VIJWPLAYER
Which ordered air is a solution for the equation y = 4.5x?

A. (0, 4.5)
B. (4.5, 1)
C. (2.9)
D. (18,4)

Answer:

a. (5,5)

b. (-5,-5)

Step-by-step explanation:

reflection over x-axis flips the sign of y-coordinate

reflection over y-axis flips the sign of x-coordinate

Answer:

5.5

Step-by-step explanation:

Answer:

15000(1.003425)^12t ;

4.11%

4.188%

Step-by-step explanation:

Given that:

Loan amount = principal = $15000

Interest rate, r = 4.11% = 0.0411

n = number of times compounded per period, monthly = 12 (number of months in a year)

Total amount, F owed, after t years in college ;

F(t) = P(1 + r/n)^nt

F(t) = 15000(1 + 0.0411/12)^12t

F(t) = 15000(1.003425)^12t

2.) The annual percentage rate is the interest rate without compounding = 4.11%

3.)

The APY

APY = (1 + APR/n)^n - 1

APY = (1 + 0.0411/12)^12 - 1

APY = (1.003425)^12 - 1

APY = 1.04188 - 1

APY = 0.04188

APY = 0.04188 * 100% = 4.188%

Answer:

No

Step-by-step explanation:

Because 0.38 is 0.08 more than 0.3.

Answer:

Step-by-step explanation:

c(25) = 85(25) + 600 = 2725

Answer:

Step-by-step explanation:

12 + 4b = 72

Subtract 12 on both sides

4b = 60

b = 15

Answer:

x = 10 since 10 x 10 = 100

Step-by-step explanation:

Answer:

Respuesta: SI

Step-by-step explanation:

Números Racionales

Un número pertenece al conjunto de los números racionales (Q) si se puede expresar como una fracción de denominador diferente de cero, es decir, x es racional si:

[tex]\displaystyle x=\frac{a}{b}[/tex]

Donde a y b son número enteros y además b es diferente de cero

el número

[tex]\displaystyle -\frac{3}{5}[/tex]

Tiene un numerador igual a 3 y un denominador igual a 5 (independientemente del signo), por lo tanto cumple con las dos condicines y es efectivamente un número racional.

Respuesta: SI

Answer:

Step-by-step explanation:

Alberto traveled v km/h.

After 1 hour they are v km apart.

Danielle travels (v+10) km/h.

The distance between them decreases by 10 km/h.

They meet in 5 hours, after Danielle has traveled 5v+50 km and Alberto has traveled 6v km.

6v = 5v+50

v = 50 km/h

Alberto travels 50 km/h

Answer:

12

Step-by-step explanation:

its either 12 or 18 try 12 first

Answer:

The relationship between d, c and p is that [tex]p = \frac{4c^2}{9d}[/tex]

Step-by-step explanation:

Roots of a quadratic equation:

The roots [tex]r_1[/tex] and [tex]r_2[/tex] of a quadratic equation in the following format:

[tex]ax^2 + bx + c = 0[/tex]

Can be given by:

[tex]r_1 + r_2 = -\frac{b}{a}[/tex]

[tex]r_1r_2 = \frac{c}{a}[/tex]

In this question:

We have the following quadratic equation:

[tex]dx^2 - cx + p = 0[/tex]

So [tex]a = d, b = -c, c = p[/tex]

One of the roots is twice the other:

So [tex]r_2 = 2r_1[/tex]

First relation:

[tex]r_1 + r_2 = -\frac{b}{a}[/tex]

[tex]r_1 + 2r_1 = -\frac{(-c)}{d}[/tex]

[tex]3r_1 = \frac{c}{d}[/tex]

[tex]r_1 = \frac{c}{3d}[/tex]

Second relation:

[tex]r_1r_2 = \frac{c}{a}[/tex]

[tex]r_1*2r_1 = \frac{p}{d}[/tex]

[tex]2r_{1}^{2} = \frac{p}{d}[/tex]

[tex](\frac{2c}{3d})^2 = \frac{p}{d}[/tex]

[tex]\frac{4c^2}{9d^2} = \frac{p}{d}[/tex]

[tex]p = \frac{4c^2}{9d}[/tex]

The relationship between d, c and p is that [tex]p = \frac{4c^2}{9d}[/tex]

Answer:

A. AC

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

25/100 × 200

= 25×2

=50

Answer:

24 pages

Step-by-step explanation:

102 copies in 4 1/4 minutes

102 / 1 ÷ 17 / 4

102 / 1 × 4 / 17 = 24

Answer:

✔️The graph contains point zero

✔️There's a closed circle on 2⁸/9

✔️The arrow points to the left

Step-by-step explanation:

The inequality, 2⁸/9 ≥ x, implies that 2⁸/9 is either equal to x or more than x. In other words, the highest value of x is 2⁸/9. Possible value of x is equal to or less than 2⁸/9.

This, on a number line, we would graph the information as follows:

✔️The graph contains point zero

Rationale: point zero is less than 2⁸/9

✔️There's a closed circle on 2⁸/9

Rationale: this indicates 2⁸/9 is included in the possible value of x

✔️The arrow points to the left

Rationale: possible value of x ranges from 2⁸/9 and below.

Answer: b c d

Step-by-step explanation:

heart it please ;) your welcome

Answer:

see explanation

Step-by-step explanation:

22

- [tex]\sqrt{x}[/tex] is a reflection of [tex]\sqrt{x}[/tex] in the x- axis

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Thus

g(x) = - [tex]\sqrt{x}[/tex] - 4

is a reflection in the x- axis, followed by a vertical translation 4 units down

23

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Thus

h(x) = [tex]\sqrt[3]{x+1}[/tex] + 5

is a horizontal translation 1 unit left and a vertical translation of 5 units up

Answer:

22

- \sqrt{x}

x

is a reflection of \sqrt{x}

x

in the x- axis

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Thus

Answer:

a.)Q' = -kQ + r

b.)Q = [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

c.) Limiting long run value of Q = [tex]\frac{r}{k}[/tex]

Step-by-step explanation:

a.)

The rate of change is directly proportional to the quantity, Q

⇒[tex]\frac{dQ}{dt}[/tex] ∝ Q

⇒[tex]\frac{dQ}{dt}[/tex] = -kQ ( because it is decreasing )

Also given, quantity is increasing with a constant rate r

⇒[tex]\frac{dQ}{dt}[/tex] = -kQ + r

⇒Q' = -kQ + r

b.)

As we have

[tex]\frac{dQ}{dt}[/tex] = -kQ + r

⇒[tex]\frac{dQ}{-kQ + r}[/tex] = dt

⇒∫[tex]\frac{dQ}{-kQ + r}[/tex] = ∫dt

⇒-[tex]\frac{1}{k}log(-kQ + r) = t + C[/tex]

⇒log(-kQ + r) = -kt -kC

Taking exponential both side, we get

⇒-kQ + r = [tex]e^{-kt +A}[/tex]

⇒-kQ = -r + [tex]e^{-kt +A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]e^{-kt +A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]e^{-kt}.e^{A}[/tex]

⇒Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex][tex]Be^{-kt}[/tex]      .......(1)

Now,

At t = 0, Q = 0

0 = [tex]\frac{r}{k}[/tex] - [tex]\frac{1}{k}[/tex]B

⇒[tex]\frac{1}{k}B = \frac{r}{k}[/tex]

⇒B = r

∴ equation (1) becomes

Q = [tex]\frac{r}{k}[/tex] - [tex]\frac{r}{k}[/tex][tex]e^{-kt}[/tex]

⇒Q = [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

c.)

for limiting long run value of Q

[tex]\lim_{n \to \infty} Q = \lim_{n \to \infty}[/tex]   [tex]\frac{r}{k} [ 1 - e^{-kt} ][/tex]

               =  [tex]\frac{r}{k}[/tex][tex]\lim_{n \to \infty} [ 1 - e^{-kt} ]= \frac{r}{k} [ 1 - e^{\infty} ] = \frac{r}{k}[ 1-0][/tex]

               = [tex]\frac{r}{k}[/tex]

⇒Limiting long run value of Q = [tex]\frac{r}{k}[/tex]

Q' = -kQ + r

Q = r/k (1- [tex]\rm e^{-kt}[/tex])

The limiting long-run value of Q = [tex]\rm \frac{r}{k}[/tex]

A drug is administered intravenously at a constant rate of r mg/hour and is excreted at a rate proportional to the quantity present, with a constant of proportionality k > 0.

The differential equation is an equation that contains the derivative of the unknown function.

a) It is given that the rate of change is directly proportional to the quantity Q

[tex]\rm \frac{dQ}{dt}[/tex] ∝ Q

[tex]\rm \frac{dQ}{dt}[/tex] = -kQ

So, Q' = -kQ + r

where quantity Q is increasing with constant rate r and k is unknown constant.

b) Q' = -kQ + r

[tex]\rm \frac{dQ}{dt}[/tex] = -kQ + r

[tex]\rm \frac{dQ}{-kQ+r}=dt\\[/tex]

[tex]\int\limits {\rm \frac{dQ}{-kQ+r} = \int\limits dt[/tex]

log(-kQ + r) = -kt -kC

by taking exponential both side, we get

-kQ + r = [tex]e^{-kt+A}[/tex]

-kQ = -r + [tex]e^{-kt+A}[/tex]

-Q /k= -r/k + [tex]e^{-kt+A}[/tex]/k

Q = -r/k -[tex]\rm \frac{1}{k}Be^{-kt}[/tex]

At t = 0, Q = 0

[tex]\rm \frac{1}{k} B=\frac{r}{k}[/tex]

B = r

by substituting the value in the above equation

Q = r/k (1- [tex]\rm e^{-kt}[/tex])

c) The limiting long-run value of Q

[tex]\rm \lim_{n \to \infty} Q= \lim_{n \to \infty} \frac{r}{k} [1-e^{-kt} ]\\\rm= \frac{r}{k}\lim_{n \to \infty} [1-e^{-kt} ]\\\rm =\frac{r}{k}[1-0]\\\rm=\frac{r}{k}[/tex]

The value Q =[tex]\rm \frac{r}{k}[/tex]

Learn more about differential equations here:

https://brainly.com/question/25731911

Answer:

[tex]c = 14.9cm[/tex]

Step-by-step explanation:

Given

[tex]b = 10cm[/tex]

[tex]B = 12^{\circ}[/tex]

[tex]A = 150^{\circ}[/tex]

Required

Determine the length of c

First, we calculate C (the third angle of the triangle).

[tex]C = 180 - A - B[/tex]

[tex]C = 180 - 150 - 12[/tex]

[tex]C = 18^{\circ}[/tex]

Using Sine's law, we make use of:

[tex]\frac{sin\ B}{b} = \frac{sin C}{c}[/tex]

By substituting values, we have:

[tex]\frac{sin\ 12}{10} = \frac{sin 18}{c}[/tex]

Cross multiply

[tex]c* sin\ 12 = 10 * sin\ 18[/tex]

Make c the subject

[tex]c = \frac{10 * sin\ 18}{sin\ 12}[/tex]

[tex]c = \frac{10 * 0.3090}{0.2079}[/tex]

[tex]c = 14.9cm[/tex] approximated

Answer:

acute angle

Step-by-step explanation:

Big brain

Answer:

Adjacent

Step-by-step explanation:

Answer:

The recurring decimal 0.004 in friction is 1/250

Answer:

Step-by-step explanation:

Let x=0.004444....

1000x-100x=4.444... -0.444...

900x=4

x=4/900=1/225

Answer:

What impact did the American Revolution have on Haiti? The American Revolution occurred first and in part inspired the Haitian and French Revolutions. ... The Haitian Revolution was the first and only slave uprising that led to the establishment of a free state without slavery and ruled by non-whites and former slaves.

What impact did the Haitian Revolution have on the United States?The Haitian Revolution had many international repercussions. It ended Napoleon's attempts to create a French empire in the Western Hemisphere and arguably caused France to decide to sell its North American holdings to the United States (the Louisiana Purchase)—thus enabling the expansion of slavery into that territory.

Step-by-step explanation:

BRAINLIST PLEASE!!

Answer:

twenty eight more weeks till$200

Answer:

0.8022

Step-by-step explanation:

difference=subtraction

so we take 1 - 0.1978 and it equals 0.8022

Answer:

The mean is 95 and the standard deviation is 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Population:

Mean 95, Standard deviation 12

Samples of size 36:

By the Central Limit Theorem,

Mean 95

Standard deviation [tex]s = \frac{12}{\sqrt{36}} = 2[/tex]

Answer:

A bar graph shows amounts as bars of different sizes and, sometimes, of different colors. Longer bars represent larger numbers.