When a rope is wrapped around a wheel (or pulley) and pulled, the lever arm is the ________ Blank 1 of the wheel and the angle between this and the force is ALWAYS ________ degrees. Blank 2

Answers

Answer 1

Answer:

the DISTANCE between the lever arm and the force is always 90º

Explanation:

In this exercise, you are asked to complete the missing words so that the phrase makes sense.

note that the torque is

              τ = F x r

where bold indicates vectors

When the rope is pulled, the DISTANCE between the lever arm and the force is always 90º


Related Questions

A boat takes off from the dock at 2.5m/s and speeds up at 4.2m/s2 for 6.0 seconds how far has the boat traveled

Answers

Answer:

The answer is "91 m"

Explanation:

[tex]v_0 = 2.5 \ \frac{m}{s}\\\\a = 4.2\ \frac{m}{s^2}\\\\t = 6.0\ s\\\\\Delta x=?[/tex]

Using formula:

[tex]\Delta x = v_0 t +\frac{1}{2} at^2\\\\[/tex]

      [tex]= 2.5 \times 6.0 +\frac{1}{2} \times 4.2 \times 6.0^2\\\\= 90.6\ m \approx 91\ m[/tex]

It was found that ice cream sales decrease significantly as the temperature outside decreases; a very strong relationship was found. What is the most likely correlation coefficient from this hypothetical study

Answers

Answer:

Value closest to 1

Explanation:

It is described from the scenario above that ice cream sales decreases as the outside temperature increases, hence showing a strong relationship between both variables (icream sales and temperature). The correlation Coefficient is a metric used in regression modeling to depict the strength of relationship between two variables, (The dependent and independent variables). Correlation Coefficient ranges from (-1 to +1). With values close to 1 or - 1. Also the positive and negative signs are used to show the type of relationship between the variables. If an increase in variable A leads to a decrease in variable B, then we have negative correlation (-) ; while an increase or decrease in both variables depicts a positive correlation. The most likely correlation Coefficient for the study above will be a positive value which is close to 1 since the relationship is described as strong.

1. Use a micrometer to find the thickness of the foil you used. Do your data confirm the measured thickness? Determine the percentage difference between the measured thickness and the thickness you found in your experiment.

Answers

Answer:

Yes.

Explanation:

Yes, my data confirm the measured thickness because the micrometer measure precise thickness of any object. If the same instrument and right method is used for the measurement of the thickness of the foil then there is zero difference occur between the measured thickness and the thickness in your experiment so using right method can reduce or eliminate the difference between the measured thickness and the thickness in experiment.

A car travelling at 10ms ,acceleration uniformly at 2ms what will be its velocity after 5s?​

Answers

[tex]we \: know \: that \\ acceleration = \frac{(final \: velocity - initial \: velocity)}{time} \\ = > a = \frac{(v - u)}{t} \\ = > 2m {s}^{ - 2} = \frac{{(v - 10m {s}^{ - 1} })}{5s} \\ = > 2m {s}^{ - 2} \times 5s = v - 10m {s}^{ - 1} \\ = > 10m {s}^{ - 1} = v - 10m {s}^{ - 1} \\ = > 10m {s}^{ - 1} + 10m {s}^{ - 1} = v \\ = > 20m {s}^{ - 1} = v \\ = > 20m {s}^{ - 1} = initial \: velocity[/tex]

Hope it helps!!

Thanks!!

Answer:

20 ms

Explanation:

You know

acceleration=2ms        initial Velocity=10ms          Time=5s

We are finding Final V

Use the equation     Final v = (a x t) + initial v

2 x 5 = 10

10 + 10 = 20

A child who is swimming toward shore at 0.78 m/s sees shark and picks up his speed
to 1.89 m/s. He covers 17.5 m until he lands on shore. What was his acceleration?

Answers

Answer:

0.085m/s²

Explanation:

Use v²=v0²+2a(d)

solve for a

v²-v0²/2d=a

Plug in givens

1.89²-0.78²/2*17.5=a

Plug into calculator

a=0.085m/s²

What is the name of the Egyptian sun god, usually depicted as a hawk-headed man with a solar disk and cobra on his head

Answers

Answer: Re-Horakhty

Explanation:

He has a human body and a falcon head, he has a crown in form of a disk with a cobra on his head. Ra-Horakhty was thought of as the god of the rising sun.

Why are dark matter and dark energy described as dark

Answers

Dark matter and dark energy described as dark because of its no interaction with electromagnetic field.

Why are dark matter and dark energy described as dark?

Dark matter is called "dark" because it does not interact with the electromagnetic field. This means that it does not absorb, reflect, or emit electromagnetic radiation and therefore, it is difficult to detect.

So we can conclude that dark matter and dark energy described as dark because of its no interaction with electromagnetic field like dark substances.

Learn more about matter here:https://brainly.com/question/3998772

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Dark matter and dark energy are described as dark because it doesn't seem to interact with the electromagnetic field.

What is the matter?

The matter is a material that fills space and has inertia. Modern physics states that matter is made up of several kinds of particles, each of which has a mass and size.

The electron, proton, and neutron are three of the most well-known instances of material particles. Atoms are made up of combinations of these particles.

Dark matter is so-called because it doesn't seem to interact with the electromagnetic field.

This means it doesn't generate electromagnetic radiation like light or absorb electromagnetic radiation as it does. As a result, it is hard to detect.

Hence, dark matter and dark energy are described as dark.

To learn more about the matter refer;

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From laboratory measurements, we know that a particular spectral line formed by hydrogen appears at a wavelength of 121.6 nanometers (nm). The spectrum of a particular star shows the same hydrogen line appearing at a wavelength of 121.8 nm. What is the receding speed of the star? c = 3x10^5 km/s

Answers

Answer:

[tex]v=-4.93\times 10^{5}~m/s[/tex] [negative sign denotes that it is moving away]

Explanation:

Actual wavelength of hydrogen spectral lines, [tex]\lambda=121.6~nm[/tex]

Apparent wavelength of hydrogen spectral lines from a star, [tex]\lambda'=121.8~nm[/tex]

So, shift in wavelength:

[tex]\Delta \lambda=\lambda'-\lambda[/tex]

[tex]\Delta \lambda=121.8-121.6[/tex]

[tex]\Delta \lambda=0.2~nm[/tex]

Using Doppler's shift:

[tex]\frac{\Delta \lambda}{\lambda} =-\frac{v}{c}[/tex]

[tex]\frac{0.2}{121.6} =-\frac{v}{3\times 10^8}[/tex]

[tex]v=-4.93\times 10^{5}~m/s[/tex] [negative sign denotes that it is moving away]

While traveling north on an expressway, a car traveling 60 mph (miles per hour) slows down to 30 mph in 12 minutes due to traffic conditions

Answers

Answer:

acceleration = - 150 m/s^2

distance = 9 miles.

Explanation:

initial speed, u = 60 mph

time, t = 12minutes = 0.2 hour

final speed, v = 30 mph

Let the acceleration is a and the distance is s.

By the first equation of motion

v = u + at

30 = 60 + a x 0.2

a = - 150 m/s^2

Let the distance is s.

Use third equation of motion is

[tex]v^2 = u^2 + 2 a s \\\\30^2 = 60^2 + 2 \times 150\times s\\\\s = 9 miles[/tex]

asset question.....only answers otherwise u will be reported ​

Answers

Answer:

C. 24 hrs

Explanation:

it takes the earth 24 hrs to make one full revolution.

To leave the gravitational pull of the Earth, and explore other planets, satellites must have at least:

Answers

Answer:

To explore the other planets, the satellite must have the velocity more than the escape velocity.

Explanation:

The minimum velocity required by any object to escape from the earth gravitational pull is called the escape velocity.

The escape velocity for any planet depends on the mass of planet and radius of planet. It does not depends on the mass of object. The escape velocity is same for any mass for a particular planet.

So, to explore the other planets, the satellite must have the velocity more than the escape velocity.

6. An object is fired from the gound at 275 m/s at an angle of 55° N of E.
a. How far away did the object first hit the ground?
b. what is the maximum height that the object reaches? ​

Answers

there u go fella hope u understood



The ability of a metal to react with air and water is a
property.
O chemical, physical, respectively
O physical, chemical, respectively
o physical, physical, respectively
O chemical, chemical, respectively

Answers

[tex]\bold{{Answer}}[/tex]

O physical, chemical, respectively

please buddy correct me if im wrong

The ability of a metal to react with air and water is a  chemical, chemical, respectively property

What is a chemical change?

A chemical change occur when the substance's composition is changed or when bonds are broken and new ones are forms a chemical change occur .

When a metal burn in air or react with air it form metal oxide and when metal react with water it forms oxides or hydroxides and release hydrogen gas . In both the cases change in composition is taking place . hence , bot are chemical reactions

correct answer is O chemical, chemical, respectively

learn more about chemical change

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Which component of weight is cause for S.H.M of bob simple pendulum

Answers

Explanation:

The Simple Pendulum. A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass ((Figure)). Here, the only forces acting on the bob are the force of gravity (i.e., the weight of the bob) and tension from the string.

hope it helps you


If voltage , V = 100 + 6 volt and current , I = 10+ 0.2 A , then find
percentage error in R.

Answers

Explanation:

As we know, resistance is the ratio of voltage used and current flowing through the circuit. So,

R = V/I

By error calculation

∆R/R = [(∆V/V)100] + [(∆I/I)100]

V = 100 ± 6% V

I = 10 ± 0.2% A

∆R/R= (5/100)×100 + (0.2/10)×100

∆R/R=5+2=7%

So, percentage error in resistance (R) = ± 7%.

Answer:

Percentage error of R is ±7%

What is the name of the part of the wave that is labeled -
answer: amplitude

the ones who have to watch the video

Answers

Answer:

amplitude

Explanation:

sound travel and it amplifies

What is the magnitude of the electric field at a point 0.0055 m from a 0.0025
C charge?
kg
Use E = and k=9.00 x 10 N.m²/C2.
O A. 7.4 x 1011 N
O B. 2.0 x 1010 N
O C. 4.1 x 10°N
OD. 7.9 x 1012 N

Answers

Answer:

Explanation:

The equation for the electric field is

[tex]E=\frac{kQ}{r^2}[/tex] so filling in:

[tex]E=\frac{9.00*10^9(.0025)}{(.0055)^2}[/tex] which in the end gives you

E = 7.4 × 10¹¹, choice A

convert the following as instructed
67 kg into gram
explain step by step
please reply quickly its urgent​

Answers

Answer:

1kg = 1000g

67kg therefore would be equal to

67 x 1000 = 67,000g = 6.7 x 10⁴g.

a car is travelling at 36 km per hour if its velocity increases to 72 km per hour in 5 seconds then find the acceleration of car in SI unit

Answers

Answer:

36 km /h means 10 m/s. Increase in speed is 10m/s in 5 s . Acceleration is ( 10/5 ) = 2 m/s^ 2.

a= 2m/s²

Explanation:

U=36km/h

V=72km/h

T=5s

Conversion of Km to m and H to s

1km = 1000m

36km=36×1000 = 36000m

1H = 3600s

For U, 36000/3600

=10m/s

For V,

72km= 72×1000 =72000

72000/3600

20m/s

a=(V-U)/T

a=(20-10)/5

a= 10/5

a= 2m/s²

If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.8 ss , how far do you travel during this inattentive period

Answers

Answer:

Distance = 70 meters

Explanation:

Given the following data;

Speed = 90 km/h

Time = 2.8 seconds

Conversion:

90 km/h to meters per seconds = 90 * 1000/3600 = 90000/3600 = 25 m/s

To find the distance covered during this inattentive period;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex] Distance = speed * time [/tex]

Substituting into the above formula, we have;

[tex] Distance = 25 * 2.8 [/tex]

Distance = 70 meters

Two students with masses of 40kg and 32 kg are sitting 22 m apart. What is the gravitational force of attraction between them?

Answers

I get 1.76 x 10^-10 Newton.

That's 0.000 000 000 176 Newton

Which is about 0.000 000 000 635 ounce of force pulling them together.

That's why we never notice it.

Two identical metallic sphere having unequal opposite charges are are placed
distance of 0.05m apart in air.
After bringing them in contact
with each other, they are again placed at the same distance apart, now the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.​

Answers

Answer:

Let the initial charges be q1 and q2 respectively.

After they come in contact, the charges are rearranged such that they acquire same charge.

let us say that charge on each of them is Q.

They are again brought apart at a distance of 0.9 m. Hence, the force between them will be given as

F = kQ2 / r2

0.025 = (9×109 x Q2) / 0.92

Q2 = 0.025 x 0.92 / 9×109

Q = 1.5 x 10-6 C

Explanation:

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Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s2 during

Answers

Complete question is;

Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s² during one of the running portions, what is her final velocity at the end of the 100.0 m? Round your answer to the nearest tenth.

Answer:

6.5 m/s

Explanation:

We are told that she is walking at 1.4 m/s and accelerates at 0.20 m/s².

Thus;

Initial velocity; u = 1.4 m/s

Acceleration; a = 0.2 m/s²

Distance; s = 100 m

From Newton's equation of motion, we know that;

v² = u² + 2as

Where v is final velocity.

Thus;

v² = 1.4² + 2(0.2 × 100)

v² = 41.96

v = √41.96

v ≈ 6.5 m/s

what is the angular speed w of the system immediately after the collision in terms f the sstem parameters and I

Answers

Answer: hello some part of your question is missing attached below is the missing detail

answer :

wf = M( v cos∅ )D / I

Explanation:

The Angular speed wf  of the system after collision in terms of the system parameters  and I can be expressed as

considering angular momentum conservation

Li = Lf

M( v cos∅ ) D = ( ML^2 / 3  + mD^2 ) wf

where ;  ( ML^2 / 3  + mD^2 ) = I ( Inertia )

In terms of system parameters and I

wf = M( v cos∅ )D / I

The force that the left team pulls with is 1000 N. If the right team's total mass is 300 kg and they accelerate by 1.2 m/s2, what is the force of resistance on the right team

Answers

Answer:

the force of resistance on the right team is 360 N

Explanation:

Given;

force of the left team, = 1000 N

total mass of the right team, m = 300 kg

acceleration of the right team, a = 1.2 m/s²

The force of resistance of the right team is calculated as;

Force = mass x acceleration

Force, F = 300 x 1.2

Force = 360 N

Therefore, the force of resistance on the right team is 360 N

What is the enthalpy change, AH, for this reaction? Show your work to receive full credit. URGENT PICTURE INCLUDED !!!

Answers

Answer:

150 kJ

Explanation:

Applying,

ΔH = Energy level of Product(E') - Energy level of reactant(E)

Where ΔH = enthalpy change, E' and E = energy level of the product and the reactant respectively

ΔH = E'-E............. Equation 1

From the diagram,

Given: E' = 200 kJ, E = 50 kJ

Substitute these values into equation 1

ΔH = 200-50

ΔH = 150 kJ

Hence the enthalpy change for the reaction is 150 kJ

1. A plane flying a triangular patter flies 150 km[N], then 400 km(E). What is the total displacement of the
plane after these two legs? {4}
2. Ken and Susie are standing together. Ken walks 10 m (N) and then 15 m [W]. Susie walks 25 m [E] and
then 30 m [S]. What is the displacement from Ken to Susie? {5}
3. Students are performing an experiment for their physics class and are testing their predictions for
projectile motion. They set up a system so that a beanbag is launched horizontally off one of their
desks with an initial speed of 4.2 m/s. They measure the height of the desk to be 1.3 m.
a. What is the time of flight for the beanbag? {3}
b. What is the range for the beanbag? {2}
4. A historical society is testing an old cannon on the top of an old fort that has rusted and can only be
fired horizontally. They perform a few test fires of the cannon and measure the time of flight to be
3.78 s. How high is the hill? {3}

Answers

Answer:

1. The displacement is 427.2 km.

Explanation:

1. A = 150 km North

B = 400 km East

The net displacement is given by

[tex]R =\sqrt{400^2 + 150^2 }\\\\R = 427.2 km[/tex]

A uniform meter rule of mass 10g is balanced on a knife edge placed at 45cm mark. Calculate the distance of a mass 25g from the pivot

Answers

Answer:

2 cm.

Explanation:

Please see attached photo for diagram.

In the attached photo, y is the distance from the pivot to which the 25 g is placed.

The value of y can be obtained as follow:

Clockwise moment = 5 × 10

Anticlock wise moment = y × 25

Anticlock wise moment = Clockwise moment

y × 25 = 5 × 10

y × 25 = 50

Divide both side by 25

y = 50/25

y = 2 cm

Thus, the distance is 2 cm

A bicycle and a car start their journey at the same time the cyclist reaches it's top speed of 10mls in 15 the car reaches a speed if 15 MLS in55 which has the greater acceleration the car or the bicycle

Answers

Complete question is;

A bicycle and a car start their journey at the same time the cyclist reaches it's top speed of 10m/s in 15 s, the car reaches a speed of 15 m/s in 55 s. which has the greater acceleration the car or the bicycle.

Answer:

The bicycle has the greater acceleration.

Explanation:

Cyclist reaches a top speed of 10m/s in 15 s.

Formula for acceleration here is;

a = v/t

a = 10/15

a = 0.67 m/s²

Car reaches a speed of 15 m/s in 55 s.

Thus;

a = 15/55

a = 0.27 m/s²

From the 2 acceleration values gotten, we can say that;

The bicycle has the greater acceleration.

The search for black holes involves searching for The search for black holes involves searching for Group of answer choices single stars that emit large amounts of X-rays. a stellar core greater than 3 solar masses large spherical regions from which no light is detected. pulsars with periods less than one millisecond. pulsars that are orbited by planets.

Answers

Answer:

Large spherical regions from which no light is detected

Explanation:

A black hole is an object that has an extremely high density such that it possesses very powerful gravitational force that prevents the escape of all objects including light from it, and consumes nearby objects.

Due to the power of the gravitational force of a black hole, at the center, objects are infinitesimally compressed resulting in the inapplicability of the concept of space and time and the location is known as a singularity

Therefore, the search for black holes involves searching for large spherical regions from which no light is detected.

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