If the m<5 = 63 degrees, find the measure of <3
Answer: 117?
Step-by-step explanation:
h(t)= (t+3)^2 + 5
What is the average rate of change of h over the interval -5 < t < -1?
Answer:
The average rate of change for the given function in the interval (-5, -1) is 0 (zero)
Step-by-step explanation:
The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:
the average rte of change of h(t) in the interval (-5, -1) is:
[tex]\frac{h(-1)-h(-5)}{-1+5}[/tex]
so we find:
[tex]h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9[/tex]
then the average rate of change becomes:
[tex]\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0[/tex]
Please help :)
If X +9 equals 13, what is the value of X?
Solution:
x+9=13
then,
13-9=4
so the value of x is 4
Answer:
X= 4Step-by-step explanation:
X +9 equals 13
X+9 =13
X=13 - 9
X= 4
[tex]hope \: this \: helps[/tex]
[tex]have \: a \: nice \: life! :) [/tex]
Practice Sum
If y is inversely proportional to x and y=4 when x=3
i) Express y in terms of X
ii) Find the value of y when x=6
Answer:
I) y = 1/x
ii) y = 1/6
Step-by-step explanation:
inversely proportional just means that the right hand side is the inverse of the left hand side of an equation.
I'VE BEEN STUCK ON THIS .... Find the volume of this triangular pyramid Volume = 1/3(Area of Base)(Height) Enter only the numerical part of your answer in cubic units.
Answer:
[tex]96ft^{3}[/tex]
Step-by-step explanation:
Step 1: Find area of base
[tex]\frac{bh}{2}=\frac{(6)(8)}{2} =\frac{48}{2}=24ft^{2}[/tex]
Step 2: Find Volume
[tex]V=\frac{1}{3} (24)12\\V=\frac{1}{3} (288)\\V=96ft^{3}[/tex]
Therefore the volume of the triangular pyramid is [tex]96ft^{3}[/tex]
The volume of the triangular pyramid will be 96 cubic feet.
What is the volume of the pyramid?Let h be the height of the pyramid, l be the slant height and A be the base area of the pyramid.
Then the volume of the pyramid will be
Volume = (1/3) × A × h
The base area of the triangular pyramid is calculated as,
A = 1/2 x 6 x 8
A = 3 x 8
A = 24 square feet
Then the volume of the triangular pyramid is calculated as,
V = 1/3 x 24 x 12
V = 8 x 12
V = 96 cubic feet
The volume of the triangular pyramid will be 96 cubic feet.
More about the volume of the pyramid link is given below.
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PLEASE HELP, I DONT UNDERSTAND THIS.....Michael is laying carpet in a perfectly rectangular hall. The area of the hall is 240 square feet, and the width of the hall is 6 feet. How long is the hall?
Answer:
40 feet
Step-by-step explanation:
We know that the area of a rectangle is represented as [tex]lw=a[/tex], where l is the length and w is the width.
We already know the width, and we know the area, so we can plug these values into the equation.
[tex]l\cdot 6 = 240[/tex]
Our goal is to now isolate the variable l, and to do this we can divide both sides by 6.
[tex](l\cdot6) \div6 = 240\div6\\\\l = 40[/tex]
Hope this helped!
Answer:
l=a/w
Step-by-step explanation:
Length equals area divided by width.
is -5.5 a rational number?
what is the answer to 3x + 7x − 2
Answer:
Step-by-step explanation:
Add like terms. 3x & 7x are like terms
3x +7x - 2 = 10x - 2
Answer:
0.2
Step-by-step explanation:
3x+7x-2
3x+7x-2=0
3x+7x=2
10x=2
x=2/10
x=[tex]\frac{1}{5}[/tex]
Can someone please help me
Answer:
never
Step-by-step explanation:
smith will run out by week 2
Answer:
After 17 weeks
Step-by-step explanation:
We can create a system of equations for this problem, where y is the total amount of money in their banks and x is the amount of weeks passed.
Mr. Smith's equation will be [tex]y = 12x+21[/tex].
Mr. Brown's equation will be [tex]y = 10x+55[/tex].
We can now solve for x by using substitution.
Let's substitute Mr. Brown's equation into Mr. Smith's equation.
This get us [tex]10x + 55 = 12x + 21[/tex].
We can now solve for x.
Let's subtract 12x from both sides:
[tex]-2x + 55 = 21[/tex]
And now let's subtract 21 from both sides:
[tex]-2x+34=0[/tex]
Now we subtract 34 from both sides:
[tex]-2x=-34[/tex]
And divide both sides by -2.
[tex]x=17[/tex]
Hope this helped!
Red kangaroos can reach speeds up to 50 feet per second. Use the linear graph at the left to answer the questions. What is the change in y-values from Point A to Point B? What is the change in x-values from Point A to Point B? What is the rate of change of the linear function? feet per second
Answer:
What is the change in y-values from
Point A to Point B?
50
What is the change in x-values from
Point A to Point B?
1
What is the rate of change of the linear function?
50
feet per second
Step-by-step explanation:
The change in y-values from Point A to Point B is from 0 to 50feet. What is the change in x-values from Point A to Point B is 0 to 1 second. Rate of change of the linear function is given by y = 50x (feet per second).
What is linear function?" Linear function is defined as the algebraic expression which represents the relation between the variables with highest exponent equals to 1."
Formula used
[tex]\frac{y-y_{1} }{x-x_{1} } =\frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]
According to the question,
Given,
Speed of Red kangaroos can reach = 50 feet per second
Number of feet represent by y - axis
Time represent by x-axis
When
[tex]x_{1} = 0 seconds \\\\y_{1} = 0 feet[/tex]
When
[tex]x_{2} = 1 seconds \\\\y_{2} = 50 feet[/tex]
Change in y-values from point A to B is given by [tex](y_{1}, y_{2} ) = (0,50)[/tex]
Change in x-values from point A to B is given by [tex](x_{1}, x_{2} ) = (0,1)[/tex]
Rate of change of the linear function
[tex]\frac{y-0 }{x-0 } =\frac{50-0}{1-0}[/tex]
⇒[tex]y= 50x[/tex]
Hence, the change in y-values from Point A to Point B is from 0 to 50feet. What is the change in x-values from Point A to Point B is 0 to 1 second. Rate of change of the linear function is given by y = 50x (feet per second).
Learn more about linear function here
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What is the midpoint of AB
Answer:
4
Step-by-step explanation: midpoint means between so from 1 to b the midpoint is 4
Which set of points does NOT represent a function?
A) (-2, 1), (6,3), (5, 1), (-4,6)
B) (-7,3), (1, 2), (5,3), (-7,2)
C) (-4,-3), (-1, 2), (0,5), (3, 2)
D) (-5, -1), (-2, -1), (1, -1), (4, -1)
Answer:
B.
Step-by-step explanation:
The X-Values cannot repeat in a function.
Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2
Answer:
(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
Step-by-step explanation:
Un par ordenado es un elemento de la forma [tex](x,f(x))[/tex], donde [tex]x[/tex] es un elemento del dominio de la función, mientras [tex]f(x)[/tex] es la imagen de la función evaluada en [tex]x[/tex]. Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:
La imagen de la función existe para un elemento dado del dominio. Esto es:
[tex]x \rightarrow f(x)[/tex]
Dado que [tex]f(x)[/tex] es una función polinómica, existe una imagen para todo elemento [tex]x[/tex]. Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:
x = 0
[tex]f(0) = 0^{3}-2\cdot (0)^{2}-2[/tex]
[tex]f(0) = -2[/tex]
(0, -2) es un par ordenado de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
x = 1
[tex]f(1) = 1^{3}-2\cdot (1)^{2}-2[/tex]
[tex]f(1) = -3[/tex]
(1, -3) es un par ordenado de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
x = 2
[tex]f(2) = 2^{3}-2\cdot (2)^{2}-2[/tex]
[tex]f(2) = -2[/tex]
(2, -2) es un par ordenado de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
x = 3
[tex]f(3) = 3^{3}-2\cdot (3)^{2}-2[/tex]
[tex]f(3) = 7[/tex]
(3, 7) es un par ordenado de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de [tex]f(x) = x^{3}-2\cdot x^{2}-2[/tex].
A slot machine has three slots; each will show a cherry, a lemon, a star, or a bar when spun. The player wins if all three slots show the same three items. a. How many simple events are in the sample space
please help with this question
Answer:
B
Step-by-step explanation:
Any number, regardless of its sign, raised to an even power will always be positive. Therefore, a⁷² will be positive. We know that -3/7 is negative, and since a positive times a negative is negative, the answer will be negative.
[tex] \sqrt{500} [/tex]
what the answer ?
f(x) = x2 -2x & g(x) = 12-8x.
Find f(2) - g(3)
=========================================
Work Shown:
f(x) = x^2 - 2x
f(2) = 2^2 - 2*2 ... replace every x with 2
f(2) = 4 - 4
f(2) = 0
----------------------------
g(x) = 12-8x
g(3) = 12-8*3 ... replace every x with 3
g(3) = 12-24
g(3) = -24
----------------------------
Subtract the results of the previous two sections
f(2) - g(3) = 0 - (-24)
f(2) - g(3) = 0 + 24
f(2) - g(3) = 24
HELP ASAP WILL MARK BRAINLIEST!!!!! The coordinates of point T are (0,3). The midpoint ST of is (1,-5). Find the coordinates of point S. The other endpoint is
Greetings from Brasil...
See the attached chart. The midpoint, M, has 8 units down on the Y axis. So the other half will also have 8 units after that point M. This is also true for the X axis.
Just make the difference between points T and M. For M and S they are the same quantities.
(0; 3) and (1; -5)
X: 1 - 0 = 1 (one unit until mid point)
Y: - 5 - 3 = - 8 (8 units until mid point)
To S:
S(W; Z) M = center point coordinate value
W = M + 1 ⇒ W = 1 + 1 = 2
Z = M - 8 ⇒ Z = - 5 - 8 = - 13
S(2; -13)2(x-4)+2x=-6x-2 what is the solution
Step-by-step explanation:
hi the answer is x= 3/5
i have added 2 methods of solving it in the above picture. ask me if you have any questions
Answer:
x = 3/5
Step-by-step explanation:
This equation can be solved with algebraic techniques. We will simplify the equation by combining like terms and then use algebraic techniques in order to solve for x.
2(x - 4) + 2x = -6x - 2 Use the distributive property.
2x - 8 + 2x = -6x - 2 Combine like terms (variable terms first).
4x - 8 = -6x - 2 Add 6x to both sides of the equation.
10x - 8 = -2 Add 8 to both sides of the equation.
10x = 6 Divide by 10 on both sides of the equation.
x = 6/10 Simplify the fraction.
x = 3/5
A road perpendicular to a highway leads to a farmhouse located 2 km away. A car travels pastthe farmhouse on on the highway at a speed of 80 km/h. How fast is the distance between thecar and the farmhouse increasing when the car is 6 km past the intersection of the highwayand the road
Answer:
75.9 km/hr
Step-by-step explanation:
Distance between the highway and farmhouse is given as = 2km = a
The distance after the intersection and the highway = b
Let the distance between the farmhouse and the car = c
Using the Pythagoras Theorem rule
c² = a² + b²
c² = 2² + b²
Step 1
Since distance is involved, time is required. Hence, we differentiate the equation above in respect to time
c² = 2² + b²
dc/dt (2c) = 4 + 2b
dc/dt =[ b/(√b² + 4)] × db/dt
We are told in the question that:
the car travels past the farmhouse on on the highway at a speed of 80 km/h.
We are asked to calculate the speed at which the distance between the car and the farmhouse kept increasing when the car is 6 km past the intersection of the highway and the road.
This calculated using the obtained differentiation above:
dc/dt = [ b/(√b² + 4)] × db/dt
Where b = 6km
db/dt = 80km/hr
[6/(√6² + 4)] × 80km/hr
6/√36 + 4 × 80km/hr
6 × 80/√40
480/√40
= 75.894663844km/hr
Approximately = 75.9km/hr
In this exercise we want to calculate the speed of the vehicle to reach the farm, in this way we will find a speed of approximately:
[tex]75.9 km/hr[/tex]
To start this exercise we have to use some data informed in the text, like this:
Distance: [tex]a=2km[/tex] Distance after the intersection and the highway: [tex]b[/tex] Distance between the farmhouse and the car: [tex]c[/tex] Pythagoras Theorem rule: [tex]c^2 = a^2 + b^2[/tex]
Since distance is involved, time is required. Hence, we differentiate the equation above in respect to time
[tex]c^2 = 2^2 + b^2\\\frac{dc}{dt} (2c) = 4 + 2b\\\frac{dc}{dt} =[ b/(\sqrt{b^2} + 4)] ( \frac{db}{dt})[/tex]
Calculate the speed at which the distance between the car and the farmhouse kept increasing when the car is 6 km past the intersection of the highway and the road. This calculated using the obtained differentiation above:
[tex]\frac{dc}{dt} = [ 6/(\sqrt{6^2} + 4)] (80)\\=6/\sqrt{36} + 4 * 80\\=6 * 80/\sqrt{40} \\=480/\sqrt{40} \\= 75.9km/hr[/tex]
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PLEASE HELP The y-intercept of the equation y = 12x - 8 is 8. True False
Answer: False!
This equation is in slope - intercept form, where y = mx + b. B is the y - intercept and m is the slope. They got the location of the y - intercept right, but they forgot to add the negative. It's actually -8.
Hope this helps!
The y-intercept is -8 as the minus always stays with the number to the right of it
The square root of 75 is_____ (round to the hundredths place if necessary)
Can someone please help me, I've been stuck on this since yesterday. Thanks!
Answer:
Since there are no common factors, the only common factor for [tex]\frac{4}{x+5}[/tex] is 1
Find the values for k so that the intersection of x = 2k and 3x + 2y = 12 lies in the first quadrant.
Answer:
0 < k < 2
Step-by-step explanation:
In the first quadrant both of x and y get positive values, so
x > 0 and y > 0x = 2k, k > 0And replacing x with 2k in the second equation:
3x + 2y = 123*2k + 2y = 122y= 12 - 6ky = 6 - 3kSince y > 0:
6 - 3k> 02 - k > 0k < 2Combining both k > 0 and k < 2, we get:
0 < k < 2Answer:
0 < k < 2
Step-by-step explanation:
The intersection will lie in the first quadrant when the solution has the characteristics: x > 0, y > 0.
For x > 0, we require ...
x = 2k
x > 0
2k > 0 . . . . substitute for x
k > 0 . . . . . divide by 2
__
For y > 0, we require ...
y = (12 -3x)/2
y = (12 -3(2k))/2 = 6 -3k . . . . . substituted for x and simplify
y > 0
6 -3k > 0 . . . . . . substitute for y
2 -k > 0 . . . . . . . divide by 3
k < 2 . . . . . . . . . add k
So, the values of k that result in the intersection being in the first quadrant are ...
0 < k < 2
distance between (-1,4) and (1,-1
Answer:
√29 units
Step-by-step explanation:
Find the distance between (-1,4) and (1,-1).
We'll use the Pythagorean Theorem:
The horizontal distance between the two points is 1 - (-1), or 2, and the vertical distance is 4 - (-1), or 5.
Thus, the distance squared is 2^2 + 5^2, or 29, and the distance between the two points is therefore
d = √29 units
Please help I need to them all
Answer:
Step-by-step explanation:
1). 6x + 7 - 18x + 4
= (6x - 18x) + (7 + 4)
= -12x + 11
2). 5x - 7x + 5x + 4 - 9
= (5x + 5x - 7x) + (4 - 9)
= 3x - 5
3). 3x + 8y - 5x + 3y
= (3x - 5x) + (8y + 3y)
= -2x + 11y
4). 17x² - 7x²- 5x + 3x + 14
= (17x² - 7x²) + (-5x + 3x) + 14
= 10x² - 2x + 14
5). 3xy - 9xy - 5x + 4x - 7 + 3
= (3xy - 9xy) + (-5x + 4x) + (-7 + 3)
= -6xy - x - 4
6). 9x + 7y - 15x + 4x - 9y
= (9x - 15x + 4x) + (7y - 9y)
= -2x - 2y
7). 3x + 7 - 5x - 8y + 4x - 2y + 7
= (3x - 5x + 4x) + (-8y - 2y) + 14
= 2x - 10y + 14
8). 3xy - xy + 15x + 4 - 11
= (3xy - xy) + 15x + (4 - 11)
= 2xy + 15x - 7
9). -8x + 3x + 7y - 5x + 4y - 2
= (-8x - 5x + 3x) + (7y + 4y) - 2
= -10x + 11y - 2
10). 3x² + 6x - 3y + 2x - 7
= 3x² + (6x + 2x) - 3y - 7
= 3x² + 8x - 3y - 7
What is the value of s?
Answer:
<o=180-132=48
so,<s=24(The angle at the circumference is half of its corresponding angle at center)
reciprocal of x is 0.25, reciprocal of y is 10. work out value of xy
Answer:
xy = [tex]\frac{2}{5}[/tex]
Step-by-step explanation:
Given the reciprocal of x is 0.25, that is [tex]\frac{1}{4}[/tex] then
x = [tex]\frac{1}{\frac{1}{4} }[/tex] = 4
Given the reciprocal of y is 10 then
y = [tex]\frac{1}{10}[/tex]
xy = 4 × [tex]\frac{1}{10}[/tex] = [tex]\frac{4}{10}[/tex] = [tex]\frac{2}{5}[/tex]
Answer:
2/5=0.4
Step-by-step explanation:
[tex]\frac{1}{x}\\[/tex]=0.25 ==> x=4
[tex]\frac{1}{y}\\[/tex]=10 ==> y=1/10
Now multiply both x and y
xy=4(1/10)=2/5=0.4
3. Evaluate at the given value: g(x)=-2x+7, g^-1(-2)
Answer:
[tex]{g}^{ - 1} ( - 2) = \frac{9}{2} [/tex]Step-by-step explanation:
To find g-¹( 2) we must first find g-¹(x)
To find g-¹(x) equate g(x) to y
That's
y = g(x)
We have
y = - 2x + 7
Now interchange the terms that's x becomes y and y becomes x
We have
x = - 2y + 7
Make y the subject in order to find g-¹(x)
Move 7 to the left side of the equation
- 2y = x - 7
Multiply both sides by - 1
We have
2y = 7 - x
Divide both sides by 2 to make y stand alone
That's
[tex]y = \frac{7 - x}{2} [/tex]So we have
[tex]g ^{ - 1} (x) = \frac{7 - x}{2} [/tex]Now to find g-¹(- 2) substitute the value of x that's - 2 into the expression
We have
[tex] {g}^{ - 1} ( - 2) = \frac{7 - - 2}{2} \\ {g}^{ - 1} ( - 2) = \frac{7 + 2}{2} [/tex]We have the final answer as
[tex]{g}^{ - 1} ( - 2) = \frac{9}{2} [/tex]Hope this helps you
Answer:
-10
-12
Step-by-step explanation:
If the ladder is 16 feet long and the window ledge is 12 feet off the ground, how far from
the house is the base of the ladder?
Answer:
10.58 feet
Step-by-step explanation:
Hello!
If you think about how it would look in life you will notice that it looks like a right triangle which means we can use the Pythagorean theorem to find the far the ladder needs to be from the house.
The Pythagorean theorem is [tex]a^{2}+ b^{2}= c^{2}[/tex]
a is a leg
b is the other leg
c is the hypotenuse
Since the ladder has to go from the ground to the window ledge it is the hypotenuse and the window ledge is a leg
Put in what we know
[tex]a^{2} +12^{2} =16^{2}[/tex]
Now we solve for a
Simplify
a^2 + 144 = 256
Subtract 144 from both sides
a^2 = 112
Take the square root of both sides
a = 10.583
The answer is 10.58 feet
Hope this helps!
Answer:
11 ft
Step-by-step explanation:
Try to imagine it or draw it out to help you. The ladder is 16 feet long and the window ledge is 12 feet high, so this is a right triangle.
The ladder is the hypotenuse, so use the given values in the pythagorean theorem.
a^2 + b^2 = c^2
12 + b^2 = 16
b = 11
12^2 + 11^2 = 16^2
1 44 + 121 = 265
√265 = 16