Which of the following is NOT true of a perpendicular bisect or?

Which Of The Following Is NOT True Of A Perpendicular Bisect Or?

Answers

Answer 1

Answer:

The forth option

It forms a right angle with the segment.


Related Questions

what is 2x + 4 = x + 40

Answers

[tex]{\boxed{\boxed { ⎆ Answer :- }}} \ [/tex]

[tex]2x + 4 = x + 40 \\ 2x - x = 40 - 4 \\ x = 36[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

X=36

Explanation: cause I said what I said

The maintenance department at the main campus of a large state university receives daily requests to replace fluorecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 54 and a standard deviation of 3. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 54 and 63?

Answers

Answer:

The approximate percentage of lightbulb replacement requests numbering between 54 and 63 is of 49.85%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 54, standard deviation = 3.

What is the approximate percentage of lightbulb replacement requests numbering between 54 and 63?

63 = 54 + 3*3

So between the mean and 3 standard deviations above the mean.

The normal distribution is symmetric, which means that 50% of the values are below the mean and 50% are above.

Of those 50% above, 99.7% are below 63. So

0.5*0.997 = 0.4985

0.4985*100% = 49.85%

The approximate percentage of lightbulb replacement requests numbering between 54 and 63 is of 49.85%.

Mark purchashed 3 giant jawbreakers at 75cents each.he also bought 1/4 pound of hot tamales.which sell for $2.76 a pound.he gave the clerk a $5 bill.how much change did mark recieve? Whith his change,mark decided to buy 1/2 pound of m&ms at $3.24 a pound.how much money does mark have left?

Answers

Answer: $0.44

Step-by-step explanation: a) (3 * 0.75) + ((1/4)*2.76) = 2.25 + 0.69 = 2.94

Pays with $5 - $2.94 = $2.06 Change

((1/2) * 3.24) = $1.62

Money left = 2.06 - 1.62 => $0.44

You are a 60 year old male. You want $1,000,000.00 in term life insurance. It will cost you $13.22 per $1,000.
Calculate the annual premium.
A $11,220.00
B $12,220.00
C $13,220.00
D $14,220.00

Answers

Answer:

C $13,220

Step-by-step explanation:

if cars A and B are traveling at the speed of 55km/hr and 75km/hr respectively. What is their average speed?​

Answers

65 Is the answer .....

But

I

Really


Don’t


Know

Answer:

130 km/hr

Step-by-step explanation:

Average Speed = Total Distance / Total Time.

Let us just make up 2 distances from a time

A: 55 km/hour for 2 hours = 110 km

B: 75 km/hour for 2 hours = 150 km

Total Distance = 260 km

Total Time = 2 hours.

Average Speed = 260 / 2 = 130 km/hr

Now let's try it again. If we get a different answer, then the problem is unanswerable.

A: 55 km/hr  for 3 hours = 165 km

B: 75 km/hr for 3 hours = 225 km

Total distance  = 390 km

Total time = 3 hours

Average speed = 390 / 3 = 130 which is the same answer we got before.

Help ASAP!! A triangle has side lengths of 11in, 15in, and 20in. Find the angle measures of the triangle. Round decimal answers to the nearest tenth. Someone help pls.

Answers

Answer:

<A = 47.7°

<B = 99.4°

<C = 32.9

Step-by-step explanation:

When given the measurements of all three sides, you can calculate the angles using the Cosine Law.

c² = a² + b² - 2ab cos C

(based on Pythagorean Theorem)

If we say: a = 15

b = 20

c = 11

11² = 15² + 20² - 2(15)(20) cos C

121 = 625 - 2(15)(20) cos C

121 = 625 - 600 cos C

⁻504 = ⁻600 cos C

cos⁻¹ (504 ÷ 600) = C

< C = 32.9°

a² = b² + c² - 2bc cos A

15² = 20² + 11² - 2(20)(11) cos A

225 = 521 - 2(20)(11) cos A

225 = 521 - 440 cos A

⁻296 = ⁻440 cos A

cos⁻¹ (296 ÷ 440) = A

<A = 47.7°

Then, since we know the sum of all three angles of a triangle equals 180°:

180° - 32.9° - 47.7° = 99.4°

<B = 99.4°

Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i
series across a 220 V line. What power is consumed in each lamp?

Answers

Answer:

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

Step-by-step explanation:

Given:

First lamp rating

Power (P) = 100W

Voltage (V) = 110V

Second lamp rating

Power (P) = 100W

Voltage (V) = 220V

Source

Voltage = 220V

i. Get the resistance of each lamp.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = [tex]\frac{V^2}{R}[/tex]

Make R subject of the formula

⇒ R = [tex]\frac{V^2}{P}[/tex]             ------------------(i)

For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)

R₁ = [tex]\frac{110^2}{100}[/tex]

R₁ = 121Ω

For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)

R₂ = [tex]\frac{220^2}{100}[/tex]

R₂ = 484Ω

ii. Get the equivalent resistance of the resistances of the lamps.

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. Get the current flowing through each of the lamps.

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = [tex]\frac{V}{R}[/tex]

I = [tex]\frac{220}{605}[/tex]

I = 0.36A

iv. Get the power consumed by each lamp.

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

For the first lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

For the second lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

please help me solve this math

Answers

Answer:

d

Step-by-step explanation:

In the diagram below, BC is an altitude of ABD. To the nearest whole unit, what is the length of CD?

Answers

Answer:

B. 23

Step-by-step explanation:

BC = 32

CA = 44

To find the length of CD, apply the altitude of right triangle formula, (altitude-on-hypotenuse theorem) which is given as:

h = √(xy)

Where,

h = CB = 32

x = CA = 44

y = CD = ?

Plug in the values

32 = √(44 × CD)

Square both sides

32² = 44 × CD

1,024 = 44 × CD

Divide both sides by 44

1,024/44 = CD

CD = 23 units (nearest whole unit)

Which expression is equivalent to…

Answers

Answer:

D

Step-by-step explanation:

14. The Elizabeth Tower is 320 feet tall. At what time or times during your ride on the London Eye are you at the same height as the top of the tower? Show your work. (4 points: 2 points for finding the correct time(s), 2 points for work shown)

Answers

Answer:

Ok so on a clock there is 12 numbers where 12 is on top so at 12 am and 12 pm noon and midnight you will be at the top of the clock

Hope This Helps!!!

During the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.

To determine the time(s) during the ride on the London Eye when you are at the same height as the top of the Elizabeth Tower (commonly known as Big Ben), we need to consider the height of the London Eye and its rotational motion.

Given that the Elizabeth Tower is 320 feet tall, we need to find the position of the London Eye when its height aligns with the top of the tower.

The London Eye has a height of 443 feet, and it completes one full rotation in approximately 30 minutes (or 1800 seconds). This means that it moves at a constant angular velocity of 360 degrees per 1800 seconds.

To find the time(s) when the heights align, we can set up a proportion:

(Height of the Elizabeth Tower) / (Height of the London Eye) = (Angle covered by the London Eye) / 360 degrees

Substituting the given values:

320 / 443 = (Time to align) / 1800

Simplifying the equation:

(Time to align) = (320 / 443) * 1800

Calculating the value:

(Time to align) ≈ 1303.16 seconds

Converting the time to minutes and seconds:

(Time to align) ≈ 21 minutes and 43.16 seconds

Therefore, during the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.

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1. Find the exact value of sin( a−B), given that sin a=−4/5 and cos B=12/13, with a in quadrant III and B in quadrant IV.

2. Find all real numbers in the interval [0,2pi) that satisfy the equation.

3sec^2 x tan x =4tan x

3. Simplify the following trigonometric expressions, using identities as needed:

sin(x)/1−cos(x) + 1−cos(x)/sin(x)

Answers

(1) Recall that

sin(x - y) = sin(x) cos(y) - cos(x) sin(y)

sin²(x) + cos²(x) = 1

Given that α lies in the third quadrant, and β lies in the fourth quadrant, we expect to have

• sin(α) < 0 and cos(α) < 0

• sin(β) < 0 and cos(β) > 0

Solve for cos(α) and sin(β) :

cos(α) = -√(1 - sin²(α)) = -3/5

sin(β) = -√(1 - cos²(β)) = -5/13

Then

sin(α - β) = sin(α) cos(β) - cos(α) sin(β) =  (-4/5) (12/13) - (-3/5) (-5/13)

==>   sin(α - β) = -63/65

(2) In the second identity listed above, multiplying through both sides by 1/cos²(x) gives another identity,

sin²(x)/cos²(x) + cos²(x)/cos²(x) = 1/cos²(x)

==>   tan²(x) + 1 = sec²(x)

Rewrite the equation as

3 sec²(x) tan(x) = 4 tan(x)

3 (tan²(x) + 1) tan(x) = 4 tan(x)

3 tan³(x) + 3 tan(x) = 4 tan(x)

3 tan³(x) - tan(x) = 0

tan(x) (3 tan²(x) - 1) = 0

Solve for x :

tan(x) = 0   or   3 tan²(x) - 1 = 0

tan(x) = 0   or   tan²(x) = 1/3

tan(x) = 0   or   tan(x) = ±√(1/3)

x = arctan(0) +   or   x = arctan(1/√3) +   or   x = arctan(-1/√3) +

x =   or   x = π/6 +   or   x = -π/6 +

where n is any integer. In the interval [0, 2π), we get the solutions

x = 0, π/6, 5π/6, π, 7π/6, 11π/6

(3) You only need to rewrite the first term:

[tex]\dfrac{\sin(x)}{1-\cos(x)} \times \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin(x)(1+\cos(x))}{1-\cos^2(x)} = \dfrac{\sin(x)(1+\cos(x)}{\sin^2(x)} = \dfrac{1+\cos(x)}{\sin(x)}[/tex]

Then

[tex]\dfrac{\sin(x)}{1-\cos(x)}+\dfrac{1-\cos(x)}{\sin(x)} = \dfrac{1+\cos(x)+1-\cos(x)}{\sin(x)}=\dfrac2{\sin(x)}[/tex]

Need help with this math

Answers

Answer:

Step-by-step explanation:

office at point A =(-7,-5)   ........................in the form (x1,y1)

supermarket and point B = (-2,-6)........in the form (x2,y2)

home Home at point C = (4,-6).............in the from (x3,y3)

find the total distance from A to B + B to C

ABdist= sqrt[ (x2-x1)^2 + (y2-y1)^2 ]

ABdist = sqrt[ (-2-(-7))^2 + (-6-(-5))^2 ]

ABdist = sqrt[ (-2 + 7)^2 + (-6 +5)^2]

ABdist = sqrt[ [tex]5^{2}[/tex] + [tex](-1)^{2}[/tex]]

ABdist = sqrt[ 25 + 1 }

ABdist = [tex]\sqrt{26}[/tex]

BCdist= sqrt[ (x3-x2)^2 + (y3-y2)^2 ]

BCdist = sqrt[ (4-(-2))^2 + (-6-(-6))^2]

BCdist = sqrt[ 4+2)^2  + -6+6)^2 ]

BCdist = sqrt [ [tex]6^{2}[/tex] + [tex]0^{2}[/tex] ]

BCdist = [tex]\sqrt{36}[/tex]

BCdist = 6

total distance = [tex]\sqrt{26}[/tex] +6

The first answer looks good

Please tell me the answer I have no idea how to do this

Answers

Answer:

60 degrees

Step-by-step explanation:

So we see there's a 90 degree angle and a 150 degree larger angle including it.

So to find out the part that the 150 degree large angle that's not a part of the 90 angle we would do: 150 - 90, and we get 60.

So the bottom right angle is 60 degrees.

Now since we have a straight line from the left to right horizontally, we know that one side has to equal 180 degrees. On the side which the x is on, we already have 2 angles: 90 and 30. 90 + 30 = 120.

Since a straight line equals 180, x + 120 has to equal 180.

So now we do simple algebra.

x + 120 = 180

x = 180 - 120

x = 60

So x is equal to 60 degrees.

PLEASE HELPPP ASAP!!! I tried all sorts of equations but no correct answer! Not sure how to approach this problem.

Answers

Answer:

[tex]44[/tex]

Step-by-step explanation:

The dimensions of the garden is 12 by 8. If we have a walkway that surrounds the garden, the dimensions of the walkway is 2. Since it surrounds the rectangle all sides add 2 to each of the dimensions so now the dimensions of the garden and walkway is 14×10.

The area of the garden is 96 square ft.

The area of the garden and walkway is 140 so let subtract the area of the garden from the total area of both the garden and walkway.

[tex]140 - 96 = 44[/tex]

The area is 44.

Answer:

120 square feet

Step-by-step explanation:

(8+2*2)

(18+2*2) - 8*18 = 120 square feet.

Can someone help me with this problem?

Answers

no i don't even think albert could

Find the first derivative for y = f(x). fox ) 3x² -5x-1 at a Pocat where a = 4​

Answers

Answer:

Step-by-step explanation:

f(x) = 3x² -5x - 1

f'(x) =2*3x - 5*1 +0

     = 6x - 5

f'(4) = 6*4 - 5

      = 24 - 5

      = 19

A ball is thrown vertically upward with an initial velocity of 19 m/s. Its height, h(t)metres after t seconds, is given by the equation h(t) = -3t2 + 20t + 2.0.

The time taken by the ball to reach the maximum height is ________ seconds. Round your answer to the nearest tenth.

Answers

Answer:

Step-by-step explanation:

There are 2 different ways to do this: calculus and by completing the square. In this particular instance, calculus is WAY easier, and since I don't know for what class you are doing this, I'll do both ways. First the calculus way. We know the position equation, and the first derivative of the position is velocity. We also know that when the velocity is equal to 0 is when the object is at its max height. So we'll find the derivative first, then solve it for t:

If [tex]s(t)=-3t^2+20t+2[/tex] then the first derivative is

v(t) = -6t + 20 Solving for t requires that we set the velocity equal to 0 (again, this is where the object is at its max height), so

0 = -6t + 20 and

-20 = -6t so

t = 3.3 seconds. Now that we know that at 3.3 seconds the object is at its highest point, we sub that time into the position function to see where it is at that time:

s(3.3) = [tex]-3(3.3)^2+20(3.3)+2[/tex] and

s(3.3) = 35.3 meters.

Now onto the more difficult way...completing the square. Begin by setting the position function equal to 0 and then move over the constant to get:

[tex]-3t^2+20t=-2[/tex] Since the leading coefficient is not a 1 (it's a 3), we have to factor out the 3, leaving us with:

[tex]-3(t^2-\frac{20}{3}t)=-2[/tex] Now the rule is to take half the linear term, square it, and add it to both sides. Our linear term is [tex]\frac{20}{3}[/tex] and half of that is [tex]\frac{20}{6}[/tex]. Squaring that:

[tex](\frac{20}{6})^2=\frac{400}{36}=\frac{100}{9}[/tex]. We will add that in to both sides. On the left it's easy, but on the right we have to take into account that we still have that -3 sitting out front, refusing to be ignored. So we have to multiply it in when we add it to the right. Doing that gives us:

[tex]-3(t^2-\frac{20}{3}t+\frac{100}{9})=-2-\frac{100}{3}[/tex] We will clean this up a bit now. The reason we do this is because on the left we have created a perfect square binomial which will give us the time we are looking for to answer this question. Simplifying the right and at the same time writing the perfect square binomial  gives us:

[tex]-3(t-\frac{20}{6})^2=-\frac{106}{3}[/tex] Now the last step is to move the constant back over and set the quadratic back equal to y:

[tex]y=-3(t-\frac{20}{6})^2+\frac{106}{3}[/tex].  The vertex of this quadratic is

[tex](\frac{20}{6},\frac{106}{3})[/tex] where

[tex]\frac{20}{6}=3.3[/tex] as the time it takes for the ball to reach its max height of

[tex]\frac{106}{3}=35.3[/tex] meters.

I'd say if you plan on taking calculus cuz you're not there yet, you'll see that many of these types of problems become much simpler when you know it!

I NEED HELP FAST!!!!!!

Answers

Answer:

6.

Step-by-step explanation:

.

Answer:

[tex]C)\:8[/tex]

8 units tiles must be added

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~HOPE IT HELPS~

~HAVE A GREAT DAY!!~

the volume of pyramid a is the volume of pyramid b. if the heigh of pyramid b increases to twice that of pyramid a the new volume of pyramid b the volume of pyramid a

Answers

Answer:

12.259-12.25 890654321

indicate the following pairs of lines are coinciding, parallel ,perpendicular or neither

Answers

1: coinciding
2: neither, they intersect but they are not parallel, perpendicular, or coinciding
3: perpendicular

A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.

Answers

Answer:

[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]

Step-by-step explanation:

Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.

We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.

In other words, given da/dt = 410 and x = 5, find dx/dt.

From the Pythagorean Theorem:

[tex]a^2+4=x^2[/tex]

Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:

[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]

Simplify:

[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]

Find a when x = 5:

[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]

Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:

[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]

The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.

If four pounds of potatoes cost $6.00, how much would 10 pounds of potatoes cost.
SHOW ALL YOUR WORK!!!!!

Answers

Answer:

10 pounds of potatoes would cost $15.

Step-by-step explanation:

Set up proportion.

4/6=10/x

simplify 4/6 into 2/3,

2/3=10/x

cross product,

2*x=3*10

2x=30

x=30/2

x=15

lemme just add some to the great reply above,

[tex]\begin{array}{ccll} lbs&\$\\ \cline{1-2} 4&6\\ 10&x \end{array}\implies \cfrac{4}{10}=\cfrac{6}{x}\implies 4x = 60\implies x = \cfrac{60}{4}\implies x = 15[/tex]

What is the place value of the 4 in 4.09?

Choose 1 answer:


(Choice A)

Tens


(Choice B)

Ones


(Choice C)

Tenths


(Choice D)

Hundredths

Answers

Answer:

B: Ones.

Step-by-step explanation:

Because this number is 4.09, and the decimal is right next to the 4, that means that it is in the ones place. Decimals are always adjacent on the right to the ones place.

An investor puts $1,200 into an account that pays 5.5% interest compounded annually. The total amount A in the account after t years is given by which function below?
A = 1200(1.55) t
A = 1200(1.055) t
A = 1200(1.055) t
A = 1200 + (1.055) t

Answers

Let's see

[tex]\\ \tt\leadsto A=P(1+r/n)^{nt}[/tex]

n=1

[tex]\\ \tt\leadsto A=1200(1+0.055)^t[/tex]

[tex]\\ \tt\leadsto A=1200(1.055)^t[/tex]

Answer:

[tex]\sf A=1200(1.055)^t[/tex]

Step-by-step explanation:

Annual Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+r\right)^{t} $}[/tex]

where:

A = final amountP = principal amountr = interest rate (in decimal form)t = time (in years)

Given:

P = $1,200r = 5.5% = 0.055t = t years

Substitute the given values into the equation:

[tex]\implies \sf A=1200(1+0.055)^t[/tex]

[tex]\implies \sf A=1200(1.055)^t[/tex]

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Solve the two step equations
1. -3x - 4 = 23
2. x/2 - 12 = -4
3. 6a + ( -1) = 10
4. - ( x + 2 ) = 12
5. 7a + 12 = 10
6. -4 ( a + 2 ) = 12

Answers

Hello!

1) -3x - 4 = 23

-3x = 23 + 4

-3x = 27

x = 27 : (-3)

x = -9

2) x/2 - 12 = -4

x - 24 = -8

x = -8 + 24

x = 16

3) 6a + (-1) = 10

6a - 1 = 10

6a = 10 + 1

6a = 11

a = 11 : 6

a = 11/6

4) -(x + 2) = 12

x + 2 = -12

x = -12 - 2

x = -14

5) 7a + 12 = 10

7a = 10 - 12

7a = -2

a = -2 : 7

a = -2/7

6) -4(a + 2) = 12

a + 2 = -3

a = -3 - 2

a = -5

Good luck! :)

What is the value of x?

Answers

Answer:

22

Step-by-step explanation:

3x-14= 4(x-9)

3×-14= 4x-36

4x-36-3x+14=0

×-22÷0

x=22

Domain and function
Function or not a function

Answers

Answer:

Top left: not a function

Top right: not a function

Bottom left: function

Bottom right: not a function

Step-by-step explanation:

A function is a relationship where each x value has it's own y value ( note that domain = x values and range = y values)

For the one on the top left.

S and n have more than one y value.

Because s and n have more than one y value the relation is not a function

For the one of the top right.

There x value "c" has multiple y values therefore the relation is not a function

For the one on the bottom left

Each x value has it's own y value therefore it is a function ( note that the y values can repeat. It's only the x values that can't repeat. )

For the one on the bottom right

The x value "-5" has multiple y values therefore the relation is not a function

The volume of a cube is 2,744 m3. What is the side length of the cube?

Answers

Answer:

The length is 14 and the area is 196 cm².

The side length of the cube is 14 meters.

We have,

Volume of Cube = 2744 m³

To find the side length of a cube when given its volume, you can use the formula:

Side length = ∛(Volume)

So, substitute this value into the formula to calculate the side length:

Side length = ∛(2,744)

= ∛ 14  x 14 x 14

= 14 m

Therefore, the side length of the cube is 14 meters.

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Sarah ordered 39 shirts that cost $8 each. She can sell each shirt for $16.19. She sold 32 shirts to customers. She had to return 7 shirts and pay a $1.4 charge for each returned shirt. Find Sarah's profit.

Answers

her profit is 204 dollars and 68 cents= 204.68

Other Questions
Which of the following supports the theory of continental drift?A. Mountains on different continents match up.B. Earth's crust is all in one piece.C. Earth has hot climates at the equator.D. There is one continent on Earth. 1. Write 3.3.3.3.3 as a power. My tongue, every atom of my blood, formd from this soil, this air, Born here of parents born here from parents the same, and their parents the same, I, now thirty-seven years old in perfect health begin, Hoping to cease not till death. Walt Whitman Life is real! Life is earnest! And the grave is not its goal; Dust thou art, to dust returnest, Was not spoken of the soul. Henry Wadsworth Longfellow Which statements accurately describe the structure of each poem? Check the three boxes that best apply. Whitmans poem has regular rhyme. Longfellows poem has regular rhyme. Whitmans poem has regular meter. Longfellows poem has regular meter. Whitmans poem has mostly regular line lengths. Longfellows poem has mostly regular line lengths. One number is 2/3 of another number. The sum of the two numbers is 40. Findthe two numbers. What type of health screening would this patient most likely receive?Sue is a 45-year-old woman with a family history of breast cancer. Her healthcare professional will most likely recommend that she receive a Find the value of a and b what is the national symbol of India Select the correct answer.In the following passage from Great Astronomers by Robert Stewall Ball, the author states that he will trace the developments in astronomyfrom the time of Ptolemy to the nineteenth century. Based on the content and style of the excerpt, what kind of audience did Ball primarily havein mind when he was writing this book?The history of astronomy thus becomes inseparable from the history of the great men to whose labours its development is due. In theensuing chapters we have endeavoured to sketch the lives and the work of the great philosophers, by whose labours the science ofastronomy has been created. We shall commence with Ptolemy, who, after the foundations of the science had been laid by Hipparchus,gave to astronomy the form in which it was taught throughout the Middle Ages. We shall next see the mighty revolution in our conceptionsof the universe which are associated with the name of Copernicus. We then pass to those periods illumined by the genius of Galileo andNewton, and afterwards we shall trace the careers of other more recent discoverers, by whose Industry and genlus the boundaries ofhuman knowledge have been so greatly extended. Our history will be brought down late enough to include some of the illustriousastronomers who laboured in the generation which has just passed away.OAstudents specializing in the study of astronomyOB. people with a casual interest in astronomyOC. scientists and mathematicians working with astronomersOD. geologists and cartographers Explain the metaphor beyond the symbol by choosing the phrase that establishes what is similar in the pair of words. Select the item that best expresses this. Use your notes if you need them.boy: old manto find one's own resourcesthe old man's youthto find one's lifeto be in life On May 25, after the transactions had been posted, Adams discovered that the following entry contains an error. The cash received represents a collection on account, rather than new service fees. 20-- May 23 Cash 101 1,270 Service Fees 401 1,270 Received cash for services previously earned Correct the error in the general journal using the correcting entry method. If an amount box does not require an entry, leave it blank. Pls help me with thisFreedom by Langston HughesFreedom will not comeToday, this yearNor everThrough compromise and fear.I have as much rightAs the other fellow hasTo standOn my two feetAnd own the land.I tire so of hearing people say,Let things take their course.Tomorrow is another day.I do not need my freedom when Im dead.I cannot live on tomorrows bread.FreedomIs a strong seedPlantedIn a great need.I live here, too.I want my freedomJust as you.Identify and briefly explain the tension/conflict in the poem. pleeeeeeese help doing all of guy please I giving 14 point please What is the purpose of using a Punnett square in studying genetics?A. to determine the probability of an offspring to breed with another of the same phenotypeB. to determine the exact number of offspring having a particular genotypeC. to determine the probability of an offspring having a particular phenotypeD.to determine the probability of an offspring having a particular genotype A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 5 answer choices - a, b, c, d, e- and only one correct answer. What is the probability that she answered neither of the problems correctly? Do not round your answer. (If necessary, consult a list of formulas.) 2 thirds divided by 4 The year is 2021 and you can't go a day without talking about computers. A greatly universal topic that could have students discussing quite a few things, which could all relate to real life too! Great questions on this could be: Describe your computer at home/work. What do you usually use a computer for? Do you like computers? Why/why not? What was the first computer you ever had like? What do you think will be the future of computers? How does the flashback to Abuela's life in Cuba affect the story?It creates a mystery having to do with why Abuela and Alejandro didn't stay in touch after Abuela 's family left Cuba.It sets up a surprise at the end of the story, where the reader learns that Alejandro, a boy Abuela loved in Cuba, has been writing the letters. It provides a suspenseful subplot by showing how Abuela's family escaped from Cuba.The flashback of the incident of young love between Abuela and Alejandro is the resolution to the story. What is the domain of D(t) as it applies in this situation? What is the value of x? What is the volume of the triangular prism shown below?10A. 100 cu. unitsB. 200 cu. unitsC. 400 cu. unitsD. 300 cu. units