [tex]z=r[cos(\theta)+isin(\theta)][/tex] where [tex]r=\sqrt{a^2+b^2}[/tex] and [tex]\theta=tan^{-1}(\frac{b}{a})[/tex]:

[tex]r=\sqrt{a^2+b^2}\\\\r=\sqrt{(36)^2+(36\sqrt{3})^2}\\\\r=\sqrt{1296+3888}\\\\r=\sqrt{5184}\\\\r=72[/tex]

[tex]\theta=tan^{-1}(\frac{b}{a})\\ \\\theta=tan^{-1}(\frac{36\sqrt{3}}{36})\\ \\\theta=tan^{-1}(\sqrt{3})\\\\\theta=\frac{\pi}{3}[/tex]

Thus, our complex number in polar form is [tex]z=72[cos(\frac{\pi}{3})+isin(\frac{\pi}{3})][/tex]. This will help us determine the square roots of the complex number using the formula [tex]\sqrt[n]{r}\biggr[cis\bigr({\frac{\theta+2\pi k}{n})\biggr][/tex] for [tex]k=0,1,2,\: ... \:,n-1[/tex]. Note that [tex]cis(\theta)=cos(\theta)+isin(\theta)[/tex]:

1st square root for k = 2-1 = 1

[tex]\sqrt[n]{r}\biggr[cis\bigr({\frac{\theta+2\pi k}{n})\biggr][/tex]

[tex]\sqrt[2]{72}\biggr[cis\bigr({\frac{\frac{\pi}{3}+2\pi(1)}{2})\biggr][/tex]

[tex]6\sqrt{2}\biggr[cis\bigr({\frac{\frac{\pi}{3}+2\pi}{2})\biggr][/tex]

[tex]6\sqrt{2}\biggr[cis\bigr(\frac{\pi}{6}+\pi)\biggr][/tex]

[tex]6\sqrt{2}\biggr[cis\bigr(\frac{7\pi}{6})\biggr][/tex]

[tex]6\sqrt{2}\biggr[cos(\frac{7\pi}{6})+isin(\frac{7\pi}{6})\biggr]\\ \\6\sqrt{2}(-\frac{\sqrt{3}}{2}-\frac{1}{2}i)\\\\-3\sqrt{6}-3\sqrt{2}i[/tex]

2nd square root for k = 1-1 = 0

[tex]\sqrt[6]{72}\biggr[cis\bigr({\frac{\frac{\pi}{3}+2\pi(0)}{2}\bigr)\biggr][/tex]

[tex]6\sqrt{2}\biggr[cis(\frac{\pi}{6} )\biggr][/tex]

[tex]6\sqrt{2}[cos(\frac{\pi}{6})+isin(\frac{\pi}{6})]\\ \\6\sqrt{2}(\frac{\sqrt{3}}{2}+\frac{1}{2})\\\\3\sqrt{6}+3\sqrt{2}i[/tex]

Therefore, the square roots of [tex]36+36\sqrt{3}i[/tex] are [tex]3\sqrt{6}+3\sqrt{2}i[/tex] and [tex]-3\sqrt{6}-3\sqrt{2}i[/tex].

Step-by-step explanation:

Frequency is b/2 pi.

Here b is 124 pi. so the frequency is

[tex] \frac{124\pi}{2\pi} = 52[/tex]

The frequency is 52

Answer: 62

Step-by-step explanation:

I got it correct with this answer

Answer:

its answer is 17 first find p and q value then use x2-x1 y2-y1 formula

Answer:

8 + x

Step-by-step explanation:

She started with 8 entries.

She added x entries.

The total now is the sum of 8 and x.

Answer: 8 + x

Answer: 6

Step-by-step explanation:

-4 -3 -2 -1 0 1 2

1   2 3 4 5 6 7

Answer:

Well "0.0000000025 x 6" is "1.5e-8" but

Step-by-step explanation:

Sadly I can't explain anything, It's just not one of my skills :(

The 6 times the width of DNA in Scientific notation will be 1.5 × 10⁻⁸.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

PEMDAS rule means the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

The width of DNA is approximately 0.0000000025 meters wide.

The 6 times the width of DNA in Scientific notation will be given as,

⇒ 6 × 0.0000000025

⇒ 6 × 2.5 × 10⁻⁹

⇒ 1.5 × 10⁻⁸

The 6 times the width of DNA in Scientific notation will be 1.5 × 10⁻⁸.

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14 + 4 +12 = 30 which means that the answer is 30 so here you go