What is the balance equation for

_ Ba + _ HNO3 —> _ H2 + _ Ba(NP3)2


_ H3PO4 + _ NaOH —> _ H2O + _ Na3PO4

Answers

Answer 1

1st one

2_2_2

2nd one

3_1_1_3

i looked it up


Related Questions

Which is a constructive process? Rivers carrying sediment down stream, the rusting of a bridge, waves cutting back a beach front, volcanic eruption caused by plate tectonics

Answers

Answer:

volcanic eruption caused by plate tectonics.

Explanation:

Constructive process is one in which memories are influenced by some events. When a person tries to retrieve the memory he first click some event which is associated with that memory and then whole flash backs comes to his mind.

The mass of a neutron is

Answers

A milimter is the answebti this

What is the molarity of the solution formed by dissolving 80. G of NAOH(s) into water to give a total volume of 4.00 l

Answers

Answer:

0.5 M

Explanation:

From the question given above, the following data were obtained:

Mass of NaOH = 80 g

Volume of solution = 4 L

Molarity =?

Next, we shall determine the number of mole in 80 g of NaOH. This can be obtained as follow:

Mass of NaOH = 80 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 80 / 40

Mole of NaOH = 2 moles

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of NaOH = 2 moles

Volume of solution = 4 L

Molarity =?

Molarity = mole / Volume

Molarity = 2/4

Molarity = 0.5 M

Therefore, the molarity of the solution is 0.5 M.

Which of the following equalities is not correct?
a. 1 cm^3 = 1 mL
b. 1000 mm = 1 m
c. 100 cg = 1 g
d. 10 kg = 1 g

Answers

Answer:

a. 1 cm^3 = 1 mL

explanation:

The answer is , A. 1 cm^3 = 1mL

If the sky is actually black, and the water is actually clear, where does the blue color for the sky and water come from?

Answers

Answer:

that the water is blue because of the way water absorbs light, the way particles in the water scatter light, and also because some of the blue light from the sky is reflected

3. How many moles are present in 100 g of Ca(NO3)2?
PLEASEEE HELP ASAPP

Answers

0Answer: 0.6094

Explanation:

no of moles = mass / molar mass = 100/164.088= 0.6094 mole

Answer:

0.609 moles

Explanation:

mass in g ÷ atomic mass = moles

Ca(NO₃)₂ = 1 Ca 40.078 amu

2 N 28.0134 amu

+ 6 O 95.994 amu

____________________

164.0854 amu

100 g ÷ 164.0854 amu = 0.609 moles

three significant digits

C₂H₄O₂ + O₂ ➞ CO₂ + H₂O

Answers

Answer:

C2H4O2 + 2O2 ==> 2CO2 + 2H2O

Explanation:

Start with the carbons

C2H4O2 + O2 ==> 2CO2 + H2O There are 2 on the left, so you need 2 on the right.

Next deal with the hydrogens. You have 4 on the left so you have to make 4 on the right

C2H4O2 + O2 ==> 2CO2 + 2H2O

The oxygens are the real devil in this question. Be careful how you handle them. There are 2 * 2 = 4 from the CO2 and 2*1 = 2 from the water. The total is 6

Now you can't just put a 3 in front of the O2. There are 2 in the given chemical. So you don't need 6. You need 6 -2 = 4. But the oxygen is O2. You have to divide the 4 by 2 to get 2

C2H4O2 + 2O2 ==> 2CO2 + 2H2O  

And that's your answer.

a beam balance is called a first class lever why?​

Answers

Answer:

A beam balance is an example of a first class lever.

Explanation:

A beam balance is an example of a first class lever. In a first class lever, the fulcrum is between the effort (force) and the load. The effort (force) moves over a large distance to move the load a smaller distance.

Other examples of first class lever are pliers, scissors, a crow bar, a claw hammer, a see-saw and a weighing balance etc.

If a man reach a 25 km distance in 30 min in his car , find the average velocity

Answers

Answer:

Average velocity of car = 50 km/h

Explanation:

Given information;

Distance cover by man in his car = 25 kilometer

Time taken by man to cover distance = 30 min

Find:

Average velocity of car

Computation:

Time taken by man to cover distance = 30 min

Time taken by man to cover distance = 30 / 60

Time taken by man to cover distance = 0.5 hour

Average velocity = Distance / Time

Average velocity of car = Distance cover by man in his car / Time taken by man to cover distance

Average velocity of car = 25 / 0.5

Average velocity of car = 50 km/h

Calculate the numerical Kc value for the following reaction if the equilibrium mixture contains 0.51 M CO , 0.30 M H2 , 1.8 M CH4 , and 2.0 M H2O.

CO(g) + 3H2 (g) ⇌ CH4 (g) + H2O (g)
Show work

Answers

Answer:

uh i think this is the answer

Explanation:

calculate the final pressure of a gas that is expanded from 725cm³ at 30C and 1.19 atm to 1.12cm³ at 43C​

Answers

Answer:

Final pressure, P2 = 1088.89 atm

Explanation:

Given the following data;

Initial volume, V1 = 725 cm³

Initial temperature, T1 = 30°C

Initial pressure, P1 = 1.19 atm

Final volume, V2 = 1.12 cm³

Final temperature, T2 = 43°C

To find the final pressure (P2), we would use the combined gas law.

Mathematically, the combined gas law is given by the formula;

[tex] \frac {PV}{T} = k [/tex]

[tex] \frac {P_{1}V_{1}}{T_{1}} = \frac {P_{2}V_{2}}{T_{2}} [/tex]

Substituting into the formula, we have;

[tex] \frac {1.19*715}{30} = \frac {P_{2}*1.12}{43} [/tex]

[tex] \frac {850.85}{30} = \frac {P_{2}*1.12}{43} [/tex]

[tex] 28.3617 = \frac {P_{2}*1.12}{43} [/tex]

Cross-multiplying, we have;

[tex] 28.3617 * 43 = 1.12P_{2} [/tex]

[tex] 1219.5531 = 1.12P_{2} [/tex]

[tex] P_{2} = \frac {1219.5531}{1.12} [/tex]

Final pressure, P2 = 1088.89 atm

In the past mining companies were not made responsible for the clean-up of any of the mine sites. As a result, abandoned mines had a severe impact on the environment in Ontario. Which of these is not a result of these mining practices?

1) Chemical reactions producing sulphuric acid decrease soil and water PH in the area.
2) Acid leaching dissolves metals found in the soil thus allowing them to enter the water system.
3) Heavy metals which are left tailing ponds can dissolve and enter the water system.
4) Old and inefficient mining smokestacks contaminate the soils around abandoned mine sites.

Answers

Answer:

Old and inefficient mining smokestacks contaminate the soils around abandoned mine sites.

Explanation:

A smokestack, is a very tall channel commonly used in many instances to release gases produced by combustion processes directly into the air. These high towers are aimed at dispersing the gaseous pollutants over a wider area thereby minimizing their impact.

Old and inefficient smokestack do not contaminate the soil since they are very high towers that discharge gases directly into the atmosphere. Hence they are not part of the sources of soil contamination in abandoned mines.

1.25 X 10^24 molecules of chlorine gas react with sodium to form how many grams of sodium
chloride?
2Na + Cl2
--> 2NaCl

Answers

Answer:

241.28 g NaCl(s)

Explanation:

Given 1.25 x 10²⁴ molecules of Cl₂ = 1.25 x 10²⁴molecules Cl₂(g)/6.023 x 10²³ molecules/mole = 2.08 mole Cl₂(g)

2Na(s)    +      Cl₂(g)      =>   2NaCl(s)

excess        2.08mole          ? mole

∴moles NaCl(s) formed from 2.08 moles Cl₂(g) = 2(2.08 mole NaCl(s))

= 4.16 mole NaCl(g) = 4.16 mole NaCl(s) x 58 g NaCl(s)/mole NaCl(s) = 241.28 g NaCl(s)  

If calcium carbonate (Cacos) decomposes. What would the product of the reaction be?


Answers

Answer:

CaO

Explanation:

Group 2 Carbonates decompose to form oxides of the Group 2 element and Carbon dioxide

The nonmetals include which of the following groups? Use the periodic table to answer the question. Check all that apply.

halogens

alkali metals

lanthanides

noble gases

alkaline earth metals

Answers

Answer:

En el grupo de los no metales se incluyen los halógenos​ (flúor, cloro, bromo, yodo, astato y téneso), que tienen 7 electrones en su última capa de valencia y los gases nobles (helio, neón, argón, kriptón, xenón, radón), que tienen 8 electrones en su última capa (excepto el helio, que tiene 2).

Explanation:

halógenos

Answer:

1,4

Explanation:


(Please Help)

1.What is the most common isotope for element X

2.Calculate the average atomic mass or element X

Answers

Answer:

1. Isotope 2 occurs most commonly

2. 39.02amu

Explanation:

1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.

2. Isotope 1 = 9.67%, mass no: 38

Isotope 2 = 78.68%, mass no: 39

Isotope 3 = 11.34%, mass no: 40

Isotope 4 = 0.31%, mass no: 41

To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:

We convert each percentage to decimal abundance:

Isotope 1 = 9.67% = 0.0967

Isotope 2 = 78.68% = 0.7868

Isotope 3 = 11.34% = 0.1134

Isotope 4 = 0.31% = 0.0031

(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)

3.6746 + 30.6852 + 4.536 + 0.1271

Average atomic mass = 39.02amu

Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
kJ/mol.
○ Cuando se quema 1 mol de octano –o sea, 114 g–, se desprenden 5500
kJ/mol.
Pareciera que el octano puede brindar más energía al quemarse, pero vamos a
hacer un análisis más cuidadoso. Comparemos la combustión de igual masa de
cada combustible.
● Calculen la cantidad de calor que se desprende cuando se quema un gramo
de cada combustible.
1 gr de metano aporta……………………………
1 gr de octano aporta………………………………

Answers

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo ([tex]Q[/tex]), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto ([tex]\bar {Q}[/tex]), en kilojoules por mol, dividido por su masa molar ([tex]M[/tex]), en gramos por mol:

[tex]Q = \frac{\bar Q}{M}[/tex] (1)

A continuación, analizamos cada caso:

Metano

[tex]Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }[/tex]

[tex]Q = 50.125\,\frac{kJ}{g}[/tex]

1 gramo de metano aporta 50.125 kilojoules.

Octano

[tex]Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }[/tex]

[tex]Q = 48.246\,\frac{kJ}{mol}[/tex]

1 gramo de metano aporta 48.246 kilojoules.

Because electrons are orbiting the nucleus, the nucleus is stationary

true or false​

Answers

Answer:

false, The nucleus of atoms still move around like crazy, it's just the electrons move more.

If you produce 35.7 grams of sodium chloride how many molecules of Chlorine gas were
needed?
2Na + Cl2 --> 2NaCl
(PLS HELP ASAP)

Answers

Explanation:

I did it in steps to help u to understand :)

need help asap!!!

so i don’t necessarily need an answer just how to solve everything.

this is the first one:
calcium hydroxide + ammonium chloride

the instructions are attached to this question. i’m just not sure how to do everything. it doesn’t give me the products side only the reactants so how am i supposed to write and balance the equation?

Answers

Explanation:

とおふぉくぉをえおろとようおいおぽあおそ・

'」*とまっぉのもヴぉこぉぞぽ、こ、

Answer:

Ca(OH)2 + 2NH4Cl .................. CaCl2 + 2NH3 + 2H2O

What are the example of molecule ?​

Answers

Explanation:

H2O water molecule

O3 Ozone

h2o n2o3c6h12o3

are some of common example of molecules

The first excited state of a particular atom in a gas is 6.1 eV above the ground state. A moving electron collides with one of these atoms, and excites the atom to its first excited state. Immediately after the collision the kinetic energy of the electron is 3.2 eV. What was the kinetic energy of the electron just before the collision

Answers

Answer:

The kinetic energy of the electron just before the collision is 9.3 eV.

Explanation:

We can find the kinetic energy of the electron before the collision can be found by energy conservation:

[tex] E_{i} = E_{f} [/tex]

[tex] K_{a_{i}} + K_{e_{i}} = K_{a_{f}} + K_{e_{f}} [/tex]   (1)

Where:

[tex]K_{a_{i}}[/tex]: is the initial kinetic energy of the atom

[tex]K_{a_{f}}[/tex]: is the final kinetic energy of the atom = 6.1 eV + [tex]K_{a_{i}}[/tex]

[tex]K_{e_{i}}[/tex]: is the initial kinetic energy of the electron =?

[tex]K_{e_{f}}[/tex]: is the final kinetic energy of the electron = 3.2 eV

By solving equation (1) for [tex]K_{e_{i}}[/tex] we have:

[tex]K_{a_{i}} + K_{e_{i}} = (6.1 eV + K_{a_{i}}) + 3.2 eV[/tex]

[tex] K_{e_{i}} = 6.1 eV + 3.2 eV = 9.3 eV [/tex]

Therefore, the kinetic energy of the electron just before the collision is 9.3 eV.

I hope it helps you!


A heat lamp produces____
light.

Answers

Answer:

infrared light

Explanation:

Cuál es el cruce para un niño donde su padre tiene el pelo rizo RR y su madre pelo lacio rr

Answers

Answer:

Rr

Explanation:

Stoichiometry - Chemistry​

Answers

Answer:

C

Explanation:

in the option C when we rearrange it then it will he C3H6O2

Answer:

yes its C

Explanation:

correct me if iam wrong

Which of the following statements about the nucleus is false?


A. Contains nearly all of the mass of the atom.

B. Able to be lost or gained in chemical reactions.

C. None of these

D. Made up of protons and neutrons

Answers

Answer:

B. Able to be lost or gained in chemical reactions.

Answer:

B

Explanation:

a chemical reaction would only move the nucleas

cuantos gramos y moleculas de dioxido de carbono hay en 0.5 moles de dioxido de carbono
paso a paso

Answers

Answer:

metro= 22g

Explanation:

In an electrically neutral atom, the number of
protons equals the number of neutrons.
protons equals the number of electrons.
neutrons equals the number of electrons.

A. Protons equals the number of neutrons
B. Protons equal the number of electrons
C. Neutrons equals the number of electrons

Answer: B

Answers

Answer:

B

Explanation:

because protons have a +1 charge and electrons have a -1 charge, so if an atom is neutral it must have the same amount of protons and neutrons

Yes I believe the correct answer is B

Polywool fibre is
a.natural
b.synthetic
c.monomer
d.blended​

Answers

Answer : -

Polywool fibre is synthetic.

⇒b. Synthetic

Hope It Helps You ✌️

Answer:

[tex]\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{b.synthetic }}}}}

[/tex]

if you have a pop quiz and you get nervous is that unconditioned response? if yes why? if not what kind of response is it

Answers

No it’s a obligated response
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