Answer:
d. 8.6 x 10-3 eV
Explanation:
Binding energy is energy that binds two atoms together . Energy is required to separate them . In the process of evaporation , energy is required to separate each molecules/ atoms of liquid so that they are separated and then get evaporated . That is why latent heat of evaporation is required .
1 mole of helium will contain 6.02 x 10²² atoms of it .
binding energy per atom = 84 / 6.02 x 10²² J
= 13.953 x 10⁻²² J
= 13.953 x 10⁻²² / 1.6 x 10⁻¹⁹ eV .
= 8.6 x 10⁻³ eV
The wave function for a particle must be normalizable because:________ a. the particle's angular momentum must be conserved. b. the particle cannot be in two places at the same time. c. the particle must be somewhere. d. the particle's momentum must be conserved. e. the particle's charge must be conserved
Answer:
C the particle must be somewhere.
Explanation:
This is because normalization of wave function means the maximum probability of finding a particle in a region is 1. And a Wave function describes the probability of finding a particle in region. Also Since it is a probability distribution, its integral over all space must be 1, explaining that the probability that the particle is somewhere and thus it must integrate to 1, meaning it must be it must be normalizable
A train is travelling along a straight track at constant velocity from Western Station to Eastern station. The mile markers increase towards the east. A passenger notices that, at mile marker 25, the reading on this stopwatch is 15 minutes, and at mile marker 60, the reading on this stopwatch is 45 minutes. What is the velocity of the train in meters per second
Answer:
Explanation:
Displacement of train = 60 - 25 = 35 mile
= 35 x 1.6 = 56 km
duration of time = 45 - 15 = 30 minutes
= 30 x 60 = 1800 s
velocity of train = displacement / time
= 56 / 1800 = .03111 km /s
= 31.111 m / s
A toy car travels at 5.3 m/s. The car travels a distance of 17.8 m. How long did it
take to travel that distance?
Explanation:
Assuming constant speed:
Distance = speed × time
17.8 m = (5.3 m/s) t
t = 3.36 s
Two identical balls are thrown directly upward, ball A at speed v and ball B at speed 2v, and they feel no air resistance. Which statement about these balls is correct
Answer:
B) Ball B will go four times as high as ball A because it had four times the initial kinetic energy.
Explanation:
The complete question is
Two identical balls are thrown directly upward, ball A at speed v and boll B at speed 2v. and they feel no air resistance. Which statement about these balls is correct? A) Ball B will go twice as high as ball A because it had twice the initial speed. B) Ball B will go four times as high as ball A because it had four times the initial kinetic energy. C) The balls will reach the same height because they have the same mass and the same acceleration. D) At its highest point, ball B will have twice as much gravitational potential energy as ball A because it started out moving twice as fast. E) At their highest point, the acceleration of each ball is instantaneously equal to zero because they stop for an instant.
According to conservation of energy, the mechanical energy of a ball thrown up is equal to the sum of the potential energy and the kinetic energy. At its highest point, all the mechanical energy will be equal to the potential energy. At the instant when it was thrown, all the mechanical energy is proportional to its kinetic energy, which will be proportional to the potential energy at the highest point. Also, potential energy is proportional to the maximum height reached.
We know that the kinetic energy is given as [tex]\frac{1}{2}mv^{2}[/tex]
where
m is the mass of the balls, which is the same for both ball,
and v is the velocity.
We can see that the kinetic energy is proportional to the square of the initial velocity with which the ball is thrown.
For the ball A thrown with velocity v, the kinetic energy is proportional to [tex]v^{2}[/tex],
and for the ball B with velocity 2v, kinetic energy is proportional to [tex]4v^{2}[/tex]
comparing the two, we'll see that the ball B will had 4 times the energy of ball A. Therefore ball B will go four times as high as ball A because it had four times the initial kinetic energy
When landing after a spectacular somersault, a 41 kg gymnast decelerates by pushing straight down on the mat. Calculate the force she must exert if her deceleration is 7.00 times the acceleration due to gravity. Explicitly show how you follow the steps in the Problem-Solving Strategy for Newton's laws of motion.
Answer:
The force the gymnast must exert is 2812.6 N.
Explanation:
Given;
mass of the gymnast, m = 41 kg
her deceleration, -a = 7g = 7 x 9.8m/s² = 68.6 m/s²
Apply Newton's second law of motion;
F = ma
where;
F is the magnitude of the force exerted
m is the mass of the gymnast
a is the deceleration
Substitute in the given values of m and a into the force equation;
F = ma
F = 41 x 68.6
F = 2812.6 N
Therefore, the force the gymnast must exert is 2812.6 N.
plz solve this. plz plz plz plz simple machine
Answer:
Explanation:
i. CW moment = 10 N (10 cm) + 30 N (30 cm) - 60 N (40 cm) = - 1400 N-cm
ii. ACW momenet = 60 N (40 cm) - 10 N (10 cm) + 30 N (30 cm) = 1400 N-cm
iii. No. The lever is not balanced in the situation. Because the moment is ± 1400 N-cm. if balance, the moment must be Zero.
iv. the location of 10N by keeping the other loads unchanged to balance the lever is 150 cm
take moment from Δ (support)
60(40) = 10(x) + 30(30)
2400 = 10x + 900
10x = 2400 - 900
10x = 1500
x = 1500/10
x = 150 cm
therefore, the location of 10N by keeping the other loads unchanged to balance the lever is 150 cm
A uniform disk a uniform hoop and a uniform sphere are released at the same time at the top of an inclined ramp. They all roll without slipping in what order do they reach the bottom of the ramp?
a. disk hoop, sphere
b. sphere, hoop, disk
c. hoop, sphere, disk
d. sphere, disk, hoop
e. hoop, disk, sphere
A positron and an electron annihilate each other upon colliding, thereby producing energy in the form of two gamma rays. Assuming that both gamma rays have the same energy (since both particles have the same mass), calculate the wavelength of the electromagnetic radiation used in pm. (1 pm = 10⁻¹² m; mass of electron (amu) = 0.000549)
Answer:
2.42631E-13m
Explanation:
First we find the mass defect
Which is m= 0-2(9.10939E-33kg)
= - 1.82188E-30kg
Now find the energy
S
E= mc²=( -18.82188E-30)(2.999792E8)²
= 1.63742E-13J
Thus energy per photon will be
1.63742E-13J/2= 8.18710E-14J
So wavelength is given as
Lambda= hc/E
= (6.62608E-34)(2.997E8)/8.18710J
= 2.42631E-13m
The wavelength of radiation used to annihilate a positron and an electron is required.
The wavelength of the electromagnetic radiation used is 2.42 pm.
The mass of positron and electron are equal
m = Mass = [tex]\dfrac{0.000549}{6.022\times 10^{26}}=9.11\times 10^{-31}\ \text{kg}[/tex]
c = Speed of light = [tex]3\times 10^{8}\ \text{m/s}[/tex]
h = Planck's constant = [tex]6.626\times 10^{-34}\ \text{Js}[/tex]
Total energy in the collision is
[tex]E_T=mc^2+mc_2\\\Rightarrow E_T=2mc^2\\\Rightarrow E_T=2\times 9.11\times 10^{-31}\times (3\times 10^{8})^2\ \text{J}[/tex]
Energy released per photon is
[tex]E=\dfrac{E_T}{2}\\\Rightarrow E=\dfrac{2\times 9.11\times 10^{-31}\times (3\times 10^{8})^2}{2}\\\Rightarrow E=9.11\times 10^{-31}\times (3\times 10^{8})^2\ \text{J}[/tex]
Energy is given by
[tex]E=\dfrac{hc}{\lambda}\\\Rightarrow \lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{9.11\times 10^{-31}\times (3\times 10^{8})^2}\\\Rightarrow \lambda=2.42\times 10^{-12}\ \text{m}=2.42\ \text{pm}[/tex]
The wavelength of the electromagnetic radiation used is 2.42 pm.
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What is the main reason why would a fan be expected to warm the air that passes through it? A or B?
A. The fan does work on the air in the room leading to an increase in its thermal energy and temperature.
B.The fan transfers heat to the air in the room leading to an increase in its thermal energy and temperature.
Answer:
A. The fan does work on the air in the room leading to an increase in its thermal energy and temperature.
Explanation:
Fans move fluid, typically a gas, such as air, through a room or an enclosure. A fan consists of a rotating arrangement of vanes or blades (impeller), which acts on the air. The action of the impeller does work on the fan by compressing and moving the air forward, doing work on it in the process. The work done on the fan leads to an increase in the thermal energy of the air.
A diffraction-limited lens can focus light to a 10-μ m-diameter spot on a screen. Do the following actions make the spot diameter larger, smaller, or leave it unchanged? a. Decreasing the wavelength of light: b. Decreasing the lens diameter c. Decreasing the focal length: d. Decreasing the lens-to-screen distance:
Answer:
a) the size of the sport DECREASES , b)the spot size is increased
c) it has no effect and d) spot size DECREASES
Explanation:
The expression for constructive interference in diffraction is
a sin θ = m λ
the chaff of the spot is given by the minimum interference m = 1
a sin θ = λ
let's use trigonometry to find the angle
tan λ= y / L
tan θ = sin θ / cos t = sin θ
sin θ = y / L
a y / L = lam
in the case of materials with circular dome, the problem must result in polar coordinates, with which a numerical constant is introduced
y = 1.22 L / a lam
let's analyze each electrode action in this equation
a) Decrease lam
y ’= 1.22 L / a lm2
lam2 <lamo
y '<y
therefore the size of the sport DECREASES
b) decreases the lens diameter
a '<a
y ’= 1.22 L / a’ lam
y '> y
the spot size is increased
c) Decrease the focal length
The expression does not depend on the focal length, so it has no effect
d) decrease in L
y ’= 1.22 L’ / a lam
spot size DECREASES
An organ pipe open at both ends has two successive harmonics with frequencies of 220 Hz and 240 Hz. What is the length of the pipe? The speed of sound is 343 m/s in air.
Answer:
The value is [tex]l = 8.58 \ m[/tex]
Explanation:
From the question we are told that
The frequencies of two successive harmonics is [tex]f_ a = 220 \ Hz[/tex] , [tex]f_b = 240 \ Hz[/tex]
The speed of sound in the air is [tex]v = 343 \ m/s[/tex]
Generally a harmonic frequency is mathematically represented as
[tex]f_n = \frac{n * v }{2l}[/tex]
here l is the length of the pipe
n is the order of position of the harmonics
Now since we do not know the order of the given harmonic frequencies but we are told that they are successive then the frequencies can be mathematically represented as
[tex]220 = \frac{n * v}{ 2 l }[/tex]
and
[tex]240 = \frac{ (n+1 ) v }{2l}[/tex]
So
[tex]240 - 220 = \frac{ (n+1 ) v }{2l} - \frac{n * v}{ 2 l }[/tex]
[tex]20 = \frac{v}{2l}[/tex]
=> [tex]l = 8.58 \ m[/tex]
When asked how to create an electromagnet, the best answer would be:
"You can create an electromagnet by applying a direct current to a non–magnetic material in order to create an electromagnetic field."
"You can create an electromagnet by covering a wire with insulation and applying a direct electrical current to the magnet."
"You can create an electromagnet by coiling a ferromagnetic material, wrapping in an insulator, and applying a current to the coil."
"You can create an electromagnet by wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current."
Answer:
"You can create an electromagnet by wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current."
Explanation:
An electromagnet is created by coiling a ferromagnetic material with the help of an insulated wire around it and applying a current . Insulated wire carrying current produces magnetic field around it . This field produces magnetic flux in the magnetic material and makes it magnet . When we switch of current , magnetic field ceases to exist and therefore , magnetic material ceases to be a magnet .
Explanation:
Friction: During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the puck and the ice
Answer:
The value is [tex]\mu_k = 0.102 0[/tex]
Explanation:
From the question we are told that
The initial speed is [tex]u = 10 \ m/s[/tex]
The distance traveled is [tex]d = 50 \ m[/tex]
Generally we can obtain the acceleration using the kinetic equation as follows
[tex]v^2 = u^2 + 2as[/tex]
=> [tex]a = \frac{v^2 - u^2 }{ 2s}[/tex]
=> [tex]a = \frac{0^2 - 10^2 }{ 2 * 50 }[/tex]
=> [tex]a = -1 m/s^2[/tex]
The negative sign shows that the pluck is decelerating
The force driving the pluck is mathematically evaluated as
[tex]F = ma[/tex]
This force is also equivalent to the frictional force acting on the pluck
So
[tex]ma = m * g* \mu_k[/tex]
=> [tex]\mu_k = \frac{a}{g}[/tex]
=> [tex]\mu_k = \frac{1}{9.8 }[/tex]
=> [tex]\mu_k = 0.102 0[/tex]
Mass on a Spring: A 0.150-kg air track cart is attached to an ideal spring with a force constant (spring constant) of 3.58 N/m and undergoes simple harmonic oscillations. What is the period of the oscillations
Answer:
The period is [tex]T = 1.286 \ s[/tex]
Explanation:
From the question we are told that
The mass of the spring is [tex]m = 0.150 \ kg[/tex]
The spring constant is [tex]k = 3.58 \ N/m[/tex]
Generally the period is mathematically represented as
[tex]T = 2 \pi \sqrt{ \frac{m}{k} }[/tex]
substituting values
[tex]T = 2 \pi \sqrt{ \frac{ 0.150}{3.58} }[/tex]
[tex]T = 1.286 \ s[/tex]
A bar of silicon is 4 cm long with a circular cross section. If the resistance of the bar is 280 Ω at room temperature, what is the cross-sectional radius of the bar?
Answer:
r = 17.05 cm
Explanation:
Given that,
Length of silicon bar is 4 cm or 0.04 m
Resistance of the bar is 280 ohms
We know that the resistivity of the silicon is 640 Ωm
We need to find the cross-sectional radius of the bar. Let it is r.
Using definition of resistance of an object. It is given by :
[tex]R=\rho\dfrac{l}{A}[/tex]
A is area of bar, A = πr²
So,
[tex]R=\rho\dfrac{l}{\pi r^2}\\\\r^2=\dfrac{\rho l}{R\pi}\\\\r^2=\dfrac{640\times 0.04}{280\pi}\\\\r=0.1705\ m\\\\r=17.05\ cm[/tex]
So, the cross-sectional radius of the bar is 17.05 cm.
which of the following graphs shows the motion of an object that starts to travel forward, stops for several seconds, and then returns to its original position
Answer:
B
Explanation:
in graph B, you can see that the position increases and remains constant for a while before returning to 0
Train A is moving at 100 kmh–1 through a station. Train B is also travelling at 100 kmh–1 through the station but in the opposite direction to train A. What is the speed of a seated passenger on? (a) train A relative to an observer on the station? (b) train A relative to another seated passenger on the same train? (c) train B relative to a passenger on train A?
Explanation:
(a) An observer on the station has a speed of 0 km/h. The speed of a passenger on Train A is 100 km/h. The relative speed is 100 km/h − 0 km/h = 100 km/h.
(b) The speed of both passengers is 100 km/h, in the same direction. The relative speed is 100 km/h − 100 km/h = 0 km/h.
(c) The speed of both passengers is 100 km/h, in opposite directions. The relative speed is 100 km/h − (-100 km/h) = 200 km/h.
Two cars collide head on while each is traveling at 60km/h .Suppose all their kinetic energy is transformed into the thermal energy of the wrecks. What is the temperature increase of each car?You can assume that each car's specific heat is that of iron.
Answer:
The temperature rise [tex]\Delta T = 0.3088 \ ^oC[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 60 \ km /h = 16.67 \ m/s[/tex]
Generally according to the law of energy conservation we have that
The kinetic energy = increase in the internal energy of the car
i,e [tex]\frac{1}{2} * m * v^2 = m * c_p * \Delta T[/tex]
Here [tex]c_p[/tex] of iron is [tex]c_p = 450 \ J/kg K[/tex]
So
[tex]0.5 * 16.67^2 = 450 * \Delta T[/tex]
=> [tex]\Delta T = 0.3088 \ ^oC[/tex]
The temperature increase of each car will be 0.3088 °C.
What is temperature?Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.
The given data in the problem is;
v is the velocity= 60 km/h=16.67 m/sec
ΔT is the temperature difference=?
[tex]\rm c_P[/tex] is the specific heat of iron=450 J/KgK
From the law of energy conservation of the energy, the kinetic energy is equal to the increase in the internal energy of the car.
[tex]\rm KE=\triangle E \\\\\ \frac{1}{2} mv^2=mc_p \triangle T \\\\ \triangle T=\frac{v^2}{2C_p} \\\\\ \triangle T=\frac{(16.67)^2}{2\times 450} \\\\ \triangle T=0.3088 ^0\C[/tex]
Hence the temperature increase of each car will be 0.3088 °C.
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What is the power in a circuit that has a current of 12 amps and a resistance of 100 ohms? a. 14,400 watts b. 8.3 watts c. 144 watts d. 1200 watts
Answer:
a. 14,400 Watts
Explanation:
Power is current times voltage.
P = IV
Voltage is current times resistance.
V = IR
Substitute:
P = I²R
P = (12 A)² (100 Ω)
P = 14,400 W
If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball? (a) The net force on the ball is directed upward. (b) The net force on the ball is zero. (c) The gravitational force is greater than the drag. (d) The drag is greater than the gravitational force.
Answer:
The net force on the ball is zero.
Explanation:
The net force and the acceleration on the falling skydiver is upward. An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down. As the speed decreases, the amount of air resistance also decreases until once more the skydiver reaches a terminal velocity.A force can cause a resting object, or it can accelerate a moving object by changing the object's speed or direction. When the forces on an object are balanced, the net force is zero and there is no change in the object's motion. When an unbalanced force acts on an object, the object accelerates.
You throw a balloon that floats in the air with a velocity of 2 m / s south . If the wind speed is 5 m / s west , how far south will the balloon travel after 2 seconds ?
Answer:
The distance traveled by the balloon is 10.77 m
Explanation:
velocity of the ball, [tex]v_b[/tex] = 2 m/s south
velocity of the air, [tex]v_a[/tex] = 5 m/s west
To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.
| 2m/s
|
|
↓
5m/s ←------------------
the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.
R² = 5² + 2²
R² = 29
R = √29
R = 5.385 m/s
The distance traveled by the balloon is calculated as;
d = R x t
where;
t is time of the motion = 2 seconds
d = 5.385 x 2
d = 10.77 m
Therefore, the distance traveled by the balloon is 10.77 m.
Which of these particles are equal in number when an atom is neutral?
A. protons, neutrons
B. protons, electrons
C. neutrons, electrons
D. protons, neutrons, electrons
A paper pinwheel is spinning in the wind. Which statement is correct about the forces responsible for the rotation?
A paper pinwheel is spinning in the wind.
Which statement is correct about the forces responsible for the rotation?
The components of gravity and the force of wind that point through the pivot are responsible for the rotation.
Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.
Only the perpendicular component of gravity is responsible for the rotation, because wind points toward the pivot.
The perpendicular components of gravity and the force of wind are responsible for the rotation.
Answer:
Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.
Explanation:
A pinwheel is a plaything that is made up of paper that is designed to spin when the wind comes in contact with it. The paper is held fast to its axle by a pin which enables it to spin.
Therefore, if the pinwheel is spun anti-clockwise, it brings electrical energy, converting the wind energy and only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.
In a double slit experiment, the intensity of light at the center of the central bright fringe is measured to be 6.2 µW/m2. What is the intensity half
Answer:
I_FWHW = 3.2 μW / m²
Explanation:
In the analysis of optics and electricity a very useful magnitude is the width at half height (FWHW) and the intensity at this height, which is given by
I_FWHW = I₀ / 2
corresponds to the width of the line for this intensity.
In this case they give the maximum intensity for which
I_FWHW = 6.2 / 2
I_FWHW = 3.2 μW / m²
You do not give more data in your exercise, but the most interesting calculation is to find the angle values for which you have this intensity since it is this range is 50% of the energy of the system, have I write the equation for this calculation
I = Io cos² x₁ (sin x / x)²
x₁ = π d sin θ /λ
x = π b sin θ /λ
where d is the separation of the slits and b the width of each slit
Ball A is dropped from the top of a building. At the same instant ball B is thrown vertically upwards from the ground. When the balls collide, they are moving in opposite direction and the speed of A is twice the speed of B. At what fraction of the height of the building did the collision occurs ?
Answer:
y/y₀ = 1/2 + v₀²/(2 g y₀)
Explanation:
This in a kinematics exercise in a mention
ball A.
Since the ball is dropped, its velocity starts at zero, at the meeting point the equation is
[tex]v_{A}^2[/tex]= - 2 g (y₀-y)
ball B
v_{B}^2 = v₀² - 2 g y
we substitute
2v_{B}^2 = -2 g (y₀ -y)
v_{B}^2 = - g y₀ + 2g y
v_{B}^2 = v₀² - 2gy
we have a system of two equations with two unknowns, therefore it can be solved. Let's multiply-by -1 and add
0 = g y₀ + v₀² -2gy
we clear the height
y = (g yo + v₀²) / 2g
y = yo / 2 + v₀² / 2g
In this exercise we assume that the height of the building is known and the initial velocity of ball B
The fraction is
y/yo = 1/2 + v₀²/(2gyo)
An electon in a box absorbs light. The longest wavelength in the absorbtion spectrum is 400 nm . How long is the box
Answer:
6.03x 10^-10 m
Explanation:
Given that
E= hc/ wavelength
And also
E= h²n2/8mL²
Equating the two and if we say the transition was from energy level 1 to 2 then
E2 - E1 = h²2/(8mL²) x ( 2² - 1²) = 3h²2/(8mL²)
So
L² = 3 h lambda / (8mc)
= 3 x6.626 10^-34 kg m^2/s x 400 10^-9 m /( 8 x 9.11 x10^-31 kg x3.00 10^8 m/s)
= 36.4 x 10^-20 m^2
L = 6.03 x 10^-10 m
The length of the box that absorbs the light is;
L = 6.03 × 10^(-10) m
We are given;
Longest wavelength of spectrum; λ = 400 nm = 400 × 10^(-9) m
Now, the formula for energy of quantization is;
E = h²n²/8mL²
Also, Energy of a photon is;
E = hc/λ
Thus;
hc/λ = h²n²/8mL²
h will cancel out to give;
c/λ = hn²/8mL²
Where;
h is Planck's constant = 6.626 × 10^(-34) m².kg/s
c is speed of light = 3 × 10^(8) m/s
λ is wavelength = 400 × 10^(-9) m
L is length of box
m is mass of electron = 9.11 × 10^(-31) kg
n² is difference in energy levels = (2² - 1²) = 3
Making L the subject gives;
L = √(hn²λ/8mc)
Thus;
L = √((6.626 × 10^(-34) × 3 × 400 × 10^(-9))/(8 × 9.11 × 10^(-31) × 3 × 10^(8))
L = √(3.636663007683 × 10^(-19))
L = 6.03 × 10^(-10) m
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A toy of mass 0.190-kg is undergoing SHM on the end of a horizontal spring with force constant k = 350 N/m . When the toy is a distance 0.0140 m from its equilibrium position, it is observed to have a speed of 0.400 m/s .
A) What is the toy's total energy at any point of its motion?
B) What is the toy's amplitude of the motion?
C) What is the toy's maximum speed during its motion?
Answer
a)0.0495 J
b)0.01681 m
c)0.7218 m/s
Explanation:
Given
Mass of the.toy M = 0.190 kg
force constant k = 350 N/m
Displacement from equilibrium x = 0.0140 m
Speed v = 0.400 m/s
a)What is the toy's total energy at any point of its motion?
The total energy at any point of it's motion can be calculated by adding together both the potential and kinetic energy of the toy, since it's posses potential energy when at rest and kinetic energy at motion
Total energy E = kinetic energy + potential energy
E = ¹/₂mv² + ¹/₂kx²
E = ¹/₂ (0.190)(0.4)² + ¹/₂ (350)(0.0140)²
E = 0.0495 J
Hence,the total energy is 0.0495 J
b) the amplitude of the motion can be calculated using below formula
Let amplitude = A
E = ¹/₂KA²
if we make Amplitude A the subject of the formula we have
A=√(2E/k)
But we have calculated our E up there, our K was given in question then if we substitute we have
A= √(2×0.0495)/350
Ans: 0.01681 m
Hence, our Amplitude is 0.01681 m
c) the the toy's maximum speed during its motion can be calculated using the expression below
Let maximum speed = vmax
E = (1/2)M * vmax^2
If we make vmax the subject of the formula we have
vmax =√(2E/m)
vmax= √(2×0.0495)/0.190
vmax=0.7218 m/s
Hence our vmax is 0.7218 m/s
A horizontal rope is tied to a 55.0 kg box on frictionless ice. What is the tension in the rope if: The box is at rest
Answer:
T = 0
Explanation:
Given that,
Mass of the box, m = 55 kg
We need to find the tension in the rope if the box is at rest. When the object is at rest, its acceleration is equal to 0. It would mean that the net force equals 0. So, the tension in the rope is equal to 0.
how far must he mirror mz of the michelson interferometer be moved so that 1600 fringes of laser light move across a line int he field of view
Answer:
The question is not complete. Let me explain Michelson interferometer and how to calculate a question like this.
Answer 4.85 * [tex]10^{-4}[/tex]m
Explanation:
The Michelson Interferometer is an instrument which produces interference fringes by splitting a light beam into two parts, it then recombines them after they have travelled different optical paths.
The formula to measure the minute displacement is Δd=m * λ[tex]_{0}[/tex]/2
where m is the number of fringes passing a given point as the movable plane mirror is moved
and λ[tex]_{0}[/tex] is the monochromatic lamp of wavelength
In the question, m = 1600. Let us assume that the wavelength is 606 nm
Solution
Δd=m * λ[tex]_{0}[/tex]/2
Δd=1600 * 606nm/2 = 1600 * 303nm = 484800nm
We convert the nm to m (nm / [tex]10^{-9}[/tex])
4.85 * [tex]10^{-4}[/tex]m
Two resistors connected in parallel, with R1 = 150 ohms and R2 = 75 ohms, are connected to a battery that experiences a current of 0.18 A. The current through R1 is _____ A.
Answer:
Explanation:
Given:
Two resistors (Parallel)
R1 = 150 ohms
R2 = 75 ohm
Current (I) = 0.18 A
Find:
Current through R1
Computation:
Common resistance
1/R = 1/R1 + 1/R2
1/R = 1/150 + 1/ 75
R = 50 ohms
V = IR
V = 0.18 x 50
V = 9v
So,
V = IR1
9 = I (150)
Current through R1 = 9 / 150
Current through R1 = 0.06 A