Two weeks in a row, the golf course hosts a group of golfers. The second week had 10 more golfers than the first week. Use the dot plots to choose the true statement.

dot plot titled Number of Golfers for Week 1 with number line labeled Age of Golfer, 1 dot at 62, 3 dots at 68, 1 dot at 69, 2 dots at 70, 3 dots at 72, 2 dots at 75, 1 dot at 76, 2 dots at 78, 3 dots at 80, and 2 dots at 89

dot plot titled Number of Golfers for Week 2 with number line labeled Age of Golfer, 2 dots at 62, 3 dots at 64, 3 dots at 68, 1 dot at 69, 2 dots at 70, 3 dots at 72, 2 dots at 75, 1 dot at 76, 2 dots at 78, 3 dots at 80, 2 dots at 85, 3 dots at 86, and 2 dots at 89

The range for Week 1 equals the range for Week 2.
The range for Week 1 is greater than the range for Week 2.
The median for Week 1 is less than the median for Week 2.
The mean for Week 1 is greater than the mean for Week 2.

Answer:

[tex]Area = 52\sqrt3 \ ft^2[/tex]

Step-by-step explanation:

Area of trapezoid

                         [tex](\frac{a+ b}{2}) \times h[/tex]      -----------( 1 )

We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.

[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex]   [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]

[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]

Therefore, h = 4√3 ft

[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex]    [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]

[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]

Therefore, a = 11 feet, b = 11 + 4 = 15 feet

Substitute the values in the Area equation :

                                                [tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]

Answer:

it's B

Step-by-step explanation:

I'm quite sure it is. Hope it helps u

Answer:

correct bayan HAHAHAHAHAHA

Answer:

[tex]18 + 18 + 18 = 18 \times 3 = 54[/tex]

Step-by-step explanation:

I ain't sure but it might help you out:D

Answer:

140.3 cm²

Step-by-step explanation:

area of an equilateral triangle

[tex] = \frac{\sqrt{3} }{4} {a}^{2} [/tex]

where a is the side of the triangle

[tex] = \frac{ \sqrt{3} }{4} \times {18}^{2} \\ = 140.3 \: cm {}^{2} [/tex]

Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Given:

The functions are:

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

To find:

The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Solution:

We have,

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

Now,

[tex](a+b)(x)=a(x)+b(x)[/tex]

[tex](a+b)(x)=4x+9+3x-5[/tex]

[tex](a+b)(x)=7x+4[/tex]

Similarly,

[tex](a-b)(x)=a(x)-b(x)[/tex]

[tex](a-b)(x)=4x+9-(3x-5)[/tex]

[tex](a-b)(x)=4x+9-3x+5[/tex]

[tex](a-b)(x)=x+14[/tex]

And,

[tex](ab)(x)=a(x)b(x)[/tex]

[tex](ab)(x)=(4x+9)(3x-5)[/tex]

[tex](ab)(x)=12x^2-20x+27x-45[/tex]

[tex](ab)(x)=12x^2+7x-45[/tex]

And,

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]

Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].

Answer:

[tex] \sqrt[5]{96x {}^{7} y {}^{11} } = 2xy {}^{2} \sqrt[5]{3x {}^{2}y } [/tex]

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

Answer:

1. C(13inches)

2. A(40°)

3. B(126°)

4. C(50°)

5. 7cm

Step-by-step explanation:

According To the Question,

1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon  with all sides equal.

Thus, Octagon has 8 equal side

So, Each Side Measure = 104/8 ⇔ 13inches

2. Given, In Triangle ABC, ∠A & ∠B each measure 70°

And, We Know Sum of all angles of a triangle is 180°.

Thus, ∠C = 180° - (∠A + ∠B)  ⇔  180°-140° ⇒ 40°

3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .

And, We know sum of all angles of quadrilateral is 360°.

Thus, ∠D=360° - (∠A+∠B+∠C)  ⇔ 360°-234° ⇒ 126°

4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .

And, We know sum of all the angles of quadrilateral is 360°.

Thus, ∠A+∠B+∠C+∠D = 360°

Put all the Values, we get

x+40+130+x+2x-10 = 360

4x+160 = 360

4x = 200 ⇔ 200/4 ⇒ 50°

5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .

Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.

So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .

Assume, if third side be 3cm (First Side+Third side > Second side)

3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)

Hence, The other Side of Triangle Surely be 7 cm.  

Answer:

[tex]\frac{7}{4.1}[/tex]

Step-by-step explanation:

the word ''to'' means over

Answer:

y-acis

Step-by-step explanation:

the function graph is symmetric about

- y-axis when it is an even function

-the origin ehen it is an even function

A symmetrical graph about the x-axis is not a function graph

f(×) is a even if and only if f(×) =f(×)

f(×) is a odd if and only f(×)=f(×)

We have the function r(0) = 4cos (50)

(only symmetry about the y-acis or about the origin)

Check r(-0)

r(-0) = 4cos (5-0) = 4cos (-50 = 4 cos (50)

Used cos (-× = cos ×

We have r(0). Therefore the graph of r(0) is symmectric about the y-axis.

Answer:

x = + 5/4 or x = - 5/4

Step-by-step explanation:

[tex]4 x^2 = 6\frac{1}{4}\\\\4 x^2 = \frac{25}{4}\\\\x^2 =\frac{25}{16}\\\\x = \pm \frac{5}{4}[/tex]

Answer:

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

3 T + 4 B =425

T + B = 125

Where T is the number of tacos sold, and B is the number of burritos sold.

Multiplying the second equation by 3, and subtracting it to the first equation:

3 T + 4 B =425

3T + 3B = 375

___________

B =50

Replacing B in any equation:

T + B = 125

T +50 =125

T =125-50

T = 75

Feel free to ask for more if needed or if you did not understand something.

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

do you have a clearer picture please? I can help :))

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

Answer:

c)  y = 8[tex]\sqrt{3}[/tex]

Step-by-step explanation:

in a 30-60-90° Δ the ratio of the sides, respectively, is 1: [tex]\sqrt{3}[/tex] : 2

if the side opposite the 30°∡ is 8 then 'y' is 8[tex]\sqrt{3}[/tex] and 'x' is 16

Answer:

x = 32 and BEC = 43

Step-by-step explanation:

3X + 41 = 137

3X = 96

X = 32

FOR BEC:

137 + 137 = 274

360-274=86 ( ANGLES AROUND A POINT ADD UP TO 360)

86/2 = 43

BEC/AED = 43 ( VERTICALLY OPPOSITE ANGLES ARE EQUAL)

hope this helps good luck!

Answer:

The given relation is presented as follows;

[tex]\dfrac{1}{a} + \dfrac{1}{b} +\dfrac{1}{c} = \dfrac{1}{a + b + c}[/tex]

Where 'a', 'b', and 'c' are member of real numbers, we have;

a⁹, b⁹, and c⁹ are also member of real numbers

When a⁹ = x, b⁹ = y, and c⁹ = z

By the above relationship, we have;

[tex]\dfrac{1}{x} + \dfrac{1}{y} +\dfrac{1}{z} = \dfrac{1}{x + y + z}[/tex]

Substituting x = a⁹, y = b⁹, and z = c⁹, we get;

[tex]\dfrac{1}{a^9} + \dfrac{1}{b^9} +\dfrac{1}{c^9} = \dfrac{1}{a^9 + b^9 + c^9}[/tex]

Step-by-step explanation:

Answer:

bjkfkvdvdejij

Step-by-step explanation:

22333444 ijdcijsivjdivdvndk snciscicicnlvjavjadvj

Answer:

40

Step-by-step explanation:

A +  B=75

A + C = 61

B = 5/3 *C

A+C * 5/3 = 75 then we got the answer

Answer:

A = 40

Step-by-step explanation:

A+B = 75

A+C = 61

Subtract

A+B = 75

-A-C = -61

----------------------

B-C = 14

B:C

5:3

for every 5B there are 3C

Replace B with 5/3 C

5/3C-C = 14

2/3C = 14

C = 21

A+C = 61

A +21 = 61

A = 40

Answer:

1. x = -6, -8, -90

2. solutions for [tex]-2x\geq 10[/tex] include -5, while -5 is not a solution for [tex]-2x>10[/tex]

Step-by-step explanation:

Answer:

(a - b)^2 = 49 - 4b^2 +2ab

Step-by-step explanation:

Given: a^2 + b^2 = 7b (assuming A is really “a”)

b^2 + (2b - a)^2 = 7^2

Find; (a - b)^2

Plan: Use Algebraic Manipulation

Start with b^2 + (2b - a)^2 = 7^2 =>

b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.

a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms

a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>

a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2

(a - b)^2 = 49 - 4b^2 +2ab

Double Check: recalculated ✅ ✅

(a - b)^2 = 49 - 4b^2 +2ab

Answer:

Step-by-step explanation:

cos(c)= x/ac

ac = cos32/9.4

ac =11.08

Answer:

Step-by-step explanation:

sin(58/9.4 = sin(90)/AC

AC= 11.08

Answer:

Here,

CD + DE = CD

x+10 + x+4 = 8

2x + 14 = 8

2x= -6

x= -3

Answer:

5 shirts

Step-by-step explanation:

Y=12x+3 equation 1

y=8x+23 equation 2

12x+3=8x+23 substituting y value will cause equations to equal

4x=20

x=5 shirts

check answer

y=12x+3

y=12(5)+3

y=60+3

y=63

y=8x+23

y=8(5)+23

y=40+23

y=63

Answer:

7√10 / 10.

Step-by-step explanation:

7/√10

Multiply top and bottom by √10:

= 7√10 / 10

Answer:

y = 2*(x - 3)^2 - 2

Step-by-step explanation:

Remember that a quadratic equation of vertex (h, k) is written as:

y = a*(x - h)^2 + k

Where a is the leading coefficient.

So, if we know that the vertex is at (3, - 2)

we have:

y = a*(x - 3)^2 + (-2)

And we want the y-intercept to be (0, 16)

This means that, when we take x = 0, we must have y = 16

if we replace these in the above equation we get:

16 = a*(0 - 3)^2 - 2

now we can solve this for a

16 = a*(-3)^2 - 2

16 = a*9 - 2

16 + 2 = a*9

18 = a*9

18/9 = a

2 = a

Then the quadratic equation is:

y = 2*(x - 3)^2 - 2