What are the operating system roles?

Answer:

Written in Python

inp = int(input("Length: "))

num = []

num.append(inp)

for i in range(1,inp+1):

    userinp = int(input("Input: "))

    num.append(userinp)

smallest = num[1]

for i in range(1,len(num)):

    if smallest > num[i]:

         smallest = num[i]

for i in range(1,len(num)):

    num[i] = num[i] - smallest

for i in range(1,len(num)):

    print(num[i],end=' ')

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

The answer to this question is given below in the explanation section.

Explanation:

This question is about mapping correct terms with their number in the given picture. The correct matching of Column A and Column B is given below

Column A                               Column B

Horizontal axis                        3

Legend                                    4

Vertical axis                             2

Chart Data                               1

def something(string1, string2):

return True if string2 in string1 else False

This would be the most concise way of writing this function.

Answer:

Slide Shorter View

Explanation:

If Maya wants to access a view that would control multiple slides within a presentation, which view should she utilize Slide Shorter View.

View of the Slide Sorter from the task bar displays the Slide View button in PowerPoint, either from the View tab on the ribbon or at the bottom of the slide window.

The Slide Sorter view (below) shows thumbnails of each slide in your presentation in a horizontally stacked order. If you need to rearrange your slides, the slide show view comes in handy.

You can simply click and drag your slides to a new spot or add sections to categorize your slides into useful groupings.

Therefore, If Maya wants to access a view that would control multiple slides within a presentation, which view should she utilize Slide Shorter View.

To learn more about Slide shorter view, refer to the link:

https://brainly.com/question/13736919

#SPJ6

Answer:

using a limited access public computer to watch movies

Explanation:

Cause it doesn't involve you performing any illegal actions.

Answer:

C. using a limited access public computer to watch movies

Explanation:

IM A DIFFERENT BREEED!!

PLUS NOTHING ELSE MAKES SENSE LOL!

Answer:

The Program written in C is as follows:

#include <stdio.h>

int main() {

   int num1, num2, num3, smallest;

   printf("Enter any three numbers: ");

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

   printf("Smallest: ");

   printf("%d", num3);

   return 0;

}

Explanation:

This line declares necessary variables

int num1, num2, num3, smallest;

This line prompts user for input of three numbers

   printf("Enter any three numbers: ");

This lines get input for the three numbers

   scanf("%d", &num1);    scanf("%d", &num2);    scanf("%d", &num3);

The following if/else statements determine the smallest of num1, num2 and num3 and assigns to variable smallest, afterwards

   if(num1 <= num2 && num1 <= num3) {

       smallest = num1;

   }

   else if(num2 <= num1 && num2 <= num3) {

       smallest = num2;

   }

   else {

       smallest = num3;

   }

The next two lines print the smallest value

   printf("Smallest: ");

   printf("%d", num3);

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //PrompT the User to enter a String

   System.out.println("Enter a sentence or phrase: ");

   //Receiving the string entered with the Scanner Object

   Scanner input = new Scanner (System.in);

   String string_input = input.nextLine();

   //Print out string entered by user

   System.out.println("You entered: "+string_input);

   //Call the first method (GetNumOfCharacters)

   System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

   //Call the second method (OutputWithoutWhitespace)

   System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

   }

 //Create the method GetNumOfCharacters

   public static int GetNumOfCharacters (String word) {

   //Variable to hold number of characters

   int noOfCharactersCount = 0;

   //Use a for loop to iterate the entire string

   for(int i = 0; i< word.length(); i++){

     //Increase th number of characters each time

     noOfCharactersCount++;

   }

   return noOfCharactersCount;

 }

 //Creating the OutputWithoutWhitespace() method

 //This method will remove all tabs and spaces from the original string

 public static String OutputWithoutWhitespace(String word){

   //Use the replaceAll all method of strings to replace all whitespaces

   String stringWithoutWhiteSpace = word.replaceAll(" ","");

   return stringWithoutWhiteSpace;

 }

}

Explanation:

question a) answer:

At the moment when it sends the package, then it has a waiting time for the acknowledgement from the receiver, however, the time will be split in two when the frameset size becomes two, meaning that two packages have been sent together, causing the receiver to acknowledge only one package.

question b) answer:

The timeout is equal to two times.

In cases when the frame size is 3, the frame will be lost since the timeout turns to be 2 times. Because the sender has to wait for the acknowledgement, therefore it will send other of the parcels.

Answer:

please find the attachment of a graph:

Explanation:

Description of the model:

Enhanced Entity relationships[EER] represent the requirements and complexities of a complex database.

Here, the account entity generalized into three entities and these are checking, savings, and loan.

Also, the common attribute the three of them have can be considered in the account entity which is common in them while the individual attributes must be specified under its own entity.

EER models are the helpful tools used for designing databases that have high-level models.

Learn more about databases on:

https://brainly.com/question/518894

Hi, your question is incomplete. Here are the options:

A. persuade the audience.

B, encourage critical thinking.

C. increase discussion.

D. relay detailed information

Answer:

D. relay detailed information

Explanation:

Indeed, slide software (like MS Powerpoint) would be an effective presentation tool, especially when the speech goal is to relay detailed information.

For example, a graph showing the exponential growth in the number of smartphone users in the United States for the last 15 years would be effectively presented using a slide that shows this data because it will allow the audience to easily see the detailed information.

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

Read more about conjunction

brainly.com/question/8094735

Answer: 40, 4

Explanation:

In python, the sort() function will alphabetically sort a list of strings

To write a block of code that will organize a list of items alphabetically  In python, the sort() function will alphabetically sort a list of strings.

A high-level, all-purpose programming language is Python. Code readability is prioritized in its design philosophy, which makes heavy use of indentation. Python uses garbage collection and has dynamic typing. It supports a variety of paradigms for programming, including functional, object-oriented, and structured programming.

Python is a popular computer programming language used to create software and websites, automate processes, and analyze data. Python is a general-purpose language, which means it may be used to make many various types of applications and isn't tailored for any particular issues.

Sorting in Python simply means putting the data in a specific format or order. The order of the data pieces can be sorted either ascendingly or descendingly. Python programming contains certain built-in functions that allow you to sort the list's elements, just like C++ and Java.

Therefore, Thus option (C) is correct.

Learn more about python here:

https://brainly.com/question/18502436

#SPJ2

Answer:

The corrected program is:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int qtr, dime, nickel, penny;

double dollars;

System.out.print("Quarters: ");

qtr =scnr.nextInt();

System.out.print("Dimes: ");

dime = scnr.nextInt();

System.out.print("Nickel: ");

nickel = scnr.nextInt();

System.out.print("Penny: ");

penny = scnr.nextInt();

dollars = qtr * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

}

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program

Answer:

Written in Python

import random

tryagain = 1

while tryagain == 1:

guess = int(input("Enter your guess number between 1 and 6: "))

num = random.randint(1,7)

if guess == num:

print("Your guess is correct")

else:

print("Wow, the dice number is "+str(num))

tryagain = int(input("Do you want to dice it up again:Enter 1 and if not enter 0: "))

Explanation:

I've added the full source code as an image attachment where I used comments to explain difficult lines

Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

Corrected Question

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a 1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – find the target element and printing out the target and its index as well as the entire array

Answer:

The solution is given in the explanation section

See detailed explanation of each step given as comments

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //Create the array of 15 elements

   int [] array = new int [15];

   //Create an object of the scanner class to receive user input

   Scanner in = new Scanner(System.in);

   //Prompt user to enter the values in sorted order

   //Using a for loop

   for (int i =0; i<array.length; i++){

         System.out.println("Enter the next element: In SORTED order please!");

         array[i] = in.nextInt();

   }

   System.out.println("All Fifteen element have been entered");

   // Ask the user for an element to be searched for

   //A target element

   System.out.println("Which element do you want to search for in the array");

   //Create the target element

   int target = in.nextInt();

   //Use a for loop to sequentially check each element in the array

   for(int i = 0; i<array.length; i++){

     if(array[i]==target){

       System.out.println(target+" is found at index "+i +" of the array");

     }

   }

       // Printout the entire array

   System.out.println(Arrays.toString(array));

 }

}

Answer:

4 beeps indicate a Memory Read / Write failure. Try re-seating the Memory module by removing and reinserting it in the slot. This could mean it could've just jiggled loose after a while or dust, there could be a hundred other problems but those are the two most common.n

Explanation:

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

true

Screenshots are basically snapshots of your computer screen. You can take a screenshot of almost any program, website, or open window. PowerPoint makes it easy to insert a screenshot of an entire window or a screen clipping of part of a window in your presentation.

Answer:

Choose file>import>import library

Explanation:

because it is the process to add images to your library

Answer:

ok so u have take the 5 and put 6

Explanation:

5-5. Ethernet network design: UTP connections from client PC and server to workgroup switches, 900m fiber optic link between switches, 800 Mbps communication.

5-6. Additional client connects to the same switch, UTP connection, maintains existing fiber optic link, 800 Mbps communication with the server.

5-5. For connecting a single client PC to a single server, both located 900 meters apart and requiring communication at 800 Mbps, the following Ethernet network design can be implemented:

- Client PC and server connect to their respective workgroup switches via UTP.

- Use fiber optic cables for the 900-meter transmission link between the switches.

- Install switches at the client PC and server locations.

- Ensure that the switches support at least 1 Gbps Ethernet speeds to accommodate the required transmission speed.

5-6. In addition to the previous design, for adding another client next to the first client:

- Connect both clients to the same switch.

- Use UTP cables to connect the second client to the switch.

- Ensure the switch supports 1 Gbps Ethernet speeds.

- Maintain the existing fiber optic transmission link between the switches.

- The second client can also communicate with the server at the required 800 Mbps transmission speed.

Learn more about Network Design at:

https://brainly.com/question/7181203

#SPJ2

Answer:

prt scan+Windows logo

Answer:

Hexagonal cell shape is perfect over square or triangular cell shapes in cellular architecture because it cover an entire area without overlapping i.e. they can cover the entire geographical region without any gaps.

I hope this helps

Pls mark as brainliest

Answer:

Here is the Coin class:

public class Coin {  //class names

 private int value;  // private member variable of type int of class Coin to store the value

 private String coinName;  // private member variable of type String of class Coin to store the coint name

 private double weight;      //private member variable of type double of class Coin to store the weight

  public void setValue (int v) {  //mutator method to set the value field

    value = v;  }  

 public void setName(String n){  //mutator method to set coinName field

    coinName = n;}  

 public void setWeight (double w) {  //mutator method to set weight field

    weight = w;  }  

 public int getValue () {  //accessor method to get the value

   return value;  }  // returns the current value

 public String getName () {  //accessor method to get the coin name

   return coinName;  }  //returns the current coin name

 public double getWeight () {   //accessor method to get the weight

   return weight;  } } //returns the current weight

Explanation:

Here is the Main.java

public class Main{ //class name

public static void main(String[] args) { //start of main method

Coin penny = new Coin(); //creates object of Coin class called penny

penny.setName("Penny");  //calls setName method of Coin using object penny to set the coinName to Penny

penny.setValue(1); //calls setValue method of Coin using object penny to set the coin value to 1

penny.setWeight(0.003); //calls setWeight method of Coin using object penny to set the coin weight to 0.003

   System.out.println("Coin name: " + penny.getName()); // calls getName method of Coin using penny object to get the current coin name stored in coinName field    

   System.out.println("Coin value: " + penny.getValue()); // calls getValue method of Coin using penny object to get the coin value stored in value field    

   System.out.println("Coin weight: " +penny.getWeight()); }} // calls getWeight method of Coin using penny object to get the coin weight stored in weight field    

The value of coinName is set to Penny, that of value is set to 1 and that of weight is set to 0.003 using mutator method and then the accessor methods to access these values and prinln() to display these accessed values on output screen. Hence the output of the entire program is:

Coin name: Penny                                                                                                                                Coin value: 1                                                                                                                                   Coin weight: 0.003

The screenshot of the program along with its output is attached.

Answer:

que pinga this is a hw website not snap

Explanation:

Answer:

all of the layers

Explanation:

Answer:

a couple of the layers

Explanation: says it in the first sentence in the last paragraph of this image