What is the HCF of 1280 and 630

9514 1404 393

Answer:

  D  neither

Step-by-step explanation:

Reflection across a vertical line is required to change the figure left-to-right without changing it top-to-bottom. Translation along a directed line segment must then map corresponding points.

Sequence A involves reflection over a horizontal line, so can be rejected immediately. Sequence B does the translation so that point N gets moved to the location of point B. However, point N corresponds to point D (see the similarity statement), so that translation is inappropriate.

Neither sequence will map KLMN to ABCD.

9514 1404 393

Answer:

  (11, 3)

Step-by-step explanation:

That point is ...

  P = a + (1/6)(b -a) = (5a +b)/6

  P = (5(14, -1) +(-4, 23))/6 = (70-4, -5+23)/6 = (11, 3)

The point of interest is (11, 3).

Answer:

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Step-by-step explanation:

Let's look first at the x coordinates of the two given points:  14 and -4.  From 14 to -4 is a decrease of 18.  Similarly, from y = -1 to y = 23 is an increase of 24.

Starting at a(14, -1) and adding 1/6 of the change in x, which is -18, we get the new x-coordinate 14 + (1/6)(-18), or 14 - 3, or 11.  Similarly, adding 1/6 of the increase in y of 24 yields -1 + 4, or 3.

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Step-by-step explanation:

[tex](\sec A - \csc A)(1 + \cot A + \tan A)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)[/tex]

[tex]=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)[/tex]

[tex]=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}[/tex]

[tex]=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}[/tex]

[tex]=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)[/tex]

[tex]=\sec^2A\csc A - \csc^2A\sec A[/tex]

Answer: the answer is c

Step-by-step explanation:brainlist [tex]\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right][/tex]

Answer:

Option B

Step-by-step explanation:

Function 'g' is,

g(x) = x²

Since, leading coefficient of this function is positive, parabola is opening upwards.

From the graph attached,

Function 'f' is opening upwards leading coefficient of the function will be positive.

Since, the graph of function 'f' is vertically stretched, equation will be in the form of f(x) = kx²

Here, k > 1

Since, function 'f' is formed by shifting the graph of function 'g' by 1 unit upwards,

f(x) = g(x) + 1

Combining all these properties, equation of the function 'f' should be,

f(x) = 4x² + 1

Option B will be the correct option.

Answer: (3, -3)

Step-by-step explanation:

You substitute each point into the function and see if it fits:

(-2, -1) ⇒ -2(-2) + 3 = 4 + 3 = 7 ≠ -1

(3, -3) ⇒ -2(3) + 3 = -6 + 3 = -3

(3, 3) ⇒ -2(3) + 3 = -6 + 3 = -3 ≠ 3

(-3, -9) ⇒ -2(-3) + 3 = 6 + 3 = 9 ≠ -9

A parallelogram is also a rhombus if the diagonal is a bisector of an angle enclosed by the two adjacent sides of a parallelogram.

In our case it means,

[tex]5x+25=12x+11[/tex]

[tex]7x=14\implies x=\boxed{2}[/tex]

Hope this helps.

In order for the parallelogram to be a rhombus, ,For the parallelogram to be a rhombus, x must be equal to 2.

To determine the value of x that would make the parallelogram a rhombus, we need to compare the lengths of its opposite sides. In a rhombus, all four sides are equal in length. So, we can equate the lengths of the opposite sides of the parallelogram and solve for x.

Given that one side has a length of (5x + 25) and the opposite side has a length of (12x + 11), we can set up the following equation: 5x + 25 = 12x + 11

To solve for x, we can start by isolating the x term on one side of the equation. We can do this by subtracting 5x from both sides: 25 = 12x - 5x + 11 Simplifying the equation further: 25 = 7x + 11 Next, we can isolate the x term by subtracting 11 from both sides: 25 - 11 = 7x 14 = 7x Finally, we can solve for x by dividing both sides by 7: 14/7 = x x = 2 Therefore, for the parallelogram to be a rhombus, x must be equal to 2.

To know more about parallelogram here

https://brainly.com/question/970600

#SPJ2

Answer:

[tex] {3}^{2} \div 48 - 6 \\ 9 \div 48 - 6 \\ = - 5.8125[/tex]

Answer:

So for example a graph in typed in word format could look like

Time   Girls   Boys

1            3        5

2            4        6

3            5         7

4             6          8

5             7          9

Not saying that this graph would be sufficient value wise for the answer, but this is how I would tackle it if I wasn't given the option to draw a graph.

Answer:

[tex]- 2x^2 +19x -24[/tex]

Step-by-step explanation:

Given

[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]

Required

Evaluate

We have:

[tex](5x + 8 - 6x)(4 + 2x - 7)[/tex]

Collect like terms

[tex](5x - 6x+ 8 )(4 - 7+ 2x )[/tex]

[tex](- x+ 8 )(- 3+ 2x )[/tex]

Expand

[tex]3x - 2x^2 -24 + 16x[/tex]

Rewrite as:

[tex]- 2x^2 + 3x+ 16x -24[/tex]

[tex]- 2x^2 +19x -24[/tex]

Answer:

Just A and C

Step-by-step explanation:

B doesn't count because you would not be looking at the 9. Only the 4.

You only look at one number to the right.

Answer:

A and C are correct, but not B

Step-by-step explanation:

When you round, you only look at the number behind the place you are rounding.

6.04 doesn't round to 6.1, so that is not correct

Answer:

BC = 28

Step-by-step explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

Answer:

[tex]x = 28[/tex] ----- Banana

[tex]y = 54[/tex] ----- Almonds

[tex]z = 18[/tex] ---- Chocolate

Step-by-step explanation:

Let

[tex]x \to[/tex] banana

[tex]y \to[/tex] almonds

[tex]z \to[/tex] chocolate

So, we have:

[tex]x + y + z = 100[/tex] --- total used

[tex]4x + 8y + 6z = 652[/tex] -- i.e. 6.52 * 100 --- total sales from 100 pounds

[tex]y = 3z[/tex]

Required

The number of pounds of each (i.e. x, y and z)

Substitute [tex]y = 3z[/tex] in [tex]x + y + z = 100[/tex]

[tex]x + 3z + z = 100[/tex]

[tex]x + 4z = 100[/tex]

Make x the subject

[tex]x = 100 - 4z[/tex]

Substitute [tex]y = 3z[/tex] in [tex]4x + 8y + 6z = 652[/tex]

[tex]4x + 8 * 3z + 6z = 652[/tex]

[tex]4x + 24z + 6z = 652[/tex]

[tex]4x + 30z = 652[/tex]

Substitute [tex]x = 100 - 4z[/tex]

[tex]4(100 - 4z) + 30z = 652[/tex]

[tex]400 - 16z + 30z = 652[/tex]

Collect like terms

[tex]- 16z + 30z = 652-400[/tex]

[tex]14z = 252[/tex]

Divide by 14

[tex]z = 18[/tex]

Substitute [tex]z = 18[/tex] in [tex]x = 100 - 4z[/tex]

[tex]x = 100 - 4 * 18[/tex]

[tex]x = 100 - 72[/tex]

[tex]x = 28[/tex]

To calculate y, we have:

[tex]y = 3z[/tex]

[tex]y = 3 * 18[/tex]

[tex]y = 54[/tex]

Answer:

y = -x.

Step-by-step explanation:

The slope of the line (m) = -1.  ( because of the -x in y = -x - 5)

y - y1 = m (x - x1)    where (x1, y1) is a point on the line, so we get;

y - 2 = -1(x - (-2))

y - 2 = -x + -1 * +2

y - 2 = -x - 2

y = -x.

Answer:

− 3 x + 1

Step-by-step explanation:

Answer: -3x + 1

Step-by-step explanation: I know Math O_O

Answer:

The program in Java is as follows:

import java.util.*;

public class PyTheorem{

   public static void main(String [] args){

       Random rNum = new Random();

       int a = rNum.nextInt(17) + 5;

       int b = rNum.nextInt(17) + 5;

       System.out.println("a: "+a);

       System.out.println("b: "+b);

       double hyp = Math.sqrt(Math.pow(a,2)+Math.pow(b,2));

       System.out.print("Hypotenuse: "+hyp);

   }}

Step-by-step explanation:

This generates random number for a

       int a = rNum.nextInt(17) + 5;

This generates random number for b

       int b = rNum.nextInt(17) + 5;

Print a

       System.out.println("a: "+a);

Print b

       System.out.println("b: "+b);

Calculate the hypotenuse

       double hyp = Math.sqrt(Math.pow(a,2)+Math.pow(b,2));

Print the calculated hypotenuse

       System.out.print("Hypotenuse: "+hyp);

9514 1404 393

Answer:

  -4, 0

Step-by-step explanation:

The denominator is x^2+4x. This is zero when ...

  x^2 +4x = 0

  x(x +4) = 0

The zero product rule tells you the product is zero when the factors are zero.

  x = 0

  x +4 = 0   ⇒   x = -4

The denominator is zero for x=0 and x=-4.

Answer:

C. 0.48

Step-by-step explanation:

Probability = number of required outcome

_______________________

number of possible outcome

= total volleyball game events

_______________________

total sophomore + junior

= 66/137

= 0.48

Answer: D) 0.31

Step-by-step explanation:

Let A denote the event that a person is a sophomore.

Let B denote the event that a person has attended volleyball game.

A∩B denote the event that a person is a sophomore and attend volleyball game.

Let P denote the probability of an event.

We are asked to find:

P(A∩B)

From the table provided to us we see that:

A∩B=42

Hence,

P(A∩B)=42/137=0.3065 which is approximately equal to 0.31. Therefore ur answer will be 0.31.

Answer:

.252

Step-by-step explanation:

[tex]{10\choose7}*.65^7*(1-.65)^3=.252219625[/tex]

Answer:

1 ans A second phi okay yed

Answer:

Dependent Samples t test

Step-by-step explanation:

The dependent samples t test also called the paired t test are employed in statistical analysis when sample measurement in a certain group is to be paired with the sample measurement on the other group. This is possible because the samples used in the two groups are usually the same. Hence, pairing the samples is feasible in this case. This is different from independent t test as the samples in the groups are entirely different and distinct. Hence, giving no chance to match the samples together. In the scenario described above, the same 20 people(samples) formed the same group of measurement.

Answer:

412.5

Step-by-step explanation:

Answer:

[tex]412.5[/tex] miles

Step-by-step explanation:

Since 1 inch=75 miles you just multiply [tex]75*5.5[/tex] to get how many miles 5.5 inches is.

Answer:

Defintion. A subset W of a vector space V is a subspace if

(1) W is non-empty

(2) For every v, ¯ w¯ ∈ W and a, b ∈ F, av¯ + bw¯ ∈ W.

Expressions like av¯ + bw¯, or more generally

X

k

i=1

aiv¯ + i

are called linear combinations. So a non-empty subset of V is a subspace if it is

closed under linear combinations. Much of today’s class will focus on properties of

subsets and subspaces detected by various conditions on linear combinations.

Theorem. If W is a subspace of V , then W is a vector space over F with operations

coming from those of V .

In particular, since all of those axioms are satisfied for V , then they are for W.

We only have to check closure!

Examples:

Defintion. Let F

n = {(a1, . . . , an)|ai ∈ F} with coordinate-wise addition and scalar

multiplication.

This gives us a few examples. Let W ⊂ F

n be those points which are zero except

in the first coordinate:

W = {(a, 0, . . . , 0)} ⊂ F

n

.

Then W is a subspace, since

a · (α, 0, . . . , 0) + b · (β, 0, . . . , 0) = (aα + bβ, 0, . . . , 0) ∈ W.

If F = R, then W0 = {(a1, . . . , an)|ai ≥ 0} is not a subspace. It’s closed under

addition, but not scalar multiplication.

We have a number of ways to build new subspaces from old.

Proposition. If Wi for i ∈ I is a collection of subspaces of V , then

W =

\

i∈I

Wi = {w¯ ∈ V |w¯ ∈ Wi∀i ∈ I}

is a subspace.

Proof. Let ¯v, w¯ ∈ W. Then for all i ∈ I, ¯v, w¯ ∈ Wi

, by definition. Since each Wi

is

a subspace, we then learn that for all a, b ∈ F,

av¯ + bw¯ ∈ Wi

,

and hence av¯ + bw¯ ∈ W. ¤

Thought question: Why is this never empty?

The union is a little trickier.

Proposition. W1 ∪ W2 is a subspace iff W1 ⊂ W2 or W2 ⊂ W1.

i hope this helped have a nice day/night :)

Answer:

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 520 hours.

This means that [tex]\sigma = 15, \mu = 520[/tex]

Find the probability of a bulb lasting for at most 528 hours.

This is the p-value of Z when X = 528. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{528 - 520}{15}[/tex]

[tex]Z = 0.533[/tex]

[tex]Z = 0.533[/tex] has a p-value of 0.7031

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Answer:

Volume = 18 cm^3

Surface Area = 58 cm^2

Step-by-step explanation:

Find the volume with the formula V=w*h*l

W= width

H = height

L = length

W= 2cm

H= 1 cm

L= 9 cm

V= w*h*l

V= 2cm * 1 cm * 9cm

V= 18 cm^3

Find the surface area with the formula A= 2(w*l + h*l + h* w)

W= width

H = height

L = length

W= 2cm

H= 1 cm

L= 9 cm

A= 2(w*l + h*l + h* w)

A= 2(2cm*9cm + 1cm*9cm + 1cm* 2cm)

A= 2(29cm)

A= 58cm^2

Answer:

68% is a special

value for these problems

empirical rule suggests ± 1 standard deviation

z = (x - μ)/σ

1 = (x - 38000)/1000

Between $37,000 and $39,000

Step-by-step explanation:

Answer:

The circumference and diameter of a circle

Step-by-step explanation:

Proportional relationships can be written as [tex]y=kx[/tex], where [tex]k[/tex] is some constant of proportionality. The formula for a circumference of a circle can be written as [tex]C=d\pi[/tex], where [tex]d[/tex] is the diameter of the circle. Therefore, the constant of proportionality is [tex]\pi[/tex] and the circumference and diameter of a circle are in a proportional relationship.