what is science explain​

Answer:

When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events and are reliable. Multiple trials can be done at one time. E.g. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.

Hope that helped.x

Answer:

option D 17proton ,17electron and 18 neutrons

I think correct answer is C.Jet stream would be displaced southwards causing heavy rain and flooding

The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is Jet stream would be displaced southwards causing heavy rain and flooding.

Answer:

A. 4,6-dimethyloct-1,4,6-yne

B. deconic acid

C. 3-ethyl-4-methyl-7-bromocyclohexene

D. 2,2,3-trimethyl-4-butyl-heptane

E. 3-methylhexane

F. ethyl hexanoate

G. butanal

H. propyne

J. 2,4-dimethyl-pent-2-ene

Explanation:

sorry i didn't have time to do I

By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Now, we can calculate the number of moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

Moles of NaCl = 157 g / 58.44 g/mol

Moles of NaCl ≈ 2.69 mol

According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.

Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:

Moles of Cl₂ = (Moles of NaCl / 2) × 1

Moles of Cl₂ = 2.69 mol / 2

Moles of Cl₂ ≈ 1.35 mol

Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

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Very Very sorry

Answer:

Explanation:

Just like a solid, the density of a liquid equals the mass of the liquid divided by its volume; D = m/v. The density of water is 1 gram per cubic centimeter.

Answer:

A.

The answer is A :)

Answer:

beta to Kr-80 or Se-80

Explanation:

sorry if wrong

Answer:

methyl 2-methyl-ethane

Explanation:

Answer:

2. Products; FeCl2 and H2S

Reactants; FeS and HCl

3. a) 36g of water

b) 64g of oxygen

I think e no

I am giving you hint

Answer:

A carbon dioxide and oxygen

Answer:

pure-bred green with pure-bred yellow peas. Since yellow is dominant to green, all of the offspring were yellow. The green phenotype had disappeared. ... When a pure-bred green plant is crossed with a pure-bred yellow plant, the offspring inherit one allele of the color gene from each parent.

Explanation:

Ppbag at it again

Answer:

A13+

Explanation:

I took a test that had this question.

Answer:

38.38 L (3 d.p.)

Explanation:

In response to questions addressing the expansion of gas via heating, Charles's Law should be considered. Charles's Law is an experimental gas law explaining the tendency of gases to expand when heated.

The law states that the volume ([tex]V[/tex])  of a gas is directly proportional to its temperature ([tex]T[/tex]) given that the pressure ([tex]P[/tex]) and the amount of gas ([tex]N_{A}[/tex]) are constant.

[tex]\displaystyle\frac{V}{T} \ = \ k \ \ \ \ \ \ \ or \ \ \ \ \ \ \ V \ = \ kT[/tex], where k is a proportionality constant.

*Note that when substituting temperature into the equation, the temperature must be in terms of the Kelvin scale and not in degrees Celsius. The relation between the Kelvin scale and the Celsius scale is  [tex]\mathrm{K} \ = \ ^{\circ}\mathrm{C} \ + \ 273[/tex].

Charles's law can be used to compare changing conditions of a particular gas. Let  [tex]V_{1}[/tex]  and  [tex]T_{1}[/tex]  be the initial volume and temperature for the gas, while  [tex]V_{2}[/tex]  and  [tex]T_{2}[/tex]  be the final volume and temperature. The mathematical relationship of Charles's law becomes:

[tex]\displaystyle\frac{V_{1}}{T_{1}} \ = \ \displaystyle\frac{V_{2}}{T_{2}}[/tex].

In accordance with the question,

[tex]V_{1} \ = \ 33.4 \ \mathrm{L}, \ T_{1} \ = \ (22 \ + \ 273) \ \mathrm{K} \ = \ 295 \mathrm{K}, \ T_{2} \ = \ (66 \ + \ 273) \ \mathrm{K} \ = \ 339 \ \mathrm{K}[/tex]

while  [tex]V_{2}[/tex]  is the final volume of the gas that we would like to find. Therefore,

[tex]V_{2} \ = \ \displaystyle\frac{V_{1} \ \times \ T_{2}}{T_{1}} \\ \\ V_{2} \ = \ \displaystyle\frac{33.4 \ \mathrm{L} \ \times \ 339 \ \mathrm{K}}{295 \ \mathrm{K}} \\ \\ V_{2} \ = \ 38.38 \ \mathrm{L}[/tex].

Answer:

A) Carbon dioxide and Oxygen

Explanation:

Percentage of gases in the Planet's atmosphere:

Percentage of gases in the Earth's atmosphere:

___________________

On observing the percentage composition of the atmospheres of the two Planets, we get:

___________________

Answer:

What's asked is the name of the gases that are in higher amounts in the atmosphere of the newly discover planet

Therefore,

The replacement reaction will not occur because iodine is less reactive than chlorine.

A replacement reaction is a type of reaction in which one element is replaced by another in a compound.

The principle behind one element replacing the other is based on the reactivity of an element. A more reactive element will displace a less reactive one.

According to this question, the following displacement reaction is given: MgCl2 + I2 → ?

This reaction will not occur because chlorine is more reactive/electronegative than iodine, hence, iodine cannot displace it.

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Answer:

MORSE CODE ISN'T THAT FUN AND I'M USING A TRANSLATOR TOO SO

Explanation:

That is what is says in morse code.

Answer:

MORSE CODE ISN'T THAT FUN AND I'M USING A TRANSLATOR TOO SO

Explanation:

The options that describe the experimental errors that would affect the percent of chloride reported are:

While performing experiments, there are some errors that occur which are generally known as experimental errors.

These experimental errors are the difference between the true measurement and what we measured.

There are three types of experimental errors they include:

Human errors occur due to carelessness of the observer.

Examples are:

Therefore, the options describe the experimental errors that would affect the percent of chloride reported are B and D.

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Answer:

huh

Explanation:

Answer:

it indicates that the lower orbitals are filled first and they have the maximum number of electrons compared to the higher orbitals

The acid ionization constant is the quantitative measure of the acidic strength. For oxalic acid, Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Acid dissociation (Ka) is the ratio of the concentration of the conjugate base and hydrogen ion to the concentration of the chemical.

Oxalic acid is a weak acid and gets dissociated as:

H₂C₂O₄ ⇌ H⁺ + HC₂O₄⁻

or

HC₂O₄⁻ ⇌ H⁺ + C₂O₄²⁻

The acid ionization constant for the reactant and the product is given as:

Ka = [H⁺] [A⁻] / [HA]

Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Therefore, the ionization constant for oxalic acid is given as Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

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[tex] = 1kg \: \: \times 9.8 {ms}^{ - 2} \\ = 9.8 \: \: N[/tex]

B. 9.8 N

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