Ben and Carson went to the movies with friends. Ben purchased 3 popcorn and 2 boxes of candy for $41. Carson purchased 1 popcorn and 2 boxes of candy for $29. How much did the popcorn cost?
Answer:
$6
Step-by-step explanation:
B- 3P+2C=$41
C-1P+2C=$29
since they both bought at least 1 popcorn and 2 candy you can just subtract 29 from 41. you get 12 which equals the other 2 popcorns that ben bought
12/2=6
since you need to find the price of 1 popcorn you have to divide 12 by 2
Help plz :)) I would appreciate it
Answer:
VW = 29
Step-by-step explanation:
Perimeter of the triangle = 82
Perimeter of the triangle = 4x + (x + 3) + (3x - 1)
4x + (x + 3) + (3x - 1) = 82
4x + x + 3 + 3x - 1 = 82
8x + 2 = 82
8x = 82 - 2
8x = 80
x = 10
VW = 3x - 1
VW = 3(10) - 1
VW = 30 - 1
VW = 29
Help please and please make sure the answer is right please!!!!
Answer:
7
Step-by-step explanation:
Write the an equation of a line that is perpendicular to y= 1/3x + 5 and intersects it at the y intercept
Answer:
y = -3x + 5
Step-by-step explanation:
For two lines to be perpendicular, the product of their slope must be -1.
Slope of the given line M = 1/3
Slope of the required line is m
If product is -1, then;
Mm = -1
1/3 m = -1
m = -3
SInce it intersects at the y intercept, y intercept c = 5
Get the required equation. Substitute m = -3 and c = 5 into the equation
y = mx+c
y = -3x + 5
Hence the required equation of the line is y = -3x + 5
Angela starts a blog about wheelchair basketball. In the first 4 days,
the blog gets 22 new subscribers. At this rate, how many new
subscribers can Angela expect in 30 days? Show your work.
Taylor invested $650 in an account paying an interest rate of 2.3% compounded
daily. Assuming no deposits or withdrawals are made, how long would it take, to the
nearest tenth of a year, for the value of the account to reach $880?
Answer:
Step-by-step explanation:
Given that:
Principal = $650
Interest rate, r = 2.3% = 0.023 compounded daily
Time, t it takes for final amount, A to reach $880
Using the relation :
A = P(1 + r/n)^nt
n = number of times compounded per period
Hence, n = 365
880 = 650(1 + 0.023/365)^365t
880/650 = 1.0000630^365t
1.3538461 = 1.0000630^365t
Take the log
0.1315692 = 0.0000273596 * 365t
0.1315692 = 0.0099862t
t = 0.1315692 / 0.0099862
t = 13.175101
t = 13.18 years a
Please help!
What is the intial value of the function represented by this graph?
A. 0
B. 1
C. 2
D. 5
Lina has five more than seven times as many pictures as photo albums. If she has 75 pictures, how many photo albums does she have?
Answer:
photo albums = x
pictures =75( seven times of albums +5)
so
seven times of x is 7x and +5
7x +5 = 75
7x= 75-5
7x = 70
x=70÷7
x =10
x = 10 = photo albums
Need help with mymathlab problem
Answer:
not question no answer
Step-by-step explanation:
sana po magets nyo po
Drag and Drop the right answer in the answers below.
CAT ~ DOG
Answer:
Do ,Ct, OG hope it helps have a nice day
The track team is trying to reduce their time for a relay race. First they reduce their time by 1.2 minutes. Then they are able to reduce that time by 1/10. If their final time is 3.60 minutes, what was their beginning time?
Answer:
5.2 Minutes, or 5 minutes and 12 seconds
Step-by-step explanation:
You can solve this problem by working backward. Since our number gets smaller by a 1/10 or 0.1, in order to work backward we must multiply 3.60 by 10/9, since one tenth has been taken away already. When we do this, we get 4.0. When we add 1.2 minutes to that, we get a final answer of 5.2 minutes, or 5 minutes and 12 seconds.
The scale of a model train is 1 inch to 13.5teet One of the cars of the model train is 5 inches long-
What is the length, in feet, of the actual car?
Show work
Given :
The scale of a model train is 1 inch to 13.5 feet.
One of the cars of the model train is 5 inches long.
To Find :
The length, in feet, of the actual car.
Solution :
It is given that scale of the model is 1 inch to 13.5 feet. It means that 1 inch in the actual scale is equal to 13.5 feet in real.
So, length of car real is :
Length = 5 × 13.5 feet
Length = 67.5 feet
Therefore, the length of the actual car is 67.5 feet.
Fahim is 6 feet tall. At noon, he stands with the sun behind him casting a shadow. The distance from the top of Fahim’s head to the furthest tip of the shadow is 13 feet.
A right triangle with side length 6 feet, s, and hypotenuse 13 feet.
[Not drawn to scale]
What is the length of Fahim’s shadow? Round to the nearest tenth of a foot.
7.0 feet
8.5 feet
11.5 feet
14.3 feet
Answer: 11.5 feet
Step-by-step explanation:
We should note that for a right angles triangle, the square of the hypothenuse equals to the square of the opposite side and its adjacent. This can be expressed as:
Let the length of Fahims shadow be x
hypotenuse² = opposite² + adjacent ²
13² = 6² + x²
169 = 36 + x²
x² = 169 - 36
x² = 133
x =✓133
x = 11.53
= 11.5 feet to nearest tenth
Answer:
C 11.5
Step-by-step explanation:
Have a great day!
The trapezoids are similar. In the figure below ABCD ~ EFGH. What is the value of x?
Answer:
abcd
Step-by-step explanation:
can someone help me out with this problem ?
under the scale factor of the dilation (with center at the origin )if point U (6,2) becomes U' (12,4) ?
Answer:
im assuming that it it went up 6,2 and prolly has a pattern and that this is just a graph problem
Step-by-step explanation:
Answer:
umm i dont knowe sorry
Step-by-step explanation:
Please help, I don't understand how to do this equation
Answer: B) -1/3i
Step-by-step explanation: 81(-1/3i)^4
Answer:
Step-by-step explanation:
81x^4=1
x^4=1/81
(x^4)^(1/4)=(1/81)^(1/4)
x=+\-1/3
so -1/3 is a solution
f(x) =
4/x²+1
Asymptotes
Answer:
vertical asymptotes at
x
=
±
1
horizontal asymptote at
y
=
0
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.
solve:
x
2
−
1
=
0
⇒
x
2
=
1
⇒
x
=
±
1
⇒
x
=
−
1
and
x
=
1
are the asymptotes
Horizontal asymptotes occur as
lim
x
→
±
∞
,
f
(
x
)
→
c
(a constant)
divide terms on numerator/denominator by the highest power of x, that is
x
2
f
(
x
)
=
4
x
x
2
x
2
x
2
−
1
x
2
=
4
x
1
−
1
x
2
as
x
→
±
∞
,
f
(
x
)
→
0
1
−
0
⇒
y
=
0
is the asymptote
Oblique asymptotes occur when the degree of the numerator > degree of the denominator. This is not the case here (numerator-degree 1 , denominator-degree 2) Hence there are no oblique asymptotes.
graph{(4x)/(x^2-1) [-10, 10, -5, 5]}
NEED HELP ASAP!!!!!!!!!!!!!!!!!
Answer:
I think it is 6 sorry if it is wrong
Step-by-step explanation:
;-;
Answer:
Since 3^5 is equal to 243, that means if you were to evaluate 3^5, the answer would be 243. That means it would be very easy to evaluate as the answer is already stated to be equal to 243.
PLS HELPP I NEED TO TURN IN IN 10 MINUTES
Answer: side CD = CY
Step-by-step explanation:
They are asking for ASA = Angle, Side, Angle. And they already gave you the two angles so they are asking for the side
Find the product of the monomial and the polynomial:
−3a·(7a^2−4)
Answer:
[tex]-21a^{3}+12a[/tex]
Step-by-step explanation:
We are given that
[tex]-3a\cdot (7a^2-4)[/tex]
We have to find the product .
To find the product we will multiply -3a with each term given in the bracket
[tex]-3a(7a^2)-3a(-4)[/tex]
[tex]-21a^{1+2}+12a[/tex]
By using the formula
[tex]a^{x}\cdot a^{y}=a^{x+y}[/tex]
[tex]-21a^{3}+12a[/tex]
Hence,
[tex]-3a\cdot (7a^2-4)=-21a^{3}+12a[/tex]
I need heeeelp please !
witch is longer distsance 20% of 320 miles of 1/2of 130 you must show your working out
Answer: [tex]\frac{1}{2}\ \text{of}\ 130> 20\%\ \text{of}\ 320[/tex]
Step-by-step explanation:
[tex]20\%\ \text{of}\ 320\ \text{is}\\\Rightarrow \frac{20}{100}\times 320=64\ \text{miles}[/tex]
[tex]\frac{1}{2}\ \text{of}\ 130\ \text{is} \\\Rightarrow \dfrac{130}{2}=65\ \text{miles}[/tex]
clearly, [tex]\frac{1}{2}\ \text{of}\ 130> 20\%\ \text{of}\ 320[/tex]
Hey guys please help!!
Answer:
Yes
Step-by-step explanation:
g(x) = - [tex]\frac{1}{4}[/tex] x + [tex]\frac{1}{4}[/tex]
y = - [tex]\frac{1}{4}[/tex] x + [tex]\frac{1}{4}[/tex] ....... (1)
(1) × 4
4y = - x + 1
x = - 4y + 1
y = - 4x + 1
f(x) = - 4x + 1
∴ f(x) and g(x) are inverses
Select all that apply.
Which representations show a direct variation?
y = - x
y = 2 x + 3
Input (x) 3 6 9 12 15
Output (y) 4 8 12 16 20
Answer:
Options 1 and 3 are direct variationStep-by-step explanation:
Direct variation is:
y = kxOptions:
1.
y = -x, k = -1, yes2.
y = 2x + 3, not a direct variation, no3.
Try the input/output to determine the direct variation:
4 = 3k k = 4/3Verify the other pairs:
x = 6, y = 6(4/3) = 8x = 9, y = 9(4/3) = 12x = 12, y = 12(4/3) = 16x = 15, y = 15(4/3) = 20This is also a direct variation
4x + y = 14. 5x +2y = 19 solve the simultaneous equation
Answer:
(3, 2 )
Step-by-step explanation:
Given the 2 equations
4x + y = 14 → (1)
5x + 2y = 19 → (2)
Multiplying (1) by - 2 and adding to (2) will eliminate the y- term
- 8x - 2y = - 28 → (3)
Add (2) and (3) term by term to eliminate y
- 3x + 0 = - 9
- 3x = - 9 ( divide both sides by - 3 )
x = 3
Substitute x = 3 into either of the 2 equations and solve for y
Substituting into (1)
4(3) + y = 14
12 + y = 14 ( subtract 12 from both sides )
y = 2
solution is (3, 2 )
Step-by-step explanation:
[tex] \underline{ \underline{ \text{USING \: ELIMINATION \: METHOD}}}[/tex]
[tex] \underline{ \underline{ \text{ Solution}}} : [/tex]
[tex] \text{4x + y = 14 - - - - - (i)}[/tex][tex] \text{5x + 2y = 19 \: - - - - - (ii)}[/tex]Multiply equation ( i ) by 2 & Subtract from ( ii ). The equation ( i ) now becomes 8x +2y = 28 { 2 ( 4x + y ) = 2 × 14 }. Remember that while subtracting the sign of each term of equation ( i ) changes and now , it becomes -8x-2y = -28.
[tex] \text{5x + 2y = 19}[/tex]
[tex] \text{ - 8x - 2y = - 28}[/tex]
_____________________
[tex] \text{ - 3x = - 9}[/tex]
Solve for x :
⤑ [tex] \tt{x = \frac{ - 9}{ - 3}} [/tex]
⤑ [tex] \tt{x = 3}[/tex]
Now , substitute the value of x in equation ( ii ) :
⟼ [tex] \text{5 × \: 3 + 2y = 19}[/tex]
⟼ [tex] \text{15 + 2y = 19} [/tex]
⟼ [tex] \text{2y = 19 - 15}[/tex]
⟼ [tex] \text{2y = 4}[/tex]
⟼ [tex] \text{y = 2}[/tex]
[tex] \pink{ \boxed{ \boxed{ \tt{⤿ \: Our \: final \: answer : \boxed{ \boxed{ \tt{x = 3 \: and \: y = 4}}}}}}}[/tex]
Hope I helped ! ツ
Have a wonderful day night ! ♡
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In the figures, area of triangle ABE is 25 cm2
and area of triangle CED is 30 cm2. Find the
area of triangle BEC and parallelogram ABCD.
Answer:
sorry where is figure.
Step-by-step explanation:
area of triangle ABE=area of triangle BE3
write an equation that models the points (-1,4) and (3,2)
Answer:
Step-by-step explanation:
y=mx+b
m=(y2-y1)/((x2-x1)=(2-4)/(3- -1)=-2/4=-.5
y=-.5(3)+b, using point (3,2)
2=-1.5+b
b=3.5
y= -.5x+3.5
gym starts at 1:00 and ends at 2:00 how long is gym?
Answer:
1 hour or 60 minutes
I'll show a pic of my question
Answer:
Umm I think you forgot to send the pic with this question
Step-by-step explanation:
Hope I can help next time!!!!!!