Coulomb, unit of electric charge in the metre-kilogram-second-ampere system, the basis of the SI system of physical units. ... The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.
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A ball of mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? (Gravity being equal to 9.8)
Answer:
Explanation:
Mass doesn't matter here because when something is falling, gravity plays fairly; an elephant falls at the same rate of acceleration as does a feather. What DOES matter is everything pertinent to the y-dimension of free-fall:
a = -9.8 m/s/s
v₀ = 0 (since the ball was held before it was dropped)
v = ??
Δx = -8 m (negative because the ball drops this far below the point from which it was released).
Putting all this together in one equation:
v² = v₀² + 2aΔx and filling in this equation:
v² = (0)² + 2(-9.8)(-8) and
v² = 156.8 so
v = 12.5 which rounds to 13 if you're using 2 sig figs, and rounds to 10 if you're only using 1 (which you should be, according to the way the numbers have been given in this problem)
Put the steps of the scientific method in order
Astronomers observe the Small Magellanic Cloud (SMC), a not very dense, rather small galaxy near us. They notice that even those stars that formed recently have relatively few heavier elements (when compared to such recent stars in our Milky Way.) What is the likely explanation for this deficiency
Answer:
The reason it has few heavier elements is due to the fact that it's stars are widely spaced and this implies that it's stars have very low rate of formation and termination.
Explanation:
The Small Magellanic Cloud, is basically a very tiny galaxy located near the Milky Way. Although it's tiny, it's diameter is approximately 7,000 light-years while it also contains over hundred million stars which are widely spaced.
Now, the reason it has few heavier elements is due to the fact that it's stars are widely spaced and this implies that it's stars have very low rate of formation and termination.
The difference between starting and ending
positions is
distance
displacement
Answer:
displacement
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.
Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, position, displacement, etc.
Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.
This ultimately implies that, the difference between the starting and ending positions of a physical object is generally referred to as displacement
Two planets are separated by a distance of 4.5x108 m. One of the planets has a mass of 2.1x1021 kg. The force of attraction between the planets is 5x1024 N. What is the mass of the other planet? (Be careful with your algebra!)
Answer:
The mass of the other planet is 7.23*10^(30) kg
Explanation:
For two objects of masses m₁ and m₂ respectively, separated by a distance r, the gravitational force between them is given by:
F = G*(m₁*m₂)/r^2
Where G = 6.67*10^(-11) m^3/(kg*s^2)
Here, we know that:
r = 4.5*10^8m
m₁ = 2.1*10^21 kg
F = 5*10^24 N
And we want to find the mass of the other planet, first, let's isolate m₂ in the force equation:
(F*r^2)/(G*m₁) = m₂
Now we can replace all the values that we know in the left side, and solve it:
m₂ =[(5*10^24 N)*( 4.5*10^8m)^2]/[6.67*10^(-11) m^3/(kg*s^2)*2.1*10^21 kg]
m₂ = 7.23*10^(30) kg
The mass of the other planet is 7.23*10^(30) kg
If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The radius of the earth is 6400km and the value of g on the earth surface is 9.8m/s2.
Answer:
Hmm, Well I am pretty sure the answer is 288N
Explanation:
I got the answer 288N but I am not sure if that is correct. Hope it helps! :D
Define couple and give 2 examples
Answer:
Two equal and opposite parallel forces not acting along the same line, form a couple. A couple is always needed to produce the rotation.
For example, turning a key in a lock and turning a steering wheel.
please help me with this question
Answer:
1. 12 V
2a. R₁ = 4 Ω
2b. V₁ = 4 V
3a. A = 1.5 A
3b. R₂ = 4 Ω
4. Diagram is not complete
Explanation:
1. Determination of V
Current (I) = 2 A
Resistor (R) = 6 Ω
Voltage (V) =?
V = IR
V = 2 × 6
V = 12 V
2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:
Voltage (V) = 12 V
Current (I) = 1 A
Equivalent resistance (R) =?
V = IR
12 = 1 × R
R = 12 Ω
a. Determination of R₁
Equivalent resistance (R) = 12 Ω
Resistor 2 (R₂) = 8 Ω
Resistor 1 (R₁) =?
R = R₁ + R₂ (series arrangement)
12 = R₁ + 8
Collect like terms
12 – 8 =
4 = R₁
R₁ = 4 Ω
b. Determination of V₁
Current (I) = 1 A
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) =?
V₁ = IR₁
V₁ = 1 × 4
V₁ = 4 V
3a. Determination of the current.
Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) = 6 V
Current (I) =?
V₁ = IR₁
6 = 4 × I
Divide both side by 4
I = 6 / 4
I = 1.5 A
Thus, the ammeter (A) reading is 1.5 A
b. Determination of R₂
We'll begin by calculating the voltage cross R₂. This can be obtained as follow:
Total voltage (V) = 12 V
Voltage 1 (V₁) = 6 V
Voltage 2 (V₂) =?
V = V₁ + V₂ (series arrangement)
12 = 6 + V₂
Collect like terms
12 – 6 = V₂
6 = V₂
V₂ = 6 V
Finally, we shall determine R₂. This can be obtained as follow:
Voltage 2 (V₂) = 6 V
Current (I) = 1.5 A
Resistor 2 (R₂) =?
V₂ = IR₂
6 = 1.5 × R₂
Divide both side by 1.5
R₂ = 6 / 1.5
R₂ = 4 Ω
4. The diagram is not complete
An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.033 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.
Answer:
(a) Both the charges are positive or negative.
(b) Teh value of each charge is 1.53 x 10^-5 C.
Explanation:
Spring constant, K = 340 N/m
Natural length, L = 0.4 m
stretch, y = 0.033 m
(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.
(b) The electrostatic force is balanced by the spring force.
[tex]\frac{kq^2}{(L + y)^2}=Ky\\\\\\\frac{9\times 10^9 q^2}{(0.4 +0.033)^2} = 340\times0.033\\\\q= 1.53\times 10^{-5} C[/tex]
The Earth orbits around the sun because the gravitational force that the sun
exerts on the Earth:
O A. causes Earth's acceleration toward the sun.
O B. is very small because the sun is so far from the Earth.
O c. is smaller than the force the Earth exerts on the sun.
O D. pushes the Earth away from the sun.
The Earth orbits around the sun because the gravitational force that the sun
exerts on the Earth:
O A. causes Earth's acceleration toward the sun.
O B. is very small because the sun is so far from the Earth.
O c. is smaller than the force the Earth exerts on the sun.
O D. pushes the Earth away from the sun.
Answer -:O A. causes Earth's acceleration toward the sun.
I hope this helps, have a nice time ahead!
In a second order lever system the force ratio is 2.5, the load is at the distance of 0.5m from the fulcrum find distance of effort if it losses are negligible
Answer:
1.25 m
Explanation:
From the question given above, the following data were obtained:
Force ratio = 2.5
Distance of load from the fulcrum = 0.5 m
Distance of effort =.?
The distance of the effort from the fulcrum can be obtained as illustrated below:
Force ratio = Distance of effort / Distance of load
2.5 = Distance of effort / 0.5
Cross multiply
Distance of effort = 2.5 × 0.5
Distance of effort = 1.25 m
Therefore, the distance of the effort from the fulcrum is 1.25 m
write any two difference between CGS and MKS system of measurement ?
Answer:
MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.
Calculate the gravitational force between two bodies of masses 10kg and 55kg, if they are placed at a distance of 2m apart.
Answer:
F = 9.177*10^-9N
Explanation:
Gravitational force between the two bodies is expressed as;
F = GMm/r²
Given tha
M = 55kg
m = 10kg
r = 2m
G = 6.67408 × 10-11 m³ kg-1 s-2
Substitute;
F = GMm/r²
F = 6.67408 × 10-11*55*10/2²
F = 3,670.744× 10-11/4
F = 9.177*10^-9N
A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 49.0 cm/s . What are You may want to review (Pages 400 - 401) . Part A The amplitude of the subsequent oscillations
Answer:
The amplitude of the subsequent oscillations is 13.3 cm
Explanation:
Given;
mass of the block, m = 1.25 kg
spring constant, k = 17 N/m
speed of the block, v = 49 cm/s = 0.49 m/s
To determine the amplitude of the oscillation.
Apply the principle of conservation of energy;
maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced
[tex]K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A = \sqrt{\frac{1.25\ \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm[/tex]
Therefore, the amplitude of the subsequent oscillations is 13.3 cm
If the particles that make up an object begin to move quickly, their average kinetic energy _____ and the object's temperature _____. Group of answer choices
Explanation:
If the particles that make up an object begin to move quickly, their average kinetic energy increases the object's temperature rises. Group of answer choices
prove that vector addition obeys commutative and associative laws
the order of vector addition doesn't affect the resultant vector and grouping or order of pair doesn't effect the sum.
Noticing large amounts of algal growth in her small farm pond, a farmer adds about 20 grass carp to feed on the abundant algae and plants. After several years, the carp grow large, exceeding 20 pounds each in size. Late one summer, the farmer notices that the carp and most of the other fish are dead. The water also smells very bad. Which one of the following is the most likely explanation for the death of these fish?
A. the algae overgrew the pond and produced toxic levels of ozone
B. carbon dioxide released by the carp and algae eventually suffocated the fish in the pond
C. the large carp grew so large that they could not get enough oxygen
D. bacteria feeding on the large volume of carp feces depleted the oxygen
Answer:
D. bacteria feeding on the large volume of carp feces depleted the oxygen
Explanation:
In the context, it is given that in a small farm pond, the owner added 20 grass carp and feed them with the abundant plants and algae that is found on her pond. The carp grew large after many years but one summer the owner found the grass carps along with other fishes were dead.
The most possible explanation for the dead of the fishes in the pond because the bacteria feeds on the carp feces which depletes the dissolved oxygen present in the water. Thus the fishes could not breathe and were finally dead.
Therefore, the correct option is (D).
1. Priya is responsible for collecting canned food along three different streets for her school's
annual Thanksgiving Food
Drive. She walks 300 m [N] along Oak Road, 500 m [E] along
Second Street, and then 150 m (S45°W) along Cross Ave. She completes the journey in 10
minutes
a. Draw a scale diagram of her trip.
b. Calculate her total distance, displacement, speed, and velocity.
Answer:
distance = 950 m
displacement = 439.2 m
speed= 1.58 m/s
velocity = 0.732 m/s
Explanation:
A = 300 m North
B = 500 m East
C = 150 m South west
Time, t = 10 minutes = 600 s
(A) The diagram is given below.
(B) Total distance = 300+ 500 + 150 = 950 m
[tex]A = 300 \widehat{j} \\\\B = 500\widehat{i}\\\\C = - 150 (cos 45 i+ sin 45 j) = - 106 \widehat{i} - 106 \widehat{j}\\\\D = A + B + C \\\\D = 394 \widehat{i} + 194 \widehat{j}\\\\D=\sqrt{394^2 +194^2} = 439.2 m[/tex]
Speed = distance / time = 950/600 = 1.58 m/s
velocity = 439.2 / 600 = 0.732 m/s
Presence of _______- in retina gives us night vision that is help us to see in dim light.Required to answer. Single choice. Immersive Reader (1 Point) cornea retina lens rods
Answer: Rods
Explanation:
The rod cells in the retina are the reason we are able to see at night and in dim light. They exist on the edges of the retina which is why they are also very useful for the peripheral vision of a human.
Rod cells number over 90 million in the eyes and although very useful for seeing in dimmer light, they are not very useful for color vision which is why humans see less colors in the dark.
Answer the question plz
Answer:
b and d
Explanation:
A screw Jack whose pitch is 2mm is used to raise a bus of mass 900kg through height of 20cm. The length of the Tommy of the Tommy of the jack is 40cm. Calculate the velocity ratio of the machine
R= 40cm —> R= 0.4 m
P= 2mm —> P= 0.002 m
[tex]V.R = \frac{2πR}{p} = \frac{2 \times 3.14 \times 0.4}{0.002} = 1256[/tex]
I think this is the answer
I hope I helped you
Good luck ^_^
Compare the vertical and horizontal components of velocity for a ball launched at an angle on a level surface. How do the vertical and horizontal components of the ball's velocities change as it travels through the air?
Answer:
horizontal velocity remaing constan thorough out the motion but the vertical motion's velocity changes due to the gravity acting on it.
for everl 1 second the velocity decreases by 9.8 that is the gravity
A 72 kg swimmer dives horizontally off a raft floating in a lake. The diver's speed immediately after leaving the raft is 3.8 m/s. If the time interval of the interaction between the diver and the raft is 0.25 s, what is the magnitude of the average horizontal force by diver on the raft?
Answer:
F = 1094.4 N
Explanation:
From impulse - momentum theorem, we now that ;
Impulse = momentum
Where;
Formula for impulse = force (F) × time(t)
Momentum = mass(m) × velocity(v)
Now, we are given;
Mass of swimmer; m = 72 kg
Speed; v = 3.8 m/s
Time; t = 0.25 s
Thus;
F × t = mv
F = mv/t
F = (72 × 3.8)/0.25
F = 1094.4 N
This value of force is the magnitude of the average horizontal force by diver on the raft.
In the diagram, q1 = +2.00 x 10-5 C,
q2 = +3.80 x 10-6 C, and q3 = +5.30 x 10-5 C.
What is the electric potential energy, Ue, for
charge qy? Include the correct sign (+ or -).
Answer:
U = 3.59 10⁻⁹ J
Explanation:
Electric potential energy is
U = k ∑ [tex]\frac{q_iq_j }{r_i_j}[/tex]
in this case
U = k (q₁q₂ / r₁₂ + q₁q₃ / r₁₃ + q₂q₃ / r₂₃)
the distances are
r₁₂ = 1.15
r₁₃ = 1.15 +2.88 = 4.03 m
r₂₃23 = 2.88
we substitute
U = 9 109 (2 10-5 3.8 10-6 / 1.15 + 2 10-5 5.30 10-5 / 4.03 + 3.8010-6 53 010-5 / 2.88)
U = 9 109 (6.609 10-11 + 2.63 10-10 + 6.99 10-11)
U = 9 109 (39,899 10-11)
U = 3.59 10⁻⁹ J
Answer:
Q2 = 0.0346 J
Explanation:
I don't know what Q1 is but I did solve for Q2. I'm using this because no other question has been asked to solve for Q2 :)
Which of the following is a primary source?
The answer is C :), I think.
A scientific paper is the primary source. A primary source is an item, document, recording, or any other source. Option C is correct.
What is a scientific paper ?Scientific papers are a specific sort of written work with certain characteristics: they are often published in a periodical called a journal, whose sole objective is to publish this type of work.
A primary source is an item, document, recording, or any other source of information created during the period being studied in the academic area of history.
A scientific paper is the primary source.
Hence,option C is correct.
To learn more about the scientific paper, refer:
https://brainly.com/question/1716162
#SPJ2
What is the dependent variable in this
experiment?
DONE
Biologists designed an experiment to test
the effect of compost on the development
of root crops. They tested several different
crops, including carrots, potatoes, beets,
and onions. They grew most of the plants
in the greenhouse, but due to space issues,
they had to grow some outdoors. They gave
all the plants the same amount of compost.
They obtained the compost from a local
farmer and from the local hardware store.
They ran out of the farmer's compost, so
some of the plants received that compost
when the seeds were planted and other
plants got hardware store compost after
the plants had already started growing.
What is the independent variable in this
experiment?
DONE
Answer:
"the plants had already started growing."
Explanation:
I think this is the answer because the definition of a dependent variable is the variable that is being affected by the change. Since the plants had already started growing BECAUSE of "They ran out of the farmer's compost, so
some of the plants received that compost
when the seeds were planted and other
plants got hardware store compost after
the plants had already started growing."
Sorry if I am wrong, I am just a 4th grader, pls don't hate on me, I am just trying to help :)
Answer:
It's compost
Explanation:
In case you needed the dependent variable, its the amount of plant growth
Which plate is the South American plate?
A
B
C
D
Answer: B
Explanation: I think that it is B.
A stone attached to a string is whirled round in a horizontal circle with constant speed of 10m/s .Calculate the difference in the velocity with the stone is at
I) opposite ends of a diameter
Ii) in two positions A and B where angle AOB is 90° & O is the centre of the circle
Answer:
Stop going on peoples pages and answering random things kid, get a life
Learn to solve problems instead
Explanation:
I answered this because this kid just goes on random pages, and answers incorrectly for points. Check this egirl wannabe's profile
1.The distance moved by objects in a given interval of time can help us to decide which one is faster or slower. Do you agree with this statement?
Answer:
The rate of change of distance is defined as speed.
Explanation:
The speed is defined as the rate of change of distance.
Speed = distance/ time
When we know the distance and the time, we get the value of speed. So, e know that who is moving fast or slow.
hen a graph is pltted beteen the distance and time, the slope of the graph gives the value of speed. So, by checking the slopes, hoseslope ismore, the speed is more and thusit is moving faster.
So, i agree with the statement.
A body weighing 50 N is placed on a wooden table. How much force is required to set it into motion? Coefficient of friction between the table and the body is 0.3.
If the coefficient of static friction is 0.3, then the minimum force required to get it moving is equal in magnitude to the maximum static friction that can hold the body in place.
By Newton's second law,
• the net vertical force is 0, since the body doesn't move up or down, and in particular
∑ F = n - mg = n - 50 N = 0 ==> n = 50 N
where n is the magnitude of the normal force; and
• the net horizontal force is also 0, since static friction keeps the body from moving, with
∑ F = F' - f = F' - µn = F' - 0.3 (50 N) = 0 ==> F' = 15 N
where F' is the magnitude of the applied force, f is the magnitude of static friction, and µ is the friction coefficient.