Which is produced in a synthesis reaction?
A) a single element
B) single compound
C) single ion
D) single atom

Answers

Answer 1

Answer:

A single compound is produced in a synthesis reaction.

Explanation:

What are chemical reactions?

Chemical reactions are when two or more reactants chemically react with one another to create one or more substances as products. There are five types: synthesis, decomposition, single-replacement, double-replacement, and combustion.

Types of Reactions and Examples of Each

A synthesis reaction takes two or more reactants and reacts chemically to turn them all into one substance.

An example of a synthesis reaction is the reaction that takes place between sodium (Na) and chlorine (Cl) to create table salt.This reaction would be displayed as [tex]{\text{Na} + \text{Cl} \rightarrow \text{NaCl}}.[/tex]The parent reaction for a synthesis reaction is [tex]\text{A} + \text{B} \rightarrow \text{AB}.[/tex]

A decomposition reaction takes one reactant and breaks itself into two or more products.

An example of a decomposition reaction would be the decomposition of hydrogen (H₂) and oxygen (O) to create two diatomic molecules - H₂ + O₂. This reaction would be displayed as [tex]\text{H}_{2}\text{O} \rightarrow \text{H}_{2} + \text{O}_{2}.[/tex]The parent reaction for a decomposition reaction is [tex]\text{AB} \rightarrow \text{A} + \text{B}[/tex].

A single-replacement reaction takes place when two compounds chemically combine but one of the elements bonds with a different element.

An example of a single-replacement reaction would be the single-replacement of calcium and water to create calcium hydroxide and dihydrogen.This reaction would be displayed as [tex]\text{Ca} + \text{H}_{2} \text{O} \rightarrow \text{CaO} + \text{H}_{2}.[/tex]The parent reaction for a single-replacement reaction is [tex]\text{A} + \text{BX} \rightarrow \text{AX} + \text{B}.[/tex]

A double-replacement reaction works in the same way as a single-replacement reaction - however, instead of one replacement, there are two replacements.

An example of a double-replacement reaction would be the double-replacement of sodium bicarbonate (baking soda) and vinegar to produce carbonic acid and sodium acetate.This reaction would be displayed as [tex]\text{NaHCO}_{3} + \text{HC}_{2} \text{H}_{3} \text{O}_{2} \rightarrow \text{NaC}_{2} \text{H}_{3} \text{O}_{2} + \text{H}_{2} \text{O} + \text{CO}_{2}.[/tex]The parent reaction for a double-replacement reaction is [tex]\text{AX} + \text{BY} \rightarrow \text{AY} + \text{BX}.[/tex]

A combustion reaction is the introduction of heat or energy and oxygen to decompose reactants into carbon dioxide and water.

An example of a combustion reaction would be the burning of propane in a grill.This reaction would be displayed as [tex]\text{C}_{3} \text{H}_{8} + \text{5O}_{2} \rightarrow \text{3CO}_2 + \text{4H}_2 \text{O}.[/tex]The parent reaction for a combustion reaction is [tex]\text{Hydrocarbon} + \text{O} \rightarrow \text{CO}_2 + \text{H}_2 \text{O}.[/tex] A hydrocarbon is a substance that is only hydrogen and carbon.

Therefore, based on the above information, we can determine that a single compound, or option B, is the product of a synthesis reaction.

Answer 2

Answer:

single compound

Explanation:

A synthesis reaction will take more than two reactants. It will chemically mix together and then it forms a synthesis reaction. The elements involved are single compounds.

Our answer is single compounds.


Related Questions

Which of the following is not a type of energy?
A. Electricity in a power cord.
B. Heat from an oven.
C. Light from a lightbulb.
D. Smoke from a fire.

Answers

Answer:

B- heat from an oven

Explanation:

temperature isn’t energy

PLZZ ANSWER QUICKLY: True or False: MOST organelles found in plant cells are DIFFERENT than organelles found in animal cells

Answers

Answer:

Organelles allow for various functions to occur in the cell at the same time. Despite their fundamental similarities, there are some striking differences between animal and plant cells (see Figure 1). Animal cells have centrosomes (or a pair of centrioles), and lysosomes, whereas plant cells do not.

Explanation:

Determine the differences In electronegativity ionic radius atomic radius and first ionization energy for oxygen and beryllium

Answers

Answer:

Electronegativity  = 1.87.

Ionic radius = 109 pm.

Atomic radius = -39 pm

First ionization energy = 410 kJ/mol

Explanation:

Hello!

In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.

In such a way, the required comparison is written below:

Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.

Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.

Atomic radius = 73 pm (oxygen) - 112 pm (beryllium) = -39 pm

First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol

It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.

Best regards!

Oxygen and Beryllium are the elements that pertain to the same period and different groups 6A and 2A.

Ionic radius, atomic radius, electronegativity and first ionization energy are periodic qualities that have selective trends.

Differences in the trends are:

Ionic radius = 109 pm

Atomic radius = -39 pm

Electronegativity = 1.87

First ionization energy = 410 kJ/mol

This can be explained as:

Ionic radius:

= 140 pm (oxygen)- 31 pm (beryllium)

= 109.

Atomic radius:

= 73 pm (oxygen) - 112 pm (beryllium)

= -39 pm

Electronegativity:

= 3.44 (oxygen) - 1.57 (beryllium)

= 1.87

First ionization energy:

= 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium)

= 410 kJ/mol

Therefore, these data tell that ionic radius, electronegativity and first ionization energy increases from left to right in a period whereas, the atomic radius increases from right to left in a period.

To learn more about periodic trends follow the link:

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10. Determine the frequency of light that has a wavelength of 400nm. c=X*v. C=3.0x108

Answers

Answer:

7.5 x 10^14 Hz

Explanation:

Aqueous solutions of ammonium sulfide and potassium hydroxide are mixed. Precipitate:
Chemical Equation:
Complete Ionic Equation:
Net ionic Equation:

Answers

Answer:

Chemical Equation: (NH4)2S(aq) + 2KOH(aq) -> K2S(aq) + 2NH4OH(s)

Complete Ionic Equation: 2NH4^+(aq) + S^2-(aq) + 2K^+(aq) 2OH^-(aq) -> 2K^+(aq) + S^2- (aq) + 2NH4OH(s) 2NH4^+(aq) + OH^-(aq) -> NH4OH(s)

Explanation:

Ammonium sulfate and potassium hydroxide interact in this process to produce aqueous potassium sulfate, gaseous ammonia, and liquid water as byproducts. In essence, an acid-base reaction is taking place here, with the ammonium ion contributing a hydrogen ion to the potassium hydroxide's hydroxide ion.

What is chemical equation ?

Chemical formulae and symbols are used to express a chemical reaction in a chemical equation.

A chemical equation represents a chemical reaction using symbols and the chemical formulas of the reactants and products involved. In this process, ammonia and hydrochloric acid are reacting to generate ammonium chloride. For solids, the symbol is (s).

( NH₄ ) 2S ₍ aq ₎ + 2KOH ₍ aq ₎ ⇒ K₂S ₍ aq ₎  + 2NH₄

Thus, Aqueous solutions of ammonium sulfide and potassium hydroxide are mixed to formed potassium sulphide and ammonia.

To learn more about chemical equation follow the link below;

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#SPJ3

Jet streams generally flow toward the

a. north
b. south
c. east
d. west

please answer thank you

Answers

Answer:

The major jet streams on Earth are westerly winds that flow west to east.

i’m pretty sure the answer would be D!!!

According to the ideal gas law, a 10.68 mol sample of methane gas in a 0.8295 L container at 501.9 K should exert a pressure of 530.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure

Answers

Answer:

The answer is "152.28%".

Explanation:

Formula for ideal gas:

PV=nRT

equation:

[tex]\to (P+\frac{an^2}{v^2})(v-nb)=nRT \\\\a=2.253 \frac{L^2 atm}{mol^2}\\\\b=4.278 \times 10^{-2} \frac{L}{mol}\\\\n=10.68 \ mol\\\\v= 0.8295 \ L\\\\\to (P+\frac{an^2}{v^2})= \frac{nRT}{(v-nb)}\\\\\to (P)= \frac{nRT}{(v-nb)} - \frac{an^2}{v^2} \\\\[/tex]

          [tex]= \frac{10.68 \times 0.0082 \times 501.9}{0.8295 - (10.68 \times 4.278 \times 10^{-2})} - \frac{2.253 \times 10.68^2}{0.8295^2}\\\\=\frac{43.9543944}{0.4568904} - \frac{256.982587}{0.68807025}\\\\ = 96.2033661- 373.483067\\\\=-277.279701 \\\\ =-277.279701 \ atm[/tex]

The pressure of gas:

[tex]= (530.3 + 277.279701) \ atm\\\\= 807.579701 \ atm \\\\[/tex]

Calculating the pressure percentage:

[tex]=\frac{807.579701}{530.3} \times 100\\\\= 152.28 \%[/tex]

Among the following options, a valid Lewis structure of __________ cannot be drawn without violating the octet rule.

a. NH3
b. SbCl3
c. PF3
d. IF3

Answers

Answer:

d. IF3

Explanation:

The Octet rule posits that atoms gain, atom lose, or share electrons in order to have a full valence shell of 8 electrons. This statement occurs when atoms also combine to form molecules until they attain or share eight valence electrons either by losing or gaining eletrons.

From the given options, a valid Lewis structure that cannot be drawn without violating the octet rule is IF3

Calculate the total Calories in one cup of watermelon containing 0.9 g protein, 0.2 g fat, and 11 g carbohydrat

Answers

Answer:

49.4 cal

Explanation:

Step 1: Given data

Composition of 1 cup of watermelon: 0.9 g protein, 0.2 g fat, and 11 g carbohydrate.

Step 2: Calculate the calories provided by 0.9 g of protein

1 g of protein yields 4 cal.

0.9 g × (4 cal/1 g) = 3.6 cal

Step 3: Calculate the calories provided by 0.2 g of fat

1 g of fat yields 9 cal.

0.2 g × (9 cal/1 g) = 1.8 cal

Step 4: Calculate the calories provided by 11 g of carbohydrate

1 g of carbohydrate yields 4 cal.

11 g × (4 cal/1 g) = 44 cal

Step 5: Calculate the total number of calories

3.6 cal + 1.8 cal + 44 cal = 49.4 cal

1.
How many kJ are required to completely vaporize a 250 gram sample of water at 100°C?
general formula

Answers

Answer:

565 kJ

Explanation:

[tex]H_v[/tex] = Heat of vaporization of water at 100°C = 2260 J/g

m = Mass of water = 250 g

Heat required is given by

[tex]Q=mH_v[/tex]

[tex]\Rightarrow Q=250\times 2260[/tex]

[tex]\Rightarrow Q=565000\ \text{J}[/tex]

[tex]\Rightarrow Q=565\times 10^3\ \text{J}[/tex]

[tex]\Rightarrow Q=565\ \text{kJ}[/tex]

The heat required to vaporize the water is 565 kJ.

What is the acceleration of gravity on Saturn if your mass is 75 kg and your weight is 800n

Answers

Answer:

The answer is 10.67 m/s²

Explanation:

The acceleration of gravity of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{800}{75} = \frac{32}{3} \\ = 10.666666...[/tex]

We have the final answer as

10.67 m/s²

Hope this helps you

Explain why the atomic radius decreases across a period and increases down a group ?​

Answers

Answer:

In general, atomic radius decreases across a period and increases down a group. ... Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital. This results in a larger atomic radius.

2. A green laser pointer emits light at 554 nm. Calculate the frequency of this light and the energy of a photon of this light.

Answers

Answer:

Explanation:

Wavelength (λ) = speed/frequency

(λ) = c/f

Where;

c = speed (3× 10^8m/s)

f = frequency (Hz)

(

Which physical property does the inventor need to consider when choosing a
material for the container?
A. Ductility
B. Thermal conductivity
C. Transparency
D. Electrical conductivity

Answers

Answer:

A.

............

Explanation:

Ductility

I need help. Will mark Brainlist.

Answers

Answer:

you are correct, the answer is 2 g

CHEMWORK The preparation of NO2(g) from N2(g) and O2(g) is an endothermic reaction: N2(g) + O2(g) + NO2(g) (unbalanced) The enthalpy change of reaction for the balanced equation (with lowest whole-number coefficients) is AH = 67.7 kJ. If 304 ml N2 (9) at 100ºC and 3.32 atm and 410 ml 0,(9) at 100°C and 3.32 atm are mixed, what amount of heat is necessary to synthesize the maximum yield of NO2(g) ? ​

Answers

Heat required : 1.523 kJ

Further explanation

Reaction

N₂+2O₂⇒2NO₂ AH = 67.7 kJ

mol of N₂:(use Pv=nRT)

[tex]\tt n=\dfrac{3.32\times 0.304}{0.082\times 373}=0.033[/tex]

mol of O₂:

[tex]\tt n=\dfrac{3.32\times 0.41}{0.082\times 373}=0.045[/tex]

Limiting reactant :

N₂ : O₂

[tex]\tt \dfrac{0.033}{1}\div \dfrac{0.045}{2}=0.033:0.0225[/tex]

Limiting reactant : O₂(smaller ratio)

mol NO₂ = mol O₂ = 0.045

2 mol ⇒ 67.7 kJ, so for 0.045 mol, heat required :

[tex]\tt \dfrac{0.045}{2}\times 67.7=1.523~kJ[/tex]

The heat required to produce the maximum yield of NO2 is 1.52 kJ.

The balanced reaction equation is;

N2(g) + 2 O2(g) -> 2 NO2(g)

The number of moles of each gas is obtained from the ideal gas equation as follows;

For N2;

P = 3.32 atm

V = 304 ml or 0.304 L

T = 100ºC + 273 = 373 K

n = ?

R = 0.082 atmLK-1mol-1

From;

PV = nRT

n = PV/RT

n = 3.32 atm × 0.304 L/0.082 atmLK-1mol-1 × 373 K

n = 0.033 moles

For O2;

PV = nRT

n =  PV/RT

V = 410 ml or 0.410 L

P = 3.32 atm

R = 0.082 atmLK-1mol-1

T = 100°C + 273 = 373 K

n =  3.32 atm × 0.410 L/0.082 atmLK-1mol-1 × 373 K

n = 0.045 moles

1 mole of N2 reacts with 2 moles of O2

0.033 moles of N2 reacts with 0.033 moles × 2 moles/1 mole

= 0.066 moles

2 moles of O2 yields 2 moles of NO2

0.045 moles O2 yields 0.045 moles × 2 moles/2 moles = 0.045 moles

If 2 mole of NO2 requires 67.7 kJ

0.045 moles of NO2 requires 0.045 moles  × 67.7 kJ/2 mole

= 1.52 kJ

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If 8.793 of heat are added to a 2.00g sample of metal and the temperature increases by 4.9°C. What is the specific heat?

Answers

The specific heat of metal = 0.897 J/g° C  

Further explanation

Heat absorbed can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q = 8.793 J

m = 2 g

∆t = 4.9 °C

[tex]\tt c=\dfrac{Q}{m.\Delta t}\\\\c=\dfrac{8.793}{2\times 4.9}\\\\c=0.897~J/g^oC[/tex]

PLS HELP
Which substance contains bonds that involve the transfer of electrons from one atom to another?
1. CO₂
2. HF
3. CH₄
4. K₂S

Answers

Answer may be 1 co2 I might be wrong sorry

How much energy is used to melt 44.33 g of solid oxygen?

Answers

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm =  54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

Answer:

In this case, 1 mole of liquid oxygen requires 3.41 kJ of heat in order to perform that liquid → solid. your sample from grams to moles by using oxygen's molar mass.

If the earth were to spin half as fast as it does now, how many hours would be in one day?

Answers

the day would be 48 hours

Answer:

48 hours

Explanation:

Because if the world would spin regularly, then it would take 24 hours. But if it spins half as fast, then it would be 2x more.

Can a closed system gain particles

Answers

No because I had this question and got it right

Write the balanced reaction and solubility product expression (KSP) for dissolving silver chromate: Ag2CrO4(s). Include all charges, stoichiometric coefficients, and phase subscripts.

Answers

Answer:

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓

Ksp = [2s]²  . [s] → 4s³

Explanation:

Ag₂CrO₄ → 2Ag⁺  + CrO₄⁻²

Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓ Ksp

That's the expression for the precipitation equilibrium.

To determine the solubility product expression, we work with the Ksp

Ag₂CrO₄ (s)  ⇄ 2Ag⁺ (aq)  + CrO₄⁻² (aq)   Ksp

                          2 s                 s

Look the stoichiometry is 1:2, between the salt and the silver.

Ksp = [2s]²  . [s] → 4s³

 

Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction.

4NA + O2 ⟶ 2Na2O

Answers

Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

Na: 4 molesO₂: 1 moleNa₂O: 2 moles

Being:

Na: 23 g/oleO: 16 g/mole

the molar mass of the compounds participating in the reaction is:

Na: 23 g/moleO₂: 2*16 g/mole= 32 g/moleNa₂O: 2*23 g/mole +16 g/mole=  62 g/mole

Then by stoichiometry of the reaction they react and are produced:

Na: 4 moles* 23 g/mole= 92 gO₂: 1 mole*32  g/mole= 32 gNa₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

[tex]massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}[/tex]

mass of Na₂O=5.39 g

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Complete and balance the equation for the single displacement reaction Cl2 + NaCl + Br2

Answers

Answer:

NaBr + Cl2 = NaCl + Br2 - Chemical Equation Balancer.

Explanation:

Chlorine dioxide is used as a disinfectant and bleaching agent. In water, it reacts to form chloric acid (HClO3), according to the following balanced equation: 6 ClO2 + 3 H2O → 5 HClO3 + HCl If excess ClO2 is mixed with 18.0 mL of H2O (d = 0.998g/1ml ) how many grams of HClO3 are formed?
would be very helpful if the answer was explained with steps

Answers

Answer:

b

Explanation:

b

Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition reactions in the table. A 2-column table with 3 rows. The first column labeled reactants has entries 2 N a C l O subscript 3, 2 K C l O subscript 3, 2 L i C l O subscript 3. The second column labeled products has entries 2 N a C l + 3 O subscript 2, 3 O subscript 2 + 2 K C l, empty. What products should she record in the last row of the table? 2LiCl + 3O2 3LiCl + 2O2 2LiO + 3Cl2 3LiO+ 2Cl2

Answers

Answer:

2LiCl + 3O2  

Explanation:

Answer:

(C) 2LiCl + 3O2

Explanation:

sub to pewds

A gas with a volume of 525 mL at a temperature of -25°C is heated to 175°C.

What is the new volume, in milliliters, of the gas if pressure and number of moles

are held constant?

Answers

Answer:

Volume V2 = 948.13 ml

Explanation:

Given:

Volume V1 = 525 ml

Temperature T1 = -25°C + 273.15

Volume V2 = ?

Temperature T1 = 175°C + 273.15

Computation:

V1 / T1 = V2 / T2

525 / [-25°C + 273.15] = V2 / [175°C + 273.15]

Volume V2 = 948.13 ml

The new volume, in milliliters, of the gas is 948 L

From the question,

We are to determine the new volume of the gas.

From Charles' law which states that the volume of a fixed mass of gas is directly proportional to the temperature (in Kelvin) provided that the pressure remains constant.

That is,

V ∝ T

Then,

V = kT

Therefore, we can write that

[tex]\frac{V_{1} }{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Where [tex]V_{1}[/tex] is the initial volume

[tex]T_{1}[/tex] is the initial temperature

[tex]V_{2}[/tex] is the final volume

and [tex]T_{2}[/tex] is the final temperature

From the given information,

[tex]V_{1} = 525 \ mL[/tex]

[tex]T_{1} = -25 ^{\circ}C = -25 + 273.15 \ K = 248.15 \ K[/tex]

[tex]T_{2} = 175 ^{\circ} C = 175 +273.15 \ K =448.15 \ K[/tex]

Putting the values into the formula, we get

[tex]\frac{525}{248.15} = \frac{V_{2} }{448.15}[/tex]

∴ [tex]V_{2} = \frac{525 \times 448.15}{248.15}[/tex]

[tex]V_{2} = \frac{235278.75}{248.15}[/tex]

[tex]V_{2} = 948.13 \ L[/tex]

V₂ ≅ 948 L

Hence, the new volume, in milliliters, of the gas is 948 L

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How much kilometers is in 6 m

Answers

Answer: 0.006 km

Explanation:

divide the length value by 1000

so 6/1000 = 0.006

.006 km because 6/1000 is .006

HELP 40 POINTS
The figures below show the Lewis structures for three nonmetals. Which of the formulas COULD NOT represent a molecule formed by two of these elements?
A) F2
B) SF
C) OF2
D) SO

Answers

Answer:

F2

Explanation:

F2 is the only element with only 1 element and eveything else is formed by 2 non-metals

Answer:d I believe

Explanation:

Globular proteins play a critical role in virtually all chemical processes.
True or false

Answers

Answer:

True

Explanation:

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