What is the slope of the line?
2x+ 4y = 6x- y

Answers

Answer 1

Answer:

4/5

Step-by-step explanation:

→ Rearrange to get into y = mx + c

5y = 4x + c

→ Divide everything by 5

y = 4/5x + c


Related Questions

In the following distribution, P(X<2) = 0.35, and expected value is 1.9

X 0 1 2 3 4
P(X) 0.10 A 0.35 B C

Required:
a. Use the fact that P(X< 2) = 0.35 to find the value of A.
b. Determine the value of B.
c. Determine the value of C.

Answers

Solution :

We have :

X            0     1          2    3   4

P(X)     0.10   A    0.35   B    C

a). P(X < 2) = 0.35

P(X < 2) = P(X = 0) + P(X = 1) = 0.35

⇒ 0.10 + A = 0.35

⇒ A = 0.25

So the value of A is 0.25

b). The total probability = 1

So ,

0.10 + A + 0.35 + B + C = 1

0.10 + 0.25 + 0.35 + B + C = 1

B + C  = 1 - 0.70

B + C  = 0.30  ......(i)

We have the expected value = 1.9

So, [tex]$\sum X P(X) = 19$[/tex]     for x  = 0, 1, 2, 3, 4

⇒ (0 x 0.10) + (1 x 0.25) + (2 x 0.35) + (3 x B) + (4 x C) = 1.9

⇒ 0 + 0.25 + 0.70 + 3B + 4C = 1.9

⇒ 3B + 4C = 1.9 - 0.95

⇒ 3B + 4C = 0.95   ...................(ii)

From (i), we take the value of B = 0.30 - C and substitute it in the equation (i), we get,

⇒ 3( 0.30 - C) + 4C = 0.95

⇒ 0.90 - 3C + 4C = 0.95

C = 0.95 - 0.90

       = 0.05

Now substituting the value of C = 0.05 in (ii), we get,

⇒ B = 0.05 = 0.30

⇒ B = 0.25

c). The value of C is 0.05

             

find the area of the following figures: ​

Answers

Answer:

Area = 156 square cm

Step-by-step explanation:

The solution set for -18 < 5x - 3 is _____.

3 > x
3 < x
-3 < x
-3 > x

Answers

Answer:

[tex]-3 < x[/tex]

Step-by-step explanation:

Given

[tex]-18 < 5x-3[/tex]

Required

The solution

[tex]-18 < 5x-3[/tex]

Add 3 to both sides

[tex]3-18 < 5x-3+3[/tex]

[tex]-15 < 5x[/tex]

Divide both sides by 5

[tex]-3 < x[/tex]

If the exponential model f(x)=3(2)x is written with the base e, it will take the form A0ekx. What is A0 and what is k?

Answers

Answer:

Answer in pic

Step-by-step explanation:

The required value of A₀ = 3 and k = ln 2, as of the given exponential model.

What is an exponential function?

The function which is in format f(x) =a^x  where a is constant and x is variable,  the domain of this exponential function lies   (-∞, ∞).

here,
Since.
[tex]a^x = e^{xlna}[/tex]
According to the question,
[tex]3(2)^x = A_oe^{kx}\\3e^{xln2} = A_oe^{kx}[/tex]
Now

Compare the values,
A₀ = 3 and k = ln 2,

Thus, According to the stated exponential model, A0 = 3 and k = ln 2.

Learn more about exponential function here:

brainly.com/question/15352175

#SPJ2

17. A loan of $8000 was paid back in 2
years in monthly payments of $400.
The interest on the loan as a
percentage, was
A. 5%
B. 8-%
C. 162 %
16
D. 20%​

Answers

Answer:

D. 20%

Step-by-step explanation:

2 years = 24 months

400 × 24 = 9600

9600 - 8000 = 1600

1600/8000 = 1/5

1/5 = 20%

Find the equation (in terms of x ) of the line through the points (-2,5) and (3,4)
y=

Answers

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[tex]y=-\frac{1}{5}x+\frac{23}{5}[/tex]

»»————- ★ ————-««  

Here’s why:  

We first need to find the slope of the equation.

⸻⸻⸻⸻

[tex]\boxed{\text{\underline{Slope Is...}}}\\\\\rightarrow\frac{y_2-y_1}{x_2-x_1}\\\\\boxed{\text{Key:}}\\\\\rightarrow (x_1,y_1)\text{ and }(x_2,y_2) - \text{Two Points Given}[/tex]

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the Slope...}}\\\\\rightarrow m=\frac{4-5}{3-(-2)}\\\\\rightarrow m=\frac{-1}{5}\\\\\rightarrow \boxed{m=-\frac{1}{5}}\\\\\\\text{The slope is } -\frac{1}{5}.[/tex]

⸻⸻⸻⸻

We then need to find the y-intercept of the equation.

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the intercept...}}\\\\y=-\frac{1}{5}x+b\\-------------\\\rightarrow 4 = -\frac{1}{5}(3) +b\\\\\rightarrow4= -\frac{3}{5}+b\\\\\rightarrow4+\frac{3}{5}= -\frac{3}{5}+\frac{3}{5} +b\\\\\rightarrow \boxed{\frac{23}{5}=b}[/tex]

⸻⸻⸻⸻

[tex]\text{The equation should be: }\boxed{ y=-\frac{1}{5}x+\frac{23}{5} }.[/tex]

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

What is the radius for the circle given by the equation x^2+(y-1)^2=12?

Round your answer to the nearest thousandth.

Answers

9514 1404 393

Answer:

  3.464

Step-by-step explanation:

Comparing the given equation to the standard form equation of a circle:

  (x -h)^2 +(y -k)^2 = r^2

we find the center to be (h, k) = (0, 1) and the radius to be √12 = 2√3.

The problem statement tells us to round the radius to the nearest thousandth, so it will be ...

  2√3 ≈ 3.4641016 ≈ 3.464 . . . radius of the circle

2hr 57min+3hrs42min​

Answers

Answer:

6 hrs 33 minutes

Step-by-step explanation:

 2hr 57min

+3hrs42min​

----------------------

5 hrs 99 minutes

But 1 hr = 60 minutes so subtract 60 minutes and add 1 hour

6 hrs 33 minutes

Answer:

6hr 39 min

Step-by-step explanation:

Add both

2hr 57 min

+ 3hr 42 min

5hr 99 min

we know that 1 hr = 60 min

then , 99 min = 1hr 39 min

so, 5hr + 1hr 39min

= 6hr 39 min

FIND THE ∛ OF 188

(USE √

Answers

9514 1404 393

Answer:

 ∛188 ≈ 5.72865

Step-by-step explanation:

Any scientific or graphing calculator or spreadsheet can tell you the cube root of 188.

  ∛188 ≈ 5.72865431598...

__

You know that 5³ = 125 and 6³ = 216, so the root will lie between 5 and 6, closer to 6. As a first approximation, you can figure it is about ...

  x = ∛188 ≈ 5 + (188-5³)/(6³ -5³) = 5 + 63/89 ≈ 5.71

You can figure this much using a 4-function calculator.

A closer approximation (x') can be had using the iteration formula ...

  x' = (2x³ +188)/(3x²)

For x = 5.71, the value of x' is ...

  x' ≈ (2×5.71³ +188)/(3×5.71²) ≈ 560.3388/97.8123 ≈ 5.7287

This value is correct when the root is rounded to 4 decimal places. Another execution of the iteration formula using this value will give the root accurate to 9 decimal places.

Use the formula v = IR for current flowing through a resistor, where V is the voltage in volts, I is current in amps, and R is resistance in ohms. Find the current through a resistor with resistance 15 ohms if the voltage across it is 3 volts.

Answers

Answer:

0.2 amps

Step-by-step explanation:

Given data

The formula V=IR is the formula for ohms law

Which state that  the voltage is directly proportional to the current and the resistance in an electric circuit

Now

R= 15 ohms

V= 3volts

V= IR

3= I*15

I= 3/15

I= 0.2 amps

Hence he current flowing is 0.2 amps

HELP PLEASE MATH PROBLEM

Answers

Answer:

x=41

Step-by-step explanation:

LM =JM

154=4x-10

154+10=4x

164=4x

164/4=4x/4

41=x

hope this is helpful

the third option , x=41 !!

GIVING OUR BRAINLIEST HELP ME PLEASE !! 10 PTS!

Answers

Answer:

The solution is D. x² + y² + 4x - 2y = -1

Step-by-step explanation:

The standard form of a circle with a center at (h,k) and a radius r is:

(x-h)² + (y-k)² = r²

Since the center is (-2,1) and the radius is

2, we know that:

h = -2k = 1r = 2

Thus, the equation of the circle is:

(x-(-2))² + (y-1)² = 2²

This simplifies to be

(x+2)² + (y-1)² = 4

The equation of the circle is:

(x+2)² + (y-1)² = 4

x²+4x+4+y²-2y+1 = 4

x²+y²+4x-2y+5 = 4

x²+y²+4x-2y = 4-5

x²+y²+4x-2y = -1

What is tan 30? A b c d e f

Answers

Answer:

try all the square roots and wichever gets to 0.58(rounded) is your answer

Step-by-step explanation:

the tangent of 30= 0.58

A positive real number is 4 less than another. if the sum of the squares of the two numbers is 72, then find the numbers

Answers

Answer:

x+4=72

x=72-4

x=68

Step-by-step explanation:

let x be one number and 4 be anothe number then sum of the two number be x and 4

Find the value for the side marked below.
Round your answer to the nearest tenth.
13
23°
у
у
[?]
Enter

Answers

Answer:

y = 30.96

Step-by-step explanation:

take 23 degree as reference angle

using tan rule

tan 23 = opposite / adjacent

0.42 = 13/y

y = 13/0.42

y = 30.96

Question 10 (1 point) Find the volume of the figure. 2.5 ft 3 ft 2 ft 6 ft. What is the volume of the figure?​

Answers

Answer:

I don’t know what type of figure you are talking about. But if there is supposed to be a picture attached, we see nothing

Step-by-step explanation:

You could repost this question though, I’ll be glad to help on that other question!

If a1 = 6 and an
-5an-1 + 4 then find the value of a4.

Answers

9514 1404 393

Answer:

  a4 = -666

Step-by-step explanation:

Use the recursive definition repeatedly.

  a1 = 6

  a2 = -5(6) +4 = -26

  a3 = -5(-26) +4 = 134

  a4 = -5(134) +4 = -666

Juan y rosa van a repartirse un pastel por partes iguales sin que sobre nada .Si de la fiesta sobró 3/4pastel .¿cuanto le tocó a cada uno?

Answers

Usando el método de polya:

a. Que se pregunta?

la fracción de cuánto obtendría cada uno de ellos y compartiría por igual.

b. ¿Cuáles son los datos dados?

¾ tarta, 2 personas (Juan y Rosa)

c. ¿Cuál es la operación que se utilizará?

división

d. oración numérica:

¾ ÷ 2

e. Solución y respuesta completa:

[tex] \frac{3}{4} \div 2 \\ = \frac{3}{4} \times \frac{1}{2} \\ = \frac{3}{8} [/tex]

explicación paso a paso:

Multiplica por el recíproco: Dividir es equivalente a multiplicar por el recíproco.Multiplicar: multiplica las fracciones

Forma decimal: 0.375

☆彡Hanna

#CarryOnLearning

An engineering consulting firm wanted to evaluate the diameter of rivet heads. The following data represent the diameters (in hundredths of an inch) for a random sample of 25 rivet heads:
(20 pts) 6.81 6.79 6.69 6.59 6.65 6.60 6.74 6.70 6.76 6.84 6.81 6.71 6.66 6.76 6.76 6.77 6.72 6.68 6.71 6.79 6.72 6.72 6.72 6.79 6.83
a. Set up a 95% confidence interval estimate of the average diameter of rivet heads (in hundredths of an inch)
b. Set up a 95% CI estimate of the standard deviation of the diameter rivet heads (in hundredths of an inch)

Answers

Answer:

a)CI 95 %  =  ( 6.7063  ;  6.7593)  ( in hundredths of an inch)

b) CI 95 %  =  ( 0.05 <  σ  <  0.089 ) ( in hundredths of an inch)

Step-by-step explanation:

From the problem statement, we have a manufacturing  process and we we assume a normal distribution, from sample data:

x =  6.7328        and  s  =  0.0644

a) CI 95 %  =  (  x ±  t(c) * s/√n )

t(c)    df =  n  -1    df  =  25 - 1     df = 24

CI  =  95 %   α = 5 %     α  = 0.05     α /2  =  0.025

Then  from t-student table   t(c) = 2.060

s/√n  =  0.0644/ √ 25      s/√n = 0.01288

CI 95 %  =  (  x ±  t(c) * s/√n )  =  ( 6.7328  ± 2.060*0.01288)

CI 95 %  = ( 6.7328 ±  0.02653 )

CI 95 %  =  ( 6.7063  ;  6.7593)  ( in hundredths of an inch)

b) CI 95 % of the variance  is:

CI 95 %  =  (  ( n - 1 ) * s² / χ²₁ - α/₂ ≤  σ²  ≤   ( n - 1 )*s² / χ²α/₂ )

( n - 1 ) * s²   = ( 25 - 1 ) * (0.0644)² =  24* 0.00414

( n - 1 ) * s²   = 0.09936

And from  χ²  table we look for values of

χ² α/₂ ,df    df = 24   and  α/2 =  0.025

χ² (0.025,24)  = 12.40      and    χ²₁ - α/₂  =   χ² (0.975, 24)

χ² (0.975, 24) = 39.36

Then

CI 95 %  = ( 0.09936 / 39.36  ≤  σ²  ≤   0.09936 / 12.40)

CI 95 %  = ( 0.0025  ≤   σ²  ≤  0.0080)

Then for the standard deviation,  we take the square root of that interval

CI 95 %  =  ( 0.05 <  σ  <  0.089 )

Last month Rudy’s Tacos sold 22 dinner specials. The next month they released a new commercial and sold 250% of last month’s dinners. How many dinner specials did they sell this month?

Answers

Answer:

the answer is 2

Step-by-step explanation: because 250 -22 is i dont even know

Answer:

55

Step-by-step explanation:

holaaaaaaaaaaaa plz help me i need it quick △SEA is rotated 270 degrees about the origin. Draw the image of this rotation.

Answers

Answer:

A will have this new coordinate (2, 1).

S will have this new coordinate (-2, 7).

E will have this new coordinate (2, 7).

Step-by-step explanation:

A is the coordinate (-1, 2).

S is the coordinate (-7, -2).

E is the coordinate (-7, 2).

To rotate that figure 270 grades (is the same to rotate 90 grades) we need to convert those coordinates to this (y, -x).

So,

A will have this new coordinate (2, 1).

S will have this new coordinate (-2, 7).

E will have this new coordinate (2, 7).

Solve the inequality c+12<16

Answers

Answer:

c+12<16

c=16-12

c=4

answer is this

Solve this for me guys

Answers

Answer:

x = 7.348

Step-by-step explanation:

I don't really know how to explain this over a computer, but it is correct. Answer credit of Omnicalculator.

Hope that this helps!

3. Betty rode her bike down a block that was 50 meters long. How many millimeters did she ride?​

Answers

Answer:

50,000 millimeters

Step-by-step explanation:

Hope this helps : ) I have no explanation but it's correct

what of the following functions is graphed below
being timed help quickly will mark brainliest !!!​

Answers

The correct answer is C

Dannette and Alphonso work for a computer repair company. They must include the time it takes to complete each repair in their repair log book. The dot plots show the number of hours each of their last 12 repairs took. Part a. Calculate the median, mean, IQR, and standard deviation of each data set. Part b. Which measure of central tendency and spread should you use to compare the two data sets? Explain your reasoning. Part c. Determine whether there are any outliers in either data set. Dannette's Repair Times х х X X X X Х Х + 9 + 1 0 Relations 2 3 4 8 10 12 5 6 7 Repair Time (hours) Geometry Alphonso's Repair Times Groups X Trigonometry X Х X X X х X х Statistics 7 X + 3 10 9 0 4 12 Series 8 1 2 5 7 Repair Time (hours) Greek​

PLZ HELP

Answers

Answer:

(a):

Dannette                   Alphonso

[tex]\bar x_D = 4.33[/tex]                    [tex]\bar x_A = 5.17[/tex]

[tex]M_D = 2.5[/tex]                    [tex]M_A = 5[/tex]

[tex]\sigma_D = 3.350[/tex]                  [tex]\sigma_A = 1.951[/tex]

[tex]IQR_D = 7[/tex]                  [tex]IQR_A = 1.5[/tex]

(b):

Measure of center: Median

Measure of spread: Interquartile range

(c):

There are no outliers in Dannette's dataset

There are outliers in Alphonso's dataset

Step-by-step explanation:

Given

See attachment for the appropriate data presentation

Solving (a): Mean, Median, Standard deviation and IQR of each

From the attached plots, we have:

IQR_A = 1.5 ---- Dannette

[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso

n = 12 --- number of dataset

Mean

The mean is calculated

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]

[tex]\bar x_D = \frac{52}{12}[/tex]

[tex]\bar x_D = 4.33[/tex] --- Dannette

[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]

[tex]\bar x_A = \frac{62}{12}[/tex]

[tex]\bar x_A = 5.17[/tex]  --- Alphonso

Median

The median is calculated as:

[tex]M = \frac{n + 1}{2}th[/tex]

[tex]M = \frac{12 + 1}{2}th[/tex]

[tex]M = \frac{13}{2}th[/tex]

[tex]M = 6.5th[/tex]

This implies that the median is the mean of the 6th and the 7th item.

So, we have:

[tex]M_D = \frac{2+3}{2}[/tex]

[tex]M_D = \frac{5}{2}[/tex]

[tex]M_D = 2.5[/tex] ---- Dannette

[tex]M_A = \frac{5+5}{2}[/tex]

[tex]M_A = \frac{10}{2}[/tex]

[tex]M_A = 5[/tex]  ---- Alphonso

Standard Deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]

[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]

[tex]\sigma_D = 3.350[/tex] ---- Dannette

[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]

[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]

[tex]\sigma_A = 1.951[/tex] --- Alphonso

The Interquartile Range (IQR)

This is calculated as:

[tex]IQR =Q_3 - Q_1[/tex]

Where

[tex]Q_3 \to[/tex] Upper Quartile       and        [tex]Q_1 \to[/tex] Lower Quartile

[tex]Q_3[/tex] is calculated as:

[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*13th[/tex]

[tex]Q_3 = 9.75th[/tex]

This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:

[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex]           [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]

[tex]Q_3 = 8[/tex] ---- Dannette                 [tex]Q_3 = 5.5[/tex] --- Alphonso

[tex]Q_1[/tex] is calculated as:

[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*13th[/tex]

[tex]Q_1 = 3.25th[/tex]

This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:

[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex]                  [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]

[tex]Q_1 = 1[/tex] --- Dannette                   [tex]Q_1 = 4[/tex] ---- Alphonso

So, the IQR is:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR_D = 8 - 1[/tex]                                     [tex]IQR_A = 5.5 - 4[/tex]

[tex]IQR_D = 7[/tex] --- Dannette                      [tex]IQR_A = 1.5[/tex] --- Alphonso

Solving (b): The measures to compare

Measure of  center

By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).

Since, the above is the case; we simply compare the median of both because it is not affected by outliers

Measure of  spread

Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.

Solving (c): Check for outlier

To check for outlier, we make use of the following formulas:

[tex]Lower =Q_1 - 1.5 * IQR[/tex]

[tex]Upper =Q_3 + 1.5 * IQR[/tex]

For Dannette:

[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]

[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]

Since, the dataset are all positive, we change the lower outlier to 0.

So, the valid data range are:

[tex]Valid = 0 \to 18.5[/tex]

From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset

For Alphonso:

[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]

[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]  

So, the valid data range are:

[tex]Valid = 1.75\to 7.75[/tex]

From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset

Triangle ABC is the pre-image and triangle DFE is the image.
What is the scale factor of the dilation?
Please helppp!!!!!

Answers

Answer:

Scale factor = ½

Step-by-step explanation:

The original image is the preimage = ∆ACB

The new image is the image = ∆DFE

The scale of factor of dilation = image/preimage = DF/AC

DF = 6 cm (given)

AC = 12 cm (given)

Plug in the values into the equation to find the scale factor of dilation:

Scale factor = 6/12

Scale factor = ½

The endpoints of a diameter are (-3,4) and (5,-2). What is the center of the circle?

Answers

(1,1) is the answer


Hope this helps!!

what are T-ratio ? explain

answer my question
plz​

Answers

Answer:

The t-ratio is the estimate divided by the standard error. With a large enough sample, t-ratios greater than 1.96 (in absolute value) suggest that your coefficient is statistically significantly different from 0 at the 95% confidence level. A threshold of 1.645 is used for 90% confidence.

Step-by-step explanation:

Hope it help you.

There are some Rs2 and Rs5 coins in a box. The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3. The value of all the Rs5 coins is Rs45. What is the value of all the Rs2 coins in the box?

Answers

Given:

The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.

The value of all the Rs5 coins is Rs45.

To find:

The value of all the Rs2 coins in the box.

Solution:

Let x be the number of Rs2 coins and y be the number of Rs5 coins.

The value of all the Rs5 coins is Rs45.

[tex]5y=45[/tex]

[tex]y=\dfrac{45}{5}[/tex]

[tex]y=9[/tex]

The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.

[tex]\dfrac{x}{y}=\dfrac{1}{3}[/tex]

[tex]\dfrac{x}{9}=\dfrac{1}{3}[/tex]

Multiply both sides by 9.

[tex]\dfrac{x}{9}\times 9=\dfrac{1}{3}\times 9[/tex]

[tex]x=3[/tex]

The value of all the Rs2 coins in the box is:

[tex]\text{Required value}=2x[/tex]

[tex]\text{Required value}=2(3)[/tex]

[tex]\text{Required value}=6[/tex]

Therefore, the value of all the Rs. 2 coins in the box is Rs. 6.

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