Two forces of magnitude 10N each . Their resultant is equal to 20N . Then angle between them is

6 possible falls producing 6 wavelengths so the Correct option is C)

no. of radiation = [tex]^{4} C_2=\frac{4\times3}{2}[/tex] =6

a wave's wavelength is the separation between two adjacent waves' corresponding points. Two points or particles that are in the same phase—i.e., points that have completed identical fractions of their periodic motion—are referred to as "corresponding points." Wavelength is typically measured from crest to crest or from trough to trough in transverse waves (waves with points vibrating at right angles to the direction of their advance); from compression to compression or from rarefaction to rarefaction in longitudinal waves (waves with points vibrating in the same direction as their advance).

6 possible falls producing 6 wavelengths

4 → 3, 4→2 , 4→1

3→2,3→1

2→1

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The repulsive electrical force  between protons is: [tex]F = 9.279 \times 10^{-8} \,{\rm{N}}[/tex]

The repulsive electrical force between two protons 3.5 * 10-15 m apart from each other in an atomic nucleus is calculated by Coulomb's law, which states that the force between two charged particles is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

So, the repulsive force between two protons 3.5 * 10-15 m apart is given by:

[tex]F = (1.602 \times 10^{-19})^2 / (3.5 \times 10^{-15})^2[/tex]

[tex]F = 9.279 \times 10^{-8} \,{\rm{N}}[/tex]

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A wave is a disturbance in a medium. The speed of a wave can be calculated by the formula: V = λf.

A wave is a propagating dynamic disturbance of one or more quantities such as sound and light. Waves can be periodic, in which case those quantities oscillate repeatedly about an equilibrium value at some frequency.

V = λf

where, V is the velocity of wave,

λ is the wavelength,

f is the frequency.

1. Time period = 0.25 second

Frequency of a wave = 1/T

F = 1/ 0.25

F = 4 sec⁻¹

2. Speed of the wave with frequency 5.0 Hz and wavelength 10cm

v = λf

v = 10 × 5.0

v = 50 cm/s

3. Frequency of a wave with speed 20cm/s and wavelength 10cm

v =  λf

f =  λ/v

f = 10/20

f = 1/2 or 0.5 Hz

4. Wavelength of a wave when frequency is 5.0 Hz and speed 30 cm/s

v = λf

λ = v/f

λ = 30/5

λ = 6cm

5. Speed of a wave when the period is 3 sec and wavelength is 20m

Period = 1/f

3 = 1/f

f = 1/3

v = λf

v = 20 × 1/3

v = 6.66m/s

6. Wavelength of the wave when frequency is 75 Hz and speed is 300m/s

v = λf

λ = v/f

λ = 300/ 75

λ = 4m

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The average kinetic energy is increased by 4 times when the average velocity of the molecules is increased by a factor of 2.

It is given that the average velocity that is average velocity is increased by a factor of 2, so it is increased by 2 x times.

Another formula to calculate kinetic energy,

[tex]\dfrac{1}{2} \times m \times v^2[/tex]

Kinetic energy will also increase by, 4 times as it is proportional to the square of velocity.

Average kinetic energy is a function of gas molecule speed, increasing temperature causes the gas molecules to move more quickly, which raises the average kinetic energy of the gas molecule.

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The voltage across the wire is 1332 V.

Voltage is a measure of electrical potential difference between two points in a circuit. It is a measure of the amount of electrical energy available to do work. Voltage is measured in volts (V). The voltage between two points is the difference in electrical potential between those two points. Voltage is the force pushing electrons through a circuit and is responsible for the current that flows in a circuit. The higher the voltage, the greater the current. Voltage is created when charge is stored in a capacitor or a battery.

The voltage across the wire is determined by Ohm's law, In this case, the resistance of the wire is given by R = L/A, where L is the length of the wire (20 cm) and A is the cross-sectional area of the wire (0.6 mm^2). Therefore, the resistance of the wire is 33.3 Ω.

The current is given by I = Q/t, where Q is the charge (4 cells) and t is the time (0.1 s). Therefore, the current is 40 A.

Using Ohm's law, we can calculate the voltage across the wire: V = IR = (40 A)(33.3 Ω) = 1332 V.

Therefore, the voltage across the wire is 1332 V.

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During 0.004s to 0.006s interval of time does the magnitude of the momentum of cart y change the most.

Momentum (more particularly linear momentum , translational momentum) is defined in Newtonian physics as the product of an object's mass and velocity. It consists of a vector quantity with magnitude and direction. If an object's mass is m and its velocity is v (also a vector quantity).

The kilogram metre per second (kgm/s) is the unit of momentum measurement in the International System of Units (SI), which really is equivalent to the newton-second. During 0.004s to 0.006s interval of time does the magnitude of the momentum of cart y change the most.

Therefore,  during 0.004s to 0.006s  interval of time does the magnitude of the momentum of cart y change the most.

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P.E  -1.57 × 10¹¹J is the gravitational potential energy.

Give the definition of gravitational potential energy

The energy that an object acquires as a result of its height or vertical position is known as gravitational potential energy. When we elevate items against Earth's gravity, the energy is held back by the gravitational force.

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

P.E  = -GMm/r

m  = 5000kg

r   =  9.9 × 10⁶ m

G  = 6.67 × 10⁻¹¹

M  = 5.18 × 10²⁴

P.E  = -(6.67 × 10⁻¹¹ *5.18 × 10²⁴ × 5000) / ( 9.9 × 10⁶ + 6.38 × 10⁶)

P.E  = -1.57 × 10¹¹J

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The increase in surface area when the temperature rises from 20 to 75 degrees Celsius.  =  11cm².

Heat waves will probably occur more frequently and persist longer as a result of the higher temperatures. Heat waves can be deadly, leading to conditions like heat cramps and heat stroke as well as actual mortality. Additionally, warmer temperatures have the potential to trigger a variety of other changes all around the world.

A fever is defined as a rise in body temperature above what is regarded as normal. It's also known as a high temperature, hyperthermia, or pyrexia, and it typically indicates that your body is attempting to protect you from an infection.

The increase in the surface area of the brass cube (which has six faces), which had side length L at 20 o, is

Δ A - 6(L - ΔL)² - 6L²

12LΔL = 12abL²ΔT

= 12(19 x 10⁻⁶/c)(30cm)²

=(75c - 20c)

= 11cm²

The increase in surface area when the temperature rises from 20 to 75 degrees Celsius.  =  11cm².

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The magnitude of the electric field between the oppositely charged parallel plates is 100,336 N/C.

The electric field (E) between the parallel plates can be calculated using the following formula:

E = V / d

where V is the potential difference between the plates and d is the separation distance between the plates.

In this case, the potential difference is 600 V and the separation distance is 5.96 mm = 0.00596 m.

So, the magnitude of the electric field between the plates can be calculated as:

E = 600 V / 0.00596 m = 100,336 N/C

Therefore, the magnitude of the electric field between the oppositely charged parallel plates is 100,336 N/C.

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Wave speed - the distance the wave travels in a given amount of time

Frequency - number of events per unit of time

Period - time it takes to complete one oscillation

For Transverse Waves:

For longitudinal Waves:

The orbital period of the asteroid to the nearest hundredth of a year is 34.43 years.

The orbital period of an asteroid is given by the formula T = 2 × pi × (a³ / G × M)^(1/2). To find the orbital period, we need to calculate T using the given values for a, G, and M.

a = 5.07 a.u.

G = 6.67 x 10⁻¹¹ N × m² / kg²

M = 1.989 x 10^30 kg

T = 2 × pi × (a³ / G × M)^(1/2)

T = 2 × pi × (5.07³ / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)

T = 2 × pi × (156.9837 / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)

T = 2 × pi × (1.8048 x 10¹² / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)

T = 2 × pi × (1.8048 x 10¹² / 1.38 x 10⁻²³)^(1/2)

T = 2 × pi × (1.30 x 10³⁵)^(1/2)

T = 2 × pi × (3.66 x 10¹⁷)^(1/2)

T = 2 × pi × 1.91 x 10⁹

T = 12.57 x 10⁹

T = 12.57 / 365.25

T = 34.43 years

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Answer:

i) The focal length of the lens is 11.1 cm. ii) The radius of curvature of the lens surface is 55.6 cm.

Explanation:

Given: refractive index of glass = 1.5, object distance u = -10 cm, image distance v = 100 cm (since the image is virtual and ten times the size of the object), and the thickness of the lens t is small.

i) To find the focal length f, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values, we get:

1/f = 1/100 - 1/-101/f = 0.01 + 0.11/f = 0.11f = 1/0.11f = 9.09 cm

However, this is the focal length of the lens surface. Since the lens is thin, we can assume that the thickness is negligible compared to the focal length.

Therefore, the focal length of the lens is approximately equal to the focal length of the lens surface, which is 9.09 cm.

The focal length of the thin plano-convex lens is -11.1 cm and the radius of curvature of the lens surface is 55.6 cm. These values are obtained by applying the lens-maker formula and considering the given conditions.

In this question, a thin plano-convex lens made of glass with a refractive index of 1.5 is described. An object is placed 10 cm from this lens and a virtual image ten times the size of the object is formed. We are required to find the focal length of the lens and the radius of curvature of the lens surface.

Using the lens-maker formula, 1/f = (n-1)(1/R1 - 1/R2 ), and considering the object distance (u) as -10 cm (the negative sign is due to the convention for virtual images), and the image distance (v) as -100 cm (ten times the object size), we find that the focal length (f) of the lens is -11.1 cm.

Next, applying the lens-maker formula again, but this time for the radius of curvature (R) of the lens surface. Since one surface of the lens is plane (R1 = ∞), the radius of curvature is that of the convex side (R2), we obtain R = 55.6 cm.

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The magnitude of the centripetal acceleration at the tip of a 3.20 m long helicopter blade that rotates at 205 rev/min is 1,474.7 m/s2

The acceleration that a body experiences when moving around in a circle is known as centripetal acceleration. Since velocity is a vector quantity (that is, it possesses both a magnitude, which is the speed, and a direction), when a body travels on a circular path, its direction is constantly changing, and as a result, its velocity is changing as well, which results in an acceleration. The acceleration is exerted in a radial direction that is directed toward the center of the circle. To calculate the centripetal acceleration, we can use this following formula:

                                                   Ac = v² ÷ r  

V = ωr

Ac = (ωr)² ÷ r

                                                    Ac = ω²r

ω = 205 rev/min = 21.47 rad/s

r = 3.20 m

Next, we can substitute the required values to find the centripetal acceleration:

Ac = (21.47 rad/s)²  × 3.20 m

Ac = 1,474.7 m/s²

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Charge q at a distance of 2.7 m away from the point charge is approximately [tex]-9.9 * 10^(-7) C[/tex]. We calculated this using Coulomb's law.

The electric potential (voltage) at a point a distance r away from a point charge q is given by the Coulomb's law:

[tex]V = k * q / r[/tex],

where k : Coulomb's constant ([tex]9 * 10^9 N*m^{2} /C^{2}[/tex]). In this case, we know that the voltage V is [tex]-3.5 * 10^3 V[/tex] and the distance r is 2.7 m. Therefore, we can write:

-[tex]3.5 * 10^3 V = (9 * 10^9 N*m^{2} /C^{2} ) * q / 2.7 m[/tex]

Solving for q:

q = [tex](-3.5 * 10^3 V) * (2.7 m) / (9 * 10^9 N*m^{2} /C^{2} ) = -9.9 * 10^(-7) C[/tex]

The negative sign indicates that the charge is negative, which means that it has an excess of electrons. This result shows that electric potential is directly proportional to the magnitude of the charge and inversely proportional to the distance from the charge.

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Answer:

the answer is 200seconds(s)

Answer:

Yes, I agree with the statement that gas particles do not respond to heat the same way people do. The reason for this is that gas particles do not have the same sensory mechanisms that people have to perceive heat.

When a person is exposed to heat, their sensory nerves respond by sending signals to the brain, which then triggers a response such as sweating, increased heart rate, or a feeling of discomfort. However, gas particles do not have nerves or brains, so they cannot respond to heat in the same way.

Instead, gas particles respond to heat by increasing their kinetic energy and moving faster. This causes the gas to expand and occupy more space. For example, if a gas is heated in a container with a fixed volume, the pressure inside the container will increase as the gas particles collide more frequently with the container walls.

Additionally, unlike people, gas particles do not have a specific temperature range in which they are comfortable or safe. They will continue to gain kinetic energy and expand as long as they are exposed to heat, without any limit to their response.

In summary, gas particles and people respond to heat in fundamentally different ways due to differences in their physical and biological properties.

The work done is 43200 joules.

Work is defined as the distance traveled in the direction of the force in the product of the forces. In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, work done with a constant force in the direction of motion is equal to the product of the force and the distance traveled. Work is the product of the displacement and the force component in the direction of displacement. When you do work, the kinetic energy of an object changes. In this task the force is given as 180 N to move the car he 240 m.

Work = 180 N x 240 m = 43200 J

In this case, the 1260 kg mass of the car is not needed. 

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The electrical capability strength of a 1.zero-C price at factor (zero, 4.zero m) is 7.sixty five x 10^6 J. 

To locate the electrical capability strength of a 1.zero-C price at factor (zero, 4.zero m), we will use the formulation: U = k * q1 * q2 / r

First, we want to locate the electrical capability at factor (zero, 4.zero m) because of the 2 expenses. The electric powered capability at a factor because of a factor price is given by: V = k * q / r

The electric powered capability at factor (zero, 4.zero m) because of the 5.zero-nC price is: V1 = k * q1 / r1

=[tex](nine x 10^nine Nm^2/C^2) * (5.zero x 10^-nine C) / (4.zero m)[/tex]

= 1.a hundred twenty five x 10^7 V

The distance among the 5.zero-nC price and the factor (zero, 4.zero m) is: r1 = [tex]\sqrt{(zero^2 + 4.zero^2) = 4.zero m}[/tex]

The electric powered capability at factor (zero, 4.zero m) because of the -2.zero-nC price is: V2 = k * q2 / r2

= [tex](9 x 10^9 Nm^2/C^2) * (-2.zero x 10^-9 C) / (5.zero m)[/tex]

= -3.6 x 10^6 V

The distance among the -2.zero-nC price and the factor (zero, 4.zero m) is: r2 = sqrt((3.zero m - zero)^2 + 4.zero^2) = 5.zero m

The overall electric powered capability at factor (zero, 4.zero m) is:

V = V1 + V2

= 1.a hundred twenty five x 10^7 V - 3.6 x 10^6 V

= 7.sixty five x 10^6 V

Now we will use the formulation for electric powered capability strength to locate the strength of a 1.zero-C price at factor (zero, 4.zero m) because of the 2 expenses: U = q * V

= (1.zero C) * (7.sixty five x 10^6 V)

= 7.sixty five x 10^6 J

Therefore, the electrical capability strength of a 1.zero-C price at factor (zero, 4.zero m) is 7.sixty five x 10^6 J. 

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The ball's maximum height during its trajectory is 22.05 meters.

Maximum range (dx) is obtained at an angle of 45°. The most horizontal distance is covered at an angle of 45 degrees or nearly there. The greatest possible height will be attained and the longest duration spent in the air when the angle is 90 degrees or higher.

The formula for determining the greatest height, ymax, is: vy 2 = vy(0)2 + 2 ay (y - y(0)). To get ymax = vy(0)2/ 2g, substitute into y(t) = vy(0) t - 12 g t2. The beginning velocity in the y-direction and the maximum height are used to calculate the maximum height.

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If the thermal bulb assembly develops a leak, The bulb pressure will reduce and the valve will close.

A thermostatic expansion valve (TXV) is a refrigeration and air conditioning throttling device which controls the amount of refrigerant liquid injected into a system's evaporator. It based on the evaporator outlet temperature and pressure which being called the superheat.

When a thermostatic expansion valve’s thermal bulb assembly develops a leak, the bulb pressure will decrease, and the valve will close. The pin or valve port piston of the electronic step-motor expansion valve could move a linear motion of 0.0783 inches/step.

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A tentative explanation for a natural phenomenon describes hypothesis .

A straightforward hypothesis can indicate that there is a causal relationship—that is, that one variable affects the other—between two variables. Here's an illustration: Higher grades are the result of more time spent preparing for a test. The number of hours spent studying is the independent variable in this statement, and the result is the dependent variable. The independent variable is altered while the dependent variable is evaluated to ascertain how the dependent variable is impacted by the independent variable. Similar to a simple hypothesis, a complex hypothesis has two or more independent variables and/or two or more dependent variables.

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The tangential velocity of the sun at the equator is, 2370.25π km/hr.

Tangential velocity is the linear component of the speed of any object which is moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center.

The equation for velocity is v = ΔxΔt. Using the circumference of the circle as the distance and the time as the period, we can rewrite the equation for velocity: v = 2πr/T.

Plug in the given values and solve for the velocity.

v = 2π (696,000km)/587.28 hr

v = π × 1392000km/587.28 hr

v = 2370.25π km/hr

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The speed of the objects after collision, given that they stocked together is 5.4 m/s

We'll beging by listing out the given parameters from the question. This is given below:

The speed after the collision can be obtained as shown below:

Momentum before = momentum after

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(2 × 4) + (5 × 6) = v(2 + 5)

8 + 30 = v × 7

38 = v × 7

Divide both sides by 7

v = 38 / 7

v = 5.4 m/s

Thus, the speed after collision is 5.4 m/s

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The required capacitance when voltage and charge of a capacitor are specified is calculated to be 0.2 F.

The expression for potential, charge and capacitance is known as,

Q = C V

where,

Q is charge

C is capacitance

V is voltage

The value of initial voltage is given as, V = 30 v

The value of initial charge is given as, Q = 6 c

Entering the values into the above equation, we have,

Q = C V

Making 'C' as subject, we have,

C = Q/V = 6/30 = 0.2 F

Thus, the required capacitance is calculated to be 0.2 F.

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The resultant displacement of the object is 45 m.

The resultant displacement of the object is calculated as follows;

Sum of the vertical displacement of the object is calculated as;

y = 27 m - 63 m = -36 m

Sum of the horizontal displacement of the object is calculated as;

x = 31 m - 58 m = -27 m

The resultant displacement of the object is calculated as follows;

d = √ [ ( -36² ) +  ( - 27² ) ]

d = 45 m

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The complete question is below;

2.4 Displacement of 27m north,31 m east,63m south and 58m west. Take east as the positive x-direction and north as the positive y-direction. 3. Check 2.4 with an accurate tail to head vector diagram​. Calculate the resultant displacement of the vector

By adding a dielectric, the capacitance rises and the energy in the capacitor decreases.

The strength of the electric field is reduced as a result of the presence of dielectric. If the overall charge on the capacitor plates is kept constant, the potential difference across the plates will decrease. The dielectric increases the capacitor's capacitance as a result. When a capacitor is given a dielectric, the electric field is diminished, the voltage is lowered, and the capacitance is increased.

You must perform negative work in order to decrease the potential energy stored in the capacitor since adding a dielectric will increase capacitance C and reduce that potential energy.

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The surface pressure is higher or lower than the SLP (Sea Level Pressure) of your location depending on the altitude at which it was measured. At Falcon Field, the surface pressure was measured at 245 meters above sea level.

This means that the pressure is lower than the SLP because the higher the altitude, the lower the atmospheric pressure. The atmospheric pressure decreases with an increase in altitude due to the decrease in the air density at higher elevations.

Surface pressure, also known as atmospheric pressure, is the pressure that the air exerts on the surface of the Earth.

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The vehicle accelerates steadily around 3 m/s2 for 15 sec while moving at 20 m/s. This indicates that when the car accelerates, it will cover a total length of 75 metres.

An item that follows a circular course while maintaining a constant speed is still moving forward because the source of its motion is shifting.

Additionally, it is either the first variant of velocity in relation to time or the second derivative for position in relation to time.

The time frame that can be measured or quantified.

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The velocity of the koala at the bottom of the circle is 2.23 m/s.

The velocity of the koala at the bottom of the circle can be determined by considering the concepts of centripetal force and centripetal acceleration. Centripetal force is the force that acts towards the center of the circle and is responsible for keeping the object moving in a circular path. Centripetal acceleration is defined as the acceleration of an object moving in a circular path, and it can be calculated as follows: a = [tex]v^{2}[/tex] / r, where v is the velocity of the object and r is the radius of the circle.

v = [tex]\sqrt{g\times r}[/tex], where v is the velocity, g is the acceleration due to gravity (9.8 m/[tex]s^{2}[/tex]), and r is the radius of the circular path.

Since the speed of the koala is constant at 2 m/s, we can use this value to find the radius of the circular path:

r = [tex]v^{2}[/tex] / g

r = [tex](2 m/s)^2[/tex] / (9.8 m/[tex]s^{2}[/tex])

r = 0.408 m

Now that we have the radius, we can use the equation for centripetal velocity to find the velocity of the koala at the bottom of the circle:

v = [tex]\sqrt{g\times r}[/tex]

v = √(9.8 m/[tex]s^{2}[/tex] × 0.408 m)

v = 2.23 m/s

Since the speed of the koala is constant, its velocity at the bottom of the circle will be equal to its speed, which is 2.23 m/s.. Hence, the velocity of the koala at the bottom of the circle is 2.23 m/s.

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A 5 cm focal length converging lens is 30 cm away from the item being observed. The image is real but it is inverted.

Light is directed to a location at the focal spot or axis of a convergent lens. a lens that creates a true image by converting parallel light beams to convergent light rays. The image is actual and inverted as longer as the thing is not within the focal point.

Since the rays concentrate after passing through the convex lens, convex lenses are indeed known as converging lenses. Since the rays disperse after striking the concave lens, curvy lenses are also known as converging lenses.

u = Object distance

= 30 cm

v = Image distance

f = Focal length

= 5 cm

Lens Equation,

1/f = 1/u + 1/v

1/f - 1/u = 1/v

1/v = 1/5 - 1/30

1/v = 1/6

v = 6cm

m = -v/u

m = -6/30

m = -0.2

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