Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each other. Which of the following statements best describes what happens to the electrical force between the objects?

A: The force of attraction increases
B: The force of attraction decreases
C: The force of attraction stays the same
D: The force of attraction becomes a force of repulsion

Answer:

cartilage

Explanation:

Answer:

Cartilage

Explanation:

Correct in AE

Answer:

30 m

General Formulas and Concepts:

Energy

Gravitational Potential Energy: [tex]\displaystyle U_g = mgh[/tex]

Kinetic Energy: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

Law of Conservation of Energy

Explanation:

Step 1: Define

Identify variables

[Given] m = 0.8 kg

[Given] g = 10 m/s²

[Given] U = 240 J

[Solve] h

Step 2: Solve for h

Answer:

Yes it will move and a= 4.19m/s^2

Explanation:

In order for the box to move it needs to overcome the maximum static friction force

Max Static Friction = μFn(normal force)

plug in givens

Max Static friction = 31.9226

Since 36.6>31.9226, the box will move

Mass= Wieght/g which is 45.8/9.8= 4.67kg

Fnet = Fapp-Fk

= 36.6-16.9918

=19.6082

=ma

Solve for a=4.19m/s^2

xin lỗi không có sơ đồ vui lòng cho biết sơ đồ



Answer:

Mercury - 800°F (430°C) during the day, -290°F (-180°C) at night. Venus - 880°F (471°C) Earth - 61°F (16°C) Mars - minus 20°F (-28°C)30-Jan-2018

Answer:

ultrasonic

Explanation:

they detect the acoustic emission created when a pressured gas expands in a low pressure area through a small orifice(the leak).

Answer:

Where is the Question?

Explanation:

I am glad to h help you out.

Answer:

Sorry is there any attachments to put with this question, If please publish question properly please so that brainly answerers will know what to answer.

Answer:

The speed of the golf ball just after the impact is 73.04 m/s.

Explanation:

Given that,

The mass of golf club, m₁ = 183 g = 0.183 kg

The mass of golf ball, m₂ = 46.6 g = 0.0466 kg

The initial speed of golf club, u₁ = 58.6 m/s

The initial speed of a golf ball, u₂ = 0

The final speeds of club, v₁ = 40 m/s

We need to find the speed of the golf ball just after impact. Using the conservation of momentum to find it.

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1u_1=m_1v_1+m_2v_2\\\\v_2=\dfrac{m_1u_1-m_1v_1}{m_2}\\\\v_2=\dfrac{0.183 (58.6)-0.183(40)}{0.0466 }\\\\=73.04\ m/s[/tex]

So, the speed of the golf ball just after the impact is 73.04 m/s.

Complete question:

A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 739 m. Calculate the initial velocity of the bullet.

Answer:

the initial velocity of the bullet is 120.35 m/s

Explanation:

Given;

maximum height reached by the bullet, h = 739 m

let the initial velocity of the bullet = u

At maximum height the final velocity of the bullet, v = 0

Apply the following kinematic equation to determine the initial velocity of the bullet.

v² = u² - 2gh

0 = u² - 2gh

u² = 2gh

u = √2gh

u = √(2 x 9.8 x 739)

u = 120.35 m/s

Therefore, the initial velocity of the bullet is 120.35 m/s

Answer:

x = 13552.6 m

Explanation:

This is a projectile throwing exercise

Let's start by looking for the time it takes for the pump to reach the ground y = 0

         y = y₀ + v_{oy} t - ½ g t²

as the plane flies horizontally the vertical speed is zero

         0 = y₀ + 0 - ½ g t²

         t = [tex]\sqrt{2y_o/g}[/tex]

         t = [tex]\sqrt{2 \ 10000/9.8}[/tex]

         t = 45.175 s

with this time we can find the distance it travels horizontally

         x = v₀ₓ t

         x = 300 45,175

         x = 13552.6 m

the bomb must be dropped at this distance before hitting the target

Answer:

Use 2>60n to get 19>089

Explanation:

Answer:

[tex]v=6.65m/sec[/tex]

Explanation:

From the Question we are told that:

Mass [tex]m=97.6[/tex]

Coefficient of kinetic friction  [tex]\mu k=0.555[/tex]

Generally the equation for Frictional force is mathematically given by

 [tex]F=\mu mg[/tex]

 [tex]F=0.555*97.6*9.8[/tex]

 [tex]F=531.388N[/tex]

Generally the  Newton's equation for Acceleration due to Friction force is mathematically given by

 [tex]a_f=-\mu g[/tex]

 [tex]a_f=-0.555 *9.81[/tex]

 [tex]a_f=-54455m/sec^2[/tex]

Therefore

 [tex]v=u-at[/tex]

 [tex]v=0+5.45*1.22[/tex]

 [tex]v=6.65m/sec[/tex]

Answer:

a because it is at a given moment

Explanation:

did u

Answer:

C) 40m/s [R]

Explanation:

Given the following data;

Force = 25 N [L]

Mass = 1 kg

Initial velocity = 0 m/s

Velocity = 10 m/s [R]

Time = 2 seconds

To find the final velocity;

First of all, we would determine the acceleration of the object.

Force = mass * acceleration

25 = 1 * acceleration

Acceleration = 25/1

Acceleration = 25 m/s²

Next, we would determine the final velocity by using the first equation of motion;

[tex] V = U + at[/tex]

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the formula, we have;

[tex] V = 0 + 25*2[/tex]

[tex] V = 0 + 50 [/tex]

V = 50 m/s

Final velocity = 50 - 10

Final velocity = 40 m/s [R]

Answer:

The induced current is 26.7 mA

Explanation:

Given;

area of the loop, A = 0.078 m²

initial magnetic field, B₁ = 3.8 T

change in the magnetic field strength, dB/dt = 0.24 T/s

The induced emf is calculated as;

[tex]emf = - \frac{d \phi}{dt} \\\\emf = -\frac{dB.A}{dt} \\\\emf = A (\frac{dB}{dt} )\\\\emf = 0.078(0.24)\\\\emf = 0.0187 \ V[/tex]

The resistance of the loop = 0.7 Ω

The induced current is calculated as;

[tex]V = IR\\\\I = \frac{V}{R} = \frac{emf}{R} = \frac{0.0187}{0.7} = 0.0267 \ A = 26.7 \ mA[/tex]

Answer:

MOMENTUM=205 IMPULSE = 5

Explanation:

The momentum of car is 22704 kg m/s.

The resulting impulse of car is 420 N-s.

Momentum is product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

p= mv

p= 1892*12

p= 22704 kg m/s

Impulse is the motion produced by a starting force.

[tex]\Delta p = F\Delta t[/tex]

[tex]\Delta p = 70*6\\\Delta p = 420 Ns[/tex]

To learn more about Momentum here

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Answer:

C. S + 02 → S02

Explanation:

A synthesis or combination reaction is that reaction involving two elements as reactants to form a single compound as product.

In the reaction given below;

S + 02 → S02

Sulphur and oxygen are elemental substances that combine to synthesize sulfur IV oxide (SO2), and hence it is an example of synthesis reaction.

Answer:

b is the correct answer i believe

Explanation:

the strong nuclear force encourages particles to come together so that they can nuetralize, a process the opposite of the electrostatic force of repulsion. This lets the atom stay intact because if the repulsion was more than the nuclear forces strength the atom would lose electrons and slowly decay

Answer:

[tex]F = 14.2 N[/tex]  

Explanation:

From the question we are told that:

Mass [tex]m=0.15kg[/tex]

Radius [tex]r=0.6[/tex]

Angular Velocity [tex]\omega=2rev/s[/tex]

                            [tex]\omega= =2x2 \pi rad/s=>4 \pi rad/s[/tex]

Generally the equation for Force applied is mathematically given by

 [tex]F =mrw2[/tex]

 [tex]F=0.15*0.6* (4*x3.14^)2[/tex]

 [tex]F = 14.2 N[/tex]    

Answer:

Explanation:

V=ds/dt

Where s =distance traveled

Given

V= 2ti - 3t²j

ds/dt=2ti - 3t²j

ds=(2ti - 3t²j)dt

Integrating

S= 2t²i/2 - 3t³j/3 + C

S=t²i - t³j + C

Since the object starts from Rest when t=0 and s(distance)=0

0=0²i - 0³j + C

C=0

Therefore

S=t²i - t³j

At t=2sec

S=(2)²i - (2)³j

S=4i - 8j

Magnitude of S(distance) = √4²+(-8)²

S= 4√5 meters

S=8.94meters.

2.mass =2kg

F(t)=5e^-0.1t

From Newton 2nd Law

F(t) = mdv/dt

5e^-0.1t= 2dv/dt

2dv = (5e^-0.1t)dt

Integrating

2V(t) = 5e^-0.1t/(-0.1) + C

2v(t) = - 50e^-0.1t + C

Since it started from rest at t=0. That is v(0)=0

2(0) = -50e^-0.1(0) + C

0 = -50 + C

C= 50

v(t) = -50e^-0.1t + 50

At t=10sec

v(10) = -50e^-0.1(10) + 50

V= -18.39 + 50

V= 31.61ms-¹.

While using your calc to evaluate -50e^-0.1(10)

Don't forget the -(minus) sign at the top of the exponential.

If you neglect it... You'll have a different answer.

Hope this helps.

Have a great day!!!

Answer:

drive reduction theory

Explanation:

I would say that because of all the cars beeping and making A Lot of cachos on the street so that will definitely affect her taking her exam

Theory explains Lori’s behavior is b) Drive-reduction theory

It is based on the idea that  the primary motivation behind all human behavior is to reduce drives . A drive is a state of  discomfort which is triggered by a person's physiology or biological need .

so , she removed discomfort that can happen by the noise outside the classroom in order to maintain student's concentration

correct answer is b) Drive-reduction theory

learn more about  Drive-reduction theory

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Answer:

a = 5.256 m / s²  with the vertical direction upwards and   T = 1090.8 N

Explanation:

to find the acceleration we must use Newton's second law, in the lowest part of the motion

          T - W = m a

where the acceleration is centripetal

         a = v² / r

let's calculate

         a = 4.51² / 3.87

         a = 5.256 m / s²

As the acceleration is centripetal it is directed towards the center of the circle, which in the lower part coincides with the vertical direction upwards.

Let's find the tension of the rope with the first equation

        T = W + m a

        W = m g

let's calculate

         T = 710 + 710 5.256 / 9.8

         T = 1090.8 N

Answer:

Teh velocity of ball with respect to the ground is 29.2 m/s.

Explanation:

Velocity of car, vc = 25 due m/s east

velocity of ball with respect to car, v(b,c) = 15 m/s due Z axis

Write the velocities in the vector form

[tex]\overrightarrow{v}_{c}=25 \widehat{i}\\\\\overrightarrow{v}_{(b,c)}=15 \widehat{k}[/tex]

The velocity of ball with respect to ground is

[tex]\overrightarrow{v}_{(b,c)}= \overrightarrow{v}_{(b,g)}-\overrightarrow{v}_{(c,g)}\\\\15 \widehat{k} = \overrightarrow{v}_{(b,g)} - 25 \widehat{i}\\\\\overrightarrow{v}_{(b,g)} = 25 \widehat{i} + 15 \widehat{k}\\\\v_{(b,g)}=\sqrt{25^2 + 15^2}=29.2 m/s[/tex]

Answer:

the correct answer is C

Explanation:

In this exercise we will analyze the situation.

When the person is on the ice, the friction coefficient is very small, if the box is in a place where there is no ice, the coefficient is different, so the friction force on each body is different.

Therefore the acceleration that each body acquires is different.

If we apply the conservation of momentum, each body moves in the opposite direction, but with different speeds.

If we use Newton's third law, the force applied to each body has the same magnitude and opposite direction, which is why the force is of the action and reaction type

Consequently the correct answer is C

Answer:

5. 32I

Explanation:

The moment of inertia of a solid sphere about its central axis is given by

I = [tex]\frac{2}{5} MR^2[/tex]            ------------------(i)

Where;

M = mass of the sphere

R = radius of the sphere.

From the question;

Case 1: The aluminum sphere has a radius R and moment of inertia I.

This means that we can substitute these values of R and I into equation (i) and get;

I = [tex]\frac{2}{5} MR^2[/tex]       --------------(ii)

M is the mass of the aluminum sphere and is given by;

M = pV

Where;

p = density of aluminum

V = Volume of the sphere = [tex]\frac{4}{3} \pi R^3[/tex]

=> M = p([tex]\frac{4}{3} \pi R^3[/tex])              --------------------(*)

Case 2: An aluminum sphere with a radius of 2R instead.

Let the moment of inertia in this case be I' and mass be M'

Substituting R = 2R, M = M' and I = I' into equation (i) gives

I' = [tex]\frac{2}{5} M'(2R)^2[/tex]       ------------------(iii)

Where;

M' = pV'

p = density of aluminum

V' = volume of the sphere = [tex]\frac{4}{3} \pi (2R)^3[/tex]

=> M' = p([tex]\frac{4}{3} \pi (2R)^3[/tex])

Rewriting gives;

M' = p([tex]\frac{4}{3} \pi (2)^3(R)^3[/tex])

M' = p([tex]\frac{4}{3} \pi8(R)^3[/tex])

M' = 8p([tex]\frac{4}{3} \pi R^3[/tex])

From equation (*), this can be written as

M' = 8M

Now substitute all necessary values into equation (ii)

I' =  [tex]\frac{2}{5} M'(2R)^2[/tex]  

I' =  [tex]\frac{2}{5} (8M)(2R)^2[/tex]  

I' =  [tex]\frac{2}{5} (8M)(2)^2(R)^2[/tex]  

I' =  [tex]\frac{2}{5} (8M)(4)(R)^2[/tex]

I' =  [tex]\frac{2}{5} (32M)(R)^2[/tex]

I' =  [tex]32[\frac{2}{5}MR^2][/tex]

Comparing with equation (ii)

I' =  [tex]32[I][/tex]

Therefore, the moment of inertia about a central axis of a solid

aluminum sphere of radius 2R is 32I

Answer:

a) [tex]\omega _1=7.56rev/s=>47.5rads/s[/tex]

b) [tex]a=30.7[/tex]

c) [tex]a=35.91[/tex]

Explanation:

From the question we are told that:

Initial angular velocity [tex]\omega _1=7.56rev/s=>47.5rads/s[/tex]

Initial Length [tex]L_1=0.600m[/tex]

Final angular velocity [tex]\omega _2=6.22rev/s=39rad/s[/tex]

Final Length [tex]L_2=0.900m[/tex]

a)

Generally the rotation with the greater speed is

[tex]\omega _1=7.56rev/s=>47.5rads/s[/tex]

b)

Generally the equation for centripetal acceleration at 8.16 is mathematically given by

[tex]a=\omega_1^2*L_1[/tex]

[tex]a=8.16 rev/s*0.6[/tex]

[tex]a=30.7[/tex]

c)

At 6.35 rev/s

[tex]a=6.35 rev/s*0.9[/tex]

[tex]a=35.91[/tex]

Answer:

PE = 82.32J

Explanation:

PE = m*g*h

PE = 2.80kg*9.8m/s²*3m

PE = 82.32J

Answer:

D I think I’m not for sure

Explanation: