The following which is not a safety concern associated with the lab to determine the molar volume of a gas include the following below:
Keep valves closed when not in use.Do not store flammable gases near oxidizers or combustible materials.What are Flammable gases?Flammable gases are explosive when they are mixed with air or oxygen in the right proportions.
This is therefore the reason why it is best to store them in a safe environment so that a fire incident doesn't occur. The valves should also be tightly closed so nas to prevent the escape of gases intyo the atmposphere.
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the energy lost when of water cools from 86.4 ∘C to 4.8 ∘C
The amount of energy needed to raise a material's heat content by precisely 1 degree per gram is known as specific heat. If we assume the mass of water 1gm the energy lost is -341.088.
What is specific heat capacity?
Heat always transfers from the warmer to the cooler material until both materials reach the same temperature when two materials, each at an initial different temperature, are placed in contact with one another.
Q = mC(T(final) - T(initial)
Q = 1 X 4.8 (4.8 - 86.4) = -341.088
The heat obtained by the initially colder substance must equal the heat lost by the initially warmer material, according to the law of conservation of energy.
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A nutritionist suspected that her company's clients had below average cholesterol. They obtained a random sample of 8 clients of the same age and gender. These clients had a mean cholesterol level of xˉ=4.28 mmol/L (millimoles per liter).To see how likely a sample like this was to happen by random chance alone, the nutritionist performed a simulation. They simulated 60 samples of n=8 cholesterol levels from a normal population with a mean of 4.6 mmol/L and a standard deviation of 0.5 mmol/L (these are generally accepted values for people with the same age and gender of those in the sample). They recorded the mean of the cholesterol levels in each sample. Here are the sample means from their 60 samples:They want to test H0:μ=4.6 mmol/L vs. Ha:μ<4.6 mmol/L where μ is the mean cholesterol level for all clients like those sampled.Based on these simulated results, what is the approximate p-value of the test?Note: The sample result was xˉ=4.28 mmol/L.
The nutritionist can deduce that the mean cholesterol level for all clients is less than 4.6 mmol/L (Ha:4.6 mmol/L) because this p-value is less than 0.05, rejecting the null hypothesis.
Calculating the likelihood that a sample mean will be equally extreme or more extreme than the observed mean if the null hypothesis is correct will yield the p-value.
Using the observed sample mean as a foundation, calculate the Z-score:
[tex]Z = \frac{4.28 - 4.6}{0.5 / \sqrt{8}}[/tex]
To ascertain the likelihood of encountering a Z-score, look up the Z-score in a typical normal table. The Z-score in this case is around -2.56, with a probability of 0.0039.
The p-value is the chance of encountering a sample mean that is as severe or more extreme than the observed mean, given that the null hypothesis is true. The p-value for this test is hence close to 0.0039.
There is a 0.0039 possibility of seeing a sample mean that is as high or more severe than the observed mean (4.28 mmol/L) if the average cholesterol level for all customers is 4.6 mmol/L.
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how many grams are in 1.53 moles of Li2Co3
To find the number of grams in 1.53 moles of Li2Co3, we need to multiply the moles by the molar mass of Li2Co3. The molar mass of Li2Co3 is calculated as follows:
Li2Co3:
Li = 2 × 6.939 g/mol = 13.878 g/mol
Co = 3 × 58.933 g/mol = 176.799 g/mol
Total: 13.878 g/mol + 176.799 g/mol = 190.677 g/mol
So, 1.53 moles × 190.677 g/mol = 294.455 g of Li2Co3.
What is molar mass?The term "molar mass" describes the weight in atomic mass units of one mole of a substance (AMU). It is a way to quantify how much of a substance has exactly as many atoms, molecules, or ions as there are in 12 grams of pure carbon-12. The atomic masses of all the atoms in a substance's molecular formula are added up to determine its molar mass. Conversions between mass, moles, and concentration are possible. For many chemical calculations, such as calculating reaction yields or figuring out the concentration of a solution, the ability to convert a mass to moles and vice versa depends on knowing a substance's molar mass.
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Rotate the molecular structure. This can be done by clicking and dragging with your mouse, track pad, or touchscreen, depending on your device. Locate the adenine nitrogenous base and determine its location within the molecular structure. Which best describes its location? Choose one: A. not as part of a base pair; at the 3' within one polynucleotide strand B. not as part of a base pair; at the 5' end in one polynucleotide strand C. as part of a base pair; at the 3' end in one polynucleotide strand D. as part of a base pair; at the 5' end in one polynucleotide strand
C. As part of a base pair; at the 3' end in one polynucleotide strand describes its location.
Which functional group is found at the 3 ends of a polynucleotide?
The functional group that is at the end of the 3' end of the DNA is a hydroxyl group. The numbers on the carbon atoms in the pentose sugar of the nucleotides corresponding to the 3' end and the 5' end in DNA. At the 3' end, there is a hydroxyl group, made of an oxygen and hydrogen atom.
What is a nitrogenous base in DNA?
Nitrogenous base: A molecule that contains nitrogen and has the chemical properties of a base. The nitrogenous bases in DNA are adenine (A), guanine (G), thymine (T), and cytosine (C). The nitrogenous bases in RNA are the same, with one exception: adenine (A), guanine (G), uracil (U), and cytosine (C).
Why is adenine called a base?
Adenine and guanine have a fused-ring skeletal structure derived of purine, hence they are called purine bases. The purine nitrogenous bases are characterized by their single amino group (−NH 2), at the C6 carbon in adenine and C2 in guanine.
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Complete combustion of 1 mole of acetone (C3H6O) liberates 1790 kJ of energy as shown in the reaction below: C3HsO (€) + 402 (g) --> 3C02 (g) + 3H20 (€) AHSrxn = -1790 kJlmol Using the information provided (AHSrxn = -1790 kJlmol) together with the data below; Calculate the enthalpy of formation (AH?f) of acetone (C3H6O): AH?f, CO2: -393.5 kJlmol, AH?f, H2O: -285.83 kJlmol -679 kJlmol 2038 kJlmol +1019 kJlmol -248 kJlmol +1790 kJlmol
When burning one mole of acetone, 1790 kJ is released. The enthalpy of formation of acetone, C₃H₆O is equal to -247.9 kJ/mol.
The combustion reaction of a substance means the burning of a substance in the presence of oxygen to form carbon dioxide and water. For example, the combustion of carbon proceeds as follows: C + O₂ --> CO₂. We have the molar enthalpy of combustion of acetone,
C₃H₆O(l) + 4O₂(g)→ 3CO₂(g) + 3H₂O(l)
Where, ∆H꜀= −1790 kJ. We need to calculate the enthalpy of formation of acetone. Now, the standard enthalpy of formation, *ΔHf(O₂)= 0 kJ/mol, *ΔHf(CO₂)
=−393.4 kJ/mol, *ΔHf(H₂O)= -285.8 kJ/mol. We determine the enthalpy of formation of acetone as follows:
∆H꜀ = 3×ΔHf (CO₂) + 3×ΔHf (H₂O) – 1× ∆Hf(C₃H₆O) – 4× ΔHf (O₂)
=> −1790 kJ = 3 mol × −393.4 kJ/mol + 3 mol × -285.8 kJ/mol - 1 mol × ∆Hf(C₃H₆O) - 4 mol × 0
=> −1790 kJ = - 1180.5 kJ - 857.4 kJ - ∆Hf(C₃H₆O)
=> 1 mol×∆Hf(C₃H₆O)= -1180.5 kJ - 857.4 kJ + 1790 kJ
=> ∆Hf(C₃H₆O) = - 247.9 kJ/mol
Therefore, the required enthalpy value for acetone is -247.9 kJ/mol.
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Part 1: Read the following information on elements, compounds and mixtures. Fill in the blanks where necessary Elements: A pure substance containing only one kind of • An element is always uniform all the way through (homogeneous). An element be separated into simpler materials (except during nuclear reactions). • Over 100 existing elements are listed and classified on the Compounds: A pure substance containing two or more kinds of The atoms are __combined in some way. Often times (but not always) they come together to form groups of atoms called molecules • A compound is always homogeneous (uniform). Compounds _ be separated by physical means. Separating a compound requires a chemical reaction The properties of a compound are usually different than the properties of the elements it contains. Mixtures: • Two or more NOT chemically combined. • No reaction between substances. • Mixtures can be uniform (called ) and are known as solutions. • Mixtures can also be non-uniform (called • Mixtures can be separated into their components by chemical or physical means. • The properties of a mixture are similar to the properties of its components. Part 2: Classify each of the following as elements (E), compounds (C) or Mixtures (M). Write the letter X if it is none of these. Diamond (C) Sugar (C.H.O.) Milk Air Sulfuric Acid (H:50.) Gasoline Krypton (K) Bismuth (B1) Uranium (U) Water (H20) Alcohol (CH,OH) Pail of Garbage Ammonia (NH3)_ Salt (NaCl) Energy Wood Bronze Dry Ice (CO) _Baking Soda (NaHCO)_Titanium (T1) Iron (Fe) Electricity Popcorn A dog Gold (Au) Pizza Concrete Ink CHEM 1101 AY 2019-2020 SEM 2
A pure substance containing two or more kinds of the atoms are elements combined in some way. Compounds can be separated by physical means.
A physical approach cannot separate the components of a substance. Chemical or electrochemical methods must be used to separate the elements from compounds because they are chemically bonded together.
A compound is anything created when two or more separate chemical elements are mixed together in a specific proportion. Chemical connections that are challenging to break are created when the elements interact with one another. These bonds develop as a result of atoms sharing or trading electrons.
A mixture is a substance composed of two or more unrelated chemical components. A mixture is a physical combination of two or more distinct substances that can take the form of solutions, suspensions, or colloids.
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the bjerrum plot shows the relative concentrations of each carbonate species in seawater at different ph's. please select the relative concentrations of carbonate species in seawater at ph of 7.
Relative concentrations of carbonate species in seawater at pH of 7 is [HCO3-]= 4.1 Mmol, [H2CO3]=0.91 Mmol-1, [CO3 2-]= 1.9x 10-3 Mmol.
Find attached Bjerrum plot shows the relative concentrations of each Carbonate species in seawater at different pHs.
The reactions between carbon dioxide, hydrogen ions, bicarbonate and Carbonate ions, all dissolved in water, are as follows:
CO2 + H2O ⇌ H+ + HCO−3
(1) HCO−3 ⇌ H+ + CO2−3
Reaction 1 is actually the combination of two elementary reactions:
CO2 + H2O ⇌ H2CO3 ⇌ H+ + HCO−3
Sea-water reactions.
H+ has very little final role in the seawater reactions. We can express Them as:
CO2 + CO3-- + H2O ⇌ 2HCO3-
Ca++ + CO3-- ⇌ CaCO3 (aragonite).
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How much volume of the above stock solution you will need to prepare the riboflavin solutions of following concentrations: (a) 0.059 mM in 25 ml (b) 14 uM in 25 ml
0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
To prepare a 0.059 mM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water.
First, we need to convert the concentration from mM to μM:
0.059 mM × 1000 μM/1 mM = 59 μM
Next, we need to calculate the amount of riboflavin required to prepare a 25 ml solution with a concentration of 59 μM:
59 μM × 25 ml = 1475 μmol
Finally, we need to convert μmol to milligrams:
1475 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.055 g
So, 0.055 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 0.059 mM solution.
To prepare a 14 μM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water:
14 μM × 25 ml = 350 μmol
Finally, we need to convert μmol to milligrams:
350 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.013 g
So, 0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
Mg2+, Al3+, F−, O2−
Answer:
Explanation:
Here are four binary ionic compounds that could be formed from the given ions, along with their empirical formulas:
Magnesium fluoride: Mg2+ + 2F- → MgF2 (empirical formula: MF2)
Aluminum oxide: 2Al3+ + 3O2- → Al2O3 (empirical formula: Al2O3)
Magnesium oxide: Mg2+ + O2- → MgO (empirical formula: MO)
Aluminum fluoride: Al3+ + 3F- → AlF3 (empirical formula: AlF3)
In each case, the positive and negative charges balance to give a neutral compound. The empirical formula of each compound shows the simplest ratio of the elements present in the compound.
what is the awnser to this
Answer: 2/3
Explanation:
Which of the following reactions
is BALANCED and shows
COMPLETE combustion?
A. 2C,H, +70,- 4CO₂ + 6H₂O
B. 2C,H, +40,5CO + 6H₂O
C. 2C,H, +40, 7CO₂ + 6H₂O
D. 2C,H, +50,- 4CO + 6H₂O
1
The balance of the reaction equation occurs when the number of atoms of each element is the same on both sides of the equation.
How do you know a balanced combustion equation of hydrocarbons?The question is incomplete but the reaction equation of the hydrocarbons for a combustion reaction can be known to be balanced in the following ways;
To write a balanced combustion equation of hydrocarbons, you need to follow these steps:
Write the chemical formula for the hydrocarbon, which has the general form CxHy.
Write the balanced chemical equation for the combustion of the hydrocarbon, which is typically written as:
CxHy + (x + y/4) O2 → x CO2 + (y/2) H2O
where O2 is the oxygen required for complete combustion, CO2 is carbon dioxide, and H2O is water. The factor of (x + y/4) in front of the O2 represents the stoichiometric coefficient required to balance the equation.
Balance the equation by adjusting the stoichiometric coefficients of the reactants and products so that the number of atoms of each element is the same on both sides of the equation.
Check that the equation is balanced by counting the number of atoms of each element on both sides of the equation.
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Choose the words that correctly complete the paragraph. Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate report of velocity because she mentioned only Choose... . She did not include Choose... , which is also a part of velocity.
Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate because she mentioned only speed.
What is velocity?Velocity is a vector measure of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.
For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below. Susan’s statement was inaccurate because she mentioned only speed.
Therefore, susan’s statement was inaccurate because she mentioned only speed.
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Mathematical Representations Quick Check
How does the formation of water from hydrogen and oxygen demonstrate the conservation of mass? (1 point)
Storm
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same
number of atoms as the reactants.
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of atoms as the reactants
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
What is the conservation of mass?The conservation of mass is a fundamental principle in physics and chemistry that states that the total mass of a system remains constant, regardless of any changes that take place within the system. In other words, mass cannot be created or destroyed, only transformed from one form to another.
This law applies to both physical and chemical processes, and is a key concept in fields such as thermodynamics, mechanics, and material science. It forms the basis for our understanding of the behavior of matter and energy in the universe, and is widely used in scientific and engineering calculations and experiments.
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Answer:
1. the reactants and the products have the same number of atoms of the same elements
2. the mass of one titanium atom is equal to the mass of four carbon atom
3. The atomic mass of the reactants equals the atomic mass of the product, and the product has the same number of atoms as the reactants.
4. 80amu
5. A molecule with two atoms combined with a molecule with three atoms to produce a molecule with a mass of 84 u.
Explanation: got 100% hope you get the same!
an acid ___ .is a solution where the water molecules are intact accepts h and removes them from a solutionreleases h in a solution
An acid is a solution where the water molecules release H+ ions (hydrogen ions) into the solution.
An acid is characterized by its ability to release hydrogen ions (H+) into a solution. When an acid is dissolved in water, it donates hydrogen ions (H+) to the water molecules, making the solution acidic. This is why an acid is often described as a solution that releases H+ ions into the solution.
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Which of the following measurements are not equivalent?
a. 84 cm=8.4 mm
b. 24 dL= 2.4 L
c. 183 L= 0.183 kL
d. 25 mg= 0.025 g
e. 150 msec= 0.150 sec
The non-equivalent measurements are:
B. 24 dL ≠ 2.4 L
C. 183 L ≠ 0.183 kL
E. 150 msec ≠ 0.150 sec
What is non-equivalent measurements?
Non-equivalent measurements are measurements that have different values despite being expressed in the same units. For example, 23 dL and 2.3 L are both expressed in liters, but they are not equivalent because 23 dL is a larger unit and 23 L is a smaller unit.
Non-equivalent measurements can occur when different units or prefixes are used, such as milli, kilo, deci, etc. It is important to ensure that the correct units and prefixes are used to avoid incorrect results in calculations and measurements.
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use the data to determine the heat of vaporization of hexane. Express your answer to three significant figures in kilojoules per mole.
Heat of vaporization of hexane is 32.3 KJ/mol.
Clausius-Clapeyron equation allows us to estimate the vapor pressure of A substance at any temperature It also provides an easy way to estimate The heat of phase transition from the vapor pressures measured at two Temperatures.
lnP2/P1=ΔHvapR(1/T1−1/T2)
Where,
P1 = vapor pressures at temperature T1
P2 = vapor pressures at temperature T2
ΔHvap = Heat of Vaporization
R = Gas constant (8.3145 J mol-1 K-1)
Using T1 =293 k and T2=303k
In(120/186) = ΔHvap/8.31 (1/303-1/293)
ΔHvap= In(120/186) x 8.31 x 303x293/(293-303)
(-0.438) x (8.31) x (303x293)/-10
32313.6 J/mol
32.3 KJ/mol
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A major component of gasoline is octane (C3H18). When liquid octane is burned in air it reacts with oxygen (O₂) gas to produce carbon dioxide gas and water
vapor. Calculate the moles of octane needed to produce 2.10 mol of water. Be sure your answer has a unit symbol, if necessary, and round it to the correct
number of significant digits.
The amount of octane produced by a reaction involving 2.10 mole of water is 18.9 mole.
What is a mole?We'll start by writing the reaction's balanced equation. This is as follows:
2C8H18 + 25O2 → 16CO2 + 18H2O
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Using the above data, we can calculate the number of moles of octane produced by the reaction of 2.10 mole of water. This can be obtained by doing the following:
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Therefore,
When x mole of octane will react to produce 18 moles of water
x = 2x / 18 x 2.10
2x = 37.8
x = 37.8/2
x = 18.9
As a result, the number of moles of octane produced by the reaction is 18.9 mole.
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Please help with the problem attached:
Answer:
the one with cars is false I think
Given the information below, determine the crystal structure. Consider only FCC and BCC structures as possibilities.Lattice parameter a = 0.4997 nmPowder x-ray: λ = 0.1542 nm2θ (°) Constructive Interference 31.0, 36.0, 51.8, 61.6, 64.8
The crystal structure of the material is FCC.
The powder x-ray diffraction pattern and the lattice parameter are used to determine the crystal structure of a material.
The presence of constructive interference at 2θ values of 31.0°, 36.0°, 51.8°, 61.6°, and 64.8° suggests that the material has a face-centered cubic (FCC) crystal structure. This is because the FCC crystal structure is characterized by diffraction peaks at 2θ values of roughly 43.5°, 46.6°, 48.3°, 50.0°, and 51.7°.
In an FCC crystal structure, the lattice points are located at the center of the faces of the unit cell. The lattice parameter "a" represents the length of one side of the unit cell.
On the other hand, a body-centered cubic (BCC) crystal structure is characterized by diffraction peaks at 2θ values of roughly 48.7°, 51.4°, and 53.1°.
Given the lattice parameter and the powder x-ray diffraction pattern, it can be concluded that the crystal structure of the material is FCC.
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Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:
2KI (aq) + Cl2 (g) --> 2KCl (aq) + I2 (g)
a. How many moles of I2 are produced? ________ moles I2 (3 sig figs)
b. How many moles of KI were used? _________ moles KI (3 sig figs)
c. How many grams of KI were used? _________ grams KI (3 sig figs)
20 points
As per the balanced reaction two mole of KI gives one mole of I2. 8.5 L at STP equal to 0.37 moles. 0.74 moles of KI or 122.8 grams are required to produce 0.37 moles of I₂.
What is STP condition ?The standard condition of temperature (298 K ) and pressure (1 atm) is called STP. At STP, one mole of every substance contains 22.4 L volume.
Hence, number of moles of 8.5 L of iodine gas at STP is = 8.5 L/22.4 L/mol = 0.37 moles.
As per the balanced reaction, 2 moles of KI is used to produce one mole of I2. Then, number of moles of KI used to give 0.37 moles of iodine is:
0.37 × 2 = 0.74 moles of KI.
Molar mass of KI = 166 g/mol
mass of 0.74 moles = 166 × 0.74 = 122.8 g.
Therefore, 122.8 grams of KI were used for 8.5 L of iodine gas.
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An aqueous solution at 25°C has a H3O+ concentration of ×8.810−12M . Calculate the OH− concentration. Be sure your answer has the correct number of significant digits.
The OH⁻ concentration will be 10^2.9031
The amount of hydrogen ions present in a solution or substance is first and foremost indicated by the pH scale, which measures acidity or alkalinity.
The concentration of hydrogen ions, or H₃O⁺, is what is referred to as the pH, which is defined as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= - log [H₃O⁺]
An aqueous solution at 25°C has a H₃O⁺ concentration of 8.8 x 10⁻¹²M
pH= - log [H⁺]= - log [H₃O⁺]
pH= - log [8.8 x 10⁻¹²M]
pH = 11.0969
The following relationship can be established between pH and pOH:
pOH + pH= 14
pOH = 14- pH
pOH = 14- 11.0969
pOH = 2.9031
pOH = - log [OH]
2.9031 = - log [OH]
[OH] = 10^2.9031
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For a certain ideal gas, the temperature is
increased from 200 K to 602 K allowing pres-
sure, which is initially 1 atm, to vary while
the volume and number of moles of gas are
held constant. What is the new pressure?
Answer in units of atm.
Answer:
3.01 atmospheres
Step by step explanation:
The pressure of an ideal gas is directly proportional to its temperature and directly inversely proportional to its volume. Since the volume and number of moles are held constant, the pressure will be directly proportional to the temperature.
So, using the ideal gas law, P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the new pressure and temperature, respectively.
Substituting the initial values, P1 = 1 atm and T1 = 200 K, and the new temperature T2 = 602 K, we can solve for P2:
P2 = (P1 x T2) / T1 = (1 atm x 602 K) / 200 K = 3.01 atm
Therefore, the new pressure is 3.01 atm.
Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released).AB+C --> AC+BA+ BC --> AB + CA2+C2 --> 2ACB2+C2 --> 2BCA2+B2 --> 2ABStrongest BondA-BA-AB-BC-CB-CA-CWeakest Bond
The answer is 1) Endothermic, 2) Exothermic, 3) Endothermic, 4) Endothermic, 5) Exothermic.
The stronger the bond, the more energy is required to break it, and the stronger the bond formed, the more energy is released.
AB is a strong bond and requires more energy to break it, forming a weak AC bond that releases very little energy, so the reaction is relatively endothermic since more energy is absorbed than given off. Similar logic can be applied to all 5.
Endothermic reactions consume energy in the form of heat. Endothermic reactions occur when molecules absorb energy from surroundings, causing them to break and form new bonds with other molecules.
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A chemist measures the amount of iodine solid produced during an experiment. She finds that of iodine solid is produced. Calculate the number of moles of iodine solid produced.
The number of moles of iodine solid produced is 1.6 g.
What are moles?Moles are a standard scientific unit for measuring large quantities of very small entities, such as atoms.
Mass of iodine solid produced = 1.6 g
Iodine solid has a molecular formula: I2
Atomic mass of iodine = 126.904 g/mol
Therefore, molar mass of I2 solid = 2 x 126.904 = 253.808 g/mol
The number of moles of a given substance is the ratio of its mass to the molar mass
moles of I2 solid = mass of I2 solid/molar mass = 1.6 g/253.808 = 0.00630 moles
Hence, the moles of iodine solid produced are 0.00630 moles.
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draw three glucose molecules joined by a,1, 4 linkages. you only need to show o's and the h's attached to o's. you may draw ring or chair forms of glucose?
Glucose (C6H12O6, molecular weight 180.18) is a hexose—a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains -CHO group).
Glucose is an aldehyde (contains -CHO group). Its five carbons and one oxygen form a ring called a "pyranose ring", the most stable form for six-carbon aldoses. In this ring, each carbon is attached to a hydroxyl and hydrogen side group except for the fifth atom, which is attached to the sixth carbon on the outside of the ring, forming the CH2OH group. This ring structure is in equilibrium with the more reactive form.
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How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?
Answer:
To prepare 200.0 mL of 0.900% (m/v) KCl solution, 91.4 grams of KCl are required. [1] This can be calculated by first converting the molarity to moles, then using the atomic mass of KCl to convert the number of moles to grams. For example, 2.45 moles of KCl is required to make 0.5 L of 2.45 M solution. [2] This calculation can also be applied to other salts, such as CuSO4.6H2O, to find the required mass to make a given 0.300 M solution. [3]
Explanation:
In order to prepare a 200.0 mL solution of 0.900% (m/v) KCL, you will need 1.8 grams of KCL.
Explanation:To resolve the question of 'How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?', first we need to understand that the %(m/v) here means grams of solute per 100 mL of solution. Hence, for a 0.900% (m/v) KCL solution, there would be 0.900 grams of KCL per 100 mL of solution.
For preparing 200.0mL (which is double of 100mL), simply double the amount of KCL needed. So, 0.900 grams x 2 = 1.8 grams.
So, you therefore need 1.8 grams of KCL to prepare 200.0mL of 0.900% (m/v) KCL solution.
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For the following reaction, 8.10 grams of silicon tetrafluoride are allowed to react with 5.90 grams of water.
Silicon tetrafluoride(s) + water(l) → hydrofluoric acid(aq) + silicon dioxide(s)
What is the maximum amount of hydrofluoric acid that can be formed?
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
The maximum amount of HF that can be formed is 0.312 mol. The formula for the limiting reagent is SiF4. The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.
What is limiting reagent?Limiting reagent is the reactant that is completely used up in reaction and hence determines when the reaction stops.
SiF4(s) + 2 H2O(l) → 4 HF(aq) + SiO2(s)
Molar masses of SiF4 and H2O are:
SiF4: 28.09 + 4 x 19.00 = 104.09 g/mol
H2O: 2 x 1.01 + 16.00 = 18.02 g/mol
Number of moles of each reactant is:
n(SiF4) = 8.10 g / 104.09 g/mol = 0.0779 mol
n(H2O) = 5.90 g / 18.02 g/mol = 0.327 mol
For SiF4: n(HF) = 0.0779 mol SiF4 × (4 mol HF / 1 mol SiF4) = 0.312 mol HF
For H2O: n(HF) = 0.327 mol H2O × (4 mol HF / 2 mol H2O) = 0.654 mol HF
We see that H2O produces a larger amount of HF than SiF4, indicating that SiF4 is limiting reagent. Therefore, the maximum amount of HF that can be formed is 0.312 mol.
The formula for the limiting reagent is SiF4.
From the balanced equation, we see that 1 mol of SiF4 reacts with 2 mol of H2O to produce 4 mol of HF. Therefore, the amount of H2O required to react with 0.0779 mol of SiF4 is:
n(H2O) = 0.0779 mol SiF4 × (2 mol H2O / 1 mol SiF4) = 0.1558 mol H2O
The amount of excess H2O that was consumed is: n(H2O excess consumed) = 0.
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Be sure to answer all parts.
Calculate the mass in grams of 16.8 mol of copper(I) carbonate. Enter your answer in scientific notation
with the correct number of significant figures.
Solving the Question
[tex]n=\dfrac{m}{M}[/tex]
m = massM = molar massRearrange for m:
[tex]m=nM[/tex]
Plug in given:
[tex]m=(16.8)M[/tex]
⇒ The molar mass of copper (1) carbonate is 187.1 g/mol:
[tex]m=(16.8)(187.1)\\m=3143.28[/tex]
Round to significant figures:
⇒ The given value has 3 significant figures:
[tex]m= 3140[/tex]
Convert to scientific notation:
3.14 × 10³ g
Answer3.14 × 10³ g
need help i need it quick
Answer:
A
Explanation:
I would expect a sandwich to look like A
if the concentration of chloride is higher inside the cell what does that mean for the nernst potential
Inside the cell, the potassium concentration is higher than outside, whereas the sodium and chloride ion concentrations are lower.
How does chloride impact the potential of resting membranes?Since chloride is a negative ion, it must exit the cell in order for the membrane potential to change from -70 mV to -65 mV by making the cell more positive.
How does concentration affect the potential of the cell?The larger concentration enables the rise in voltage difference in an electrochemical cell. Increased voltage is seen as a result of the reaction moving more quickly in a forward direction due to the higher reactant concentration.
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