By decreasing agitation, rate of dissolution of a solid in a liquid can be decreased. Therefore, the correct option is option C.
What is dissolution?To dissolve means to move a solute into a solution in chemistry. Dissolution is another word for dissolving. Dissolution often entails a solid transitioning into such a liquid phase, although it can also involve additional changes.
For instance, when alloys develop, a solid solution is created when one resulting effect into another. A process must fulfill specific requirements in order to be deemed dissolution. By decreasing agitation, rate of dissolution of a solid in a liquid can be decreased.
Therefore, the correct option is option C.
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A 524.7 ng sample of an unknown radioactive substance was placed in storage and its mass was measured periodically. After 47 days the amount of radioactive substance had decreased to 65.59ng. How many half‑lives of the unknown radioactive substance have occurred?
Number of half-lives is 3
The decay of this radioactive unknown compound is a first-order process.
We can express the time dependence of its mass m using a first-order integrated rate law, where k is the rate constant:
mt = mass at time t
m0 = initial mass
t = time
Procedure:
1) We need to find "k":
From the first-order rate law we clear k,
[tex]\frac{mt}{mo} = e^{-kxt}[/tex]
㏑[tex](\frac{mt}{mo})= -kxt[/tex]
[tex]\frac{ln(\frac{mt}{mo}) }{-t} = k[/tex]
[tex]k=\frac{ln(\frac{65.59ng}{ 524.7 ng} )}{-47 }[/tex]
k = 0.044[tex]days^{-1}[/tex]
2) We find the half-life from the value of k we have just calculated:
[tex]t\frac{1}{2}[/tex] =[tex]\frac{ln2}{k}[/tex] = 15.7days
3) The number of half-lives of the unknown sample is:
Number of Half-lives = 47 days / 15.7 days = 3 (approx.)
Hence 3 is a correct answer.
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Draw an alternative Lewis (resonance) structure for the incomplete structure. Show the unshared electron pairs and nonzero formal charges in your structure. Don't use radicals. Select Draw Rings More Erase С H N H Н. Н. CEN H H a Determine the formal charge on the nitrogen atom in the structure. If the atom is formally neutral, indicate a charge of zero. Screenshot
To draw an alternative Lewis structure, we need to move electrons to form a double or triple bond between the nitrogen atom and another atom in the molecule. We can also move electrons to form a lone pair on another atom in the molecule. The goal is to achieve a more stable structure with formal charges as close to zero as possible.
For example, consider the incomplete Lewis structure:
H
|
N
One possible resonance structure is:
H
|
N=H
In this structure, we have formed a double bond between the nitrogen atom and one of the hydrogen atoms. We have also placed a lone pair of electrons on the other hydrogen atom.
The formal charge on the nitrogen atom in this structure is:
Valence electrons in nitrogen = 5
Non-bonding electrons = 2
Number of bonds = 1
Formal charge = Valence electrons - Non-bonding electrons - 1/2(Number of bonds) = 5 - 2 - 1/2(1) = 2
Therefore, the formal charge on the nitrogen atom in this structure is +2.
Note that this is just one possible resonance structure. There may be other valid resonance structures that can be drawn, and the actual distribution of electrons in the molecule is a combination of all possible resonance structures.
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Which of the following will increase the rate of dissolution of a gas in a liquid?
a
decrease pressure
b
increase temperature
c
decrease agitation
(30 points)
Answer:
the answer is C. decrease agitation
In a combination reaction, 2.07 g of magnesium is heated with 9.05 g of nitrogen. How many moles of product are formed? Assume the reaction goes to completion.
Answer:
Many moles are formed
Explanation:
if 1.00 grams of hydrogen peroxide (h2o2) and 2.00 grams of hydroquinone (c6h4(oh)2) are added to the reaction chamber:
Benzoquinone is created when the hydroquinone reacts with the hydrogen peroxide that is breaking down (C6H4O2). The oxygen and hydrogen reaction causes
What is meant by benzoquinone?A yellow, crystalline (sand-like) substance with a chlorine-like odor is known as p-benzoquinone. It serves as a fungicide, reagent in photography, and a raw material for the production of dyes and other compounds. Blood levels of the hazardous metabolite 1,4-benzoquinone can be used to monitor exposure to benzene or combinations of benzene and benzene derivatives, such as gasoline. Animals exposed severely to the substance have shown kidney damage, and it has the potential to interfere with cellular respiration. The higher plants, fungi, bacteria, and animal kingdom are where you'll mostly find the benzoquinones class of natural quinones. They participate in crucial biological activities such bioenergetic transport, oxidative phosphorylation, and electron transport mechanisms.To learn more about benzoquinone, refer to:
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you have just installed a new hard drive in your desktop computer. which of the following power supply connectors is designed to provide power to your new hard drive?
The power supply connector that is designed to provide power to a new hard drive in a desktop computer is the SATA power connector.
What is Hard Drive?
A hard drive, also known as a hard disk drive (HDD), is a type of data storage device that uses magnetic storage to store and retrieve digital information on a computer.
Hard drives consist of one or more rigid, rotating platters coated with a magnetic material, and a read/write head that moves over the platters to read and write data. The platters are spun at high speeds by a motor, while the read/write head floats just above the surface of the platters, using magnetic fields to read and write data.
SATA (Serial Advanced Technology Attachment) power connectors are used to provide power to SATA hard drives, as well as to other SATA devices such as optical drives and solid-state drives (SSDs). The SATA power connector is a small, rectangular, 15-pin connector that is typically located on the power supply cable coming from the power supply unit (PSU) in a desktop computer.
If your new hard drive requires power from the power supply unit, you will need to connect a SATA power connector to the drive's power port, which is usually located on the back of the drive. Some older hard drives may use a different type of power connector, such as the 4-pin Molex connector, but SATA is the most common type of power connector used for modern hard drives.
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for part 3: in your lab notebook, write a net ionic equation for the two changes observed: (1) the solid forming and (2) the solid dissolving. these changes are explained within the lab manual. if you did not see these changes, make a note to repeat this part on day 2.
The ionic equation for solid forming is Cu2+(aq) + 2OH-(aq) → Cu(OH)2(s) and the ionic equation for the solid dissolving is Cu(OH)2(s) + 2OH-(aq) → Cu(OH)4 2-(aq).
Solid forming refers to the process of creating a solid object or structure from a material that is initially in a liquid, powder, or semi-solid state. This process can be achieved through a variety of methods, including casting, molding, extrusion, and additive manufacturing (3D printing).
Casting involves pouring molten metal or other material into a mold to create a specific shape as the material cools and solidifies. Molding is similar to casting, but typically involves using a preformed mold made of material such as plastic, silicone, or metal. Extrusion involves pushing a material through a die to create a continuous shape, such as a tube or rod.
• ionic equation for Solid forming:
Cu2+(aq) + 2OH-(aq) → Cu(OH)2(s)
Solid dissolving is a process by which a solid substance dissolves in a liquid to form a homogenous solution. In this process, the solid substance (solute) is broken down into individual molecules or ions, which are then surrounded by the molecules of the liquid (solvent).
The rate at which a solid dissolves in a liquid depends on a number of factors, including the surface area of the solid, the temperature of the liquid, and the concentration of the solute in the liquid. Generally, increasing the surface area of the solid, increasing the temperature of the liquid, and increasing the concentration of the solute in the liquid all increase the rate of dissolution.
The process of solid dissolving can be understood using the concept of intermolecular forces. The attractive forces between the molecules of the solute and solvent play an important role in the dissolution process. When the forces of attraction between the solute and solvent molecules are stronger than the forces holding the solute together, the solute dissolves in the solvent.
• Solid dissolving:
Cu(OH)2(s) + 2OH-(aq) → Cu(OH)4 2-(aq)
If you did not observe these changes, it is recommended to repeat the experiment on day 2.
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When 25.00 mL of an unknown weak base is titrated with 0.122 M HCI, it takes 32.42 mL to reach the equivalence point. Reference Material pH = -log[H") (H+) = 10 pk = -log K K = 10 X pOH = -log(OH) (OH) = 10-POH pk = -log K K = 10pk Molar Mass HCI 36.458 g/mol The ionic product of water = Kw = [H] x [OH-] = 1.0 x 10-14 at 298 K. The expression varies with temperature a) What is the concentration, in M, of the weak base? Enter a number only, no text. b) At half-equivalence point, the pH is 11.58. What would be the Kb of the weak base?
a) 0.158 M is the concentration of the weak base.
b) 5.01 x [tex]10^{-3}[/tex] is the Kb of the weak base.
a) To determine the concentration of the weak base, we can use the equation:
moles of HCl = moles of weak base
We can calculate the moles of HCl from the volume and concentration:
moles of HCl
= 0.122 M x 0.03242 L
= 0.00395 mol
At the equivalence point, the moles of HCl will be equal to the moles of the weak base. Therefore, we can use this information to find the moles of the weak base:
moles of weak base = 0.00395 mol
Now we can use the volume and moles of the weak base to calculate its concentration:
The concentration of weak base = moles of weak base/volume of the weak base
The concentration of weak base = 0.00395 mol / 0.02500 L
The concentration of weak base = 0.158 M
Therefore, the concentration of the weak base is 0.158 M.
b) We have added half the quantity of HCl required to achieve the equivalence point at the half-equivalence point. We may thus conclude that half of the weak base has been neutralized while the other half is still in its fundamental state. This indicates that the weak base and its conjugate acid are present in equal proportions.
[weak base] = [conjugate acid]
We can use the expression for the ionization constant (Kb) to relate the concentrations of the weak base and its conjugate acid:
Kb = [conjugate acid] x [OH-] / [weak base]
Since the solution is at half-equivalence, the concentration of the weak base and its conjugate acid are both equal to 0.079 M (half of the initial concentration of the weak base). We can use this information and the given pH to calculate the concentration of hydroxide ions ([OH-]):
pH = 11.58 = 14 - pOH
pOH = 2.42
[OH-] = [tex]10^{-pOH}[/tex]
[OH-] = 5.01 x [tex]10^{-3}[/tex] M
Now we can use the expression for Kb to calculate its value:
Kb = [conjugate acid] x [OH-] / [weak base]
Kb = (0.079 M) x (5.01 x 10^(-3) M) / (0.079 M)
Kb = 5.01 x 10^(-3)
Therefore, the Kb of the weak base is 5.01 x [tex]10^{-3}[/tex].
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which of the following compound that uncouples electron transport from atp synthesis and allow h back across without atp synthase? 2,4-dinitrophenol (dnp) rotenone oligomycin antimycin a cyanide
A: 2,4-dinitrophenol (DNP) is the compound that uncouples electron transport from ATP synthesis and allows H+ back across without ATP synthase.
DNP is a protonophore that acts by making the inner mitochondrial membrane leaky to protons. This causes a disruption of the proton gradient that drives ATP synthesis by the ATP synthase, which in turn uncouples the electron transport chain from ATP synthesis. This can result in a decrease in the efficiency of cellular respiration, and in some cases, can be toxic to cells. In contrast, the other compounds listed (rotenone, oligomycin, antimycin A, and cyanide) act by inhibiting various components of the electron transport chain and do not directly uncouple electron transport from ATP synthesis.
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What quantity of moles of C are formed upon complete reaction of 2 mol of B according to the generic chemical reaction: A + 2B = C
1 mole of C are formed upon complete reaction of 2 mol of B according to the generic chemical reaction.
What is moles?In the International System of Units, the mole (sign mol) is the unit of material quantity (SI). The amount of material is a measurement that indicates how many elementary constituents of a certain substance are present inside of an object or sample.
The mole has been defined as having 6.022×10²³ basic entities. An elementary entity can be an atom, chemical molecule, an ion, and ion pair, or perhaps a subatomic particle like an electron, depending on the substance.
A + 2B → C
moles of B = 2
the mole ratio between C and B is 1:2
moles of C= 1 mole
Therefore, 1 mole of C are formed upon complete reaction of 2 mol of B according to the generic chemical reaction.
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which of the following molecules is not directly formed by any of the steps of the citric acid cycle? a. ATP.
b. CO2. c. NADH. d. FADH2
e. coenzyme
ATP is not directly formed by any of the steps of the citric acid cycle. Option A is correct.
Although, the citric acid cycle produces some ATP indirectly through the electron transport chain, the production of ATP from the citric acid cycle does not occur directly in any of the steps of the cycle. The other options (CO₂, NADH, FADH₂, and coenzyme) are all directly involved in various steps of the citric acid cycle.
Citric acid cycle: The citric acid cycle, also known as the Krebs cycle or tricarboxylic acid (TCA) cycle, is a series of chemical reactions that occur in the mitochondria of eukaryotic cells and the cytoplasm of prokaryotic cells. It is a central metabolic pathway that completes the oxidation of carbohydrates, fats, and proteins, releasing energy that is used to produce ATP, the primary energy currency of the cell.
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for the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.
The limiting reactant depends on the relative amounts of Al and O2 and can be determined by converting the amounts to the same unit and comparing them to the stoichiometric ratio in the balanced equation.
The Explanation for Each ScenarioIn this case, both Al and O2 are in excess: meaning neither is the limiting reactant.This question should be provided as:
For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.
4Al(s)+3O2(g)?2Al2O3(s)In which is Al limiting and which is O2 limiting?
1 mole Al and 1 mole O24 mole Al and 2.6 mole O211.4 mole Al and 9.5 mole O224 mole Al and 19 mole O2Learn more about limiting reactant brainly.com/question/14222359
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You sit comfortably in your room studying and notice that the air temperature is fluctuating considerably. Perhaps the air conditioning system is not well regulated. Sometimes it gets too hot and you sweat while other times you get so cold that you shiver. When you are sweating or shivering, you are exhibiting yourA) limits of tolerance.B) temperature optima.C) resource range.D) abiotic independence.
When you are sweating or shivering, you are exhibiting your limits of tolerance.
What are the limits of tolerance?The human body can only withstand certain amounts of environmental stress. A key element in defining the body's tolerance limitations is temperature. Only a small range of temperatures is tolerable for the human body, and both hypothermia and hyperthermia can be fatal. Air pressure and humidity both have an impact on how well the body can withstand the environment. Altitude sickness and dehydration are both caused by low air pressure and high humidity, respectively. The body's capacity to endure the environment can also be impacted by pollution and chemical exposure. While exposure to radiation can result in cancer and genetic damage, noise pollution can also induce stress and hearing loss. Overall, a complex interplay of many environmental influences affects the human body's tolerance thresholds.
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you have isolated a decapeptide (a 10-residue peptide) called fp, which has anticancer activity. determine the sequence of the peptide from the following information. (note that amino acids are separated by commas when their sequence is not known.) (a) one cycle of edman degradation of intact fp yields 2 mol of pth-aspartate per mole of fp. (b) treatment of a solution of fp with 2-mercaptoethanol followed by the addition of trypsin yields three peptides with the composition (ala, cys, phe), (arg, asp), and (asp, cys, gly, met, phe). the intact (ala, cys, phe) peptide yields pth-cysteine in the first cycle of edman degradation. (c) treatment of 1 mol of fp with carboxypeptidase (which cleaves the c-terminal residue from peptides) yields 2 mol of phenylalanine. (d) treatment of the intact pentapeptide (asp, cys, gly, met, phe) with cnbr yields two peptides with the composition (homoserine lactone, asp) and (cys, gly, phe). the (cys, gly,phe) peptide yields pth-glycine in the first cycle of edman degradation.
Due to its simplicity of use and high-throughput operations, liquid chromatography-mass spectrometry (LC-MS) is a widely used technique for determining peptide sequences.
What is meant by LC-MS?Liquid chromatography-mass spectrometry is an analytical chemistry method that combines the mass spectrometric mass analysis skills with the physical separation capabilities of liquid chromatography. A method used in laboratories to separate, identify, and quantify the concentration of several compounds in a liquid sample by combining two distinct processes.Liquid chromatography (LC) can be used to separate the components, and the sample eluents from LC are then carried into mass spectrometry (MS), where the detection, identification, and measurement of the masses of the components can be done while other components are present.The components within each peak are then recognised and detected using the mass spectra of those components. Using LC-MS, mixtures are separated depending on their physical and chemical features.To learn more about LC-MS, refer to:
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An oxide of tin crystallizes with the following unit cell (where tin = gray and oxygen = red)
Tetragonal crystalline structure is shared by several other metal oxides, including the mineral tin dioxide, often known as stannic oxide or cassiterite (SnO 2).
What is the unit cell in An oxide of tin crystallizes?The tetragonal unit cell of SnO 2's rutile structure possesses P4 2 /mnm space-group symmetry and lattice constants of a = b = 4.7374 and c = 3.1864 [13].
When we look at this unit cell, we can tell that the titanium is the block. The lead is blue, which equals 123456 and P. B. 6. As a result, there is one titanium since there are six lead. P B six T. I., then.
therefore, The red is oxygen after that. We may also observe that we have 1234 Last 678 liters of oxygen. Thus, it should be 08. So, the formula for this unit cell is as follows. The number would be PB 6 Ki I-08.
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polymers may be composed of thousands of monomers. draw three repeat units of acrylonitrile. assume there are hydrogen atoms on the two ends of the trimer. ignore stereochemistry
H
|
H2C = CH - C ≡ N
|
H
This is a repeat unit of acrylonitrile. Three such units together, with hydrogen atoms on each end, would be drawn as:
H H
| |
H2C = CH - C≡N-CH2-CH=C H - C≡N
| |
H H
What is acrylonitrile?
Acrylonitrile is a colorless, liquid organic compound with the chemical formula C3H3N. It is an important monomer used in the production of various synthetic polymers, such as polyacrylonitrile, which is used in the manufacture of carbon fibers, and acrylonitrile-butadiene-styrene (ABS), a thermoplastic used in various applications such as automotive parts, toys, and electronic housings. Acrylonitrile is also used as a fumigant, in the production of specialty chemicals, and as a precursor to various pharmaceuticals. It is a highly reactive compound and must be handled with care due to its toxicity and flammability.
Hence, the answer is,
H H
| |
H2C = CH - C≡N-CH2-CH=C H - C≡N
| |
H H
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Determine the number of moles in 5.00 × 10²³ formula units of BaBr₂.
The number of moles in 5.00 × 10²³ formula units of BaBr₂ is approximately 0.83 moles, calculated by dividing the given number of formula units by Avogadro's number (6.022 × 10²³).
Explanation:To determine the number of moles in 5.00 × 10²³ formula units of BaBr₂, you have to know the Avogadro's number, which is 6.022 × 10²³ formula units per mole.
Therefore, using Avogadro's number, you divide the given number of formula units by this value. So, the calculation is as follows: 5.00 × 10²³ formula units / 6.022 × 10²³ formula units per mole = 0.83 moles of BaBr₂.
So, there are approximately 0.83 moles in 5.00 × 10²³ formula units of BaBr₂.
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which of the following is the correct wedge and dash conformation for the following newman projection g
The correct wedge and dash conformation for the following Newman projection is: IV
What are wedge and dash conformation?The 3D structure of organic molecules is depicted using the wedge and dash conformation. It is frequently used in organic chemistry to display how substituents are oriented around chiral centers. The atoms in this conformation are dots, and the bonds in the molecule are represented by lines. Dashes and wedges depict bonds entering and exiting the paper's or screen's plane, respectively. The atoms' three-dimensional configuration can then be seen by rotating the molecule and looking at the direction of the bonds. Dashes denote the substituent is down and below the ring, whereas wedges denote the substituent is up and above the rings. Predicting the stereochemistry of chemical processes is made easier with the use of this notation.
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Determine the vapor pressure (in mm Hg) of a substance at 29°C, whose
boiling point is 76°C at 714.6 mm Hg and has a AHvap of 38.7 kJ/mol.
Hint: Use the Clausius-Clapeyron 2-point equation, and R = 8.31 J/K mol
The vapor pressure of the substance at 29°C is 622.5 mm Hg.
What is vapor pressure?Vapor pressure is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a given temperature in a closed system. It is often used as a measure of a substance's ability to vaporize.
The Clausius-Clapeyron equation can be used to calculate the vapor pressure of a substance at a given temperature by using the boiling temperature (Tb) and vapor pressure (Pb) at the boiling point. The equation is given by:
ln(P2/P1) = (AHvap/R)(1/T1 - 1/T2)
where P2 and T2 are the vapor pressure and temperature of interest, P1 and T1 are the vapor pressure and temperature at the boiling point, AHvap is the enthalpy of vaporization, and R is the universal gas constant.
For this problem, we are given T1 = 76°C, P1 = 714.6 mm Hg, AHvap = 38.7 kJ/mol, and R = 8.31 J/K mol. We want to calculate the vapor pressure at T2 = 29°C.
Using the equation above, we can calculate the vapor pressure at T2 as follows:
ln(P2/714.6) = (38.7 kJ/mol)(1/298.15 K - 1/303.15 K)
ln(P2/714.6) = (38.7 kJ/mol)(-0.0033 K-1)
ln(P2/714.6) = -0.128
P2 = e-0.128 x 714.6 = 622.5 mm Hg
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most of the starch is broken down into___which are then absorbed by the cells of___ and transported to the___by the veins.
Most of the starch is broken down into glucose molecules, which are then absorbed by the cells of the small intestine and transported to the liver by the portal vein. In the small intestine, starch is hydrolyzed by enzymes, such as amylase, into its constituent glucose molecules.
Glucose is then transported across the intestinal wall and into the bloodstream by specialized transport proteins. From there, glucose is carried to the liver through the portal vein, where it can be stored, metabolized, or released into the bloodstream as needed to fuel other tissues. The breakdown of starch and subsequent transport of glucose are essential processes for providing energy to the body's cells and maintaining normal physiological functions.
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Succinic anhydride, the structure of which is shown, is a cyclic anhydride often used in Friedel-Crafts acylations. Draw the structure of the product obtained when benzene is acylated with succinic anhydride in the presence of aluminum chloride.
The reaction of benzene with succinic anhydride in the presence of aluminum chloride as a catalyst is a Friedel-Crafts acylation reaction. The product obtained from this reaction is benzene-1,4-dicarboxylic acid.
A carbonyl group is a functional group that consists of a carbon atom double-bonded to an oxygen atom (C=O). It is a polar group and is found in a variety of organic compounds, such as aldehydes, ketones, carboxylic acids, esters, amides, and others.
carbonylgroup from succinic anhydride adds to one of the ortho- or para- positions of benzene, but the resulting intermediate is unstable and rearranges to the more stable meta- isomer. The final product is the result of two such additions to opposite carbons of the succinic anhydride.
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Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation 4NH3 + 5O2 → 4NO + 6H2O An 8.9-g sample of NH3 gives 12.0 g of NO. The percent yield of NO is .
Answer:
≈ 177.7%
Explanation:
To calculate the percent yield of NO, we need to compare the actual yield (what was obtained in the experiment) to the theoretical yield (what should have been obtained if the reaction had gone to completion).
First, we need to determine the theoretical yield of NO. We can do this by using stoichiometry to convert the given mass of NH3 to the expected mass of NO, based on the balanced equation. The ratio of the coefficients in the balanced equation tells us that 4 moles of NH3 produce 4 moles of NO, so the mole ratio of NH3 to NO is 1:1. Therefore, the mass of NO that should be produced is:
12.0 g NO = (8.9 g NH3) × (1 mole NO / 4 moles NH3) × (30.01 g NO / 1 mole NO)
where we have used the molar mass of NO (30.01 g/mol) to convert from moles of NO to grams of NO. Evaluating this expression gives:
12.0 g NO = 6.748 g NO
So, the theoretical yield of NO is 6.748 g.
To calculate the percent yield, we use the following formula:
percent yield = (actual yield / theoretical yield) × 100%
Substituting the given values, we get:
percent yield = (12.0 g / 6.748 g) × 100% ≈ 177.7%
This result suggests that the actual yield is greater than the theoretical yield, which is not possible. The most likely explanation is that there was an error in the experiment, such as incomplete reaction, loss of product during handling, or inaccurate measurement of the masses. Therefore, we should check the experimental procedure and repeat the experiment to obtain a more reliable result.
Why do we have little information about other parts of dinosaurs’ bodies?
Answer: To date, approximately 1,200 dinosaur skeletons have been discovered.
Explanation:Scientists can only guesstimate the other parts of the bodies of dinosaurs because a lot of times, partial skeletons have been found. Or even, when a full skeleton has been found, the skin and organs and everything else are gone. This leaves the scientists to make educated guesses about how they stood, what they looked like and everything else in between based on the skeletons they've found.
A small amount of acetonitrile (CH3CN) is dissolved in a large amount of formaldehyde (H2CO). Imagine separating this process into the four stages sketched below. (These sketches show only a portion of the substances, so you can see the density and distribution of atoms and molecules in them.) CH^CN H2CO solution Use these sketches to answer the questions in the table below The enthalpy of solution ?1.0 CH3CN dissolves in formaldehyde. Use this information is positive when | ? to list the stages in order of increasing enthalpy absorbed released neither absorbed nor released Would heat be absorbed or released if the system moved from Stage A to B? none ionic bonding force covalent bonding force metal bonding force hydrogen-bonding force dipole force ion-dipole force dispersion force What force would oppose or favor the system moving from Stage A to B? Check all that apply
The order is d, a e c 4 h, 2 heat is absorbed, heat is a part, 3 dipole force And dispersion force.
H2CO is a polar molecule and will have both dipole-dipole forces and London dispersion forces while CH3CH3 is a non-polar molecule and will Only have London dispersions forces.
The intermolecular forces present for the molecules given are the London Dispersion forces and the dipole-dipole forces. The London Dispersion Forces exist for all molecules. Therefore, it will exist between H2O H 2 O And CH3CN C H 3 C N .
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Which of the following elements would be a good selection as the sacrificial electrode in the cathodic protection of tin (Sn)?
I. Silver
II. Copper
III. Nickel
IV. Magnesium
The elements that would be the good selection as the sacrificial electrode in the cathodic protection of tin, Sn is the correct option is III. Nickel and IV. Magnesium.
The Sacrificial anodes are helpful to protect the metal structures from the corroding. The Sacrificial anodes will work by the oxidizing to quickly as compared to the the metal that is protecting, and that is being consumed completely and before the other metal will reacts with the electrolytes. The Sacrificial anodes is the metals or the alloys that is attached to the hull that is more anodic.
Thus, the nickel and magnesium is used as the sacrificial electrode in the cathode protection of the tin.
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uestion: Consider the following four structures, followed by mass spectral data. Match each structure with its characteristic molecular ion or fragment. In each case, give a likely structure of the ion responsible for the base peak
(a) base peak at 105
(b) base peak at 72
(c) doublet at 198 and 200, base peak at 91
(d) base peak at 91, large peak at 43
The matching of likely structure of the ion responsible for the base peak at 105, 72, 198,200, 91 and 43 differently.
The explanation and matching structure of the ions are given below:
a) The likely structure of the ion responsible for the base peak at 105 is a benzene ring with a substituent containing a nitrogen atom, such as aniline or N-methylaniline.
b) The likely structure of the ion responsible for the base peak at 72 is a methyl group, possibly as a fragment of a larger molecule.
c) The doublet at 198 and 200 suggests the presence of an isotope, and the base peak at 91 suggests the presence of a nitrogen-containing functional group, so a likely structure for the ion is an N-oxide functional group, such as a pyridine N-oxide.
d) The likely structure of the ion responsible for the base peak at 91 is a nitrogen-containing functional group, such as an amine or pyridine ring, and the large peak at 43 is likely a fragment containing a single nitrogen atom, such as NH2 or CH3N.
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NH4HS(s) ßà NH3(g) + H2S(g)For this reaction, ΔH° = + 93 kJ. The equilibrium above is established by placing solid NH4HS in an evacuated container at 25 °C. At equilibrium, some solid NH4HS remains in the container. Predict and explain each of the following.a.The effect on the equilibrium partial pressure of NH3 gas when additional solid NH4HS is introduced into the container.b.The effect on the equilibrium partial pressure of NH3 gas when additional H2S gas is introduced into the container.c. The effect on the mass of solid NH4HS present when the volume of the container is decreased.d. The effect on the mass of solid NH4HS present when the temperature is increased
The answers for following multiple question are given below.
(a)The equilibrium pressure of NH3 gas would remain unaffected. KP = (PNH3)(PH2S). Thus the amount of solid NH4HS present usually does not affect the equilibrium of the reaction.
(b) Generally, the equilibrium pressure of NH3 gas would decrease. In order for the pressure equilibrium to be constant, KP, to remain constant, the equilibrium pressure of NH3 must decrease when the pressure of H2S is increased. KP = (PNH3)(PH2S). (The complete explanation is based on the LeChatelier’s principle is also acceptable.)
(c) The mass of NH4HS increases because a decrease in volume causes the pressure of each gas to increase. To maintain the value of the pressure equilibrium constant, Kp, the pressure of each of the gases must decrease. The decrease in pressure is realized by the formation of more solid NH4HS. Kp = (PNH3)(PH2S). (A complete explanation based on LeChatelier’s principle is also acceptable.)
(d) Basically, the mass of NH4HS decreases because the endothermic reaction absorbs heat and goes nearer to completion (to the right) as the temperature increases.
Generally, for any chemical reaction, the equilibrium constant can be defined as the ratio between the amount of reactant and the amount of product which is used to determine chemical behaviour. At equilibrium, for any reaction, Rate of the forward reaction = Rate of the backward reaction.
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if we formed 39.5 grams of water the reaction has occurred what volume of oxygen gas was burned initially
To calculate the initial volume of oxygen gas burned in the reaction, we need to use the stoichiometry of the reaction, which relates the amounts of reactants and products based on their balanced chemical equation.
To find the initial volume of oxygen gas burned in the reaction, we need to use stoichiometry to relate the amounts of reactants and products. The balanced chemical equation for the combustion of hydrogen gas and oxygen gas to form water tells us that for every 1 mole of O2 consumed, 2 moles of H2O are produced.
We can use this ratio to convert the mass of water produced to the number of moles of O2 consumed. Finally, we can use the ideal gas law to calculate the initial volume of O2 consumed. Using STP of 0°C and 1 atm, we find that the initial volume of O2 burned in the reaction was about 24.3 liters.
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2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O In the above equation how many grams of N2 can be made when 132 grams of CuO are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
[tex]7.7 g[/tex] of N2 can be made when 132 grams of CuO are consumed.
The equation can be written as: NH3 + 3CuO → 3Cu + N2 + 3H2O
To calculate the amount of N2 produced in grams when 132 grams of CuO is consumed, we need to use the molar mass of each element.
Molar Mass of N2 = [tex]14 g/mol[/tex]
Molar Mass of CuO = [tex](63.5 + 16) g/mol = 79.5 g/mol[/tex]
Therefore, the number of moles of CuO consumed is [tex]\frac{ 132}{79.5} = 1.65 mol[/tex]
The ratio of N2 to CuO in the equation is 1 : 3. Therefore, the number of moles of N2 produced is[tex]\frac{1.65}{3 }= 0.55 mol.[/tex].
Now, to calculate the mass of N2 produced, we need to multiply the number of moles of N2 produced by the molar mass of N2, i.e. [tex]0.55 * 14 = 7.7 g.[/tex]
Therefore, the answer is [tex]7.7 g[/tex] of N2 can be made when 132 grams of CuO are consumed.
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complete question:2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O
In the above equation, how many grams of N2 can be made when 15 moles of CuO are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16
which of the following properly represents the order of orbital filling based on the relative energy of the orbitals?
The properly represents the order of orbital filling based on the relative energy of the orbitals is:
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p.
What Is OrbitalsOrbitals are the regions or regions in space around the atomic nucleus that have the highest probability of finding electrons. In the arrangement of the orbital diagram, an electron is symbolized by an arrow facing up which represents an electron with spin +½, or facing down which represents an electron with spin -½. To mark the distribution of orbitals within the atom, these arrows are placed on a horizontal line, in a circle, or generally in a box.
Orbital diagrams are used to facilitate the determination of the value of the quantum numbers, namely the magnetic quantum number and the spin quantum number.
Your question is incomplete but most probably your full question was:
Which of the following properly represents the order of orbital filling based on the relative energy of the orbitals?
Multiple Choice
1s 2s 3s 4s 2p 3p 4p 3p
1s 2s 2p 3s 3p 3d 4s 4p
1s 2s 2p 3s 3d 3p 4s 4p
1s 2s 2p 3s 3p 4s 3d 4p
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