The slope of the line that passes through (5,-11) and (-9,17) is "-2".
The given points are:
[tex](x_1,y_1) = (5, -11)[/tex][tex](x_2,y_2) = (-9,17)[/tex]As we know the formula of slope (m),
= [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
By putting the given values in the formula, we get
= [tex]\frac{17-(-11)}{-9-5}[/tex]
= [tex]\frac{17+11}{-14}[/tex]
= [tex]\frac{28}{-14}[/tex]
= [tex]-2[/tex]
Thus the solution above is appropriate.
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