Answer:
2.2763 x 10 to the power of 4
for some reason it doesn't let me put in the explanation
30 POINTS
Help on Part B pleaseeee
In verse of B.g(x)=[tex]\frac{x+5}{4}[/tex] is:
4x-5
Answer:
Solution given:
B.g(x)=[tex]\frac{x+5}{4}[/tex]
let
g(x)=y
y=[tex]\frac{x+5}{4}[/tex]
Interchanging role of x and y
we get:
x=[tex]\frac{y+5}{4}[/tex]
doing crisscrossed multiplication
4x=y+5
y=4x-5
So
g-¹(x)=4x-5
Given that,
→ g(x) = x+5/4
Then g(x)=y,
→ y = x+5/4
Now we can interchange role of x and y,
→ x = y+5/4
Then use the cross multiplication,
→ 4x = y+5
→ y = 4x-5
Hence, g-¹(x) = 4x-5 is the solution.
1. Write 3.3.3.3.3 as a power.
Answer:
3^5
Step-by-step explanation:
On the iPad it looks like that but the five is on the top right smaller
Answer:
3⁵
every 3 has it own power that is 1 however that .3 confused us
The shaded region R in diagram below is enclosed by y-axis, y = x^2 - 1 and y = 3.
Determine the volume of the solid generated when the shaded region R is revolved
about x = -1 by using Disk method.
Cross sections of the volume are washers or annuli with outer radii x(y) + 1, where
y = x(y) ² - 1 ==> x(y) = √(y + 1)
and inner radii 1. The distance between the outermost edge of each shell to the axis of revolution is then 1 + √(y + 1), and the distance between the innermost edge of R on the y-axis to the axis of revolution is 1.
For each value of y in the interval [-1, 3], the corresponding cross section has an area of
π (1 + √(y + 1))² - π (1)² = π (2√(y + 1) + y + 1)
Then the volume of the solid is the integral of this area over [-1, 3]:
[tex]\displaystyle\int_{-1}^3\pi y\,\mathrm dy = \frac{\pi y^2}2\bigg|_{-1}^3 = \boxed{4\pi}[/tex]
[tex]\displaystyle\int_{-1}^3 \pi\left(2\sqrt{y+1}+y+1\right)\,\mathrm dy = \pi\left(\frac43(y+1)^{3/2}+\frac{y^2}2+y\right)\bigg|_{-1}^3 = \boxed{\frac{56\pi}3}[/tex]
what is the correct answer to my question ?
Answer:
13/17
Step-by-step explanation:
.Solve : 3 / 8 (x-5) = 11 -7x
Answer:
1.74 or [tex]\frac{103}{59}[/tex]
Step-by-step explanation:
3(x-5) = 8 (11-7x)
3x-15=88-56x
59x=103
x = 1.74
(a)234.3x13 (b) 31.38 X 5 (c) 0.653X 45 (d) 21.45X 10
(e) 25.41X 18 (f) 93.2 X 47 (g) 234.2X 342 (h) 89.4X20
(a)1.1 X 3.0 (b) 2.5 X 1.4 (c) 3.4X 4.6 (d) 2.4X4.8
(e) 2.6 X 12.3 (f) 6.72 X 56.1 (e) 24.59 X 31.2 (f) 27.15 X 3.7
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you have passed subject A, the probability of passing subject B is 0.8. Find the probability that the student passes both subjects? Find the probability that the student passes at least one of the two subjects
Answer:
0.64 = 64% probability that the student passes both subjects.
0.86 = 86% probability that the student passes at least one of the two subjects
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Passing subject A
Event B: Passing subject B
The probability of passing subject A is 0.8.
This means that [tex]P(A) = 0.8[/tex]
If you have passed subject A, the probability of passing subject B is 0.8.
This means that [tex]P(B|A) = 0.8[/tex]
Find the probability that the student passes both subjects?
This is [tex]P(A \cap B)[/tex]. So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64[/tex]
0.64 = 64% probability that the student passes both subjects.
Find the probability that the student passes at least one of the two subjects
This is:
[tex]p = P(A) + P(B) - P(A \cap B)[/tex]
Considering [tex]P(B) = 0.7[/tex], we have that:
[tex]p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86[/tex]
0.86 = 86% probability that the student passes at least one of the two subjects
which is the correct answer?
Answer:
11/12
Step-by-step explanation:
1/4 + 2/3
= 3/12 + 8/12
= 11/12
Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.
The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).
The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120
(0+2)^3*(0-3)*k = 120
-24k = 120
k = -5
Combining all three conditions, f(x)
= -5(x+2)^3*(x-3)
= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)
= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)
= -5(x^4 + 3x^3 - 6x^2 - 28x -24)
= -5x^4 - 15x^3 + 30x^2 + 140x + 120
Polinômio (2x+6y)(4x-2y)
Answer:
I'm pretty sure it's 8x^2+20xy-12y^2
Answer:
pff don't know . sssory
Step-by-step explanation:
What is the domain of D(t) as it applies in this situation?
Answer:
t could be all real numbers.
Step-by-step explanation:
The function D(t) is given by:
[tex]D(t)=-1.5t+12[/tex]
The domain is all the posible x-values for which the function is defined.
In our case, t could be all real numbers.
The answer is the first option.
I hope it helps you!
Which figure can be formed from the net?
pls answer fast for brainiest !
Answer:
It should be the top right one
(with 6ft as the height)
Step-by-step explanation:
Answer:
It must be the lower to the left choice.
Step-by-step explanation:
As you can see, the net we have is composed of only triangles.
So we should be choosing a figure with a triangular base.
Our answers are narrowed down into the top right and lower left choices because both figures have triangular bases.
The other person down there chose the top right choice and was incorrect, so the answer should be the lower to the left figure.
Also, its the lower left figure because look at the triangular base, it is an isosceles meaning that two sides have the same length.
If the net says that the long side measures 9 ft, then the other two sides should be the same length and shorter than 9 ft. So the answer is the lower left figure.
Hope this helps
if i need 90 square feet of tile and each piece of tile covers 0.34 square feet, how much do i need in pieces
Answer:
265
Step-by-step explanation:
9514 1404 393
Answer:
265
Step-by-step explanation:
Let t represent the number of tiles needed. Then the area covered by those t tiles will be ...
area = t·0.34 ft²
We want that area to be 90 ft², so we can solve this equation for t:
90 ft² = t·(0.34 ft²)
90 ft²/(0.34 ft²) = t ≈ 264.71
About 265 tiles are needed to cover 90 ft².
find the LCM of ;
(1+4x+4x2-16x) and (1+2x-8x3-16x4)
Answer:
16x4−4x2+4x−116x4−4x2+4x−1
=16x4−(4x2−4x+1)=16x4−(4x2−4x+1)
=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2=(4x2)2−(2x−1)2∵a2−2ab+b2=(a−b)2
=(4x2−2x+1)(4x2+2x−1)∵a2−b2=(a−b)(a+b
Step-by-step explanation:
You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 95% confidence level and a margin of error of 2%. A pilot survey reveals that 5 of the 50 sampled hold two or more jobs.
How many in the workforce should be interviewed to meet your requirements? (Round up your answer to the next whole number.)
Answer:
865 in the workforce should be interviewed to meet your requirements
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
A pilot survey reveals that 5 of the 50 sampled hold two or more jobs.
This means that [tex]\pi = \frac{5}{50} = 0.1[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
How many in the workforce should be interviewed to meet your requirements?
Margin of error of 2%, so n for which M = 0.02.
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.02 = 1.96\sqrt{\frac{0.1*0.9}{n}}[/tex]
[tex]0.02\sqrt{n} = 1.96\sqrt{0.1*0.9}[/tex]
[tex]\sqrt{n} = \frac{1.96\sqrt{0.1*0.9}}{0.02}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96\sqrt{0.1*0.9}}{0.02})^2[/tex]
[tex]n = 864.4[/tex]
Rounding up:
865 in the workforce should be interviewed to meet your requirements
Consider the quadratic function F(x)=-x^2-x+20
The line of symmetry has the equation ?
Answer:
[tex]x = - \frac{1}{2} [/tex]
Step-by-step explanation:
[tex]x = \frac{ - b}{2a} = \frac{1}{ - 2} [/tex]
Please help me there’s a image above.
Answer:
4,-1 that is the answer so
The data set shows the number of players on each softball team in a tournament:
9
12
8
7
7
21
11
9
8
7
10
7
10
11
Which of the following statements is true based on the data set?
There is one outlier that indicates an unusually large number of players on that team.
There are two outliers that indicate an unusually large number of players on those two teams.
There is one outlier that indicates an unusually small number of players on that team.
There are two outliers that indicate an unusually small number of players on those two teams.
1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute.
a. What is the mean or expected number of customers that will arrive in a five-minute period?
b. Assume that the Poisson probability distribution can be used to describe the arrival process. Use the arrival rate in part (a) and compute the probabilities that exactly 0, 1, 2, and 3 customers will arrive during a five-minute period.
c. Delays are expected if more than three customers arrive during any five-minute period. What is the probability that delays will occur?
2. In the Willow Brook National Bank waiting line system (see Problem 1), assume that the service times for the drive-up teller follow an exponential probability distribution with a service rate of 36 customers per hour, or 0.6 customers per minute. Use the exponential probability distribution to answer the following questions:
a. What is the probability that the service time is one minute or less?
b. What is the probability that the service time is two minutes or less?
c. What is the probability that the service time is more than two minutes?
Answer:
1.
a. 2
b. 0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.
c. 0.1428 = 14.28% probability that delays will occur.
2.
a. 0.4512 = 45.12% probability that the service time is one minute or less.
b. 0.6988 = 69.88% probability that the service time is two minutes or less.
c. 0.3012 = 30.12% probability that the service time is more than two minutes.
Step-by-step explanation:
Poisson distribution:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Question 1:
a. What is the mean or expected number of customers that will arrive in a five-minute period?
0.4 customers per minute, so for 5 minutes:
[tex]\mu = 0.4*5 = 2[/tex]
So 2 is the answer.
Question b:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]
[tex]P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707[/tex]
[tex]P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707[/tex]
[tex]P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1805[/tex]
0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.
Question c:
This is:
[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]
In which:
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
The values we have in item b, so:
[tex]P(X \leq 3) = 0.1353 + 0.2707 + 0.2707 + 0.1805 = 0.8572[/tex]
[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8572 = 0.1428[/tex]
0.1428 = 14.28% probability that delays will occur.
Question 2:
[tex]\mu = 0.6[/tex]
a. What is the probability that the service time is one minute or less?
[tex]P(X \leq 1) = 1 - e^{-0.6} = 0.4512[/tex]
0.4512 = 45.12% probability that the service time is one minute or less.
b. What is the probability that the service time is two minutes or less?
[tex]P(X \leq 2) = 1 - e^{-0.6(2)} = 1 - e^{-1.2} = 0.6988[/tex]
0.6988 = 69.88% probability that the service time is two minutes or less.
c. What is the probability that the service time is more than two minutes?
[tex]P(X > 2) = e^{-1.2} = 0.3012[/tex]
0.3012 = 30.12% probability that the service time is more than two minutes.
One number is 2/3 of another number. The sum of the two numbers is 40. Find
the two numbers.
Answer:
5353454
Step-by-step explanation:
Answer: 16 and 24
Step-by-step explanation:
2x+3x= 40
5x = 40
x=8
that means 2x8 equal 16 and 3x8 equals 24 which leads us to the answer
What is the volume of the triangular prism shown below?
10
A. 100 cu. units
B. 200 cu. units
C. 400 cu. units
D. 300 cu. units
Answer:
B. 200 cu. units
Step-by-step explanation:
Volume of the triangular prism = ½*b*h*l
Where,
b = 8 units
h = 5 units
l = 10 units
Plug in the values
Volume of the prism = ½*8*5*10
= 4*5*10
= 200 cu. units
A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 5 answer choices - a, b, c, d, e- and only one correct answer. What is the probability that she answered neither of the problems correctly? Do not round your answer. (If necessary, consult a list of formulas.)
Answer:
there is a 64% chance that the student got both problems wrong
a 32% chance that they got only 1 correct
and a 4% chance that they got both correct
Step-by-step explanation:
There are 25 total possible combinations of answers, with 8 possible combinations where the student would get 1 answer right, and 1 combination where the student would get both answers correct.
[tex]25-9=16[/tex]
[tex]\frac{16}{25} =\frac{x}{100}[/tex]
[tex]\frac{64}{100}[/tex]
[tex]64[/tex]%
[tex]\frac{8}{25} =\frac{y}{100}[/tex]
[tex]\frac{32}{100}[/tex]
[tex]32[/tex]%
[tex]\frac{1}{25} =\frac{z}{100}[/tex]
[tex]\frac{4}{100}[/tex]
[tex]4[/tex]%
(3a+2b-4c)+(3a+2b-4c)
6
+
4
−
8
Step-by-step explanation:
Please mark me as brain list and please like my answer and rate also
Answer:
hope this will help you more
We have 9 pens, of which 5 are green ink, 3 are red ink, and 1 is black. If we put the pens in a line, how many arrangements are possible
Answer:
504 arrangements are possible
Step-by-step explanation:
Arrangements of n elements:
The number of arrangements of n elements is given by:
[tex]A_{n} = n![/tex]
Arrangements of n elements, divided into groups:
The number of arrangements of n elements, divided into groups of [tex]n_1, n_2,...,n_n[/tex] elements is given by:
[tex]A_{n}^{n_1,n_2,...,n_n} = \frac{n!}{n_1!n_2!...n_n!}[/tex]
In this case:
9 pens, into groups of 5, 3 and 1. So
[tex]A_{9}^{5,3,1} = \frac{9!}{5!3!1!} = 504[/tex]
504 arrangements are possible
What is 5.071 in words?
Answer:
Step-by-step explanation:
The number 5.071 written in english words is "five and seventy-one thousandths
Martina made$391for17hours of work. At the same rate, how many hours would she have to work to make$253? a 11 hours b 9 hours c 22 hours d 33 hours
Answer:
11 hours is right answer i hope it will help you
what is the inverse of the function shown
Step-by-step explanation:
the down function clearly is
y = x - 5, -2 <= x <= 8
the reasons :
1. it is linear. so, we have only a form of ax+b
2. x=0 => y=-5
x=5 => y=0
so, with these 2 points alone we can see
y = ax + b
-5 = a×0 +b = b
0 = a×5 - 5
5 = a×5
1 = a
the inverse function is based on
y = x - 5
=>
x = y + 5
now renaming the variables so that y is the result and x the input variable delivers
y = x + 5
and because the original function only delivered y- values between -7 and +3, this is also the defined domain for the inverse function.
so,
y = x + 5, -7 <= x <= +3
so, we have the points
x=-7 => y=-2
x=+3 => y=8
you need to draw the line between these 2 points with filled dots at the end points (as they are included in the function).
A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers the color green. If 14 buyers are randomly selected, what is the probability that exactly 12 buyers would prefer green
Answer:
The probability that exactly 12 buyers would prefer green
=0.00555
Step-by-step explanation:
We are given that
p=50%=50/100=0.50
n=14
We have to find the probability that exactly 12 buyers would prefer green.
q=1-p
q=1-0.50=0.50
Using binomial distribution formula
[tex]P(X=x)=nC_r p^r q^{n-r}[/tex]
[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^{14-12}[/tex]
[tex]P(x=12)=14C_{12}(0.50)^{12}(0.50)^2[/tex]
[tex]P(x=12)=14C_{12}(0.50)^{14}[/tex]
[tex]P(x=12)=\frac{14!}{12!2!}(0.50)^{14}[/tex]
[tex]P(x=12)=\frac{14\times 13\times 12!}{12!2\times 1}(0.50)^{14}[/tex]
[tex]P(x=12)=91\cdot (0.50)^{14}[/tex]
[tex]P(x=12)=0.00555[/tex]
Hence, the probability that exactly 12 buyers would prefer green
=0.00555
please answer me as soon as posible
Answer:
yes your answer is right
Answer:
Yes it's Perfectly correct
Find the values of the sine, cosine, and tangent for ZA C A 36ft B
24ft
Find the values of the sine, cosine, and tangent for ∠A
a. sin A = [tex]\frac{\sqrt{13} }{2}[/tex], cos A = [tex]\frac{\sqrt{13} }{3}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
b. sin A = [tex]3\frac{\sqrt{13} }{13}[/tex], cos A = [tex]2\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{3}{2}[/tex]
c. sin A = [tex]\frac{\sqrt{13} }{3}[/tex], cos A = [tex]\frac{\sqrt{13} }{2}[/tex], tan A = [tex]\frac{3}{2}[/tex]
d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex], cos A = [tex]3\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
Answer:d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex], cos A = [tex]3\frac{\sqrt{13} }{13}[/tex], tan A = [tex]\frac{2 }{3}[/tex]
Step-by-step explanation:The triangle for the question has been attached to this response.
As shown in the triangle;
AC = 36ft
BC = 24ft
ACB = 90°
To calculate the values of the sine, cosine, and tangent of ∠A;
i. First calculate the value of the missing side AB.
Using Pythagoras' theorem;
⇒ (AB)² = (AC)² + (BC)²
Substitute the values of AC and BC
⇒ (AB)² = (36)² + (24)²
Solve for AB
⇒ (AB)² = 1296 + 576
⇒ (AB)² = 1872
⇒ AB = [tex]\sqrt{1872}[/tex]
⇒ AB = [tex]12\sqrt{13}[/tex] ft
From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of [tex]12\sqrt{13}[/tex] ft (43.27ft).
ii. Calculate the sine of ∠A (i.e sin A)
The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e
sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex] -------------(i)
In this case,
Ф = A
opposite = 24ft (This is the opposite side to angle A)
hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)
Substitute these values into equation (i) as follows;
sin A = [tex]\frac{24}{12\sqrt{13} }[/tex]
sin A = [tex]\frac{2}{\sqrt{13}}[/tex]
Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]
sin A = [tex]\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]
sin A = [tex]\frac{2\sqrt{13} }{13}[/tex]
iii. Calculate the cosine of ∠A (i.e cos A)
The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e
cos Ф = [tex]\frac{adjacent}{hypotenuse}[/tex] -------------(ii)
In this case,
Ф = A
adjacent = 36ft (This is the adjecent side to angle A)
hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)
Substitute these values into equation (ii) as follows;
cos A = [tex]\frac{36}{12\sqrt{13} }[/tex]
cos A = [tex]\frac{3}{\sqrt{13}}[/tex]
Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]
cos A = [tex]\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]
cos A = [tex]\frac{3\sqrt{13} }{13}[/tex]
iii. Calculate the tangent of ∠A (i.e tan A)
The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e
tan Ф = [tex]\frac{opposite}{adjacent}[/tex] -------------(iii)
In this case,
Ф = A
opposite = 24 ft (This is the opposite side to angle A)
adjacent = 36 ft (This is the adjacent side to angle A)
Substitute these values into equation (iii) as follows;
tan A = [tex]\frac{24}{36}[/tex]
tan A = [tex]\frac{2}{3}[/tex]