Will most likely cause the formation of a Mountain
A. Divergent boundary
B. Convergent boundary
C. Transform boundary
Answer:
Convergent boundaries. When two plates collide and one is pushed over the other, forming a mountain.
which line represnts object moving fastest
**WILL MARK BRAINLEST ANSWER, IF RIGHT**
Line - A: (15/10) = 1.5 inch/second
Line - B: (0/10) = 0
Line - C: (10/10) = 1.0 inch/second
Line - D: (-25/20) = -1.25 inch/second
Line-A represents the greatest speed.
Why is the air temperature shown on Sensor 4 different from Sensor 5, even though they are at the same latitude?
Answer:
Hello your question lacks some information but i will give you a more General answer about differences in temperature of bodies on same latitude
answer : Continentality is the reason
Explanation:
Sensors or objects on the same latitude are supposed to have the same air temperatures but in some cases this might not be true. This is because of the proximity of the bodies to an Ocean or any water body.
Areas close to water bodies experience modest temperatures even if they are on the same latitude with Areas experiencing harsh temperatures. This effect is termed as Continentality
Which of the following statements is correct A. College degree isn't as important as it was in the past b. Over time, I can earn more money by not going to college c. College graduates earn about double the income of high school graduates d. The money I make after college does not compensate for the four years I spent in college
Answer:
I'd say C is the answer they want, though my pedantic side wants to argue for B being true as well.
Answer: C. College graduates earn about double the income of high school graduates.
Explanation: I just took the quiz :)
What does it take to change the direction or speed of an object
Answer:
An object's speed or direction can be changed by a force. This means a greater force against a lesser force, and it results in acceleration. This means any push or pull against another equal push or pull. It results in no change of acceleration
Explanation:
A 12 kg object has a velocity of 37.5 m/s. What is its momentum
Answer:
Solution:
Explanation:
Here, mass of body ( m)=12kg.
velocity (v)=37.5 m/s. momentum = mass× velocity = 12kg×37.5m/s =450kgm/s ans.
what happens to our bodies if we do not eat nutritious meals? give three reasons.
3 things that happen to our body when we don't eat nutritious meals:
1. It can lead to bad eating habits that may cause obesity or diabetes
2. It can also cause heart disease and cancer
3. it can also make you more tired, and may contribute to stress.
Poor nutrition can contribute to stress, tiredness and our capacity to work, and over time. It can contribute to the risk of developing some illnesses and other health problems such as being overweight or obese.
Hope this helps; have a great day!
A 12-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
What does "the following" mean ?
Kinetic energy is directly proportional to speed² .
So kinetic energy doubles if the speed is increased by √2 .
(3 m/s) · (√2) = 4.243 m/s
A hunter is standing on flat ground between two vertical cliffs that are directly opposite one another. He is closer to one cliff than to the other. He fires a gun and, after a while, hears three echoes. The second echo arrives 2.1 s after the first, and the third echo arrives 0.5 s after the second. Assuming that the speed of sound is 343 m/s and that there are no reflections of sound from the ground, find the distance between the cliffs. 445.9 Incorrect: Your answer is incorrect. m
Answer:
531.65 m
Explanation:
Let d₁ be the distance between the hunter and the closer cliff and d₂ be the distance between the hunter and the farther cliff. The speed of sound v = 343 m/s.
t₁ is the time taken for the sound to reach the neared cliff and return back to the hunter as echo. Hence:
t₁ = 2d₁/343
t₂ is the time taken for the sound to reach the farther cliff and return back to the hunter as echo. Hence:
t₂ = 2d₂/343
t₂ - t₁ = 2.1
2d₂/343 - 2d₁/343 = 2.1
d₂ - d₁ = 360.15 (2)
t₃ is the time taken by the third echo as a result of the second echo reaching the nearer cliff. Hence:
t₃ = 2d₁/343
0.5 = 2d₁/343
d₁ = 85.75 m
d₂ - d₁ = 360.15
d₂ - 85.75 = 360.15
d₂ = 445.9 m
The distance between the two cliffs = d₁ + d₂ = 445.9 + 85.75 = 531.65 m
Write a paragraph describe the desert biome
Answer:
The desert biome is an ecosystem that forms due to the low level of rainfall it receives each year. Deserts cover about 20% of the Earth. There are four major types of desert in this biome - hot and dry, semiarid, coastal, and cold. They are all able to inhabit plant and animal life that are able to survive there. Although the daytime temperatures of the desert biome are very hot, they can get very cold at night. The Sahara Desert is the largest desert in the desert biome. It covers over 300 million square miles.
Explanation:
Which may result from an increase in friction?
decreased traction
increased speed
reduced wear and tear
generation of heat
Answer:
The Answer is B: to provide traction so that slipping does not occur
Explanation:
if it is wrong please correct me
In an example food chain, mice only eat plants, and then snakes eat the mice. These snakes are examples of consumers.
a Quaternary
b Primary
c Secondary
d Tertiary
Which stretch focuses on stretching the glutes and hamstrings while laying on your back?
Question 4 options:
Knee to hip
Bent knee
Knee to Chest
Chest flies
tyyyyyyyy
Answer:
knee to chest
Explanation:
I took the test
Answer:
C. Knee to chest.
A weight - lifter lifts a bell weighing 2 000 N and holds it in the air for 5 seconds. Has he done any work? Explain your answer.
Answer:
No, he hasn't done any work.
Explanation:
In this scenario, the weightlifter hasn't done any work because even though he lifted the bell for a specific period of time, he didn't cover any distance.
Mathematically, work done is given by the formula;
Work done = force * distance
[tex] W = F * d[/tex]
Where,
W is the work done
F represents the force acting on a body.
d represents the distance covered by the body.
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
whenever velocity increases the kinetic energy will ?
Answer:
It will increase.
Explanation:
Because kinetic energy is proportional to the square of the velocity, when velocity is doubled, kinetic energy is quadrupled. Kinetic energy K=mv^2/2
Three equal charge 1.8*10^-8 each are located at the corner of an equilateral triangle ABC side 10cm.calculate the electric potential due to these charge at the mid point of AB
Answer:
If all these three charges are positive with a magnitude of [tex]1.8 \times 10^{-8}\; \rm C[/tex] each, the electric potential at the midpoint of segment [tex]\rm AB[/tex] would be approximately [tex]8.3 \times 10^{3}\; \rm V[/tex].
Explanation:
Convert the unit of the length of each side of this triangle to meters: [tex]10\; \rm cm = 0.10\; \rm m[/tex].
Distance between the midpoint of [tex]\rm AB[/tex] and each of the three charges:
[tex]d({\rm A}) = 0.050\; \rm m[/tex].[tex]d({\rm B}) = 0.050\; \rm m[/tex].[tex]d({\rm C}) = \sqrt{3} \times (0.050\; \rm m)[/tex].Let [tex]k[/tex] denote Coulomb's constant ([tex]k \approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex].)
Electric potential due to the charge at [tex]\rm A[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm A})}[/tex].
Electric potential due to the charge at [tex]\rm B[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm B})}[/tex].
Electric potential due to the charge at [tex]\rm A[/tex]: [tex]\displaystyle \frac{k\, q}{d({\rm C})}[/tex].
While forces are vectors, electric potentials are scalars. When more than one electric fields are superposed over one another, the resultant electric potential at some point would be the scalar sum of the electric potential at that position due to each of these fields.
Hence, the electric field at the midpoint of [tex]\rm AB[/tex] due to all these three charges would be:
[tex]\begin{aligned}& \frac{k\, q}{d({\rm A})} + \frac{k\, q}{d({\rm B})} + \frac{k\, q}{d({\rm C})} \\ &= k\, \left(\frac{q}{d({\rm A})} + \frac{q}{d({\rm B})} + \frac{q}{d({\rm C})}\right) \\ &\approx 8.99 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2} \\ & \quad \quad \times \left(\frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{0.050\; \rm m} + \frac{1.8 \times 10^{-8} \; \rm C}{\sqrt{3} \times (0.050\; \rm m)}\right) \\ &\approx 8.3 \times 10^{3}\; \rm V\end{aligned}[/tex].
A student in your class whom you kind-of like asks you come to watch a meteor shower. What exactly are you being invited to? a. something your mom would not approve of, involving streams of dirty water b. the closest approach of an active bright comet to the Earth c. a once-in-a-lifetime experience at the end of which you will be completely covered with dust particles from space d. watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere e. something quite dangerous where you are likely to be hit when many larger rocks fall from above Submit Your Answer
Answer:D. Watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
Explanation: A meteor shower is giant rocks moving across the sky
There must be an invitation for d. watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
What is a Meteor showers ?
Meteor showers occur when dust or particles from asteroids or comets enter Earth's atmosphere at very high speed. When they hit the atmosphere, meteors rub against air particles and create friction, heating the meteors. The heat vaporizes most meteors, creating what we call shooting stars
hence correct option will be D) Watching the left-over dirt from a comet burn up by friction as the pieces hit the Earth's atmosphere
learn more about Meteor showers
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The parallel plates in a capacitor, with a plate area of 8.00 cm2 and an air-filled separation of 2.70 mm, are charged by a 8.70 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.80 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
Answer:
a) ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J, d) W = 150 10⁻¹² J
Explanation:
Let's find the capacitance of the capacitor
C = [tex]\epsilon_o \frac{A}{d}[/tex]
C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³
C = 2.62 10⁻¹² F
for the initial data let's look for the accumulated charge on the plates
C = [tex]\frac{Q}{\Delta V}[/tex]
Q₀ = C ΔV
Q₀ = 2.62 10⁻¹² 8.70
Q₀ = 22.8 10⁻¹² C
a) we look for the capacity for the new distance
C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³
C₁ = 1.04 10⁻¹² F
C₁ = Q₀ / ΔV₁
ΔV₁ = Q₀ / C₁
ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²
ΔV₁ = 21.9 V
b) initial stored energy
U₀ = [tex]\frac{Q_o}{ 2C}[/tex]
U₀ = (22.8 10⁻¹²)²/(2 2.62 10⁻¹²)
U₀ = 99.2 10⁻¹² J
c) final stored energy
U_f = (22.8 10⁻¹²) ² /(2 1.04 10⁻⁻¹²)
U_f = 249.9 10⁻¹² J
d) the work of separating the plates
as energy is conserved work must be equal to energy change
W = U_f - U₀
W = (249.2 - 99.2) 10⁻¹²
W = 150 10⁻¹² J
note that as the energy increases the work must be supplied to the system
An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the object?
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
[tex]F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N[/tex]
Therefore, the force of attraction between the two charges is 3.55 N.
PLZ HELP ILL GIVE BRAINLIEST
Answer:
x10 - 6 +(8+6-4)= 10
10m -10x y0
A stone of mass 0.2kg is thrown vertically upwards from the ground with a velocity of 20m/s. Find the maximum height attained by the stone
Answer: 20.4 m
Explanation: speed v upward is v = vo -gt.
When maximum height v = 0, vo -gt = 0 and
T = vo / g = 20 m/s / 9.81 m/s² = 2.04 s
Now height y = vot -0.5 gt^2 = 20,4 m
This is possible to solve using
Conservation of energy Ek= Ep
0.5mv² = mgh. And h = v²/2g. Results same
A penguin swimming underwater goes 20 meters in 5 seconds. What is its average speed?
Answer:
4 meters per second
Explanation:
What volume of silver metal will have a mass of exactly 2.5 kg, given that the density of silver is 10.5 g/cm3? (Hint: Note the units of mass given and the units of density.)
Answer:
238.09 cm^3
Explanation:
V=mass/density
V=2500/10.5
V=238.09 cm^3
HELP FAST
How did the lab activities help you answer the lesson question, "How do atmospheric conditions influence weather patterns?" What did you learn from conducting this lab?
Answer:
not enough
Explanation:
information given
Answer:
Sample Response: In the lab, I discovered the air pressure, air temperature, and relative humidity conditions that create snow, rain, thunderstorms, fog, and clear skies. I learned that low-pressure areas usually experience snowy, rainy, and stormy weather, and that high-pressure areas usually experience either foggy or sunny weather. Knowing how these atmospheric conditions influence weather help weather forecasters predict weather patterns through maps and other information.
(Sorry this was not fast enough )
An electric motor turns a flywheel through a drive belt that joins a pulley on the motor and a pulley that is rigidly attached to the flywheel. The flywheel is a solid disk with a mass of 70.5 kg and a diameter of 1.25 m. It turns on a frictionless axle. Its pulley has much smaller mass and a radius of 0.230 m. If the tension in the upper (taut) segment of the belt is 165 N, and the flywheel has a clockwise angular acceleration of 1.67 rad/s2, find the tension in the lower (slack) segment of the belt.
Answer:
The tension on the slack segment of the belt is 65 N
Explanation:
The given parameters are;
The mass of the solid disk = 70.5 kg
The diameter of the flywheel disk, D = 1.25 m
The radius of the pulley = 0.230 m
If the tension in the upper segment of the belt = 165 N
The angular acceleration of the flywheel = 1.67 rad/s²
The moment of inertia of a circular disc, I = 1/2·M·r²
The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m
The moment of inertia of the flywheel, I = 1/2 × 70.5 kg × (0.625 m)² = 13.7695312 m²·kg
The moment of inertia, I = 13.7695312 m²·kg
Torque, τ = Moment of Inertia, I × Angular acceleration, α
Torque, τ = I × α
τ = 13.7695312 m²·kg × 1.67 rad/s² = 22.9951171 N·m ≈ 23 N·m
The torque applied from the pulley side is given as follows;
Let [tex]T_{slk}[/tex] represent the tension on the slack segment of the belts, we have;
23 N·m = (165 N - [tex]T_{slk}[/tex]) × 0.230 m
∴ 165 N - [tex]T_{slk}[/tex] = 23 N·m/0.230 m = 100 N
[tex]T_{slk}[/tex] = 165 N - 100 N = 65 N
The tension on the slack segment of the belt, [tex]T_{slk}[/tex] = 65 N
The tension on the slack segment of the belt is 65 N
What is flywheel?flywheel, heavy wheel attached to a rotating shaft so as to smooth out delivery of power from a motor to a machine. The inertia of the flywheel opposes and moderates fluctuations in the speed of the engine and stores the excess energy for intermittent use.
The given parameters are;
The mass of the solid disk = 70.5 kg
The diameter of the flywheel disk, D = 1.25 m
The radius of the pulley = 0.230 m
If the tension in the upper segment of the belt = 165 N
The angular acceleration of the flywheel = 1.67 rad/s²
The moment of inertia of a circular disc, I = 1/2·M·r²
The radius of the flywheel, r = D/2 = (1.25 m)/2 = 0.625 m
Now we will calculate tension on the slack side
The moment of inertia of the flywheel,
[tex]I = \dfrac{1}{2} \times 70.5 kg \times (0.625 m)^2 = 13.7695312 \ m^2 \ kg[/tex]
The moment of inertia, I = 13.7695312 m²·kg
Torque, τ = Moment of Inertia, I × Angular acceleration, α
Torque, τ = I × α
τ = [tex]13.7695312 \times 1.67 = 22.9951171 Nm = 23 Nm[/tex]
The torque applied from the pulley side is given as follows;
Let represent the tension on the slack segment of the belts, we have;
23 N·m = (165 N - ) × 0.230 m
∴ 165 N - = 23 N·m/0.230 m = 100 N
= 165 N - 100 N = 65 N
The tension on the slack segment of the belt, = 65 N
To know more about flywheels follow
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which of the following is the best definition for homestasis
A property of cells, tissues, and organisms that allows the maintenance and regulation of the stability and constancy needed to function properly. Homeostasis is a healthy state that is maintained by the constant adjustment of biochemical and physiological pathways.
have a good day :).
3. What happens when you get a large number of magnetic domains aligned?
a strong magnet
a weak magnet
a non-magnetic material
HELP!!!!!!!!
When a large number of magnetic domains are aligned, a strong magnet produces more magnetic attraction compared to a weak magnet and non-magnetic material.
What is magnetic induction?
Magnetic induction occurs when a magnetic field is used to magnetize another object.
This process occurs when the magnetic domains are aligned in the same direction, which causes the object become magnetized in that direction, thereby forming a magnet.
Thus, when a large number of magnetic domains are aligned, a strong magnet produces more magnetic attraction compared to a weak magnet and non-magnetic material.
Learn more about magnetic domains here: https://brainly.com/question/31744
how do you find the focal length of an lens experimentally
Answer:
Place the convex lens on a 'V' stand. . ii) Light a candle and take it far away from the lens along the principal axis. iii) Adjust the screen on the other side of the lens to get a clear image on it. iv) Measure the distance between the 'V' stand and the screen which gives a rough idea of the focal length of the lens.
Does anybody know the formula needed to calculate distance given the values for mass, power, and time?
Answer:
Joules/second^2=(Newton×meter)/second^2.
Solving for mass: Kg= (second^3/ meter^2).
Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it completely and throws Sheila forward onto the pavement. If there is no net force on the system, what is Sheila's velocity immediately after she is thrown from the bike? 1.8 m/s 2.0 m/s 5.0 m/s 5.7 m/s
Answer:
v₂ = 5.7 m/s
Explanation:
We will apply the law of conservation of momentum here:
[tex]Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\[/tex]
where,
Total Initial Momentum = 340 kg.m/s
m₁ = mass of bike
v₁ = final speed of bike = 0 m/s
m₂ = mass of Sheila = 60 kg
v₂ = final speed of Sheila = ?
Therefore,
[tex]340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\[/tex]
v₂ = 5.7 m/s
Answer:
5.7 I got it right on edg 2021
Explanation: