an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
A metric unit of volume equal to a milliliter
Explain whether the size of an object's displacement could be greater than the distance the object travels
Answer:
Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector. So displacement cannot be more than distance.
The size of an object's displacement can never be greater than the distance the object travels by the object because displacement is the shortest distance traveled between the initial and the final position.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
Displacement can never be greater than the distance covered by any moving body.
Since displacement is the smallest distance between the beginning and final positions, the size of an object's displacement can never be more than the distance the object travels.
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True or false:
A small wire can conduct an infinite amount of current.
Answer:
True
Explanation:
Answer: very true
Explanation:
A car traveling at 30 m/s is brought to rest at a constant rate in 20 s by applying the brake. a) What is its acceleration? b) How far did it travel after the brake was applied?
Wanda is afraid of gaining weight and putting herself at high risk for disease. she works out on a regular basis and eats right most of time. recently, Wanda some testing done. her BMI with some 17.2 and her waist circumference is 30 inches. what statement best describes next move for Wanda so she will be at the least risk for disease?
Answer:
C. Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.
Explanation:
edge 2020 Brainliest would be appreciated
Answer:
Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.
Explanation:
I just did the Cumulative Exam Review
Which direction is the force of gravity on earth
Answer:
It is toward the center
Explanation:
I WILL MARK YOU AS BRAINLIEST IF RIGHT
In order to climb up a mountainside, a train needs to start at a speed of 40 mph. The speed limit on the track, however, is 25 mph. How much time does the train need to get up to 40 mph if it can accelerate 4 mph per minute ?
How do waves transfer energy? Be detailed.
Answer:
Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^
PLS HELP THIS IS FOR AN EXAM!!!
How many exercises encompass stretching in the human body
A) eight
B) too many to count
C) that depends on each individual
D) none
Answer: (B) Too many to count
Explanation: Have a wonderful day everyone! :D
The exercises that encompasses stretching in the human body is : B) too many to count
Meaning of exerciseexercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.
exercises are one of the keys to staying and living healthy.
exercises are of different types and forms and some encompasses stretching in the human body.
In conclusion, The exercises that encompasses stretching in the human body is too many to count
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What happens to the acceleration of a ball if the force increases while the mass remains the same?
Answer:
if the force increases while the mass of the ball remains the same, the acceleration increases.
Explanation:
According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
Suppose the net force doubles to 2Fn. The new acceleration will be:
[tex]\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a[/tex]
The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.
If you had a 30 pound barbell at home and you wanted to compare your muscular endurance to your younger brother's which method would be the best to use.
Answer:A
Explanation:
Absolute method
Answer:
absolute method
Explanation:
trust
Someone is spinning a basketball on his finger. If it is spinning at a rate of 8.92 times per second, what is the basketball's angular velocity in units of radians per second?
Answer:
angular velocity = 56.04 rad/s.
Explanation:
It is given that,
The baseball is spinning at the rate of 8.92 times per second.
We need to find the basketball's angular velocity in units of radians per second.
Here, frequency of the baseball is 8.92 Hz.
We know that Angular velocity is given by :
[tex]\omega=2\pi f\\\\\omega=2\pi \times 8.92 \\\\\omega=56.04\ rad/s[/tex]
So, the angular velocity of the basketball is 56.04 rad/s.
Physics Vectors-- Please could you help me ? For first question.
A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer). On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion). (a) Determine the barometric pressure in psia. If the ambient temperature increased to 85oF and the barometric pressure did not change, (b) would the mercury column be longer, be shorter, or remain the same length
Answer:
(a). 14.4 lbf/in^2.
(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
Explanation:
So, from the question above we are given the following parameters which are going to help us in solving this particular Question;
=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"
=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."
With these knowledge, let us delve right into the solution;
(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].
The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.
(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.
Length of mercury = 27.8 in.
AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
what happends when you slowly pull out the paper while theirs a coin on top
-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much practice. The observation of his parents swinging and practicing what he saw mainly involved _____ neurons; the neurons that are the basis of
Motor
Mirror
Sensory
Reticular
The observation of his parents swinging and practicing what he saw mainly involved sensory neurons.
There are five senses in the human body, they are;
SightSmellTouch TasteHearingInformation is passed to the central nervous system (CNS) from each of these senses.
The neurons that convey sensory information of sight, smell, touch, taste and hearing to the brain are called sensory neurons.
Thus, the observation of his parents swinging and practicing what he saw mainly involved sensory neurons.
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What element has similar chemical properties to lodine?*
Answer:
Iodine is most similar to the other non- metals in the Halogen Family, such as Fluorine, Chlorine, Bromine, Astatine .
Explanation:
A 30.0 g object fell from a height y = 2.94 m. It’s velocity when y is zero is approximately equal to (in m/s) (a) 0 (b) 19.6 (c) 29.4 (d) 8.64
Analysing the question:
We are given:
mass of object (m) = 0.03 kg
height of object (h) = 2.94 m
acceleration due to gravity (a) = 10 m/s²
initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]
final velocity (v) = v m/s
Solving for Final velocity:
from the third equation of motion:
v² - u² = 2ah
replacing the variables
(v)² - (0)² = 2(10)(2.94)
v² = 58.8
v = 7.67 m/s
A small mailbag is released from a helicopter that is rising\ steadily at 2.32 m/s.
(a) After 5.00 s, what is the speed of the mailbag?
(b) How far is it below the helicopter?
(c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.32 m/s?
Given parameters:
Velocity of the helicopter = 2.32m/s
Time given = 5.00s
Unknown:
a. Speed of the mailbag after 5s
b. How far is the mail bag below the helicopter
Solution:
In this problem, we must apply the appropriate motion equation to solve.
For a;
v = u + gt
v is the velocity of the mail bag
u is the initial velocity
g is the acceleration due to gravity
t is the time taken
Notice that the initial velocity of the mail bag is 0;
V = 0 + 9.8 x 5 = 49m/s
For b;
Using;
h = ut + [tex]\frac{1}{2}[/tex] gt²
where u is 0;
h = [tex]\frac{1}{2}[/tex] x 9.8 x 5² = 122.5m
Invisible fence for dogs. In this type of system, a wire is buried under the surface and a current at a given frequency passes through the wire. The dog wears a small unit made of a pickup coil and electronics that delivers a short high-voltage pulse to the dog through a couple of electrodes pressed against its skin. The pulse is not harmful, but it does provide a correction that encourages the dog to keep away. In an invisible fence, the wire carries a 10kHz sinusoidal current with an amplitude of 0.5 Amps. The dog carries a sensoron its collar made as a coil with 150 turns and 30 mm in diameter.If the detection level at the coil inside the collar is set at 200 μV RMS (i.e., the level at which the dog will receive a correction pulse), what is the furthest distance from the wire the dog will "feel" the presence of the fence?
Answer:
The distance is [tex] s = 2.3 \ m [/tex]
Explanation:
From the question we are told that
The frequency of the current is [tex]f = 10\ kHz = 10 *10^{3} \ Hz[/tex]
The magnitude of the current is [tex]I_o = 0.5\ Amps[/tex]
The number of turns is [tex]N = 150\ turns[/tex]
The diameter is [tex]d = 30 mm = 0.03 \ m[/tex]
The detection level is [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.03}{2}[/tex]
=> [tex]r 0.015 \ m [/tex]
Generally the magnetic field generated by the fence is mathematically represented as
[tex]B = \frac{\mu_o * N * I}{2 * \pi * s}[/tex]
Here s is the point where the do will feel the magnetic field
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2 [/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s}[/tex]
Generally the magnetic flux is mathematically represented as
[tex]\Phi = B * \pi * r^2[/tex]
=> [tex]\Phi = \frac{ 4\pi * 10^{-7} * 150 * I}{2 * 3.142 * s} * \pi * r^2[/tex]
=> [tex]\Phi = \frac{2.121 *10^{-8} * I }{s}[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon =- \frac{d \Phi}{dt}[/tex]
=> [tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d I}{dt}[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi f[/tex]
=> [tex]w = 2 * 10*10^{3} \pi [/tex]
=> [tex]w = 20000 \pi [/tex]
So the current is mathematically represented as
[tex]I = I_o sin (wt)[/tex]
=> [tex]I = I_o sin ( 20000 \pi * t)[/tex]
So
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * I_o * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi [ cos ( 20000 \pi * t) [/tex]
[tex]\epsilon =- \frac{ 6.6*10^{-4} }{ s } [ cos ( 20000 \pi * t) [/tex]
Here the
[tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]
=> [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2} }[/tex]
But from the question we are told that [tex]V_{rms} = 200 \mu V = 200 * 10^{-6} \ V[/tex]
So
[tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2} } = 200 * 10^{-6}[/tex]
=> [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]
=> [tex] s = 2.3 \ m [/tex]
To a stationary observer, a man jogs east at 2 m/s and a woman jogs west at
3 m/s. From the woman's frame of reference, what is the man's velocity?
Answer:
5 m/s east
Explanation:
i just took the test and it was correct
Answer:
Just took the test. 5 m/s east.
Explanation:
A target lies flat on the ground 4 m from the side of a building that is 10 m tall, as shown below.
The acceleration of gravity is 10 m/s^2.
Air resistance is negligible.
A student rolls a 4 kg ball off the horizontal
the roof of the building in the direction of the
target.
The horizontal speed v with which the ball
must leave the roof if it is to strike the target
is most nearly
1. v =√3 /4 m/s.
2. v =4√3 /3 m/s.
3. v = 4 m/s.
4. v = 2√2 m/s.
5. v =√2 / 4 m/s.
6. v =√5 / 4 m/s.
7. v = 4√3 m/s.
8. v = 4√5 m/s.
9. v = 6 m/s.
10. v = 4√2 m/s.
Answer:
v = 2√2 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Horizontal distance (s) = 4 m
Horizontal velocity (v) =.?
Next, we shall determine the time taken for the ball to get to the target.
This can be obtained as shown below:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
h = ½gt²
10 = ½ × 10 × t²
10 = 5 × t²
Divide both side by 5
t² = 10/5
t² = 2
Take the square root of both side.
t = √2 s
Finally, we shall determine the horizontal velocity as shown below:
Horizontal distance (s) = 4 m
Time (t) = √2 s
Horizontal velocity (v) =.?
s = vt
4 = v × √2
Divide both side by √2
v = 4 /√2
Rationalise the denominator
v = (4 /√2) × √2/√2
v = 4 × √2 / √2 × √2
v = 4 × √2 / 2
v = 2√2 m/s
Lien is pushing a box across a table. She used a force of 100 N to get the box moving. Which force did she overcome
to get the box moving?
O the downward force of gravity on the box
O the upward force of the table on the box
the reaction force on the box
O the push force on the box
Answer:
the reaction force on the box
Explanation:
In order to push or pull an object, an external force is needed to overcome the weight of that object. This force is called ACTION FORCE. However, according to 3rd law of Newton, which states that for every action, there is an equal and opposite reaction, an opposite force counters the object in an opposite direction. This force is called REACTION FORCE.
According to this question, Lien is pushing a box across a table. She used a force of 100 N to get the box moving. This means that she had to overcome an opposite force called REACTION FORCE, with an ACTION FORCE of 100N
Answer:
C. the reaction force on the box
Explanation:
i literally just finished the quiz
Position vs Time
for Two Cars
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions.
Car A is moving faster than car B.
A
B
O Car A and car B started at the same location.
Position (m)
O Car A started ahead of car B.
Time (s)
) Intro
Done
Explanation:
Based on the diagram below we can make the following conclusions that:
Car A and Car B are moving in opposite directionsCar A is moving faster than Car B.This conclusion is based on the type of slope evident in each case. One has a positive slope, the other a negative slope.
What is the equivalent temperature in kelvin if you have a metal at 50°F?
A.
50 K
B.
150 K
C.
283 K
D.
300 K
Answer:
The answer is C 283 kelvin
Answer: C.
283 K
Explanation: edmentum
An electron is accelerated from rest by a potential difference of 435 V. It then enters a uniform magnetic field of magnitude 167 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
Answer:
(a) the speed of the electron is 1.237 x 10⁷ m/s
(b) the radius of its path in the magnetic field is 4.21 x 10⁻⁴ m
Explanation:
Given;
potential difference, V = 435 V
magnetic field, B = 167 mT = 0.167 T
(a) the speed of the electron
eV = ¹/₂mv²
[tex]v = \sqrt{\frac{2eV}{m} }\\\\ v = \sqrt{\frac{2(1.6*10^{-19})(435)}{(9.1*10^{-31})}}\\\\v = 1.237*10^7 \ m/s[/tex]
(b) the radius of its path in the magnetic field
[tex]r = \frac{mv}{eB}\\\\r = \frac{(9.1*10^{-31})(1.237*10^7)}{(1.6*10^{-19})(0.167)}\\\\r = 4.21 *10^{-4} \ m[/tex]
FIGURE 1 shows a horizontal human arm lifting a dumbbell. The forearm is
in equilibrium under the action of the weight of the dumbbell, the tension
in the tendon connected to the biceps muscle, and the force exerted on the
forearm itself. (For clarity, the point A where the tendon is attached is drawn
farther from the elbow than its actual position) Given the weight of the forearm
is 20 N and the mass of the dumbbell is 20 kg. The angle between the tension
force and the horizontal, is 80°. The length of the horizontal arm is 0.30 m.
The horizontal distance between elbow pivot and point A is 0.050 m. Find and
the vector and draw free body diagram for this case
Answer:
Explanation:
See attached file for answer.
Why does a sound come out when you blow into a bottle?
When does the jet of air convert to vibrations?
g A person exploring a deep cave system becomes injured and needs to be rescued. The fastest way to get them is to pull them straight up out of the cave through a small opening just overhead, using a motor-driven cable. The lift is performed in three stages, each of them 10 m in height (total of 30 meters to extract the person). In the first stage, the person is accelerated to a speed of 5 m/s. They are then lifted at constant speed of 5 m/s, then in the last stage they are slowly decelerated to zero speed. If the person weighs 80 kg, how much work is done in each stage
Answer:
1. W = 8848 J
2. W = 7848 J
3. W = 6848 J
Explanation:
The work (W) can be found using the following equation:
[tex] W = E_{k} + E_{p} [/tex]
Where: E(k) is the kinetic energy and E(p) is the potential energy
Now let's find the work for every stage.
Stage 1:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh [/tex]
Where: m is the mass, g is the gravity, h is the height, v is the speed
[tex] W = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 8848 J [/tex]
Stage 2:
[tex] W = E_{k} + E_{p} = 0 + E_{p} [/tex]
The kinetic energy is equal to zero because the acceleration is constant.
[tex] W = E_{p} = mgh = 80 kg*9.81 m/s^{2}*10 m = 7848 J [/tex]
Stage 3:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh = -\frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 6848 J [/tex]
I hope it helps you!
please please please please
Answer:
....................
Answer:
20
Explanation:
40/2.0=20.......
hope it helps