What is the mass in grams of 2.4 x 10-2 mol K2SO4

Answer. After cytokinesis is completed at end of meiosis - I two haploid cells are formed.on:

Answer:

C. TWO HAPLOID CELLS ARE FORMED

Explanation:

I TOOK THE EDGUNITY TEST AND I GOT IT CORRECT

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

Answer:

A-protons, B-nucleus, D-electrons, C-nucleus, E-electric cloud

Explanation:

Answer:

No

Explanation:

Henry’s law is a gas law which states that at the amount of gas that is dissolved in a liquid is directly proportional to the partial pressure of that gas above the liquid when the temperature is kept constant. The constant of proportionality for this relationship is called Henry’s law constant (usually denoted by ‘kH‘). The mathematical formula of Henry’s law is given by:

P ∝ C (or) P = kH.C

Where,‘

Limitations of Henry’s Law

Answer:

Required heat = 2,259.36 N (approx)

Explanation:

Given:

Mass = 135 g

Specific heat (c) =4.184 J/gC

Change in temperature ΔT = 27-23 = 4 c

Find:

Required heat

Computation:

Q = mcΔT

Q = (135)(4.184)(4)

Required heat = 2,259.36 N (approx)

The heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J

To solve this question, we'll begin by calculating the change in the temperature of the reservoir. This can be obtained as follow:

Initial temperature (T₁) = 23 °C

Final temperature (T₂) = 27 °C

ΔT = T₂ – T₁

ΔT = 27 – 23

Finally, we shall determine the heat transferred to the reservoir.

Change in temperature (ΔT) = 4 °C

Mass (M) = 135 g

Specific heat capacity (C) = 4.184 J/gºC

Q = MCΔT

Q = 135 × 4.184 × 4

Therefore, the heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J

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Answer:

Sugar can't enter cells directly , so when blood sugar level rises, ... signal for the release of insulin into the bloodstream.

Explanation:

yes when the sugar enter the bloodstream it may slowly slowly effect in your body and it may causes diabetes

Answer:

true

Explanation:

hope it helps

Answer:

I'm pretty sure it's true

Explanation:

20 characters

Answer:

stratosphere

Explanation:

contains a high concentration of ozone in relation to other parts of the atmosphere, although still small in relation to other gases in the stratosphere.

Answer:

stratosphere

Explanation: Most atmospheric ozone is concentrated in a layer in the stratosphere, about 9 to 18 miles (15 to 30 km) above the Earth's surface. Ozone is a molecule that contains three oxygen atoms.

Answer:

The molecular formula of the hydrocarbon is C10H10

Explanation:

Here, we are interested in finding the molecular formula for the hydrocarbon.

Since there are equal number of moles of carbon and hydrogen, then we have the molecular formula looking like;

CnHn

Kindly recall that the atomic mass of carbon is 12 a.m.u while that of hydrogen is 1 amu

so calculating the atomic mass of the compound, we have;

12(n) + 1(n) = 130.18

13n = 130.18

n = 130.18/13

n = 10.01

So the molecular formula will be C10H10

Answer:

C10H10

Explanation:

A hydrocarbon is a binary compound of carbon and hydrogen. Hence a hydrocarbon is a compound of the general formula (CH)n

Thus;

(12 + 1) n = 130.18

n= 130.18/13

n = 10

Hence the molecular formula of the compound is C10H10

Answer:

1.53 L

Explanation:

Step 1: Given data

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L

Answer:Two Main Types of Pure Substances

Elements and compounds are the two types of pure substances. Examples of common elements include carbon, nitrogen and hydrogen. They consist of one type of atom and cannot break down into something else. Every pure carbon substance, for example, has the same particles in it.

Explanation:I think

Answer:

56.41 g

Explanation:

Moles = Mass ÷ [tex]A_{r}[/tex]

Given that,

moles = 0.523 mol

[tex]A_{r}[/tex] = 107.8682 u

mass = ?

Mass = Moles × [tex]A_{r}[/tex]

Mass = 0.523 × 107.8682

mass =  56.41 g

Answer:

A. it is a strong basic solution

Answer:

(see below)

Explanation:

First, refer to the pH scale:

1  2  3  4  5  6        7        8  9  10  11  12  13  14

<==  acidic        neutral             basic  ==>

You can see that the smaller the number, the stronger the acid and the bigger the number, the more basic the base is. 7 is neutral, such as water. it's neither basic nor acidic.

Now, using the process of elimination:

A) It's a strong basic solution.

No, because this solution's pH hasn't even reached basic.

B) It's a weak acidic solution.

Yes, because it is acidic and it's just a little bit more acidic than a neutral solution.

C) It's a weak basic solution.

No, because this solution's pH hasn't even reached basic.

D) It's a strong acidic solution.

No, because even though it's acidic, it's just below neutral. For something to be a strong acidic solution would be around a pH of 3.

So the answer would be B) It's a weak acidic solution.

Answer:

Explanation:

Its a elemental potassium is soft ,white  in colour  and has one more electron than argon,an element that we know is extremely stable ... Potassium extra electron is easily lost to form the much more stable cation, K+

Answer:

The electrons are found on the outer shell of the atom.

Explanation:

Answer:

Phagocytosis

Explanation:

Answer:

1 gram of N2 is equal to 0.035697202053303 mole. i dont know the rest but intried to help

. hopefully this will give you someone else a starting point. goodluck

Fe(s) would have the greatest ductility.

Ductility is the capability of a fabric to be drawn or plastically deformed without fracture. it's far therefore a demonstration of how 'gentle' or malleable the fabric is. The ductility of steel varies relying on the sorts and levels of alloying factors gift.

Ductility is the property of metallic associated with the capability to be stretched into twine without breaking. Malleability is the assets of metallic associated with the ability to be hammered into thin sheets without breaking. The outside force or strain is tensile pressure.

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Answer:

What mass of sodium hydroxide is needed to react completely with 10.0 g of iron( III) chloride? The conversion sequence is: A. B.

Explanation:

make me as brain liest

Answer:

dangerous woman by ariana grande

Explanation:

Answer:

C6H10O6

Explanation:

Convert % and make them to grams. Convert grams to mols. Use mole ratios to find empirical formula. I will calculate it in a second. Hope this helps for now. This is my quick answer imma check my work one sec.

Answer:

Explanation:

Let the final volume be v .

from the formula

S₁ V₁ = S₂V₂

4 x 7 = .8 x V₂

V₂ = 35 mL

Final volume of the solution will be 35 mL .

Answer:

3.76

Explanation:

You start by finding the mass of part d. Mass=  Density times Volume.In this case you would multiply 62.7 and 2.59 which is 162.393 rounded is 162.4. Then density= mass/ volume which is 162.4/ 43.2. density equals 3.76

Answer:

[tex]x_{He}=0.975\\x_{O_2}=0.025[/tex]

Explanation:

Hello.

In this case, since we know the mass of both helium and oxygen, in order to obtain the mole fractions we first need the compute the moles by using their atomic masses, 4.00 g/mol and 32.00 g/mol respectively as shown below:

[tex]n_{He}=23.6gHe*\frac{1molHe}{4.00gHe}=5.90molHe\\ \\n_{O_2}=4.85gO_2*\frac{1molO_2}{32.00gO_2}=0.152molO_2\\[/tex]

Therefore, the mole fractions are:

[tex]x_{He}=\frac{n_{He}}{n_{He}+n_{O_2}}=\frac{5.90}{5.90+0.152} \\\\x_{He}=0.975\\\\x_{O_2}=\frac{n_{O_2}}{n_{He}+n_{O_2}} =\frac{0.152}{5.90+0.152} \\\\x_{O_2}=0.025[/tex]

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Answer:

Rubidium

Answer: Rubidium is the most reactive metal. Explanation: Metals are the elements that looses electrons and thus, their chemical reactivity will be the tendency to loose electrons.

Explanation:

Answer:

0.05 g/cm^3.

Explanation:

The volume of the block = 9*2*6 = 108 cm^3.

Density = mass/volume

= 5.4 / 108

= 0.05 g/cm^3.

Explanation:

Ionisation isomerism is shown by [Cr(NH₃)₄Cl₂]Br and [Cr(NH₃)₄ClBr]Cl

Answer:

inorganic compounds that take the form of discrete molecules

Answer:

Compounds that take the form of discrete molecules.

Explanation:

Rather than forming ions, the atoms of a molecule share their electrons in such a way that a bond forms between pairs of atoms.

Answer:

2Na₃PO₄ + 3CaCl₂       →      6NaCl + Ca₃(PO₄)₂

Explanation:

Chemical equation:

Na₃PO₄ + CaCl₂       →      NaCl + Ca₃(PO₄)₂

Balance chemical equation:

2Na₃PO₄ + 3CaCl₂       →      6NaCl + Ca₃(PO₄)₂

First step:

Na₃PO₄ + CaCl₂       →      NaCl + Ca₃(PO₄)₂

Left hand side                        Right hand side

Na = 3                                          Na =1

P  =  1                                            P  = 2

O = 4                                            O  = 8

Ca = 1                                          Ca = 3

Cl =2                                             Cl = 1

2nd step:

2Na₃PO₄ + CaCl₂       →      NaCl + Ca₃(PO₄)₂

Left hand side                        Right hand side

Na = 6                                          Na =1

P  =  2                                           P  = 2

O = 8                                            O  = 8

Ca = 1                                          Ca = 3

Cl =2                                             Cl = 1

3rd step:

2Na₃PO₄ + 3CaCl₂       →      NaCl + Ca₃(PO₄)₂

Left hand side                        Right hand side

Na = 6                                          Na =1

P  =  2                                           P  = 2

O = 8                                            O  = 8

Ca = 3                                          Ca = 3

Cl = 6                                             Cl = 1

3rd step:

2Na₃PO₄ + 3CaCl₂       →      6NaCl + Ca₃(PO₄)₂

Left hand side                        Right hand side

Na = 6                                          Na =6

P  =  2                                           P  = 2

O = 8                                            O  = 8

Ca = 3                                          Ca = 3

Cl = 6                                             Cl = 6

Answer:

It's a representative metal

Explanation: Transitional metals are metals of various chemical elements and have valence electrons—i.e., electrons that can participate in the formation of chemical bonds.

Answer:

Kindly check the explanation section.

Explanation:

Without mincing words let us dive right into the solution to the question above, taking each compound at a time.

NB: Kindly Check attachment for the Lewis Structure of each of the chemical compounds.

Therefore, the number of valence electrons, electronic shape, molecular shape and whether the molecules are polar(Polarity) is given below for each chemical compound.

(1). Compound: HCN

(a). number of valence electrons = 10.

(b). electronic shape =linear.

(c). molecular shape = linear.

(d). Polarity = Y.

(2). Compound: PH3

(a). number of valence electrons = 8.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Trigonal Pyramidal.

(d). Polarity = Y.

(3). Compound: CHCl3.

(a). number of valence electrons = 26.

(b). electronic shape = tetrahedral.

(c). molecular shape = tetrahedral.

(d). Polarity = Y.

(4). Compound: NH4^+

(a). number of valence electrons = 8

(b). electronic shape = tetrahedral

(c). molecular shape = tetrahedral

(d). Polarity = Y.

(5). Compound: H2CO

(a). number of valence electrons = 12.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Trigonal planar

(d). Polarity = Y.

(6). Compound: SO4^2-

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(7). Compound: SeF2.

(a). number of valence electrons = 20.

(b). electronic shape = Tetrahedral.

(c). molecular shape = bent.

(d). Polarity = Y.

(8). Compound: CO2.

(a). number of valence electrons = 16.

(b). electronic shape = linear.

(c). molecular shape = linear.

(d). Polarity = N.

(9). Compound: O2

(a). number of valence electrons = 32.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Linear.

(d). Polarity = N.

(10). Compound: ClO4-.

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(11). Compound: HBr.

(a). number of valence electrons = 8.

(b). electronic shape = Linear.

(c). molecular shape = Linear.

(d). Polarity = Y.

(12). Compound: PF5.

(a). number of valence electrons = 40.

(b). electronic shape = Trigonal Bipyramidal.

(c). molecular shape = Trigonal Bipyramidal.

(d). Polarity = N.

(13). Compound: BeH2.

(a). number of valence electrons = 4.

(b). electronic shape = Linear.

(c). molecular shape = Linear.

(d). Polarity = N.

(14). Compound: PO4^3-.

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(15). Compound: BH3.

(a). number of valence electrons = 6.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Trigonal planar.

(d). Polarity = N

(16). Compound: Br3-.

(a). number of valence electrons = 32.

(b). electronic shape = Trigonal Bipyramidal.

(c). molecular shape = Linear.

(d). Polarity = N.