Answer:
Divide the first number by the second.
Explanation:
~55%
Answer:
About 54-55% It depends on if you need to round.
Explanation:
The Jones family paid
$
253
in August for electricity. The September bill was
21
%
lower.
How much was the September bill?
Answer:
$199.87
Explanation:
Just take $253 times 0.21 to get $53.13. This is how much lower the bill was. Next take 253 - 53.13 to get 199.87, which is the total bill amount for September.
the fixed scale specifies 10.5 millimeters and the thimble specifies 30 hundredths of a mm. what is the total value shown by the micrometer when you add these readings together
Answer:
10.80 mm
Explanation:
Given that the reading of the fixed scale is : 10.5 mm
The thimble scale specifies : 0.30 mm
The micrometer reading will be : 10.5 + 0.30 =10.80 mm
What does abbreviation vom stand for
Answer:
vom = Volt Ohm Meter
Explanation:
A business owned by one people is a
Answer:
A sole proprietorship, also known as the sole trader, individual entrepreneurship or proprietorship, is a type of enterprise that is owned and run by one person and in which there is no legal distinction between the owner and the business entity.
Explanation:
Answer:
A business owned by one people is a-Sole proprietorship
Explanation:
This is correct i did it for my electives class which was career reaserch and decision making.
brainliest?
List 3 specific things you can do with a Tape measure (not just measure things)
Answer:
See how many inches are in a foot
measure width and hight of places
Nail grabbing
Explanation:
A plane stress state (2D) of material is defined by: [σ] = [800300300−400] (MPa). Define the principal stresses σ1, σ2 using:
• Determinant Method
• Mohr’s Circle (determine also ????max)
Answer:
Explanation:
Given that:
[tex][\sigma] = \left[\begin{array}{cc}800&300\\ \\300&-400\end{array}\right] (MPa)[/tex]
[tex][\sigma] = \left[\begin{array}{cc}\sigma_{xx}&\sigma_{xy}\\ \\\sigma_{yx}&\sigma_{yy}\end{array}\right][/tex]
Using Determinant method
The principal stress is the maximum or minimum normal stress acting on any plane. For the 2D stress system, the 2-principle plane always carries zero shear stress.
For principal stress [tex]( \sigma_1, \sigma_2)[/tex]
[tex]\sigma_{1,2} = \dfrac{\sigma_x+ \sigma_y}{2} \pm \sqrt{( \dfrac{\sigma_x - \sigma_y}{2} )^2 + \sigma^2_{xy}}[/tex]
[tex]\sigma_{1} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{1} = \dfrac{400}{2} \pm \sqrt{ (600)^2 + (300)^2}[/tex]
[tex]\sigma_{1} = 200+ 670.82 \\ \\ \sigma_{1} = 870.82 \ MPa[/tex]
[tex]\sigma_{2} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{2} = 200- 670.82 \\ \\ \sigma_{1} = - 470.82 \ MPa[/tex]
According to Mohr's circle;
Mohr's circle is the locus provided that the position of the normal stress and the shear stress is acting on any plane.
Center = (a,0)
[tex]a = \dfrac{\sigma_{x}+\sigma_{y}}{2}[/tex]
[tex]a = \dfrac{800+(-400)}{2}[/tex]
a = 200 MPa
radius (r) = [tex]\sqrt{ (\dfrac{\sigma_{x}-\sigma_{y}}{2})^2 + \sigma^2 _{xy}}[/tex]
[tex]=\sqrt{ (\dfrac{800-(-400)}{2})^2 + (300)^2}[/tex]
[tex]=\sqrt{ (600)^2 + (300)^2}[/tex]
r = 670.82 MPa
[tex]\sigma_1 = a +r \\ \\ \sigma_1 = 200 + 670.82 \\ \\ \sigma_1 = 870.82 \ MPa[/tex]
[tex]\sigma_2 =-(r-a)[/tex] (it is negative because of the negative x-axis)
[tex]\sigma_2 =670.82 - 200 \\ \\ \sigma_1 = 470.82 \ MPa[/tex]
[tex]\tau_{max} = radius \ of \ Mohr's \ circle[/tex]
[tex]\tau_{max} = 670.82 \ MPa[/tex]
Need help tryna get a good grade
Answer:
C - Prototype model
Explanation:
I believe it's C but Hope this Helps!
Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.
Answer:
1. Vgs<0.7
2. Vgs>2.5
3. 0.7<vgs<2.5
Explanation:
The information below was used to answer to answer this question.
Vds = 1.8V
Vt = 0.7V
1.
The cutoff region
Vgs < Vt
= Vgs < 0.7 volts
This the cut off region
2.
Linear region
Vds < Vgs - Vt
When we put in the values
1.8V < Vgs - 0.7V
1.8V+0.7V < Vgs
2.5Volts < Vgs
This is the linear region when Vgs > 2.5 volts
3.
The saturation region
Vds > Vgs - Vt
When we put in the values we have:
1.8V > Vgs - 0.7V
2.5V > Vgs
And 0.7 < Vgs
Then the saturation region is:
0.7V < Vgs < 2.5 V
List 3 specific things you can do with a screw gun (not just screw in screws)
Answer:
1: Attaching a fork and wip eggs/batter/ ect.
2: You can entertain a cat by putting yarn on the gun/drill
3: If you get yarn everywere, you can spin the yarn up on the drill/gun
Explanation:
I hope this helps you out somehow
Select four components of the drivetrain used in a large tractor. shaft drive O belt transmission O engine O clutch O final drive blade O chain
Answer:
1
Explanation:
. Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.
Answer:
1. Cut off region: Vgs < 0.7 volts
2. Linear region: Vgs > 2.5
3. Saturation region: 0.7 < Vgs < 2.5
Explanation:
This question has provided us with these details
Vds = 1.8V
Vt = 0.7V
1. To get The cutoff region
Vgs < Vt
Such that when we put in the value, we have:
Vgs < 0.7 volts
This gives us the cut off region
2. The we get the Linear region using this formula:
Vds < Vgs - Vt
After we put in the values;
1.8V < Vgs - 0.7V
Such that
1.8V + 0.7V < Vgs
2.5V < Vgs
This is therefore the linear region of the transistor when Vgs > 2.5 volts
3. We get The saturation region using
Vgs < Vt and
Vds > Vgs - Vt
When we put in the values we have:
Vgs < 0.7V and
1.8V > Vgs - 0.7V
1.8V+0.7V > Vgs
2.5V > Vgs
Then our saturation region would be
0.7V < Vgs < 2.5 V
this is it dont anwser this is for my other account
Answer:
thanks for the poiunts
Explanation:
The displacement of a certain object is described by y(t) = 23 sin 5t, where t is measured in seconds. Compute its period and its oscillation frequency in rad/sec and in hertz
Answer:
5 rad/sec
0.796 Hz
1.256 seconds
Explanation:
Y(t) = 23sin5t ----1
Y(t) = aSin(w)t----2
w = 5 rad/sec
Then we get the Oscillation frequency from the formula below
w = 2πf
We make f to be the subject of this formula
f = w/2π
f = 5/2*3.24
f = 5/6.28
f = 0.796Hz
From the calculated frequency, we get the period = 1/f
= 1/0.796
= 1.256 seconds
Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.
Answer:
He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.
Technician A says that the refractometer reading is determined at the point of the scale where the dark and light areas meet. Technician B says that the reading is determined by where a dial points on a scale. Who is correct
Answer:
Technician B says that the reading is determined by where a dial points on a scale.
Explanation:
A refractometer is a devise used by scientists to gauge a liquids index of refraction.
The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.
The steps of reading a measurement are;
point the front of the refractometer towards the light source and view into the eyepieceYou will see the line outlined at a different point on the refractometer's internal indexRead the point on the index at which the line falls
A train starts from rest at station A and accelerates at 0.6 m/s^2 for 60 s. Afterwards it travels with a constant velocity for 25 min. It then decelerates at 1.2 m/s^2 until it is brought to rest at station B. Determine the distance between the stations.
Answer:
The distance between the station A and B will be:
[tex]x_{A-B}=55.620\: km[/tex]
Explanation:
Let's find the distance that the train traveled during 60 seconds.
[tex]x_{1}=x_{0}+v_{0}t+0.5at^{2}[/tex]
We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:
[tex]x_{1}=\frac{1}{2}(0.6)(60)^{2}[/tex]
[tex]x_{1}=1080\: m[/tex]
Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.
[tex]v_{1}=v_{0}+at[/tex]
[tex]v_{1}=(0.6)(60)=36\: m/s[/tex]
Then the second distance will be:
[tex]x_{2}=v_{1}*1500[/tex]
[tex]x_{2}=(36)(1500)=54000\: m[/tex]
The final distance is calculated whit the decelerate value:
[tex]v_{f}^{2}=v_{1}^{2}-2ax_{3}[/tex]
The final velocity is zero because it rests at station B. The initial velocity will be v(1).
[tex]0=36^{2}-2(1.2)x_{3}[/tex]
[tex]x_{3}=\frac{36^{2}}{2(1.2)}[/tex]
[tex]x_{3}=540\: m[/tex]
Therefore, the distance between the station A and B will be:
[tex]x_{A-B}=x_{1}+x_{2}+x_{3}[/tex]
[tex]x_{A-B}=1080+54000+540=55.620\: km[/tex]
I hope it helps you!
if citrus overlord is 200 (I'm offering for a lucid leaf) and shiny eternal contrast is 250, 450 so far and I'm also last thing offering for lucid (which is 100 secret value and I'm offering in shiny value and Lucid's shiny value is 500 but gets op's because it's a secret pet) is a shiny dark omen which is 100, I'm offering 550 for 500 but gets op's, w or l, I think w.
Answer: I'm pretty sure your taking a W.
your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.
Explanation:
Answer:
gg's if you did it cause w
Explanation:
If a shear stress acts in one plane of an element, there must be an equal and opposite shear stress acting on a plane that is
Answer:
90 degrees
Explanation:
In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane
Therefore as per the given situation it should be 90 degrees from the plane
hence, the same is to be considered and relevant too
(Giving Brainliest to 1st!)Which organelle acts as a temporary storage center, containing water, waste, and other products?
A. cell membrane
B. cytoplasm
C. vacuole
D. nucleus
Visual interpretations when driving are two things: first, what the driver sees around him or her passively, so it is what the eyes receive, and the second is:
Choose one
A. How the driver understands and processes the things his or her eyes receive.
B. How the driver disregards these things.
C. How the driver violates these things whenever he can.
D. How the driver appreciates all the colors he sees.
Answer:
A. How the driver understands and processes the things his or her eyes receive.
Explanation:
When driving, visual interpretation occurs in two things;
What the driver sees around him or her passively, mainly what is received by the eyeHow the driver understands and processes the things his or her eyes receiveProper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.
In driving, visual interpretations are important as it entails what the driver sees and A. How the driver understands and processes the things his or her eyes receive.
It's important for drivers to have proper vision when driving. A driver should be able to interpret what the driver sees around him or her passively.
Also, it's important for the drive to be able to understand and processes the things his or her eyes receive. This is vital in order to prevent accidents.
Learn more about driving on:
https://brainly.com/question/24606937
The gross weight of a two-place Piper Cherokee is 2000lb and its wing area is 160 ft^2. What is its wing loading
Answer:
[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]
[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]
Explanation:
Given
[tex]Weight=2000lb[/tex]
[tex]Area = 160ft^2[/tex]
Required
Determine the wing loading (W)
Wing loading is calculated using:
[tex]W = \frac{Weight}{Area}[/tex]
Substitute values for Weight and Area
[tex]W = \frac{2000lb}{160ft^2}[/tex]
[tex]W = 12.5\ lb/ft^2[/tex]
The answer can also be converted to N/m^2
[tex]1\ lb = 4.4482216153N[/tex]
[tex]1ft^2 = 0.092903m^2[/tex]
So, we have:
[tex]W = \frac{12.5 * 4.4482216153N}{0.092903m^2}[/tex]
[tex]W = \frac{55.6027701912N}{0.092903m^2}[/tex]
[tex]W = 598.503N/m^2[/tex]
Hence, the wing loading is:
[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]
[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]
Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answer:
true
Explanation: