What is an equation of the line that passes through the points (-6, -3) and
(-3, -5)?

Answer:

y = − 2 /3 x − 7

Step-by-step explanation:

Use the slope formula and slope-intercept form  y = m x + b  to find the equation.

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Hey buddy ....

I really appreciate God to give me this chance to help u.

Let's see what to do...

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First we need to find the slope of the line using this equation :

Suppose a = ( - 6 , - 3 ) , b = ( - 3 , - 5 )

[tex]slope = m = \frac{y(b) - y(a)}{x(b) - x(a)} \\ [/tex]

Just need to put the coordinates in the equation:

[tex]slope = \frac{ - 5 - ( - 3)}{ - 3 - ( - 6)} \\ [/tex]

[tex]slope = \frac{ - 5 + 3}{ - 3 + 6} \\ [/tex]

[tex]slope = \frac{ - 2}{ - 3} \\ [/tex]

[tex]slope = \frac{3}{2} \\ [/tex]

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We have this equation as the point-slope form of the linear functions :

[tex]y - y(one \: \: of \: \: the \: \: given \: \: points) = (slope) \times ( \: x - x(o \: o \: f \: t \: g \: p) \: ) \\ [/tex]

Now just need to put the slope and one the given points ( a or b ) in the above equation:

I like to use a ( you can use b bro )

[tex]y - ( - 3) = \frac{3}{2} \times (x - ( - 6) \: ) \\ [/tex]

[tex]y + 3 = \frac{3}{2} \times (x + 6) \\ [/tex]

[tex]y + 3 = \frac{3}{2} x + 9 \\ [/tex]

Subtract sides 3

[tex]y + 3 - 3 = \frac{3}{2} x + 9 - 3 \\ [/tex]

[tex]y = \frac{3}{2} x + 6 \\ [/tex]

And this is the equation of the line.

So we're done.....

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Take care dude ❤❤❤❤❤

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